Search Results

Search found 1326 results on 54 pages for 'orm'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 17/54 | < Previous Page | 13 14 15 16 17 18 19 20 21 22 23 24  | Next Page >

  • JPA/Hibernate query with class name?

    - by Petteri Hietavirta
    In this example com.test.Cat extends com.test.Animal and there is no field DB in CAT table of com.test.Cat explicitly defining its type (it wasn't me). When I query my animals from DB I get a collection of Animals. It is possible to sort them by class name: order by r.class but is there a way to use class name as a criteria? For example I would like to get all animals expect dogs. But no luck - even this does not work: where r.class = ? (String "ccc.test.Cat") as I get an exception: Caused by: java.lang.ClassCastException: java.lang.String cannot be cast to java.lang.Integer at org.hibernate.type.IntegerType.set(IntegerType.java:64) at org.hibernate.type.NullableType.nullSafeSet(NullableType.java:154) at org.hibernate.type.NullableType.nullSafeSet(NullableType.java:136) at org.hibernate.param.PositionalParameterSpecification.bind(PositionalParameterSpecification.java:62) at org.hibernate.loader.hql.QueryLoader.bindParameterValues(QueryLoader.java:514) at org.hibernate.loader.Loader.prepareQueryStatement(Loader.java:1589) at org.hibernate.loader.Loader.doQuery(Loader.java:696) at org.hibernate.loader.Loader.doQueryAndInitializeNonLazyCollections(Loader.java:259) at org.hibernate.loader.Loader.doList(Loader.java:2228) at org.hibernate.loader.Loader.listIgnoreQueryCache(Loader.java:2125) at org.hibernate.loader.Loader.list(Loader.java:2120) at org.hibernate.loader.hql.QueryLoader.list(QueryLoader.java:401) at org.hibernate.hql.ast.QueryTranslatorImpl.list(QueryTranslatorImpl.java:361) at org.hibernate.engine.query.HQLQueryPlan.performList(HQLQueryPlan.java:196) at org.hibernate.impl.SessionImpl.list(SessionImpl.java:1148) at org.hibernate.impl.QueryImpl.list(QueryImpl.java:102) at org.hibernate.ejb.QueryImpl.getResultList(QueryImpl.java:67)

    Read the article

  • Popularity Algorithm - SQL / Django

    - by RadiantHex
    Hi folks, I've been looking into popularity algorithms used on sites such as Reddit, Digg and even Stackoverflow. Reddit algorithm: t = (time of entry post) - (Dec 8, 2005) x = upvotes - downvotes y = {1 if x > 0, 0 if x = 0, -1 if x < 0) z = {1 if x < 0, otherwise x} log(z) + (y * t)/45000 I have always performed simple ordering within SQL, I'm wondering how I should deal with such ordering. Should it be used to define a table, or could I build an SQL with the ordering within the formula (without hindering performance)? I am also wondering, if it is possible to use multiple ordering algorithms in different occasions, without incurring into performance problems. I'm using Django and PostgreSQL. Help would be much appreciated! ^^

    Read the article

  • What's the best way to calculate similarity between rows in a table based on association?

    - by André Pena
    Suppose each Person has a collection of favorite Books. So I have a table for: Person Book The association between Person and Book (joint table for MxN) I want to fetch the Persons that are similar to a Person1 based on the favorite Books overlaping. That is: The more books they have in common, the more they are similar. I don't have to use only SQL to solve this problem. I could use programming also. I'm using SQL Server 2008 and C#. What solution would you experts use?

    Read the article

  • bi-directional o2m/m2o beats uni-directional o2m in SQL efficiency?

    - by Henry
    Use these 2 persistent CFCs for example: // Cat.cfc component persistent="true" { property name="id" fieldtype="id" generator="native"; property name="name"; } // Owner.cfc component persistent="true" { property name="id" fieldtype="id" generator="native"; property name="cats" type="array" fieldtype="one-to-many" cfc="cat" cascade="all"; } When one-to-many (unidirectional) Note: inverse=true on unidirectional will yield undesired result: insert into cat (name) values (?) insert into Owner default values update cat set Owner_id=? where id=? When one-to-many/many-to-one (bi-directional, inverse=true on Owner.cats): insert into Owner default values insert into cat (name, ownerId) values (?, ?) Does that mean setting up bi-directional o2m/m2o relationship is preferred 'cause the SQL for inserting the entities is more efficient?

    Read the article

  • How to make a mapped field inherited from a superclass transient in JPA?

    - by Russ Hayward
    I have a legacy schema that cannot be changed. I am using a base class for the common features and it contains an embedded object. There is a field that is normally mapped in the embedded object that needs to be in the persistence id for only one (of many) subclasses. I have made a new id class that includes it but then I get the error that the field is mapped twice. Here is some example code that is much simplified to maintain the sanity of the reader: @MappedSuperclass class BaseClass { @Embedded private Data data; } @Entity class SubClass extends BaseClass { @EmbeddedId private SubClassId id; } @Embeddable class Data { private int location; private String name; } @Embeddable class SubClassId { private int thingy; private int location; } I have tried @AttributeOverride but I can only get it to rename the field. I have tried to set it to updatable = false, insertable = false but this did not seem to work when used in the @AttributeOverride annotation. See answer below for the solution to this issue. I realise I could change the base class but I really do not want to split up the embedded object to separate the shared field as it would make the surrounding code more complex and require some ugly wrapping code. I could also redesign the whole system for this corner case but I would really rather not. I am using Hibernate as my JPA provider.

    Read the article

  • versioning fails for onetomany collection holder

    - by Alexander Vasiljev
    given parent entity @Entity public class Expenditure implements Serializable { ... @OneToMany(mappedBy = "expenditure", cascade = CascadeType.ALL, orphanRemoval = true) @OrderBy() private List<ExpenditurePeriod> periods = new ArrayList<ExpenditurePeriod>(); @Version private Integer version = 0; ... } and child one @Entity public class ExpenditurePeriod implements Serializable { ... @ManyToOne @JoinColumn(name="expenditure_id", nullable = false) private Expenditure expenditure; ... } While updating both parent and child in one transaction, org.hibernate.StaleObjectStateException is thrown: Row was updated or deleted by another transaction (or unsaved-value mapping was incorrect): Indeed, hibernate issues two sql updates: one changing parent properties and another changing child properties. Do you know a way to get rid of parent update changing child? The update results both in inefficiency and false positive for optimistic lock. Note, that both child and parent save their state in DB correctly. Hibernate version is 3.5.1-Final

    Read the article

  • PHP ORMs: Doctrine vs. Propel

    - by Tom
    Hi, I'm starting a new project with symfony which is readily integrated with Doctrine and Propel, but I of course need to make a choice.... I was wondering if more experienced people out there have general pros and/or cons for going with either of these two? Thanks a lot. EDIT: Thanks for the all the responses, useful stuff. There's no truly correct answer to this question so I'll just mark as approved the one that got the most popular up-votes.

    Read the article

  • NHibernate mapping one table on two classes with where selection

    - by Rene Schulte
    We would like to map a single table on two classes with NHibernate. The mapping has to be dynamically depending on the value of a column. Here's a simple example to make it a bit clearer: We have a table called Person with the columns id, Name and Sex. The data from this table should be mapped either on the class Male or on the class Female depending on the value of the column Sex. In Pseudocode: create instance of Male with data from table Person where Person.Sex = 'm'; create instance of Female with data from table Person where Person.Sex = 'f'; The benefit is we have strongly typed domain models and can later avoid switch statements. Is this possible with NHibernate or do we have to map the Person table into a flat Person class first? Then afterwards we would have to use a custom factory method that takes a flat Person instance and returns a Female or Male instance. Would be good if NHibernate (or another library) can handle this.

    Read the article

  • How do I migrate a ManyToOne to a ManyToMany relationship in Hibernate?

    - by spderosso
    I have a instance field of a class X that is mapped using Hibernate as a Many to One relationship. E.g: public class X{ ... @ManyToOne(optional=false) private Y iField; ... } That is correctly working with a particular schema. I know want to change this instance field iField to a List and a Many to Many relationship. public class X{ ... @ManyToMany(optional=false) private List<Y> iField; ... } What steps should I follow? Do I have to change the schema? in which way? In case you need more info let me know. Thanks!

    Read the article

  • Where do DQL statements live in an application that is using Zend Framework and Doctrine

    - by Dewayne
    In an application that is using Zend Framework 1.10 and Doctrine 1.2, where should the DQL statements live if our application is built such that it has a Service Layer and a Gateway(aka Doctrine_Table) layer. It seems that our possibilities include: 1) Placing the DQL statements in the Service layer which seems to be a bit too high in our application hierarchy to store DQL. 2) Placing the DQL statements within each model's Table/Gateway which seems a bit redundant because we also need to expose the DQL statements that do things such as getAllUsers() through the Service layer. Which of these is a preferable design? We intend to make use of the Service layer as much as possible so that other projects might consume various parts of our application.

    Read the article

  • Nhibernate not tracking changes

    - by Lavinski
    I'm using nhibernate and it appears that changes to my new object are not persisted. After creating and saving an object I then modify it and commit the transaction. However none of the modifications are saved. The strange thing is this code was working previously and I have no idea what could cause this. Nothing was changed that's obviously related.. As an attempted work around I saved the object later in the procedure after all the changes where made however I was greeted with an Assertion Failure collection [] was not processed by flush. Any ideas?

    Read the article

  • Mapping two tables 0..n in Hibernate

    - by simon
    I have a table Users CREATE TABLE "USERS" ( "ID" NUMBER NOT NULL , "LOGINNAME" VARCHAR2 (150) NOT NULL ) and I have a second table SpecialUsers. No UserId can occur twice in the SpecialUsers table, and only a small subset of the ids of users in the Users table are contained in the SpecialUsers table. CREATE TABLE "SPECIALUSERS" ( "USERID" NUMBER NOT NULL, CONSTRAINT "PK_SPECIALUSERS" PRIMARY KEY ("USERID") ) ALTER TABLE "SPECIALUSERS" ADD CONSTRAINT "FK_SPECIALUSERS_USERID" FOREIGN KEY ("USERID") REFERENCES "USERS" ("ID") / Mapping the Users table in Hibernate works ok <hibernate-mapping package="com.initech.domain"> <class name="com.initech.User" table="USERS"> <id name="id" column="ID" type="java.lang.Long"> <meta attribute="use-in-tostring">true</meta> <generator class="sequence"> <param name="sequence">SEQ_USERS_ID</param> </generator> </id> <property name="loginName" column="LOGINNAME" type="java.lang.String" not-null="true"> <meta attribute="use-in-tostring">true</meta> </property> </class> </hibernate-mapping> But I'm struggling in creating the mapping for the SpecialUsers table. All the examples (e.g. in Hibernate documentation) in Internet I found don't have this type of self-reference. I tried a mapping like this: <hibernate-mapping package="com.initech.domain"> <class name="com.initech.User" table="SPECIALUSERS"> <id name="id" column="USERID"> <meta attribute="use-in-tostring">true</meta> <generator class="foreign"> <param name="property">user</param> </generator> </id> <one-to-one name="user" class="User"/> </class> </hibernate-mapping> but got the error Invocation of init method failed; nested exception is org.hibernate.DuplicateMappingException: Duplicate class/entity mapping com.initech.User How should I map the SpecialUsers table? What I need on the application level is a list of the User objects contained in the SpecialUsers table.

    Read the article

  • Entity Framework v4 examples and tutorials of conceptual model mapping

    - by Rody van Sambeek
    In an application I'm writing I have a fairly complicated Database model. I'd like to use EF4 to map this to a whole lot nicer conceptual model. However all the tutorials I've read are with samples of 2 or 3 tables which all map 1 on 1 to the conceptual model. I'd like to learn how to correctly map the database model to a different conceptual model using VS 2010. However I can't find any good tutorials or (preferabally) instruction video's. Somebody got any tips, links or even books?

    Read the article

  • How to make an entity out of a join table without primary key

    - by tputkonen
    I'm trying to generate JPA entities out of an existing database having an "interesting" design. Database has a table called UserSet, which can have links to several other UserSets. There is a one to many relation between UserSets and LinkedUserSets. LinkedUserSets also has one to one relation to UserSets. I tried to generate a JPA Entity out of the database structure using Dali JPA Tools. The resulting entity Linkeduserset misses @Id or @EmbeddedId annotation and thus failes to compile. As the resulting entity contains only two @JoinColumns (which cannot be marked as @Id), I have not so far found a way around this issue. Database structure can not be modified in any way. Is there a way to overcome this somehow? Relevant pars of create table statements: CREATE TABLE `LinkedUserSets` ( `UsrSetID` INT(11) NOT NULL DEFAULT '0' , `ChildID` INT(11) NOT NULL DEFAULT '0' , CONSTRAINT `fk_LinkedUserSets_UserSet1` FOREIGN KEY (`UsrSetID` ) REFERENCES `UserSet` (`UsrSetID` )); CREATE TABLE `UserSet` ( `UsrSetID` INT(11) NOT NULL AUTO_INCREMENT , PRIMARY KEY (`UsrSetID`), CONSTRAINT `fk_UserSet_LinkedUserSets1` FOREIGN KEY (`UsrSetID` ) REFERENCES `LinkedUserSets` (`ChildID` )); Generated entities: @Entity @Table(name="linkedusersets") public class Linkeduserset { //bi-directional many-to-one association to Userset @ManyToOne @JoinColumn(name="UsrSetID") private Userset userset1; //bi-directional one-to-one association to Userset @OneToOne @JoinColumn(name="ChildID") private Userset userset2; } @Entity @Table(name="userset") public class Userset { private static final long serialVersionUID = 1L; @Id @Column(name="UsrSetID") private int jngSetID; //bi-directional many-to-one association to Linkeduserset @OneToMany(mappedBy="userset1") private Set<Linkeduserset> linkedusersets; //bi-directional one-to-one association to Linkeduserset @OneToOne(mappedBy="userset2") private Linkeduserset linkeduserset; } Error message: Entity "Linkeduserset" has no Id or EmbeddedId

    Read the article

  • Hibernate HQL with interfaces

    - by Benju
    According to this section of the Hibernate documentation I should be able to query any java class in HQL http://docs.jboss.org/hibernate/core/3.3/reference/en/html/queryhql.html#queryhql-polymorphism Unfortunately when I run this query... "from Transaction trans where trans.envelopeId=:envelopeId" I get the message "Transaction is not mapped [from Transaction trans where trans.envelopeId=:envelopeId]". Transaction is an interface, I have to entity classes that implement it, I want on HQL query to return a Collection of type Transaction.

    Read the article

  • Help choose a code generation tools for ASP.NET

    - by Kintaro
    Hello, I am new to the code generation tools and I would like to know how does a tool like LLBGen Pro compares with the Entity Framework? On top of that my boos is really looking into a tool called CodeOnTime http://codeontime.com/default.aspx because he likes their good UI support. I am asking here because I really want an unbiased opinion. I am not sure if LLBGen can also generate the UI. So far all the development in the house we do it the classic way coding each layer manually. However we are in need of a fast prototyping tool. Any advice to help me choose wisely will be much appreciated thanks in advance.

    Read the article

  • Load vs Get in Nhibernate

    - by Quintin Par
    The master page in my web application does authentication and loads up the user entity using a Get. After this whenever the user object is needed by the usercontrols or any other class I do a Load. Normally nhibernate is supposed to load the object from cache or return the persistent loaded object whenever Load of called. But this is not the behavior shown by my web application. NHprof always shows the sql whenever Load is called. How do I verify the correct behavior of Load? I use the S#arp architecture framework.

    Read the article

  • How to use Linq with Castle ActiveRecord

    - by Ronnie Overby
    I am playing around with Castle ActiveRecord and noticed that the download included the file, Castle.ActiveRecord.Linq.dll. I haven't found any documentation for using Linq with ActiveRecord, only some old blog posts. What is the usage pattern? Is Castle.ActiveRecord.Linq ready for production use? I'm using reflector, pending an answer.

    Read the article

  • How to detect open database connection with Hibernate / JPA?

    - by John K
    I am learning JPA w/Hibernate using a Java SE 6 project. I'd simply like to be able to detect if the connection between Hibernate and my database (MS SQL Server) is open. For example, I'd like to be able to detect this, log it, and try reconnecting again in 60 seconds. This is what I thought would work but isOpen() doesn't appear to be what I want (always is true): EntityManagerFactory emf = Persistence.createEntityManagerFactory("rcc", props); if (emf != null && emf.isOpen()) { EntityManager em = emf.createEntityManager(); if (em == null || !emf.isOpen()) // error connecting to database else ... This seems to me to be a simple problem, but I cannot find an answer!

    Read the article

  • Having an issue with org.hibernate.SessionException: Session is closed! in Hibernate

    - by hal10001
    I've done quite a bit a research on this with no luck, but all the answers have a tendency to point toward the session context settings in the config file. What is odd is that I get a session connection the very first time I hit the page (and therefore, a successful result set), but then when I reload I get the following exception: org.hibernate.SessionException: Session is closed! Here are my config settings that are not DB connection string related: <property name="hibernate.show_sql">false</property> <property name="hibernate.dialect">org.hibernate.dialect.SQLServerDialect</property> <property name="hibernate.current_session_context_class">thread</property> <property name="hibernate.cache.provider_class">org.hibernate.cache.NoCacheProvider</property> <property name="hibernate.cache.use_query_cache">false</property> <property name="hibernate.cache.use_minimal_puts">false</property> Here is an example of a call I make that produces the situation I described above. public T get(int id) { session.beginTransaction(); T type; try { type = getTypeClass().cast(session.get(getTypeClass(), id)); } catch (ClassCastException classCastException) { throw new ClassCastException(classCastException.getMessage()); } session.getTransaction().commit(); return type; } The session variable reference is to a static field that contains the current session. All of the session connection details are textbook reference manual. For example, here is my Hibernate session utility: import org.hibernate.SessionFactory; import org.hibernate.cfg.Configuration; public class HibernateSessionFactoryUtil { private static final SessionFactory sessionFactory = buildSessionFactory(); private static SessionFactory buildSessionFactory() { try { return new Configuration().configure().buildSessionFactory(); } catch (Throwable ex) { System.err.println("Initial SessionFactory creation failed." + ex); throw new ExceptionInInitializerError(ex); } } public static SessionFactory getSessionFactory() { return sessionFactory; } }

    Read the article

  • How to generate Doctrine models/classes that extend a custom record class

    - by Shane O'Grady
    When I use Doctrine to generate classes from Yaml/db each Base class (which includes the table definition) extends the Doctrine_Record class. Since my app uses a master and (multiple) slave db servers I need to be able to make the Base classes extend my custom record class to force writes to go to the master db server (as described here). However if I change the base class manually I lose it again when I regenerate my classes from Yaml/db using Doctrine. I need to find a way of telling Doctrine to extend my own Base class, or find a different solution to a master/slave db setup using Doctrine. Example generated model: abstract class My_Base_User extends Doctrine_Record { However I need it to be automatically generated as: abstract class My_Base_User extends My_Record { I am using Doctrine 1.2.1 in a new Zend Framework 1.9.6 application if it makes any difference.

    Read the article

  • Updatable false behvior incosistent

    - by jpanewbie
    I need LastUpdatedDttm to be updated by SYSDATE whenever record is updated. But below annoataions do nt work as desired. SYSDATE is inserted only once and not updated for subsequent updations. Also, lastUpdDTTM is not part of sql generated by hibernate. @Generated(GenerationTime.ALWAYS) @Column(name="LAST_UPDATED_DTTM",insertable=false,updatable=true, columnDefinition ="timestamp default SYSDATE") private Date lastUpdDTTM; @Generated(GenerationTime.ALWAYS) @Column(name="CREATED_DTTM", insertable=false, updatable=false) private Date createdDTTM;

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 13 14 15 16 17 18 19 20 21 22 23 24  | Next Page >