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  • hibernate or eclipselink?

    - by opensas
    It seems like EclipseLink has been chosen by sun as the reference implementation of JPA 2.0, nevertheless I see lots of people continue to use hibernate... I have no experience with none of them, so I wonder which one should I choose for a new project... I'd like to know the pros / cons of each one... thanks a lot ps: btw, and this is part of the answer, there are 3636 questions on stackoverflow about hibernate, and only 68 about eclipselink...

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  • Tricky model inheritance - Django

    - by RadiantHex
    Hi folks, I think this is a bit tricky, at least for me. :) So I have 4 models Person, Singer, Bassist and Ninja. Singer, Bassist and Ninja inherit from Person. The problem is that each Person can be any of its subclasses. e.g. A person can be a Singer and a Ninja. Another Person can be a Bassist and a Ninja. Another one can be all three. How should I organise my models? Help would be much appreciated!

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  • Kohana v3 ACL A2 with database support

    - by Asif
    Hi, I am using Kohana V 3.0.3. I was looking for ACL library and found from http://dev.kohanaphp.com/projects A2 Kohana's ACL module. Apparently it's found that, it manages Roles,Resources and Rules using config file and authenticate object basis. I want it to be dynamic, like Resources and Rules should be loaded from database dynamically if valid user logs in. Auth part is done now looking for ACL part. Is it possible to use same A2 module with database or need to rewrite own logic?

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  • Storing Objects in columns using Hibernate JPA

    - by user210791
    Is it possible to store something like the following using only one table? Right now, what hibernate will do is create two tables, one for Families and one for people. I would like for the familymembers object to be serialized into the column in the database. @Entity(name = "family") class Family{ private final List<Person> familyMembers; } class Person{ String firstName, lastName; int age; }

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  • Mapping parent-child relationships with iBatis

    - by agnul
    I have the classic setup public class Parent { Integer id; ... // No generics Collection someCollectionAttribute; ... public void setChildren(Collection c) { ... } } public class Child { Integer id; ... } and I'm trying to map this on the usual table setup using iBatis (version 2.30... don't ask). create table parents ( ID integer primary key ... ) create table children ( ID integer primary key PARENT_ID integer references parents(id) ... ) My mapping file looks like this <resultMap id="ParentResult" groupBy="id"> <result property="id" column="ID" /> ... <result property="children" resultMap="ChildResult" /> </resultMap> <resultMap id="ChildResult"> <result property="id" column="ID" /> <result property="parentId" column="PARENT_ID" /> ... </result> <sql id="loadParent" resultMap="ParentResult"> select P.ID as p1, ..., C.ID as c1, C.PARENT_ID as c2 ... from parents P join children C on (P.ID = C.PARENT_ID) where P.ID = #id# order by P.ID </sql> Doing the usual sqlMap.queryForObject("loadParent", new Integer(42)) at first caused a NullPointerException inside the setChildren setter which apparently is called with a null argument (my bad). Fixing the setter everything works fine, but the logs show that setChildren is called only once before even running a single SQL statement, still with a null argument, so I'm wondering what's going on here. Anyone has any clues?

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  • With Eclipselink/JPA, can I have a Foreign Composite Key that shares a field with a Primary Composit

    - by user107924
    My database has two entities; Company and Person. A Company can have many People, but a Person must have only one Company. The table structure looks as follows. COMPANY ---------- owner PK comp_id PK c_name PERSON ---------------- owner PK, FK1 personid PK comp_id FK1 p_fname p_sname It has occurred to me that I could remove PERSON.OWNER and derive it through the foreign key; however, I can't make this change without affecting legacy code. I have modeled these as JPA-annotated classes; @Entity @Table(name = "PERSON") @IdClass(PersonPK.class) public class Person implements Serializable { @Id private String owner; @Id private String personid; @ManyToOne @JoinColumns( {@JoinColumn(name = "owner", referencedColumnName = "OWNER", insertable = false, updatable = false), @JoinColumn(name = "comp_id", referencedColumnName = "COMP_ID", insertable = true, updatable = true)}) private Company company; private String p_fname; private String p_sname; ...and standard getters/setters... } @Entity @Table(name = "COMPANY") @IdClass(CompanyPK.class) public class Company implements Serializable { @Id private String owner; @Id private String comp_id; private String c_name; @OneToMany(mappedBy = "company", cascade=CascadeType.ALL) private List people; ...and standard getters/setters... } My PersonPK and CompanyPK classes are nothing special, they just serve as a struct holding owner and the ID field, and override hashCode and equals(o). So far so good. I come across a problem, however, when trying to deal with associations. It seems if I have an existing Company, and create a Person, and associate to the Person to the Company and persist the company, the association is not saved when the Person is inserted. For example, my main code looks like this: EntityManager em = emf.createEntityManager(); em.getTransaction().begin(); CompanyPK companyPK = new CompanyPK(); companyPK.owner="USA"; companyPK.comp_id="1102F3"; Company company = em.find(Company.class, companyPK); Person person = new Person(); person.setOwner("USA"); person.setPersonid("5116628123"); //some number that doesn't exist yet person.setP_fname("Hannah"); person.setP_sname("Montana"); person.setCompany(company); em.persist(person); This completes without error; however in the database I find that the Person record was inserted with a null in the COMP_ID field. With EclipseLink debug logging set to FINE, the SQL query is shown as: INSERT INTO PERSON (PERSONID,OWNER,P_SNAME,P_FNAME) VALUES (?,?,?,?) bind = [5116628123,USA,Montana,Hannah,] I would have expected this to be saved, and the query to be equivalent to INSERT INTO PERSON (PERSONID,OWNER,COMP_ID,P_SNAME,P_FNAME) VALUES (?,?,?,?,?) bind = [5116628123,USA,1102F3,Montana,Hannah,] What gives? Is it incorrect to say updatable/insertable=true for one half of a composite key and =false for the other half? If I have updatable/insertable=true for both parts of the foreign key, then Eclipselink fails to startup saying that I can not use the column twice without having one set to readonly by specifying these options.

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  • JPA merge fails due to duplicate key

    - by wobblycogs
    I have a simple entity, Code, that I need to persist to a MySQL database. public class Code implements Serializable { @Id private String key; private String description; ...getters and setters... } The user supplies a file full of key, description pairs which I read, convert to Code objects and then insert in a single transaction using em.merge(code). The file will generally have duplicate entries which I deal with by first adding them to a map keyed on the key field as I read them in. A problem arises though when keys differ only by case (for example: XYZ and XyZ). My map will, of course, contain both entries but during the merge process MySQL sees the two keys as being the same and the call to merge fails with a MySQLIntegrityConstraintViolationException. I could easily fix this by uppercasing the keys as I read them in but I'd like to understand exactly what is going wrong. The conclusion I have come to is that JPA considers XYZ and XyZ to be different keys but MySQL considers them to be the same. As such when JPA checks its list of known keys (or does whatever it does to determine whether it needs to perform an insert or update) it fails to find the previous insert and issuing another which then fails. Is this corrent? Is there anyway round this other than better filtering the client data? I haven't defined .equals or .hashCode on the Code class so perhaps this is the problem.

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  • CF9 HQL Statement for many-to-many and Multiple Criteria

    - by Jeremy Battle
    I have the following setup: Listing.cfc component persistent="true" { property name="ListingId" column="ListingId" type="numeric" ormtype="int" fieldtype="id" generator="identity"; ... property name="Features" type="array" hint="Array of features" singularname="Feature" fieldtype="many-to-many" cfc="Feature" linktable="Listing_Feature" FKColumn="ListingId" inversejoincolumn="FeatureId"; } Feature.cfc component persistent="true" table="Feature" schema="dbo" output="false" { property name="FeatureId" column="FeatureId" type="numeric" ormtype="int" fieldtype="id" generator="identity"; property name="FeatureDescription" column="FeatureDescription" type="string" ormtype="string"; ... /*property name="Listings" fieldtype="many-to-many" cfc="Listing" linktable="Listing_Feature" fkcolumn="FeatureId" inversejoincolumn="ListingId" lazy="true" cascade="all" orderby="GroupOrder";*/ } I can select all listings that have a particular feature using: <cfset matchingListings = ormExecuteQuery("from Listing l left join l.Features as feature where feature.FeatureId = :feature",{feature = 110}) /> Which is fine, however, I'd like to be able to select all listings that have multiple features (for example a listing that has both "Dishwasher" AND "Garage") After a couple hours of googling and looking through hibernate documentation haven't been able to find a solution that won't give me an error. My guess is that the solution is pretty simple and I am just over-thinking it...anyone have any suggestions?

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  • Doctrine Problem: Couldn't get last insert identifier.

    - by cnkt
    When i try to save data to my model Doctrine throws this exception: Message: Couldn't get last insert identifier. My table setup code is: $this->hasColumn('id', 'integer', 4, array( 'type' => 'integer', 'length' => 4, 'fixed' => false, 'unsigned' => false, 'primary' => true, 'autoincrement' => true, )); Please help. Thanks.

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  • ORA-22835 using JPA (Buffer too small)

    - by Kenneth
    I am trying to persist an Entity with a @Lob annotated String field. The content of that fiels if bigger than the 40k buffer size limit. The first problem I had was related to the setString method used internally by the JPA implementation (Hibernate in my case) and the Oracle JDBC Driver. This problem was solved adding <property name="hibernate.connection.SetBigStringTryClob" value="true"/> to my persistence.xml file. Then, the error changed to a ORA-22835 error (the buffer is too small). ¿Is there any way that JPA solves this problem without going to a low-level implementation? ¿Any suggestions?

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  • Java type for date/time when using Oracle Date with Hibernate

    - by Marcus
    We have a Oracle Date column. At first in our Java/Hibernate class we were using java.sql.Date. This worked but it didn't seem to store any time information in the database when we save so I changed the Java data type to Timestamp. Now we get this error: springframework.beans.factory.BeanCreationException: Error creating bean with name 'org.springframework.dao.an notation.PersistenceExceptionTranslationPostProcessor#0' defined in class path resource [margin-service-domain -config.xml]: Initialization of bean failed; nested exception is org.springframework.beans.factory.BeanCreatio nException: Error creating bean with name 'sessionFactory' defined in class path resource [m-service-doma in-config.xml]: Invocation of init method failed; nested exception is org.hibernate.HibernateException: Wrong column type: CREATE_TS, expected: timestamp Any ideas on how to map an Oracle Date while retaining the time portion? Update: I can get it to work if I use the Oracle Timestamp data type but I don't want that level of precision ideally. Just want the basic Oracle Date.

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  • JPA ManyToMany referencing issue

    - by dharga
    I have three tables. AvailableOptions and PlanTypeRef with a ManyToMany association table called AvailOptionPlanTypeAssoc. The trimmed down schemas look like this CREATE TABLE [dbo].[AvailableOptions]( [SourceApplication] [char](8) NOT NULL, [OptionId] [int] IDENTITY(1,1) NOT NULL, ... ) CREATE TABLE [dbo].[AvailOptionPlanTypeAssoc]( [SourceApplication] [char](8) NOT NULL, [OptionId] [int] NOT NULL, [PlanTypeCd] [char](2) NOT NULL, ) CREATE TABLE [dbo].[PlanTypeRef]( [PlanTypeCd] [char](2) NOT NULL, [PlanTypeDesc] [varchar](32) NOT NULL, ) And the Java code looks like this. //AvailableOption.java @ManyToMany(cascade={CascadeType.ALL}, fetch=FetchType.EAGER) @JoinTable( name = "AvailOptionPlanTypeAssoc", joinColumns = { @JoinColumn(name = "OptionId"), @JoinColumn(name="SourceApplication")}, inverseJoinColumns=@JoinColumn(name="PlanTypeCd")) List<PlanType> planTypes = new ArrayList<PlanType>(); //PlanType.java @ManyToMany @JoinTable( name = "AvailOptionPlanTypeAssoc", joinColumns = { @JoinColumn(name = "PlanTypeCd")}, inverseJoinColumns={@JoinColumn(name="OptionId"), @JoinColumn(name="SourceApplication")}) List<AvailableOption> options = new ArrayList<AvailableOption>(); The problem arises when making a select on AvailableOptions it joins back onto itself. Note the following SQL code from the backtrace. The second inner join should be on PlanTypeRef. SELECT t0.OptionId, t0.SourceApplication, t2.PlanTypeCd, t2.EffectiveDate, t2.PlanTypeDesc, t2.SysLstTrxDtm, t2.SysLstUpdtUserId, t2.TermDate FROM dbo.AvailableOptions t0 INNER JOIN dbo.AvailOptionPlanTypeAssoc t1 ON t0.OptionId = t1.OptionId AND t0.SourceApplication = t1.SourceApplication INNER JOIN dbo.AvailableOptions t2 ON t1.PlanTypeCd = t2.PlanTypeCd WHERE (t0.SourceApplication = ? AND t0.OptionType = ?) ORDER BY t0.OptionId ASC, t0.SourceApplication ASC [params=(String) testApp, (String) junit0]}

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  • Map enum in JPA with fixed values ?

    - by Kartoch
    I'm looking for the different ways to map an enum using JPA. I especially want to set the integer value of each enum entry and to save only the integer value. @Entity @Table(name = "AUTHORITY_") public class Authority implements Serializable { public enum Right { READ(100), WRITE(200), EDITOR (300); private int value; Right(int value) { this.value = value; } public int getValue() { return value; } }; @Id @GeneratedValue(strategy = GenerationType.AUTO) @Column(name = "AUTHORITY_ID") private Long id; // the enum to map : private Right right; } A simple solution is to use the Enumerated annotation with EnumType.ORDINAL: @Column(name = "RIGHT") @Enumerated(EnumType.ORDINAL) private Right right; But in this case JPA maps the enum index (0,1,2) and not the value I want (100,200,300). Th two solutions I found do not seem simple... First Solution A solution, proposed here, uses @PrePersist and @PostLoad to convert the enum to an other field and mark the enum field as transient: @Basic private int intValueForAnEnum; @PrePersist void populateDBFields() { intValueForAnEnum = right.getValue(); } @PostLoad void populateTransientFields() { right = Right.valueOf(intValueForAnEnum); } Second Solution The second solution proposed here proposed a generic conversion object, but still seems heavy and hibernate-oriented (@Type doesn't seem to exist in JEE): @Type( type = "org.appfuse.tutorial.commons.hibernate.GenericEnumUserType", parameters = { @Parameter( name = "enumClass", value = "Authority$Right"), @Parameter( name = "identifierMethod", value = "toInt"), @Parameter( name = "valueOfMethod", value = "fromInt") } ) Is there any other solutions ? I've several ideas in mind but I don't know if they exist in JPA: use the setter and getter methods of right member of Authority Class when loading and saving the Authority object an equivalent idea would be to tell JPA what are the methods of Right enum to convert enum to int and int to enum Because I'm using Spring, is there any way to tell JPA to use a specific converter (RightEditor) ?

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  • Hibernate - query caching/second level cache does not work by value object containing subitems

    - by Zoltan Hamori
    Hi! I have been struggling with the following problem: I have a value object containing different panels. Each panel has a list of fields. Mapping: <class name="com.aviseurope.core.application.RACountryPanels" table="CTRY" schema="DBDEV1A" where="PEARL_CTRY='Y'" lazy="join"> <cache usage="read-only"/> <id name="ctryCode"> <column name="CTRY_CD_ID" sql-type="VARCHAR2(2)" not-null="true"/> </id> <bag name="panelPE" table="RA_COUNTRY_MAPPING" fetch="join" where="MANDATORY_FLAG!='N'"> <key column="COUNTRY_LOCATION_ID"/> <many-to-many class="com.aviseurope.core.application.RAFieldVO" column="RA_FIELD_MID" where="PANEL_ID='PE'"/> </bag> </class> I use the following criteria to get the value object: Session m_Session = HibernateUtil.currentSession(); m_Criteria = m_Session.createCriteria(RACountryPanels.class); m_Criteria.add(Expression.eq("ctryCode", p_Country)); m_Criteria.setCacheable(true); As I see the query cache contains only the main select like select * from CTRY where ctry_cd_id=? Both RACountryPanels and RAFieldVO are second level cached. If I check the 2nd level cache content I can see that it cointains the RAFields and the RACountryPanels as well and I can see the select .. from CTRY where ctry_cd_id=... in query cache region as well. When I call the servlet it seems that it is using the cache, but second time not. If I check the content of the cache using JMX, everything seems to be ok, but when I measure the object access time, it seems that it does not always use the cache. Cheers Zoltan

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  • What's best practice to check if an object is part of a ManyToMany relationship in Django

    - by PhilGo20
    from an instance of Site with a ManyToMany relationship to Kiosk, i'd like to check if a Kiosk object is part of the relationship. I could do self.apps.get(id=app_id).exists() and check if True or self.apps.get(id=app_id) and catch the ObjectDoesNotExist error or self.apps.filter(id=app_id) and check if True If I have to catch a possible ObjectDoesNotExist error, I may as well use the second one I can do the second but doesnt seem super clean can use the third one but using filter on a unique ID seems wrong to me You can tell me to use whatever works and that'll be a valid answer ;-)

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  • When is lazy evaluation not useful?

    - by Cherian
    Delay execution is almost always a boon. But then there are cases when it’s a problem and you resort to “fetch” (in Nhibernate) to eager fetch it. Do you know practical situations when lazy evaluation can bite you back…?

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  • Embed a Python persistance layer into a C++ application - good idea?

    - by Rickard
    say I'm about to write an application with a thin GUI layer, a really fat calculation layer (doing computationally heavy calibrations and other long-running stuff) and fairly simple persistance layer. I'm looking at building the GUI + calculation layer in C++ (using Qt for the gui parts). Now - would it be a crazy idea to build the persistance layer in Python, using sqlalchemy, and embed it into the C++ application, letting the layers interface with eachother through lightweigth data transfer objects (written in C++ but accessible from python)? (the other alternative I'm leaning towards would probably be to write the app in Python from the start, using the PyQt wrapper, and then calling into C++ for the computational tasks) Thanks, Rickard

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  • JPA Cascade delete.

    - by Win Man
    Hi, I am new to JPA/Hibernate. Currently using EJB3, Hibernate/JPA. I have an inheritacnce structure as follows.. @Entity @DiscriminatorColumn(name = "form_type") @Inheritance(strategy = InheritanceType.JOINED) @GenericGenerator(name = "FORMS_SEQ", strategy = "sequence-identity", parameters = @Parameter(name = "sequence", value = "FORMS_SEQ")) @Table(name = "Forms") public abstract class Form{ //code for Form } @Entity @Table(name = "CREDIT_CARDS") @PrimaryKeyJoinColumn(name="CREDIT_CARD_ID") public class CreditCardForm extends Form { //Code for CreditCards. } When I add a row with save the rows are properly inserted into the parent and the child table. However when I try to delete I get an error - 10:19:35,465 ERROR [TxPolicy] javax.ejb.EJBTransactionRolledbackException: Removing a detached instance com.data.entities.form.financial.CreditCard#159? I am using a simple for loop to determine the inheritance type - CreditCard or DebitCard and then calling entityManager.remove(entity). What am I doing wrong? Code for delete.. for(Form content: contents){ if(content.getType()==Type.CREDIT_CARD){ creditCardService.delete((CreditCard)content); } Thanks. WM

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  • Django queries: Count number of objects with FK to model instance

    - by Chris Lawlor
    This should be easy but for some reason I'm having trouble finding it. I have the following: App(models.Model): ... Release(models.Model): date = models.DateTimeField() App = models.ForeignKey(App) ... How can I query for all App objects that have at least one Release? I started typing: App.objects.all().annotate(release_count=Count('??????')).filter(release_count__gt=0) Which won't work because Count doesn't span relationships, at least as far as I can tell. BONUS: Ultimately, I'd also like to be able to sort Apps by latest release date. I'm thinking of caching the latest release date in the app to make this a little easier (and cheaper), and updating it in the Release model's save method, unless of course there is a better way. Edit: I'm using Django 1.1 - not averse to migrating to dev in anticipation of 1.2 if there is a compelling reason though.

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  • error : java.lang.String cannot be cast to coldfusion.cfc.CFCBeanProxy anyone know about this ?

    - by faheem
    Hi does anyone know about this error I get when I try to insert a foreign key value in my entry entity using cf9 Hibernate ? java.lang.ClassCastException: java.lang.String cannot be cast to coldfusion.cfc.CFCBeanProxy Root cause :org.hibernate.HibernateException: java.lang.ClassCastException: java.lang.String cannot be cast to coldfusion.cfc.CFCBeanProxy Below is the code for my entity object and then for my user object.. Is there anything wrong with this ? entry.cfc /** * Entries Object */ component output="false" persistent="true"{ property name="entry_id" fieldType="id" generator="uuid"; property name="entryBody" ormType="text"; property name="title" notnull="true" type="string"; property name="time" fieldtype="timestamp"; property name="isCompleted" ormType="boolean" dbdefault="0" default="false"; property name="userID" fieldtype="many-to-one" fkcolumn="userID" cfc="user"; Entry function init() output=false{ return this; } } user.cfc /** * Users Object */ component output="false" persistent="true"{ property name="userID" fieldType="id" generator="uuid"; property name="firstName" notnull="true" type="string"; property name="lastName" notnull="true" type="string"; property name="password" notnull="true" type="string"; property name="userType" notnull="true" type="string"; //property name="entry" fieldtype="one-to-many" type="array" fkcolumn="userID" cfc="entry"; User function init() output=false{ return this; } }

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  • SqlMetal, Sql Server 2008 database, Table with HierachyID, dal cs file is created sometimes ?

    - by judek.mp
    I have 2 databases with a 2 tables with HierachyID fields. For one database I can get a dal cs file, for the other database I cannot get a dal cs file ? HBus is a database I can get the dal cs for, ... SqlMetal /server:.\SQLSERVER2008 /database:HBus /code:HBusDC.cs /views /functions /sprocs /namespace:HBusDC /context:HBusDataContext This kicks me out a file, ... which works, but excludes the HierarchyID field for the table and includes all other fields for that table. This is OK I do not mind. The above cmd line kicks out an warning but still produces a file, like so SqlMetal /server:.\SQLSERVER2008 /database:HBus /code:HBusDC.cs /views /functions /sprocs /namespace:HBusDC /context:HBusDataContext Microsoft (R) Database Mapping Generator 2008 version 1.00.30729 for Microsoft (R) .NET Framework version 3.5 Copyright (C) Microsoft Corporation. All rights reserved. Warning : SQM1021: Unable to extract column 'OrgNode' of Table 'dbo.HMsg' from SqlServer because the column's DbType is a user-defined type (UDT). Warning : SQM1021: Unable to extract column 'OrgNode' of Table 'dbo.vwHMsg' from SqlServer because the column's DbType is a user-defined type (UDT). HMsg is a table with a HierarchyID field. I have another database, Elf, almost the same thing but I get a warning and an Error when using sql metal and I do not get a dal cs file ... SqlMetal /server:.\SQLSERVER2008 /database:Elf /code:ElfDataContextDal.cs /views /functions /sprocs /namespace:HBusDC /context:HBusDataContext An error as well as the warning and the cs file fails to appear on my disc, ... :-( SqlMetal /server:.\SQLSERVER2008 /database:Elf /code:ElfDataContextDal.cs /views /functions /sprocs /namespace:HBusDC /context:HBusDataContext Microsoft (R) Database Mapping Generator 2008 version 1.00.30729 for Microsoft (R) .NET Framework version 3.5 Copyright (C) Microsoft Corporation. All rights reserved. Warning : SQM1021: Unable to extract column 'OrgNode' of Table 'dbo.EntityLink' from SqlServer because the column's DbType is a user-defined type (UDT). Error : Requested value 'ELF.SYS.HIERARCHYID' was not found. The fields are declared the same way in Elf db OrgNode [HierarchyID] null , in HBus db ... OrgNode [HierarchyID] null , Both databases are in the same instance of sql server 2008, so the HierarchyID is an inbuilt type, neither db has HierarchyID udt ,... cheers in advance for any replies ...

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