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  • Is a JOIN more/less efficient than EXISTS IN when no data is needed from the second table?

    - by twpc
    I need to look up all households with orders. I don't care about the data of the order at all, just that it exists. Is it more efficient to say something like this: SELECT HouseholdID, LastName, FirstName, Phone FROM Households INNER JOIN Orders ON Orders.HouseholdID = Households.HouseholdID or this: SELECT HouseholdID, LastName, FirstName, Phone FROM Households WHERE EXISTS (SELECT HouseholdID FROM Orders WHERE Orders.HouseholdID = Households.HouseholdID)

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  • methods of joining 2 tables without using JOIN or SELECT more than one distinct table in the query

    - by GB_J
    Is there a way of joining results from 2 tables without using JOIN or SELECT from more than one table? The reason being the database im working with requires queries that only contain SELECT, FROM, and WHERE clauses containing only one distinct table. I do, however, need information from other tables for the project i'm working on. More info: the querier returns the query results in a .csv format, is there something we can manipulate there?

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  • Find min. "join" operations for sequence

    - by utyle
    Let's say, we have a list/an array of positive integers x1, x2, ... , xn. We can do a join operation on this sequence, that means that we can replace two elements that are next to each other with one element, which is sum of these elements. For example: - array/list: [1;2;3;4;5;6] we can join 2 and 3, and replace them with 5; we can join 5 and 6, and replace them with 11; we cannot join 2 and 4; we cannot join 1 and 3 etc. Main problem is to find minimum join operations for given sequence, after which this sequence will be sorted in increasing order. Note: empty and one-element sequences are sorted in increasing order. Basic examples: for [4; 6; 5; 3; 9] solution is 1 (we join 5 and 3) for [1; 3; 6; 5] solution is also 1 (we join 6 and 5) What I am looking for, is an algorithm that solve this problem. It could be in pseudocode, C, C++, PHP, OCaml or similar (I mean: I woluld understand solution, if You wrote solution in one of these languages). I would appreciate Your help.

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  • SQL SERVER Subquery or Join Various Options SQL Server Engine Knows the Best Part 2

    This blog post is part 2 of the earlier written article SQL SERVER Subquery or Join Various Options SQL Server Engine knows the Best by Paulo R. Pereira. Paulo has left excellent comment to earlier article once again proving the point that SQL Server Engine is smart enough to figure out the [...]...Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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  • How to join two collections with LINQ

    - by JustinGreenwood
    Here is a simple and complete example of how to perform joins on two collections with LINQ. I wrote it for a friend to show him, in one simple file, the power of LINQ queries and anonymous objects. In the file below, there are two simple data classes defined: Person and Item. In the beginning of the main method, two collections are created. Note that the Item's OwnerId field reference the PersonId of a Person object. The effect of the LINQ query below is equivalent to a SQL statement looking like this: select Person.PersonName as OwnerName, Item.ItemName as OwnedItem from Person inner join Item on Item.OwnerId = Person.PersonId order by Item.ItemName desc; using System; using System.Collections.Generic; using System.Linq; namespace LinqJoinAnonymousObjects { class Program { class Person { public int PersonId { get; set; } public string PersonName { get; set; } } class Item { public string ItemName { get; set; } public int OwnerId { get; set; } } static void Main(string[] args) { // Create two collections: one of people, and another with their possessions. var people = new List<Person> { new Person { PersonId=1, PersonName="Justin" }, new Person { PersonId=2, PersonName="Arthur" }, new Person { PersonId=3, PersonName="Bob" } }; var items = new List<Item> { new Item { OwnerId=1, ItemName="Armor" }, new Item { OwnerId=1, ItemName="Book" }, new Item { OwnerId=2, ItemName="Chain Mail" }, new Item { OwnerId=2, ItemName="Excalibur" }, new Item { OwnerId=3, ItemName="Bubbles" }, new Item { OwnerId=3, ItemName="Gold" } }; // Create a new, anonymous composite result for person id=2. var compositeResult = from p in people join i in items on p.PersonId equals i.OwnerId where p.PersonId == 2 orderby i.ItemName descending select new { OwnerName = p.PersonName, OwnedItem = i.ItemName }; // The query doesn't evaluate until you iterate through the query or convert it to a list Console.WriteLine("[" + compositeResult.GetType().Name + "]"); // Convert to a list and loop through it. var compositeList = compositeResult.ToList(); Console.WriteLine("[" + compositeList.GetType().Name + "]"); foreach (var o in compositeList) { Console.WriteLine("\t[" + o.GetType().Name + "] " + o.OwnerName + " - " + o.OwnedItem); } Console.ReadKey(); } } } The output of the program is below: [WhereSelectEnumerableIterator`2] [List`1] [<>f__AnonymousType1`2] Arthur - Excalibur [<>f__AnonymousType1`2] Arthur - Chain Mail

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  • Looking for 2 SQL Contractors to join my team in North London

    - by simonsabin
    I am looking for 2 SQL Contractors to join my data team to help build our database platform. The role is for a SQL generalist. The person will be doing TSQL, SSIS, SSRS and maybe some SSAS. Experience of agile development processes would be great. This is a great opportunity to work in a great team. If you are interested them please let me know. http://sqlblogcasts.com/blogs/simons/contact.aspx...(read more)

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  • How to join two command output

    - by UAdapter
    for example I have command that shows how much space folder takes du folder | sort -n it works great, however I would like to have human readable form du -h folder however if I do that than I cannot sort it as numeric. How to join "du folder" and "du -h folder" to see output sorted as "du folder", but with first column from "du -h folder" P.S. this is just an example. this technique might be very useful for me (if its possible)

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  • When calling CRUD check if "parent" exists with read or join?

    - by Trick
    All my entities can not be deleted - only deactivated, so they don't appear in any read methods (SELECT ... WHERE active=TRUE). Now I have some 1:M tables on this entities on which all CRUD operations can be executed. What is more efficient or has better performance? My first solution: To add to all CRUD operations: UPDATE ... JOIN entity e ... WHERE e.active=TRUE My second solution: Before all CRUD operations check if entity is active: if (getEntity(someId) != null) { //do some CRUD } In getEntity there's just SELECT * FROM entity WHERE id=? AND active=TRUE. Or any other solution, recommendation,...?

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  • PHP / Zend Framework: Which object would handle a complex table join?

    - by Thomas
    I think one of the more difficult concepts to understand in the Zend Framework is how the Table Data Gateway pattern is supposed to handle multi-table joins. Most of the suggestions I've seen claim that you simply handle the joins using a $db-select()... Zend DB Select with multiple table joins Joining Tables With Zend Framework PHP Joining tables wthin a model in Zend Php Zend Framework Db Select Join table help Zend DB Select with multiple table joins My question is: Which object is best suited to handle this kind of multi-table select statement? I feel like putting it in the model would break the 1-1 Table Data Gateway pattern between the class and the db table. Yet putting it in the controller seems wrong because why would a controller handle a SQL statement? Anyway, I feel like ZF makes handling datasets from multiple tables more difficult than it needs to be. Any help you can provide is great... Thanks!

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  • Is it possible to write a SQL query to return specific rows, but then join some columns of those row

    - by Rob
    I'm having trouble wrapping my head around how to write this query. A hypothetical problem that is that same as the one I'm trying to solve: Say I have a table of apples. Each apple has numerous attributes, such as color_id, variety_id and the orchard_id they were picked from. The color_id, variety_id, and orchard_id all refer to their respective tables: colors, varieties, and orchards. Now, say I need to query for all apples that have color_id = '3', which refers to yellow in the colors table. I want to somehow obtain this yellow value from the query. Make sense? Here's what I was trying: SELECT * FROM apples, colors.id WHERE color_id = '3' LEFT JOIN colors ON apples.color_id = colors.id

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  • Windows 8 doesn't automatically join Wi-Fi network if Ethernet connection is active

    - by Herb Caudill
    In Windows 7, my laptop would automatically join both an Ethernet network and the Wi-Fi network in my house (both going through the same router). In Windows 8, if the Ethernet connection is present, it doesn't join the Wi-Fi network at all. The reason I noticed this is that if Wi-Fi isn't active, I don't see my AirPlay speakers. My wireless printer is also unavailable until I manually connect to Wi-Fi. To recap: When I turn on my computer and it's connected to Ethernet, this is what my Network Connections control panel looks like: After I manually join my Wi-Fi network, it looks like this: I would prefer for it to join both networks automatically on startup, the way it did in Windows 7. Is there a way to make this happen?

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  • Multiple many-to-many JOINs in a single mysql query without Cartesian Product

    - by VWD
    At the moment I can get the results I need with two seperate SELECT statements SELECT COUNT(rl.refBiblioID) FROM biblioList bl LEFT JOIN refList rl ON bl.biblioID = rl.biblioID GROUP BY bl.biblioID SELECT GROUP_CONCAT( CONCAT_WS( ':', al.lastName, al.firstName ) ORDER BY al.authorID ) FROM biblioList bl LEFT JOIN biblio_author ba ON ba.biblioID = bl.biblioID JOIN authorList al ON al.authorID = ba.authorID GROUP BY bl.biblioID Combining them like this however SELECT GROUP_CONCAT( CONCAT_WS( ':', al.lastName, al.firstName ) ORDER BY al.authorID ), COUNT(rl.refBiblioID) FROM biblioList bl LEFT JOIN biblio_author ba ON ba.biblioID = bl.biblioID JOIN authorList al ON al.authorID = ba.authorID LEFT JOIN refList rl ON bl.biblioID = rl.biblioID GROUP BY bl.biblioID causes the author result column to have duplicate names. How can I get the desired results from one SELECT statement without using DISTINCT? With subqueries?

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  • SQL SELECT multiple INNER JOINs

    - by Noam Smadja
    The SELECT statement includes a reserved word or an argument name that is misspelled or missing, or the punctuation is incorrect its Access database.. i have a Library table, where Autnm Topic Size Cover Lang are foreign Keys each record is actually a book which has its properties such as author and stuff. i am not quite sure i am even using the correct JOIN.. quite new with "complex" SQL :) SELECT Library.Bknm_Hebrew, Library.Bknm_English, Library.Bknm_Russian, Library.Note, Library.ISBN, Library.Pages, Library.PUSD, Author.ID AS [AuthorID], Author.Author_hebrew AS [AuthorHebrew], Author.Author_English AS [AuthorEnglish], Author.Author_Russian AS [AuthorRussian], Topic.ID AS [TopicID], Topic.Topic_Hebrew AS [TopicHebrew], Topic.Topic_English AS [TopicEnglish], Topic.Topic_Russian AS [TopicRussian], Size.Size AS [Size], Cover.ID AS [TopicID], Cover.Cvrtyp_Hebrew AS [CoverHebrew], Cover.Cvrtyp_English AS [TopicEnglish], Cover.Cvrtyp_Russian AS [CoverRussian], Lang.ID AS [LangID], Lang.Lang_Hebrew AS [LangHebrew], Lang.Lang_English AS [LangEnglish], FROM Library INNER JOIN Author ON Library.Autnm = Author.ID INNER JOIN Topic ON Library.Topic = Topic.ID INNER JOIN Size ON Library.Size = Size.ID INNER JOIN Cover ON Library.Cover = Cover.ID INNER JOIN Lang ON Library.Lang = Lang.ID Thx in advance

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  • How to join this table?

    - by pamella
    ads table img90.imageshack.us/img90/6295/adsvo.png phones table img194.imageshack.us/img194/3713/phones.png cars table img35.imageshack.us/img35/1035/carsm.png i have 3 tables ads,cars and phones. i want to join tables is based on category in ads table. and i tried this query but no luck,any helps? SELECT * FROM `ads` JOIN `ads.category` ON `ads.id` = `ads.category.id` ** i cant add comment any of your post,but i want it to be automatic based on category in ads table. for example :- if in table have phones category,i will automatic join phones table then SELECT * FROM `ads` JOIN `phone` ON `ads.id` = `phone.id` if in table have cars category,i will automatic join cars table SELECT * FROM `ads` JOIN `cars` ON `ads.id` = `cars.id`

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  • Why does this SELECT ... JOIN statement return no results?

    - by Stephen
    I have two tables: 1. tableA is a list of records with many columns. There is a timestamp column called "created" 2. tableB is used to track users in my application that have locked a record in tableA for review. It consists of four columns: id, user_id, record_id, and another timestamp collumn. I'm trying to select up to 10 records from tableA that have not been locked by for review by anyone in tableB (I'm also filtering in the WHERE clause by a few other columns from tableA like record status). Here's what I've come up with so far: SELECT tableA.* FROM tableA LEFT OUTER JOIN tableB ON tableA.id = tableB.record_id WHERE tableB.id = NULL AND tableA.status = 'new' AND tableA.project != 'someproject' AND tableA.created BETWEEN '1999-01-01 00:00:00' AND '2010-05-06 23:59:59' ORDER BY tableA.created ASC LIMIT 0, 10; There are currently a few thousand records in tableA and zero records in tableB. There are definitely records that fall between those timestamps, and I've verified this with a simple SELECT * FROM tableA WHERE created BETWEEN '1999-01-01 00:00:00' AND '2010-05-06 23:59:59' The first statement above returns zero rows, and the second one returns over 2,000 rows.

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  • How do I create a self referential association (self join) in a single class using ActiveRecord in Rails?

    - by Daniel Chang
    I am trying to create a self join table that represents a list of customers who can refer each other (perhaps to a product or a program). I am trying to limit my model to just one class, "Customer". The schema is: create_table "customers", force: true do |t| t.string "name" t.integer "referring_customer_id" t.datetime "created_at" t.datetime "updated_at" end add_index "customers", ["referring_customer_id"], name: "index_customers_on_referring_customer_id" My model is: class Customer < ActiveRecord::Base has_many :referrals, class_name: "Customer", foreign_key: "referring_customer_id", conditions: {:referring_customer_id => :id} belongs_to :referring_customer, class_name: "Customer", foreign_key: "referring_customer_id" end I have no problem accessing a customer's referring_customer: @customer.referring_customer.name ... returns the name of the customer that referred @customer. However, I keep getting an empty array when accessing referrals: @customer.referrals ... returns []. I ran binding.pry to see what SQL was being run, given a customer who has a "referer" and should have several referrals. This is the SQL being executed. Customer Load (0.3ms) SELECT "customers".* FROM "customers" WHERE "customers"."id" = ? ORDER BY "customers"."id" ASC LIMIT 1 [["id", 2]] Customer Exists (0.2ms) SELECT 1 AS one FROM "customers" WHERE "customers"."referring_customer_id" = ? AND "customers"."referring_customer_id" = 'id' LIMIT 1 [["referring_customer_id", 3]] I'm a bit lost and am unsure where my problem lies. I don't think my query is correct -- @customer.referrals should return an array of all the referrals, which are the customers who have @customer.id as their referring_customer_id.

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  • Join us for Live Oracle Linux and Oracle VM Cloud Events in Europe

    - by Monica Kumar
    Join us for a series of live events and discover how Oracle VM and Oracle Linux offer an integrated and optimized infrastructure for quickly deploying a private cloud environment at lower cost. As one of the most widely deployed operating systems today, Oracle Linux delivers higher performance, better reliability, and stability, at a lower cost for your cloud environments. Oracle VM is an application-driven server virtualization solution fully integrated and certified with Oracle applications to deliver rapid application deployment and simplified management. With Oracle VM, you have peace of mind that the entire Oracle stack deployed is fully certified by Oracle. Register now for any of the upcoming events, and meet with Oracle experts to discuss how we can help in enabling your private cloud. Nov 20: Foundation for the Cloud: Oracle Linux and Oracle VM (Belgium) Nov 21: Oracle Linux & Oracle VM Enabling Private Cloud (Germany) Nov 28: Realize Substantial Savings and Increased Efficiency with Oracle Linux and Oracle VM (Luxembourg) Nov 29: Foundation for the Cloud: Oracle Linux and Oracle VM (Netherlands) Dec 5: MySQL Tech Tour, including Oracle Linux and Oracle VM (France) Hope to see you at one of these events!

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  • Join the Dark Side of Visual Studio 2010

    - by InfinitiesLoop
    Hard to believe it’s been so long, but it was almost 4 years ago when I published Join the Dark Side of Visual Studio . That was when a lot of people were still using VS2003, and importing and exporting environment settings required a custom add-in, VSStyler, which has since fallen off the planet and is hard to find (link, anyone? Let me know). Three versions of VS later, and I’m still using and loving the dark side. Pleased, I am (haha). In fact, that article for one reason or another is still one...(read more)

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  • Join Our Call: Sun Storage 2500-M2 Announcement

    - by user797911
    Oracle's Sun Storage 2500-M2 array brings together the latest Fibre Channel (FC) and SAS2 technologies with Oracle's Sun Storage Common Array software from Oracle to create a robust solution that’s equally adept in an entry-level storage area network (SAN) for the mid-size business and integrating into an existing storage network within the enterprise. The Sun Storage 2500-M2 replaces Sun's Storage 2500 array product line and is designed so that the customer may have a quick qualification time for fast and easy deployment in the traditional 2500 environments. Jun Jang, Oracle Principal Product Manager will be hosting this 1 hour live call (a recording will be available), please join us to find out more: Event Date: 24-JUN-11 Event Time: 08:00 am PST/PDT/4pm UK time Web Registration and Access: http://oukc.oracle.com/static09/opn/login/?t=livewebcast|c=1031672594 Access for Mobile Devices: http://my.oracle.com/content/web/cnt636926 Call Provider: Intercall International Participant Dial-In Number: 706-634-8508 Additional International Dial-In Numbers Link: http://www.intercall.com/national/oracleuniversity/gdnam.html Dial-In Passcode: 96395

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  • Join Our Call: Sun Storage 2500-M2 Announcement

    - by mseika
    Oracle's Sun Storage 2500-M2 array brings together the latest Fibre Channel (FC) and SAS2 technologies with Oracle's Sun Storage Common Array software from Oracle to create a robust solution that’s equally adept in an ! entry-level storage area network (SAN) for the mid-size business and integrating into an existing storage network within the enterprise. The Sun Storage 2500-M2 replaces Sun's Storage 2500 array product line and is designed so that the customer may have a quick qualification time for fast and easy deployment in the traditional 2500 environments. Jun Jang, Oracle Principal Product Manager will be hosting this 1 hour live call (a recording will be available), please join us to find out more:24. Jun 2011 08:00 am PST/PDT/4pm UK timeWeb Registration and AccessAccess for Mobile DevicesInternational Participant Dial-In Number: 706-634-8508Additional International Dial-In Numbers LinkDial-In Passcode: 6395

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  • mysql join with multiple values in one column

    - by CYREX
    I need to make a query that creates 3 columns that come from 2 tables which have the following relations: TABLE 1 has Column ID that relates to TABLE 2 with column ID2 In TABLE 1 there is a column called user In TABLE 2 there is a column called names There can be 1 unique user but there can be many names associated to that user. If i do the following i get all data BUT the user column repeats itself for each name it has associated. What i want is for use to appear unique but the names columns appear with all the names associated to the user column but separated by commas, like the following: select user,names from TABLE1 left join TABLE2 on TABLE1.id = TABLE2.id This will show the users repeated everytime a name appears for that user. what i want is to appear like this: USER - NAMES cyrex - pedrox, rambo, zelda homeboy - carmen, carlos, tom, sandra jerry - seinfeld, christine ninja - soloboy etc....

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  • Join Us for the Next Quarterly Customer Update Webcast

    - by michelle.huff
    Join us for the next Oracle Content Management Quarterly Customer Update Webcast scheduled for this coming June 30 / July 1 2010. Don't miss this chance to get an overview on the latest updates to Oracle Content Management. We'll be covering the latest ECM Suite 11g release - highlighting the Universal Content Management (UCM) and Universal Records Management releases. Register Today! Americas / EMEA time zones: Customer Update June 30, 2010 9:00am US PDT / 12:00pm US EDT / 16:00 GMT Length: 1 hour *Please use your corporate email address to register. Asia-Pacific time zones: Customer Update (Repeat Webcast) July 1, 2010 12:00pm Sydney AEST, 10:00am Singapore (June 30, 2010 @ 7:00pm US PDT) Length: 1 hour *Please use your corporate email address to register Please Note: If you have attended previous Quarterly Customer Update Webcasts, we are now using a new web conference system, WebEx, to host the meeting. Missed Previous Customer Quarterly Updates? Get caught up on Oracle & ECM news. View a recording or the presentation from previous Webcasts held since June 2008 (available from My Oracle Support).

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  • Join Us for the Next Quarterly Customer Update Webcast

    - by michelle.huff
    Join us for the next Oracle Content Management Quarterly Customer Update Webcast scheduled for this coming January 19 & 20, 2010. In this webcast we'll bring you up to speed on the latest updates and changes made available these past few months. Additionally, we'll cover the new features and certifications in the latest ODC & ODDC 10.1.3.5.1 release, as well as the upcoming Enterprise Content Management Suite 11gR1 PS3 (patch set 3) release. Register Today! Americas / EMEA time zones: Customer Update January 19, 2010 9:00am US PT / 12:00pm US ET / 17:00 London Length: 1 hour *Please use your corporate email address to register. Asia-Pacific time zones: Customer Update (Repeat Webcast) January 20, 2010 1:00pm Sydney AET, 10:00am Singapore (Jan 19, 2010 @ 6:00pm US PT) Length: 1 hour *Please use your corporate email address to register Missed Previous Customer Quarterly Updates? Get caught up on Oracle & ECM news. View a recording or the presentation from previous Webcasts held since June 2008 (available from My Oracle Support).

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