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  • What does a forward slash before a pipe in cmd do to remove the line ending of an echo?

    - by user66001
    This code: @echo off echo/|set /p ="Executing backup...." echo/|set /p =" backup procedure" ... came from Echoing in the same line and produces the below output in a cmd window: Executing backup....backup procedure However, I cant seem to find an explanation through google on what the forward slash does to the ¿pipe? to cause set's output to be echoed to the console / stdout If anyone could also suggest a good website for learning more about cmd / cmd programs' features like this, it would be appreciated.

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  • What could cause a returning function to crash? C++

    - by JeanOTF
    So I have been debugging this error for hours now. I writing a program using Ogre3d relevant only because it doesn't load symbols so it doesn't let me stack trace which made finding the location of the crash even harder. So, write before I call a specific function I print out "Starting" then I call the function and immediately after I print "Stopping". Throughout the function I print out letters A-F where F is printed right before the function returns (one line above the last '}') The weird thing is when the crash occurs it is after the 'F' is printed but there is no 'Stopping'. Does this mean that the crash is happening in between somewhere? The only thing I can think of is something going wrong during the deallocation of some of the memory allocated during the function. I've never had anything happen like this, I will keep checking to make sure it's going wrong where I think it is.

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  • Replace carriage returns and line feeds in out.println?

    - by Mike
    I am a novice coder and I am using the following code to outprint a set of Image keywords and input a "|" between them. <% Set allKeywords = new HashSet(); for (AlbumObject ao : currentObjects) { XmpManager mgr = ao.getXmpManager(); if (mgr != null) { allKeywords.addAll(mgr.getKeywordSet()); } } //get the Iterator Iterator itr = allKeywords.iterator(); while(itr.hasNext()){ String str = itr.next(); out.println(str +"|"); } %> I want the output to be like this: red|blue|green|yellow but it prints out: red| blue| green| yellow which breaks my code. I've tried this: str.replaceAll("\n", ""); str.replaceAll("\r", ""); and str.replaceAll("(?:\\n|\\r)", ""); No luck. I'd really appreciate some help!

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  • a function that returns a random number that is a multiple of 3 between 0 and the function's non-negative integer parameter n

    - by martin
    I need to write a function called multipleOf3 that returns a random number that is a multiple of 3 between 0 and the function's non-negative integer parameter n and here is the result i want [Note: No number returned can be greater than the value of the parameter n] Examples: multipleOf3(0) -- 0 multipleOf3(1) -- 0 multipleOf3(2) -- 0 multipleOf3(3) -- 0 or 3 multipleOf3(20) -- 0 or 3 or 6 or 9 or 12 or 15 or 18

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  • fatal: git-http-push-failed (return code 22)

    - by Mariusz
    Hello, that's me again. After having problem with estabilishing connection to github.com now I have a problem with next step - pushing. I need to mention, that I am novice at GIT service, and this whole Distributed Subversion Checking Systems world.. I have done git init, then git add *.h and git add *.cpp, but currently git status does not print anything in "# On branch master" section? Previously It was correctly printing whole list of added files, now this list is gone. Nextly, I have executed: git remote add origin https://github.com/mgeeky/disasm.git and error has occured after: git push origin master Username: Password: error: Cannot access URL https://github.com/mgeeky/disasm.git/, return code 22 fatal: git-http-push failed What should I do now? I've tried: git push origin Username: Password: No refs in common and none specified; doing nothing. Perhaps you should specify a branch such as 'master'. Everything up-to-date But it seems to be okey.

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  • Mount Return Code for CIFS mount

    - by laikadad101
    When I run the following command (as root or via sudo) from a bash script I get an exit status (or return code in mount man page parlance) of 1: mount -v -t cifs //nasbox/volume /tmpdir/ --verbose -o credentials=/root/cifsid & /tmp/mylog It outputs the following into the myflog file: parsing options: rw,credentials=/root/cifsid mount.cifs kernel mount options unc=//nasbox\volume,ip=192.168.1.1,user=root,pass=xxxx,ver=1,rw,credentials=/root/cifsid It mounts the volume fine but returns the exit code (from the mount man page): 1 Incorrect invocation or permissions The standard Linux log files don't contain any error information. Hence, all seems to go well but I get an exit code of 1 instead of 0. Any ideas? The -v and --verbose options are just there for debugging this problem.

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  • use of [!NOTFOUND=return] in nsswitch.conf

    - by Chris Phillips
    Has anyone come across the use of this config for passwd and groups config in nsswitch.conf? Where I'm working I've been told it's been shown to help situations where a group exists both locally and in ldap which was causing issues for group memberships etc. However this config seems to totally mess up nscd which will be aware of the groups and all their members but will not flip the data around to say the user is a member of all it's remote groups. Initially it seems, given a fully available environment, to be exactly the same as [FOUND=return] which is an implict default between stages anyway. However apparently a lengthy ticket with Redhat resulted in the recommended use of that configuration.

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  • Getting ROBOCOPY to return a "proper" exit code?

    - by Lasse V. Karlsen
    Is it possible to ask ROBOCOPY to exit with an exit code that indicates success or failure? I am using ROBOCOPY as part of my TeamCity build configurations, and having to add a step to just silence the exit code from ROBOCOPY seems silly to me. Basically, I have added this: EXIT /B 0 to the script that is being run. However, this of course masks any real problems that ROBOCOPY would return. Basically, I would like to have exit codes of 0 for SUCCESS and non-zero for FAILURE instead of the bit-mask that ROBOCOPY returns now. Or, if I can't have that, is there a simple sequence of batch commands that would translate the bit-mask of ROBOCOPY to a similar value?

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  • Implementing Variable Envelope Return Path (VERP) using Exchange

    - by iammichael
    We're looking into implementing Variable Envelope Return Path (VERP) for improved bounce processing for our application. Our current mail infrastructure is MS Exchange 2007 but are in the process of upgrading to 2010. We're also implementing Postini for spam filtering. Exchange doesn't support sub-addressing (see also this question on disposable addresses) -- and VERP is somewhat of a specialized application of sub-addressing. Are there any options for implementing VERP in Exchange without putting another non-Exchange SMTP relay in front of Exchange to pre-process incoming messages? Specifically could a transport rule be created that could match against the target (non-existing) recipient, store that recipient address in a special header added to the message, and redirect the message to a pre-created mailbox? Note: we have developer resources available if custom code could be used somehow.

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  • Use linefeed or carriage return in Subversion commit message from the command line

    - by Scott
    I am using Subversion 1.6.6 on Ubuntu 10.04. I would like to insert a carriage return, or linefeed, or newline into my commit message so that when reading the log, the comments are formatted appropriately. It works fine when I use the system editor, or specify a file for the commit comment, but what I really want is to be able to do something like the following: svn ci -m "This is the first line\nThis is the second line" and have the comment presented as: This is the first line This is the second line My example does not work, it produces output: This is the first line\nThis is the second line So, is there a way to do this? If so, how?

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  • Google Mini Search Does Not Return Results

    - by James Lawruk
    I pointed the Google Mini to a small intranet site. (8 simple HTML pages) It crawls all 8 pages just fine, but a simple search with a word clearing contained within the body of the pages returns 0 results. If I enter a search like this: "site:mysite.net", it returns all 8 pages. If I enter a search with a word contained in a Url, it will return that Url. In the search results, only the Url is returned in the list items. There is no Page Title or blurb text you normally see in Google search results. It's as if it is only indexing the Url and skipping the page title, body, etc. I have an old software Version 3.4.14, but I wanted to try to get this thing working without an upgrade. It worked before for another domain, so why would it not work now. Any ideas?

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  • Refering to another field in a form and return entries based on the filed

    - by Claus Machholdt
    Structure of DB is: Org_Year(Table) ID Org_Name_ID Org_Year Ft(Table) ID Org_Year_ID Count Org_Name(Table) ID Org_Name I've created a form to input data into Ft. Form has reference to Org_name. I should be able to choose between different org first. Afterwards i want to choose which year to enter data into Ft for. I only want to be presented with a list of Years according to the entries in the Org_Year table, where org matches my selection in the dropdown above. The query to populate the select box (Org_year_Box) is: SELECT Org_Year FROM Org_Year WHERE Org_Name_ID=Organisation_Name_ID.value; I't doesn't return the Years for the given Org_id when using the above query. But if i replace "Organisation_Name_ID.value" with the actual value ie. "2" it returns the correct years. How to do?

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  • Return http status ok (200) on request method OPTIONS Apache

    - by jazz
    I have a apache server which uses Reverse Proxy to connect/direct to a tomcat server. Using virtualHost, RequestHeader set X-Forwarded-Proto "http" ServerName image.abc.local DocumentRoot "/var/www/html" ProxyRequests Off ProxyTimeout 600 ProxyPass /abc http://image.abc.local:9001/abc ProxyPass /xyz http://image.abc.local:9001/xyz ProxyPassReverse /abc http://image.abc.local:9001/abc ProxyPassReverse /xyz http://image.abc.local:9001/xyz what i want to achieve here is that, when there is a REQUEST_METHOD OPTIONS i want simply return HTTP status OK (200). I dont want the request to be received by the tomcat server and process it. For performance based concerns i want this request to be handled at apache level. with all the research i was still unable to get this to run; RewriteEngine on RewriteCond %{REQUEST_METHOD} OPTIONS RewriteRule .* - [R=200m] can somebody assist me with what rewrite rule should be there? or is there an alternative to RewriteEngine? Thanks

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  • High fan speed after return from suspend (on Ubuntu)

    - by Bolo
    Hi, I've got a HP ProBook 5310m laptop with Ubuntu 10.04 (32 bit). When I return from suspend, the fan speed is usually very high: FDTZ sensor reports "90 °C". Yes, the units are wrong, since FDTZ does not report temperature, but fan speed – that's probably just a small bug in reporting. Interestingly, when I plug or unplug the power cable for a moment, the fan speed returns back to normal. My questions: Where can I report this problem? Is it about ACPI support in the kernel? What is the address of the relevant bug tracker? As a workaround for now, how can I programmatically trigger a behavior equivalent to (un)plugging the power cable. More generally, how can I force ACPI to recalculate fan speed? Ideally, I'm looking for something like echo foo > /proc/bar. Thanks in advance!

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  • Enter / Return key stops working

    - by andygrunt
    I have a Dell Latitude E5400 laptop running Windows 7. Everything runs fine on it for days then I suddenly notice the enter/return key is no longer working e.g. I could be writing an email, press enter for a new line but it doesn’t ‘register’ – so no new line. I thought it might be some dirt under the key perhaps so I tried running the Windows onscreen keyboard but the Enter key on that doesn’t work either. A reboot always fixes the problem but it’s a pain. Any ideas a) how to fix it and b) out of interest, is there some other key combination that I can use as an alternative to using the Enter key when I need to?

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  • Dell replacement return

    - by terrani
    Hi, I am not sure if I can ask this question here. Please let me know if my question is not suitable here. I just received my replacement monitor from dell. While I was talking to dell tech., he told me that Dell would charge me for the replacement monitor if I fail to return my defective monitor within 15 days. I don't know why he told me that when I didn't ask it. so here is my question. How are they going to charge me?? Dell does not have my credit card or bank account info. Do they store my credit card or bank account information on their database???

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  • Enter / Return key stops working

    - by andygrunt
    I have a Dell Latitude E5400 laptop running Windows 7. Everything runs fine on it for days then I suddenly notice the enter/return key is no longer working e.g. I could be writing an email, press enter for a new line but it doesn’t ‘register’ – so no new line. I thought it might be some dirt under the key perhaps so I tried running the Windows onscreen keyboard but the Enter key on that doesn’t work either. A reboot always fixes the problem but it’s a pain. Any ideas a) how to fix it and b) out of interest, is there some other key combination that I can use as an alternative to using the Enter key when I need to? UPDATE: Thanks to CarlF's suggestion, I tried exiting running programmes and found it seems to be a problem with PhraseExpress.

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  • Telnet Postfix on 25 connect but doesn't return any banner

    - by Moh
    I have configured postfix on RHEL 6.4 and I can connect to postfix on 25 port but no banners return and ehlo doesn't work either. I have uncommented the smtpd_banner line and here it how looks. smtpd_banner = $myhostname ESMTP $mail_name ($mail_version) My hostname returns my server's FQDN postfix.labp.com Postfix is listening on all IPs on port 25. I didn't touch the master.cf file and it looks configured properly or so I have noticed from other posts. I'm unable to find the culprit. I would appreciate any help. Thanks Mo

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  • How to find problem with PHP XSLTProcessor when return from transformToXML is false and libxml_get_

    - by John
    I'm working on the code below to allow HTTP user agents that cannot perform XSL transformations to view the resources on my server. I'm mystified because the result of transformToXML is false, but the result of libxml_get_errors() is an empty array. As you can see, the code outputs the LibXSLT version ID and I'm getting the problem on WinVista with version 1.1.24. Is libxml_get_errors() not the right function to get the errors from the XSLTProcessor object? If you're interested in the XML documents, you can get them from http://bobberinteractive.com/index.xhtml and .../stylesheets/layout.xsl <?php //redirect browsers that can handle the source files. if (strpos ( $_SERVER ['HTTP_ACCEPT'], 'application/xhtml+xml' )) { header ( "HTTP/1.1 301 Moved Permanently" ); header ( "Location: http://" . $_SERVER ['SERVER_NAME'] . "/index.xhtml" ); header ( "Content-Type: text/text" ); echo "\nYour browser is capable of processing the <a href='/index.xhtml' site contents on its own."; die (); } //start by checking the template $baseDir = dirname ( __FILE__ ); $xslDoc = new DOMDocument (); if (! $xslDoc-load ( $baseDir . '/stylesheets/layout.xsl' )) { header ( "HTTP/1.1 500 Server Error" ); header ( "Content-Type: text/plain" ); echo "\n Can't load " . $baseDir . '/stylesheets/layout.xsl'; die (); } //resolve the requested resource (browsers that need transformation will request the resource without the suffix) $uri = $_SERVER ['REQUEST_URI']; $len = strlen ( $uri ); if (1 = $len || '/' == substr ( $uri, $len - 1 )) { $fileName = $baseDir . "/index.xhtml"; // use 'default' document if pathname ends in '/' } else { $fileName = $baseDir . (1 load ( $fileName )) { header ( "HTTP/1.1 500 Server Error" ); echo "\n Can't load " . $fileName; die (); } // now start the XSL template processing $proc = new XSLTProcessor (); $proc-importStylesheet ( $xslDoc ); $doc = $proc-transformToXML ( $xmlDoc ); if (false === $doc) { header ( "HTTP/1.1 500 Server Error" ); header ( "Content-Type: text/plain" ); echo "\n"; // HERE is where it gets strange: the value of $doc is false and libxml_get_errors returns 0 entries. display_xml_errors ( libxml_get_errors() ); die (); } header ( "Content-Type: text/html" ); echo "\n"; echo $doc; function display_xml_errors($errors) { echo count ( $errors ) . " Error(s) from LibXSLT " . LIBXSLT_DOTTED_VERSION; for($i = 0; $i level) { case LIBXML_ERR_WARNING : $return .= "Warning $error-code: "; break; case LIBXML_ERR_ERROR : $return .= "Error $error-code: "; break; case LIBXML_ERR_FATAL : $return .= "Fatal Error $error-code: "; break; } $return .= trim ( $error-message ) . "\n Line: $error-line" . "\n Column: $error-column"; if ($error-file) { $return .= "\n File: $error-file"; } echo "$return\n\n--------------------------------------------\n\n"; } }

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  • Please Help i keep getting a no match for call to error!!??

    - by Timothy Poseley
    #include <iostream> #include <string> using namespace std; // Turns a digit between 1 and 9 into its english name // Turn a number into its english name string int_name(int n) { string digit_name; { if (n == 1) return "one"; else if (n == 2) return "two"; else if (n == 3) return "three"; else if (n == 4) return "four"; else if (n == 5) return "five"; else if (n == 6) return "six"; else if (n == 7) return "seven"; else if (n == 8) return "eight"; else if (n == 9) return "nine"; return ""; } string teen_name; { if (n == 10) return "ten"; else if (n == 11) return "eleven"; else if (n == 12) return "twelve"; else if (n == 13) return "thirteen"; else if (n == 14) return "fourteen"; else if (n == 14) return "fourteen"; else if (n == 15) return "fifteen"; else if (n == 16) return "sixteen"; else if (n == 17) return "seventeen"; else if (n == 18) return "eighteen"; else if (n == 19) return "nineteen"; return ""; } string tens_name; { if (n == 2) return "twenty"; else if (n == 3) return "thirty"; else if (n == 4) return "forty"; else if (n == 5) return "fifty"; else if (n == 6) return "sixty"; else if (n == 7) return "seventy"; else if (n == 8) return "eighty"; else if (n == 9) return "ninety"; return ""; } int c = n; // the part that still needs to be converted string r; // the return value if (c >= 1000) { r = int_name(c / 1000) + " thousand"; c = c % 1000; } if (c >= 100) { r = r + " " + digit_name(c / 100) + " hundred"; c = c % 100; } if (c >= 20) { r = r + " " + tens_name(c /10); c = c % 10; } if (c >= 10) { r = r + " " + teen_name(c); c = 0; } if (c > 0) r = r + " " + digit_name(c); return r; } int main() { int n; cout << endl << endl; cout << "Please enter a positive integer: "; cin >> n; cout << endl; cout << int_name(n); cout << endl << endl; return 0; } I Keep getting this Error code: intname2.cpp: In function âstd::string int_name(int)â: intname2.cpp:74: error: no match for call to â(std::string) (int)â intname2.cpp:80: error: no match for call to â(std::string) (int)â intname2.cpp:86: error: no match for call to â(std::string) (int&)â intname2.cpp:91: error: no match for call to â(std::string) (int&)â

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  • Where did the notion of "one return only" come from?

    - by FredOverflow
    I often talk to Java programmers who say "Don't put multiple return statements in the same method." When I ask them to tell me the reasons why, all I get is "The coding standard says so." or "It's confusing." When they show me solutions with a single return statement, the code looks uglier to me. For example: if (blablabla) return 42; else return 97; "This is ugly, you have to use a local variable!" int result; if (blablabla) result = 42; else result = 97; return result; How does this 50% code bloat make the program any easier to understand? Personally, I find it harder, because the state space has just increased by another variable that could easily have been prevented. Of course, normally I would just write: return (blablabla) ? 42 : 97; But the conditional operator gets even less love among Java programmers. "It's incomprehensible!" Where did this notion of "one return only" come from, and why do people adhere to it rigidly?

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  • I keep getting a no match for call to error!!??

    - by Timothy Poseley
    #include <iostream> #include <string> using namespace std; // Turns a digit between 1 and 9 into its english name // Turn a number into its english name string int_name(int n) { string digit_name; { if (n == 1) return "one"; else if (n == 2) return "two"; else if (n == 3) return "three"; else if (n == 4) return "four"; else if (n == 5) return "five"; else if (n == 6) return "six"; else if (n == 7) return "seven"; else if (n == 8) return "eight"; else if (n == 9) return "nine"; return ""; } string teen_name; { if (n == 10) return "ten"; else if (n == 11) return "eleven"; else if (n == 12) return "twelve"; else if (n == 13) return "thirteen"; else if (n == 14) return "fourteen"; else if (n == 14) return "fourteen"; else if (n == 15) return "fifteen"; else if (n == 16) return "sixteen"; else if (n == 17) return "seventeen"; else if (n == 18) return "eighteen"; else if (n == 19) return "nineteen"; return ""; } string tens_name; { if (n == 2) return "twenty"; else if (n == 3) return "thirty"; else if (n == 4) return "forty"; else if (n == 5) return "fifty"; else if (n == 6) return "sixty"; else if (n == 7) return "seventy"; else if (n == 8) return "eighty"; else if (n == 9) return "ninety"; return ""; } int c = n; // the part that still needs to be converted string r; // the return value if (c >= 1000) { r = int_name(c / 1000) + " thousand"; c = c % 1000; } if (c >= 100) { r = r + " " + digit_name(c / 100) + " hundred"; c = c % 100; } if (c >= 20) { r = r + " " + tens_name(c /10); c = c % 10; } if (c >= 10) { r = r + " " + teen_name(c); c = 0; } if (c > 0) r = r + " " + digit_name(c); return r; } int main() { int n; cout << endl << endl; cout << "Please enter a positive integer: "; cin >> n; cout << endl; cout << int_name(n); cout << endl << endl; return 0; } I Keep getting this Error code: intname2.cpp: In function âstd::string int_name(int)â: intname2.cpp:74: error: no match for call to â(std::string) (int)â intname2.cpp:80: error: no match for call to â(std::string) (int)â intname2.cpp:86: error: no match for call to â(std::string) (int&)â intname2.cpp:91: error: no match for call to â(std::string) (int&)â

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  • Mock static method Activator.CreateInstance to return a mock of another class

    - by Jeep87c
    I have this factory class and I want to test it correctly. Let's say I have an abstract class which have many child (inheritance). As you can see in my Factory class the method BuildChild, I want to be able to create an instance of a child class at Runtime. I must be able to create this instance during Runtime because the type won't be know before runtime. And, I can NOT use Unity for this project (if so, I would not ask how to achieve this). Here's my Factory class that I want to test: public class Factory { public AnAbstractClass BuildChild(Type childType, object parameter) { AnAbstractClass child = (AnAbstractClass) Activator.CreateInstance(childType); child.Initialize(parameter); return child; } } To test this, I want to find a way to Mock Activator.CreateInstance to return my own mocked object of a child class. How can I achieve this? Or maybe if you have a better way to do this without using Activator.CreateInstance (and Unity), I'm opened to it if it's easier to test and mock! I'm currently using Moq to create my mocks but since Activator.CreateInstance is a static method from a static class, I can't figure out how to do this (I already know that Moq can only create mock instances of objects). I took a look at Fakes from Microsoft but without success (I had some difficulties to understand how it works and to find some well explained examples). Please help me! EDIT: I need to mock Activator.CreateInstance because I want to force this method to return another mocked object. The correct thing I want is only to stub this method (not to mock it). So when I test BuildChild like this: [TestMethod] public void TestBuildChild() { var mockChildClass = new Mock(AChildClass); // TODO: Stub/Mock Activator.CreateInstance to return mockChildClass when called with "type" and "parameter" as follow. var type = typeof(AChildClass); var parameter = "A parameter"; var child = this._factory.BuildChild(type, parameters); } Activator.CreateInstance called with type and parameter will return my mocked object instead of creating a new instance of the real child class (not yet implemented).

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  • ASP.NET MVC Return to Previous Page

    - by Jason Enochs
    I have a basic Edit method in my controller that redirects back to a top level listing (“Index”) when the edit succeeds. Standard setup after scaffolding. I am trying to change this Edit method to redirect back to the previous page (not Index). Since my Edit method is not using the default mapped input parameter “id”, I am using that to pass the previous URL. In my Edit “get” method, I use this line to grab the previous URL and it works fine: ViewBag.ReturnUrl = Request.UrlReferrer.AbsoluteUri; I send this return URL to the Edit “post” method by using my form tag like this: @using (Html.BeginForm(new { id = ViewBag.ReturnUrl })) Now this is where the wheels fall off. I can't seem to get the URL parsed from the id parameter properly. UPDATE**** Using Gary's example as a guide, I changing my parameter name from "id" to "returnUrl" and used a hidden field to pass my parameter. Lesson: Only use the id parameter how it was intended to be used...keep it simple. It works now... Here is my updated code. // // GET: /Question/Edit/5 public ActionResult Edit(int id) { Question question = db.Questions.Find(id); ViewBag.DomainId = new SelectList(db.Domains, "DomainId", "Name", question.DomainId); ViewBag.Answers = db.Questions .AsEnumerable() .Select(d => new SelectListItem { Text = d.Text, Value = d.QuestionId.ToString(), Selected = question.QuestionId == d.QuestionId }); ViewBag.returnUrl = Request.UrlReferrer; ViewBag.ExamId = db.Domains.Find(question.DomainId).ExamId; ViewBag.IndexByQuestion = string.Format("IndexByQuestion/{0}", question.QuestionId); return View(question); } // // POST: /Question/Edit/5 [HttpPost] public ActionResult Edit(Question question, string returnUrl) { int ExamId = db.Domains.Find(question.DomainId).ExamId; if (ModelState.IsValid) { db.Entry(question).State = EntityState.Modified; db.SaveChanges(); //return RedirectToAction("Index"); return Redirect(returnUrl); } ViewBag.DomainId = new SelectList(db.Domains, "DomainId", "Name", question.DomainId); return View(question); } and I changed my form tag to this: @using (Html.BeginForm()) { <input type="hidden" name="returnUrl" value="@ViewBag.returnUrl" /> Thanks Gary

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