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• Unix Piping using Fork and Dup

  - by Jacob

  Lets say within my program I want to execute two child processes, one to to execute a "ls -al" command and then pipe that into "wc" command and display the output on the terminal. How can I do this using pipe file descriptors so far the code I have written: An example would be greatly helpful int main(int argc, char *argv[]) { int pipefd[2] pipe(pipefd2); if ((fork()) == 0) { dup2(pipefd2[1],STDOUT_FILENO); close(pipefd2[0]); close(pipefd2[1]); execl("ls", "ls","-al", NULL); exit(EXIT_FAILURE); } if ((fork()) == 0){ dup2(pipefd2[0],STDIN_FILENO); close(pipefd2[0]); close(pipefd2[1]); execl("/usr/bin/wc","wc",NULL); exit(EXIT_FAILURE); } close(pipefd[0]); close(pipefd[1]); close(pipefd2[0]); close(pipefd2[1]); }

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• Aggregate Functions on subsets of data based on current row values with SQL

  - by aasukisuki

  Hopefully that title makes sense... Let's say I have an employee table: ID | Name | Title | Salary ---------------------------- 1 | Bob | Manager | 15285 2 | Joe | Worker | 10250 3 | Al | Worker | 11050 4 | Paul | Manager | 16025 5 | John | Worker | 10450 What I'd like to do is write a query that will give me the above table, along with an averaged salary column, based on the employee title: ID | Name | Title | Salary | Pos Avg -------------------------------------- 1 | Bob | Manager | 15285 | 15655 2 | Joe | Worker | 10250 | 10583 3 | Al | Worker | 11050 | 10583 4 | Paul | Manager | 16025 | 15655 5 | John | Worker | 10450 | 10583 I've tried doing this with a sub-query along the lines of: Select *, (select Avg(e2.salary) from employee e2 where e2.title = e.title) from employee e But I've come to realize that the sub-query is executed first, and has no knowledge of the table alias'd e I'm sure I'm missing something REALLY obvious here, can anyone point me in the right diretion?

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• Must I loop to search results for a specific value?

  - by tag

  I have a table in the database: name Opinion Tim Tim has an opinion John other random text Dan Dan's random text Al Al says something else I call this data and get it back in getRecords.lastResult To access John's opinion, I could use: getRecords.lastResult[1].opinion But that's only because I know that John is the second record (record 1), but this may change. So the right way is to search through the results to first find the record index for John, then access his opinion. My guess is I need some sort of a loop? Is there an easier way to search for John directly without a loop?

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• Making your class an event source in Java

  - by Crystal

  I'm making a custom button in Java that has two states, mousePressed, and mouseReleased. At the same time, if I wanted to reuse this button, so that other event listeners can register with it, are these the appropriate steps I should do: override addActionListener(ActionListener action) override removeActionListener(ActionListener action) have a private variable like List <ActionListener> list = new List <ActionListener>() to keep track of when events get added and some sort of function with for loop to run all the actions: public void runListeners() { for (ActionListener al : list) { al.actionPerfomed; } } I'm not really sure if this is the way you can do it or if there are other things I am missing. Like does my custom class have to be implements ActionListener? Thanks.

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• PHP or C# script to parse CSV table values to fill in one-to-many table

  - by Yaaqov

  I'm looking for an example of how to split-out comma-delimited data in a field of one table, and fill in a second table with those individual elements, in order to make a one-to-many relational database schema. This is probably really simple, but let me give an example: I'll start with everything in one table, Widgets, which has a "state" field to contain states that have that widget: Table: WIDGET =============================== | id | unit | states | =============================== |1 | abc | AL,AK,CA | ------------------------------- |2 | lmn | VA,NC,SC,GA,FL | ------------------------------- |3 | xyz | KY | =============================== Now, what I'd like to create via code is a second table to be joined to WIDGET called *Widget_ST* that has widget id, widget state id, and widget state name fields, for example Table: WIDGET_ST ============================== | w_id | w_st_id | w_st_name | ------------------------------ |1 | 1 | AL | |1 | 2 | AK | |1 | 3 | CA | |2 | 1 | VA | |2 | 2 | NC | |2 | 1 | SC | |2 | 2 | GA | |2 | 1 | FL | |3 | 1 | KY | ============================== I am learning C# and PHP, so responses in either language would be great. Thanks.

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• Interrupt On GAS

  - by Nathan Campos

  I'm trying to convert my simple program from Intel syntax to the AT&T(to compile it with GAS). I've successfully converted a big part of my application, but I'm still getting an error with the int(the interrupts). My function is like this: printf: mov $0x0e, %ah mov $0x07, %bl nextchar: lodsb or %al, %al jz return int 10 jmp nextchar return: ret msg db "Welcome To Track!", 0Ah But when I compile it, I got this: hello.S: Assembler messages: hello.S:13: Error: operand size mismatch for int' hello.S:19: Error: no such instruction:msg db "Hello, World!",0Ah' What I need to do?

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• How to sum up values of an array in assembly?

  - by Pablo Fallas

  I have been trying to create a program which can sum up all the values of an "array" in assembly, I have done the following: ORG 1000H TABLE DB DUP(2,4,6,8,10,12,14,16,18,20) FIN DB ? TOTAL DB ? MAX DB 13 ORG 2000H MOV AL, 0 MOV CL, OFFSET FIN-OFFSET TABLE MOV BX, OFFSET TABLE LOOP: ADD AL, [BX] INC BX DEC CL JNZ LOOP HLT END BTW I am using msx88 to compile this code. But I get an error saying that the code 0 has not been recognized. Any advise?

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• UCA + Natural Sorting

  - by Alix Axel

  I recently learnt that PHP already supports the Unicode Collation Algorithm via the intl extension: $array = array ( 'al', 'be', 'Alpha', 'Beta', 'Álpha', 'Àlpha', 'Älpha', '????', 'img10.png', 'img12.png', 'img1.png', 'img2.png', ); if (extension_loaded('intl') === true) { collator_asort(collator_create('root'), $array); } Array ( [0] => al [2] => Alpha [4] => Álpha [5] => Àlpha [6] => Älpha [1] => be [3] => Beta [11] => img1.png [9] => img10.png [8] => img12.png [10] => img2.png [7] => ???? ) As you can see this seems to work perfectly, even with mixed case strings! The only drawback I've encountered so far is that there is no support for natural sorting and I'm wondering what would be the best way to work around that, so that I can merge the best of the two worlds. I've tried to specify the Collator::SORT_NUMERIC sort flag but the result is way messier: collator_asort(collator_create('root'), $array, Collator::SORT_NUMERIC); Array ( [8] => img12.png [7] => ???? [9] => img10.png [10] => img2.png [11] => img1.png [6] => Älpha [5] => Àlpha [1] => be [2] => Alpha [3] => Beta [4] => Álpha [0] => al ) However, if I run the same test with only the img*.png values I get the ideal output: Array ( [3] => img1.png [2] => img2.png [1] => img10.png [0] => img12.png ) Can anyone think of a way to preserve the Unicode sorting while adding natural sorting capabilities?

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• Creating ActionEvent object for CustomButton in Java

  - by Crystal

  For a hw assignment, we were supposed to create a custom button to get familiar with swing and responding to events. We were also to make this button an event source which confuses me. I have an ArrayList to keep track of listeners that would register to listen to my CustomButton. What I am getting confused on is how to notify the listeners. My teacher hinted at having a notify and overriding actionPerformed which I tried doing, but then I wasn't sure how to create an ActionEvent object looking at the constructor documentation. The source, id, string all confuses me. Any help would be appreciated. Thanks! code: import java.awt.*; import java.awt.event.*; import javax.swing.*; import java.util.List; import java.util.ArrayList; public class CustomButton { public static void main(String[] args) { EventQueue.invokeLater(new Runnable() { public void run() { CustomButtonFrame frame = new CustomButtonFrame(); frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); frame.setVisible(true); } }); } public void addActionListener(ActionListener al) { listenerList.add(al); } public void removeActionListener(ActionListener al) { listenerList.remove(al); } public void actionPerformed(ActionEvent e) { System.out.println("Button Clicked!"); } private void notifyListeners() { ActionEvent event = new ActionEvent(CONFUSED HERE!!!!; for (ActionListener action : listenerList) { action.actionPerfomed(event); } } List<ActionListener> listenerList = new ArrayList<ActionListener>(); } class CustomButtonFrame extends JFrame { // constructor for CustomButtonFrame public CustomButtonFrame() { setTitle("Custom Button"); CustomButtonSetup buttonSetup = new CustomButtonSetup(); this.add(buttonSetup); this.pack(); } } class CustomButtonSetup extends JComponent { public CustomButtonSetup() { ButtonAction buttonClicked = new ButtonAction(); this.addMouseListener(buttonClicked); } // because frame includes borders and insets, use this method public Dimension getPreferredSize() { return new Dimension(200, 200); } public void paintComponent(Graphics g) { Graphics2D g2 = (Graphics2D) g; // first triangle coords int x[] = new int[TRIANGLE_SIDES]; int y[] = new int[TRIANGLE_SIDES]; x[0] = 0; y[0] = 0; x[1] = 200; y[1] = 0; x[2] = 0; y[2] = 200; Polygon firstTriangle = new Polygon(x, y, TRIANGLE_SIDES); // second triangle coords x[0] = 0; y[0] = 200; x[1] = 200; y[1] = 200; x[2] = 200; y[2] = 0; Polygon secondTriangle = new Polygon(x, y, TRIANGLE_SIDES); g2.drawPolygon(firstTriangle); g2.setColor(firstColor); g2.fillPolygon(firstTriangle); g2.drawPolygon(secondTriangle); g2.setColor(secondColor); g2.fillPolygon(secondTriangle); // draw rectangle 10 pixels off border int s1[] = new int[RECT_SIDES]; int s2[] = new int[RECT_SIDES]; s1[0] = 5; s2[0] = 5; s1[1] = 195; s2[1] = 5; s1[2] = 195; s2[2] = 195; s1[3] = 5; s2[3] = 195; Polygon rectangle = new Polygon(s1, s2, RECT_SIDES); g2.drawPolygon(rectangle); g2.setColor(thirdColor); g2.fillPolygon(rectangle); } private class ButtonAction implements MouseListener { public void mousePressed(MouseEvent e) { System.out.println("Click!"); firstColor = Color.GRAY; secondColor = Color.WHITE; repaint(); } public void mouseReleased(MouseEvent e) { System.out.println("Released!"); firstColor = Color.WHITE; secondColor = Color.GRAY; repaint(); } public void mouseEntered(MouseEvent e) {} public void mouseExited(MouseEvent e) {} public void mouseClicked(MouseEvent e) {} } public static final int TRIANGLE_SIDES = 3; public static final int RECT_SIDES = 4; private Color firstColor = Color.WHITE; private Color secondColor = Color.DARK_GRAY; private Color thirdColor = Color.LIGHT_GRAY; }

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• i want to find determinant of 4x4 matrix in c#

  - by vj4u

  i want to find determinant of 4x4 matrix in c# please help urgent int ss = 4; int count = 0; int[,] matrix=new int[ss,ss]; ArrayList al = new ArrayList() {1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16 }; for (int i = 0; i < ss; i++) { for (int j = 0; j < ss; j++) { matrix[i, j] =Convert.ToInt32( al[count]); ++count; Response.Write(matrix[i, j] + " "); } Response.Write("<br/>"); }

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• How to generate <a> tag from input fields

  - by NonProgrammer

  Using ASP.Net (in C#), I need to generate a tag that contains person's name, address, etc. I have barely any experience with ASP.NET (or .NET languages) and I am given this assignment. Could someone please guide me to correct path please? Link should look like this: https://example.com/PRR/Info/Login.aspx?SupplierId=36&RegisteredUserLogin=T000001&Mode=RegisteredLoginless&RegisteredModeFunction=AutoShowTotals&RegisteredModeFunction=AutoShowTotals&PayerCountry=FI&ForcePayerEmail=al@lea.al.banthien.net&ExternalOrderId=1000123&ServiceId=286&Amount286=5000.00&PayerInfo286=T000001|10000123|type1|m&SuccessReturnURL=http://success.html&FailureReturnURL=http://failure.html&SuccessCallbackURL=http://youpay.com/p247/success.html&FailureCallbackURL=http://yourfailure.html following components/fields needs to be sent to API in order to pre-populate information for users: FirstName, LastName, SupplierID = integer, Person's userlogin (Should increment by 1. Example: person 1 = t00001. Person2 = t00002, etc.), PayerCountry, Email, amount For some reason, my management thinks that this is something a non-technical person can do! Any help would be appreciated! Thanks!

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• DataGridView cells not editable when using an outside thread call

  - by joslinm

  Hi, I'm not able to edit my datagridview cells when a number of identical calls takes place on another thread. Here's the situation: Dataset table is created in the main window The program receives in files and processes them on a background thread in class TorrentBuilder : BackgroundWorker creating an array objects of another class Torrent My program receives those objects from the BW result and adds them into the dataset The above happens either on my main window thread or in another thread: I have a separate thread watching a folder for files to come in, and when they do come in, they proceed to call TorrentBuilder.RunWorkerAsynch() from that thread, receive the result, and call an outside class that adds the Torrent objects into the table. When the files are received by the latter thread, the datagridview isn't editable. All of the values come up properly into the datagridview, but when I click on a cell to edit it: I can write letters and everything, but when I click out of it, it immediately reverts back to its original value. If I restart the program, I can edit the same cells just fine. If the values are freshly added from the main window thread, I can edit the cells just fine. The outside thread is called from my main window thread, and sits there in the background. I don't believe it to be ReadOnly because I would have gotten an exception. Here's some code: From my main window class: private void dataGridView_DragDrop(object sender, DragEventArgs e) { ArrayList al = new ArrayList(); string[] files = (string[])e.Data.GetData(DataFormats.FileDrop); foreach (string file in files) { string extension = Path.GetExtension(file); if (Path.GetExtension(file).Equals(".zip") || Path.GetExtension(file).Equals(".rar")) { foreach (string unzipped in dh.UnzipFile(file)) al.Add(unzipped); } else if (Path.GetExtension(file).Equals(".torrent")) { al.Add(file); } } dataGridViewProgressBar.Visible = true; tb.RunWorkerCompleted += new RunWorkerCompletedEventHandler(tb_DragDropCompleted); tb.ProgressChanged += new ProgressChangedEventHandler(tb_DragDropProgress); tb.RunWorkerAsync() } void tb_DragDropCompleted(object sender, RunWorkerCompletedEventArgs e) { data.AddTorrents((Torrent[])e.Result); builder.Dispose(); dh.MoveProcessedFiles(data); dataGridViewProgressBar.Visible = false; } From my outside Thread while (autocheck) { if (torrentFiles != null) { builder.RunWorkerAsync(torrentFiles); while (builder.IsBusy) Thread.Sleep(500); } } void builder_RunWorkerCompleted(object sender, System.ComponentModel.RunWorkerCompletedEventArgs e) { data.AddTorrents((Torrent[])e.Result); builder.Dispose(); dh.MoveProcessedFiles(xml); data.Save(); //Save just does an `AcceptChanges()` and saves to a XML file }

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• XPath 1.0 to find if an element's value is in a list of values

  - by user364902

  Is there a way to construct an XPath that evaluates whether an element's value is in a predefined list of values? Something akin to this: /Location/Addr[State='TX or AL or MA'] Which would match nodes whith State elements for Texas, Alabama, or Massachusetts? I know that I can unpack the expression: /Location/Addr[State='TX] or /Location/Addr[State='AL'], etc... But this is a bit cumbersome since the xpaths are quite long, as is the list of values. My google-fu isn't turning up much on the issue...

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• ¿Como puedo instalar Age of Mythology en Ubuntu? - How I can install Age of Mythology on Ubuntu?

  - by edgarsalguero93

  Spanish: Tengo un problema al tratar de instalar Age of Mythology Gold Edition (v 1.03). Al iniciarle con el Wine (1.3.28) en mi Ubuntu 11.10, y después de ingresar el serial y pulsar Siguiente, me sale un error "No se puede cargar PidGen.dll", y se regresa a la ventana anterior. En Configurar Wine, y en la pestaña Librerías le añadí el archivo DLL que me pide pero todo sigue igual. He intentado todo para que se instale pero no funciona. También he intentado instalarlo en una maquina virtual de VMware Workstation 8.0.1 con Microsoft Windows XP SP3 y me sale un error de compatibilidad con la tarjeta de vídeo: "Tarjeta de vídeo 0: vmx_fb.dll VMware SVGA II Vendor(0x15AD) Device(0x405)" y se cierra el Age of Mythology. Me parece que la solución en este caso seria aumentar la cantidad de vídeo que pone a disposición el VMware a la maquina virtual o un driver para esta tarjeta, pero no se como hacer eso. O tal vez alguien sabe la manera de que mi tarjeta de vídeo que tiene mi computadora se use también para VMware o destinar parte de la memoria del vídeo a la maquina virtual. He buscado en varios sitios, pero ninguno soluciona mi problema. Por favor, si alguien ya encontró la respuesta, que responda a esta pregunta, y de antemano gracias. English: I have a problem trying to install Age of Mythology Gold Edition (v 1.03). At the beginning of the Wine (1.3.28) on my Ubuntu 11.10, and after entering the serial and click Next, I get an error "Unable to load pidgen.dll" and return to the previous window. In Configure Wine and in the Libraries tab I added the DLL that calls me but nothing has changed. I tried everything to be installed but not working. I have also tried to install in a virtual machine with VMware Workstation 8.0.1 Microsoft Windows XP SP3 and I get a compatibility error with video card: "Video Card 0: VMware SVGA II vmx_fb.dll Vendor (0x15AD) Device (0x405) "and closes the Age of Mythology. I think the solution in this case would increase the amount of video available to the VMware virtual machine or a driver for this card, but not how to do that. Or maybe someone knows the way that my video card that has my computer is also used for VMware or earmark part of the video memory to the virtual machine. I searched several sites, but none solved my problem. Please, if someone already found the answer, to answer this question. I also apologize if the translation is not well understood. I used the Google translator. Thanks and greetings from Latin America

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• WCF client hell (2 replies)

  I've a remote service available via tcp://. When I add a service reference on my client project, VS doesn't create all proxy objects! I miss every xxxClient class, and I have only types used as parameters in my methods. I tried to start a new empty project, add the same service reference, and in this project I can see al proxy objects! It's an hell, what can I do? thanks

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• Windows CE training in Italy

  - by Valter Minute

  Se volete approfondire le vostre conoscenze su Windows CE (anche relativamente alle novità introdotte con la versione R3), o desiderate acquisire le basi per cominciare a lavorare con questo sistema operativo, questa è un'occasione da non perdere. Dal 12 al 16 Aprile si terrà presso gli uffici di Fortech Embedded Labs di Saronno (VA) il corso "Building Solutions with Windows Embedded CE 6.0", tenuto dal sottoscritto. Per maggiori informazioni sui contenuti e i costi: http://www.fortechembeddedlabs.it/node/27

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• WCF client hell (2 replies)

  I've a remote service available via tcp://. When I add a service reference on my client project, VS doesn't create all proxy objects! I miss every xxxClient class, and I have only types used as parameters in my methods. I tried to start a new empty project, add the same service reference, and in this project I can see al proxy objects! It's an hell, what can I do? thanks

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• Don’t miss a thing when you going the Mix, DevConnections, Tech-ed or PDC conferences.

  - by albertpascual

  Besides all sessions and courses found in the agenda there are events happening around that you will miss, those events are being published and index in this iPhone & iPad app for you to find the parties or external events around the conference that otherwise you will miss. Download it for free here if you are going to the Mix, DevConnections, TechEd or Pdc this year. http://itunes.apple.com/us/app/eventmeetup/id421597442?mt=8&ls=1 Cheers Al

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• Invitación a evento de Oracle sobre Transformación del CPD

  - by Eloy M. Rodríguez

  Ahora que se acaba el año y se van dejando atrás los últimos empujones a los temas que hay que cerrar, es un buen momento para hacer un pequeño alto en el camino y asistir a este evento que organiza Oracle y reflexionar sobre los enfoques innovadores que se plantean ya que la actual situación reclama actuaciones diferentes y, a veces, el árbol tapa al bosque. Adjunto la invitación oficial, con la agenda y acceso al registro automático.. Oracle Transformación del Centro de Datos: Acelerando la adopción eficaz de la Cloud Transformación del Centro de Datos: Acelerando la adopción eficaz de la Cloud Únase a nosotros en el evento Transformación del Centro de Datos y descubra cómo implementar un centro de datos que esté diseñado para promover la innovación, ofreciendo un mayor rendimiento y fiabilidad, simplificando la gestión y reduciendo significativamente los costes. Venga a conocer los últimas novedades tecnológicas aplicables a su negocio que Oracle acaba de anunciar en Oracle Open World, su conferencia mundial por excelencia, como el Supercluster, el nuevo procesador T4 y las soluciones de Storage Pillar. Sólo Oracle diseña hardware y software, para que estos trabajen conjuntamente desde las aplicaciones al disco, lo que permite reducir la complejidad, impulsar la productividad en toda la empresa y acelerar la innovación empresarial. Únase a nosotros para descubrir cómo transformar su centro de datos para maximizar la eficacia y restablecer IT como una ventaja competitiva del negocio de su empresa. Comparta ideas y experiencias con los mejores expertos y ejecutivos y descubra como: Acelerar la transformación del centro de datos a través de la tecnología que proporciona un rendimiento espectacular y una mayor eficiencia Reducir costes, acelerar y simplificar el despliegue y la consolidación de bases de datos y aplicaciones Optimizar el rendimiento a través de la utilización de los productos Oracle con la tecnología de virtualización incorporada sin coste adicional Minimizar el riesgo durante los despliegues de cloud empresarial con el apoyo de los productos líderes del mercado en materia de seguridad Aumentar la productividad y responder rápidamente a los cambios del mercado con las soluciones optimizadas de Oracle Transforme su centro de datos para optimizar el rendimiento, incrementar la agilidad de su negocio y maximizar sus inversiones en IT. No deje pasar esta oportunidad e inscríbase hoy mismo a este evento que tendrá lugar el próximo 14 de diciembre en Madrid. Inscríbase hoy mismo Para más información, contacte con [email protected] Inscríbase ahora 14 de diciembre de 2011 09:00 - 16:00 CÍRCULO DE BELLAS ARTES DE MADRID C/ Alcalá, 42 28014 MadridEntrada por c/ Marqués de Casa Riera Programa 09:00 Registro 09:30 Bienvenida e IntroducciónJoão Taron, Vice-President & Hardware Leader, Oracle Iberia 09:45 Estrategia OracleGerhard Schlabschi, Business Development Director, Oracle Systems EMEA 10:20 Como transformar su centro de datos eficazmente Manuel Vidal, Director Systems Presales, Oracle Iberia 10:45 Caso de Éxito 11:15 Café 11:45 Consolidacion en Private Cloud Rendimiento extremo con Oracle Exalogic Elastic Cloud & Exadata Lisa Martinez,Business Development Manager, Oracle  Aceleración de las aplicaciones empresariales con SPARC SuperClusters y servidores empresariales T4                                     Carlos Soler Ibanez, Principal Sales Consultant, Oracle 13:15 Almuerzo 14:15 Optimización del Centro de Datos Cómo maximizar el potencial de su infrastructura con sistemas virtualizados de Oracle Javier Cerrada, Senior Sales Consultant, Oracle Optimización de los recursos de almacenamiento con Data Tiering Miguel Angel Borrega, Storage Architect, Oracle 15:00 Gestión del Centro de Datos Oracle Solaris 11                                                                             Javier Cerrada, Senior Sales Consultant, Oracle Enterprise Manager 12c                                                                     Jesus Robles, Master Principal Sales Consultant, Oracle 15:45 Preguntas & respuestas 16:00 Conversaciones con sus interlocutores de Oracle & sorteo de iPAD If you are an employee or official of a government organization, please click here for important ethics information regarding this event. Copyright © 2011, Oracle and/or its affiliates. All rights reserved. Contacte con nosotros | Notas Legales y | Política de Privacidad

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• An Introduction to Cash Till

  Cash till is a machine that can tabulate the amount of sales transactions and usually prints receipt for the customers. It can also make a permanent and cumulative record of the day’s sales. Al... [Author: Alan Wisdom - Computers and Internet - April 05, 2010]

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• Controlar Autentificaci&oacute;n Crystal Reports

  - by Jason Ulloa

  Para todos los que hemos trabajamos con Crystal Reports, no es un secreto que cuando tratamos de conectar nuestro reporte directamente a la base de datos, se nos viene encima el problema de autenticación. Es decir nuestro reporte al momento de iniciar la carga nos solicita autentificarnos en el servidor y sino lo hacemos, simplemente no veremos el reporte. Esto, además de ser tedioso para los usuarios se convierte en un problema de seguridad bastante grande, de ahí que en la mayoría de los casos se recomienda utilizar dataset. Sin embargo, para todos los que aún sabiendo esto no desean utilizar datasets, sino que, quieren conectar su crystal directamente veremos como implementar una pequeña clase que nos ayudará con esa tarea. Generalmente, cuando trabajamos con una aplicación web, nuestra cadena de conexión esta incluida en el web.config y también en muchas ocasiones contiene los datos como el usuario y password para acceder a la base de datos.  De esta cadena de conexión y estos datos es de los que nos ayudaremos para implementar la autentificación en el reporte. Generalmente, la cadena de conexión se vería así <connectionStrings> <remove name="LocalSqlServer"/> <add name="xxx" connectionString="Data Source=.\SqlExpress;Integrated Security=False;Initial Catalog=xxx;user id=myuser;password=mypass" providerName="System.Data.SqlClient"/> </connectionStrings>   Para nuestro ejemplo, nombraremos a nuestra clase CrystalRules (es solo algo que pensé de momento) 1. Primer Paso Creamos una variable de tipo SqlConnectionStringBuilder, a la cual le asignaremos la cadena de conexión que definimos en el web.config, y que luego utilizaremos para obtener los datos del usuario y el password para el crystal report. SqlConnectionStringBuilder builder = new SqlConnectionStringBuilder(ConfigurationManager.ConnectionStrings["xxx"].ConnectionString); 2. Implementación de propiedad Para ser más ordenados crearemos varias propiedad de tipo Privado, que se encargarán de recibir los datos de:   La Base de datos, el password, el usuario y el servidor private string _dbName; private string _serverName; private string _userID; private string _passWord;   private string dataBase { get { return _dbName; } set { _dbName = value; } }   private string serverName { get { return _serverName; } set { _serverName = value; } }   private string userName { get { return _userID; } set { _userID = value; } }   private string dataBasePassword { get { return _passWord; } set { _passWord = value; } } 3. Creación del Método para aplicar los datos de conexión Una vez que ya tenemos las propiedades, asignaremos a las variables los valores que se han recogido en el SqlConnectionStringBuilder. Y crearemos una variable de tipo ConnectionInfo para aplicar los datos de conexión. internal void ApplyInfo(ReportDocument _oRpt) { dataBase = builder.InitialCatalog; serverName = builder.DataSource; userName = builder.UserID; dataBasePassword = builder.Password;   Database oCRDb = _oRpt.Database; Tables oCRTables = oCRDb.Tables; //Table oCRTable = default(Table); TableLogOnInfo oCRTableLogonInfo = default(TableLogOnInfo); ConnectionInfo oCRConnectionInfo = new ConnectionInfo();   oCRConnectionInfo.DatabaseName = _dbName; oCRConnectionInfo.ServerName = _serverName; oCRConnectionInfo.UserID = _userID; oCRConnectionInfo.Password = _passWord;   foreach (Table oCRTable in oCRTables) { oCRTableLogonInfo = oCRTable.LogOnInfo; oCRTableLogonInfo.ConnectionInfo = oCRConnectionInfo; oCRTable.ApplyLogOnInfo(oCRTableLogonInfo);     }   }   4. Creación del report document y aplicación de la seguridad Una vez recogidos los datos y asignados, crearemos un elemento report document al cual le asignaremos el CrystalReportViewer y le aplicaremos los datos de acceso que obtuvimos anteriormente public void loadReport(string repName, CrystalReportViewer viewer) {   // attached our report to viewer and set database login. ReportDocument report = new ReportDocument(); report.Load(HttpContext.Current.Server.MapPath("~/Reports/" + repName)); ApplyInfo(report); viewer.ReportSource = report; } Al final, nuestra clase completa ser vería así public class CrystalRules { SqlConnectionStringBuilder builder = new SqlConnectionStringBuilder(ConfigurationManager.ConnectionStrings["Fatchoy.Data.Properties.Settings.FatchoyConnectionString"].ConnectionString);   private string _dbName; private string _serverName; private string _userID; private string _passWord;   private string dataBase { get { return _dbName; } set { _dbName = value; } }   private string serverName { get { return _serverName; } set { _serverName = value; } }   private string userName { get { return _userID; } set { _userID = value; } }   private string dataBasePassword { get { return _passWord; } set { _passWord = value; } }   internal void ApplyInfo(ReportDocument _oRpt) { dataBase = builder.InitialCatalog; serverName = builder.DataSource; userName = builder.UserID; dataBasePassword = builder.Password;   Database oCRDb = _oRpt.Database; Tables oCRTables = oCRDb.Tables; //Table oCRTable = default(Table); TableLogOnInfo oCRTableLogonInfo = default(TableLogOnInfo); ConnectionInfo oCRConnectionInfo = new ConnectionInfo();   oCRConnectionInfo.DatabaseName = _dbName; oCRConnectionInfo.ServerName = _serverName; oCRConnectionInfo.UserID = _userID; oCRConnectionInfo.Password = _passWord;   foreach (Table oCRTable in oCRTables) { oCRTableLogonInfo = oCRTable.LogOnInfo; oCRTableLogonInfo.ConnectionInfo = oCRConnectionInfo; oCRTable.ApplyLogOnInfo(oCRTableLogonInfo);     }   }   public void loadReport(string repName, CrystalReportViewer viewer) {   // attached our report to viewer and set database login. ReportDocument report = new ReportDocument(); report.Load(HttpContext.Current.Server.MapPath("~/Reports/" + repName)); ApplyInfo(report); viewer.ReportSource = report; }       #region instance   private static CrystalRules m_instance;   // Properties public static CrystalRules Instance { get { if (m_instance == null) { m_instance = new CrystalRules(); } return m_instance; } }   public DataDataContext m_DataContext { get { return DataDataContext.Instance; } }     #endregion instance   }   Si bien, la solución no es robusta y no es la mas segura. En casos de uso como una intranet y cuando estamos contra tiempo, podría ser de gran ayuda.

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• Nuevo Video del Curso Introducción a C# con Visual Studio 2012

  - by carlone

  Estimad@s Amig@s, Ya se encuentra publicado un Nuevo video del curso Introducción a C# con Visual Studio 2012.  13:3211WATCHEDIntroducción a C# con Visual Studio 2012: Estructuras Cíclicas (Bucle For)by Carlos Lone 35 viewsEn este video daremos una introducción al concepto de las estructuras cíclicas y aprenderemos a utilizar el Bucle For  El código de los ejemplos utilizados pueden descargarlos en https://latamcsharpvs2012.codeplex.com/ Saludos, Carlos A. Lone  

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• Presentaciones del Customers Day sobre PeopleSoft

  - by [email protected]

  Por petición de los asistentes al Customers Day sobre PeopleSoft, celebrado el pasado 11 de marzo de 2010, ponemos a su disposición las presentaciones que tuvieron lugar durante el evento. Los siguientes enlaces recoge cada una de las presentaciones. Además, también puede verlas a través de las presentaciones integradas que hay más abajo. Aplicaciones Analíticas de RRHH Migración en Entornos PeopleSoft Presentacion PSFT Customers Day 1 Aplicaciones Analiticas de RRHHView more presentations from oracledirect. Presentacion PSFT Customers Day 2 Migracion en Entornos PeopleSoftView more presentations from oracledirect.

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• Soluciones Oracle para Servicios Sociales: Demo "El Ciudadano"

  - by alvaro.desantiago(at)oracle.com

  Las Soluciones Oracle mejoran la ejecución de los programas sociales de las Administraciones y el resultado obtenido por los ciudadanos. La Solución Oracle para Servicios Sociales permite a las Administraciones Públicas optimizar los resultados de las políticas sociales y maximizar la tasa de participación, através de la implantación de Siebel Case Management y Oracle Policy Automation.Les facilita, asimismo, compartir una visión única del ciudadano, gestionar los continuos cambios de políticas de mejora de los programas sociales y su prestación directa a los interesados.Oracle proporciona la solución de Servicios Sociales, para una variedad de áreas como son Beneficios Sociales, Empleo, Violencia de Género y Protección al Menor.

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• R in a Nutshell de Joseph Adler, critique par ced

  Bonjour, La rédaction de DVP a lu pour vous l'ouvrage suivant: R in a Nutshell, de Joseph Adler. paru aux éditions O'Reilly. [IMG]http://covers.oreilly.com/images/9780596801717/lrg.jpg[/IMG] Citation: R is rapidly becoming the standard for developing statistical software, and R in a Nutshell provides a quick and practical way to learn this increasingly popular open source language and environment. You'll not only learn how to program in R, but al...

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