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  • most widely used python web app deployment style

    - by mete
    I wonder which option is more stable (leaving performance aside) and is more widely used (I assume the widely used one is the most stable): apache - mod_wsgi apache - mod_fcgid apache - mod_proxy_ajp apache - mod_proxy_http for a project that will serve REST services with small json formatted input and output messages and web pages, up to 100 req/s. Please comment on apache if you think nginx etc. is more suitable. Thanks.

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  • Iterating through a range of dates in Python

    - by ShawnMilo
    This is working fine, but I'm looking for any feedback on how to do it better. Right now I think it's better than nested loops, but it starts to get Perl-one-linerish when you have a generator in a list comprehension. Any suggestions are welcome. day_count = (end_date - start_date).days + 1 for single_date in [d for d in (start_date + timedelta(n) for n in range(day_count)) if d <= end_date]: print strftime("%Y-%m-%d", single_date.timetuple()) Notes: I'm not actually using this to print; that's just for demo purposes. The variables start_date and end_date are datetime.date objects, because I don't need the timestamps (they're going to be used to generate a report). I checked the StackOverflow questions which were similar before posting this, but none were exactly the same. Sample Output (for a start date of 2009-05-30 and an end date of 2009-06-09): 2009-05-30 2009-05-31 2009-06-01 2009-06-02 2009-06-03 2009-06-04 2009-06-05 2009-06-06 2009-06-07 2009-06-08 2009-06-09

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  • Python finding repeating sequence in list of integers?

    - by tijko
    I have a list of lists and each list has a repeating sequence. I'm trying to count the length of repeated sequence of integers in the list: list_a = [111,0,3,1,111,0,3,1,111,0,3,1] list_b = [67,4,67,4,67,4,67,4,2,9,0] list_c = [1,2,3,4,5,6,7,8,9,0,1,2,3,4,5,6,7,8,9,0,23,18,10] Which would return: list_a count = 4 (for [111,0,3,1]) list_b count = 2 (for [67,4]) list_c count = 10 (for [1,2,3,4,5,6,7,8,9,0]) Any advice or tips would be welcome. I'm trying to work it out with re.compile right now but, its not quite right.

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  • Python: How should I make instance variables available?

    - by swisstony
    Suppose I have: class myclass: def __init__(self): self.foo = "bar" where the value of foo needs to be available to users of myclass. Is it OK to just read the value of foo directly from an instance of myclass? Should I add a get_foo method to myclass or perhaps add a foo property? What's the best practice here?

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  • Manipulating Directory Paths in Python

    - by G Ullman
    Basically I've got this current url and this other key that I want to merge into a new url, but there are three different cases. Suppose the current url is localhost:32401/A/B/foo if key is bar then I want to return localhost:32401/A/B/bar if key starts with a slash and is /A/bar then I want to return localhost:32401/A/bar finally if key is its own independent url then I just want to return that key = htt p://foo.com/bar - http://foo.com/bar I assume there is a way to do at least the first two cases without manipulating the strings manually, but nothing jumped out at me immediately in the os.path module.

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  • python: importing modules with incorrect import statements => unexhaustive info from resulting Impor

    - by bbb
    Hi there, I have a funny problem I'd like to ask you guys ('n gals) about. I'm importing some module A that is importing some non-existent module B. Of course this will result in an ImportError. This is what A.py looks like import B Now let's import A >>> import A Traceback (most recent call last): File "<stdin>", line 1, in <module> File "/tmp/importtest/A.py", line 1, in <module> import B ImportError: No module named B Alright, on to the problem. How can I know if this ImportError results from importing A or from some corrupt import inside A without looking at the error's string representation. The difference is that either A is not there or does have incorrect import statements. Hope you can help me out... Cheers bb

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  • Need help in writting re in python

    - by laspal
    Hi, My string is mystring = "<tr><td><span class='para'><b>Total Amount : </b>INR (Indian Rupees) 100.00</span></td></tr>" My problem here is I have to search and get the total amount test = re.search("(Indian Rupees)(\d{2})(?:\D|$)", mystring) but my test give me None. How can I get the values and values can be 10.00, 100.00, 1000.00 Thanks

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  • Overriding Built-in Classes (Python)

    - by Yipeng
    How can I view and override the full definition for built in classes? I have seen the library docs but am looking for something more. For e.g. is it possible to override the Array Class such that the base index starts from 1 instead of 0, or to override .sort() of list to a sorting algorithm of my own liking?

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  • Testing variable types in Python

    - by Jasper
    Hello, I'm creating an initialising function for the class 'Room', and found that the program wouldn't accept the tests I was doing on the input variables. Why is this? def __init__(self, code, name, type, size, description, objects, exits): self.code = code self.name = name self.type = type self.size = size self.description = description self.objects = objects self.exits = exits #Check for input errors: if type(self.code) != type(str()): print 'Error found in module rooms.py!' print 'Error number: 110' elif type(self.name) != type(str()): print 'Error found in module rooms.py!' print 'Error number: 111' elif type(self.type) != type(str()): print 'Error found in module rooms.py!' print 'Error number: 112' elif type(self.size) != type(int()): print 'Error found in module rooms.py!' print 'Error number: 113' elif type(self.description) != type(str()): print 'Error found in module rooms.py!' print 'Error number: 114' elif type(self.objects) != type(list()): print 'Error found in module rooms.py!' print 'Error number: 115' elif type(self.exits) != type(tuple()): print 'Error found in module rooms.py!' print 'Error number: 116' When I run this I get this error: Traceback (most recent call last): File "/Users/Jasper/Development/Programming/MyProjects/Game Making Challenge/Europa I/rooms.py", line 148, in <module> myRoom = Room(101, 'myRoom', 'Basic Room', 5, '<insert description>', myObjects, myExits) File "/Users/Jasper/Development/Programming/MyProjects/Game Making Challenge/Europa I/rooms.py", line 29, in __init__ if type(self.code) != type(str()): TypeError: 'str' object is not callable

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  • Appending item to lists - python

    - by ariel
    I have a list lets say a=[[1,2],[3,4],[5,6]]. I want to add to each item in a the char 'a'. when I use a=[x.append('a') for x in a] it return [None,None,None]. But if I use a1=[x.append('a') for x in a] then it do someting odd. a and not a1 is [[1,2,a],[3,4,a],[5,6,a]]. I don't understand why the first return [None, None, None] nor why the second works on a.

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  • Serialize the @property methods in a Python class.

    - by ashchristopher
    Is there a way to have any @property definitions passed through to a json serializer when serializing a Django model class? example: class FooBar(object.Model) name = models.CharField(...) @property def foo(self): return "My name is %s" %self.name Want to serialize to: [{ 'name' : 'Test User', 'foo' : 'My name is Test User', },]

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  • python equivalent of filter() getting two output lists

    - by FX
    Let's say I have a list, and a filtering function. Using something like >>> filter(lambda x: x > 10, [1,4,12,7,42]) [12, 42] I can get the elements matching the criterion. Is there a function I could use that would output two lists, one of elements matching, one of the remaining elements? I could call the filter() function twice, but that's kinda ugly :) Edit: the order of elements should be conserved, and I may have identical elements multiple times.

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  • Python : Convert from C-Char to Int

    - by cuband
    I have a string read in from a binary file that is unpacked using struct.unpack as a string of length n. Each byte in the string is a single integer (1-byte) representing 0-255. So for each character in the string I want to convert it to an integer. I can't figure out how to do this. Using ord doesn't seem to be on the right track...

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  • Python - creating a list with 2 characteristics bug

    - by user2733911
    The goal is to create a list of 99 elements. All elements must be 1s or 0s. The first element must be a 1. There must be 7 1s in total. import random import math import time # constants determined through testing generation_constant = 0.96 def generate_candidate(): coin_vector = [] coin_vector.append(1) for i in range(0, 99): random_value = random.random() if (random_value > generation_constant): coin_vector.append(1) else: coin_vector.append(0) return coin_vector def validate_candidate(vector): vector_sum = sum(vector) sum_test = False if (vector_sum == 7): sum_test = True first_slot = vector[0] first_test = False if (first_slot == 1): first_test = True return (sum_test and first_test) vector1 = generate_candidate() while (validate_candidate(vector1) == False): vector1 = generate_candidate() print vector1, sum(vector1), validate_candidate(vector1) Most of the time, the output is correct, saying something like [1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 0, 1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0] 7 True but sometimes, the output is: [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0] 2 False What exactly am I doing wrong?

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  • How to reverse a dictionary that it has repeated values (python)

    - by Galois
    Hi guys! So, I have a dictionary with almost 100,000 (key, values) pairs and the majority of the keys map to the same values. For example imagine something like that: dict = {'a': 1, 'c': 2, 'b': 1, 'e': 2, 'd': 3, 'h': 1, 'j': 3} What I want to do, is to reverse the dictionary so that each value in dict is going to be a key at the reverse_dict and is going to map to a list of all the dict.keys that used to map to that value at the dict. So based on the example above I would get: reversed_dict = {1: ['a', 'b', 'h'], 2:['e', 'c'] , 3:['d', 'j']} I came up with a solution that is very expensive and I would really want to hear any ideas more efficient than mine. my expensive solution: reversed_dict = {} for value in dict.values(): reversed_dict[value] = [] for key in dict.keys(): if dict[key] == value: if key not in reversed_dict[value]: reversed_dict[value].append(key) Output >> reversed_dict = {1: ['a', 'b', 'h'], 2: ['c', 'e'], 3: ['d', 'j']} I would really appreciate to hear any ideas better and more efficient than than mine. Thanks!

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  • regex in python, can this be improved upon?

    - by tipu
    I have this piece of code that finds words that begin with @ or #, p = re.findall(r'@\w+|#\w+', str) Now what irks me about this is repeating \w+. I am sure there is a way to do something like p = re.findall(r'(@|#)\w+', str) That will produce the same result but it doesn't, it instead returns only # and @. How can that regex be changed so that I am not repeating the \w+? This code comes close, p = re.findall(r'((@|#)\w+)', str) But it returns [('@many', '@'), ('@this', '@'), ('#tweet', '#')] (notice the extra '@', '@', and '#'.

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