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  • bulls and cows game -- programming algorithm(python)

    - by IcyFlame
    This is a simulation of the game Cows and Bulls with three digit numbers I am trying to get the number of cows and bulls between two numbers. One of which is generated by the computer and the other is guessed by the user. I have parsed the two numbers I have so that now I have two lists with three elements each and each element is one of the digits in the number. So: 237 will give the list [2,3,7]. And I make sure that the relative indices are maintained.the general pattern is:(hundreds, tens, units). And these two lists are stored in the two lists: machine and person. ALGORITHM 1 So, I wrote the following code, The most intuitive algorithm: cows and bulls are initialized to 0 before the start of this loop. for x in person: if x in machine: if machine.index(x) == person.index(x): bulls += 1 print x,' in correct place' else: print x,' in wrong place' cows += 1 And I started testing this with different type of numbers guessed by the computer. Quite randomly, I decided on 277. And I guessed 447. Here, I got the first clue that this algorithm may not work. I got 1 cow and 0 bulls. Whereas I should have got 1 bull and 1 cow. This is a table of outputs with the first algorithm: Guess Output Expected Output 447 0 bull, 1 cow 1 bull, 1 cow 477 2 bulls, 0 cows 2 bulls, 0 cows 777 0 bulls, 3 cows 2 bulls, 0 cows So obviously this algorithm was not working when there are repeated digits in the number randomly selected by the computer. I tried to understand why these errors are taking place, But I could not. I have tried a lot but I just could not see any mistake in the algorithm(probably because I wrote it!) ALGORITHM 2 On thinking about this for a few days I tried this: cows and bulls are initialized to 0 before the start of this loop. for x in range(3): for y in range(3): if x == y and machine[x] == person[y]: bulls += 1 if not (x == y) and machine[x] == person[y]: cows += 1 I was more hopeful about this one. But when I tested this, this is what I got: Guess Output Expected Output 447 1 bull, 1 cow 1 bull, 1 cow 477 2 bulls, 2 cows 2 bulls, 0 cows 777 2 bulls, 4 cows 2 bulls, 0 cows The mistake I am making is quite clear here, I understood that the numbers were being counted again and again. i.e.: 277 versus 477 When you count for bulls then the 2 bulls come up and thats alright. But when you count for cows: the 7 in 277 at units place is matched with the 7 in 477 in tens place and thus a cow is generated. the 7 in 277 at tens place is matched with the 7 in 477 in units place and thus a cow is generated.' Here the matching is exactly right as I have written the code as per that. But this is not what I want. And I have no idea whatsoever on what to do after this. Furthermore... I would like to stress that both the algorithms work perfectly, if there are no repeated digits in the number selected by the computer. Please help me with this issue. P.S.: I have been thinking about this for over a week, But I could not post a question earlier as my account was blocked(from asking questions) because I asked a foolish question. And did not delete it even though I got 2 downvotes immediately after posting the question.

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  • Shell halts while looping and 'transforming' values in dictionary (Python 2.7.5)

    - by Gus
    I'm building a program that will sum digits in a given list in a recursive way. Say, if the source list has 10 elements, the second list will have 9, the third 8 and so on until the last list that will have only one element. This is done by adding the first element to the second, then the second to the third and so on. I'm stuck without feedback from the shell. It halts without throwing any errors, then in a couple of seconds the fan is spinning like crazy. I've read quite a few posts here and changed my approach, but I'm not sure that what have so far can produce the results I'm looking for. Thanks in advance: #--------------------------------------------------- #functions #--------------------------------------------------- #sum up pairs in a list def reduce(inputList): i = 0 while (i < len(inputList)): #ref to current and next item j = i + 1 #don't go for the last item if j != len(inputList): #new number eq current + next number newNumber = inputList[i] + inputList[j] if newNumber >= 10: #reduce newNumber to single digit newNumber = sum(map(int, str(newNumber))) #collect into temp list outputList.append(newNumber) i = i + 1 return outputList; #--------------------------------------------------- #program starts here #--------------------------------------------------- outputList = [] sourceList = [7, 3, 1, 2, 1, 4, 6] counter = len(sourceList) dict = {} dict[0] = sourceList print '-------------' print 'Level 0:', dict[0] for i in range(counter): j = i + 1 if j != counter: baseList = dict.get(i) #check function to understand what it does newList = reduce(baseList) #new key and value from previous/transformed value dict[j] = newList print 'Level %d: %s' % (j, dict[j])

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  • Python: Random integer

    - by user3696440
    I been hitting a wall thats been keeping me from tinkering on a game. class Damage: def shortsword(): shortsword=randint(1,6)+1 shortsword=int(shortsword) return shortsword I been wanting this number to pop up as part of a message on print and then use the same number as part of another function to help with subtracting of health on the target. Though each time I grab this it is always going to change.

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  • python check value not in unicode list

    - by John
    Hi, I have a list and a value and want to check if the value is not in the list. list = [u'first record', u'second record'] value = 'first record' if value not in list: do something however this is not working and I think it has something to do with the list values having a u at the start, how can I fix this? And before someone suggests the list is returned from Django queryset so I can't just take the u out of the code :) Thanks

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  • Python | How to append elements to a list randomly

    - by MMRUser
    Is there a way to append elements to a list randomly, built in function ex: def random_append(): lst = ['a'] lst.append('b') lst.append('c') lst.append('d') lst.append('e') return print lst this will out put ['a', 'b', 'c', 'd', 'e'] But I want it to add elements randomly and out put something like this: ['b', 'd', 'b', 'e', 'c'] And yes there's a function random.shuffle() but it shuffles a list at once which I don't require, I just want to perform random inserts only.

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  • Python how to convert this for loop into a while loop

    - by user1690198
    I have this for a for loop which I made I was wondering how I would write so it would work with a while loop. def scrollList(myList): negativeIndices=[] for i in range(0,len(myList)): if myList[i]<0: negativeIndices.append(i) return negativeIndices So far I have this def scrollList2(myList): negativeIndices=[] i= 0 length= len(myList) while i != length: if myList[i]<0: negativeIndices.append(i) i=i+1 return negativeIndices

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  • Python 2.7 creating a multidimensional list

    - by poop
    I don't know why I am having so much trouble creating a 3 dimensional list. I need the program to create an empty n by n list. So for n = 4: x = [[[],[],[],[]],[[],[],[],[]],[[],[],[],[]],[[],[],[],[]]] I've tried using: y = [n*[n*[]]] y = [[[]]* n for i in range(n)] Which both appear to be creating copies of a reference. I've also tried naieve application of the list builder with little success: y = [[[]* n for i in range(n)]* n for i in range(n)] y = [[[]* n for i in range(1)]* n for i in range(n)] I've also tried building up the array iteratively using loops, with no success. In my rapid flurry of attempts to not post something stupidly easy to SO, I came upon a solution: y = [] for i in range(0,n): y.append([[]*n for i in range(n)]) Is there an easier/ more intuitive way of doing this?

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  • Problem with python !!

    - by the-ifl
    Well I Have a little problem , i want to Get the sum of all numbers below to 1000000 , and who has 4 Divisors... I Try but i have a problem : http://pastebin.com/bhiDb5fe

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  • Reading from CSVs in Python repeatedly?

    - by matt
    I'm trying to check the value of extracted data against a csv I already have. It will only loop through the rows of the CSV once, I can only check one value of feed.items(). Is there a value I need to reset somewhere? Is there a better/more efficient way to do this? Thanks. orig = csv.reader(open("googlel.csv", "rb"), delimiter = ';') goodrows = [] for feed in gotfeeds: for link,comments in feed.items(): for row in orig: print link if link in row[1]: row.append(comments) goodrows.append(row)

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  • Invoking a function of library libfprint in Python

    - by Ivanelson
    I need help to call a function(Struct C) that detects the devices, so I'm calling the function this way: from ctypes import * fp = CDLL('./libfprint.so.0') fp.fp_discover_devs.argtypes = None fp.fp_discover_devs.restype = c_char_p ret = fp.fp_discover_devs() print ret # is "0" That is not detected any device, because the return is "0". See the documentation of the function: I'm using Ubuntu and I downloaded the "fprint_demo" and works perfectly. Did you install any package missing? Thanks.

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  • Python: Sort a dictionary by value

    - by the empirical programmer
    I have a dictionary of values read from 2 fields in a database: a string field and a numeric field. The string field is unique so that is the key of the dictionary. I can sort on the keys, but how can I sort based on the values? Note: I have read this post 72899 and probably could change my code to have a list of dictionaries but since I do not really need a list of dictionaries I wanted to know if there a simpler solution.

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  • good practice for string.partition in python

    - by user1544915
    some case i write code like these: a,temp,b = s.partition('-') i just need to pick the first and 3rd element. temp would never be used. is there a better way to do this? the common case is ,a better way to pick separted element to make a new list? for example i want to make a new list use old list 0,1,3,7 element code would be this: newlist = [oldlist[0],oldlist[1],oldlist[3],oldlist[7]] it's pretty ugly,isn't it?

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  • (Python) Extracting Text from Source Code?

    - by zhuyxn
    Currently have a large webpage whose source code is ~200,000 lines of almost all (if not all) HTML. More specifically, it is a webpage whose content is a few thousand blocks of paragraphs separated by line breaks (though a line break does not specifically mean there is a separation in content) My main objective is to extract text from the source code as if I were copying/pasting the webpage into a text editor. There is another parsing function I would like to use, which originally took in copied/pasted text rather than the source code. To do this, I'm currently using urllib2, and calling .get_text() in Beautiful Soup. The problem is, Beautiful Soup is leaving tremendous amounts of white space in my code, and it is difficult to pass the result into the second "text" parser. I have done quite a bit of research on parsing HTMLs, but I'm frankly not sure how to solve this problem easily. Furthermore, I'm a bit confused on how to use imports like lxml to extract text as if I were to simply copy and paste?

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  • check if a process is running in python

    - by shash
    I am trying to find if the process is running based on process id. The code is as follows based on one of the post on the forum. I cannot consider process name as there are more than one process running with the same name. def findProcess( processId ): ps= subprocess.Popen("ps -ef | grep "+processId, shell=True, stdout=subprocess.PIPE) output = ps.stdout.read() ps.stdout.close() ps.wait() return output def isProcessRunning( processId): output = findProcess( processId ) if re.search(processId, output) is None: return true else: return False Output : 1111 72312 72311 0 0:00.00 ttys000 0:00.00 /bin/sh -c ps -ef | grep 71676 1111 72314 72312 0 0:00.00 ttys000 0:00.00 grep 71676 It always return true as it can find the process id in the output string. Any suggestions? Thanks for any help.

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  • Python if statement not working as expected

    - by Chris Esposito
    I'm searching for a string in a website and checking to see if the location of this string is in the expected location. I know the string starts at the 182nd character, and if I print temp it will even tell me that it is 182, however, the if statement says 182 is not 182. Some code f = urllib.urlopen(link) #store page contents in 's' s = f.read() f.close() temp = s.find('lettersandnumbers') if (htmlsize == "197"): #if ((s.find('lettersandnumbers')) == "182"): if (temp=="182"): print "Glorious" doStuff() else: print "HTML not correct. Aborting." else: print htmlsize print "File size is incorrect. Aborting."

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  • Parsing groupings of strings (Python)

    - by j00niner
    I have a string that looks something like this: [["Name1","ID1","DDY1", "CALL1", "WHEN1"], ["Name2","ID2","DDY2", "CALL2", "WHEN2"],...]; This string was taking from a website. Their can be any amount of groupings. How could I parse this string and print just the Name variables of each grouping?

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  • Python: Determine whether list of lists contains a defined sequence

    - by duhaime
    I have a list of sublists, and I want to see if any of the integer values from the first sublist plus one are contained in the second sublist. For all such values, I want to see if that value plus one is contained in the third sublist, and so on, proceeding in this fashion across all sublists. If there is a way of proceeding in this fashion from the first sublist to the last sublist, I wish to return True; otherwise I wish to return False. In other words, for each value in sublist one, for each "step" in a "walk" across all sublists read left to right, if that value + n (where n = number of steps taken) is contained in the current sublist, the function should return True; otherwise it should return False. (Sorry for the clumsy phrasing--I'm not sure how to clean up my language without using many more words.) Here's what I wrote. a = [ [1,3],[2,4],[3,5],[6],[7] ] def find_list_traversing_walk(l): for i in l[0]: index_position = 0 first_pass = 1 walking_current_path = 1 while walking_current_path == 1: if first_pass == 1: first_pass = 0 walking_value = i if walking_value+1 in l[index_position + 1]: index_position += 1 walking_value += 1 if index_position+1 == len(l): print "There is a walk across the sublists for initial value ", walking_value - index_position return True else: walking_current_path = 0 return False print find_list_traversing_walk(a) My question is: Have I overlooked something simple here, or will this function return True for all true positives and False for all true negatives? Are there easier ways to accomplish the intended task? I would be grateful for any feedback others can offer!

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  • Python: Closing a for loop by reading stdout

    - by user1732102
    import os dictionaryfile = "/root/john.txt" pgpencryptedfile = "helloworld.txt.gpg" array = open(dictionaryfile).readlines() for x in array: x = x.rstrip('\n') newstring = "echo " + x + " | gpg --passphrase-fd 0 " + pgpencryptedfile os.popen(newstring) I need to create something inside the for loop that will read gpg's output. When gpg outputs this string gpg: WARNING: message was not integrity protected, I need the loop to close and print Success! How can I do this, and what is the reasoning behind it? Thanks Everyone!

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