Search Results

Search found 8344 results on 334 pages for 'count'.

Page 174/334 | < Previous Page | 170 171 172 173 174 175 176 177 178 179 180 181  | Next Page >

  • text overlay for tray icon

    - by AnC
    I have a simple tray icon using PyGTK's gtk.StatusIcon: import pygtk pygtk.require('2.0') import gtk statusIcon = gtk.StatusIcon() statusIcon.set_from_stock(gtk.STOCK_EDIT) statusIcon.set_tooltip('Hello World') statusIcon.set_visible(True) gtk.main() How can I add a text label (one or two characters; basically, unread count) to the tooltip - without creating separate images for set_from_file?

    Read the article

  • SQLite trigger to update Summary Counts

    - by jrhicks
    Consider the following two (hypothetical) tables Temperature * day * time * lake_name * station * temperature_f Temperature_summary * day * lake_name * station * count_readings_over_75f * count_readings_below_75f How can I write an SQLite Trigger to update the temperature_summary table on insert. I want to increment the count. Thank You, Jeff

    Read the article

  • SQL query to get most

    - by chama
    I have a database with the following tables: Employee (EmpID, FirstName, LastName, RegionID) EmployeeSkills(EmpID, SkillID) [this is a linking table for the M:N relationship between Employees and skills] Skills(SkillID, Description) I need to list the name of the skill that most employees have. I tried doing a max(count(skillID)), sqlserver said that you can't do an aggregate function on an aggregate function. Any other ideas? Thank you in advance!

    Read the article

  • YouTube .Net API - Not getting correct View Counts

    - by Ardman
    I've managed to plug away through the YouTube documentation, and have managed to successfully implement the majority of what I want to work. My question is, I get the video View count and it comes back lower than the actual video on YouTube. It was fine this morning and both showed correctly, but now my version is out by 4 views. Does anyone have any experience with this? Or can tell me if they update the values every 5/10/15/24 hours?

    Read the article

  • iPhone - Track three touches

    - by Striker
    Suppose you have three points of contact on the iPhone screen and one of those touches moves... The touchesMoved method will be invoked and the [[event touchesForView:self] count] will be equal to '3' because there are three touches for the event, but how can you distinguish between the touches? For example - find out whether it was the first, second, or third touch which moved? Thanks.

    Read the article

  • Trouble with arrays

    - by Ockonal
    Hi guys, I have such string in PHP: $data = '1;3;5;7;9'; And cycle: for ($i=0; $i < count($someArray); $i++) { // If $i == any number in $data } What is the faster way to compare $i from cycle with numbers in string. I have to check that cycle-counter is in string.

    Read the article

  • MySQL get variable from SELECT

    - by rlb.usa
    MySQL keeps saying my syntax is incorrect. I want to do this: DELIMITER $$ DROP PROCEDURE IF EXISTS `myprocedure` $$ CREATE DEFINER=`db`@`%` PROCEDURE `myprocedure`( var_name varchar(10) ) BEGIN /* syntax errors below */ DECLARE countTemp integer; SET countTemp=(SELECT COUNT(Name) FROM mytable WHERE Name= var_name); /* more stuff */ END $$ DELIMITER ; What's the correct syntax?

    Read the article

  • Selecting the 2nd row in sql

    - by Alex Chen
    I want to select the second row only from the table. From the ClientUserName column. SELECT ClientUserName, DestHost, count(DestHost) counts FROM #ProxyLog_record WHERE ClientUserName = (Select top 1 ClientUserName from #ProxyLog_count_2) GROUP BY ClientUserName, DestHost ORDER BY counts DESC The (Select top 1 ClientUserName from #ProxyLog_count_2) shows top 1 only but I need to get the 2nd data from that table. How can I do this?

    Read the article

  • Controling page number shwon in printing dialog

    - by Matthias Wandel
    I'm trying to implement printing a range of pages in c# While printing, the .net framework throws up a message box that says "Page # of document". This starts at 1, and counts up to the number of pages printed. If I'm printing pages 10-11, I want that count to start at 10, not 1. Is there a way to set the starting value? The logical thing would be if it started at PrinterSettings.FromPage, but it ignores that value.

    Read the article

  • length between 2 values

    - by alex
    In R, what is the most efficient way to count the length between 2 values. for example, i have vector x , which are all randomly choose from 1 to 100, how can i find out the length between the first"2" and first"40", x=(1,2,3,4,5,6,7,40,1,2,3,21,4,1,23,4,43,23,4,12,3,43,5,36,3,45,12,31,3,4,23,41,23,5,53,45,3,7,6,36) for this vector, the answer should be 5 and 6

    Read the article

  • How to treat 64-bit words on a CUDA device?

    - by pikkio
    Hi, I'd like to handle directly 64-bit words on the CUDA platform (eg. uint64_t vars). I understand, however, that addressing space, registers and the SP architecture are all 32-bit based. I actually found this to work correctly (on my CUDA cc1.1 card): __global__ void test64Kernel( uint64_t *word ) { (*word) <<= 56; } but I don't know, for example, how this affects registers usage and the operations per clock cycle count.

    Read the article

  • Generating SQL for website

    - by Ethan
    I am working on a webapplication How can i create SQL for the following Database Information User information Username - String Password - String Admin or Client - boolean Last login – Date/Time LogItem typeLogItem – String (Page name?) hitCount – int View PageURL UserID Transaction User – String DateTimeStamp SKU – int Purchase-boolean TransactionID-int Inventory information Sku number - int Item description - String Price to customer - double Count - in

    Read the article

  • Can a process have two pid's?

    - by limp_chimp
    I'm studying computer systems and I've made this very simple function which uses fork() to create a child process. fork() returns a pid_t that is 0 if it's a child process. But calling the getpid() function within this child process returns a different, nonzero pid. In the code I have below, is newPid only meaningful in the context of the program, and not to the operating system? Is it possibly only a relative value, measured against the pid of the parent? #include <stdio.h> #include <unistd.h> #include <sys/types.h> #include <string.h> #include <errno.h> #include <stdlib.h> void unixError(char* msg) { printf("%s: %s\n", msg, strerror(errno)); exit(0); } pid_t Fork() { pid_t pid; if ((pid = fork()) < 0) unixError("Fork error"); return pid; } int main(int argc, const char * argv[]) { pid_t thisPid, parentPid, newPid; int count = 0; thisPid = getpid(); parentPid = getppid(); printf("thisPid = %d, parent pid = %d\n", thisPid, parentPid); if ((newPid = Fork()) == 0) { count++; printf("I am teh child. My pid is %d, my other pid is %d\n", getpid(), newPid); exit(0); } printf("I am the parent. My pid is %d\n", thisPid); return 0; } Output: thisPid = 30050, parent pid = 30049 I am the parent. My pid is 30050 I am teh child. My pid is 30052, my other pid is 0 Lastly, why is the child's pid 2 higher than the parent's, and not 1? The difference between the main function's pid and its parent is 1, but when we create a child it increments the pid by 2. Why is that?

    Read the article

  • PHP looping through an array to fetch a value for each key from database (third normal form)

    - by zomboble
    I am building a system, mostly for consolidating learning but will be used in practice. I will try and verbally explain the part of the E-R diagram I am focusing on: Each cadet can have many uniformID's Each Uniform ID is a new entry in table uniform, so cadets (table) may look like: id | name | ... | uniformID 1 | Example | ... | 1,2,3 uniform table: id | notes | cadet 1 | Need new blahh | 1 2 | Some stuff needed | 1 3 | Whatever you like | 1 On second thought, looks like I wont need that third column in the db. I am trying to iterate through each id in uniformID, code: <?php $cadet = $_GET['id']; // set from URL $query = mysql_query("SELECT `uniformID` FROM `cadets` WHERE id = '$cadet' LIMIT 1") or die(mysql_error()); // get uniform needed as string // store it while ($row = mysql_fetch_array($query)) { $uniformArray = $row['uniformID']; } echo $uniformArray . " "; $exploded = explode(",", $uniformArray); // convert into an array // for each key in the array perform a new query foreach ($exploded as $key => $value) { $query(count($exploded)); $query[$key] = mysql_query("SELECT * FROM `uniform` WHERE `id` = '$value'"); } ? As I say, this is mainly for consolidation purposes but I have come up with a error, sql is saying: Fatal error: Function name must be a string in C:\wamp\www\intranet\uniform.php on line 82 line 82 is: $query[$key] = mysql_query("SELECT * FROM `uniform` WHERE `id` = '$value'"); I wasn't sure it would work so I tried it and now i'm stuck! EDIT: Thanks to everyone who has contributed to this! This is now the working code: foreach ($exploded as $key => $value) { //$query(count($exploded)); $query = mysql_query("SELECT * FROM `uniform` WHERE `id` = '$value'"); while ($row = mysql_fetch_array($query)) { echo "<tr> <td>" . $row['id'] . "</td> <td>" . $row['note'] . "</td> </tr>"; } } Added the while and did the iteration by nesting it in the foreach

    Read the article

  • Group by with ActiveRecord in Rails

    - by Adnan
    Hello, I have a the following table with rows: ================================================================ id | name | group1 | group2 | group3 | group4 | ================================================================ 1 | Bob | 1 | 0 | 0 | 1| ================================================================ 2 | Eric| 0 | 1 | 0 | 1| ================================================================ 3 | Muris | 1 | 0 | 1 | 1| ================================================================ 4 | Angela | 0 | 0 | 0 | 1| ================================================================ What would be the most efficient way to get the list with ActiveRecords ordered by groups and show their count like this: group1 (2) group2 (1) group3 (1) group4 (4) All help is appreciated.

    Read the article

  • criticle join query mysql

    - by Bharanikumar
    i have table country and having country name and country code, i have customer table having countomer mobile number like customer_mobile field values like 0044-123456798 , 0024-582654753 , 012-52686145 , i want to populate my country oce into combo, that country name should in customer table which country code count is high that country name should come in the dropdown list top , How to write the join query... Thanks

    Read the article

  • Django: GROUP BY two values

    - by AP257
    I would basically like to do the same as this question, but grouping by combinations of two values, rather than just one: SELECT player_type, team, COUNT(*) FROM players GROUP BY player_type, team; Does anyone know whether, and how, this is possible in Django? I'm using 1.2.

    Read the article

  • T-SQL Subquery Question

    - by Nick
    Hi, i have two queries. For each tuple of query1 i want to run query2. i dont want to use cursors. i tried several approaches using subqueries. query1: select distinct category, Count(category) as CategoryCount from mytable group by category query2: select top 3 Text, Title, Category from mytable where Category = '1' Category = '1' is a sample. the value should come from query1

    Read the article

  • How to combine these three sql queries into one?

    - by lam3r4370
    How to combine these two sql queries into one? SELECT DISTINCT * FROM rss WHERE MATCH(content,title) AGAINST ('$filter') SELECT COUNT(content) FROM rss WHERE MATCH(content,title) AGAINST ('$filters') And if the result is 0 from the above query - SELECT DISTINCT * FROM rss WHERE content LIKE '%$filters%' OR title LIKE '%$filters%'; $filter .= $row['filter']; $filters = $row['filter']; $filters may be more than one keyword

    Read the article

< Previous Page | 170 171 172 173 174 175 176 177 178 179 180 181  | Next Page >