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  • PHP: problem rendering large images (error 321)

    - by JP19
    Hi ... its me again with a php problem :) Following is part of my PHP script which is rendering JPEG images. ... $tf=$requested_file; $image_type="jpeg"; header("Content-type: image/${image_type}"); $CMD="\$image=imagecreatefrom${image_type}('$tf'); image${image_type}(\$image);"; eval($CMD); exit; ... There is no syntactical error, because above code is working fine for small images, but for large images, it gives: Error 321 (net::ERR_INVALID_CHUNKED_ENCODING): Unknown error. in the browser. To be sure, I created two images using imagemagick from same source image - one resized to 10% of original and other 90%. http://mostpopularsports.net/images/misc/ttt10.jpg works http://mostpopularsports.net/images/misc/ttt90.jpg gives Error 301 in the browser. There is a related question with solution posted by OP here Error writing content through Apache. but I cannot understand how to make the fix. Can someome help me with it? I have looked at the headers in Chrome. For the first request, everything is fine. For the second request - the request headers are all garbled. Both images are jpeg (as they are created from imagemagick. But still to be sure I checked): misc/ttt10.jpg: JPEG image data, JFIF standard 1.01 misc/ttt90.jpg: JPEG image data, JFIF standard 1.01 Finally, the way I fixed is, remove the Transfer-Encoding: chunked header from the response. [This header was sent by apache only when the data was large enough]. (I had an internal proxy, so did it in the proxy script - otherwise one may need to do it in apache settings). There were some good answers and I have selected the one that helped me solve the problem best. thanks JP

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  • Random syntactical error in my php code that I can't find

    - by user348538
    Ordinarily I hate coming here with newbie code questions but nobody can find the error with this code. Maybe you guys can :-) <?php defined('SYSPATH') or die('No direct script access.'); /** * to interact with photos * * @author Max Padraig Wolfgang Bucknell-Leahy */ class Model_Photos { private $apiKey = '12664498208a1380fe49fb1b5a238ef0'; private $secret = '03d43dee65a34513'; private $perms = 'read'; private $sigString = 'test'; private $apiSig = md5($_sigString); private $authArray = array('api_key' => $apiKey, 'perms' => $perms, 'api_sig' => $apiSig); private $authArrayImploded = implode('&', $authArray); private $authLink = 'http://www.flickr.com/services/auth/?' . $authArrayImploded; public function get_photos($number = 5) { if(file_exists(APPPATH . 'cache/main_cache.xml') { echo $authLink; } else { echo 'not so good'; /** */ } } } $class = new Model_Photos; $class->get_photos; the error is: Parse error: syntax error, unexpected '(', expecting ',' or ';' in /home/p14s9nnd/public_html/testing.php on line 15 Thank you in advance and sorry Regards, Max

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  • PHP - Find a string in file then show it's line number

    - by xZero
    I have an application which needs to open the file, then find string in it, and print a line number where is string found. For example, file example.txt contains few hashes: APLF2J51 1a79a4d60de6718e8e5b326e338ae533 EEQJE2YX 66b375b08fc869632935c9e6a9c7f8da O87IGF8R c458fb5edb84c54f4dc42804622aa0c5 APLF2J51 B7TSW1ZE 1e9eea56686511e9052e6578b56ae018 EEQJE2YX affb23b07576b88d1e9fea50719fb3b7 So, I want to PHP search for "1e9eea56686511e9052e6578b56ae018" and print out its line number, in this case 4. Please note that there are will not be multiple hashes in file. I found a few codes over Internet, but none seem to work. I tried this one: <?PHP $string = "1e9eea56686511e9052e6578b56ae018"; $data = file_get_contents("example.txt"); $data = explode("\n", $data); for ($line = 0; $line < count($data); $line++) { if (strpos($data[$line], $string) >= 0) { die("String $string found at line number: $line"); } } ?> It just says that string is found at line 0.... Which is not correct.... Final application is much more complex than that... After it founds line number, it should replace string which something else, and save changes to file, then goes further processing.... Thanks in advance :)

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  • js loading page message not working on php file

    - by eggman20
    Merry Christmas guys, I found a code that displays a loading message using a gif. It uses the onLoad="init()" in the body tag. It works fine on an HTML file but it doesn't when the file is in PHP. Do I need to change anything in here or this just won't work in a PHP file? here's the code: <body onLoad="init()"> <div id="loading" style="position:absolute; width:100%; text-align:center; top:300px;"> <img src="loading.gif" border=0></div> <script> var ld=(document.all); var ns4=document.layers; var ns6=document.getElementById&&!document.all; var ie4=document.all; if (ns4) ld=document.loading; else if (ns6) ld=document.getElementById("loading").style; else if (ie4) ld=document.all.loading.style; function init() { if(ns4){ld.visibility="hidden";} else if (ns6||ie4) ld.display="none"; } </script> <!-- Content here --> </body> Thanks in advance!!!

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  • PHP resizing PNGs results in corrupted files

    - by Robert
    I have a PHP script that resizes .jpg, .gif, and .png files to a bounding box. $max_width = 500; $max_height = 600; $filetype = $_FILES["file"]["type"]; $source_pic = "img/" . $idnum; if($filetype == "image/jpeg") { $src = imagecreatefromjpeg($source_pic); } else if($filetype == "image/png") { $src = imagecreatefrompng($source_pic); } else if($filetype == "image/gif") { $src = imagecreatefromgif($source_pic); } list($width,$height)=getimagesize($source_pic); $x_ratio = $max_width / $width; $y_ratio = $max_height / $height; if( ($width <= $max_width) && ($height <= $max_height) ) { $tn_width = $width; $tn_height = $height; } else if (($x_ratio * $height) < $max_height) { $tn_height = ceil($x_ratio * $height); $tn_width = $max_width; } else { $tn_width = ceil($y_ratio * $width); $tn_height = $max_height; } $tmp = imagecreatetruecolor($tn_width,$tn_height); imagecopyresampled($tmp,$src,0,0,0,0,$tn_width, $tn_height,$width,$height); $destination_pic = "img/thumbs/" . $idnum . "thumb"; if($filetype == "image/jpeg") { imagejpeg($tmp,$destination_pic,80); } else if($filetype == "image/png") { imagepng($tmp,$destination_pic,80); } else if($filetype == "image/gif") { imagegif($tmp,$destination_pic,80); } imagedestroy($src); imagedestroy($tmp); The script works fine with jpeg and gif but when running on a png the file will be corrupted. Is there anything special I need to use when working with a png? I have never worked with this sort of thing in PHP so I'm not very familiar with it.

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  • PHP Dom problem, how to insert html code in a particular div

    - by sala_7
    I am trying to replace the html code inside the div 'resultsContainer' with the html of $response. The result of my unsuccessful code is that the contents of 'resultsContainer' remain and the html of $response shows up on screen as text rather than being parsed as html. Finally, I would like to inject the content of $response inside 'resultContainer' without having to create any new div, I need this: <div id='resultsContainer'>Html inside $response here...</div> and NOT THIS: <div id='resultsContainer'><div>Html inside $response here...</div></div> // Set Config libxml_use_internal_errors(true); $doc = new DomDocument(); $doc->strictErrorChecking = false; $doc->validateOnParse = true; // load the html page $app = file_get_contents('index.php'); $doc->loadHTML($app); // get the dynamic content $response = file_get_contents('search.php'.$query); $response = utf8_decode($response); // add dynamic content to corresponding div $node = $doc->createElement('div', $response); $doc->getElementById('resultsContainer')->appendChild($node); // echo html snapshot echo $doc->saveHTML();

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  • PHP Pass Dynamic Array name to function

    - by Brad
    How do I pass an array key to a function to pull up the right key's data? // The array <?php $var['TEST1'] = Array ( 'Description' => 'This is a Description', 'Version' => '1.11', 'fields' => Array( 'ID' => array( 'type' => 'int', 'length' =>'11', 'misc' =>'auto_increment' ), 'DATA' => array( 'type' => 'varchar', ' length' => '255' ) ); $var['TEST2'] = Array ( 'Description' =? 'This is the 2nd Description', 'Version' => '2.1', 'fields' => Array( 'ID' => array( 'type' => 'int', 'length' =>'11', 'misc' =>'auto_increment' ), 'DATA' => array( 'type' => 'varchar', ' length' => '255' ) ) // The function <?php $obj = 'TEST1'; print_r($schema[$obj]); // <-- Fives me output. But calling the function doesn't. echo buildStructure($obj); /** * @TODO to add auto_inc support */ function buildStructure($obj) { $output = ''; $primaryKey = $schema["{$obj}"]['primary key']; foreach ($schema["{$obj}"]['fields'] as $name => $tag) // #### ERROR #### Invalid argument supplied for foreach() { $type = $tag['type']; $length = $tag['length']; $default = $tag['default']; $description = $tag['description']; $length = (isset($length)) ? "({$length})" : ''; $default = ($default == NULL ) ? "NULL" : $default; $output .= "`{$name}` {$type}{$length} DEFAULT {$default} COMMENT `{$DESCRIPTION}`, "; } return $output; }

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  • jQuery AJAX tabs + PHP

    - by ufw
    Hi, seems like I'm stuck with jQuery tabs. I'm trying to pass selected tab name to some php script but is seems like it doesn't get any data. This is how tabs normally work without any response from server side: http://pastebin.com/KBxj7p5k And this is how I try to pass the the current tab name to the server: $(document).ready(function() { $('ul.tabs li').css('cursor', 'pointer'); $('ul.tabs.tabs1 li').click(function(){ var thisClass = this.className.slice(0,2); $('div.t1').hide(); $('div.t2').hide(); $('div.t3').hide(); $('div.t4').hide(); $('div.' + thisClass).show('fast'); $('ul.tabs.tabs1 li').removeClass('tab-current'); $(this).addClass('tab-current'); var name = thisClass; var data = 'name='+name; $.ajax ({ type:"GET", url:"handler.php", data:data, success:function(html) { thisClass.html(html); } }); }); Thanks.

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  • "Ghost" values in PHP/Smarty.

    - by Kyle Sevenoaks
    I've been working on a site for a while changing the layout and skin of a webshop checkout process. I've noticed that if you go all the way through the process until the last page, then click the link to go back to the view products page, the delivery method price displays underneath the navigation buttons, until you refresh and it goes away again. I've downloaded both sourced from the browser (Chrome, but this bug applies to all browsers) and used a file difference tool to display the differences, the result being only: < error.html vs > normal.html 34c34 < <link href="gzip.php?file=167842c1496093fbcd391b41cf7b03da.css&time=1272272181" rel="Stylesheet" type="text/css"/> --- > <link href="gzip.php?file=167842c1496093fbcd391b41cf7b03da.css&time=1272272348" rel="Stylesheet" type="text/css"/> Which is just the way it zips up the CSS stylesheets. (afaik) Has anyone ever encountered such a problem, or anything similar? Normal: Error: I can't even hazard a guess as to what is causing this, at all. I've searched over Google for anything and come up with nothing. What could be causing this? The site in question is Euroworker.no. HTML @ Pastebin. Smarty snippet: {if !$CANONICAL} {canonical}{self}{/canonical} {/if} <link rel="canonical" href="{$CANONICAL}" /> <!-- Css includes --> {includeCss file="frontend/Frontend.css"} {includeCss file="backend/stat.css"} {if {isRTL}} {includeCss file="frontend/FrontendRTL.css"} {/if} {compiledCss glue=true nameMethod=hash} <!--[if lt IE 8]> <link href="stylesheet/frontend/FrontendIE.css" rel="Stylesheet" type="text/css"/> {if $ieCss} <link href="{$ieCss}" rel="Stylesheet" type="text/css"/> {/if} <![endif]--> Thanks.

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  • PHP Form multiple buttons

    - by Ken
    I have a form with 2 buttons, that depending on which is selected will either be deleted or edited from the database. Those are each individual pages using SQL statements (questionedit and questiondelete). However, when i press a button, nothing happens...Any Ideas Here is my javascript <script type="text/javascript"> function SelectedButton(button) { if(button == 'edit') { document.testedit_questionform.action ="testedit_questionedit.php"; } else if(button == 'delete') { document.testedit_questionform.action ="testedit_questiondelete.php"; } document.forms[].testedit_questionform.submit(); } </script> Here is my form (being echoed from a loop) <form name=\"testedit_questionform\" action=\"SelectedButton\" method=\"POST\"> <span class=\"grid_11 prefix_1\" id=\"\" > Question:<input type=\"text\" name=\"QuestionText\" style=\"width:588px; margin-left:10px;\" value=\"$row[0]\"/> <input type=\"button\" value=\"Edit\" name=\"Operation\"onclick=\"submitForm(\'edit\')\" /> <input type=\"button\" value=\"Delete\" name=\"Operation\"onclick=\"submitForm(\'delete\')\" /> <input type=\"hidden\" name=\"QId\" value=\"$row[3]\" /><br />"); </form>

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  • PHP - complete url parser help

    - by Mark
    I have been trying to find an effective url parser, php's own does not include subdomain or extension. On php.net a number of users had contributed and made this: function parseUrl($url) { $r = "^(?:(?P<scheme>\w+)://)?"; $r .= "(?:(?P<login>\w+):(?P<pass>\w+)@)?"; $r .= "(?P<host>(?:(?P<subdomain>[-\w\.]+)\.)?" . "(?P<domain>[-\w]+\.(?P<extension>\w+)))"; $r .= "(?::(?P<port>\d+))?"; $r .= "(?P<path>[\w/]*/(?P<file>\w+(?:\.\w+)?)?)?"; $r .= "(?:\?(?P<arg>[\w=&]+))?"; $r .= "(?:#(?P<anchor>\w+))?"; $r = "!$r!"; // Delimiters preg_match ( $r, $url, $out ); return $out; } Unfortunately it fails on paths with a '-' and I can't for the life of me workout how to amend it to accept '-' in the path name. Thanks

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  • Recommended approach for error handling with PHP and MYSQL

    - by iama
    I am trying to capture database (MYSQL) errors in my PHP web application. Currently, I see that there are functions like mysqli_error(), mysqli_errno() for capturing the last occurred error. However, this still requires me to check for error occurrence using repeated if/else statements in my php code. You may check my code below to see what I mean. Is there a better approach to doing this? (or) Should I write my own code to raise exceptions and catch them in one single place? What is the recommended approach? Also, does PDO raise exceptions? Thanks. function db_userexists($name, $pwd, &$dbErr) { $bUserExists = false; $uid = 0; $dbErr = ''; $db = new mysqli(SERVER, USER, PASSWORD, DB); if (!mysqli_connect_errno()) { $query = "select uid from user where uname = ? and pwd = ?"; $stmt = $db->prepare($query); if ($stmt) { if ($stmt->bind_param("ss", $name, $pwd)) { if ($stmt->bind_result($uid)) { if ($stmt->execute()) { if ($stmt->fetch()) { if ($uid) $bUserExists = true; } } } } if (!$bUserExists) $dbErr = $db->error(); $stmt->close(); } if (!$bUserExists) $dbErr = $db->error(); $db->close(); } else { $dbErr = mysqli_connect_error(); } return $bUserExists; }

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  • drawing graphs in php

    - by user434885
    i am using php to generate graphs from arrays. I wish to create multiple graphs on the same page as i need to design a summary report from answers extracted from a database. Currently i am using this code and am only able to get one single graph. what additions to the code do i need to make to get multiple graphs? <?php function draw_graph($values) { // Get the total number of columns we are going to plot $columns = count($values); // Get the height and width of the final image $width = 300; $height = 200; // Set the amount of space between each column $padding = 5; // Get the width of 1 column $column_width = $width / $columns ; // Generate the image variables $im = imagecreate($width,$height); $gray = imagecolorallocate ($im,0xcc,0xcc,0xcc); $gray_lite = imagecolorallocate ($im,0xee,0xee,0xee); $gray_dark = imagecolorallocate ($im,0x7f,0x7f,0x7f); $white = imagecolorallocate ($im,0xff,0xff,0xff); // Fill in the background of the image imagefilledrectangle($im,0,0,$width,$height,$white); $maxv = 0; // Calculate the maximum value we are going to plot for($i=0;$i<$columns;$i++)$maxv = max($values[$i],$maxv); // Now plot each column for($i=0;$i<$columns;$i++) { $column_height = ($height / 100) * (( $values[$i] / $maxv) *100); $x1 = $i*$column_width; $y1 = $height-$column_height; $x2 = (($i+1)*$column_width)-$padding; $y2 = $height; imagefilledrectangle($im,$x1,$y1,$x2,$y2,$gray_dark); } header ("Content-type: image/png"); imagepng($im); imagedestroy($im); } $values = array("23","32","35","57","12"); $values2 = array("123","232","335","157","102"); draw_graph($values2); draw_graph($values);//no output is coming draw_graph($values2);//no output is coming draw_graph($values);//no output is coming ?>

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  • Uploading File Problem in PHP on Drupal

    - by Nitz
    I don't know why but i had written clear cut code for uploading file in my page. i had written like this... on the client side. <form id="recipeform" onsubmit="return checkAll()" action="submit.php" method="post" class="niceform" enctype="multipart/form-data"> <input name="uploaded" type="file" /> And on submit.php... i am writting like this..... $target = "newupload/"; $target = $target . basename( $_FILES['uploaded']['name']) ; $ok=1; if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target)){ echo "The file ". basename( $_FILES['uploaded']['name']). " has been uploaded"; } else{ echo "Sorry, there was a problem uploading your file."; } simple code but then also i can't able to upload the file.. And i had made my webiste in Drupal. Thanks in advance. www.panchjanyacorp.com

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  • Can I use php SESSIONS in spotify apps?

    - by user1593846
    since PHP can't be used in Spotify apps directly I am using it on my server only, but I am having problems getting the sessions to work, is it possible to use sessions even? I want to use it to see if a user is registered in my database or not so I am doing it like this: session_start(); $query="SELECT * FROM user WHERE facebookID = {$fbid}"; $result = mysql_query($query) or die(mysql_error()); $row = mysql_fetch_array($result); $num_results = mysql_num_rows($result); if ($num_results > 0) { echo"THERE IS A USER!"; $row['facebookID'] = $_SESSION[fid]; } else { echo"THERE IS NO USER!"; } the authentication to the server works fine but the session does not seem to be working, on another PHP page witch is being called after the above code has been called with some ajax code I simply wanted to try this: session_start(); if(isset($_SESSION['fid'])) { echo"SESSION EXIST"; } else { echo"NO SESSION"; } anyways is there a special way to do this in Spotify apps or do I have to do this in some other way?

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  • forcing a download using PHP / jQuery

    - by Dirty-flow
    I know there are already many questions about forcing a download with PHP, but I can't find what I'm doing wrong and what should I do. I'm having an list with filenames, and I want to download one of them by clicking a button. My jQuery: $(".MappeDownload").on("click",function(e){ e.stopPropagation(); fileId=$(this).val() $.post("ajax/DownloadFile.php",{ id : fileId}) }) and on the server side I have a table with the file names and the file path. $sql = "SELECT vUploadPfad, vUploadOriginname FROM tabUpload WHERE zUploadId='$_POST[id]'"; $result = mysql_query($sql) or die(""); $file = mysql_fetch_array($result); $localfile = $file["vUploadPfad"]; $name=$file["vUploadOriginname"]; $fp = fopen($localfile, 'rb'); header("Cache-Control: "); header("Pragma: "); header("Content-Type: application/octet-stream"); header("Content-Length: " . filesize($localfile)); header("Content-Disposition: attachment; filename='".$name."';"); header("Content-Transfer-Encoding: binary\n"); fpassthru($fp); exit; The AJAX request is successful, I'm getting the right header(filesize, filename etc...) but the download are not starting.

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  • php while loop throwing a error over a $var < 10 statement

    - by William
    Okay, so for some reason this is giving me a error as seen here: http://prime.programming-designs.com/test_forum/viewboard.php?board=0 However if I take away the '&& $cur_row < 10' it works fine. Why is the '&& $cur_row < 10' causing me a problem? $sql_result = mysql_query("SELECT post, name, trip, Thread FROM (SELECT MIN(ID) AS min_id, MAX(ID) AS max_id, MAX(Date) AS max_date FROM test_posts GROUP BY Thread ) t_min_max INNER JOIN test_posts ON test_posts.ID = t_min_max.min_id WHERE Board=".$board." ORDER BY max_date DESC", $db); $num_rows = mysql_num_rows($sql_result); $cur_row = 0; while($row = mysql_fetch_row($sql_result) && $cur_row < 10) { $sql_max_post_query = mysql_query("SELECT ID FROM test_posts WHERE Thread=".$row[3].""); $post_num = mysql_num_rows($sql_max_post_query); $post_num--; $cur_row++; echo''.$cur_row.'<br/>'; echo'<div class="postbox"><h4>'.$row[1].'['.$row[2].']</h4><hr />' .$row[0]. '<br /><hr />[<a href="http://prime.programming-designs.com/test_forum/viewthread.php?thread='.$row[3].'">Reply</a>] '.$post_num.' posts omitted.</div>'; }

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  • PHP/Javascript: Restart Form Button Isn't Working, Code Insde

    - by Josh K
    Basically I want a confirmation box to pop up when they click the button asking if they sure they want to restart, if yes, then it destroys session and takes them to the first page. Heres what i got... echo "<form id=\"form\" name=\"form\" method=\"post\" action=\"nextpage.php\">\n"; echo " <input type=\"button\" name='restart' value='Restart' id='restart' onclick='restartForm()' />"; and for the script... <script type=\"text/javascript\"> <!-- function restartForm() { var answer = confirm('Are you sure you want to start over?'); if (answer) { form.action=\"firstpage.php\"; session_destroy(); form.submit(); } else alert ('Restart Cancelled'); } // -- </script>"; EDIT: Note that pressing the button brings up the confirm box, but if you click okay nothing happens sometimes. Sometimes if u click cancel it still submits the form (To the original action)

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  • PHP – Slow String Manipulation

    - by Simon Roberts
    I have some very large data files and for business reasons I have to do extensive string manipulation (replacing characters and strings). This is unavoidable. The number of replacements runs into hundreds of thousands. It's taking longer than I would like. PHP is generally very quick but I'm doing so many of these string manipulations that it's slowing down and script execution is running into minutes. This is a pain because the script is run frequently. I've done some testing and found that str_replace is fastest, followed by strstr, followed by preg_replace. I've also tried individual str_replace statements as well as constructing arrays of patterns and replacements. I'm toying with the idea of isolating string manipulation operation and writing in a different language but I don't want to invest time in that option only to find that improvements are negligible. Plus, I only know Perl, PHP and COBOL so for any other language I would have to learn it first. I'm wondering how other people have approached similar problems? I have searched and I don't believe that this duplicates any existing questions.

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  • Generating random thumbnails with PHP+FFMPEG

    - by MrGhost
    I am trying to generate thumbnails from movies using FFMPEG and the FFMPEG-PHP extension. My script works OK however takes 20 minutes just to generate 5-10 thumbnails! The script works by generating random numbers which are used as frame numbers later. All numbers generated are within the movies frame count. Can you work out why this script is taking 20 mins to finish? <?php //Dont' timeout set_time_limit(0); //Load the file (This can be any file - still takes ages) $mov = new ffmpeg_movie('1486460.mp4'); //Get the total frames within the movie $total_frames = $mov->getFrameCount(); //Loop 5 times to generate random frame times for ($i = 1; $i <= 5; ) { // Generate a number within 200 and the total number of frames. $frame = mt_rand(200,$total_frames); $getframe = $mov->getFrame($frame); // Check if the frame exists within the movie // If it does, place the frame number inside an array and break the current loop if($getframe){ $frames[$frame] = $getframe ; $i++; } } //For each frame found generate a thumbnail foreach ($frames as $key => $getframe) { $gd_image = $getframe->toGDImage(); imagejpeg($gd_image, "images/shot_".$key.'.jpeg'); imagedestroy($gd_image); echo $key.'<br/>'; } ?> The script SHOULD be generating frame numbers which are valid? Anything within START - END should be valid frame numbers? Yet the loop takes ages!

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  • How to give new life into a five years old, simple but reliable PHP form?

    - by Sam
    Hi all. I have a script in php 5.2. I want to use a simple form. I found something a programmer made for me about 5 years ago. When I use it, PHP outputs an error now unless I set register_long_arrays = On, then it works fine. On the PHP website, however, it says: Warning This feature has been DEPRECATED as of PHP 5.3.0. Relying on this feature is highly discouraged. It's recommended to turn them off, for performance reasons. Instead, use the superglobal arrays, like $_GET. Should I listen to PHP's warning, or just enable the option and keep using my old form happily? If the former, then how/where do I change this simple form, so it does not rely on the deprecated setting? Your answer is much appreciated. form.htm <html><body> <form method="POST" action="form_sent.php"> ... </form> </body></html> form_sent.php <html><body> <?php $email = $HTTP_POST_VARS[email]; $mailto = "[email protected]"; $mailsubj = "A Form was Sent from Website!"; $mailhead = "From: $email\n"; reset ($HTTP_POST_VARS); $mailbody = "Values submitted from web site form:\n"; while (list($key, $val) = each ($HTTP_POST_VARS)){$mailbody .= "$key : $val\n";} if (!eregi("\n",$HTTP_POST_VARS[email])) { mail($mailto, $mailsubj, $mailbody, $mailhead); } ?> <b>Form Sent. Thank you.</b> </body></html>

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  • Print table data mysql php

    - by Marcelo
    Hi people, i'm having a problem trying to print some data of a table. I'm new at this php mysql stuff but i think my code is right. Here it is: <html> <body> <h1>Lista de usuários</h1> <?php $host="localhost"; // Host name $username="root"; // Mysql username $password=""; // Mysql password $db_name="sabs"; // Database name $tbl_name="doador"; // Table name // Connect to server and select database. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); $sql="SELECT * FROM $tbl_name"; $result=mysql_query($sql); while($rows = mysql_fetch_array($result)){ echo $row['id'] . " " .$row['nome'] . " " . $row['sobrenome'] . " " . $row['email'] . " " . $row['login'] . " " . $row['senha'] . " " . $row['idade'] . " ". $row['peso'] . " " . $row['fuma'] . " " . $row['sexo'] . " " . $row['doencas']; echo "<BR/>"; } mysql_close(); ?> </body> </html> All columns of the echo command exist in my table in the database. Don't get why it's not printing those values. Thanks for the attention.

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  • Input html tag not parsing properly in php

    - by Akaash
    I have a database with names that I would like displayed in the form of a table with checkboxes. Everything works until I try to place the html tag into my php code. When I put the input tag in it gives me the error: Parse error: syntax error, unexpected T_STRING, expecting ',' or ';' I can't see where I would put a comma or semi colon. <form> <?php $name = $_POST['name']; $host = "mysql16.000webhost.com"; $user_name = "a1611480_akaash"; $pwd = "****"; $database_name = "a1611480_akaash"; $db = mysql_connect($host, $user_name, $pwd); mysql_select_db($database_name); $result = mysql_query("SELECT name FROM Sort"); $var = array(); while ($row = mysql_fetch_array($result)) { $var[] = $row['name']; } $unique = array_unique($var); foreach ($unique as $value) { echo "<p class = Body_text><label>$value</label> <input type="checkbox" name="name" value="$value" /> </p>\n"; } ?> </form>

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  • The different of SHA512 between openssl and php

    - by solomon_wzs
    Here is C code: #include <openssl/sha.h> #include <stdio.h> char *hash_sha512(char *data){ SHA512_CTX ctx; char *md=malloc(sizeof(char)*(SHA512_DIGEST_LENGTH+1)); SHA512_Init(&ctx); SHA512_Update(&ctx, data, strlen(data)); SHA512_Final(md, &ctx); md[SHA512_DIGEST_LENGTH]='\0'; return md; } int main(int argc, char *argv[]){ str=hash_sha512("GFLOuJnR19881218"); printf("%s\n", str); free(str); return 1; } The output: ?<?4????IIA[r?? ?#? 6p?8jD????J?b9?????^X? Here is PHP code: $hash=hash('sha512', 'GFLOuJnR19881218', TRUE); The output: ?<??4??j??II?-A[r???? ??#??D6p?8jD???????J?b9?????^X? The results of C code and PHP code are different, what is wrong with my code?

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  • PHP syntax for postgresql Mixed-case table names

    - by yam
    I have a code below: <?php require "institution.php" /* in this portion, query for database connection is executed, and */ $institution= $_POST['institutionname']; $sCampID = 'SELECT ins_id FROM institution where ins_name= '$institution' '; $qcampID = pg_query($sCampID) or die("Error in query: $query." . pg_last_error($connection)); /* this portion outputs the ins_id */ ?> My database before has no mixed-case table names, that's why when I run this query, it shows no error at all. But because I've changed my database for some reasons, and it contains now mixed-case table names, i have to change the code above into this one: $sCampID = 'SELECT ins_id FROM "Institution" where ins_name= '$institution' '; where the Institution has to be double quoted. The query returned parse error. When i removed this portion: where ins_name= '$institution', no error occured. My question is how do I solve this problem where the table name which contains a mixed-case letter and a value stored in a variable ($institution in this case) will be combined in a single select statement? Your answers and suggestions will be very much appreciated.

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