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  • C#, AES encryption check!

    - by Data-Base
    I have this code for AES encryption, can some one verify that this code is good and not wrong? it works fine, but I'm more concern about the implementation of the algorithm // Plaintext value to be encrypted. //Passphrase from which a pseudo-random password will be derived. //The derived password will be used to generate the encryption key. //Password can be any string. In this example we assume that this passphrase is an ASCII string. //Salt value used along with passphrase to generate password. //Salt can be any string. In this example we assume that salt is an ASCII string. //HashAlgorithm used to generate password. Allowed values are: "MD5" and "SHA1". //SHA1 hashes are a bit slower, but more secure than MD5 hashes. //PasswordIterations used to generate password. One or two iterations should be enough. //InitialVector (or IV). This value is required to encrypt the first block of plaintext data. //For RijndaelManaged class IV must be exactly 16 ASCII characters long. //KeySize. Allowed values are: 128, 192, and 256. //Longer keys are more secure than shorter keys. //Encrypted value formatted as a base64-encoded string. public static string Encrypt(string PlainText, string Password, string Salt, string HashAlgorithm, int PasswordIterations, string InitialVector, int KeySize) { byte[] InitialVectorBytes = Encoding.ASCII.GetBytes(InitialVector); byte[] SaltValueBytes = Encoding.ASCII.GetBytes(Salt); byte[] PlainTextBytes = Encoding.UTF8.GetBytes(PlainText); PasswordDeriveBytes DerivedPassword = new PasswordDeriveBytes(Password, SaltValueBytes, HashAlgorithm, PasswordIterations); byte[] KeyBytes = DerivedPassword.GetBytes(KeySize / 8); RijndaelManaged SymmetricKey = new RijndaelManaged(); SymmetricKey.Mode = CipherMode.CBC; ICryptoTransform Encryptor = SymmetricKey.CreateEncryptor(KeyBytes, InitialVectorBytes); MemoryStream MemStream = new MemoryStream(); CryptoStream CryptoStream = new CryptoStream(MemStream, Encryptor, CryptoStreamMode.Write); CryptoStream.Write(PlainTextBytes, 0, PlainTextBytes.Length); CryptoStream.FlushFinalBlock(); byte[] CipherTextBytes = MemStream.ToArray(); MemStream.Close(); CryptoStream.Close(); return Convert.ToBase64String(CipherTextBytes); } public static string Decrypt(string CipherText, string Password, string Salt, string HashAlgorithm, int PasswordIterations, string InitialVector, int KeySize) { byte[] InitialVectorBytes = Encoding.ASCII.GetBytes(InitialVector); byte[] SaltValueBytes = Encoding.ASCII.GetBytes(Salt); byte[] CipherTextBytes = Convert.FromBase64String(CipherText); PasswordDeriveBytes DerivedPassword = new PasswordDeriveBytes(Password, SaltValueBytes, HashAlgorithm, PasswordIterations); byte[] KeyBytes = DerivedPassword.GetBytes(KeySize / 8); RijndaelManaged SymmetricKey = new RijndaelManaged(); SymmetricKey.Mode = CipherMode.CBC; ICryptoTransform Decryptor = SymmetricKey.CreateDecryptor(KeyBytes, InitialVectorBytes); MemoryStream MemStream = new MemoryStream(CipherTextBytes); CryptoStream cryptoStream = new CryptoStream(MemStream, Decryptor, CryptoStreamMode.Read); byte[] PlainTextBytes = new byte[CipherTextBytes.Length]; int ByteCount = cryptoStream.Read(PlainTextBytes, 0, PlainTextBytes.Length); MemStream.Close(); cryptoStream.Close(); return Encoding.UTF8.GetString(PlainTextBytes, 0, ByteCount); } Thank you

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  • Moving from MySQL to MySQLi? I have the code here but I don't get it

    - by MuqMan
    I have posted the code there, please help me out as I am a newbie, I don't know much in terms of deprecation and stuff. <?php session_start(); include('settings.php'); $issub = $_POST['issub']; if($issub == "yes") { require('settings.php'); $dbcon = mysql_connect($dbhost, $dbuser, $dbpword); if(!dbcon) { die('Could not connect'.mysql_error()); } $selectdb = mysql_select_db($db, $dbcon); $formset = 'yes'; $val = 0; $user = trim($_POST['username'], ' '); $luser = mysql_real_escape_string($user); $password = $_POST['password']; $lpassword = mysql_real_escape_string($password); $selectdb; $userq = mysql_query("SELECT user FROM users WHERE user='".$luser."'"); $userresult = @mysql_result($userq, 0); //echo $userresult; if($userresult == $user) { $val = $val + 1; $usercorrect = 'yes'; } else { $usercorrect = 'no'; } $dbselect; $passwordq = mysql_query("SELECT password FROM users where user='".$luser."'"); $passresult = @mysql_result($passwordq, 0); if($passresult == sha1($password)) { $val = $val + 1; $passcorrect = 'yes'; } else { $passcorrect = 'no'; } if ($val == 2) { $_SESSION['loggedin'] = 'yes'; $_SESSION['uloggedin'] = $user; header('location: logged.php'); } }?> <?php ini_set('display_errors', 1); require('testinclude.php'); ?> <body> <div id="loginform"> <form action="/login.php" method="post" > <input type="hidden" name="issub" value="yes" /> <?php if($usercorrect == 'no') { echo '<span class="required"><i><small>The email address or password you entered is incorrect, please try again.</a></small></i></span>'; } ?> <br /> email: <?php if ($issub == 'yes') { if($user == null){ echo '<br /><span class="required"><i><small>Please enter your email address</a></small></i></span>'; } } ?> <br /><input type="text" name="username" id="usename" /> <br /> password: <br /><input type="password" name="password" id="password" /> <br /> <input type="submit" value="login" /> </form> <div> </body>

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  • expanding/collapsing div using jQuery

    - by Hristo
    I'm trying to expand and collapse a <div> by clicking some text inside the <div>. The behavior right now is very odd. For example, if I click the text after the <div> is expanded... the <div> will collapse and then expand again. Also, if I click somewhere inside the div after it is expanded, it will collapse again, and I think that is because I'm triggering the animation since the <div> being animated is inside the wrapper <div>. Here's the code: <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> <title>Insert title here</title> <!-- Links --> <link rel="stylesheet" type="text/css" href="style.css" /> <!-- Scripts --> <script type="text/javascript" src="jQuery.js"></script> <script> // document script $(function(){ // login box event handler $('#login').click(function() { $('#loginBox').toggle( function() { $('.loginBox').animate({ height: '150px' }, '1000' ); $('#username').show(); $('#password').hide(); $('#placeHolder').show(); }, function() { $('.loginBox').animate({ height: '50px' }, '1000' ); $('#username').hide(); $('#password').hide(); $('#placeHolder').hide(); } ); }); // username field focus and blur event handlers $('#username').focus(function() { if($(this).hasClass('placeHolder')){ $(this).val(''); $(this).removeClass('placeHolder'); } }); $('#username').blur(function() { if($(this).val() == '') { $(this).val('Username'); $(this).addClass('placeHolder'); } }); // password field focus and blur event handlers $('#placeHolder').focus(function() { $(this).hide(); $('#password').show(); $('#password').focus(); $('#password').removeClass('placeHolder'); }); $('#password').blur(function() { if($(this).val() == '') { $('#placeHolder').show(); $(this).hide(); } }); }); </script> </head> <body> <div id="loginBox" class="loginBox"> <a id="login" class="login">Proceed to Login</a><br /> <div> <form> <input type="text" id="username" class="placeHolder" value="Username" /> <input type="password" id="password" class="placeHolder" value="" /> <input type="text" id="placeHolder" class="placeHolder" value="Password" /> </form> </div> </div> </body> </html> Any ideas? Thanks, Hristo

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  • Multi tenant membership provider ASP.NET MVC

    - by Masna
    Hello, I'm building a multi-tenant app with ASP.NET MVC and have a problem with validating users. Situation I have: -a table with User(ID, Name, FirstName, Email) This table is made, so that a users who is registered in two tenants doesn't need to login again. -a table with Tentantuser(ID, TenantID, UserID (FK to table User), UserName, Loginname, Password, Active) This table contains de login en password for one tenant. Example: UserX is registered in TenantA and TenantB UserX logs in on TenantA, with his login and password for TenantA System verifies or login and password are correct in the table TenantUser System validates UserX which userID corresponds to the Id in the table User UserX goes to TenantB and is automatically logged in My problem: How can I create a custom Provider so I can check the login & password in a tenant? For example: public abstract bool ValidateUser(string username,string password); How can I say to my provider on which tenant the user is? How can I change this in something like: public overrides bool ValidateUser(string username,string password, string tenant); ? Or what is another way to solve this issue?

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  • Android SDK Manager and AVD Manager doesn't have the correct information and fails to update on Ubun

    - by Johan Carlsson
    I'm trying to install Android SDK on Ubuntu but fail when I try to use the SDK Manager and AVD Manager to install Android platforms. I've downloaded: android-sdk_r04-linux_86.tgz The I start the SDK Manager and AVD Manager (UI) according to the README file: ./tools/android And I get the following Installed Packages: - Install SDK Tools, revision 4 Available Packages: - https://dl-ssl.google.com/android/repoisotry/repository.xml - This repository requires a more recent version of the Tools. Please update- - Android SDK Tools, revision 4 - Archive for Linux (comment: funny since rev 4 seems to be what's installed this is what seems to be installed) Now doing an update of the Android SDK Tools, revision 4 or everything results in 99% progress and then the application hangs. Here's the console feedback: johanc@johan-desktop:~/android/android-sdk-linux_86$ tools/android Starting Android SDK and AVD Manager No command line parameters provided, launching UI. See 'android --help' for operations from the command line. Error: null In the app I choose to upgate the following package: Package Description Android SDK Tools, revision 4 Archive Description Archive for Linux Size: 15 MiB SHA1: 99380c9330c1c3728c836206947350cc00fa28c2 Site https://dl-ssl.google.com/android/repository/repository.xml The console output reads (and the app hangs at 99%): Exception in thread "Installing Archives" java.lang.AssertionError at com.android.sdkuilib.internal.tasks.ProgressTask.incProgress(ProgressTask.java:97) at com.android.sdkuilib.internal.repository.UpdaterData$2.run(UpdaterData.java:358) at com.android.sdkuilib.internal.tasks.ProgressTask$1.run(ProgressTask.java:135)

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  • ASP.NET MVC Page - hyper links in HTML.ValidationSummary

    - by Rita
    Hi I have Registration page and if the validation fails, it displays the error messages using HTML.ValidationSummary control. Now i have to display the Hyperlink in that Validation Error Message. But it is treating href also as string. The Validation Message that I am trying to display with hyperlink is: **"User already exists in the system, please <a href='../Login.aspx'>login</a>"** Appreciate your responses. Here is my Code: <% using (Html.BeginForm()) {%> <%= Html.ValidationSummary(false) %> <fieldset> <div class="cssform">; <p> <%= Html.LabelFor(model => model.email)%><em>*</em> <%= Html.TextBoxFor(model => model.email, new { @class = "required email" })%> <%= Html.ValidationMessageFor(model => model.email)%> </p> <p> <%= Html.Label("Confirm email")%><em>*</em> <%= Html.TextBox("confirm_email")%> <%= Html.ValidationMessage("confirm_email") %> </p> <p> <%= Html.Label("Password")%><em>*</em> <%= Html.Password("Password", null, new { @class = "required" })%> <%= Html.ValidationMessage("Password")%><br /> (Note: Password should be minimum 6 characters) </p> <p> <%= Html.Label("Confirm Password")%><em>*</em> <%= Html.Password("confirm_password")%> <%= Html.ValidationMessage("confirm_password") %> </p><hr /> <% } %

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  • XMPP SASL authentication on Ejabberd with PHP

    - by bucabay
    I'm trying to authenticate with an XMPP server using SASL. /** * Send Authentication, SASL * @return Bool * @param $username String * @param $password String */ function authenticate($username, $password) { $this->username = $username; $this->password = $password; var_dump($username, $password, $this->domain); $auth = base64_encode($username.'@'.$this->domain."\u0000".$username."\u0000".$password); $xml = '<auth mechanism="PLAIN" xmlns="urn:ietf:params:xml:ns:xmpp-sasl">'.$auth.'</auth>'; if ($this->write($xml)) { if ($xml = $this->listen(1, true)) { if (preg_match("/<success/i", $xml)) { $this->authenticated = $this->_sendStream(); } } } $this->events->trigger('authenticate', $this->authenticated); return $this->authenticated; } The XMPP server however responds with: <failure xmlns='urn:ietf:params:xml:ns:xmpp-sasl'><bad-protocol/></failure> This is against an Ejabberd server. When I open the XMPP stream, it advertises: <stream:features><starttls xmlns='urn:ietf:params:xml:ns:xmpp-tls'/><mechanisms xmlns='urn:ietf:params:xml:ns:xmpp-sasl'><mechanism>DIGEST-MD5</mechanism><mechanism>PLAIN</mechanism></mechanisms><register xmlns='http://jabber.org/features/iq-register'/></stream:features> So it seams to me that SASL - PLAIN should work. I have a JavaScript version, that works perfectly on OpenFire server. (I can't test it on Ejabberd at the moment) sendAuthentication: function() { clearTimeout(XMPP.sendAuthentication_timer); var auth = Base64.encode(XMPP.username+'@'+XMPP.domain+'\u0000'+XMPP.username+'\u0000'+XMPP.password); mySocket.events.receive.observe(XMPP.receivedAuthSuccess, function() { mySocket.send('<auth mechanism="PLAIN" xmlns="urn:ietf:params:xml:ns:xmpp-sasl">' + auth + '</auth>'); }); } So I can't get why the PHP version is not working.

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  • Generating scala AST for recursive method.

    - by scout
    I am generating the scala AST using the following code: val setting = new Settings(error) val reporter = new ConsoleReporter(setting, in, out) { override def displayPrompt = () } val compiler = new Global(setting, reporter) with ASTExtractor{ override def onlyPresentation = true } //setting.PhasesSetting("parser", "parserPhase") val run = new compiler.Run val sourceFiles:List[String] = List("Test.scala") run.compile(sourceFiles.toList) I guess this is the standard code used to run the compiler in the code and generate the AST to work with. The above code worked fine for any valid scala code in Test.scala till now. When I use a recursive function in Test.scala, like def xMethod(x:Int):Int = if(x == 0) -1 else xMethod(x-1) It gives me a java.lang.NullPointerException. The top few lines of the stack trace look like this at scala.tools.nsc.typechecker.Typers$Typer.checkNoDoubleDefsAndAddSynthetics$1(Typers.scala:2170) at scala.tools.nsc.typechecker.Typers$Typer.typedStats(Typers.scala:2196) at scala.tools.nsc.typechecker.Typers$Typer.typedBlock(Typers.scala:1951) at scala.tools.nsc.typechecker.Typers$Typer.typed1(Typers.scala:3815) at scala.tools.nsc.typechecker.Typers$Typer.typed(Typers.scala:4124) at scala.tools.nsc.typechecker.Typers$Typer.typed(Typers.scala:4177) at scala.tools.nsc.transform.TailCalls$TailCallElimination.transform(TailCalls.scala:199) The code works fine for a method like def aMethod(c:Int):Int = { bMethod(c) } def bMethod(x:Int):Int = aMethod(x) Please let me know if recursive functions need any other setting.

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  • Grails + GAE - Issue using app.servlet.version=2.5

    - by Taylor L
    Updating the servlet version in application.properties to 2.5 has no affect on the generated web.xml. The generated web.xml is still version 2.4. app.servlet.version=2.5 Also, if I try to execute "run-app" I get the exception below: Running Grails application.. Starting AppEngine generated indices thread. Starting reload monitor thread. [java] Jan 26, 2010 5:27:05 AM com.google.apphosting.utils.jetty.JettyLogger warn [java] WARNING: Failed startup of context com.google.apphosting.utils.jetty.DevAppEngineWebAppContext@4178460d{/,C:\Users\Taylor Leese\workspace\test-gae\web-app} [java] java.lang.IllegalStateException: No such servlet: grails [java] at org.mortbay.jetty.servlet.ServletHandler.updateMappings(ServletHandler.java:953) [java] at org.mortbay.jetty.servlet.ServletHandler.setServletMappings(ServletHandler.java:1037) [java] at org.mortbay.jetty.webapp.WebXmlConfiguration.initialize(WebXmlConfiguration.java:305) [java] at org.mortbay.jetty.webapp.WebXmlConfiguration.configure(WebXmlConfiguration.java:222) [java] at org.mortbay.jetty.webapp.WebXmlConfiguration.configureWebApp(WebXmlConfiguration.java:180) [java] at org.mortbay.jetty.webapp.WebAppContext.startContext(WebAppContext.java:1215) [java] at org.mortbay.jetty.handler.ContextHandler.doStart(ContextHandler.java:500) [java] at org.mortbay.jetty.webapp.WebAppContext.doStart(WebAppContext.java:448) [java] at org.mortbay.component.AbstractLifeCycle.start(AbstractLifeCycle.java:40) [java] at org.mortbay.jetty.handler.HandlerWrapper.doStart(HandlerWrapper.java:117) [java] at org.mortbay.component.AbstractLifeCycle.start(AbstractLifeCycle.java:40) [java] at org.mortbay.jetty.handler.HandlerWrapper.doStart(HandlerWrapper.java:117) [java] at org.mortbay.jetty.Server.doStart(Server.java:217) [java] at org.mortbay.component.AbstractLifeCycle.start(AbstractLifeCycle.java:40) [java] at com.google.appengine.tools.development.JettyContainerService.startContainer(JettyContainerService.java:188) [java] at com.google.appengine.tools.development.AbstractContainerService.startup(AbstractContainerService.java:120) [java] at com.google.appengine.tools.development.DevAppServerImpl.start(DevAppServerImpl.java:217) [java] at com.google.appengine.tools.development.DevAppServerMain$StartAction.apply(DevAppServerMain.java:162) [java] at com.google.appengine.tools.util.Parser$ParseResult.applyArgs(Parser.java:48) [java] at com.google.appengine.tools.development.DevAppServerMain.<init>(DevAppServerMain.java:113) [java] at com.google.appengine.tools.development.DevAppServerMain.main(DevAppServerMain.java:89) [java] The server is running at http://localhost:8080/ Any ideas how to resolve these issues?

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  • how does hash element make a secure login on zend framework?

    - by ulduz114
    hello all i saw a example for login form same blow code class Form_Login extends Zend_Form { //put your code here public function init($timeout=360){ $this->addElement('hash', 'token', array( 'timeout' => $timeout )); $this->setName('Login'); $username = $this->createElement ( 'text', 'username' ); $username->setLabel('user name:') ->setRequired(); $this->addElement($username); $password=$this->createElement('password','password'); $password->setLabel('password:'); $password->setRequired(); $this->addElement($password); $login=$this->createElement('submit','login'); $login->setLabel('Login'); $this->addElement($login); $this->setMethod('post'); $this->setAction(Zend_Controller_Front::getInstance()->getBaseUrl().'/authentication/login'); } } and in submitAction a part code same below if (!$form->isValid($request->getPost())) { if (count($form->getErrors('token')) > 0) { return $this->_forward('csrf-forbidden', 'error'); } $this->view->form = $form; return $this->render('login'); } now , my question, whats the reason for use of hash element? how this hash element make secure login? anybody may help explain these? thanks

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  • Asp.net Login Status Question: It Aint Working

    - by contactmatt
    I'm starting to use Role Management in my website, and I'm current following along on the tutorial from http://www.asp.net/Learn/Security/tutorial-02-vb.aspx . I'm having a problem with the asp:LoginStatus control. It is not telling me that I am currently logged in after a successful login. This can't be true because after successfully logging in, my LoggedInTemplate is shown. The username and passwords are simply stored in a array. Heres the Login.aspx page code. Protected Sub btnLogin_Click(ByVal sender As Object, ByVal e As System.EventArgs) _ Handles btnLogin.Click ' Three valid username/password pairs: Scott/password, Jisun/password, and Sam/password. Dim users() As String = {"Scott", "Jisun", "Sam"} Dim passwords() As String = {"password", "password", "password"} For i As Integer = 0 To users.Length - 1 Dim validUsername As Boolean = (String.Compare(txtUserName.Text, users(i), True) = 0) Dim validPassword As Boolean = (String.Compare(txtPassword.Text, passwords(i), False) = 0) If validUsername AndAlso validPassword Then FormsAuthentication.RedirectFromLoginPage(txtUserName.Text, chkRemember.Checked) End If Next ' If we reach here, the user's credentials were invalid lblInvalid.Visible = True End Sub Here is the content place holder on the master page specifically designed to hold Login Information. On successfull login, the page is redirected to '/Default.aspx', and the LoggedIn Template below is shown...but the status says Log In. <asp:ContentPlaceHolder Id="LoginContent" runat="server"> <asp:LoginView ID="LoginView1" runat="server"> <LoggedInTemplate> Welcome back, <asp:LoginName ID="LoginName1" runat="server" />. </LoggedInTemplate> <AnonymousTemplate> Hello, stranger. </AnonymousTemplate> </asp:LoginView> <br /> <asp:LoginStatus ID="LoginStatus1" runat="server" LogoutAction="Redirect" LogoutPageUrl="~/Logout.aspx" /> </asp:ContentPlaceHolder> Forms authentication is enabled. I'm not sure what to do about this :o.

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  • Why can't I get a TRUE return in this prepared statement?

    - by Cortopasta
    I can't seem to get this to do anything but return false. My best guess is that the prepared statement isn't executing, but I have no idea why. private function check_credentials($plain_username, $md5_password) { global $dbcon; $ac = new ac(); $ac->dbconnect(); $userid = $dbcon->prepare('SELECT id FROM users WHERE username = :username AND password = :password LIMIT 1'); $userid->bindParam(':username', $plain_username); $userid->bindParam(':password', $md5_password); $userid->execute(); $id = $userid->fetch(); Return $id; } *EDIT:*I've even tried hard coding the username and password into the function itself to try and isolate the problem like this: private function check_credentials($plain_username, $md5_password) { global $dbcon; $plain_username = "jim"; $md5_username = "waffles"; $ac = new ac(); $ac->dbconnect(); $userid = $dbcon->prepare('SELECT id FROM users WHERE username = :username AND password = :password LIMIT 1'); $userid->bindParam(':username', $plain_username); $userid->bindParam(':password', $md5_password); $userid->execute(); print_r($dbcon->errorInfo()); $id = $userid->fetch(); Return $id; } Still nothing :-/

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  • Designing secure consumer blackberry application

    - by Kiran Kuppa
    I am evaluating a requirement for a consumer blackberry application that places high premium on security of user's data. Seems like it is an insurance company. Here are my ideas on how I could go about it. I am sure this would be useful for others who are looking for similar stuff Force the user to use device password. (I am guessing that this would be possible - though not checked it yet). Application can request notifications when the device is about to be locked and just after it has been unlocked. Encryption of application specific data can be managed at those times. Application data would be encrypted with user's password. User's credentials would be encrypted with device password. Remote backup of the data could be done over HTTPS (any better ideas are appreciated) Questions: What if the user forgets his device password. If the user forgets his application password, what is the best and secure way to reset the password? If the user losses the phone, remote backup must be done and the application data must be cleaned up. I have some ideas on how to achieve (3) and shall share them. There must be an off-line verification of the user's identity and the administrator must provide a channel using which the user must be able to send command to the device to perform the wiping of application data. The idea is that the user is ALWAYS in control of his data. Without the user's consent, even the admin must not be able to do activities such as cleaning up the data. In the above scheme of things, it appears as if the user's password need not be sent over the air to server. Am I correct? Thanks, --Kiran Kumar

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  • Simplest way to handle and display errors in a Python Pylons controller without a helper class

    - by ensnare
    I have a class User() that throw exceptions when attributes are incorrectly set. I am currently passing the exceptions from the models through the controller to the templates by essentially catching exceptions two times for each variable. Is this a correct way of doing it? Is there a better (but still simple) way? I prefer not to use any third party error or form handlers due to the extensive database queries we already have in place in our classes. Furthermore, how can I "stop" the chain of processing in the class if one of the values is invalid? Is there like a "break" syntax or something? Thanks. >>> u = User() >>> u.name = 'Jason Mendez' >>> u.password = '1234' Traceback (most recent call last): File "<stdin>", line 1, in <module> File "topic/model/user.py", line 79, in password return self._password ValueError: Your password must be greater than 6 characters In my controller "register," I have: class RegisterController(BaseController): def index(self): if request.POST: c.errors = {} u = User() try: u.name = c.name = request.POST['name'] except ValueError, error: c.errors['name'] = error try: u.email = c.email = request.POST['email'] except ValueError, error: c.errors['email'] = error try: u.password = c.password = request.POST['password'] except ValueError, error: c.errors['password'] = error try: u.commit() except ValueError, error: pass return render('/register.mako')

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  • Problems using Maven to initialize a local thoughtsite (App Engine sample) project in Eclipse

    - by ovr
    This sample app ("thoughtsite") for App Engine contains a pom.xml in its trunk: http://code.google.com/p/thoughtsite/source/browse/#svn/trunk I ran mvn eclipse:eclipse and also tried using m2eclipse to import this source code into an Eclipse project. But I end up with this error despite the fact that I have the Google App Engine plugin and the Google App Engine SDK installed: Exception in thread "main" java.lang.ExceptionInInitializerError at com.google.appengine.tools.info.SdkImplInfo.<clinit>(SdkImplInfo.java:19) at com.google.appengine.tools.util.Logging.initializeLogging(Logging.java:36) at com.google.appengine.tools.development.DevAppServerMain.main(DevAppServerMain.java:82) Caused by: java.lang.RuntimeException: Unable to discover the Google App Engine SDK root. This code should be loaded from the SDK directory, but was instead loaded from file:~/.m2/repository/com/google/appengine/appengine-tools-sdk/1.3.0/appengine-tools-sdk-1.3.0.jar. Specify -Dappengine.sdk.root to override the SDK location. at com.google.appengine.tools.info.SdkInfo.findSdkRoot(SdkInfo.java:106) at com.google.appengine.tools.info.SdkInfo.<clinit>(SdkInfo.java:24) ... 3 more When I go into the project settings under "Google" and try to set it to use the default App Engine SDK it always reverts to trying to use Maven's App Engine SDK instead. No idea how to get this project working.

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  • Devise routes to only use custom sign in page

    - by eblume
    I am trying to learn Devise and seem to have hit a problem that is nearly the same as many, many questions here on SO but just slightly different enough that I am not getting much traction following those questions' threads. I have a very simple application. Users can sign in and sign out (and also the devise 'forgot password' stuff is enabled - I am not concerned about it at this time) and that is it. They can't register, they can't edit their profile other than to change their password, they can't do anything except sign in and sign out. (Account creation will, for now, be handled manually at the command line.) I would vastly prefer that the only page that users can log in from was "/" (root_path). I already have it working where you can log in from "/", and that is great. The problem I am having is that if you type in your user/password combination incorrectly from the root_path login page, it automatically sends you to the Devise sign-in page to continue trying to sign in. How can I make Devise redirect to root_path on sign-in failure? Here are my routes - they are probably not optimal or correctly configured and I would appreciate pointers on fixing them: root to: "core_pages#splash" devise_for :users, skip: [:sessions] as :user do # get 'signin' => 'devise/sessions#new', as: :new_user_session post 'signin' => 'devise/sessions#create', as: :user_session delete 'signout' => 'devise/sessions#destroy', as: :destroy_user_session, via: Devise.mappings[:user].sign_out_via end match '/home' => 'core_pages#home' Note the commented-out 'get signin' line. The system works without this line but, surprisingly (to me), "GET /signin" results in a HTTP 400 (OK) response and renders the Devise login template. I would prefer it return some sort of 'invalid request' or just silently redirect the user to root_path. Running rake routes on these routes gives: root / core_pages#splash user_password POST /users/password(.:format) devise/passwords#create new_user_password GET /users/password/new(.:format) devise/passwords#new edit_user_password GET /users/password/edit(.:format) devise/passwords#edit PUT /users/password(.:format) devise/passwords#update user_session POST /signin(.:format) devise/sessions#create destroy_user_session DELETE /signout(.:format) devise/sessions#destroy home /home(.:format) core_pages#home Thanks!

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  • Using PHP and cURL to login to indyarocks.com

    - by Divya
    I am new to cURL and don't know much about it. I basically want to login to my account on www.indyarocks.com through libcurl for PHP. I don't know what type of authentication it uses (I don't know how to find that out.). When I go to http://www.indyarocks.com, I get a login form which asks for my username and password. I put in my username and password and click login and everything is good. I tried to automate this using cURL. This is a snippet of my code. curl_setopt($curl_connection, CURLOPT_URL, "http://www.indyarocks.com/loginchk.php"); curl_setopt($curl_connection, CURLOPT_POST, 1); curl_setopt($curl_connection, CURLOPT_HTTPAUTH, CURLAUTH_ANY); curl_setopt($curl_connection, CURLOPT_USERPWD, $username.':'.$password); I looked at the source of the login page and found out the address of the page to which the username and password are sent (the action attribute of the form) which is "http://www.indyarocks.com/loginchk.php" and set it as the target url. When I run this, I get username or password is wrong error and the login fails. My username and password is correct. I don't know what the problem is. Can the password be encrypted? Can that be responsible for this failure? Please help me get around this problem. I'll be really thankful. Thanks in advance.

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  • SSL + Jquery + Ajax

    - by chobo2
    Hi I starting too look at a bit of security into my site. My site I would consider a very low security risk as it has really no personal information from the user other than email. However the security risk will go up a bit as I am partnering with a company and the initial password for this companies users will be the same password they use essentially to get onto the network and every piece of software. So I have up my security( what is fine by me...I wanted to get around to this anyways). So one of my security concerns is this. A user logs in. form submit(non ajax is done). Password is hashed & Salted and compared to one in the database. Reject or let them proceed. So this uses no jquery or ajax but is just asp.net mvc and C#. Still if my understanding is right the password is sent in clear text. So if a use SSL and I would not need to worry about that is this correct? If that is true is that all I need? Second the user can change their password at anytime. This is done through ajax. So when the password is sent it is sent in clear text( and I can verify this by looking at firebug). So if I have SSL enabled on this page is that all I need or do I need to do more? So I am just kinda confused of what I need to make the password being sent to the server(both ajax and full post ways secure). I am not sure if I need to do more then SSL or if that is enough and if it is not enough what is the next layer of security?

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  • Basic security, PHP mySQl

    - by yuudachi
    So I am making a basic log-in page. I have a good idea of what to do, but I'm still unsure of some things. I have a database full of students and a password column of course. I know I'm going to use md5 encryption in that column. The student enters their e-mail and student ID, and they get e-mailed a password if correct. But, where do I create the password? Do I have to manually add the password (which is just a randomly generated string) in mySQL to all the students? And I am suppose to send the password to the student; how will I know what to send the student if the password is encrypted? I was thinking about generating the password when the student first enters their e-mail and student ID. They get an e-mail of the random string, and at the same time, I add the same random string to the database, encrypted. Is that how it's suppose to work though? And it feels unsafe doing that all on the same page. Sorry for the long-winded, newbish question. I find this all facisnating at the same time as well (AES and RSA encryption :O)

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  • Error occurs while validating form input using jQuery in Firebug

    - by Param-Ganak
    I have written a custom validation code in jQuery, which is working fine. I have a login form which has two fields, i.e. userid and password. I have written a custom code for client side validation for these fields. This code is working fine and gives me proper error messages as per the situation. But the problem with this code is that when I enter the invalid data in any or both field and press submit button of form then it displays the proper error message but at the same time when I checked it in Firebug it displays following error message when submit button of the form is clicked validate is not defined function onclick(event) { javascript: return validate(); } (click clientX=473, clientY=273) Here is the JQUERY validation code $(document).ready(function (){ $("#id_login_form").validate({ rules: { userid: { required: true, minlength: 6, maxlength: 20, // basic: true }, password: { required: true, minlength: 6, maxlength: 15, // basic: true } }, messages: { userid: { required: " Please enter the username.", minlength: "User Name should be minimum 6 characters long.", maxlength: "User Name should be maximum 15 characters long.", // basic: "working here" }, password: { required: " Please enter the password.", minlength: "Password should be minimum 6 characters long.", maxlength: "Password should be maximum 15 characters long.", // basic: "working here too.", } }, errorClass: "errortext", errorLabelContainer: "#messagebox" } }); }); /* $.validator.addMethod('username_alphanum', function (value) { return /^(?![0-9]+$)[a-zA-Z 0-9_.]+$/.test(value); }, 'User name should be alphabetic or Alphanumeric and may contain . and _.'); $.validator.addMethod('alphanum', function (value) { return /^(?![a-zA-Z]+$)(?![0-9]+$)[a-zA-Z 0-9]+$/.test(value); }, 'Password should be Alphanumeric.'); $.validator.addMethod('basic', function (value) { return /^[a-zA-Z 0-9_.]+$/.test(value); }, 'working working working'); */ So please tell me where is I am wrong in my jQuery code. Thank You!

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  • How to add Remember me function at custom login box ?

    - by morningglory
    In my theme, there's custom page for the login. Login function at functions.php is like this function log_in($username, $password) { $user = parse_user($username); $username = $username; $password = $password; if(isEmptyString($username)) return new WP_Error('username', 'required'); if(isEmptyString($password)) return new WP_Error('password', "required"); if(!wp_check_password( $password, $user->user_pass ) ) return new WP_Error('wrong_password', "wrong"); wp_set_auth_cookie($user->ID, $remember); wp_login($username, $password); redirect_profile(); } function parse_user($info = null, $return = 'object') { if ( is_null( $info ) ) { global $current_user; if ( empty( $current_user->ID ) ) return null; $info = get_userdata( $current_user->ID ); } elseif ( empty( $info ) ) { return null; } if( $return == 'ID' ) { if ( is_object( $info ) ) return $info->ID; if ( is_numeric( $info ) ) return $info; } elseif( $return == 'object' ) { if ( is_object( $info ) && $info->ID) return $info; if ( is_object( $info )) return get_userdata( $info->ID ); if ( is_numeric( $info ) ) return get_userdata( $info ); if ( is_string( $info ) ) return get_userdatabylogin( $info ); } else { return null; } } I want to add remember me checkbox for user to logged in all the time until they logout. How can i add this ? Please kindly help me out. Thank you.

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  • How to insert form data into MySQL database table

    - by Richard
    So I have this registration script: The HTML: <form action="register.php" method="POST"> <label>Username:</label> <input type="text" name="username" /><br /> <label>Password:</label> <input type="text" name="password" /><br /> <label>Gender:</label> <select name="gender"> <optgroup label="genderset"> <option value="Male">Male</option> <option value="Female">Female</option> <option value="Hermaphrodite">Hermaphrodite</option> <option value="Not Sure!!!">Not Sure!!!</option> </optgroup> </select><br /> <input type="submit" value="Register" /> </form> The PHP/SQL: <?php $username = $_POST['username']; $password = $_POST['password']; $gender = $_POST['gender']; mysql_query("INSERT INTO registration_info (username, password, gender) VALUES ('$username', '$password', '$gender') ") ?> The problem is, the username and password gets inserted into the "registration_info" table just fine. But the Gender input from the select drop down menu doesn't. Can some one tell me how to fix this, thanks.

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  • Stored procedure or function expects parameter which is not supplied

    - by user2920046
    I am trying to insert data into a SQL Server database by calling a stored procedure, but I am getting the error Procedure or function 'SHOWuser' expects parameter '@userID', which was not supplied. My stored procedure is called "SHOWuser". I have checked it thoroughly and no parameters is missing. My code is: public void SHOWuser(string userName, string password, string emailAddress, List preferences) { SqlConnection dbcon = new SqlConnection(conn); try { SqlCommand cmd = new SqlCommand(); cmd.Connection = dbcon; cmd.CommandType = System.Data.CommandType.StoredProcedure; cmd.CommandText = "SHOWuser"; cmd.Parameters.AddWithValue("@userName", userName); cmd.Parameters.AddWithValue("@password", password); cmd.Parameters.AddWithValue("@emailAddress", emailAddress); dbcon.Open(); int i = Convert.ToInt32(cmd.ExecuteScalar()); cmd.Parameters.Clear(); cmd.CommandText = "tbl_pref"; foreach (int preference in preferences) { cmd.Parameters.Clear(); cmd.Parameters.AddWithValue("@userID", Convert.ToInt32(i)); cmd.Parameters.AddWithValue("@preferenceID", Convert.ToInt32(preference)); cmd.ExecuteNonQuery(); } } catch (Exception) { throw; } finally { dbcon.Close(); } and the stored procedure is: ALTER PROCEDURE [dbo].[SHOWuser] -- Add the parameters for the stored procedure here ( @userName varchar(50), @password nvarchar(50), @emailAddress nvarchar(50) ) AS BEGIN INSERT INTO tbl_user(userName,password,emailAddress) values(@userName,@password,@emailAddress) select tbl_user.userID,tbl_user.userName,tbl_user.password,tbl_user.emailAddress, stuff((select ',' + preferenceName from tbl_pref_master inner join tbl_preferences on tbl_pref_master.preferenceID = tbl_preferences.preferenceID where tbl_preferences.userID=tbl_user.userID FOR XML PATH ('')),1,1,' ' ) AS Preferences from tbl_user SELECT SCOPE_IDENTITY(); END Pls help, Thankx in advance...

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  • Variable won't store in session

    - by Mittens
    So I'm trying to store the "rank" of a user when they log in to a control panel which displays different options depending on the given rank. I used the same method as I did for storing and displaying the username, which is displayed on the top of each page and works just fine. I can't for the life of me figure out why it won't work for the rank value, but I do know that it is not saving it in the session. Here is the bit that's not working; $username = ($_POST['username']); $password = hash('sha512', $_POST['password']); $dbhost = 'mysql:host=¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦;dbname=¦¦¦¦¦¦¦¦¦¦¦'; $dbuser = '¦¦¦¦¦¦¦¦¦¦¦'; $dbpassword = '¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦'; try { $db = new PDO($dbhost, $dbuser, $dbpassword); $statement = $db->prepare("select password from users where email = :name"); $statement->execute(array(':name' => $username)); $result = $statement->fetch(); $pass = $result[password]; $rank = $result[rank];} catch(PDOException $e) {echo $e->getMessage();} if ($password == $pass) { session_start(); $_SESSION['username'] = $username; $_SESSION['rank'] = $rank; header('Location: http://¦¦¦¦¦¦¦¦¦.ca/manage.php'); } else{ include'../../includes/head.inc'; echo '<h1>Incorrect username or password.</h1>'; include'../../includes/footer.inc'; } I'm also new to the whole PDO thing, hence why my method of authenticating the password is pretty sketchy.

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  • Pipelining String in Powershell

    - by ChvyVele
    I'm trying to make a simple PowerShell function to have a Linux-style ssh command. Such as: ssh username@url I'm using plink to do this, and this is the function I have written: function ssh { param($usernameAndServer) $myArray = $usernameAndServer.Split("@") $myArray[0] | C:\plink.exe -ssh $myArray[1] } If entered correctly by the user, $myArray[0] is the username and $myArray[1] is the URL. Thus, it connects to the URL and when you're prompted for a username, the username is streamed in using the pipeline. Everything works perfectly, except the pipeline keeps feeding the username ($myArray[0]) and it is entered as the password over and over. Example: PS C:\Users\Mike> ssh xxxxx@yyyyy login as: xxxxx@yyyyy's password: Access denied xxxxx@yyyyy's password: Access denied xxxxx@yyyyy's password: Access denied xxxxx@yyyyy's password: Access denied xxxxx@yyyy's password: Access denied xxxxx@yyyyy's password: FATAL ERROR: Server sent disconnect message type 2 (protocol error): "Too many authentication failures for xxxxx" Where the username has been substituted with xxxxx and the URL has been substituted with yyyyy. Basically, I need to find out how to stop the script from piping in the username ($myArray[0]) after it has been entered once. Any ideas? I've looked all over the internet for a solution and haven't found anything.

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