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  • Convert JSON data into String

    - by san6086
    Hi I am converting JSON data into String. Please find the JSON data below. I am facing an issue where in the system is unable to convert NULL values into string. Therefore, I am getting the following error: can't convert nil into String (TypeError) JSON DATA: {"success":true,"message":null,"data":null} Code Used: c = Curl::Easy.new(Configuration.fetch("<URL where we can find the above JSON DATA and nothing else>")) # c.follow_location = true # c.http_auth_types = :basic # c.username = Configuration.fetch('auth_user', false) # c.password = Configuration.fetch('auth_pass', false) # c.headers["User-Agent"] = 'Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.17 (KHTML, like Gecko) Chrome/24.0.1312.52 Safari/537.17' # c.perform result=JSON.parse(c) puts result["Success"] Please help.

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  • This query show me with this active record

    - by New Kid
    I am having trouble getting two tables and passing them to controller: IN A MODEL: function get_all_entries() { $query = $this->db->get('entry'); return $query->result(); $this->db->select('entry_id , count(comment_id) as total_comment'); $this->db->group_by('entry_id'); $comment = $this->db->get('comment'); return $comment->result(); } IN A CONTROLLER: $data['query'] = $this->blog_model->get_all_entries(); $this->load->view('blog/index',$data); How do I return $query and $comment variables to controller? I think I am doing it wrong.

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  • php var_dump returning blank array

    - by Oroku
    I'm following this tutorial on youtube: https://www.youtube.com/watch?v=VSF5p00uorc Around 4:28 - I get the following array when I load the sql.php page as in the tutorial: array(8) { [1]=> NULL [2]=> NULL [3]=> NULL [4]=> NULL [5]=> NULL [6]=> NULL [7]=> NULL [8]=> NULL } I do have 8 ids all with values in my data table. This is my code: <?php $con = mysqli_connect("localhost","root","","test2") or die('error'); $query = "select * from data"; $result = mysqli_query($con,$query); while($row = mysqli_fetch_array($result)) { $id = $row['id']; $feed = $row['feed']; $data[$id] = $feed; } var_dump($data); ?>

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  • What's the difference between FireBug's conole.log() and console.debug() ?

    - by 6bytes
    A very simple code to illustrate the difference. var x = [0, 3, 1, 2]; console.debug('debug', x); console.log('log', x); // above display the same result x.splice(1, 2); // below display kind of a different result console.debug('debug', x); console.log('log', x); The javascript value is exactly the same but console.log() displays it a bit differently than before applying splice() method. Because of this I lost quite a few hours as I thought splice is acting funny making my array multidimensional or something. I just want to know why does this work like that. Does anyone know? :)

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  • php/mysql question, retrieving information

    - by chance
    Hey SO, I have a question, pretty new at PHP and MySql but was curious is it possible to display only the most recent column to a table, from a database? I know it is possible to display a list of all information, or if you have just one column of information in your table to display that using the Here is my code for my basic script (just loads 1 column of information) I would like it to only print out the recent column i added to the table $con = mysql_connect ("localhost","username","password"); if (!$con) { die ('Could not connect:' . mysql_error()0; } mysql_select_db("db_name", $con); $result = mysql_query(Select column FROM table"); while($row = mysql_fetch_array($result)) { echo $row['column']; } mysql_close($con); * keep in mind, im not looking for someone to shoot me my code with it completed, though it would be handy, however just giving me the options of what I have to do, or what the script is called would be plentiful enough for my research, thanks!

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  • What PHP function(s) can I use to perform operations on non-integer timestamps?

    - by stephenhay
    Disclaimer, I'm not a PHP programmer, so you might find this question trivial. That's why I'm asking you! I've got this kind of timestamp: 2010-05-10T22:00:00 (That's Y-m-d) I would like to subtract, say, 10 days (or months, whatever) from this, and have my result be in the same format, i.e. 2010-04-30T22:00:00. What function(s) do I need to do this in PHP? Note: I'm using this to do a computed field in Drupal. The result will be the date that an e-mail is sent. Bonus question: If 2010-05-10T22:00:00 means "May 10, 2010 at 10pm", is there a timestamp equivalent of "May 10, 2010 (all day)"? Thanks everyone.

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  • Django: Converting an entire Model into a single dictionary

    - by LarrikJ
    Is there a good way in Django to convert an entire model to a dictionary? I mean, like this: class DictModel(models.Model): key = models.CharField(20) value = models.CharField(200) DictModel.objects.all().to_dict() ... with the result being a dictionary with the key/value pairs made up of records in the Model? Has anyone else seen this as being useful for them? Thanks. Update I just wanted to add is that my ultimate goal is to be able to do a simple variable lookup inside a Template. Something like: {{ DictModel.exampleKey }} With a result of DictModel.objects.get(key__exact=exampleKey).value Overall, though, you guys have really surprised me with how helpful allof your responses are, and how different the ways to approach it can be. Thanks a lot.

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  • PHP table problem

    - by maltad
    Hello, Im want to create a table that show the values of a mysql table. The problem is that when I open the page I only have the columns name. But I dont see any row. I also want to make a hyperlink of each row. How I will do that. Here is my code: <p> <?php </p> <p> include_once 'rnheader.php'; echo '</br>'; </p> <p> echo '<a href = "rnservices.php"> Create Service</a> '; </p> <p> echo '<table>'; echo '<tr>'; echo '<th>Service ID</th>'; echo '<th>Title</th>'; echo '<th>Description</th>'; echo '<th>Notes</th>'; echo '<th>Submit By</th>'; echo '<th>Assigned Employee</th>'; echo '<th>Assigned Group</th>'; echo '<th>Category</th>'; echo '<th>Status</th>'; echo '<th>Urgency</th>'; echo '<th>Customer</th>'; echo '<th>Day Created</th>'; echo '</tr>'; </p> <p> $query = ("SELECT ServiceID, Title, Description, Notes, SubmitBy, AssignedEmp, " . "AssignedGroup, NameCategory, TipoStatus, TiposUrgencia, CustomerName, DayCreation FROM Service"); $result = queryMysql($query); echo 'Number of Rows: ' . mysql_num_rows($result); </p> <p> while ($row = mysqli_fetch_assoc($result)) { </p> echo '<tr>'; echo '<td>' . $row['ServiceID'] . '</td>'; echo '<td>' . $row['Title'] . '</td>'; echo '<td>' . $row['Description'] . '</td>'; echo '<td>' . $row['Notes'] . '</td>'; echo '<td>' . $row['SubmitBy'] . '</td>'; echo '<td>' . $row['AssignedEmp'] . '</td>'; echo '<td>' . $row['AssignedGroup'] . '</td>'; echo '<td>' . $row['NameCategory'] . '</td>'; echo '<td>' . $row['TipoStatus'] . '</td>'; echo '<td>' . $row['TiposUrgencia'] . '</td>'; echo '<td>' . $row['CustomerName'] . '</td>'; echo '<td>' . $row['DayCreation'] . '</td>'; echo '</tr>'; } mysqli_free_result($result); echo ''; ?

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  • Allow users to pull temporary data then delete table data (headers remain)?

    - by JM4
    I don't know the best way to title this question but am trying to accomplish the following goal: When a client logs into their profile, they are presented with a link to download data from an existing database in CSV format. The process works, however, I would like for this data to be 'fresh' each time they click the link so my plan was - once a user has clicked the link and downloaded the CSV file, the database table would 'erase' all of its data and start fresh (be empty) until the next set of data populated it. My EXISTING CSV creation code: <?php $host = 'localhost'; $user = 'username'; $pass = 'password'; $db = 'database'; $table = 'tablename'; $file = 'export'; $link = mysql_connect($host, $user, $pass) or die("Can not connect." . mysql_error()); mysql_select_db($db) or die("Can not connect."); $result = mysql_query("SHOW COLUMNS FROM ".$table.""); $i = 0; if (mysql_num_rows($result) > 0) { while ($row = mysql_fetch_assoc($result)) { $csv_output .= $row['Field'].", "; $i++; } } $csv_output .= "\n"; $values = mysql_query("SELECT * FROM ".$table.""); while ($rowr = mysql_fetch_row($values)) { for ($j=0;$j<$i;$j++) { $csv_output .= '"'.$rowr[$j].'",'; } $csv_output .= "\n"; } $filename = $file."_".date("Y-m-d",time()); header("Content-type: application/vnd.ms-excel"); header("Content-disposition: csv" . date("Y-m-d") . ".csv"); header( "Content-disposition: filename=".$filename.".csv"); print $csv_output; exit; ?> any ideas?

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  • Warning that users must handle

    - by hagaik
    I am looking for a way to set warning that the user will have to respond. In a sense I would like to use late exception mechanize that occur after the function already finished executing.and returned the wanted value. SomeObject Foo(int input) { SomeObject result; // do something. oh, we need to warn the user. return result; } void Main() { SomeObject object; object = Foo(1); // after copy consturctor is done I would like an exception to be thrown }

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  • [VC++ 2010] Stack around the variable 'xyz' was corrupted.

    - by tirolerhut
    hi, I'm trying to get some simple piece of code I found on a website to work in VC++ 2010 on windows vista 64: #include "stdafx.h" #include <windows.h> int _tmain(int argc, _TCHAR* argv[]) { DWORD dResult; BOOL result; char oldWallPaper[MAX_PATH]; result = SystemParametersInfo(SPI_GETDESKWALLPAPER, sizeof(oldWallPaper)-1, oldWallPaper, 0); fprintf(stderr, "Current desktop background is %s\n", oldWallPaper); return 0; } it does compile, but when I run it, I always get this error: Run-Time Check Failure #2 - Stack around the variable 'oldWallPaper' was corrupted. I'm not sure what is going wrong, but I noticed, that the value of oldWallPaper looks something like "C\0\:\0\0U\0s\0e\0r\0s[...]" -- I'm wondering where all the \0s come from. A friend of mine compiled it on windows xp 32 (also VC++ 2010) and is able to run it without problems any clues/hints/opinions? thanks

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  • How to echo an array in PHP?

    - by Kaoukkos
    The following code $results = $facebook->api('/fql', array('q'=>'SELECT page_id, type FROM page_admin WHERE uid = me()')); print_r($results); returned me this array Array ( [data] => Array ( [0] => Array ( [page_id] => 204725966262837 [type] => WEBSITE ) [1] => Array ( [page_id] => 163703342377960 [type] => COMMUNITY ) ) ) My question is how can I just echo the content without this structure? I tried foreach ($results as $result) { echo $result->type; echo "<br>"; }

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  • Fill data gaps without UNION

    - by Dave Jarvis
    Problem There are data gaps that need to be filled, possibly using PARTITION BY. Query Statement The select statement reads as follows: SELECT count( r.incident_id ) AS incident_tally, r.severity_cd, r.incident_typ_cd FROM report_vw r GROUP BY r.severity_cd, r.incident_typ_cd ORDER BY r.severity_cd, r.incident_typ_cd Code Tables The severity codes and incident type codes are from: severity_vw incident_type_vw Actual Result Data 36 0 ENVIRONMENT 1 1 DISASTER 27 1 ENVIRONMENT 4 2 SAFETY 1 3 SAFETY Required Result Data 36 0 ENVIRONMENT 0 0 DISASTER 0 0 SAFETY 27 1 ENVIRONMENT 0 1 DISASTER 0 1 SAFETY 0 2 ENVIRONMENT 0 2 DISASTER 4 2 SAFETY 0 3 ENVIRONMENT 0 3 DISASTER 1 3 SAFETY Any ideas how to use PARTITION BY (or JOINs) to fill in the zero counts?

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  • Return Total Rows from a table.

    - by theband
    while($row=mysql_fetch_array($result)) { $output .= "<Reports>"; $output .= "<ProjectName>"; $output .= $row['ProjectName']; $output .= "</ProjectName>"; $output .= "<ProjectCount>"; $output .= $row=mysql_fetch_array($result) $output .= "</ProjectCount>"; $output .= "</Reports>"; } Can i return the number of rows in table like this, i am getting XML markup error.

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  • Java Thread wait() => blocked?

    - by Chris
    According to http://java.sun.com/j2se/1.5.0/docs/api/java/lang/Thread.State.html calling wait() will result a thread to go in BLOCKED state. However this piece of code will result (after being called) in a Thread in WAITING State. class bThread extends Thread { public synchronized void run() { try { wait(); } catch (InterruptedException e) { e.printStackTrace(); } } } Have I got something wrong? Can anybody explain this behaviour to me? Any help would be appreciated!

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  • How to display a border-bottom only if table cells are not empty (CSS)

    - by Polarpro
    Hey there, I've got a Filemaker calculation that generates an HTML page with several tables. If the calculation results in values for certain fields the result would be <table> <tr><td>Example value 1</td></tr> <tr><td>Example value 2</td></tr> ... </table> If the calculation finds no values to be displayed, the result would simply be <table> </table> In the first case, I want to the table to display a border at the bottom (or any other horizontal line); in the second case, I don't want to display a border at the bottom. I cannot find a way to get this done using a CSS... Thanks in adavance :-)

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  • Array to string conversion in (cant get it to work)

    - by user2966551
    ok I am trying to pull a a specific row of data that corresponds to the username logged in. on my page I have started my session but for some reason I cant get the code to work.i keep getting a "Array to string conversion in " on the line " WHERE username = '$_SESSION[user]'");" what am I doing wrong? if I set username = a set username it works but I need it to draw from the session id so it will display different values based on whos logged in. <?php $con=mysqli_connect("localhost","root","xxx","xxxx"); // Check connection if (mysqli_connect_errno()) { echo "Failed to connect to MySQL: " . mysqli_connect_error(); } $result = mysqli_query($con,"SELECT * FROM users WHERE username = '$_SESSION[user]'"); while($row = mysqli_fetch_array($result)) { echo $row['username'] . " " . $row['att']; echo "<br>"; } ?>

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  • Prioritize SQL WHERE clause

    - by JaTochNietDan
    Basically I want to do this: SELECT * FROM `table` WHERE x = 'hello' OR x = 'bye' LIMIT 1'; I want it to return 1 value, but to prioritize results from the 1st where clause. So if there exists a row where column x's value is "hello", it will not return the result from the 'bye' value. If the "hello" value doesn't exist though, it will return the result from the 'bye' value. Can't figure out a way to do it even though it seems fairly trivial. Any ideas?

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  • Constructors and method chaining in JavaScript

    - by Sethen Maleno
    I am trying to make method chaining work in conjunction with my constructors, but I am not exactly sure how to go about it. Here is my code thus far: function Points(one, two, three) { this.one = one; this.two = two; this.three = three; } Points.prototype = { add: function() { return this.result = this.one + this.two + this.three; }, multiply: function() { return this.result * 30; } } var some = new Points(1, 1, 1); console.log(some.add().multiply()); I am trying to call the multiply method on the return value of the add method. I know there is something obvious that I am not doing, but I am just not sure what it is. Any thoughts?

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  • Ruby: What's going on here?

    - by user204078
    This question is based off some really odd code I recently found in a colleagues work. He claims not to know how it works only he copied it from somewhere else. That's not good enough for me I want to understand what's going on here. Say we have something like (test1, test2, test3="3", test4="4") the result will be that test1 == "3", test2 == "4", test3 == nil and test4 == "4" I understand why this happens, but if we do something like (test1, test2, test3="3", test4="4", test5 = "5", test6 = "6") now the result is test1 == "3", test2 == "4", test3 == "5", test4 == "6", test5 == "5", test6 == "6" Why isn't test5 == nil?

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  • jQuery.post not working when using data type json

    - by swift
    I have been trying to utilize json in this jQuery.post because I need to return two values from my executed php. The code was working when I was not implementing json. I need to see if a promo code entered is valid for a particular broker. The two variables I need back are the instant message whether or not it's valid (this is displayed to the user) and I need to update a hidden field that will be used later while updating the database. The jQuery.post does not seem to be firing at all, but the code directly above it (the ajax-loader.gif) is working. I did re-write the whole thing at one point using jQuery.ajax, and had issues there too. Granted, I have probably been looking at this too long and have tried to re-write too many times, but any help is greatly appreciated!! Here's the jQuery.post <!-- Below Script is for Checking Promo Code Against Database--> <script type="text/javascript"> jQuery(document).ready(function() { jQuery("#promocode").keyup(function (e) { //removes spaces from PromoCode jQuery(this).val(jQuery(this).val().replace(/\s/g, '')); var promocode = jQuery(this).val(); var brokerdealerid = document.getElementById("BrokerDealerId").value; if(promocode.length > 0 ){ jQuery("#promo-result").html('<img src="../imgs/ajax-loader.gif" />'); jQuery.post( '../check_promocode.php', {promocode:promocode, brokerdealerid:brokerdealerid}, function(data) { $("#promo-result").html(data.promoresult); $("#promo-result-valid").html(data.promovalid); }, "json"); } }); }); </script> <!-- End Script is for Checking Promo Code Against Database--> Here's relevant code from check_promocode.php: //sanitize incoming parameters if (isset($_POST['brokerdealerid'])) $brokerdealerid = sanitizeMySQL($_POST['brokerdealerid']); $promocode = sanitizeMySQL($promocode); //check promocode in db $results = mysql_query("SELECT PromotionCodeIdentifier FROM PromotionCode WHERE PromotionCodeIdentifier='$promocode' AND BrokerDealerId='$brokerdealerid' AND PromotionCodStrtDte <= CURDATE() AND PromotionCodExpDte >= CURDATE()"); //return total count $PromoCode_exist = mysql_num_rows($results); //total records //if value is more than 0, promocode is valid if($PromoCode_exist) { echo json_encode(array("promoresult"=>"Promotion Code Valid", "promovalid"=>"Y")); exit(); }else{ echo json_encode(array("promoresult"=>"Invalid Promotion Code", "promovalid"=>"N")); exit(); }

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  • How can I pass select field ID and its value to ajax without having any form?

    - by user3766078
    I have a select field which has ID name as 'region_code' well as its value. And I want pass ID in ajax. As you can see below, the input field is not included in any form. It has a value and the ID Is it possible to get value in ajax as shown below? echo '<select id="region_code" onchange="show_region_code();">'; $result = mysql_query("SELECT region_code, region_name FROM list_region"); while($rows = mysql_fetch_array($result)) { echo "<option value=\"$rows[0]\">".$rows["1"].'</option>'; } echo '</select>'; My ajax function as below function show_region_code() { var region_code = $("#region_code").val(); $.ajax ({ type: "POST", url: "show_region_code.php", data: { region_code1: region_code }, success: function(data) { $("#region_code").html(data); } }); }

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