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  • Retain a list of objects and pass it to the create/edit view when validation fails in ASP.NET MVC 2

    - by brainnovative
    I am binding a Foreign key property in my model. I am passing a list of possible values for that property in my model. The model looks something like this: public class UserModel { public bool Email { get; set; } public bool Name { get; set; } public RoleModel Role { get; set; } public IList<RoleModel> Roles { get; set; } } public class RoleModel { public string RoleName { get; set; } } This is what I have in the controller: public ActionResult Create() { IList<RoleModel> roles = RoleModel.FromArray(_userService.GetAllRoles()); UserModel model = new UserModel() { Roles = roles }; return View(model); } In the view I have: <div class="editor-label"> <%= Html.LabelFor(model => model.Role) %> </div> <div class="editor-field"> <%= Html.DropDownListFor(model => model.Role, new SelectList(Model.Roles, "RoleName", "RoleName", Model.Role))%> <%= Html.ValidationMessageFor(model => model.Role)%> </div> What do I need to do to get the list of roles back to my controller to pass it again to the view when validation fails. This is what I need: [HttpPost] public ActionResult Create(UserModel model) { if (ModelState.IsValid) { // insert logic here } //the validation fails so I pass the model again to the view for user to update data but model.Roles is null :( return View(model); } As written in the comments above I need to pass the model with the list of roles again to my view but model.Roles is null. Currently I ask the service again for the roles (model.Roles = RoleModel.FromArray(_userService.GetAllRoles());) but I don't want to add an extra overhead of getting the list from DB when I have already done that.. Anyone knows how to do it?

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  • Oracle: Is there a way to get the column data types for a view?

    - by rally25rs
    For a table in oracle, I can query "all_tab_columns" and get table column information, like the data type, precision, whether or not the column is nullable. In SQL Developer or TOAD, you can click on a view in the GUI and it will spit out a list of the columns that the view returns and the same set of data (data type, precision, nullable, etc). So my question is, is there a way to query this column definition for a view, the way you can for a table? How do the GUI tools do it?

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  • In which controller do you put the CRUD for the child part of a relationship?

    - by uriDium
    I am using ASP.Net MVC but this probably applies to all MVC patterns in general. My problem, for example I have companies and in each company I have a list of contacts. When I have selected a company I can see its details and a list of the contacts for that company. When I want to add a new contact for that company, should the implementation of that action go into the company controller as an "AddContact" action or should it go into the contact controller into a "New" action and we pass the Company ID in the URL? What is the usual way of dealing with this sort of thing in ASP.Net MVC? Is there a better stategy?

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  • How to call a php controller method using jquery?

    - by chandru_cp
    I am developing a web application and i am integrating jquery in it... Now looking for ajax calls with jquery to my controller function.... jquery.ajax() would be useful i think so... But how to call my controller method.... $.ajax({ type: "POST", url: "", data: "", contentType: "application/json; charset=utf-8", async: false, dataType: "json", success: function(jsonObj) { function loadbookdetails() { //Paging $college=$_SESSION['college']; $this->load->library('pagination'); $data['bookdetails'] = $this->librarymodel->selectbook($college); //$data['rackOptionData'] = $this->librarymodel->selectrack(); if(empty($data['bookdetails'])) { $data['comment'] = 'no record found!'; } $this->load->view('bookdetials',$data); } I am fetching this records here how to use it with jquery.ajax() function and how to convert $data to json and use it with jquery and iterate with a table...

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  • Send copy of class to view class so it can render him? ( iPhone )

    - by Johannes Jensen
    I'm making a game for the iPhone, and I have a class called Robot. Then I have a class called View, which renders everything. I want to send a copy of my Robot, which I defined in my ViewController, and I send it to gameView (which is View *gameView), like this: robot = [Robot new]; [gameView setRobot: [robot copy]]; I tried to make a copy but that didn't work, I could also do it with a pointer to Robot (&robot) but sometimes it just crashes ? I tried this in my View.h @interface definition: @property (copy) Robot* robot; but I get the error /RobotsAdventure/Classes/View.h:24: error: setter '-robot' argument type does not match property type :/ Help? I'm pretty new at this, heh.

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  • Default controller name is removed on browser refresh (CodeigniterPHP/Nginx issue?)

    - by tim peterson
    For all pages in my codeigniter app except my default controller, when I refresh the browser the url isn't affected as one would expect. However for my default controller, main.php, when when I refresh the browser at "http://localhost/main" or "http://mysite.com/main", the main part is stripped off the url. So the browser bar shows just "http://localhost" or "http://mysite.com". Totally lost on where to start with this but was just wondering if anyone has come across this before...? Here's what I think could be the relevant part of my nginx.conf (if Nginx is the problem). if ($request_uri ~* ^(/main(/index)?|/index(.php)?)/?$) { rewrite ^(.*)$ / permanent; }

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  • Spring mvc: controller returns [][], usable in jsp with foreach, but how to bind?

    - by Joe
    I'm building a spring mvc application. Now the problem I have is the following. I have a controller which adds a DayInfo[][] to my ModelMap. (DayInfo has an id, a title (String) and Text(also String). Now the problem I have is that I have no problem displaying this DayInfo[][] with foreach tags in my jsp. However I'm outputting the Title property as an input box(type text), and I'd like to be able to update this value (and thus saving it to be a database but that shouldn't be a problem). However I'm having trouble with binding this value to the input box so that it is actually returned to the controller. If anyone has some advice it would be welcome.

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  • Asp.Net (C#) MVC Routing - Trying avoid using the same controller in different places and think rout

    - by sheefy
    Hi Guys, I'm currently building a site which has a bunch of main categories and in each category you can perform a search. Basically, I want my addresses to work like this... When the website loads (as in when someone goes to www.mySite.com) it will redirect them to the default category. www.mySite.com/Category Then when you search within a category, the results would come up in a page like the following. www.mySite.com/Category/Search I want to put everything in one controller and have one main view for the Category and one for the Search, I would then render these based on which category is currently being viewed. Can this be done, maybe with routing? I don't want to have to create a different controller for each category as it's just duplicating a lot of the code. Thanks in advance for your help.

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  • How to call a jquery function from an action method in controller?

    - by Hasan Fahim
    I have a requirement to open a popup from an action method in controller. The action method is basically registering a user. [HttpPost] public ActionResult Register(RegisterModel model) { if (ModelState.IsValid) { MembershipCreateStatus createStatus; Membership.CreateUser(model.UserName, model.Password, model.Email, null, null, true, null, out createStatus); if (createStatus == MembershipCreateStatus.Success) { FormsAuthentication.SetAuthCookie(model.UserName, false /* createPersistentCookie */); //------------------------------------------ //I need to call a jquery function from here //------------------------------------------ return RedirectToAction("Index", "Home"); } else { ModelState.AddModelError("", ErrorCodeToString(createStatus)); } } return View(model); } The jquery function, present in the view, would just make a hidden DIV, visible, and set the opacity, etc, to represent a popup. I need to call such a jquery function from the controller's action method shown above.

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  • Codeigniter pre_system hook for DB driven dynamic controller selection - best approach?

    - by Andy
    Although I can tentatively see a solution to this, I was wondering if there may be a glaringly obvious simpler approach. My aim is to use the first segment of a given URI to query the DB as to which controller should be run. I assume I would have to reform the URI with the resultant controller name in segment 1, then allow the system to continue processing as normal (hence a pre_system hook). Although not essential I would also like to hold a couple of other variables from the same DB request to be used later in the call stack, and assume this would have to be done using global variables? Any better suggestions would be gladly received. Thanks.

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  • Loading an external NIB, how do I set the view property?

    - by Sheehan Alam
    If I am loading a view from another NIB, how do I set the File's Owner view property? IB is not letting me hook it up to my View Controller which is loading the external NIB. My NIB looks like this: File's Owner - Identity is set to LBRootViewController First Responder LBTableViewController - Identity is set to LBTableViewController, NIB Name is LBTableViewController

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  • Android layouts within layouts, with separate classes handling their input?

    - by Demonofloom
    Hey all, I have created a program in Java that uses Jpanels within Jpanels. One example of this is having a side view containing buttons that change the main view when pressed. The main view also has buttons that can be used to alter itself. I am trying to re-create this on the android. I have my layout set up from an xml, with a side panel containing buttons and the main view. There is another xml that contains what I want in the main view. Now I am struggling to get this separate xml to be displayed in the main view and can’t figure out how I would get the class to handle its own input. I don’t want to paste the code into the main.xml as I want to keep things object orientated and each view needs some custom elements such as different textviews. An example of what I am trying to convert for the android is below:- //The ViewInt class has its own layout ViewInt tempView = new ViewInt(i, mFloorNo); //The viewInt class is then added to the main window. mainWindowPanel.add(tempView); This small bit of code would create a view, add it to the main view and then any input in the main window is handled by that class, but at the same time any input not in this main window is handled by another class (probably the root class). Any help is greatly appreciated, thanks. To clarify: The program has a side panel layout, containing buttons. And a main view layout that is empty. I am trying to set a .xml layout to this main view layout, and have it so that if any buttons are pressed in that main view then a class for that layout will handle it.

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  • Qt: QStackedWidget solution

    - by Martin
    I'm building a Qt application that have about 30 different views (QWidgets). My idea is to use a QStackedWidget to make it easy to switch between the different views in the application. I have two different solutions of how to implement this and use as little memory as possible when the user navigates through the application. Solution 1: Everytime I need to show a view I check if it is already in the stack. (The user might open the same view many times, maybe a view showing an item from a database). If the view is in the stack already it doesn't need to be created again and I can just show the view. The good thing with this solution is that I reuse the views (widgets) so they only need to be created once. This is good as the UI and other stuff should look the same everytime the user show a view, so why not reuse it? The problem with this solution is that every view has childrens. Maybe an object, a QList with objects or other things. A good thing with Qt is that you can use the parent-children mechanism so that the children will be deleted when the parent is deleted. As I never delete the parent (view) I need to handle this myself as the children might need to be deleted from different times when the view is shown. (Maybe the view show a list with objects and the list should be updated from a database each time the view is shown.) Solution 2: Everytime I need to show a QWidget I create a new one and show it. When it is not shown anymore, I delete it from memory. This is a quite easy solution. And as I delete the views when they are not shown both the view and it's children should be deleted from memory so it shouldn't increase memory, am I right? Which one of the solutions do you recommend?

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  • View / ViewModel - what is the sense (in a WPF control)?

    - by TomTom
    Not as funny as it sounds. Normally the View / ViewModel should decouple the presentation from the business logic. Good. Now, a Control in WPF is basically invisible unless made different (with the exceptions of UserControl and Window that have XAML directly attached). The Style is putting in the "visual presentation" - which basically means a Control does not need a view mechanism as WPF already has one? In addition. the ViewModel is actually part of the Control, or? Just fighting with that stuff. I know in ASP.NET, WinForms the separation makes a lot of sense - but there, basically, controls HAVE an intrinsic look. In WPF, I have some where it makes sense (derived from UserControl), but for the majority of the controls I write, the View & ViewModel look like pretty much totally superflous thanks to the already presenting view mechanism.

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  • How do I reset the state of a view inside a tabbar?

    - by ABeanSits
    Hello CocoaTouch-Experts! This is a fairly straightforward question though my Googling session gave me nothing. How do I reset the state of a view hierarchy located in a tabbar programmatically? The behavior I want to replicate is when the user tapps on a tab twice. This causes the view located under that tab to return to it's initial state. The tab is "owned" by a UINavigationController and when the user reaches a certain point in the view hierarchy there is a button which I want to connect this behavior to. All my attempts have failed except calling on a method in AppDelegate which kills the view and adds it back to the UITabBarController again. But this does not feel like the right way to go. Thanks in advance. Best regards //Abeansits

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  • What special configuration is needed to have a domain controller with DNS on a VM in Hyper-V?

    - by Michael J. Gray
    I have a server running Windows Server 2012 and it only has the Hyper-V role. I have a VM also running Windows Server 2012 and it has the Active Directory: Directory Services and DNS ([example.com]) roles. It has been promoted to a domain controller for [example.com]. In the virtualization host I have joined the domain successfully. On a laptop on the network, it can ping my DNS that is inside the VM on the virtualization host. However, it can't resolve anything through the DNS. I figured it was a firewall issue where the DNS had the firewall allow rule, but the virtualization host did not. I added that, but it didn't fix the issue. On my laptop, I get "UnKnown can't find [example.com]: No response from server" immediately. There's no time out, it just comes back right away. What have I overlooked?

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  • How to separate model and view with Core Data?

    - by andrewebling
    I have a subclass of UIView which draws itself based on data held in a corresponding model class, which is a subclass of NSManagedObject. The problem is, some fields in the data model (e.g. the position of the view) are already held in the view (i.e. the frame property in this case). I then have a data duplication/synchronization problem to solve. To complicate matters further, the view needs to update in response to changes made to the data model and the data model needs to be updated in responses made to the view (e.g. the user dragging it to a new location). What's the best way to solve this? Using KVO and references in both directions? Or is there a better approach?

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  • Fetching only the first record in the table (via the view) without changing controller?

    - by bgadoci
    I am trying to only fetch the first record in my table for display. I am creating a site where a user can upload multiple images and attach to a post but I only want to display the first image view for each post. For further clarification posts belong_to projects. So when you are on the projects show page you see multiple posts. In this view I only want to display the first image for each post. Is there a way to do this in the view without affecting the controller (as later I want to allow users to browse all photos through the addition of a lightbox). Here is my /views/posts/_post.html.erb code: <% div_for post do %> <% post.photos.each do | photo | %> <%= image_tag(photo.data.url(:large), :alt => '') %> <%= photo.description %> <% end unless post.photos.first.new_record? rescue nil %> <%= link_to h(post.link_title), post.link %> <%= h(post.description) %> <%= link_to 'Manage this post', edit_post_path(post) %> <% end %> UPDATE: I am using a photos model to attach multiple photos to each post and using paperclip here.

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  • How to perform a cell deselection when a user returns to a table view?

    - by Panagiotis Korros
    I am using a UITableView to display a list of cells, when the user selects a cell then a new view appears by using the following code: - (void) tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath { [self.navigationController pushViewController: detailsViewController animated: TRUE]; } By using the code above, the view is displayed correctly, but when I return back to the root table view, then the cell is still selected. I noticed, in many sdk examples, that the cell is deselected (with a nice animation) when the root view is poped pack, but I could not find the code that implemented this feature in any of the examples. I know that I can use: [tableView deselectRowAtIndexPath:indexPath animated: YES]; to implement this, but I am very curious on how these examples do it without using any code. Any ideas?

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  • How to show empty view when ListView is empty?

    - by Sheehan Alam
    Here is my layout. For some reason the empty view (TextView in this case) always appears, even when the List is not empty. I thought the ListView would automatically detect when to show the empty view. How can I hook up the empty view properly? <RelativeLayout android:id="@+id/LinearLayoutAR" android:layout_height="fill_parent" android:layout_width="fill_parent"> <ListView android:layout_width="fill_parent" android:layout_height="fill_parent" xmlns:android="http://schemas.android.com/apk/res/android" android:id="@+id/ARListView"></ListView> <ProgressBar android:layout_width="wrap_content" android:layout_height="wrap_content" android:id="@+id/arProgressBar" android:layout_centerHorizontal="true" android:layout_centerVertical="true"></ProgressBar> <!-- Here is the view to show if the list is emtpy --> <TextView android:id="@id/android:empty" android:layout_width="match_parent" android:layout_height="match_parent" android:text="No Results" /> </RelativeLayout>

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