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  • Big Data Sessions at Openworld 2012

    - by Jean-Pierre Dijcks
    If you are coming to San Francisco, and you are interested in all the aspects to big data, this Focus On Big Data is a must have document.  Some (other) highlights: A performance demo of a full rack Big Data Appliance in the engineered systems showcase A set of handson labs on how to go from a NoSQL DB to an effective analytics play on big data Much, much more See you all in a few weeks in SF!

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  • How do you make sure your pakcet is delivered to right client using public ip address

    - by TemporaryNickName
    So private IP addresses are 192.168.00 ~ 192.168.255.255 or 10.0.0.0 or 172.16.0.0 ~ 172.31.255.255 If I accepted a client to my serversocket, I can get the client's remoteIp address by using socket.getremotesocketaddress(); But I suspect the IP address that I'm getting from this method is only the public IP address and it must have more than one client using same public IP as this one (one like you see when you go on to the website www.whatismyip.com). So if I want to make sure that my packet is delivered to the right person using some IP address or otherthing that uniquely identifies a person, what should I have to do?

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  • Big Oh Notation - formal definition.

    - by aloh
    I'm reading a textbook right now for my Java III class. We're reading about Big-Oh and I'm a little confused by its formal definition. Formal Definition: "A function f(n) is of order at most g(n) - that is, f(n) = O(g(n)) - if a positive real number c and positive integer N exist such that f(n) <= c g(n) for all n = N. That is, c g(n) is an upper bound on f(n) when n is sufficiently large." Ok, that makes sense. But hold on, keep reading...the book gave me this example: "In segment 9.14, we said that an algorithm that uses 5n + 3 operations is O(n). We now can show that 5n + 3 = O(n) by using the formal definition of Big Oh. When n = 3, 5n + 3 <= 5n + n = 6n. Thus, if we let f(n) = 5n + 3, g(n) = n, c = 6, N = 3, we have shown that f(n) <= 6 g(n) for n = 3, or 5n + 3 = O(n). That is, if an algorithm requires time directly proportional to 5n + 3, it is O(n)." Ok, this kind of makes sense to me. They're saying that if n = 3 or greater, 5n + 3 takes less time than if n was less than 3 - thus 5n + n = 6n - right? Makes sense, since if n was 2, 5n + 3 = 13 while 6n = 12 but when n is 3 or greater 5n + 3 will always be less than or equal to 6n. Here's where I get confused. They give me another example: Example 2: "Let's show that 4n^2 + 50n - 10 = O(n^2). It is easy to see that: 4n^2 + 50n - 10 <= 4n^2 + 50n for any n. Since 50n <= 50n^2 for n = 50, 4n^2 + 50n - 10 <= 4n^2 + 50n^2 = 54n^2 for n = 50. Thus, with c = 54 and N = 50, we have shown that 4n^2 + 50n - 10 = O(n^2)." This statement doesn't make sense: 50n <= 50n^2 for n = 50. Isn't any n going to make the 50n less than 50n^2? Not just greater than or equal to 50? Why did they even mention that 50n <= 50n^2? What does that have to do with the problem? Also, 4n^2 + 50n - 10 <= 4n^2 + 50n^2 = 54n^2 for n = 50 is going to be true no matter what n is. And how in the world does picking numbers show that f(n) = O(g(n))? Please help me understand! :(

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  • Big O Complexity of a method

    - by timeNomad
    I have this method: public static int what(String str, char start, char end) { int count=0; for(int i=0;i<str.length(); i++) { if(str.charAt(i) == start) { for(int j=i+1;j<str.length(); j++) { if(str.charAt(j) == end) count++; } } } return count; } What I need to find is: 1) What is it doing? Answer: counting the total number of end occurrences after EACH (or is it? Not specified in the assignment, point 3 depends on this) start. 2) What is its complexity? Answer: the first loops iterates over the string completely, so it's at least O(n), the second loop executes only if start char is found and even then partially (index at which start was found + 1). Although, big O is all about worst case no? So in the worst case, start is the 1st char & the inner iteration iterates over the string n-1 times, the -1 is a constant so it's n. But, the inner loop won't be executed every outer iteration pass, statistically, but since big O is about worst case, is it correct to say the complexity of it is O(n^2)? Ignoring any constants and the fact that in 99.99% of times the inner loop won't execute every outer loop pass. 3) Rewrite it so that complexity is lower. What I'm not sure of is whether start occurs at most once or more, if once at most, then method can be rewritten using one loop (having a flag indicating whether start has been encountered and from there on incrementing count at each end occurrence), yielding a complexity of O(n). In case though, that start can appear multiple times, which most likely it is, because assignment is of a Java course and I don't think they would make such ambiguity. Solving, in this case, is not possible using one loop... WAIT! Yes it is..! Just have a variable, say, inc to be incremented each time start is encountered & used to increment count each time end is encountered after the 1st start was found: inc = 0, count = 0 if (current char == start) inc++ if (inc > 0 && current char == end) count += inc This would also yield a complexity of O(n)? Because there is only 1 loop. Yes I realize I wrote a lot hehe, but what I also realized is that I understand a lot better by forming my thoughts into words...

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  • [php + mysql] Save IP in database

    - by Knarf
    When a user logs inn I want to save their IP in the database. How would I do that? What type is best to use for the MySQL field? How would the PHP code to get IP look like? I'm thinking of using it as an extra security feature for the login/session stuff. I'm thinking of checking the IP the user logged in with from the DB with the IP the user have now as addition to checking the session. So that it first check the session, and then check if you have a valid IP. Is that an allright extra feature? And what other things can I do to make it more secure?

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  • Trying to reconcile global ip address and Vhosts

    - by puk
    I have been using my local machine as a web server for a while, and I have several websites set up locally on my machine, all with similar Vhost files like the one seen here /etc/apache2/sites-available/john.smith.com: <VirtualHost *:80> RewriteEngine on RewriteOptions Inherit ServerAdmin [email protected] ServerName john.smith.com ServerAlias www.john.smith.com DocumentRoot /home/john/smith # Possible values include: debug, info, notice, warn, error, crit, # alert, emerg. LogLevel warn LogFormat "%v %l %u %t \"%r\" %>s %b" comonvhost CustomLog /var/log/apache2/access.log comonvhost </VirtualHost> then I set up the /etc/hosts file like so for every Vhost: 192.168.1.100 www.john.smith.com john.smith.com 192.168.1.100 www.jane.smith.com jane.smith.com 192.168.1.100 www.joe.smith.com joe.smith.com 192.168.1.100 www.jimbob.smith.com jimbob.smith.com Now I am hosting my friend's website until he gets a permanent domain. I have port forwarding set up to redirect port 80 to my machine, but I don't understand how the global ip fits into all of this. Do I for example use the following web site addresses (assume global ip is 12.34.56.789): 12.34.56.789.john.smith 12.34.56.789.jane.smith 12.34.56.789.joe.smith 12.34.56.789.jimbob.smith

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  • VPS with Plesk, one ip, and godaddy (definely need help)

    - by Francesco
    Hi there, here's my situation : i've Plesk 8.3.0 with one IP and i've registered my domains at godaddy.com My problem : i cannot figure out how to configure plesk and godaddy to have my domains (6) properly working into the VPS. i've only one IP, so i can't have my personal NS and need to use godaddy ns. But.. how do i set all the stuff ? I've made a try but it's not working. Please take a look : This is an example of how the domain i'm actually working on is configured On Plesk : Host Record type Value 1.2.3.4 / 24 PTR mydomain.com. ftp.mydomain.com. CNAME mydomain.com. mail.mydomain.com. A 1.2.3.4 ns.mydomain.com. A 1.2.3.4 mydomain.com. NS ns.mydomain.com. mydomain.com. A 1.2.3.4 mydomain.com. MX (10) mail.mydomain.com. webmail.mydomain.com. A 1.2.3.4 www.mydomain.com. CNAME mydomain.com. On godaddy,(Total DNS Control) for the same domain i have this setup : A (Host) Host Points To TTL Actions * 1.2.3.4 1 Hour CNAMES (Aliases) Host Points To TTL Actions e email.secureserver.net 1 Hour email email.secureserver.net 1 Hour ftp @ 1 Hour imap imap.secureserver.net 1 Hour mail pop.secureserver.net 1 Hour mobilemail mobilemail-v01.prod.mesa1.secureserver.net 1 Hour pda mobilemail-v01.prod.mesa1.secureserver.net 1 Hour pop pop.secureserver.net 1 Hour smtp smtp.secureserver.net 1 Hour webmail webmail.secureserver.net 1 Hour www @ 1 Hour MX (Mail Exchange) Priority Host Goes To TTL Actions 10 @ mailstore1.secureserver.net 1 Hour 0 @ smtp.secureserver.net Host Points To TTL Actions @ ns53.domaincontrol.com @ ns54.domaincontrol.com What should i correct ? Thanks for helping me Francesco

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  • Running two different websites domains one one IP address

    - by Akshar Prabhu Desai
    Here is my apache configuration file. I have two domain names running on same ip but i want them to point to different webapps. But in this case both point to the one intended for e-yantra.org. If I copy paste akshar.co.in part before E-yantra.org both start pointing to akshar.co.in I have two A DNS entries (one per domain name) pointing to the same IP. NameVirtualHost *:80 <VirtualHost *:80> ServerName www.e-yantra.org ServerAdmin [email protected] DocumentRoot /var/www <Directory /> Options FollowSymLinks AllowOverride All </Directory> <Directory /var/www/> Options Indexes FollowSymLinks MultiViews AllowOverride All Order allow,deny allow from all </Directory> <Directory /var/www/ci/> Options Indexes FollowSymLinks MultiViews AllowOverride All Order allow,deny allow from all </Directory> <Directory /var/www/db2/> Options Indexes FollowSymLinks MultiViews AllowOverride All Order allow,deny allow from all </Directory> ScriptAlias /cgi-bin/ /usr/lib/cgi-bin/ <Directory "/usr/lib/cgi-bin"> AllowOverride None Options +ExecCGI -MultiViews +SymLinksIfOwnerMatch Order allow,deny Allow from all </Directory> ErrorLog /var/log/apache2/error.log # Possible values include: debug, info, notice, warn, error, crit, # alert, emerg. LogLevel warn CustomLog /var/log/apache2/access.log combined Alias /doc/ "/usr/share/doc/" <Directory "/usr/share/doc/"> Options Indexes MultiViews FollowSymLinks AllowOverride None Order deny,allow Deny from all Allow from 127.0.0.0/255.0.0.0 ::1/128 </Directory> </VirtualHost> <VirtualHost *:80> ServerName www.akshar.co.in ServerAdmin [email protected] DocumentRoot /var/akshar.co.in <Directory /var/akshar.co.in/> Options Indexes FollowSymLinks MultiViews AllowOverride All Order allow,deny allow from all </Directory> </VirtualHost>

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  • Varnish configuration, NamevirtualHosts, and IP Forwarding

    - by Brent
    I currently have a bunch of NameVirtualHost based websites, load balanced between 3 apache2 servers using ldirectord. I would like to insert varnish as a reverse-web-proxy between ldirectord and apache in the following way: a request comes in to ldirectord it is then load balanced between the 3 apache2 servers and varnish, with a weight of 1 for the webservers, and 99 for varnish (so if varnish is rebooted, the webservers will take over seamlessly) varnish will then load balance its requests between my apache2 servers. However, the varnish part is not working. I wonder whether this has to do with the fact that my apache servers use x.x.x.x:80 for their NameVirtualHosts, instead of *:80? (they have to do this, since each server hosts multiple IP addresses) Or perhaps it has to do with the need for IP Forwarding to be set up on the varnish server? (I did echo 1 /proc/sys/net/ipv4/ip_forward on this server, is that sufficient?) How can I debug this problem? ldirectord doesn't produce logs of what it does with each request (and if it did, I would be overwhelmed with information since I'm serving hundreds of requests per second) varnish log shows the ldirectord server connecting to it every 5 seconds, but nothing else. I have set up a test site using this configuration, but it fails - no apache access logs, no applicable varnish logs.

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  • Force local IP traffic to an external interface

    - by calandoa
    I have a machine with several interfaces that I can configure as I want, for instance: eth1: 192.168.1.1 eth2: 192.168.2.2 I would like to forward all the traffic sent to one of these local addresses through the other interface. For instance, all requests to an iperf, ftp, http server at 192.168.1.1 should be not just routed internally, but forwarded through eth2 (and the external network will take care of re-routing the packet to eth1). I tried and looked at several commands, like iptables, ip route, etc... but nothing worked. The closest behavior I could get was done with: ip route change to 192.168.1.1/24 dev eth2 which send all 192.168.1.x on eth2, except for 192.168.1.1 which is still routed internally. May be I could then do NAT forwarding of all traffic directed to fake 192.168.1.2 on eth1, rerouted to 192.168.1.1 internally? I am actually struggling with iptables, but it is too tough for me. The goal of this setup is to do interface driver testing without using two PCs. I am using Linux, but if you know how to do that with Windows, I'll buy it!

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  • Multiple IP's using one NIC connectivity problem - Windows

    - by Vincent
    I have a frame relay network that is directly connected to a GPRS network. I also have a ADSL high speed network and recently I have been trying to achieve the following network configuration using windows 7 (Also tried XP) with no success to date. On one server I have two NIC's NIC1 I would like the following two static IP address's 10.0.1.110 and 10.0.1.200 the cisco router has a default gateway of 10.0.1.1 the ADSL is DHCP. NIC1 and the cisco router do not have access to the internet. NIC2 is setup for DHCP with a primary DNS and secondary DNS configured to enable internet connectivity. With NIC1 all incoming TCP connections are from IP address's starting with 10.192.x.x I cannot establish a TCP connection to both 10.0.1.110 and 10.0.1.200. Its either one or the other. I have a static route implemented in windows of: route -p 10.192.0.0 mask 255.255.0.0 10.0.1.1 metric 1 I have tried leaving out the gateway in the NIC1 and many other combinations with no success. Can anyone please help? What am I doing wrong?

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  • Get Internal IP Address From DHCP Hostname

    - by ell
    I would like to try and get an internal ip address of one of the computers on my network. The reason for this is I have a little home server box downstairs but every time I want to SSH into it I have to open my router configuration and go on the DHCP client table and look at the IP address. For example I would like to be able to go ssh ell-sever instead of ssh 192.168.1.105 or whatever it happens to be. My network configuration is like so: Router downstairs that is connected to the Internet and is running a DHCP server My server computer (ell-server) is a headless pc connected to the router via ethernet cable. Running Ubuntu 11.04 Server Edition My laptop upstairs (ell-laptop) that is running Ubuntu 11.10 Desktop Edition connected wirelessly Other (irrelevant) computers - 2 x Windows XP, 1 x Xubuntu - all connected with cables. (It seemed to me the method of connection isn't useful information but I put it in anyway - just in case. If I have missed any information please tell me) Do I have to run a DNS server on one of my computers? If so which one? And does that mean I will have to run a DDNS client on each computer? Thanks in advance, ell.

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  • Private IP getting routed over Internet

    - by WernerCD
    We are setting up an internal program, on an internal server that uses the private 172.30.x.x subnet... when we ping the address 172.30.138.2, it routes across the internet: C:\>tracert 172.30.138.2 Tracing route to 172.30.138.2 over a maximum of 30 hops 1 6 ms 1 ms 1 ms xxxx.xxxxxxxxxxxxxxx.org [192.168.28.1] 2 * * * Request timed out. 3 12 ms 13 ms 9 ms xxxxxxxxxxx.xxxxxx.xx.xxx.xxxxxxx.net [68.85.xx.xx] 4 15 ms 11 ms 55 ms te-7-3-ar01.salisbury.md.bad.comcast.net [68.87.xx.xx] 5 13 ms 14 ms 18 ms xe-11-0-3-0-ar04.capitolhghts.md.bad.comcast.net [68.85.xx.xx] 6 19 ms 18 ms 14 ms te-1-0-0-4-cr01.denver.co.ibone.comcast.net [68.86.xx.xx] 7 28 ms 30 ms 30 ms pos-4-12-0-0-cr01.atlanta.ga.ibone.comcast.net [68.86.xx.xx] 8 30 ms 43 ms 30 ms 68.86.xx.xx 9 30 ms 29 ms 31 ms 172.30.138.2 Trace complete. This has a number of us confused. If we had a VPN setup, it wouldn't show up as being routed across the internet. If it hit an internet server, Private IP's (such as 192.168) shouldn't get routed. What would let a private IP address get routed across servers? would the fact that it's all comcast mean that they have their routers setup wrong?

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  • Two network interfaces and two IP addresses on the same subnet in Linux

    - by Scott Duckworth
    I recently ran into a situation where I needed two IP addresses on the same subnet assigned to one Linux host so that we could run two SSL/TLS sites. My first approach was to use IP aliasing, e.g. using eth0:0, eth0:1, etc, but our network admins have some fairly strict settings in place for security that squashed this idea: They use DHCP snooping and normally don't allow static IP addresses. Static addressing is accomplished by using static DHCP entries, so the same MAC address always gets the same IP assignment. This feature can be disabled per switchport if you ask and you have a reason for it (thankfully I have a good relationship with the network guys and this isn't hard to do). With the DHCP snooping disabled on the switchport, they had to put in a rule on the switch that said MAC address X is allowed to have IP address Y. Unfortunately this had the side effect of also saying that MAC address X is ONLY allowed to have IP address Y. IP aliasing required that MAC address X was assigned two IP addresses, so this didn't work. There may have been a way around these issues on the switch configuration, but in an attempt to preserve good relations with the network admins I tried to find another way. Having two network interfaces seemed like the next logical step. Thankfully this Linux system is a virtual machine, so I was able to easily add a second network interface (without rebooting, I might add - pretty cool). A few keystrokes later I had two network interfaces up and running and both pulled IP addresses from DHCP. But then the problem came in: the network admins could see (on the switch) the ARP entry for both interfaces, but only the first network interface that I brought up would respond to pings or any sort of TCP or UDP traffic. After lots of digging and poking, here's what I came up with. It seems to work, but it also seems to be a lot of work for something that seems like it should be simple. Any alternate ideas out there? Step 1: Enable ARP filtering on all interfaces: # sysctl -w net.ipv4.conf.all.arp_filter=1 # echo "net.ipv4.conf.all.arp_filter = 1" >> /etc/sysctl.conf From the file networking/ip-sysctl.txt in the Linux kernel docs: arp_filter - BOOLEAN 1 - Allows you to have multiple network interfaces on the same subnet, and have the ARPs for each interface be answered based on whether or not the kernel would route a packet from the ARP'd IP out that interface (therefore you must use source based routing for this to work). In other words it allows control of which cards (usually 1) will respond to an arp request. 0 - (default) The kernel can respond to arp requests with addresses from other interfaces. This may seem wrong but it usually makes sense, because it increases the chance of successful communication. IP addresses are owned by the complete host on Linux, not by particular interfaces. Only for more complex setups like load- balancing, does this behaviour cause problems. arp_filter for the interface will be enabled if at least one of conf/{all,interface}/arp_filter is set to TRUE, it will be disabled otherwise Step 2: Implement source-based routing I basically just followed directions from http://lartc.org/howto/lartc.rpdb.multiple-links.html, although that page was written with a different goal in mind (dealing with two ISPs). Assume that the subnet is 10.0.0.0/24, the gateway is 10.0.0.1, the IP address for eth0 is 10.0.0.100, and the IP address for eth1 is 10.0.0.101. Define two new routing tables named eth0 and eth1 in /etc/iproute2/rt_tables: ... top of file omitted ... 1 eth0 2 eth1 Define the routes for these two tables: # ip route add default via 10.0.0.1 table eth0 # ip route add default via 10.0.0.1 table eth1 # ip route add 10.0.0.0/24 dev eth0 src 10.0.0.100 table eth0 # ip route add 10.0.0.0/24 dev eth1 src 10.0.0.101 table eth1 Define the rules for when to use the new routing tables: # ip rule add from 10.0.0.100 table eth0 # ip rule add from 10.0.0.101 table eth1 The main routing table was already taken care of by DHCP (and it's not even clear that its strictly necessary in this case), but it basically equates to this: # ip route add default via 10.0.0.1 dev eth0 # ip route add 130.127.48.0/23 dev eth0 src 10.0.0.100 # ip route add 130.127.48.0/23 dev eth1 src 10.0.0.101 And voila! Everything seems to work just fine. Sending pings to both IP addresses works fine. Sending pings from this system to other systems and forcing the ping to use a specific interface works fine (ping -I eth0 10.0.0.1, ping -I eth1 10.0.0.1). And most importantly, all TCP and UDP traffic to/from either IP address works as expected. So again, my question is: is there a better way to do this? This seems like a lot of work for a seemingly simple problem.

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  • How can I change the location of my ip address to Orlando, FL from other city where I live and using forum/chat-room? [on hold]

    - by MSEUCF
    I live in West Palm Beach, Florida. However, I am attending to school at University of Center Florida for materials science and engineering. Right now, I am on vacation and live in WPB, FL. There is one certainly problem when I login at private forum I'm getting error for not same the ip-address so I had to make new account with false information in city and still unable to success. Of course, it won't do that due to policy from forum required the ip-address has to be same in Orlando, FL. local only. How can I change the location of my ip address to Orlando? Also, in chat-room from forum it would show my ip-address so I'd be in trouble if they find out that I am not live in Orlando. Please help with me. Tell me how to change ip adress step and step. Thank you. *I use AT&T and Belkin Router Wifi. Forgiven me for my English is not very well. ESL. I am a foreign student.

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  • big O notation algorithm

    - by niggersak
    Use big-O notation to classify the traditional grade school algorithms for addition and multiplication. That is, if asked to add two numbers each having N digits, how many individual additions must be performed? If asked to multiply two N-digit numbers, how many individual multiplications are required? . Suppose f is a function that returns the result of reversing the string of symbols given as its input, and g is a function that returns the concatenation of the two strings given as its input. If x is the string hrwa, what is returned by g(f(x),x)? Explain your answer - don't just provide the result!

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  • Tricky Big-O complexity

    - by timeNomad
    public void foo (int n, int m) { int i = m; while (i > 100) i = i/3; for (int k=i ; k>=0; k--) { for (int j=1; j<n; j*=2) System.out.print(k + "\t" + j); System.out.println(); } } I figured the complexity would be O(logn). That is as a product of the inner loop, the outer loop -- will never be executed more than 100 times, so it can be omitted. What I'm not sure about is the while clause, should it be incorporated into the Big-O complexity? For very large i values it could make an impact, or arithmetic operations, doesn't matter on what scale, count as basic operations and can be omitted?

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  • Database indexes and their Big-O notation

    - by miket2e
    I'm trying to understand the performance of database indexes in terms of Big-O notation. Without knowing much about it, I would guess that: Querying on a primary key or unique index will give you a O(1) lookup time. Querying on a non-unique index will also give a O(1) time, albeit maybe the '1' is slower than for the unique index (?) Querying on a column without an index will give a O(N) lookup time (full table scan). Is this generally correct ? Will querying on a primary key ever give worse performance than O(1) ? My specific concern is for SQLite, but I'd be interested in knowing to what extent this varies between different databases too.

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  • Can someone help with big O notation?

    - by Dann
    void printScientificNotation(double value, int powerOfTen) { if (value >= 1.0 && value < 10.0) { System.out.println(value + " x 10^" + powerOfTen); } else if (value < 1.0) { printScientificNotation(value * 10, powerOfTen - 1); } else // value >= 10.0 { printScientificNotation(value / 10, powerOfTen + 1); } } I understand how the method goes but I cannot figure out a way to represent the method. For example, if value was 0.00000009 or 9e-8, the method will call on printScientificNotation(value * 10, powerOfTen - 1); eight times and System.out.println(value + " x 10^" + powerOfTen); once. So the it is called recursively by the exponent for e. But how do I represent this by big O notation? Thanks!

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  • Calculating and billing IP multicast usage on the Internet

    - by obvio171
    I've been searching for the reasons why IP multicast isn't widely supported on the Public Internet, and a commonly-cited reason is the difficulty ISPs have in tracking Multicast usage for later billing. Given this difficulty, since ISPs control the routers and they're not forced to support Multicast (as per IPv4), they just disable it. I couldn't find what this difficulty was though. Since an ISP has full control of any inbound and outbound traffic, be it Unicast or Multicast, what's the difficulty in tracking and billing the latter that does not exist in the former?

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  • Ubuntu 12.04: apt-get "failed to fetch"; apt is trying to fetch via old static IP

    - by gabe
    Sample error: W: Failed to fetch http://security.ubuntu.com/ubuntu/dists/precise-security/universe/i18n/Translation-en Unable to connect to 192.168.1.70:8118: Now this was working just fine until I changed the IP this morning. I have the server set to a static IP of 10.0.1.70 and for years it has been 192.168.1.70 - the IP apt-get is trying to use right now. I use privoxy and tor thus the 8118 port. Like I said it all worked until I changed the static IP from 192.168.1.70 to 10.0.1.70. I was forced to do so because of router issues. (Long and involved story, I didn't really want to change the IP because I know something like this would happen.) The setup for TOR/Privoxy requires that has you point Privoxy at TOR via 127.0.0.1:9050. Then point curl, etc to Privoxy via $HOME/.bashrc. Typically you would set the listen to IP for Privoxy to 127.0.0.1 but if you want it accessible to the rest of the LAN you set the IP to the server's LAN IP. Which I did a long time ago and was working fine until this morning. I have changed all instances of 192.168.1.70 to 10.0.1.70 in both /etc/privoxy/config and $HOME/.bashrc. What makes this really strange for me is that curl is working fine. I curl icanhazip.com and voila I get a new IP every 10 minutes or so. I curl CNN.com and I get the short but sweet permanently moved to www.cnn.com message I expect. Firefox works fine. Ping works fine. And I've tested all of this via Remote Desktop over my LAN. So the connection appears to be fine for everything except apt. I've also rebooted hoping that would clear 192.168.1.70 from apt. So the connection to the internet and DNS aren't an issue for these programs. And they are, as far as I can tell, using Privoxy/TOR just fine. The real irony here is that I've tried to open up Privoxy to go to Ubuntu's servers directly without going through TOR to speed up the downloads from Ubuntu (did this months ago). So somewhere that I have not been able to find, apt has stored the IP 192.168.1.70. And 192.168.1.70 is no longer valid. Thanks for the help

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  • Restrict VPN client traffic to certain domains/IP

    - by mr-euro
    Hi Is there any way to restrict a VPN client to only route certain traffic via the VPN and the rest via their local gateway? For example: traffic to a certain IP or domain gets routed across the VPN and all other requests do not. Let me know if you need more details. Thank you.

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  • Issues with static IP (Ubuntu Server 10.04)

    - by letseatfood
    I am following this tutorial for setting up a testing server for my web development projects. When I attempt setting up a static IP address (using the configuration below), I receive the error "ping: unknown host www.google.com" when I attempt using ping. auto eth0 iface eth0 inet static address 192.168.0.100 netmask 255.255.255.0 network 192.168.0.0 broadcast 192.168.0.255 gateway 192.168.0.1 Ping works fine when the configuration is: auto eth0 iface eth0 inet static I am a novice to server setup and administration.

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