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• Password-protected sharing allows access to users who have no account?

  - by romkyns

  Running Win7 on two computers in my LAN. Computer A has password-protected sharing enabled, and shares a folder. It has a single user account "Bob", and the Guest account is turned off. The network is workgroup-based. According to the descriptions of the "password-protected sharing" I could find, the only people who can access the shared folder via the LAN are those who know the username+password for the "Bob" account. However a second computer on the LAN is able to view this shared folder by simply browsing to Computer A. They don't need to enter any passwords or anything. The only user account registered on that PC is called "Jim", and has a different password from "Bob". How on earth is computer B able to view this shared folder? Is the popular description of the "password-protected sharing" feature inaccurate / did I misunderstand it big time? P.S. There is a possibility that the password for "Bob" has been entered on that PC once, and possibly the "remember password" box was checked. I've looked in the "Credential Manager" on both computers and there is nothing saved anywhere.

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• What does Apache's "Require all granted" really do?

  - by John Crawford

  I've just update my Apache server to Apache/2.4.6 which is running under Ubuntu 13.04. I used to have a vhost file that had the following: <Directory "/home/john/development/foobar/web"> AllowOverride All </Directory> But when I ran that I got a "Forbidden. You don't have permission to access /" After doing a little bit of googling I found out that to get my site working again I needed to add the following line "Require all granted" so that my vhost looked like this: <Directory "/home/john/development/foobar/web"> AllowOverride All Require all granted </Directory> I want to know if this is "safe" and does not bring in any security issues. I read on Apache's page that this "mimics the functionality the was previously provided by the 'Allow from all' and 'Deny from all' directives. This provider can take one of two arguments which are 'granted' or 'denied'. The following examples will grant or deny access to all requests." But it didn't say if this was a security issue of some sort or why we now have to do it when in the past you did not have to.

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• Silverlight Cream for March 21, 2010 -- #816

  - by Dave Campbell

  In this Issue: Michael Washington, John Papa(-2-, -3-, -4-), Jonas Follesø, David Anson, Scott Guthrie, Andrej Tozon, Bill Reiss(-2-), Pete Blois, and Lee. Shoutouts: Frank LaVigne has a Mix10 Session Downloader for us all to use... thanks Frank! Read what Ward Bell has to say about MVVM, Josh Smith’s Way ... it's all good. Robby Ingebretsen posts on his 10 Favorite Open Source Fonts You Can Embed in WPF or Silverlight Mike Harsh posted Slides and Demos from my MIX10 Session . The download link at Drop.io is down for maintenance until Sunday evening, March 21. From SilverlightCream.com: Blend 4: TreeView SelectedItemChanged using MVVM Michael Washington has a post up about doing SelectedItemChanged on a TreeView with MVVM, oh and he's starting out in Blend 4... Silverlight TV 14: Developing for Windows Phone 7 with Silverlight John Papa hit Silverlight TV pretty hard at the beginning of MIX10. This first one is with Mike Harsh talking about WP7. (Hi Mike ... wondered where you'd run off to!), and you can go to the shoutout section to get Mike's session material from MIX as well. Silverlight TV 15: Announcing Silverlight 4 RC at MIX 10 In this next Silverlight TV(15), John Papa and Adam Kinney discuss Silverlight 4RC ... thank goodness it's out, we can all let go of the breath we've been holding in :) Silverlight TV 16: Tim Heuer and Jesse Liberty Talk about Silverlight 4 RC at MIX 10 Silverlight TV 16 has John Papa sharing the spotlight with Jesse Liberty and Tim Heuer ... geez... can you find 3 more kowledgable Silverlight folks to listen to? No? then go listen to this :) Silverlight TV 17: Build a Twitter Client for Windows Phone 7 with Silverlight The latest Silverlight TV has John Papa bringing Mike Harsh back to produce a Twitter Client for WP7. Simulating multitouch on the Windows Phone 7 Emulator Jonas Follesø has a great post up about simulating multi-touch on WP7 using multiple mice ... yeah, you read that right :) Using IValueConverter to create a grouped list of items simply and flexibly David Anson demonstrates grouping items in a ListBox using IValueConverter. I think I can pretty well guarantee I would NOT have thought of doing this.. :) Building a Windows Phone 7 Twitter Application using Silverlight In the MIX10 first-day keynote, Scott Guthrie did File->New Project and built a WP7 Twitter app. He has that up as a tutorial with all sorts of external links including one to the keynote itself. Named and optional parameters in Silverlight 4 Andrej Tozon delves into the optional parameters that are now available to Silverlight developers... pretty cool stuff. Space Rocks game step 4: Inheriting from Sprite Bill Reiss continues with his game development series with this one on inheriting from the Sprite class and centering objects Space Rocks game step 5: Rotating the ship Bill Reiss's episode 5 is on rotating the ship you setup in episode 4. Don't worry about the transforms, Bill gives it all to us :) Labyrinth Sample for Windows Phone Wow... check out the sample Pete Blois did for the Phone... Silverlight coolness :) PathListBox in SL4 – firstlook Lee has a post up on the PathListBox. I think this is going to catch on quick... it's just too cool not to! Stay in the 'Light! Twitter SilverlightNews | Twitter WynApse | WynApse.com | Tagged Posts | SilverlightCream Join me @ SilverlightCream | Phoenix Silverlight User Group Technorati Tags: Silverlight    Silverlight 3    Silverlight 4    Windows Phone MIX10

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• ASP.NET/C#: How to use a Subclassed Control on a Page?

  - by Bob Kaufman

  I've subclassed DropDownList to add functionality specific to my application: public class MyDropDownList : DropDownList { ... } ... then referenced it in Web.Config, which is where I figure things start to go wrong: <pages theme="Main"> <controls> <add tagPrefix="bob" tagName="MyDropDownList" src="~/Components/MyDropDownList.cs" /> </controls> </pages> my reference to it does not work: <tr><td>Category</td> <td><bob:MyDropDownList runat="server" ID="Category"... /> and my best clue is the complier error message: "The file 'src' is not a valid [sic] here because it doesn't expose a type." I figure I'm misapplying knowledge of how to create a Web User Control here. What I want to be able to do is refer to this control on an ASP.NET page just like I would the parent DropDownList. Refactoring back into a Web User Control that contains a DropDownList is not desirable, because I want to apply a RequiredFieldValidator to it.

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• ArchBeat Link-o-Rama Top 10 for October 28 - November 3, 2012

  - by Bob Rhubart

  The Top 10 most popular items shared on the OTN ArchBeat Facebook Page for the week of Oct 28 - Nov 3, 2012. Eventually, 90% of tech budgets will be outside IT departments | ZDNet Another interesting post from ZDNet blogger Joe McKendrick about changing roles in IT. ADF Mobile - Login Functionality | Andrejus Baranovskis "The new ADF Mobile approach with native deployment is cool when you want to access phone functionality (camera, email, sms and etc.), also when you want to build mobile applications with advanced UI," reports Oracle ACE Director Andrejus Baranovskis. Mobile Development Platform Strategy Chart: ADF Mobile, WebCenter Sites, Portal, Content and Social "Unlike desktop web focused efforts, the world of mobile has undergone change at a feverish pace," says social enterprise expert John Brunswick. His extensive post charts various resources that will help you keep up. ADF Essentials - The Bare Necessities | Floyd Teter The experiment is over… And now Oracle ACE Director Floyd Teter shares his impressions after spending some time with Oracle ADF Essentials, the free version of Oracle ADF. A review of Oracle SOA Suite 11g Administrator’s Handbook | RedStack "More so than any other single piece of content that I have seen on the topic, it provides the information that a SOA administrator needs to know in order to successfully configure, manage, monitor, troubleshoot and backup an Oracle SOA environment." So says Oracle Fusion Middleware A-Team solution architect Mark Nelson of Oracle SOA Suite 11g Administrator’s Handbook, by Ahmed Aboulnaga and Arun Pareek. Expanding the Oracle Enterprise Repository with functional documentation Capgemini middleware specialist Marc Kuijpers shares information on how Oracle Enterprise Repository can be configured "to contain functional assets, i.e. functional designs, use cases and a logical data model" to aid in SOA governance efforts. Podcast: Are You Future Proof? - Part 2 In Part 2, practicing architects and Oracle ACE Directors Ron Batra (AT&T), Basheer Khan (Innowave Technology), and Ronald van Luttikhuizen discuss re-tooling one’s skill set to reflect changes in enterprise IT, including the knowledge to steer stakeholders around the hype to what’s truly valuable. Easy way to access JPA with REST (JSON / XML) | Edwin Biemond Oracle ACE Edwin Biemond shows you "what is possible with JPA-RS, how easy it is and howto setup your own EclipseLink REST service." Clustering ODI11g for High-Availability Part 1: Introduction and Architecture | Richard Yeardley "JEE agents can be deployed alongside, or instead of, standalone agents," says Rittman Meade's Richard Yeardley. "But there is one key advantage in using JEE agents and WebLogic: when you deploy JEE agents as part of a WebLogic cluster they can be configured together to form a high availability cluster." Learn more in Yeardley's extensive post. 2012 IOUG Virtualization SIG – Online Symposium on Nov 7 and Nov 8 | Kai Yu Oracle ACE Director Kai Yu shares information on this week's IOUG Virtualization SIG online event. Does that make it a virtual virtualization event? Thought for the Day "If McDonalds were run like a software company, one out of every hundred Big Macs would give you food poisoning — and the response would be, 'We’re sorry, here’s a coupon for two more.'" — Mark Minasi Source: SoftwareQuotes.com

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• Architect Day: Boston - Agenda Update

  - by Bob Rhubart

  Here's the latest information on the session schedule and content for Oracle Technology Network Architect Day in Boston, MA on September 12, 2012. Registration is open, but seating is limited. When: September 12, 2012 8:30am – 5:00pm Where: Boston Marriott Burlington One Burlington Mall Road Burlington, MA 01803 Register now Agenda Time Session Title Room 8:30 am - 9:00 am Registration and Continental Breakfast Salon E Foyer 9:00 am - 9:15 am Welcome and Opening Comments | Bob Rhubart Salon E 9:15 am - 10:00 am Engineered Systems: Oracle's Vision for the Future | Ralf Dossmann Oracle's Exadata and Exalogic are impressive products in their own right. But working in combination they deliver unparalleled transaction processing performance with up to a 30x increase over existing legacy systems, with the lowest cost of ownership over a 3 or 5 year basis than any other hardware. In this session you'll learn how to leverage Oracle's Engineered Systems within your enterprise to deliver record-breaking performance at the lowest TCO. Salon E 10:00 am - 10:30 am Securing Public and Private Clouds | Anton Nielsen Long before the term "Cloud Computing" existed, Oracle technologies supported and promoted the concept. Centralized data with remote users has been at the core of these technologies for decades. The public cloud, and extending private clouds to the internet, though, has added security challenges never imagined decades ago. This presentation will examine a real life security breach and introduce architecture, technologies and policies to secure public and private clouds.  Salon E 10:30 am - 10:45 am Break 10:45 am - 11:30 am Breakout Sessions (pick one) Cloud Computing - Making IT Simple | Scott Mattoon The road to Cloud Computing is not without a few bumps. This session will help to smooth out your journey by tackling some of the potential complications. We'll examine whether standardization is a prerequisite for the Cloud. We'll look at why refactoring isn't just for application code. We'll check out deployable entities and their simplification via higher levels of abstraction. And we'll close out the session with a look at engineered systems and modular clouds. Salon E Innovations in Grid Computing with Oracle Coherence | Rob Misek Learn how Coherence can increase the availability, scalability and performance of your existing applications with its advanced low-latency data-grid technologies. Also hear some interesting industry-specific use cases that customers had implemented and how Oracle is integrating Coherence into its Enterprise Java stack. Salon C 11:30 am - 12:15 pm Breakout Sessions (pick one) Enterprise Strategy for Cloud Security | Dave Chappelle Security is high on the list of concerns for many organizations as they evaluate their cloud computing options. This session will examine security in the context of the various forms of cloud computing. We'll consider technical and non-technical aspects of security, and discuss several strategies for cloud computing, from both the consumer and producer perspectives. Salon E Oracle Enterprise Manager | Avi Huber Much more than a DB management tool, Oracle Enterprise Manager provides management and monitoring coverage for the entire Oracle stack, and beyond. This session will concentrate on the middleware management functionality in OEM, starting with Real User Experience monitoring, through AppServer management, and into deep-dive Java diagnostics. We’ll discuss Business Driven Application Management (BDAM) and the benefits of top-down monitoring. Lastly, we’ll demonstrate how to trace a specific user experience problem, through a multitier SOA application, to its root cause, deep in the JVM. Salon C 12:15 pm - 1:15 pm Lunch Salon E Foyer 1:15 pm - 2:00 pm Panel Discussion - Q&A with session speakers Salon E 2:00 pm - 2:45 pm Breakout Sessions (pick one) Oracle Cloud Reference Architecture | Anbu Krishnaswamy Cloud initiatives are beginning to dominate enterprise IT roadmaps. Successful adoption of Cloud and the subsequent governance challenges warrant a Cloud reference architecture that is applied consistently across the enterprise. This presentation will answer the important questions: What exactly is a Cloud, why you need it, what changes it will bring to the enterprise, and what are the key capabilities of a Cloud infrastructure are - using Oracle's Cloud Reference Architecture, which is part of the IT Strategies from Oracle (ITSO) Cloud Enterprise Technology Strategy (ETS). Salon E 21st Century SOA | Peter Belknap Service Oriented Architecture has evolved from concept to reality in the last decade. The right methodology coupled with mature SOA technologies has helped customers demonstrate success in both innovation and ROI. In this session you will learn how Oracle SOA Suite's orchestration, virtualization, and governance capabilities provide the infrastructure to run mission critical business and system applications. And we'll take a special look at the convergence of SOA & BPM using Oracle's Unified technology stack. Salon C 2:45 pm - 3:00 pm Break 3:00 pm - 4:00 pm Roundtable Discussion Salon E 4:00 pm - 4:15 pm Closing Comments & Readouts from Roundtables Salon E 4:15 pm - 5:00 pm Networking / Reception Salon E Foyer Note: Session schedule and content subject to change.

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• Updated Agenda for OTN Architect Day Los Angeles (Oct 25)

  - by Bob Rhubart

  Here's the latest information on the session schedule and content for Oracle Technology Network Architect Day in Los Angeles on October 25, 2012. Registration is open, but seating is limited. When: Thursday October 25 12, 2012 8:30am – 5:00pm Where: Sofitel Los Angeles 8555 Beverly Boulevard Los Angeles, CA 90048 Agenda Time Session Title Room 8:30 am - 9:00 am Registration and Continental Breakfast 9:00 am - 9:15 am Welcome and Opening Comments | Bob Rhubart Beverly Ballroom 9:15 am - 10:00 am Engineered Systems: Oracle's Vision for the Future | Ralf Dossmann Oracle's Exadata and Exalogic are impressive products in their own right. But working in combination they deliver unparalleled transaction processing performance with up to a 30x increase over existing legacy systems, with the lowest cost of ownership over a 3 or 5 year basis than any other hardware. In this session you'll learn how to leverage Oracle's Engineered Systems within your enterprise to deliver record-breaking performance at the lowest TCO. Beverly Ballroom 10:00 am - 10:30 am Monitoring and Managing Applications in the Cloud | Basheer Khan Oracle offers a broad portfolio of software and hardware products and services to enable public, private and hybrid clouds to power the enterprise. However, enterprise cloud computing presents new management challenges, that need to be addressed to realize the economic benefits of cloud computing. In this session you will learn about the methods and tools you can use to proactively monitor your end-to-end Oracle Applications environment in the cloud, define service-level objectives, gain insight into your end users, and troubleshoot performance problems from a single console. Beverly Ballroom 10:30 am - 10:45 am Break 10:45 am - 11:30 am Breakout Sessions (pick one) Cloud Computing - Making IT Simple | Dr. James Baty The road to Cloud Computing is not without a few bumps. This session will help to smooth out your journey by tackling some of the potential complications. We'll examine whether standardization is a prerequisite for the Cloud. We'll look at why refactoring isn't just for application code. We'll check out deployable entities and their simplification via higher levels of abstraction. And we'll close out the session with a look at engineered systems and modular clouds. Beverly Ballroom Innovations in Grid Computing with Oracle Coherence | Ashok Aletty Learn how Oracle Coherence can increase the availability, scalability and performance of your existing applications with its advanced low-latency data-grid technologies. Also hear some interesting industry-specific use cases that customers had implemented and how Oracle is integrating Coherence into its Enterprise Java stack. Hollywood Room 11:30 am - 12:15 pm Breakout Sessions (pick one) Enterprise Strategy for Cloud Security | Dave Chappelle Security is high on the list of concerns for many organizations as they evaluate their cloud computing options. This session will examine security in the context of the various forms of cloud computing. We'll consider technical and non-technical aspects of security, and discuss several strategies for cloud computing, from both the consumer and producer perspectives. Beverly Ballroom Oracle Enterprise Manager | Perren Walker This session examines new Oracle Enterprise Manager monitoring, administration, and management features for Oracle Exalogic. It focuses on two management themes: cloud management related to virtualization and applications-to-disk management. For private cloud management, it discusses virtualization management features providing an enhanced set of application deployment capabilities enabling IaaS as well as PaaS interactions. Then from an end-to-end perspective, it covers the specific capabilities and—where applicable—best practices for machine, cloud, middleware, and application administration. Hollywood Room 12:15 pm - 1:15 pm Lunch Beverly Ballroom Lounge 1:15 pm - 2:00 pm Panel Discussion - Q&A with session speakers Beverly Ballroom 2:00 pm - 2:45 pm Breakout Sessions (pick one) Oracle Cloud Reference Architecture | Anbu Krishnaswamy Cloud initiatives are beginning to dominate enterprise IT roadmaps. Successful adoption of Cloud and the subsequent governance challenges warrant a Cloud reference architecture that is applied consistently across the enterprise. This presentation will answer the important questions: What exactly is a Cloud, why you need it, what changes it will bring to the enterprise, and what are the key capabilities of a Cloud infrastructure are - using Oracle's Cloud Reference Architecture, which is part of the IT Strategies from Oracle (ITSO) Cloud Enterprise Technology Strategy ETS). Beverly Ballroom 21st Century SOA | Jeff Davies Service Oriented Architecture has evolved from concept to reality in the last decade. The right methodology coupled with mature SOA technologies has helped customers demonstrate success in both innovation and ROI. In this session you will learn how Oracle SOA Suite's orchestration, virtualization, and governance capabilities provide the infrastructure to run mission critical business and system applications. We'll also take a special look at the convergence of SOA & BPM using Oracle's Unified technology stack. Hollywood Room 2:45 pm - 3:00 pm Break 3:00 pm - 4:00 pm Roundtable Discussion Beverly Ballroom 4:00 pm - 4:15 pm Closing Comments & Readouts from Roundtables Beverly Ballroom 4:15 pm - 5:00 pm Networking / Reception Beverly Ballroom Lounge Note: Session schedule and content subject to change.

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• hierachical query to return final row

  - by jeff

  I have a hierarchical query that doesn't return an expected row (employee badge = 444). TABLE: hr_data badge fname supervisor_badge 111 Jeff 222 222 Joe 333 333 John 444 444 Tom 444 SQL: SELECT CONNECT_BY_ISCYCLE As IC, badge, fname, supervisor_badge FROM hr_data START WITH badge = '111' CONNECT BY NOCYCLE badge = PRIOR supervisor_badge What is Returned: IC badge fname supervisor_badge 0 111 Jeff 222 0 222 Joe 333 1 333 John 444 What is Expected: IC badge fname supervisor_badge 0 111 Jeff 222 0 222 Joe 333 **0** 333 John 444 **1** 444 Tom 444 How can I get this query to return the employee Tom and then stop?

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• Tricky SQL query involving consecutive values

  - by Gabriel

  I need to perform a relatively easy to explain but (given my somewhat limited skills) hard to write SQL query. Assume we have a table similar to this one: exam_no | name | surname | result | date ---------+------+---------+--------+------------ 1 | John | Doe | PASS | 2012-01-01 1 | Ryan | Smith | FAIL | 2012-01-02 <-- 1 | Ann | Evans | PASS | 2012-01-03 1 | Mary | Lee | FAIL | 2012-01-04 ... | ... | ... | ... | ... 2 | John | Doe | FAIL | 2012-02-01 <-- 2 | Ryan | Smith | FAIL | 2012-02-02 2 | Ann | Evans | FAIL | 2012-02-03 2 | Mary | Lee | PASS | 2012-02-04 ... | ... | ... | ... | ... 3 | John | Doe | FAIL | 2012-03-01 3 | Ryan | Smith | FAIL | 2012-03-02 3 | Ann | Evans | PASS | 2012-03-03 3 | Mary | Lee | FAIL | 2012-03-04 <-- Note that exam_no and date aren't necessarily related as one might expect from the kind of example I chose. Now, the query that I need to do is as follows: From the latest exam (exam_no = 3) find all the students that have failed (John Doe, Ryan Smith and Mary Lee). For each of these students find the date of the first of the batch of consecutively failing exams. Another way to put it would be: for each of these students find the date of the first failing exam that comes after their last passing exam. (Look at the arrows in the table). The resulting table should be something like this: name | surname | date_since_failing ------+---------+-------------------- John | Doe | 2012-02-01 Ryan | Smith | 2012-01-02 Mary | Lee | 2012-01-04 Ann | Evans | 2012-02-03 How can I perform such a query? Thank you for your time.

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• Query only the first detail record for each master record

  - by Neal S.

  If I have the following master-detail relationship: owner_tbl auto_tbl --------- -------- owner --- owner auto year And I have the following table data: owner_tbl auto_tbl --------- -------- john john, corvette, 1968 john, prius, 2008 james james, f-150, 2004 james, cadillac, 2002 james, accord, 2009 jeff jeff, tesla, 2010 jeff, hyundai, 1996 Now, I want to perform a query that returns the following result: john, corvette, 1968 jeff, hyundai, 1996 james, cadillac, 2002 The query should join the two tables, and sort all the records on the "year" field, but only return the first detail record for each master record. I know how to join the tables and sort on the "year" field, but it's not clear how (or if) I might be able to only retrieve the first joined record for each owner. Three related questions: Can I perform this kind of query using LINQ-to-SQL? Can I perform the query using T-SQL? Would it be best to just create a stored procedure for the query given its likely complexity?

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• Odd SQL Results

  - by Ryan Burnham

  So i have the following query Select id, [First], [Last] , [Business] as contactbusiness, (Case When ([Business] != '' or [Business] is not null) Then [Business] Else 'No Phone Number' END) from contacts The results look like id First Last contactbusiness (No column name) 2 John Smith 3 Sarah Jane 0411 111 222 0411 111 222 6 John Smith 0411 111 111 0411 111 111 8 NULL No Phone Number 11 Ryan B 08 9999 9999 08 9999 9999 14 David F NULL No Phone Number I'd expect record 2 to also show No Phone Number If i change the "[Business] is not null" to [Business] != null then i get the correct results id First Last contactbusiness (No column name) 2 John Smith No Phone Number 3 Sarah Jane 0411 111 222 0411 111 222 6 John Smith 0411 111 111 0411 111 111 8 NULL No Phone Number 11 Ryan B 08 9999 9999 08 9999 9999 14 David F NULL No Phone Number Normally you need to use is not null rather than != null. whats going on here?

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• How to get only one row for each distinct value in the column ?

  - by Chavdar

  Hi Everybody, I have a question about Access.If for example I have a table with the following data : NAME | ADDRESS John Taylor | 33 Dundas Ave. John Taylor | 55 Shane Ave. John Taylor | 786 Edward St. Ted Charles | 785 Bloor St. Ted Charles | 90 New York Ave. I want to get one record for each person no matter of the address.For example : NAME | ADDRESS John Taylor | 33 Dundas Ave. Ted Charles | 90 New York Ave. Can this be done with queries only ? I tried using DISTINCT, but when I am selecting both columns, the combination is allways unique so I get all the rows. Thank you !

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• c# ListView unable to check a checkbox! Strange problem.

  - by Kurt

  This is a strange problem, I've not added much code as I don't know were to start. I have a listview control in virtual mode, if I filter the listview to show me all people called John, I then see 3 users called John, I then cancel the filter setting all values to null and return all data to the listview, I now have several hundred items in the list but I can only see 30 on screen unless I scroll down the listview. I then use the code below to check a checkbox in each row, all get checked apart from the 3 Johns but if I can see 1 of the 3 Johns in listview without scrolling and then run the code below the visible John is checked. for (int i = 0; i < this._items.Count; i++) { this._items[i].Checked = true; } I have checked the status of the checkbox just before it is checked in the above code and if John is visible then the checkbox believes it is unchecked (false), if it is not visible it belives it is checked (true). So having one visible John on screen the checkbox looks unchecked and running a test proves it is unchecked, for the two Johns I can't see they believe they are checked but if I scroll down so I can see them they aren't. Any ideas? Thanks

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• Perl script matching a certain patern

  - by kivien

  Assuming the file.txt is as follows:- John Depp is a great guy. He is very inteligent. He can do anything. Come and meet John Depp. The perl code is as follows:- open ( FILE, "file.txt" ) || die "can't open file!"; @lines = <FILE>; close (FILE); $string = "John Depp"; foreach $line (@lines) { if ($line =~ $string) { print "$line"; } } The output is going to be first and fourth line. I want to make it working for the file having random line breaks rather than one English sentence per line. I mean it should also work for the following:- John Depp is a great guy. He is very inteligent. He can do anything. Come and meet John Depp. The output should be first and fourth sentence. Any ideas please?

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• ruby eval('\1') of gsub possible?

  - by Horace Ho

  I try to replace a sub-str by the content of a valiable where its name matches the sub-str by: >> str = "Hello **name**" => "Hello **name**" >> name = "John" => "John" str.gsub(/\*\*(.*)\*\*/, eval('\1')) # => error! the last line in the code above is a syntax error. and: >> str.gsub(/\*\*(.*)\*\*/, '\1') => "Hello name" >> str.gsub(/\*\*(.*)\*\*/, eval("name")) => "Hello John" what I want is the result of: str.gsub(/\*\*(.*)\*\*/, eval("name")) # => "Hello John" any help will be appreciated. thx!

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• Confused with ECMAScript Language Specification Function Calls section

  - by Ding

  Hi, I am reading ECMAScript Language Specification Function Calls section Can someone rephrase or detailed explains the following sentense for me? The production CallExpression : MemberExpression Arguments is evaluated as follows: Evaluate MemberExpression. let's take this code as an example. var john = { name: 'John', greet: function(person) { alert("Hi " + person + ", my name is " + this.name); } }; john.greet("Mark"); Take above code as an example, what does production CallExpression mean? what is MemberExpression in this case, john.greet? Thanks!

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• How can I print lines that match a pattern in Perl?

  - by kivien

  Assuming the file.txt having just one sentence per line as follows:- John Depp is a great guy. He is very inteligent. He can do anything. Come and meet John Depp. The perl code is as follows:- open ( FILE, "file.txt" ) || die "can't open file!"; @lines = <FILE>; close (FILE); $string = "John Depp"; foreach $line (@lines) { if ($line =~ $string) { print "$line"; } } The output is going to be first and fourth line. I want to make it working for the file having random line breaks rather than one English sentence per line. I mean it should also work for the following:- John Depp is a great guy. He is very inteligent. He can do anything. Come and meet John Depp. The output should be first and fourth sentence. Any ideas please?

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• Class Problem (c++ and prolog)

  - by Joshua Green

  I am using the C++ interface to Prolog (the classes and methods of SWI-cpp.h). For working out a simple backtracking that john likes mary and emma and sara: likes(john, mary). likes(john, emma). likes(john, ashley). I can just do: { PlFrame fr; PlTermv av(2); av[0] = PlCompound("john"); PlQuery q("likes", av); while (q.next_solution()) { cout << (char*)av[1] << endl; } } This works in a separate code, so the syntax is correct. But I am also trying to get this simple backtracking to work within a class: class UserTaskProlog { public: UserTaskProlog(ArRobot* r); ~UserTaskProlog(); protected: int cycles; char* argv[1]; ArRobot* robot; void logTask(); }; This class works fine, with my cycles variable incrementing every robot cycle. However, when I run my main code, I get an Unhandled Exception error message: UserTaskProlog::UserTaskProlog(ArRobot* r) : robotTaskFunc(this, &UserTaskProlog::logTask) { cycles = 0; PlEngine e(argv[0]); PlCall("consult('myFile.pl')"); robot->addSensorInterpTask("UserTaskProlog", 50, &robotTaskFunc); } UserTaskProlog::~UserTaskProlog() { robot->remSensorInterpTask(&robotTaskFunc); // Do I need a destructor here for pl? } void UserTaskProlog::logTask() { cycles++; cout << cycles; { PlFrame fr; PlTermv av(2); av[0] = PlCompound("john"); PlQuery q("likes", av); while (q.next_solution()) { cout << (char*)av[1] << endl; } } } I have my opening and closing brackets for PlFrame. I have my frame, my query, etc... The exact same code that backtracks and prints out mary and emma and sara. What am I missing here that I get an error message? Here is what I think the code should do: I expect mary and emma and sara to be printed out once, every time cycles increments. However, it opens SWI-cpp.h file automatically and points to class PlFrame. What is it trying to tell me? I don't see anything wrong with my PlFrame class declaration. Thanks,

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• Split a line from a para in java

  - by John

  Hi... I am having problem splitting a para into line.... i need to first read a file then split in into lines if i get a . or ! or ? I also need to remove any extra white space... This is wad i've written so far.... try { Scanner line = new Scanner(mFile); mLine = line.nextLine(); String Matrix[]=mLine.split("\\."); for (int i = 0; i < Matrix.length; ++i) { System.out.println(Matrix[i]); } Input: Hi. My name is John. Who are you ? Output: Hi My name is John Who are you

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• Excel code question

  - by karatekid

  I have 2 different excel files(all people and special people) that i want to kick special people from all people. Cant find a way.. if you don't understand check my example: all people special people ---------- -------------- 1-john 1-john 2-jim 2-marry 3-mariah 4-russel 5-marry I want: all people special people ---------- -------------- 1-jim 1-john 2-mariah 2-marry 3-russel

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• Is it possible to use ContainsTable to get results for more than one column?

  - by LockeCJ

  Consider the following table: People FirstName nvarchar(50) LastName nvarchar(50) Let's assume for the moment that this table has a full-text index on it for both columns. Let's suppose that I wanted to find all of the people named "John Smith" in this table. The following query seems like a perfectly rational way to accomplish this: SELECT * from People p INNER JOIN CONTAINSTABLE(People,*,'"John*" AND "Smith*"') Unfortunately, this will return no results, assuming that there is no record in the People table that contains both "John" and "Smith" in either the FirstName or LastName columns. It will not match a record with "John" in the FirstName column, and "Smith" in the LastName column, or vice-versa. My question is this: How does one accomplish what I'm trying to do above? Please consider that the example above is simplified. The real table I'm working with has ten columns and the input I'm receiving is a single string which is split up based on standard word breakers (space, dash, etc.)

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• Graph databases and Php

  - by stagas

  I want to use a graph database using php. Can you point out some resources on where to get started? Is there any example code / tutorial out there? Or are there any other methods of storing data that relate to each other in totally random/abstract situations? Very abstract example of the relations needed: John relates to Mary, both relate to School, John is Tall, Mary is Short, John has Blue Eyes, Mary has Green Eyes, query I want is which people are related to 'Short people that have Green Eyes and go to School' - answer John It is possible in MySQL but it would require a fixed set of attributes/columns for each item and a complex non-flexible query, instead I need every attribute to be an item by itself and instead of 'belonging' to something, to be 'related' to something.

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• Why should I prepend my custom attributes with "data-"?

  - by Horace Loeb

  So any custom data attribute that I use should start with "data-": <li class="user" data-name="John Resig" data-city="Boston" data-lang="js" data-food="Bacon"> <b>John says:</b> <span>Hello, how are you?</span> </li> Will anything bad happen if I just ignore this? I.e.: <li class="user" name="John Resig" city="Boston" lang="js" food="Bacon"> <b>John says:</b> <span>Hello, how are you?</span> </li> I guess one bad thing is that my custom attributes could conflict with HTML attributes with special meanings (e.g., name), but aside from this, is there a problem with just writing "example_text" instead of "data-example_text"? (It won't validate, but who cares?)

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• scala integer weirdness

  - by williamstw

  Suppose you inadvertently use Integer instead of Int, as in this code: import scala.collection.mutable.Map val contributors = Map[String,Integer]() val count = contributors.getOrElseUpdate("john",0) contributors.put("john",count+1) println(contributors) Compiler output: (fragment of test.scala):7: error: type mismatch; found : Int(1) required: String contributors.put("john",count+1) ^ Why "required: String"?

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• Filter entities that match all pairs

  - by Jon

  I have an entity (let's say Person) with a set of arbitrary attributes with a known subset of values. I need to search for all of these entities that match all my filter conditions. For example, my table structures look like this: Person: id | name 1 | John Doe 2 | Jane Roe 3 | John Smith Attribute: id | attr_name 1 | Sex 2 | Eye Color ValidValue: id | attr_id | value_name 1 | 1 | Male 2 | 1 | Female 3 | 2 | Blue 4 | 2 | Green 5 | 2 | Brown PersonAttributes id | person_id | attr_id | value_id 1 | 1 | 1 | 1 2 | 1 | 2 | 3 3 | 2 | 1 | 2 4 | 2 | 2 | 4 5 | 3 | 1 | 1 6 | 3 | 2 | 4 In JPA, I have entities built for all of these tables. What I'd like to do is perform a search for all entities matching a given set of attribute-value pairs. For instance, I'd like to be able to find all males (John Doe and John Smith), all people with green eyes (Jane Roe or John Smith), or all females with green eyes (Jane Roe). I see that I can already take advantage of the fact that I only really need to match on value_id, since that's already unique and tied to the attr_id. But where can I go from there?

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