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• Multiply with negative integer just by shifting.

  - by stex

  Hi, I'm trying to find a way to multiply an integer value with negative value just with bit shifting. Usually I do this by shifting with the power of 2 which is closest to my factor and just adding / subtracting the rest, e.g. x * 7 = ((x << 3) - x) Let's say I'd want to calculate x * -112. The only way I can imagine is -((x << 7) - (x << 4), so to calculate x * 112 and negate it afterwards. Is there a "prettier" way to do this?

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• error: switch quantity not an integer

  - by nikeunltd

  I have researched my issue all over StackOverflow and multi-google links, and I am still confused. I figured the best thing for me is ask... Im creating a simple command line calculator. Here is my code so far: const std::string Calculator::SIN("sin"); const std::string Calculator::COS("cos"); const std::string Calculator::TAN("tan"); const std::string Calculator::LOG( "log" ); const std::string Calculator::LOG10( "log10" ); void Calculator::set_command( std::string cmd ) { for(unsigned i = 0; i < cmd.length(); i++) { cmd[i] = tolower(cmd[i]); } command = cmd; } bool Calculator::is_legal_command() const { switch(command) { case TAN: case SIN: case COS: case LOG: case LOG10: return true; break; default: return false; break; } } the error i get is: Calculator.cpp: In member function 'bool Calculator::is_trig_command() const': Calculator.cpp: error: switch quantity not an integer Calculator.cpp: error: 'Calculator::TAN' cannot appear in a constant-expression Calculator.cpp: error: 'Calculator::SIN' cannot appear in a constant-expression Calculator.cpp: error: 'Calculator::COS' cannot appear in a constant-expression The mighty internet, it says strings are allowed to be used in switch statements. Thanks everyone, I appreciate your help.

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• Unsupported operand types when value is integer

  - by Adam Tester

  I'm getting this error when trying to add 2 to an integer. I am using the Codeigniter framework. Fatal error: Unsupported operand types in D:\wamp\www\application\libraries\Gen_images.php on line 180 Here is where its called: // Now process the image var_dump($this->upload->data('image_width')); $this->gen_login->resize($file_name, $this->upload->data('image_width'), $this->upload->data('image_height')); I get the error on line 180 which is: $config['width'] = $width + 2; So I thought $width must be an array or string so I wouldn't be able to add to it, but the var dump shows this: array 'file_name' => string 'genyx_1341414096.jpg' (length=20) 'file_type' => string 'image/jpeg' (length=10) 'file_path' => string 'D:/wamp/www/beer/uploads/' (length=25) 'full_path' => string 'D:/wamp/www/beer/uploads/genyx_1341414096.jpg' (length=45) 'raw_name' => string 'genyx_1341414096' (length=16) 'orig_name' => string 'genyx_1341414096.jpg' (length=20) 'client_name' => string '294207_177080222375077_100002193022560_361510_991268937_s.jpg' (length=61) 'file_ext' => string '.jpg' (length=4) 'file_size' => float 55.85 'is_image' => boolean true 'image_width' => int 720 'image_height' => int 479 'image_type' => string 'jpeg' (length=4) 'image_size_str' => string 'width="720" height="479"' (length=24) Can anyone help me?

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• ActionView::TemplateError (integer 23656121084180 too big to convert to `unsigned int')

  - by jaycode

  Hi, this is the weirdest error I've ever got on Rails. Any idea what this may be is? NOTE: the error DOES NOT come from @order.get_invoice_number, I've tried to separate the code into multiple lines and it was clear the problem is within {:host... } ActionView::TemplateError (integer 23656121084180 too big to convert to `unsigned int') on line #56 of app/views/order_mailer/order_detail.text.html.erb: 53: <b>Order #:</b> 54: </td> 55: <td width="98%"> 56: <%= link_to "#{@order.get_invoice_number}", {:host => Thread.current[:host], :controller => 'store/account', :action => 'view_order', id => "#{@order.id}"}, {:target => '_blank'} %> 57: </td> 58: </tr> 59: <tr> app/views/order_mailer/order_detail.text.html.erb:56 app/controllers/store/ test_controller.rb:11:in `order_email'

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• Map large integer to a phrase

  - by Alexander Gladysh

  I have a large and "unique" integer (actually a SHA1 hash). I want (for no other reason than to have fun) to find an algorithm to convert that SHA1 hash to a (pseudo-)English phrase. The conversion should be reversible (i.e., knowing the algorithm, one must be able to convert the phrase back to SHA1 hash.) The possible usage of the generated phrase: the human readable version of Git commit ID, like a motto for a given program version (which is built from that commit). (As I said, this is "for fun". I don't claim that this is very practical — or be much more readable than the SHA1 itself.) A better algorithm would produce shorter, more natural-looking, more unique phrases. The phrase need not make sense. I would even settle for a whole paragraph of nonsense. (Though quality — englishness — of a paragraph should probably be better than for a mere phrase.) A variation: it is OK if I will be able to work only with a part of hash. Say, first six digits is OK. Possible approach: In the past I've attempted to build a probability table (of words), and generate phrases as Markov chains, seeding the generator (picking branches from probability tree), according to the bits I read from the SHA. This was not very successful, the resulting phrases were too long and ugly. I'm not sure if this was a bug, or the general flaw in the algorithm, since I had to abandon it early enough. Now I'm thinking about attempting to solve the problem once again. Any advice on how to approach this? Do you think Markov chain approach can work here? Something else?

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• warning: assignment makes pointer from integer without a cast

  - by FILIaS

  Im new in programming c with arrays and files. Im just trying to run the following code but i get warnings like that: warning: assignment makes pointer from integer without a cast Any help? It might be silly... but I cant find what's wrong. FILE *fp; FILE *cw; char filename_game[40],filename_words[40]; int main() { while(1) { /* Input filenames. */ printf("\n Enter the name of the file with the cryptwords array: \n"); gets(filename_game); printf("\n Give the name of the file with crypted words:\n"); gets(filename_words); /* Try to open the file with the game */ if (fp=fopen("crypt.txt","r")!=NULL) { printf("\n Successful opening %s \n",filename_game); fclose(fp); puts("\n Enter x to exit,any other to continue! \n "); if ( (getc(stdin))=='x') break; else continue; } else { fprintf(stderr,"ERROR!%s \n",filename_game); puts("\n Enter x to exit,any other to continue! \n"); if (getc(stdin)=='x') break; else continue; } /* Try to open the file with the names. */ if (cw=fopen("words.txt","r")!=NULL) { printf("\n Successful opening %s \n",filename_words); fclose(cw); puts("\n Enter x to exit,any other to continue \n "); if ( (getc(stdin))=='x') break; else continue; } else { fprintf(stderr,"ERROR!%s \n",filename_words); puts("\n Enter x to exit,any other to continue! \n"); if (getc(stdin)=='x') break; else continue; } } return 0; }

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• how to determine if a character vector is a valid numeric or integer vector

  - by Andrew Barr

  I am trying to turn a nested list structure into a dataframe. The list looks similar to the following (it is serialized data from parsed JSON read in using the httr package). myList <- list(object1 = list(w=1, x=list(y=0.1, z="cat")), object2 = list(w=2, x=list(y=0.2, z="dog"))) unlist(myList) does a great job of recursively flattening the list, and I can then use lapply to flatten all the objects nicely. flatList <- lapply(myList, FUN= function(object) {return(as.data.frame(rbind(unlist(object))))}) And finally, I can button it up using plyr::rbind.fill myDF <- do.call(plyr::rbind.fill, flatList) str(myDF) #'data.frame': 2 obs. of 3 variables: #$ w : Factor w/ 2 levels "1","2": 1 2 #$ x.y: Factor w/ 2 levels "0.1","0.2": 1 2 #$ x.z: Factor w/ 2 levels "cat","dog": 1 2 The problem is that w and x.y are now being interpreted as character vectors, which by default get parsed as factors in the dataframe. I believe that unlist() is the culprit, but I can't figure out another way to recursively flatten the list structure. A workaround would be to post-process the dataframe, and assign data types then. What is the best way to determine if a vector is a valid numeric or integer vector?

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• Problem in inferring instances that have integer cardinality constraint

  - by Mikae Combarado

  Hello, I have created an RDF/OWL file using Protege 4.1 alpha. I also created a defined class in Protege called CheapPhone. This class has a restriction which is shown below : (hasPrice some integer[< 350]) Whenever, a price of a phone is below 350, it is inferred as CheapPhone. There is no problem for inferring this in Protege 4.1 alpha. However, I cannot infer this using Jena. I also created a defined class called SmartPhone. This class also has a restriction which is shown below : (has3G value true) and (hasInternet value true) Whenever, a phone has 3G and Internet, it is inferred as SmartPhone. In this situation, there is no problem inferring this in both Protege and Jena. I have started to think that there is a problem in default inference engine of Jena. The code that I use in Java is below : Reasoner reasoner = ReasonerRegistry.getOWLReasoner(); reasoner = reasoner.bindSchema(ontModel); OntModelSpec ontModelSpec = OntModelSpec.OWL_MEM_MINI_RULE_INF; ontModelSpec.setReasoner(reasoner); // Create ontology model with reasoner support // ontModel was created and read before, so I don't share the code in order // not to create garbage here OntModel model = ModelFactory.createOntologyModel(ontModelSpec, ontModel); OntClass sPhone = model.getOntClass(ns + "SmartPhone"); ExtendedIterator s = sPhone.listInstances(); while(s.hasNext()) { OntResource mp = (OntResource)s.next(); System.out.println(mp.getURI()); } This code works perfectly and returns me the instances, but when I change the code below and make it appropriate for CheapPhone, it doesn't return anything. OntClass sPhone = model.getOntClass(ns + "CheapPhone"); Am I doing something wrong ?

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• Returning an integer from a select box - JavaScript

  - by Ross

  Very simply, I want to be able to access the year from the select box as an integer. In my test, my alertbox is telling me the value is undefined. <form name="form1" method="post" action=""> <label>birth year <select name="birth year" id="dueYear"> <OPTION VALUE='' SELECTED>--Year--</OPTION> <OPTION VALUE='2011'>2011</OPTION> <OPTION VALUE='2010'>2010</OPTION> <OPTION VALUE='2009'>2009</OPTION></SELECT> </select> </label> </form> <script type="text/javascript"> var dueDateYear = parseInt(document.getElementById("dueYear")); </script> <button onclick="alert(dueDateYear)">Click Me!</button> All I want it to do, is tell me the year I have selected -- any help would be appreciated, I am a newbie :(

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• Enhancing an 'ORDER BY' clause to judge condition by more than 1 integer

  - by Yvonne

  Hi folks, I have some PHP code which allows me to sort a column into ascending and descending order (upon click of a table row title), which is good. It works perfectly for my D.O.B colum (with date/time field type), but not for a quantity column. For example, I have quantites of 10, 50, 100, 30 and another 100. The order seems to be only appreciating the 1st integer, so my sorting of the column ends up in this order: 10, 100, 100, 30, 50... and 50, 30, 100, 100, 10. This is obviously incorrect as 100 is bigger than 50, therefore both 100 values should appear at the end surely? It seems to me that 100 is only being taken into account as having the '1' value, then it appears before 10 because the system recognises it has another 0. Is this normal to happen? Is there any way I can solve this problem? Thanks for any help. P.S. I can show code if necessary, but would like to know if this is a common issue by default.

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• Prob comparing pointers and integer in C

  - by Dimitri

  Hi I have a problem with this code. When i am using this function I have no warnings. : void handler(int sig){ switch(sig) { case SIGINT : { click++; fprintf(stdout,"SIGINT recu\n"); if( click == N){ exit(0); } } case SIGALRM : fprintf(stdout,"SIGALRM received\n"); exit(0); case SIGTERM: fprintf(stdout,"SIGTERM received\n"); exit(0); } } But when i rewrite the function with this new version, I have a " comparison between pointer and integer" warning on the if statement: void handler( int sig){ printf("Signal recu\n"); if( signal == SIGINT){ click++; fprintf(stdout,"SIGINT received; Click = %d\n",click); if(click == N){ fprintf(stdout,"Exiting with SIGINT\n"); exit(0); } } else if(signal == SIGALRM){ fprintf(stdout,"SIGALRM received\n"); exit(0); } else if(signal == SIGTERM){ fprintf(stdout,"SIGTERM received\n"); exit(0); } Can someone tell me where is the prob?

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• C++ : integer constant is too large for its type

  - by user38586

  I need to bruteforce a year for an exercise. The compiler keep throwing this error: bruteforceJS12.cpp:8:28: warning: integer constant is too large for its type [enabled by default] My code is: #include <iostream> using namespace std; int main(){ unsigned long long year(0); unsigned long long result(318338237039211050000); unsigned long long pass(1337); while (pass != result) { for (unsigned long long i = 1; i<= year; i++) { pass += year * i * year; } cout << "pass not cracked with year = " << year << endl; ++year; } cout << "pass cracked with year = " << year << endl; } Note that I already tried with unsigned long long result(318338237039211050000ULL); I'm using gcc version 4.8.1 EDIT: Here is the corrected version using InfInt library http://code.google.com/p/infint/ #include <iostream> #include "InfInt.h" using namespace std; int main(){ InfInt year = "113"; InfInt result = "318338237039211050000"; InfInt pass= "1337"; while (pass != result) { for (InfInt i = 1; i<= year; i++) { pass += year * i * year; } cout << "year = " << year << " pass = " << pass << endl; ++year; } cout << "pass cracked with year = " << year << endl; }

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• Ruby & ActiveRecord: referring to integer fields by (uniquely mapped) strings

  - by JP

  While its not my application a simple way to explain my problem is to assume I'm running a URL shortener. Rather than attempt to try and figure out what the next string I should use as the unique section of the URL, I just index all my URLs by integer and map the numbers to strings behind the scenes, essentially just changing the base of the number to, let's say, 62: a-z + A-Z + 0-9. In ActiveRecord I can easily alter the reader for the url_id field so that it returns my base 62 string instead of the number being stored in the database: class Short < ActiveRecord::Base def url_id i = read_attribute(:convo) return '0' if i == 0 s = '' while i > 0 s << CHARS[i.modulo(62)] i /= 62 end s end end but is there a way to tell ActiveRecord to accept Short.find(:first,:conditions=>{:url_id=>'Ab7'}), ie. putting the 'decoding' logic into my Short ActiveRecord class? I guess I could define my own def self.find_by_unique_string(string), but that feels like cheating somehow! Thanks!

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• Public class: Makes pointer from integer without cast

  - by meridimus

  I have written a class to help save and load data for the sake of persistence for my iPhone application but I have a problem with some NSUIntegers that I'm passing across. Basically, I have the code to use pointers, but eventually it has to start out being an actual value right? So I get this error warning: passing argument 1 of 'getSaveWithCampaign:andLevel:' makes pointer from integer without a cast My code is laid out like so. (Persistence is the name of the class) NSDictionary *saveData = [Persistence getSaveWithCampaign:currentCampaign andLevel:[indexPath row]]; Here's Persistence.m #import "Persistence.h" @implementation Persistence + (NSString *)dataFilePath { NSArray *paths = NSSearchPathForDirectoriesInDomains(NSDocumentDirectory, NSUserDomainMask, YES); NSString *documentsDirectory = [paths objectAtIndex:0]; return [documentsDirectory stringByAppendingPathComponent:kSaveFilename]; } + (NSDictionary *)getSaveWithCampaign:(NSUInteger *)campaign andLevel:(NSUInteger *)level { NSString *filePath = [self dataFilePath]; if([[NSFileManager defaultManager] fileExistsAtPath:filePath]) { NSDictionary *saveData = [[NSDictionary alloc] initWithContentsOfFile:filePath]; NSString *campaignAndLevelKey = [self makeCampaign:campaign andLevelKey:level]; NSDictionary *campaignAndLevelData = [saveData objectForKey:campaignAndLevelKey]; [saveData release]; return campaignAndLevelData; } else { return nil; } } + (NSString *)makeCampaign:(NSUInteger *)campaign andLevelKey:(NSUInteger *)level { return [[NSString stringWithFormat:@"%d - ", campaign+1] stringByAppendingString:[NSString stringWithFormat:@"%d", level+1]]; } @end

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• Overwriting a range of bits in an integer in a generic way

  - by porgarmingduod

  Given two integers X and Y, I want to overwrite bits at position P to P+N. Example: int x = 0xAAAA; // 0b1010101010101010 int y = 0x0C30; // 0b0000110000110000 int result = 0xAC3A; // 0b1010110000111010 Does this procedure have a name? If I have masks, the operation is easy enough: int mask_x = 0xF00F; // 0b1111000000001111 int mask_y = 0x0FF0; // 0b0000111111110000 int result = (x & mask_x) | (y & mask_y); What I can't quite figure out is how to write it in a generic way, such as in the following generic C++ function: template<typename IntType> IntType OverwriteBits(IntType dst, IntType src, int pos, int len) { // If: // dst = 0xAAAA; // 0b1010101010101010 // src = 0x0C30; // 0b0000110000110000 // pos = 4 ^ // len = 8 ^------- // Then: // result = 0xAC3A; // 0b1010110000111010 } The problem is that I cannot figure out how to make the masks properly when all the variables, including the width of the integer, is variable. Does anyone know how to write the above function properly?

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• Storing Number in an integer from sql Database

  - by ar31an

  i am using database with table RESUME and column PageIndex in it which type is number in database but when i want to store this PageIndex value to an integer i get exception error Specified cast is not valid. here is the code string sql; string conString = "Provider=Microsoft.ACE.OLEDB.12.0; Data Source=D:\\Deliverable4.accdb"; protected OleDbConnection rMSConnection; protected OleDbDataAdapter rMSDataAdapter; protected DataSet dataSet; protected DataTable dataTable; protected DataRow dataRow; on Button Click sql = "select PageIndex from RESUME"; rMSConnection = new OleDbConnection(conString); rMSDataAdapter = new OleDbDataAdapter(sql, rMSConnection); dataSet = new DataSet("pInDex"); rMSDataAdapter.Fill(dataSet, "RESUME"); dataTable = dataSet.Tables["RESUME"]; int pIndex = (int)dataTable.Rows[0][0]; rMSConnection.Close(); if (pIndex == 0) { Response.Redirect("Create Resume-1.aspx"); } else if (pIndex == 1) { Response.Redirect("Create Resume-2.aspx"); } else if (pIndex == 2) { Response.Redirect("Create Resume-3.aspx"); } } i am getting error in this line int pIndex = (int)dataTable.Rows[0][0];

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• how can i read the integer value from xml document in objective-c

  - by uttam

  this is my xml document, i want to use the value of id and mlsid in in my viewcontroller. how can i read it. <Table> <ID>1</ID> <MLSID>70980420</MLSID> <STREET_NO>776</STREET_NO> <STREET_NAME>Boylston</STREET_NAME> <AreaName>Back Bay</AreaName <Table> i have created one object file book which store the all value of xml data and then i put that objects in the array . now i am able to retrive the string value but not getting the integer value. this is my object class. @interface Book : NSObject { NSInteger ID; NSInteger MLSID //Same name as the Entity Name. } how to trieve the value of MLSID in the viewcontroller. or how to print it.

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• php validate integer [updated]

  - by George Garchagudashvili

  Read B A: I'll give quick example: $a = "\n \t 34 3"; // string(9) $aint = intval($a); // int(34) var_dump($a == $aint); result: bool(true) call me noob but can you tell me why/how does these variables do pass equalization test? What I want to achieve is to check if '1989' equals 1989 would be true, but not any other case. ex: '1989 ' should not pass the test. Also I don't want to use regex. B: I need to validate if variable is integer, I've tried all the available built-in functions or helpful tips, but the only best solution would be regex which I don't want to use this time. also filter_var is not best because it also filters data, but I want to only validate it. 123 -123 '123' '-123' these inputs to be only true, false otherwise I've tried many different options: ctype_digit("-123"); // false - doesn't work is_int('123'); // false filter_var(' 123 ', FILTER_VALIDATE_INT) !== false; // true - doesn't work

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• A specific string format with a number and character together represeting a certain item

  - by sil3nt

  Hello there, I have a string which looks like this "a 3e,6s,1d,3g,22r,7c 3g,5r,9c 19.3", how do I go through it and extract the integers and assign them to its corresponding letter variable?. (i have integer variables d,r,e,g,s and c). The first letter in the string represents a function, "3e,6s,1d,3g,22r,7c" and "3g,5r,9c" are two separate containers . And the last decimal value represents a number which needs to be broken down into those variable numbers. my problem is extracting those integers with the letters after it and assigning them into there corresponding letter. and any number with a negative sign or a space in between the number and the letter is invalid. How on earth do i do this?

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• PostgreSQL like + Hibernate problem

  - by Marat_Galiev

  Hi all. I want to do search in PostgreSQL for INTEGER based columns. if (!sSearch.isEmpty()) { sSearch = sSearch.replaceAll("[^a-zA-Z0-9]", "_").toLowerCase(); String[] search = sSearch.split(" "); sWhere = " "; for (NewsColumns column : NewsColumns.values()) { for (String s : search) { sWhere += "lower(" + column + "::TEXT) LIKE '%" + s + "%' OR "; } } sWhere = sWhere.substring(0,sWhere.length()-3); } Ok, I want to convert INT value to String before search, with '::TEXT' expression. But after executing I'm getting: org.hibernate.QueryException: Not all named parameters have been set: [:TEXT] [select * from news WHERE lower(ID::TEXT) LIKE '%5%' Exception. Looks like hibernate parse my convert exp as parameter. Any help is appreciated. Thanks.

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• Integers in JavaScript

  - by muntoo

  I'm a beginner to Javascript so forgive me if I sound dumb because I learned some Javascript from W3Fools (which are really difficult tutorials - they don't explain anything I want to know, but everything I probably can guess from my experience with C++). I may be switching over to MDN, but if you can recommend any other tutorials, that be great. Anyways, so here's my question: I just read a few lines of this, and apparently: Numbers in JavaScript are "double-precision 64-bit format IEEE 754 values", according to the spec. This has some interesting consequences. There's no such thing as an integer in JavaScript, so you have to be a little careful with your arithmetic if you're used to math in C or Java. I've already seen that there are few of the data types (for variables) I'm used to from C++. But I didn't expect all numbers to automatically be floats. Isn't there any way to use integers, not float? Will a future version of JavaScript support ints?

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• C: Recursive function for inverting an int

  - by Jorge

  I had this problem on an exam yesterday. I couldn't resolve it so you can imagine the result... Make a recursive function: int invertint( int num) that will receive an integer and return it but inverted, example: 321 would return as 123 I wrote this: int invertint( int num ) { int rest = num % 10; int div = num / 10; if( div == 0 ) { return( rest ); } return( rest * 10 + invert( div ) ) } Worked for 2 digits numbers but not for 3 digits or more. Since 321 would return 1 * 10 + 23 in the last stage. Thanks a lot! PS: Is there a way to understand these kind of recursion problems in a faster manner or it's up to imagination of one self?

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• Write a recursive function in C that converts a number into a string

  - by user3501779

  I'm studying software engineering, and came across this exercise: it asks to write a recursive function in C language that receives a positive integer and an empty string, and "translates" the number into a string. Meaning that after calling the function, the string we sent would contain the number but as a string of its digits. I wrote this function, but when I tried printing the string, it did print the number I sent, but in reverse. This is the function: void strnum(int n, char *str) { if(n) { strnum(n/10, str+1); *str = n%10 + '0'; } } For example, I sent the number 123 on function call, and the output was 321 instead of 123. I also tried exchanging the two lines within the if statement, and it still does the same. I can't figure out what I did wrong. Can someone help please? NOTE: Use of while and for loop statements is not allowed for the exercise.

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• C programming, why does this large array declaration produce a segmentation fault?

  - by noneme

  This code produces a segmentation fault during the array declaration. I'm confused as to why this happens. I intentionally selected 2000000000 as a value because it is below 2^31 and can fit into an integer variable. int main() { int nums_size = 2000000000; int nums[nums_size]; int i; for(i = 0; i < nums_size; i++) { nums[i] = i; } return 0; }

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• Why is it inserting 0's instead of blank spaces into my DB using php?

  - by zeckdude

  I have an insert: $sql = 'INSERT into orders SET fax_int_prefix = "'.$_SESSION['fax_int_prefix'].'", fax_prefix = "'.$_SESSION['fax_prefix'].'", fax_first = "'.$_SESSION['fax_first'].'", fax_last = "'.$_SESSION['fax_last']; The value of all of these fields is that they are blank right before the insert. Here is an example of one of them I echo'd out just before the insert: $_SESSION[fax_prefix] = For some reason it inserts the integer 0, instead of a blank value or null, as it should. Why is it inserting 0's instead of blank spaces into my DB?

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