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  • Xcode / Interface Builder - better workflow from designer to coder?

    - by tbarbe
    Were dealing with some pretty custom UI elements while building our OSX / Cocoa and iPhone / IPad apps. I was wondering if anyone has good recommendations or tricks for getting a better workflow between UI designers and coders while using Xcode / Interface Builder? It seems that many things require programmatic settings with UI editing in Cocoa... if you stray from the pre-built UI elements then you can't really easily drag-drop build a UI... instead we end up handing off a design doc ( photoshop/illustrator ) and then the poor developer has to deal with recreating this masterpiece in code or by using interface builder - usually a combination of both. This work flow is leading us to not so great results and we have to re-iterate around the UI elements to get them to work better. We love CSS and / or Flash designer to developer workflow where the UI could look exactly as it should and the hand off to developer was more seamless. Is there anyone out there who has some tricks - or insights into getting better workflow when using tools like Xcode / Interface Builder and doing Cocoa apps?

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  • Understanding #DAX Query Plans for #powerpivot and #tabular

    - by Marco Russo (SQLBI)
    Alberto Ferrari wrote a very interesting white paper about DAX query plans. We published it on a page where we'll gather articles and tools about DAX query plans: http://www.sqlbi.com/topics/query-plans/I reviewed the paper and this is the result of many months of study - we know that we just scratched the surface of this topic, also because we still don't have enough information about internal behavior of many of the operators contained in a query plan. However, by reading the paper you will start reading a query plan and you will understand how it works the optimization found by Chris Webb one month ago to the events-in-progress scenario. The white paper also contains a more optimized query (10 time faster), even if the performance depends on data distribution and the best choice really depends on the data you have. Now you should be curious enough to read the paper until the end, because the more optimized query is the last example in the paper!

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  • How do I backup my C++ Builder component installation?

    - by Gary Benade
    Hi I finally have my c++ Builder 2010 installation the way I want it, with all my components upgraded and installed. (touch wood) I have been working with c++builder since version 1 and I know from countless previous traumatic experiences that this state of affairs could change in an instant. I would like to backup the installation and component set. Is there a way to do this? A tool perhaps? A menu command that I have maybe missed all these years? I don't want to have to reinstall all the components from the bpl source again. I make nightly backup images of my entire drive, I would like to do this for c++builder only if possible. If it's a matter of simply copying files, which files would I need to copy? Are there entries in the registry that would need to be restored? Thanks in advance for any thoughts and suggestions

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  • Why is doing a top(1) on an indexed column in SQL Server slow?

    - by reinier
    I'm puzzled by the following. I have a DB with around 10 million rows, and (among other indices) on 1 column (campaignid_int) is an index. Now I have 700k rows where the campaignid is indeed 3835 For all these rows, the connectionid is the same. I just want to find out this connectionid. use messaging_db; SELECT TOP (1) connectionid FROM outgoing_messages WITH (NOLOCK) WHERE (campaignid_int = 3835) Now this query takes approx 30 seconds to perform! I (with my small db knowledge) would expect that it would take any of the rows, and return me that connectionid If I test this same query for a campaign which only has 1 entry, it goes really fast. So the index works. How would I tackle this and why does this not work? edit: estimated execution plan: select (0%) - top (0%) - clustered index scan (100%)

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  • Why is doing a top(1) on an indexed column in mssql slow?

    - by reinier
    I'm puzzled by the following. I have a DB with around 10 million rows, and (among other indices) on 1 column is an index. Now I have 700k rows where the campaignid is indeed 3835 For all these rows, the connectionid is the same. I just want to find out this connectionid. use messaging_db; SELECT TOP (1) connectionid FROM outgoing_messages WITH (NOLOCK) WHERE (campaignid_int = 3835) Now this query takes approx 30 seconds to perform! I (with my small db knowledge) would expect that it would take any of the rows, and return me that connectionid If I test this same query for a campaign which only has 1 entry, it goes really fast. So the index works. How would I tackle this and why does this not work?

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  • Insert new row with data computed from other rows

    - by Tyler McHenry
    Suppose I have a MySQL table called MyTable, that looks like this: +----+------+-------+ | Id | Type | Value | +----+------+-------+ | 0 | A | 1 | | 0 | B | 1 | | 1 | A | 2 | | 1 | B | 3 | | 2 | A | 5 | | 2 | B | 8 | +----+------+-------+ And, for each Id, I want to insert a new row with type C whose Value is the sum of the type A and B values for the rows of the same Id. The primary key on this table is (Id, Type), so there's no question of duplication of Id,Type pairs. I can create the rows I want with this query: SELECT MyTable_A.Id AS Id, 'C' AS Type, (A_Val + B_Val) AS Value FROM (SELECT Id, Value AS A_Val FROM MyTable WHERE Type='A') AS MyTable_A JOIN (SELECT Id, Value AS B_Val FROM MyTable WHERE Type='B') AS MyTable_B ON MyTable_A.Id = MyTable_B.Id Giving: +----+------+-------+ | Id | Type | Value | +----+------+-------+ | 0 | C | 2 | | 1 | C | 5 | | 2 | C | 13 | +----+------+-------+ But the question is: How do I use this result to insert the generated type-C rows into MyTable? Is there a relatively simple way to do this with a query, or do I need to write a stored procedure? And if the latter, guidance would be helpful, as I'm not too well versed in them.

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  • How To Use a Free Website Builder

    Building websites are easy to do. Whether you use software or use the free download-able version, there are tutorials and tools to help you along the way. With free website builder, you have the ben... [Author: Scott Murray - Web Design and Development - May 23, 2010]

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  • How to Evaluate the Best Web Builder Through a Website Building Review

    There is a lot of software that are specifically designed for creating websites. This makes it hard for one to choose which website building software to use. There are website builders which are perfect for e-commerce websites while some are fit for small business owners or those who make websites as a form of hobby. To help you find the right website builder, you can check out some of the website building review available online.

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  • Report Builder 3.0: Formatting the Elements in your Report

    here is a lot that can be done to make basic tabular reports more readable, using Microsoft's free Report Builder. Rob Sheldon continues his exploration of the power of this tool by showing how to format various elements within reports. Learn Agile Database Development Best PracticesAgile database development experts Sebastian Meine and Dennis Lloyd are running day-long classes designed to complement Red Gate’s SQL in the City US tour. Classes will be held in San Francisco, Chicago, Boston and Seattle. Register Now.

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  • Report Builder 3.0: Formatting the Elements in your Report

    There is a lot that can be done to make basic tabular reports more readable, using Microsoft's free Report Builder. Rob Sheldon continues his exploration of the power of this tool by showing how to format various elements within reports Is your SQL Database under Version Control?SSMS plug-in SQL Source Control connects SVN, TFS, Git, Hg and all others to SQL Server. Learn more.

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  • Yola Website Builder Review

    A website is necessary for any small business that wants to be taken seriously, but getting it out there can be a problem, especially for the technologically challenged small business owner. With easy-to-use online tools combined with domain name registration and web hosting, Yola provides a solution for anyone who can't build their own site and can't afford to hire someone to do it for them. When Yola says their online website builder is easy to use, they aren't kidding.

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  • Optional parameters with named query in Hibernate?

    - by Ickster
    Is there any way to specify optional parameters (such as when search parameters are provided from a form and not all parameters are required) in a named query when using Hibernate? I'm using a native SQL query, but the question is probably applicable to named HQL queries as well. I'm pretty sure the answer to this is 'no', but I haven't find the definitive answer in the documentation yet.

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  • hierachical query to return final row

    - by jeff
    I have a hierarchical query that doesn't return an expected row (employee badge = 444). TABLE: hr_data badge fname supervisor_badge 111 Jeff 222 222 Joe 333 333 John 444 444 Tom 444 SQL: SELECT CONNECT_BY_ISCYCLE As IC, badge, fname, supervisor_badge FROM hr_data START WITH badge = '111' CONNECT BY NOCYCLE badge = PRIOR supervisor_badge What is Returned: IC badge fname supervisor_badge 0 111 Jeff 222 0 222 Joe 333 1 333 John 444 What is Expected: IC badge fname supervisor_badge 0 111 Jeff 222 0 222 Joe 333 **0** 333 John 444 **1** 444 Tom 444 How can I get this query to return the employee Tom and then stop?

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  • Using Treelist Values to Query a Sitecore Item

    - by kirk.burleson
    I have an item named All Recipes that contains recipes named R1, R2, and R3. I have another item named My Recipes that has a treelist field named Recipes and it contains selected values R2 and R3 from the All Recipes item. The query I'm trying to write is for the Items field of an RSS Feed. What is the query syntax to show the items in All Recipes that appear in the Recipes field of My Recipes?

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  • Problemwit sql query

    - by phenevo
    Hi, I've got query: INSERT INTO [Tasks] ([LoginName] ,[Type] ,[Filter] ,[Dictionary] ,[Description]) Select N'Anonymous',4,'SomeTable.targetcode in (select Code from cities where countrycode in ('TN')) and SomeTable.SomeValue in ('13','15')',3,N'Cities from tunis' Union All ... [Dictionary] is a part of query that i need to function on my server. I get: Incorrect syntax near ')) and SomeTable.SomeValue in (13,15)'.

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  • MySQL query from subquery not working

    - by James Goodwin
    I am trying to return a number based on the count of results from a table and to avoid having to count the results twice in the IF statement I am using a subquery. However I get a syntax error when trying to run the query, the subquery I have tested by itself runs fine. Any ideas what is wrong with the query? The syntax looks correct to me SELECT IF(daily_count>8000,0,IF(daily_count>6000,1,2)) FROM ( SELECT count(*) as daily_count FROM orders201003 WHERE DATE_FORMAT(date_sub(curdate(), INTERVAL 1 DAY),"%d-%m-%y") = DATE_FORMAT(reqDate,"%d-%m-%y") ) q

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  • Using Hibernate to do a query involving two tables

    - by Nathan Spears
    I'm inexperienced with sql in general, so using Hibernate is like looking for an answer before I know exactly what the question is. Please feel free to correct any misunderstandings I have. I am on a project where I have to use Hibernate. Most of what I am doing is pretty basic and I could copy and modify. Now I would like to do something different and I'm not sure how configuration and syntax need to come together. Let's say I have two tables. Table A has two (relevant) columns, user GUID and manager GUID. Obviously managers can have more than one user under them, so queries on manager can return more than one row. Additionally, a manager can be managing the same user on multiple projects, so the same user can be returned multiple times for the same manager query. Table B has two columns, user GUID and user full name. One-to-one mapping there. I want to do a query on manager GUID from Table A, group them by unique User GUID (so the same User isn't in the results twice), then return those users' full names from Table B. I could do this in sql without too much trouble but I want to use Hibernate so I don't have to parse the sql results by hand. That's one of the points of using Hibernate, isn't it? Right now I have Hibernate mappings that map each column in Table A to a field (well the get/set methods I guess) in a DAO object that I wrote just to hold that Table's data. I could also use the Hibernate DAOs I have to access each table separately and do each of the things I mentioned above in separate steps, but that would be less efficient (I assume) that doing one query. I wrote a Service object to hold the data that gets returned from the query (my example is simplified - I'm going to keep some other data from Table A and get multiple columns from Table B) but I'm at a loss for how to write a DAO that can do the join, or use the DAOs I have to do the join. FYI, here is a sample of my hibernate config file (simplified to match my example): <hibernate-mapping package="com.my.dao"> <class name="TableA" table="table_a"> <id name="pkIndex" column="pk_index" /> <property name="userGuid" column="user_guid" /> <property name="managerGuid" column="manager_guid" /> </class> </hibernate-mapping> So then I have a DAOImplementation class that does queries and returns lists like public List<TableA> findByHQL(String hql, Map<String, String> params) etc. I'm not sure how "best practice" that is either.

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  • Convert SQL query to Ruby help

    - by Verloren
    Hey all, I need to query my database table to find which employee has the most support tickets related to them. I can do this just fine using this MySQL query: SELECT employee_id, COUNT(id) AS number_of_tickets FROM tickets GROUP BY employee_id ORDER BY number_of_tickets DESC LIMIT 1; How would write this in Ruby-on-Rails? Thanks very much for your assistance. I use Ruby version 1.8.6, Rails version 2.2.2 and MySQL Server version 5.0.

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  • Issues with Rails 3.1 API with Query String to Create action on Mac OSX Mountain Lion

    - by hjaved
    Hi I've been stuck on this problem for a while and would appreciate your help. I'm writing an API to allow an external source like a Browser Query String or a smartphone to enter some model User info in a form and hit the User create action to write the data to the db. Please tell me what I'm doing wrong with the code below. I've also observed that if I have code like @user = User.new(params[:user]), that this approach only works when a user enters their data within the form. And that if I have code such as @user = User.new( name: params[:name], location: params[:location], password = params[:password], email: params[:email]), that this code ONLY works for a Query string entry, but NOT both Query string AND regular form submission. Why is that and how can I write the code above in the Users Controller Create action, so that it takes care of both situations? URL used: localhost:3000/users/create?name=John&&[email protected]&&password=secret&&location=SanFrancisco&date=06122012 The date is of type string but it doesn't show up in the database. Why? Everything else does. UsersController.rb def create @user = User.new(params[:user]) if @user.save session[:uid] = @user.id redirect_to thanks_path, notice: "Welcome #{@user.name}!" else redirect_to root_path end end New User Form: <%=u.text_field :name, placeholder: "Name"%><br> <%=u.text_field :email, placeholder: "Email"%><br> <%=u.password_field :password, placeholder: "Password"%><br> <%=u.text_field :location, placeholder: "City"%><br> <%=u.text_field :date, placeholder: "Date"%><br> <%if params[:partner_id]%> <%=u.hidden_field :partner_id, value: params[:partner_id]%> <%end%> <button class="btn btn-large btn-primary">Enter</button> I also tried to create a separate method called remotecreate for User creation for something other than a regular web form. I entered remotecreate in the Query string but it didn't work. def remotecreate @user = User.create(name: params[:name], email: params[:email], password: params[:password], location: params[:location], date: params[:date]) if @user.save session[:uid] = @user.id redirect_to thanks_path, notice: "Welcome #{@user.name}" else redirect_to root_path end end Thanks!

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  • Any way to speed up this hierarchical query?

    - by RenderIn
    I've got a serious performance problem with a hierarchical query that I can't seem to fix. I am modeling several organization charts in my database, each representing a virtual organization within our company. For example, we have several temporary committees that are created from time to time and there may be a Committee Organizer role at the top of this virtual hierarchy, with several people assigned to the Committee Member role beneath the organizer. Some of our virtual organizations have many levels and several branches at each level. I have a single table in which I represent all the role assignments. i.e. a ROLE_ID column and a PARENT_ROLE_ID column which is a foreign key to the ROLE_ID column. For each assignment we also store as a column the location in the company where this person has the assignment. For example, the Committee Organizer would have a company-level/ CEO assignment, while the committee members would have department-level assignments such as ACCOUNTING, MARKETING, etc. So to model the organizer/member relationship for two individuals we would have: ROLE_ID = 4 PARENT_ROLE_ID = NULL EMPLOYEE_NUMBER = 213423 COMPANY_LOCATION = CEO ROLE_ID = 5 PARENT_ROLE_ID = 4 EMPLOYEE_NUMBER = 838221 COMPANY_LOCATION = ACCOUNTING Here's where things get tricky. I have an application that every person in the organization can log in to. When they log in they should be able to view all the virtual organizations in our company. e.g. the committee members should be able to see the committee organizer and vice-versa. However, only the committee organizer should be able to edit the committee members. The difficulty is in determining whether an individual (who can have multiple role assignments) has edit access for each other assignment. While this seems simple in the example, consider a virtual organization in which we have President at the top, 5 departments directly beneath him, 2 subdepartments below each department. We only want people in the Accounting department to be able to edit individuals in the subdepartments belonging to the Accounting department. They should not have edit access to anybody in the Marketing department or its subdepartments. To determine edit access when a user views a virtual organization in our company I run a query that executes two inline views: A) Hierarchically query for all assignments in this virtual organization and using SYS_CONNECT_BY_PATH to store the entire path to each user/role/company_location and B) Hierarchically retrieve all the assignments the individual logged in has and using the SYS_CONNECT_BY_PATH to store the entire path to each of these assignments. The result of the query is all the records from A) plus a boolean determined by joining with B) which flags whether the logged in user has edit access for each record. Indexes don't seem to be helping... it simply appears that there is too much processing going on to separate all the records and then determine edit access. One issue is that I can't store the SYS_CONNECT_BY_PATH and index it... determining whether an individual record has edit access consists of comparing if: test_record_sys_path LIKE individual_record_sys_path || '%' Is a materialized view the answer?

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  • How to update multiple rows with one single query

    - by xRobot
    I use Postgresql + PHP. Say I have this table: Books ( id, title, year ) and this array of titles in PHP: $titles = array ("bible","kafka","Book of Eli"); now I want update all rows where the title is in the $titles array above. So I need a query like this: UPDATE books SET year = '2001-11-11' WHERE title is in $titles; Is is possible with one single query ? Or do I need to use FOR loop ?

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  • Explicit disable MySQL query cache in some parts of program

    - by jack
    In a Django project, some cronjob programs are mainly used for administrative or analysis purposes, e.g. generating site usage stats, rotating user activities log, etc. We probably do not hope MySQL to cache queries in those programs to save memory usage and improve query cache efficiency. Is it possible to turn off MySQL query cache explicitly in those programs while keep it enabled for other parts including all views.py?

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  • Selecting from 2 tables in a single query

    - by duder
    I have a table that I'm querying for value 43 in the second field and I return the value of the third field SELECT t1_field3 FROM table1 WHERE t1_field2=43 this returns 19, 39,73 t1_id t1_field2 t1_field3 ----- --------- --------- 1 43 19//// 2 43 39//// 3 43 73//// 4 73 43 5 13 40 Then I separately query a second table for additional information SELECT * FROM table2 WHERE t2_id=t1_field3 t2_id t2_field2 t2_field3 ----- --------- --------- 19 value19.2 value19.3 39 value39.2 value39.3 73 value73.2 value73.3 Is there a way I could combine both table1 and table2 in the same query?

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