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• How to manually start and re-start Apache with mod_wsgi powering a password protected Python WSGI app?

  - by Mahmoud Abdelkader

  I'm working on a project where I have to meet some regulatory requirements that require at least 3 out of 5 authorized users to start a backend web service that handles very sensitive information using pre-assigned passwords. Right now, the prototype has been approved and is running using Python's wsgiref.simple_server(), which I have programmed to manually prompt for the passwords. Now that the prototype has been approved, I have to migrate the web application to a production environment where I will need to run it behind Apache and mod_wsgi. I have two questions: Right now, I use a thin Python wrapper around expect to programmatically allow for remote password entry. How do I get Apache to prompt me for a password before starting? Will this have to be in the app.wsgi script that's executed by mod_wsgi? How would that work since Apache daemonizes, and thus, has no stdin! Will I have to worry about some type of code reload? Apache probably has some maximum number of requests before it kills and restarts another worker process, but, would this require a password prompt as well?

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• What's the best way to get a stored POP3 password out of Outlook 2007?

  - by Tom Morris

  If you have a password for a POP3 account in Outlook 2007 (Windows 7 Home Premium) and you then forget the password, how do you retrieve it? I tried copy-and-paste. No go. I downloaded Mail PassView, but upon installing it, AVG said it was malware, so I removed it. I eventually found the account details by opening up RegEdit, and found it in HKCU\Software\Microsoft\Windows NT\CurrentVersion\Windows Messaging Subsystem\Profiles\Outlook\ (...) but it was encoded in REG_BINARY. I Googled around and found various Visual Basic routines for decoding it but being a Unix dork I had absolutely no idea what to do with said scripts. By this point, I gave up and managed to get hold of the password by another means (it was written down on a piece of paper in the briefcase of the owner of the account - I know, it makes the inner sysadmin rage). I also attempted to write a simple POP3 server in Python and then get Outlook to log on to it, but that didn't really work out (it was about 4am at that point). For future reference, is there an easy and sensible way of doing this? Is Mail PassView actually evil spyware or was AVG just giving me a false positive? (Any chance of Windows 8 having something like OS X's Keychain?)

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• How can I estimate the entropy of a password?

  - by Wug

  Having read various resources about password strength I'm trying to create an algorithm that will provide a rough estimation of how much entropy a password has. I'm trying to create an algorithm that's as comprehensive as possible. At this point I only have pseudocode, but the algorithm covers the following: password length repeated characters patterns (logical) different character spaces (LC, UC, Numeric, Special, Extended) dictionary attacks It does NOT cover the following, and SHOULD cover it WELL (though not perfectly): ordering (passwords can be strictly ordered by output of this algorithm) patterns (spatial) Can anyone provide some insight on what this algorithm might be weak to? Specifically, can anyone think of situations where feeding a password to the algorithm would OVERESTIMATE its strength? Underestimations are less of an issue. The algorithm: // the password to test password = ? length = length(password) // unique character counts from password (duplicates discarded) uqlca = number of unique lowercase alphabetic characters in password uquca = number of uppercase alphabetic characters uqd = number of unique digits uqsp = number of unique special characters (anything with a key on the keyboard) uqxc = number of unique special special characters (alt codes, extended-ascii stuff) // algorithm parameters, total sizes of alphabet spaces Nlca = total possible number of lowercase letters (26) Nuca = total uppercase letters (26) Nd = total digits (10) Nsp = total special characters (32 or something) Nxc = total extended ascii characters that dont fit into other categorys (idk, 50?) // algorithm parameters, pw strength growth rates as percentages (per character) flca = entropy growth factor for lowercase letters (.25 is probably a good value) fuca = EGF for uppercase letters (.4 is probably good) fd = EGF for digits (.4 is probably good) fsp = EGF for special chars (.5 is probably good) fxc = EGF for extended ascii chars (.75 is probably good) // repetition factors. few unique letters == low factor, many unique == high rflca = (1 - (1 - flca) ^ uqlca) rfuca = (1 - (1 - fuca) ^ uquca) rfd = (1 - (1 - fd ) ^ uqd ) rfsp = (1 - (1 - fsp ) ^ uqsp ) rfxc = (1 - (1 - fxc ) ^ uqxc ) // digit strengths strength = ( rflca * Nlca + rfuca * Nuca + rfd * Nd + rfsp * Nsp + rfxc * Nxc ) ^ length entropybits = log_base_2(strength) A few inputs and their desired and actual entropy_bits outputs: INPUT DESIRED ACTUAL aaa very pathetic 8.1 aaaaaaaaa pathetic 24.7 abcdefghi weak 31.2 H0ley$Mol3y_ strong 72.2 s^fU¬5ü;y34G< wtf 88.9 [a^36]* pathetic 97.2 [a^20]A[a^15]* strong 146.8 xkcd1** medium 79.3 xkcd2** wtf 160.5 * these 2 passwords use shortened notation, where [a^N] expands to N a's. ** xkcd1 = "Tr0ub4dor&3", xkcd2 = "correct horse battery staple" The algorithm does realize (correctly) that increasing the alphabet size (even by one digit) vastly strengthens long passwords, as shown by the difference in entropy_bits for the 6th and 7th passwords, which both consist of 36 a's, but the second's 21st a is capitalized. However, they do not account for the fact that having a password of 36 a's is not a good idea, it's easily broken with a weak password cracker (and anyone who watches you type it will see it) and the algorithm doesn't reflect that. It does, however, reflect the fact that xkcd1 is a weak password compared to xkcd2, despite having greater complexity density (is this even a thing?). How can I improve this algorithm? Addendum 1 Dictionary attacks and pattern based attacks seem to be the big thing, so I'll take a stab at addressing those. I could perform a comprehensive search through the password for words from a word list and replace words with tokens unique to the words they represent. Word-tokens would then be treated as characters and have their own weight system, and would add their own weights to the password. I'd need a few new algorithm parameters (I'll call them lw, Nw ~= 2^11, fw ~= .5, and rfw) and I'd factor the weight into the password as I would any of the other weights. This word search could be specially modified to match both lowercase and uppercase letters as well as common character substitutions, like that of E with 3. If I didn't add extra weight to such matched words, the algorithm would underestimate their strength by a bit or two per word, which is OK. Otherwise, a general rule would be, for each non-perfect character match, give the word a bonus bit. I could then perform simple pattern checks, such as searches for runs of repeated characters and derivative tests (take the difference between each character), which would identify patterns such as 'aaaaa' and '12345', and replace each detected pattern with a pattern token, unique to the pattern and length. The algorithmic parameters (specifically, entropy per pattern) could be generated on the fly based on the pattern. At this point, I'd take the length of the password. Each word token and pattern token would count as one character; each token would replace the characters they symbolically represented. I made up some sort of pattern notation, but it includes the pattern length l, the pattern order o, and the base element b. This information could be used to compute some arbitrary weight for each pattern. I'd do something better in actual code. Modified Example: Password: 1234kitty$$$$$herpderp Tokenized: 1 2 3 4 k i t t y $ $ $ $ $ h e r p d e r p Words Filtered: 1 2 3 4 @W5783 $ $ $ $ $ @W9001 @W9002 Patterns Filtered: @P[l=4,o=1,b='1'] @W5783 @P[l=5,o=0,b='$'] @W9001 @W9002 Breakdown: 3 small, unique words and 2 patterns Entropy: about 45 bits, as per modified algorithm Password: correcthorsebatterystaple Tokenized: c o r r e c t h o r s e b a t t e r y s t a p l e Words Filtered: @W6783 @W7923 @W1535 @W2285 Breakdown: 4 small, unique words and no patterns Entropy: 43 bits, as per modified algorithm The exact semantics of how entropy is calculated from patterns is up for discussion. I was thinking something like: entropy(b) * l * (o + 1) // o will be either zero or one The modified algorithm would find flaws with and reduce the strength of each password in the original table, with the exception of s^fU¬5ü;y34G<, which contains no words or patterns.

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• Log all files saved on XP system.

  - by Jason Taylor

  I have a user that frequently saves items (or even forgets to save) to places that he forgets. Usually a simple search finds them, but not always. Is there any way to log/track the most recently saved files? It would be great to be the last "saved" files as the recent documents feature is unreliable if he constantly opens documents in his search for the file he just saved. Alternatively, any ideas on how to control this situation?

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• Prevent URLs from specific domains from being saved in Firefox history

  - by noam

  I want to prevent or block URLs of specific domains from being saved or shown in my history. I want to be able to go to these certain websites normally, just not have them saved and not have to use private or incognito mode. For instance, I don't want any of Google's search result pages to be saved in my history since then when I use the awesomebar I get a lot of Google's search results, which are of no use to me. Of course I can keep on deleting them, but I would like a way to specify that any URL starting with www.google.com shouldn't be saved.

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• PHP: Safe way to store decryptable passwords

  - by Jammer

  I'm making an application in PHP and there is a requirement that it must be possible to decrypt the passwords in order to avoid problems in the future with switching user database to different system. What encryption/decryption algorithm would you suggest? Is it good idea to just store the encrypted value and then compare the future authentication attempts to that value? Are the passwords still as safe as MD5/SHA1 when the private key is not available to the attacker (Hidden in USB drive for example)? I should still use salting, right? What encryption libraries should I use for PHP?

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• PAM Winbind Expired Password

  - by kernelpanic

  We've got Winbind/Kerberos setup on RHEL for AD authentication. Working fine however I noticed that when a password has expired, we get a warning but shell access is still granted. What's the proper way of handling this? Can we tell PAM to close the session once it sees the password has expired? Example: login as: ad-user [email protected]'s password: Warning: password has expired. [ad-user@server ~]$ Contents of /etc/pam.d/system-auth: auth required pam_env.so auth sufficient pam_unix.so nullok try_first_pass auth requisite pam_succeed_if.so uid >= 500 quiet auth sufficient pam_krb5.so use_first_pass auth sufficient pam_winbind.so use_first_pass auth required pam_deny.so account [default=2 success=ignore] pam_succeed_if.so quiet uid >= 10000000 account sufficient pam_succeed_if.so user ingroup AD_Admins debug account requisite pam_succeed_if.so user ingroup AD_Developers debug account required pam_access.so account required pam_unix.so broken_shadow account sufficient pam_localuser.so account sufficient pam_succeed_if.so uid < 500 quiet account [default=bad success=ok user_unknown=ignore] pam_krb5.so account [default=bad success=ok user_unknown=ignore] pam_winbind.so account required pam_permit.so password requisite pam_cracklib.so try_first_pass retry=3 password sufficient pam_unix.so md5 shadow nullok try_first_pass use_authtok password sufficient pam_krb5.so use_authtok password sufficient pam_winbind.so use_authtok password required pam_deny.so session [default=2 success=ignore] pam_succeed_if.so quiet uid >= 10000000 session sufficient pam_succeed_if.so user ingroup AD_Admins debug session requisite pam_succeed_if.so user ingroup AD_Developers debug session optional pam_mkhomedir.so umask=0077 skel=/etc/skel session optional pam_keyinit.so revoke session required pam_limits.so session optional pam_mkhomedir.so session [success=1 default=ignore] pam_succeed_if.so service in crond quiet use_uid session required pam_unix.so session optional pam_krb5.so

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• duplicity fail: not promping for password: "Running 'sftp user@host' failed"

  - by Thr4wn

  I have two linode VPS accounts and I want to back up one onto the other (the reasons are mainly for fun and to practice server administration.) the short version Duplicity isn't even asking for my password, but immediately says "invalid SSH password" (but I can ssh into the other server). why? the long version When I run duplicity /home/me scp://[email protected]//root/backup I get Invalid SSH password Running 'sftp [email protected]' failed (attempt #1) Invalid SSH password Running 'sftp [email protected]' failed (attempt #2) Invalid SSH password Running 'sftp [email protected]' failed (attempt #3) And it says Invalid SSH password immediately with no opportunity for me to actually type the password. When I type duplicity full -v9 --num-retries 4 /home/me scp://[email protected]//root/backup I get Main action: full Running 'sftp [email protected]' (attempt #1) State = sftp, Before = 'Connecting to 97.107.129.67... [email protected]'s' State = sftp, Before = '' Invalid SSH password Running 'sftp [email protected]' failed (attempt #1) I can ssh into [email protected] fine, and in fact have the ip in known_hosts before I tried any of this. serer 1 (from which I'm running the duplicity command) is Linode's default Ubuntu 8 setup with only a handful of programs installed via apt-get. server 2 (represented by x.x.x.x) is literally only Linode's default Ubuntu 8 setup I previously tried using SystemImager -- would that have changed settings in a destructive way? (I have removed and rebooted since then) Isn't Duplicity supposed to prompt for password? Am I using it wrong? are there common mistakes/dependencies I need to know about? Is there any way that x.x.x.x could be setup that could make this not work (I used Linode's default Ubuntu 8 setup and barely )?

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• How is the "change password at next logon" requirement supposed to work with RDP using Network Level Authentication?

  - by NReilingh

  We have a Windows server (2008 R2) with the "Remote Desktop Services" feature installed and no Active Directory domain. Remote desktop is set up to "Allow connections only from computers running Remote Desktop with Network Level Authentication (more secure)". This means that before the remote screen is displayed, the connection is authenticated in a "Windows Security: Enter your credentials" window. The only two role services installed on this server is the RD Session Host and Licensing. When the "User must change password at next logon" checkbox is selected in the properties for a local user on this server, the following displays on a client computer after attempting to connect using the credentials that were last valid: On some other servers using RDP for admin access (but without the Remote Desktop Services role installed), the behavior is different -- the session begins and the user is given a change password prompt on the remote screen. What do I need to do to replicate this behavior on the Remote Desktop Services server?

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• How to reset Administrator password Windows Server 2003 installed on Vmware?

  - by Cucumber

  I want to reset administrator password on Windows Server 2003. OS installed on VMware server VMware Server version 2.0.1. And problem is this: when i try to boot from live cd, after boot disk with Windows not detected. I tried to use Windows Admin Hack - Linux Boot; Hirens.BootCD.10.4; ophcrack-xp-livecd-2.3.1.iso None of these programs did not see the hard drive! Any ideas? Thank! ADD: I want to reset LOCAL admin password, not domain. And this computer are not domain controller.

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• OpenLDAP Password Expiration with pwdReset=TRUE?

  - by jsight

  I have configured the ppolicy overlay for OpenLDAP to enable password policies. These things work: Password lockouts on too many failed attempts Password Change required once pwdReset=TRUE added to user entry Password Expirations If the account is locked out due to intrusion attempts (too many bad passwords) or time (expiration time hit), the account must be reset by an administrator. However, when the administrator sets pwdReset=TRUE in the profile, this seems to also override the expiration policy. So, the password that the administrator sent out (which should be a temporary password) ends up being valid permanently. Is there a way in OpenLDAP to have a password that must be changed, but also MUST expire?

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• OpenLDAP Password Expiration with pwdReset=TRUE?

  - by jsight

  I have configured the ppolicy overlay for OpenLDAP to enable password policies. These things work: Password lockouts on too many failed attempts Password Change required once pwdReset=TRUE added to user entry Password Expirations If the account is locked out due to intrusion attempts (too many bad passwords) or time (expiration time hit), the account must be reset by an administrator. However, when the administrator sets pwdReset=TRUE in the profile, this seems to also override the expiration policy. So, the password that the administrator sent out (which should be a temporary password) ends up being valid permanently. Is there a way in OpenLDAP to have a password that must be changed, but also MUST expire?

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• Blackberry Gmail password change

  - by Highstead

  I've updated my gmail password and so i must update my blackberry password. I tried updating the email password to which i got the following message. Invalid email address or password. Please verify your email address and password. The information you provided is incorrect. If the error persists contact gmail.com (Your email provider). Please try again. I tried again, with what i know the password to be, with password show on. I've also deleted the account and tried to create it. I've tried going to the "Last account activity: XXXX details" menu and signing out all devices. I'm continually getting the above error, but the account activities don't seem to show any sign of a mobile attempt to access my mail account. Has anyone had this issue before and how did you sign it. Thanks in advance.

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• How to allow password protected start-stop-daemon functionality?

  - by Mahmoud Abdelkader

  I would like to use Ubuntu's start-stop-daemon to start my application, but the application protects some sensitive information, so I have a mechanism where the application prompts for a password that's then used to generate a hashkey, which is used as the secret key for a symmetric encryption (AES) to encrypt and decrypt things from a database. I'd like to daemonize this application and have it run from start-stop-daemon, so that sudo service appname stop and sudo service appname start would work, but, I'm not sure how to go about doing this with the added complexity of a password prompt. Is there something that supports this or do I have to program it from scratch? I figured I should ask first before re-inventing the wheel. Thanks in advance.

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• SSH only works after intentionally failed password

  - by pyraz

  So, I'm having a rather weird problem. I have a server, that when I try to SSH into, immediately closes the connection if I type in the correct password on the first attempt. However, if I purposefully enter a wrong password on the first attempt, and then enter a correct password at the second or third prompt, it successfully logs me into the computer. Similarly, when I try to use public key authentication, I get an immediate closed connection. If, however, I enter a wrong password for my key file, followed by another wrong password once it reverts to password authentication, I can successfully log in as long as I provide the correct password at the second or third prompt. The machine is running Red Hat Enterprise Linux Server release 6.2 (Santiago), and is using LDAP and PAM for authentication. Any ideas on where to start debugging this one? Let me know what config files I need to provide and I'll be happy to do so.

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• iPhone 3G backup encryption? I've never entered a password?

  - by Lewis

  I can't unclick or access my backup iPhone encrypted file. For the life of me I can not remember ever entering a password for the encrypted iPhone backups. I've tried every password I've used or use and nothing is working. I'm not getting anywhere with long searches online. Can anyone here help? iPhone 3.1.2 iTunes 9.1.1 Mac OSX 10.5.8 Please help, how do I get my iPhone backed up from my 'locked' file I've never locked?

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• How to set a password on a folder in Windows XP?

  - by karthik

  How do I to set a password for a folder in Windows XP?

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• How to Use a PIN Instead of a Password in Windows 8

  - by Taylor Gibb

  Entering your full password on a touch screen device can really become a pain in the neck, luckily for us we can link a short 4 digit PIN to our user account and log in with that instead. Note: PIN codes are nowhere near as safe as using an alphanumeric password, however, they do still have a purpose when you don’t want to enter your 15 character password on a touch screen device. Creating a PIN Press the Win + I keyboard combination to bring up the Settings Charm, then click on the Change PC settings link. This will open up the Modern UI PC Settings app, where you can click on the Users section. On the right hand side you will see a Create a PIN button, click on it. Now you will need to verify that you are the owner of this user account by entering your password. Then you can choose a PIN, remember that it can only contain digits. Now when you get to the login screen you will have the option to use a PIN. How To Boot Your Android Phone or Tablet Into Safe Mode HTG Explains: Does Your Android Phone Need an Antivirus? How To Use USB Drives With the Nexus 7 and Other Android Devices

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• SSH asks for password

  - by user1435470

  I have already : Installed the server Generated the pub/pri keys with -P "" Copied the id_rsa.pub to authorized_keys ssh localhost answered "yes", copied to known_hosts tried ssh localhost still asks for password Output: hduser@hduser1-desktop:~$ ssh -v localhost OpenSSH_5.3p1 Debian-3ubuntu7, OpenSSL 0.9.8k 25 Mar 2009 debug1: Reading configuration data /etc/ssh/ssh_config debug1: Applying options for * debug1: Connecting to localhost [127.0.0.1] port 22. debug1: Connection established. debug1: identity file /home/hduser/.ssh/identity type -1 debug1: identity file /home/hduser/.ssh/id_rsa type 1 debug1: Checking blacklist file /usr/share/ssh/blacklist.RSA-2048 debug1: Checking blacklist file /etc/ssh/blacklist.RSA-2048 debug1: identity file /home/hduser/.ssh/id_dsa type -1 debug1: Remote protocol version 2.0, remote software version OpenSSH_5.3p1 Debian- 3ubuntu7 debug1: match: OpenSSH_5.3p1 Debian-3ubuntu7 pat OpenSSH* debug1: Enabling compatibility mode for protocol 2.0 debug1: Local version string SSH-2.0-OpenSSH_5.3p1 Debian-3ubuntu7 debug1: SSH2_MSG_KEXINIT sent debug1: SSH2_MSG_KEXINIT received debug1: kex: server->client aes128-ctr hmac-md5 none debug1: kex: client->server aes128-ctr hmac-md5 none debug1: SSH2_MSG_KEX_DH_GEX_REQUEST(1024<1024<8192) sent debug1: expecting SSH2_MSG_KEX_DH_GEX_GROUP debug1: SSH2_MSG_KEX_DH_GEX_INIT sent debug1: expecting SSH2_MSG_KEX_DH_GEX_REPLY debug1: Host 'localhost' is known and matches the RSA host key. debug1: Found key in /home/hduser/.ssh/known_hosts:3 debug1: ssh_rsa_verify: signature correct debug1: SSH2_MSG_NEWKEYS sent debug1: expecting SSH2_MSG_NEWKEYS debug1: SSH2_MSG_NEWKEYS received debug1: SSH2_MSG_SERVICE_REQUEST sent debug1: SSH2_MSG_SERVICE_ACCEPT received debug1: Authentications that can continue: publickey,password debug1: Next authentication method: publickey debug1: Offering public key: /home/hduser/.ssh/id_rsa debug1: Authentications that can continue: publickey,password debug1: Trying private key: /home/hduser/.ssh/identity debug1: Trying private key: /home/hduser/.ssh/id_dsa debug1: Next authentication method: password Any suggestions ? Cheers

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• Password Cracking in 2010 and Beyond

  - by mttr

  I have looked a bit into cryptography and related matters during the last couple of days and am pretty confused by now. I have a question about password strength and am hoping that someone can clear up my confusion by sharing how they think through the following questions. I am becoming obsessed about these things, but need to spend my time otherwise :-) Let's assume we have an eight-digit password that consists of upper and lower-case alphabetic characters, numbers and common symbols. This means we have 8^96 ~= 7.2 quadrillion different possible passwords. As I understand there are at least two approaches to breaking this password. One is to try a brute-force attack where we try to guess each possible combination of characters. How many passwords can modern processors (in 2010, Core i7 Extreme for eg) guess per second (how many instructions does a single password guess take and why)? My guess would be that it takes a modern processor in the order of years to break such a password. Another approach would consist of obtaining a hash of my password as stored by operating systems and then search for collisions. Depending on the type of hash used, we might get the password a lot quicker than by the bruteforce attack. A number of questions about this: Is the assertion in the above sentence correct? How do I think about the time it takes to find collisions for MD4, MD5, etc. hashes? Where does my Snow Leopard store my password hash and what hashing algorithm does it use? And finally, regardless of the strength of file encryption using AES-128/256, the weak link is still my en/decryption password used. Even if breaking the ciphered text would take longer than the lifetime of the universe, a brute-force attack on my de/encryption password (guess password, then try to decrypt file, try next password...), might succeed a lot earlier than the end of the universe. Is that correct? I would be very grateful, if people could have mercy on me and help me think through these probably simple questions, so that I can get back to work.

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• Can't work out security

  - by user215351

  I installed Ubuntu on puter I am the only user I alone use. I was trying a to find out how to repair hardware faults. Surprised to find I was not the owner and that there is a password that locks me out. I only set one password during set up so what is this mysterious password. As far as I'm concerned it is overdone on security, Im sick of authenticating every 3 seconds. I need a simpler system

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• Fixing /etc/shadow with md5 passwords to sha512 passwords

  - by dr jimbob

  I recently upgraded an ubuntu server with many users to a recent version from a version from 2008. The server used to use md5 password hashes (e.g., the shadow passwords began with $1$) and now is configured to use sha512. I'd prefer to keep using sha512, but would like the old users to be able to partially login once with their old password and then be forced to update their password (even if its the same password) generating a sha512. Right now, the old md5-based passwords in /etc/shadow won't let the user login at all (and just appear to be incorrect passwords). This seems like plenty of people should have had to do this before; yet I can't see how to do it, looking in the common places like /etc/pam.d/common-password nad /etc/login.defs. Also users will be logging in via ssh; and I do not have everyone's contact info (email or otherwise); and some login fairly rarely. Any help? (Googling doesn't seem to give any good solutions).

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• Can't Enter Password in Recovery Mode

  - by Mike Lentini

  When I go into recovery mode to get to the command line, I enter "telinit 3" to drop out of root. This works on my desktop, but on my laptop it asks for my username and password, then I hit enter and the first letter of my password appears and it doesn't log me in. It then proceeds to ask me for my username and password again, and the issue continues. Am I doing something wrong? Is this a known issue with a solution? EDIT: Worked around this by going into /etc/default/grub and setting it to boot in text mode. Still would like a solution for this though.

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• Can not enter password for sudo [duplicate]

  - by Michael

  This question already has an answer here: add repository to ubuntu from terminal with pgp key 3 answers I have used Ubuntu for several years, and I can not enter password for sudo, and this is when i wanna add a key to public.gpg for itunes10 it dos not work, and the password normal works wite sudo but not in the terminal when i enter: sudo wget -q "http:// deb.playonlinux.com/public.gpg" -o- | sudo apt-get add - and it says this 'sorry try again', and i just had installed itunes10, and have to add a key whit wget to public.gpg, and i tried to enter in the terminal: sudo apt-get update and the password works fine but not whit using sudo wget, and can some one please help.

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• How to disable password prompt for default keyring?

  - by user110431

  I'm using Ubuntu 12.10 64Bit. How to disable ubuntu enter password for keyring default to unlock prompt ? Every time I open Chrome or ubuntu software center, this annoying window jump out. I have being searching online for a long time, most of the answers are like delete ~/.gnome2/keyring XX , but I don't have such directory or go to password and keys , disable some option, but this window is empty in my case, very strange , even I add a new password keyring, it is still empty. None of these methods works in my case. I will be very appreciate if you can help

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