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  • Python Newbie: Sphinx on App Engine - too much at a time?

    - by Pekka
    Following up on my last year's question on documentation, I now want to get started and try out Python-based Sphinx for putting together the developer documentation for a PHP CMS I've been working on. Instead of setting up Python locally on my workstation, I would like to run it on a publicly accessible web server from the start. All the web hosting packages I have access to run on the LAMP stack, and I'm reluctant to buy Python-based hosting. I am very interested in the Google App Engine, the free quotas they provide will do for me a hundred times over, and even if not, their pricing looks very reasonable. Now I have zero knowledge of Python - getting Sphinx to work would be my first contact with it - and very little time. As far as I understand, the platform and python libraries the App Engine provides are very compatible to a standard Python library but not identical. So my question is: Can Sphinx run on App Engine at all? Is installing Sphinx on the App Engine as straightforward as if I would install it on top of a normal Python installation? Or will the App Engine's environment require tweaking of the source code that I can't perform in reasonable time with my current level of Python? Should I be installing Sphinx on a local server and a "normal" Python stack instead first? Does anybody know any helpful How-to's, tutorials or other resources for this?

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  • elisp newbie question: Can't find 'filename' function definition in org.el?

    - by Dave Paroulek
    I really love org-mode in emacs and want to customize a few things. While reading thru org.el, I'm finding several references to filename but can't find filename using describe-function? I'm sure there's a simple answer, but I'm just learning elisp and it's not obvious. Any insight into where filename is defined? And/or if it's not a function, what is it? For example, filename on line 25502: (filename (if to-buffer (expand-file-name (concat (file-name-sans-extension (or (and subtree-p (org-entry-get (region-beginning) "EXPORT_FILE_NAME" t)) (file-name-nondirectory buffer-file-name))) "." html-extension) (file-name-as-directory (or pub-dir (org-export-directory :html opt-plist))))))

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  • What should a conference newbie bring to make the most out of their first conference?

    - by skarnis
    I am planning to attend my first developer conference (Microsoft TechDays 2008 in Toronto). I have been looking around for suggestions so that I can prepare and make the most out of my first developer conference. Many articles make suggestions about asking questions, getting involved, being social. These are great! I am also wondering about physical items. I have seen many conference photos with most of the audience having their laptops. Are they just taking notes? Are they working on a problem during the session? Are these photos just during a break and everyone is catching up on blogs/email/outside contact? Thank you StackOverflow-ers (StackOverflow-ites?)

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  • Another total newbie question: what exactly is a "run-time"?

    - by Russel
    Hello, here's my question: My company is always having problems with software not working because "run-times" or missing. I hear people say this a lot (you need the 32-bit run times, Microsoft run-times, etc etc). What exactly is being referred to? DLL files? Something different? Can anyone please clarify? Thanks! RKL

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  • ASP.NET MVC Newbie: why isn't my model available when creating a strongly-typed view?

    - by Rax Olgud
    I'm starting with ASP.NET MVC, and working with NerdDinner as reference. I did the following: Created a new project Added a couple of tables Created LINQ to SQL for them Created a new controller My Models directory now contains MyModel.dbml, under which I have MyModel.designer.cs, that contains classes for models relating to both of my tables (let's call them Categories and Products). Now, under my new controller, I would like to create a strongly typed view. So for example I have the following code in my controller (for my application I must work by name, and the "Name" field is unique): public ActionResult Details(string name) { MyModelDataContext db = new MyModelDataContext(); Product user = db.Products.Single(t => t.Name == name); return View(user); } I would like to create a strongly-typed view. So I right-click the line "return View(user)", and choose "Add View...". I click "Create a strongly-typed view". When I click the dropdown of "View data class", I don't see my models, but only: MyProject.Controllers.AccountMembershipService MyProject.Controllers.FormsAuthenticationService What am I missing?

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  • newbie need help ! !

    - by Florent
    ok guys so i'm new in iphone dev you know it ! I want to add badge from my app : i know how to in the application did finish launching. But i want to it depending on an int value i have stored in a plist (just one string an int value) i have placed on my server htt://anadress/myplist.plist How can i read the content of this value in the plist from my server thanks to all it'll help so much

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  • Ruby on Rails - where to write business logic while processing a request? (newbie)

    - by Genadinik
    I am learning Ruby on Rails. I made a simple link like this: <%= link_to "Alex Link", alexes_path(@alex) %> then I routed it in routes.rb like this: resources :alexes get "home/index" then I am a bit unclear, but I think it goes to this part of the controller: def index #@alexes = Alex.all respond_to do |format| format.html # index.html.erb format.json { render json: @alexes } end end Am I correct that it goes to this part of the controller? Then nothing much happens and it goes to the next page which is index.html.rb under views\alexes So what I am wondering is - if I needed to do some business logic, would I write that in the controller snippet? Where inside the snippet? An example would be nice to take a look. Also, I would like to connect to a MongoDb database. Would I also write that in the middle of the controller? Thanks!

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  • Java newbie problem: classes of the same package accessing one another?

    - by HH
    Test.java and SetWord.java belong to the package tools. Test.java needs to access SetWord but an odd error 'cannot find' SetWord appear. The package limits the visibility, it works without 'package tools;' lines. How can I acess the SetWords with Test in the same pkg? In general, how can classes access one another in the same pkg? Test.java package tools; import java.io.*; import java.util.*; public class Test{ public static void main(String[] args) { //IT CANNOT FIND SetWords despite the same folder, why? SetWord sw=new SetWord(); System.out.println(st.set("HELLO)"); } } SetWord.java package tools; import java.io.*; import java.util.*; public class SetWord{ public SetWord(){} public String set(String s) { return s.trim().toLowerCase(); } }

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  • Newbie programmer looking for a fun, small project (pref. C++/Python)

    - by Francisco P.
    Hello everyone, I have some experience in Scheme and C++ (read: a semester of each) I know the very basics of Python (used it for physics simulations with the Visual Python module). Can you recommend me some fun and small (i.e. don't take much time) projects on either Python or C++? I have no real preferences, just that it is fun :P Thanks for your time! PS: I've tried projecteuler and python challenge. Euler is good, but more about math than coding, and py challenge just didn't work for me.

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  • Cocoa's newbie question: is it possible to bind a NSTableView's selection to another tableview's selection?

    - by cocoaOverloaded
    http://img651.imageshack.us/img651/6999/modelsf.jpg Let'say, I've 2 entities in the Core Data's Model file, one being all "transactions" ever done by X company. The "transactions" entity has among other properties, a "DATE" property and a to-one relationship "COMPANY"(specifying the company with which X company has done that particular transaction). The other entity:"companies" of course contains all the companies' info ,with which X company has done transaction. The "companies" entity has a to-many relationships "TRANSACTIONS" which is an inverse relationship to "transactions" entity's "COMPANY" relationship. So within IB, I created a NSTableView(with its own NSArrayController) showing all the transactions on a particular Date (with the help of NSPredicate). Then I create another table view showing the to-many relationship "TRANSACTIONS" of the company of the selected transaction in the first table view(which shows transactions on a particular date). The 2nd table view's NSArrayController binding is like this: ** bind to: "name of the first tableview's controller", Controller Key: selection, Model Key Path:COMPANY.TRANSACTIONS(the to-many relationship in the "companies" entity)** Everythings work fine up to this moment, the 2nd tableview shows all the transactions X company has done with the company of the selected transactions in the 1st table view. But I have a group of textfields showing details of a particular transactions. Binding the these textfields with the controller of the 1st table view(the one showing transactions on a particular date) is pretty straightforward. But what I want to do are: 1/ Look up the transactions on a particular date in the first table view, select any one of them 2/ Then, check all previous transactions of the company of that transaction( selected in the first table view) from the 2nd table view 3/ Select any previous transactions and check the details of the transaction from that group of textfields So naturally I should have bind the textfields' gp to the 2nd table view's controller. But I found the default selected row in the 2nd table view(the one show all previous transactions of a company) wasn't the transaction I've selected in the 1st tableView for a particular date. Of course, i can manually select that transaction in the 2nd table view again.... So I just want to know if it's possible to have the 2nd table view automatically select the transaction according to the transaction I've selected in the 1st table view thr binding?? After hours of googling, I solved the problem by implementing the tableview Delegate protocol: - (void)tableViewSelectionDidChange:(NSNotification *)aNotification { if (["nameOf1stTableView" selectedRow] > -1) { NSArray *objsArray = ["nameOf2ndTableView'sController" arrangedObjects]; for (id obj in objsArray) { if ([[obj valueForKey:@"DATE"] isEqualToDate: ["nameOf1stTableView'sController".selection valueForKey:@"DATE"]]) { ["nameOf2ndTableView" selectRowIndexes:[NSIndexSet indexSetWithIndex:[objsArray indexOfObject:obj]] byExtendingSelection:NO]; } } } } But,this just look too cumbersome... can it be done with binding alone? Thanks in Advance,

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  • WCF newbie - how to install and use a SSL certificate?

    - by Shaul
    This should be a snap for anyone who's done it before... I'm trying to set up a self-hosted WCF service using NetTcpBinding. I got a trial SSL certificate from Thawte and successfully installed that in my IIS store, and I think I've got it correctly set up in the service - at least it doesn't exception out on me! Now, I'm trying to connect the client (this is still all on my dev machine), and it's giving me an error, "Message = "The X.509 certificate CN=ssl.mydomain.com, OU=For Test Purposes Only. No assurances., OU=IT, O=My Company, L=My Town, S=None, C=IL chain building failed. The certificate that was used has a trust chain that cannot be verified. Replace the certificate or change the certificateValidationMode. A certificate chain processed, but terminated in a root certificate which is not trusted by the trust provider." Ooookeeeey... now what? Client code (I want to do this in code, not app.config): var baseAddress = "localhost"; var factory = new DuplexChannelFactory<IMyWCFService>(new InstanceContext(SiteServer.Instance)); factory.Endpoint.Address = new EndpointAddress("net.tcp://{0}:8000/".Fmt(baseAddress)); var binding = new NetTcpBinding(SecurityMode.Message); binding.Security.Message.ClientCredentialType = MessageCredentialType.UserName; factory.Endpoint.Binding = binding; var u = factory.Credentials.UserName; u.UserName = userName; u.Password = password; return factory.CreateChannel()

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  • Cocoa Drag and Drop, reading back the data. [Newbie]

    - by kodai
    Ok, I have a NSOutlineView set up, and I want it to capture PDF's if a pdf is dragged into the NSOutlineView. My first question, I have the following code: [outlineView registerForDraggedTypes:[NSArray arrayWithObjects:NSStringPboardType, NSFilenamesPboardType, nil]]; In all the apple Docs and examples I've seen I've also seen something like MySupportedType being an object registered for dragging. What does this mean? Do I change the code to be: [outlineView registerForDraggedTypes:[NSArray arrayWithObjects:@"pdf", NSStringPboardType, NSFilenamesPboardType, nil]]; Currently I have it set up to recognize drag and drop, and I can even make it spit out the URL of the dragged file once the drag is accepted, however, this leads me to my second question. I want to keep a copy of those PDF's app side. I suppose, and correct me if I'm wrong, that the best way to do this is to grab the data off the clipboard, save it in some persistant store, and that's that. (as apposed to using some sort of copy command and literally copying the file to the app director.) That being said, I'm not sure how to do that. I've the code: - (BOOL)outlineView:(NSOutlineView *)ov acceptDrop:(id <NSDraggingInfo>)info item:(id)item childIndex:(NSInteger)childIndex { NSPasteboard *pboard = [info draggingPasteboard]; NSURL *fileURL; if ( [[pboard types] containsObject:NSURLPboardType] ) { fileURL = [NSURL URLFromPasteboard:pboard]; // Perform operation using the file’s URL } NSData *data = [pboard dataForType:@"NSPasteboardTypePDF"]; But this never actually gets any data. Like I said before, it does get the URL, just not the data. Does anyone have any advise on how to get this going? Thanks so much!

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  • Applescript for a Newbie: Copy file to a new folder.

    - by Mike
    Hi there! I've also posted this on the macnn forums, but thought I may get a better response here. I was hoping to find some help with using applescript (something I have never tried before, though I have a good knowledge of php etc) I need to create an applescript that will copy specified files from one folder to a newly created folder. These files need to be specified in the applescript. so something like: start fileToBeMoved = "Desktop/Test Folder 1/test.doc" newfoldername = "Test Folder 2" make newfolder and name it 'newfoldername' copy 'fileToBeMoved' to 'newfolder' end I'm so sorry for the rubbish description! Hope someone can help! Thanks!

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  • Newbie jQuery question: Need slideshow to rotate automatically, not just when clicking navigation.

    - by Justin
    Hi everyone, This is my first post, so please forgive me if this question has been asked a million times. I'm a self professed jQuery hack and I need a little guidance on taking this script I found and adapting it to my needs. Anyway, what I'm making is an image slide show with navigation. The script I found does this, but does not automatically cycle through the images. I'm using jQuery 1.3.2 and would rather stick with that than using the newer library. I would also prefer to edit what is already here rather than start from scratch. Anywho, here's the html: <div id="myslide"> <div class="cover"> <div class="mystuff"> <img alt="&nbsp;" src="http://www.mfhc.com/wp/wp-content/uploads/2010/05/current_Denver-skyline.jpg" /> </div> <div class="mystuff"> <img alt="&nbsp;" src="http://www.mfhc.com/wp/wp-content/uploads/2010/05/pepsi_center-IS42RF-0D111C.jpg" /> </div> <div class="mystuff"> <img alt="&nbsp;" src="http://www.mfhc.com/wp/wp-content/uploads/2010/05/columbine-2689820469_D1104.jpg" /> </div> <div class="mystuff"> <img alt="&nbsp;" src="http://www.mfhc.com/wp/wp-content/uploads/2010/05/ist2_10460354-RedRocks.jpg" /> </div> </div> <!-- end of div cover --> </div> <!-- end of div myslide --> And here's the jQuery: <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.min.js"></script> <script type="text/JavaScript"> $(document).ready(function (){ $('#button a').click(function(){ var integer = $(this).attr('rel'); $('#myslide .cover').css({left:-820*(parseInt(integer)-1)}).hide().fadeIn(); /*----- Width of div #mystuff (here 820) ------ */ $('#button a').each(function(){ $(this).removeClass('active'); if($(this).hasClass('button'+integer)){ $(this).addClass('active')} }); }); }); </script> Here's where I got the script: http://www.webdeveloperjuice.com/2010/04/07/create-lightweight-jquery-fade-manual-slideshow/ Again, if this question is too basic for this site please let me know and possibly provide a reference link or two. Thanks a ton!

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  • Google App Engine/GWT/Eclipse Plugin Newbie Question- how to autobuild client side resources?

    - by Dieter Hanover
    Hi there, I'm tinkering with the default GWT application generated by the Google Eclipse plugin when I click the Google "New Web Application Project" button in Eclipse 3.5. This will no doubt be familiar to many of you.. basically there is an h1 title stating "Web Application Starter Project," a text field, and a Send button. What I've found is that whenever I make changes to the client side resources, e.g. change the text on the Send button to "Submit" in the .java file, Eclipse does not appear to autobuild these resources. In fact I have to rebuild the entire project in order for these changes to be reflected in my browser. I do have "build automatically" selected in eclipse. I should state that this is my second GWT project, the first was almost entirely server side (restlet on GAE) and everything built automatically nicely. When I first tried this new project with updated client resources, on refreshing my browser, the browser stated "you may need to (re)compile your project." I'm not sure if this is relevant but I thought I'd mention it all the same. So what's going on? How do I get Eclipse/GWT to autobuild these client side resources? Cheers for any help you can offer! :-)

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  • Java-Hibernate-Newbie: How do I acces the values from this list?

    - by Mes
    I have this class mapped @Entity @Table(name = "USERS") public class User { private long id; private String userName; } and I make a query: Query query = session.createQuery("select id, userName, count(userName) from User order by count(userName) desc"); return query.list(); How can I acces the value returned by the query?

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  • The return value should be a list but doesn't return as expected?! - Python newbie

    - by user1432941
    Hi this must be a very simple solution that has eluded me this last hour. I've tried to build this test function where the return value of the test_cases list should match the values in the test_case_answers list but for some reason, test case 1 and test case 2 fail. When i print the return values for the test cases they return the correct answers, but for some reason test case 1 and test case 2 return False. Thanks for your help! import math test_cases = [1, 9, -3] test_case_answers = [1, 3, 0] def custom_sqrt(num): for i in range(len(test_cases)): if test_cases[i] >= 0: return math.sqrt(test_cases[i]) else: return 0 for i in range(len(test_cases)): if custom_sqrt(test_cases[i]) != test_case_answers[i]: print "Test Case #", i, "failed!" custom_sqrt(test_cases)

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  • Where does the 'method' implementation go? (I'm a newbie)

    - by Spokane-Dude
    I have this code: #import "SQLiteDB.h" @implementation SQLiteDB @synthesize db, dbPath, databaseKey; @end //-------------- check for database or create it ----------------| - (void)checkForDatabase { NSFileManager *filemanager = [NSFileManager defaultManager]; NSString *databasePath = [[NSSearchPathForDirectoriesInDomains(NSDocumentDirectory, NSUserDomainMask, YES) objectAtIndex:0] stringByAppendingString:@"/ppcipher.s3db"]; if(![filemanager fileExistsAtPath:databasePath]) { //Database doesn't exist yet, so we create it... NSString *defaultDBPath = [[[NSBundle mainBundle] resourcePath] stringByAppendingString:@"/ppcipher.s3db"]; sqlite3 *db; if(sqlite3_open(databasePath, db) == SQLITE_OK) { } } } It's complaining that "method definition not in @implementation context". So where does it go? (I tried in the .h file, but still get the error)

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  • Styling a comment box to appear below dynamically-generated comments

    - by John
    Hello, For the code below, how could I make the form always appear 30 pixels below the bottom of the HTML table styled with "commentecho"? Thanks in advance, John $sqlStr = "SELECT comment.comment, comment.datecommented, login.username FROM comment LEFT JOIN login ON comment.loginid=login.loginid WHERE submissionid=$submissionid ORDER BY comment.datecommented DESC LIMIT 100"; $result = mysql_query($sqlStr); $arr = array(); echo "<table class=\"commentecho\">"; while ($row = mysql_fetch_array($result)) { echo '<tr>'; echo '<td class="commentname1">'.$row["comment"].'</td>'; echo '</tr>'; echo '<tr>'; echo '<td class="commentname2"><a href="http://www...com/sandbox/members/index.php?profile='.$row["username"].'">'.$row["username"].'</a>'.date('l, F j, Y &\nb\sp &\nb\sp g:i a &\nb\sp &\nb\sp \N\E\W &\nb\sp \Y\O\R\K &\nb\sp \T\I\M\E', strtotime($row["datecommented"])).'</td>'; echo '</tr>'; } echo "</table>"; echo '<form action="http://www...com/sandbox/comments/comments2.php" method="post"> <input type="hidden" value="'.$_SESSION['loginid'].'" name="uid"> <input type="hidden" value="'.$submissionid.'" name="submissionid"> <input type="hidden" value="'.$submission.'" name="submission"> <label class="addacomment" for="title">Add a comment:</label> <input class="commentsubfield" name="comment" type="comment" id="comment" maxlength="1000"> <div class="commentsubbutton"><input name="submit" type="submit" value="Submit"></div> </form> ';

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  • using a JOIN in an UPDATE in SQL

    - by SDLFunTimes
    Hi, I'm having trouble formulating a legal statement to double the statuses of the suppliers (s) who have shipped (sp) more than 500 units. I've been trying: update s set s.status = s.status * 2 from s join sp on (sp.sno = s.sno) group by sno having sum(qty) > 500; however I'm getting this error from Mysql: ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'from s join sp on (sp.sno = s.sno) group by sno having sum(qty) > 500' at line 1 Does anyone have any ideas about what is wrong with this query? Here's my schema: create table s ( sno char(5) not null, sname char(20) not null, status smallint, city char(15), primary key (sno) ); create table p ( pno char(6) not null, pname char(20) not null, color char(6), weight smallint, city char(15), primary key (pno) ); create table sp ( sno char(5) not null, pno char(6) not null, qty integer not null, primary key (sno, pno) );

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  • How to configure outgoing connections from an SQL stored procedure?

    - by Peter Vestberg
    I am working on a .NET project which uses Microsoft SQL server. In this project, I need a CLR stored procedure (written in C#) that uses a remote web service. So, when the stored procedure is executed on the SQL server, it makes web service calls and thus sends packets to a remote location. The problem is that when executing the SP I get: "System.Net.WebException: The request failed with HTTP status 403: Forbidden." The database user has full permission, the deployed CLR assembly and SP are even marked "unsafe", I tried signing it etc., so any of that is not causing the problem. When I am executing the very same C# code, but from a simple console application instead of as a SP, it all works fine. So I started to suspect a network related problem and had a packet sniffer running when executing both the SP and the console app version. What I realized was that the packets sent out had different destination IP addresses: the console app sent the packets directly to the web service IP while the SP sent the packets to a proxy server we use in our company. Due to network policies the latter is not allowed and that explains the "403 Forbidden" exception. So my question boils down to this: How can I configure the SP/MS SQL server to NOT use that proxy? I want it to send the packets directly to the web service IP, just like the test console app. (again, the C# code is the same , so it's not a programming matter). I've disabled all proxy settings in Internet Explorer in case the SQL server inherits these settings or something. However, no luck. Any help would be greatly appreciated! Best regards, Peter

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  • Numerating Comments

    - by John
    The code below prints out all comments for a given "submissionid" in chronological order. How could I numerate these comments? (In other words, how do I print out a "1." next to the oldest comment, a "2." next to the second-oldest comment, etc.?) $submission = mysql_real_escape_string($_GET['submission']); $submissionid = mysql_real_escape_string($_GET['submissionid']); $sqlStr = "SELECT comment.comment, comment.datecommented, login.username FROM comment LEFT JOIN login ON comment.loginid=login.loginid WHERE submissionid=$submissionid ORDER BY comment.datecommented ASC LIMIT 100"; $result = mysql_query($sqlStr); $arr = array(); echo "<table class=\"commentecho\">"; while ($row = mysql_fetch_array($result)) { echo '<tr>'; echo '<td class="commentname1">'.stripslashes($row["comment"]).'</td>'; echo '</tr>'; echo '<tr>'; echo '<td class="commentname2"><a href="http://www...com/sandbox/members/index.php?profile='.$row["username"].'">'.$row["username"].'</a>'.date('l, F j, Y &\nb\sp &\nb\sp g:i a &\nb\sp &\nb\sp \N\E\W &\nb\sp \Y\O\R\K &\nb\sp \T\I\M\E', strtotime($row["datecommented"])).'</td>'; echo '</tr>'; } echo "</table>"

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