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  • Django query get recent record for each entry and display as combined list

    - by gtujan
    I have two models device and log setup as such: class device(models.Model): name = models.CharField(max_length=20) code = models.CharField(max_length=10) description = models.TextField() class log(model.Model): device = models.ForeignKey(device) date = models.DateField() time = models.TimeField() data = models.CharField(max_length=50) how do I get a list which contains only the most recent record/log (based on time and date) for each device and combine them in the format below: name,code,date,time,data being a Django newbie I would like to implement this using Django's ORM. TIA!

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  • Django json serialization problem

    - by codingJoe
    I am having difficulty serializing a django object. The problem is that there are foreign keys. I want the serialization to have data from the referenced object, not just the index. For example, I would like the sponsor data field to say "sponsor.last_name, sponsor.first_name" rather than "13". How can I fix my serialization? json data: {"totalCount":"2","activities":[{"pk": 1, "model": "app.activity", "fields": {"activity_date": "2010-12-20", "description": "my activity", "sponsor": 13, "location": 1, .... model code: class Activity(models.Model): activity_date = models.DateField() description = models.CharField(max_length=200) sponsor = models.ForeignKey(Sponsor) location = models.ForeignKey(Location) class Sponsor(models.Model): last_name = models.CharField(max_length=20) first_name= models.CharField(max_length=20) specialty = models.CharField(max_length=100) class Location(models.Model): location_num = models.IntegerField(primary_key=True) location_name = models.CharField(max_length=100) def activityJSON(request): activities = Activity.objects.all() total = activities.count() activities_json = serializers.serialize("json", activities) data = "{\"totalCount\":\"%s\",\"activities\":%s}" % (total, activities_json) return HttpResponse(data, mimetype="application/json")

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  • Djangoo Foreign key queries

    - by Hulk
    In the following model: class header(models.Model): title = models.CharField(max_length = 255) created_by = models.CharField(max_length = 255) def __unicode__(self): return self.id() class criteria(models.Model): details = models.CharField(max_length = 255) headerid = models.ForeignKey(header) def __unicode__(self): return self.id() class options(models.Model): opt_details = models.CharField(max_length = 255) headerid = models.ForeignKey(header) def __unicode__(self): return self.id() If there is a row in the database for table header as Id=1, title=value-mart , createdby=CEO How do i query criteria and options tables to get all the values related to header table id=1 Also can some one please suggest a good link for queries examples, Thanks..

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  • Uninstall Rails 3 with dependencies?

    - by Trevor Burnham
    I like that Rails 3 is so easy to install: gem install rails --pre, and all of the dependencies are automatically installed for you. But, what about uninstalling it? If I just do gem uninstall rails, I still have actionmailer (3.0.0.beta3) actionpack (3.0.0.beta3) activemodel (3.0.0.beta3) activerecord (3.0.0.beta3) activeresource (3.0.0.beta3) activesupport (3.0.0.beta3) which I want to get rid of. What's the easiest way to do so?

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  • How to access image folder in django

    - by anc1revv
    I just started django and i want to access images uploaded by a user. here is my model: class Food(models.Model): name = models.CharField(max_length=100) price = models.DecimalField(max_digits=4, decimal_places=2) quantity = models.IntegerField(blank=True, null=True) description = models.CharField(max_length=200) location = models.CharField(max_length=100) time = models.DateTimeField() photo_thumbnail = models.ImageField(upload_to="images") photo_fullsize = models.ImageField(upload_to="images") i stored the image in the "images" folder below the html is this: img src="{{steak.photo_thumbnail}}" and steak.photo_thumbnail = images/steak_and_egg_thumbnail_1.png here is the error i get: [06/Jul/2012 19:08:24] "GET /menu/ HTTP/1.1" 200 99 [06/Jul/2012 19:08:24] "GET /menu/images/steak_and_egg_thumbnail_1.png HTTP/1.1" 404 2127

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  • Django. Invalid keyword argument for this function. ManyToMany

    - by sagem_tetra
    I have this error: 'people' is an invalid keyword argument for this function class Passage(models.Model): name= models.CharField(max_length = 255) who = models.ForeignKey(UserProfil) class UserPassage(models.Model): passage = models.ForeignKey(Passage) people = models.ManyToManyField(UserProfil, null=True) class UserProfil(models.Model): user = models.OneToOneField(User) name = models.CharField(max_length=50) I try: def join(request): user = request.user user_profil = UserProfil.objects.get(user=user) passage = Passage.objects.get(id=2) #line with error up = UserPassage.objects.create(people= user_profil, passage=passage) return render_to_response('thanks.html') How to do correctly? Thanks!

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  • How to override 'where' in rails 3

    - by Zakwan Alhajjar
    I have upgraded my application from rails 2.3.8 to 3.0.3 . But I'm facing a problem. I was using 'find' but the overriding doesn't work in rails 3: # override activerecord's find to allow us to find by name or id transparently def self.find(*args) if args.is_a?(Array) and args.first.is_a?(String) and (args.first.index(/[a-zA-Z\-_]+/) or args.first.to_i.eql?(0) ) find_by_login_slug(args) else super end end I'm wondering if there is a way to make this work in rails 3 or even by using where instead. thanks

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  • Are all View Models supposed to be accessed through the Main View Model in MVVM?

    - by chustar
    I am currently working on a WP8 application. My current design is to have each view bind against a specific view model directly. Looking through the samples though, it seems that another way is to have all the view models accessed through the Main View Model and then have all the views to their view models through the MVM. Is this the correct way to do it (So that it doesn't cause flexibility and other issues in the future)?

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  • Django 1.2 + South 0.7 + django-annoying's AutoOneToOneField leads to TypeError: 'LegacyConnection'

    - by konrad
    I'm using Django 1.2 trunk with South 0.7 and an AutoOneToOneField copied from django-annoying. South complained that the field does not have rules defined and the new version of South no longer has an automatic field type parser. So I read the South documentation and wrote the following definition (basically an exact copy of the OneToOneField rules): rules = [ ( (AutoOneToOneField), [], { "to": ["rel.to", {}], "to_field": ["rel.field_name", {"default_attr": "rel.to._meta.pk.name"}], "related_name": ["rel.related_name", {"default": None}], "db_index": ["db_index", {"default": True}], }, ) ] from south.modelsinspector import add_introspection_rules add_introspection_rules(rules, ["^myapp"]) Now South raises the following error when I do a schemamigration. Traceback (most recent call last): File "manage.py", line 11, in <module> execute_manager(settings) File "django/core/management/__init__.py", line 438, in execute_manager utility.execute() File "django/core/management/__init__.py", line 379, in execute self.fetch_command(subcommand).run_from_argv(self.argv) File "django/core/management/base.py", line 196, in run_from_argv self.execute(*args, **options.__dict__) File "django/core/management/base.py", line 223, in execute output = self.handle(*args, **options) File "South-0.7-py2.6.egg/south/management/commands/schemamigration.py", line 92, in handle (k, v) for k, v in freezer.freeze_apps([migrations.app_label()]).items() File "South-0.7-py2.6.egg/south/creator/freezer.py", line 33, in freeze_apps model_defs[model_key(model)] = prep_for_freeze(model) File "South-0.7-py2.6.egg/south/creator/freezer.py", line 65, in prep_for_freeze fields = modelsinspector.get_model_fields(model, m2m=True) File "South-0.7-py2.6.egg/south/modelsinspector.py", line 322, in get_model_fields args, kwargs = introspector(field) File "South-0.7-py2.6.egg/south/modelsinspector.py", line 271, in introspector arg_defs, kwarg_defs = matching_details(field) File "South-0.7-py2.6.egg/south/modelsinspector.py", line 187, in matching_details if any([isinstance(field, x) for x in classes]): TypeError: 'LegacyConnection' object is not iterable Is this related to a recent change in Django 1.2 trunk? How do I fix this? I use this field as follows: class Bar(models.Model): foo = AutoOneToOneField("foo.Foo", primary_key=True, related_name="bar") For reference the field code from django-tagging: class AutoSingleRelatedObjectDescriptor(SingleRelatedObjectDescriptor): def __get__(self, instance, instance_type=None): try: return super(AutoSingleRelatedObjectDescriptor, self).__get__(instance, instance_type) except self.related.model.DoesNotExist: obj = self.related.model(**{self.related.field.name: instance}) obj.save() return obj class AutoOneToOneField(OneToOneField): def contribute_to_related_class(self, cls, related): setattr(cls, related.get_accessor_name(), AutoSingleRelatedObjectDescriptor(related))

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  • Editing Django's admin index <div id='module'> tag

    - by zen
    I am new to the Django framework. On Django's admin index page I'd like to get rid of the "s" at the end of my model names. Example: <div class="module"> <table summary="Models available in the my application."> <caption><a href="" class="section">My application</a></caption> <tr> <th scope="row"><a href="model/">Model**s**</a></th> <td><a href="model/add/" class="addlink">Add</a></td> <td><a href="model/" class="changelink">Change</a></td> </tr> </table> </div> I know of a way to do this but I am really looking for the file I should edit. Where is it and what exactly should I do? I can't seem to pinpoint where it is coming from.

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  • Django Querying Relation of Relation

    - by Brent
    I'm stuck on a Django ORM issue that is bugging me. I have a set of models linked by a foreign key but the requirements are a bit odd. I need to list items by their relation's relation. This is hard to explain so I've tried to depict this below, given: Work ManyToMany(Award) Award ForeignKey(AwardCategory) AwardCategory I need to list work items so they are listed by the award category. Desired output would be: Work Instance A Award Instance A that belongs to Award Category Instance A Award Instance C that belongs to Award Category Instance A Award Instance G that belongs to Award Category Instance A Work Instance A (same instance as above, but listed by different award__category) Award Instance F that belongs to Award Category Instance B Award Instance R that belongs to Award Category Instance B Award Instance Z that belongs to Award Category Instance B Work Instance B Award Instance B that belongs to Award Category Instance A Award Instance A that belongs to Award Category Instance A Essentially I want to list all work by the award category. I can get this to work in part but my solution is filthy and gross. I'm wondering if there is a better way. I considered using a ManyToMany and a through attribute but I'm not certain if I'm utilizing it correctly.

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  • Asynchronous daemon processing / ORM interaction with Django

    - by perrierism
    I'm looking for a way to do asynchronous data processing with a daemon that uses Django ORM. However, the ORM isn't thread-safe; it's not thread-safe to try to retrieve / modify django objects from within threads. So I'm wondering what the correct way to achieve asynchrony is? Basically what I need to accomplish is taking a list of users in the db, querying a third party api and then making updates to user-profile rows for those users. As a daemon or background process. Doing this in series per user is easy, but it takes too long to be at all scalable. If the daemon is retrieving and updating the users through the ORM, how do I achieve processing 10-20 users at a time? I would use a standard threading / queue system for this but you can't thread interactions like models.User.objects.get(id=foo) ... Django itself is an asynchronous processing system which makes asynchronous ORM calls(?) for each request, so there should be a way to do it? I haven't found anything in the documentation so far. Cheers

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  • user inheritance in django

    - by amateur
    Hi guys, I saw a couple of ways extending user information of users and decided to adopt the model inheritance method. for instance, I have : class Parent(User): contact_means = models.IntegerField() is_staff = False objects = userManager() Now it is done, I've downloaded django_registration to help me out with sending emails to new users. The thing is, instead of using registration forms to register new user, I want to to invoke the email sending/acitvation capability of django_registration. So my workflow is: 1. add new Parent object in admin page. 2. send email My problem is, the django-registration creates a new registration profile together with a new user in the user table. how do I tweak this such that I am able to add the user entry into the custom user table. I have tried to create a modelAdmin and alter the save_model method to launch the create_inactive_user from django_registration, however I do not how to save the user object generated from django_registration into my Parent table when I have using model inheritance and I do not have a Foreign key attribute in my parent model.

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  • Ruby number_to_currency displays a totally wrong number!

    - by SueP
    Greetings! I’m an old Delphi programmer making the leap to the Mac, Ruby, Rails, and web programming in general. I’m signed up for the Advanced Rails workshop at the end of the month. In the meantime, I’ve been working on porting a mission-critical (of course) app from Delphi to RAILS. It feels like I’ve spent most of the past year with my head buried in a book or podcast. Right now, I’ve hit a major issue and I’m tearing my hair out. I literally don’t know where to go with this, I desperately don’t want to deploy with this bug, and I’m feeling a bit frantic. (The company database is currently running on an ancient XP box that’s looking rustier by the day.) So, I set up a test database that shows the problem. I’m running: OS/X 10.6.3 Rails 2.3.5 ruby 1.8.7 (2009-06-08 patchlevel 173) [universal-darwin10.0] MySQL 5.1.38-log via socket MySQL Client Version 5.1.8 ActiveRecord::Schema.define(:version => 20100406222528) do create_table “money”, :force => true do |t| t.decimal “amount_due”, :precision => 10, :scale => 2, :default => 0.0 t.decimal “balance”, :precision => 10, :scale => 2, :default => 0.0 t.text “memofield” t.datetime “created_at” t.datetime “updated_at” end The index view is right out of the generator, slightly modified to add the formatting that's breaking on me. Listing money <table> <tr> <th>Amount</th> <th>Amount to_s </th> <th>Balance to $</th> <th>Balance with_precision </th> <th>Memofield</th> </tr> <% @money.each do |money| %> <tr> <td><%=h money.amount_due %></td> <td><%=h money.amount_due.to_s(‘F’) %></td> <td><%=h number_to_currency(money.balance) %></td> <td><%=h number_with_precision(money.balance, :precision => 2) %></td> <td><%=h money.memofield %></td> <td><%= link_to ‘Show’, money %></td> <td><%= link_to ‘Edit’, edit_money_path(money) %></td> <td><%= link_to ‘Destroy’, money, :confirm => ‘Are you sure?’, :method => :delete %></td> </tr> *<% end %> *</table> <%= link_to ‘New money’, new_money_path %> This seemed to work pretty well. Then I started testing with production data and hit a major problem with number_to_currency. The number in the database is: 10542.28, I verified it with the MySQL Query Browser. RAILS will display this as 10542.28 unless I call number_to_currency, then that number is displayed as: $15422.80 The error seems to happen with any number between 10,000.00 and 10,999.99 So far, I haven’t seen it outside of that range, but I obviously haven’t tested everything. I guess my workaround is to remove number_to_currency, but that leaves the views looking really sloppy and unprofessional. The formatting is messed up, things don’t line up properly and I can’t force the display to 2 decimal places. I’m seriously hoping there is an easy fix for this. I can’t imagine this being a widespread problem. It would affect so many people that someone would have fixed it! But I don’t know where to go from here. I’d desperately like some help. (Later – number_with_precision fails the same way number_to_currency does.) Sue Petersen

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  • django: results in in_bulk style without IDs

    - by valya
    in django 1.1.1, Place.objects.in_bulk() does not work and Place.objects.in_bulk(range(1, 100)) works and returns a dictionary of Ints to Places with indexes - primary keys. How to avoid using range in this situation (and avoid using a special query for ids, I just want to get all objects in this dictionary format) >>> Place.objects.in_bulk() Traceback (most recent call last): File "<console>", line 1, in <module> File "/usr/lib/python2.5/site-packages/Django-1.1.1-py2.5.egg/django/db/models/manager.py", line 144, in in_bulk return self.get_query_set().in_bulk(*args, **kwargs) TypeError: in_bulk() takes exactly 2 arguments (1 given) >>> Place.objects.in_bulk(range(1, 100)) {1L: <Place: "??? ????">, 3L: <Place: "???????????? ?????">, 4L: <Place: "????????? "??????"">, 5L: <Place: "????????? "??????"">, 8L: <Place: "????????? "??????????????"">, 9L: <Place: "??????? ????????">, 10L: <Place: "????????? ???????">, 11L: <Place: "??????????????? ???">, 14L: <Place: "????? ????? ??????">}

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  • Django Datetime field question

    - by Shehzad009
    Hello I have been having a problem with django while trying to work with datetime. In my webapp I have a table like so when I run server. ID Owing 1 -100 (All the same value) 2 -100 3 -100 . . . . . . It has in one column Invoice id and the other owing. One-one relationship as well. sow for example owing value for 1 is 100. Unfortunately, this is where it all goes wrong because throughout column (Owing), it is giving me the owing value for ID=1. I want each ID to give me their owing value. Here is my view. I also wonder if I may need a for loop somewhere as well. def homepage(request): invoices_list = Invoice.objects.all() invoice_name = invoices_list[0].client_contract_number.client_number.name invoice_gross = invoices_list[0].invoice_gross payment_date = invoices_list[0].payment_date if payment_date <= datetime.now(): owing = invoice_gross if payment_date > datetime.now(): owing = 0 else: owing= 0 return render_to_response(('index.html', locals()), {'invoices_list': invoices_list ,'invoice_number':invoice_number, 'invoice_name':invoice_name, 'invoice_gross':invoice_gross, 'payment_date':payment_date, 'owing': owing}, context_instance=RequestContext(request)) EDIT: Here is my template. The thing is the function owing is not in my models so saying {{invoices.owing}} wont work. {% for invoices in invoices_list %} <tr> <td>{{invoices.invoice_number}}</td> <td>{{invoices.invoice_contact}}</td> <td>{{invoices.client_contract_number}}</td> <td>{{invoices.payment_date|date:"d M Y"}}</td> <td>{{invoices.invoice_gross}}</td> <td>{{owing}}</td> {% endfor %}

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  • Connecting a django application to a drupal database?

    - by Hans
    I have a 3 - 4000 nodes in a drupal 6 installation on mysql and want to access these data through my django application. I have used manage.py inspectdb to get a skeleton of a model structure. I guess that there are good/historical reasons for drupal's database schemes, but find that there are some hard to understand structure and that there are some challenges in applying django models on the database. Some experiences this far are: node and node revision are intertwined and I solved this by using a OneToOneField (don't need the versions). This meens that the node's body gets accessible through node.vid.body, but it works. Foreign keys need to define the proper db_column to sort out the primary keys. Terms need to use an intermediary table with ManyToManyField.through. Drupal stores both the original and the thumbnailed/resized versions of any image as files in the files table. Does anyone have experiences in accessing drupal data in django? Are there better solution to for example the node <- node revision relationship? Drupal stores time/dates as unix-style timestamps in integerfields. Any recommendations? How about time zones?

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  • How to install libv8 using a specific version of g++?

    - by Catfish
    I'm trying to install therubyracer gem for a rails project - http://stackoverflow.com/questions/13793533/unable-to-install-therubyracer-on-centos-errors-with-v8-and-gcc and i'm thinking that now that i installed g++44, that all i need to do is get gem install libv8 to use g++44 instead of g++. Is there a way to run gem install libv8 and to have it look at my updated g++ version? Or is there a way to set the default g++ to the g++44 location? some helpful output [root@allthingswebdesign current]# which g++ /usr/bin/g++ [root@allthingswebdesign current]# which g++44 /usr/bin/g++44 [root@allthingswebdesign current]# [root@allthingswebdesign current]# cd /usr/bin/ [root@allthingswebdesign bin]# ls -al g++* -rwxr-xr-x 4 root root 218432 May 10 2012 g++ -rwxr-xr-x 2 root root 263704 Feb 21 2012 g++44 lrwxrwxrwx 1 root root 12 Dec 9 17:21 g++-4.4 -> /usr/bin/g++

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  • Can I shorten my directory commands in ubuntu?

    - by Spencer Cooley
    When working on a rails app I like to open all of my files through the command line like so cd my_app gedit app/views/user/show.html.erb Is there a way that I could shorten this so that I could just write something like gedit user_views/show.html.erb ? I would like the console to stay in the main directory, I just don't like having to type out app/controller/user_controler.rb every time I want to open the user controller. I know that I could just open the file with my mouse, but I feel like moving from keyboard to mouse breaks my focus a little bit. When I can just tap away at the keyboard it seems like I have a more smooth workflow.

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  • Mysql out of disk space

    - by Paddy
    I have just finished developing a rails app which has a mysql db as a backend. The app is meant for high traffic and will store lots of information. I am planning to set up my own web server and host the site from it. If in future my disk space runs out i would want to expand by adding more space. But say if my mysql database is housed in my /disk0s1 and by adding a new drive i have more partitions (and hence more disk space), how then would i extend my database to store information on those partitions too, and at the same time prevent any information from being written on the original partition. Should i go for multiple databases? if so how? If i went for a hosting solution i wouldn't be bothering about this as i would just have to worry about making payments for the extra space :) I always wondered how space is added on-the-go by these webhosts. Is there any specific mysql configuration that i have to make?

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  • Redirect folder to different server

    - by yuval
    Just for clarity, I already posted this on StackOverflow and got advice that this better fits in ServerFault.com so here goes: I know you can redirect subdomains to a different server, but can you do the same with folders? Say I have example.com. I can redirect mysubdomain.example.com to a different server, but can I redirect example.com/mysubdomain to a different server? I'd like to host a rails app in that folder on a site that runs php while still maintaining good search engines ratings (by not creating a sub domain which in my experience in recognized as a different site). Any help? Thanks!

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  • SASL (Postfix) authentication with MySQL and Blowfish pre-encrypted passwords

    - by webo
    I have a Rails app with the Devise authentication gem running user registration and login. I want to use the db table that Devise populates when a user registers as the table that Postfix uses to authenticate users. The table has all the fields that Postfix may want for SASL authentication except that Devise encrypts the password using Blowfish before placing it in the database. How could I go about getting Postfix/SASL to decrypt those passwords so that the user can be authenticated properly? Devise salts the password so I'm not sure if that helps. Any suggestions? I'd likely want to do something similar with Dovecot or Courier, I'm not attached to one quite yet.

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  • Nginx & Passenger - failed (11: Resource temporarily unavailable) while connecting to upstream

    - by Toby Hede
    I have an Nginx and Passenger setup that is proving problematic. At relatively low loads the server seems to get backed up and start churning results like this into the error.log: connect() to unix:/passenger_helper_server failed (11: Resource temporarily unavailable) while connecting to upstream My passenger setup is: passenger_min_instances 2; passenger_pool_idle_time 1200; passenger_max_pool_size 20; I have done some digging, and it looks like the CPU gets pegged. Memory usage seems fine passenger_memory_stats shows at most about 700MB being used, but CPU approaches 100%. is this enough to cause this type of error? Should i bring the pool size down? Are there other configuration settings I should be looking at? Any help appreciated Other pertinent information: Amazon EC2 Small Instance Ubuntu 10.10 Nginx (latest stable) Passenger (latest stable) Rails 3.0.4

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  • Ignoring GET parameters in Varnish VCL

    - by JamesHarrison
    Okay: I've got a site set up which has some APIs we expose to developers, which are in the format /api/item.xml?type_ids=34,35,37&region_ids=1000002,1000003&key=SOMERANDOMALPHANUM In this URI, type_ids is always set, region_ids and key are optional. The important thing to note is that the key variable does not affect the content of the response. It is used for internal tracking of requests so we can identify people who make slow or otherwise unwanted requests. In Varnish, we have a VCL like this: if (req.http.host ~ "the-site-in-question.com") { if (req.url ~ "^/api/.+\.xml") { unset req.http.cookie; } } We just strip cookies out and let the backend do the rest as far as times are concerned (this is a hackaround since Rails/authlogic sends session cookies with API responses). At present though, any distinct developers are basically hitting different caches since &key=SOMEALPHANUM is considered as part of the Varnish hash for storage. This is obviously not a great solution and I'm trying to work out how to tell Varnish to ignore that part of the URI.

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  • Passenger apache default page error

    - by gshankar
    I just installed Passenger and the Passenger Pref Pane on OSX. However, when I try to browse to one of my Rails applications I just get the default Apache "it works!" page. I've checked the vhost definitions and they seem ok so I can't seem to figure out whats wrong... I've tried reinstalling passenger and the pref pane and restarting apache but to no avail. Anyone know how to fix this? My vhost definition looks like this: <VirtualHost *:80> ServerName boilinghot.local DocumentRoot "/Users/ganesh/Code/boilinghot/public" RailsEnv development <Directory "/Users/ganesh/Code/boilinghot/public"> Order allow,deny Allow from all </Directory> </VirtualHost>

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