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• Lighttpd not starting - no error

  - by Furism

  I recently installed Lighttpd on Ubuntu Server 10.04 x86_64 and created several websites. What I do is include /etc/lighttpd/vhost.d/*.conf and put a configuration file for each website in that directory. The problem I have is when I "service lighttpd start" I get the message that the service started, there is no error message: root@178-33-104-210:~# service lighttpd start Syntax OK * Starting web server lighttpd [ OK ] But then if I take a look at the services listening, Lighttpd is nowhere to be seen: root@178-33-104-210:~# netstat -tap Active Internet connections (servers and established) Proto Recv-Q Send-Q Local Address Foreign Address State PID/Program name tcp 0 0 localhost:mysql *:* LISTEN 829/mysqld tcp 0 0 *:ftp *:* LISTEN 737/vsftpd tcp 0 0 *:ssh *:* LISTEN 739/sshd tcp6 0 0 [::]:ssh [::]:* LISTEN 739/sshd So I'm looking at ways I could troubleshoot this. I checked in /var/log/lighttpd/error.log and there's nothing in it. Edit: Sorry, I indicated I use CentOS but it's actually Ubuntu Server (I usually use CentOS but had to go with Ubuntu for that one).

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• Why does my iOS app crash when trying presentModalViewController?

  - by user555807

  I've been banging my head against this all day, it seems like something simple but I can't figure it out. I've got an iOS app that I created using the "View-based Application" template in XCode. Here is essentially the code I have: AppDelegate.h: #import <UIKit/UIKit.h> @interface AppDelegate : NSObject <UIApplicationDelegate> { UIWindow *window; MainViewController *viewController; } @property (nonatomic, retain) IBOutlet UIWindow *window; @property (nonatomic, retain) IBOutlet MainViewController *viewController; @end AppDelegate.m: #import "AppDelegate.h" #import "MainViewController.h" @implementation AppDelegate @synthesize window, viewController; - (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions { [self.window addSubview:viewController.view]; [self.window makeKeyAndVisible]; return YES; } - (void)dealloc { [viewController release]; [window release]; [super dealloc]; } @end MainViewController.h: #import <UIKit/UIKit.h> @interface MainViewController : UIViewController { } -(IBAction) button:(id)sender; @end MainViewController.m: #import "MainViewController.h" #import "ModalViewController.h" @implementation MainViewController ... -(IBAction) button:(id)sender { ModalViewController *mvc = [[[ModalViewController alloc] initWithNibName:NSStringFromClass([ModalViewController class]) bundle:nil] autorelease]; [self presentModalViewController:mvc animated:YES]; } @end There's nothing of interest in the ModalViewController. So the modal view should display when the button is pressed. When I press the button, it hangs for a second then crashes back to the home screen with no error message. I am stumped, please show me what I'm doing wrong!

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• UINaviagtionBar not displaying?

  - by Rajendra Bhole

  Hi, I developing an application in which initially choose UINavigationController based application. In rooViewController xib i added two more UIView, the code is written as follows. @implementation RootViewController @synthesize introductionView, WheelView; (void)viewDidLoad { [super viewDidLoad]; [self.navigationController setNavigationBarHidden:YES]; } pragma mark pragma mark strart up screen: -(void)startIntroductionScreen{ if(window == nil) { window = [[UIWindow alloc] initWithFrame:CGRectMake(0, 0, 320, 480)]; } [window addSubview: introductionView]; [window makeKeyAndVisible]; } -(void)WheelScreen{ [window addSubview:carnivalWheelView]; [window makeKeyAndVisible]; self.navigationController.navigationBar.hidden = NO; [self.navigationItem setLeftBarButtonItem:[[UIBarButtonItem alloc] initWithTitle:@"Setting" style:UIBarButtonItemStylePlain target:nil action:nil] animated:YES]; } pragma mark pragma mark IBAction: -(IBAction)breakGlass:(id)sender{ [self startIntroductionScreen]; } -(IBAction)anotherView:(id)sender{ [self WheelScreen]; } In above code, when the -(void)WheelScreen method on the IBAction anotherView of invoke the UINaviagtionBar is not displaying. Thank's in advance.

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• ASA 5505 Vlan question

  - by Wayne

  I am setting up a cisco asa 5505 with the base license. I can communicate from inside-outside, outside-inside, inside-home, which is my desired traffic security. I can get http, ssh, and other access from inside-home, but I can't ping from inside-home (192.168.110.0 host to 192.168.7.1 or 192.168.7.0 host). Can someone explain. My config is listed below interface Vlan1<br> nameif inside<br> security-level 100<br> ip address 192.168.110.254 255.255.255.0 <br> !<br> interface Vlan2<br> nameif outside<br> security-level 0<br> pppoe client vpdn group birdie<br> ip address removedIP 255.255.255.255 pppoe <br> !<br> interface Vlan3<br> no forward interface Vlan1<br> nameif home<br> security-level 50<br> ip address 192.168.7.1 255.255.255.0 <br> ! <br> interface Ethernet0/0<br> switchport access vlan 2<br> ! <br> interface Ethernet0/1<br> ! <br> interface Ethernet0/2<br> ! <br> interface Ethernet0/3<br> ! <br> interface Ethernet0/4<br> switchport access vlan 3<br> ! <br> interface Ethernet0/5<br> shutdown <br> ! <br> interface Ethernet0/6<br> shutdown <br> ! <br> interface Ethernet0/7<br> shutdown <br> ! <br> ftp mode passive<br> clock timezone EST -5<br> clock summer-time EDT recurring<br> access-list Outside-In extended permit icmp any any <br> access-list Outside-In extended permit tcp any any eq www <br> access-list Outside-In extended permit tcp any any eq https <br> access-list Outside-In extended permit tcp any any eq 5969 <br> access-list inside_nat0_outbound extended permit ip any 192.168.111.0 255.255.255.224 <br> access-list standardUser_splitTunnelAcl1 extended permit ip 192.168.111.0 255.255.255.0 any <br> access-list standardUser_splitTunnelAcl1 extended permit ip 192.168.110.0 255.255.255.0 <br>any access-list inside_in extended permit icmp any any <br> access-list inside_in extended permit ip any any <br> access-list home_in extended permit icmp any any <br> access-list home_in extended permit ip any any <br> pager lines 24<br> logging enable<br> logging asdm informational<br> mtu inside 1492<br> mtu outside 1492<br> mtu home 1500 <br> ip local pool vpnuser 192.168.111.5-192.168.111.20<br> icmp unreachable rate-limit 1 burst-size 1<br> asdm image disk0:/asdm-524.bin<br> no asdm history enable<br> arp timeout 14400<br> nat-control <br> global (outside) 1 interface<br> nat (inside) 0 access-list inside_nat0_outbound<br> nat (inside) 1 0.0.0.0 0.0.0.0<br> nat (home) 1 192.168.7.0 255.255.255.0<br> static (inside,outside) tcp interface https 192.168.110.6 https netmask 255.255.255.255 <br> static (inside,outside) tcp interface www 192.168.110.6 www netmask 255.255.255.255 <br> static (inside,outside) tcp interface 5969 192.168.110.12 5969 netmask 255.255.255.255 <br> static (inside,home) 192.168.110.0 192.168.110.0 netmask 255.255.255.0 <br> access-group inside_in in interface inside<br> access-group Outside-In in interface outside<br> access-group home_in in interface home<br> route outside 0.0.0.0 0.0.0.0 RemovedIP 1<br>

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• how do I zoom to normal text size in vs2008?

  - by gerryLowry

  I can not find any help on this issue in vs2008 help, Google, or SO. Scenario: I'm looking at a source file in vs2008 SP1; Windows 2003 Server SP2 Standard Edition, 1280x1024. The irrelevant name of this file is index.aspx. What is relevant is that the file has only 65 lines of code. The print is unreadably small--less than 4 point. It uses less than a third of the vs2008 text window vertically and less that a quarter of the vs2008 text window horizontally. It's not just index.aspx; e.g. another file with 142 lines only fills about 3/4 of the vs2008 text window vertically and less that a quarter of the vs2008 text window horizontally. Possible cause: Probably, but not certainly, I found the equivalent of zoom in/zoom out such as one finds in products like Microsoft Word. However, I've explored many vs2008 toolbars and other customization options and unfortunately I can not find out how to get myself out of this mess. Window, Reset Window Layout has no effect on the text size; my tiny text size did not change. QUESTION: how do I zoom vs2008 text size in and out and back to normal size? Thank you. Regards ~~ Gerry (Lowry)

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• DB auto failover in c# does not work when the principal server physically goes offline

  - by user62521

  I'm setting up DB auto failover in C# with SQL Server 2008 and I have a 'high safety with automatic failover mirror' using a witness setup and my connection string looks like "Server=tcp:DC01; Failover Partner=tcp:DC02; database=dbname; uid=sewebsite;pwd=somerndpwd;Connect Timeout=10;Pooling=True;" During testing, when I turn off the SQL Server service on the principal server the auto failover works like a charm, but if I take the principal server offline (by shutting down the server or killing the network card) auto failover does not work and my website just times out. I found this article where the second last post suggests that its because we are using named pipes which does not work when the principal goes offline, but we force TCP in our connection string. What am I missing to get this DB auto failover working?

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• VirtualBox Port Fowarding to Connect to PostgreSQL Database

  - by kliao

  I'm trying to connect to a PostgreSQL database hosted on a Win7 guest from a Win7 host. I've configured security in pg_hba.conf host all all 127.0.0.1/32 md5 host all all 10.0.2.15/32 md5 host all all 192.168.1.6/32 md5 and set the listen_addresses setting in postgresql.conf to '*'. I think I've set up port forwarding correctly as I see: Key: VBoxInternal/Devices/e1000/0/LUN#0/Config/win7_vm1/GuestPort, Value: 5432 Key: VBoxInternal/Devices/e1000/0/LUN#0/Config/win7_vm1/HostPort, Value: 5432 Key: VBoxInternal/Devices/e1000/0/LUN#0/Config/win7_vm1/Protocol, Value: TCP when I call getextradata. This is similar to http://serverfault.com/questions/106168/cant-connect-to-postgresql-on-virtualbox-guest but I'm not sure what I'm doing wrong. In the vbox.log file I see: 00:00:01.019 NAT: set redirect TCP host port 5432 = guest port 5432 @ 10.0.2.15 00:00:01.033 NAT: failed to redirect TCP 5432 = 5432 but I'm not sure how to fix that. Any ideas? Thanks.

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• Amazon EC2 - Unable to connect to MySQL

  - by alexus

  I'm having issue connecting from one VM to another # nmap -p3306 ip-XX-XX-XX-XX.ec2.internal Starting Nmap 6.40 ( http://nmap.org ) at 2014-06-10 17:50 EDT Nmap scan report for ip-XX-XX-XX-XX.ec2.internal (XX.XX.XX.XX) Host is up (0.000033s latency). PORT STATE SERVICE 3306/tcp closed mysql Nmap done: 1 IP address (1 host up) scanned in 1.05 seconds # in my Security Group I allowed Inbound connectivity via port TCP, portrange 3306 and Source 0.0.0.0/0, so theoratically it should work, but in reality it doesn't( I'm running red hat enterprise linux 7 on both VMs. mariadb.service running fine on another VM and I am able to connect to it locally. DB's: # netstat -anp | grep 3306 tcp 0 0 0.0.0.0:3306 0.0.0.0:* LISTEN 2324/mysqld # iptables -L Chain INPUT (policy ACCEPT) target prot opt source destination Chain FORWARD (policy ACCEPT) target prot opt source destination Chain OUTPUT (policy ACCEPT) target prot opt source destination # Any ideas what else I missed?

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• Hp Procurve Switch : port filtered

  - by user117140

  My HP Procurve switch is blocking port 22 and I dont know how to unblock it.Please let me know From the server, see port 22 is blocked [root@server ~]#nmap -p22,80,443 10.247.172.70 Starting Nmap 4.11 ( http://www.insecure.org/nmap/ ) at 2012-04-16 14:12 IST mass_dns: warning: Unable to determine any DNS servers. Reverse DNS is disabled. Try using --system-dns or specify valid servers with --dns_servers Interesting ports on 10.247.172.70: PORT STATE SERVICE 22/tcp filtered ssh ------------------> see 80/tcp filtered http 443/tcp filtered https This is blocked on cisco switch but I dont have any clue how this is done. I know that vlan is configured on switch. vlan 54 ip ospf 10.247.172.65 area 0.0.0.10 vrrp vrid 54 owner virtual-ip-address 10.247.172.65 255.255.255.192 priority 255 enable exit exit Please let me know how to unblock ssh port 22 access on this switch?

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• Can't add to NSMutableArray from SecondaryView

  - by Antonio

  Hi guys, I've searched and read and still haven't found a concrete answer. Brief: I have an application where I declare an NSMutableArray in my AppDelegate to synthesize when the application loads. (code below). I have a SecondaryViewController call this function, and I have it output a string to let me know what the array size is. Every time I run it, it executes but it does not add any objects to the array. How do I fix this? AppDelegate.h file #import <UIKit/UIKit.h> @class arrayTestViewController; @interface arrayTestAppDelegate : NSObject <UIApplicationDelegate> { UIWindow *window; arrayTestViewController *viewController; NSMutableArray *myArray3; } @property (nonatomic, retain) NSMutableArray *myArray3; @property (nonatomic, retain) IBOutlet UIWindow *window; @property (nonatomic, retain) IBOutlet arrayTestViewController *viewController; -(void)addToArray3; @end AppDelegate.m file #import "arrayTestAppDelegate.h" #import "arrayTestViewController.h" @implementation arrayTestAppDelegate @synthesize window; @synthesize viewController; @synthesize myArray3; #pragma mark - #pragma mark Application lifecycle - (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions { myArray3 = [[NSMutableArray alloc] init]; // Override point for customization after application launch. // Add the view controller's view to the window and display. [window addSubview:viewController.view]; [window makeKeyAndVisible]; return YES; } -(void)addToArray3{ NSLog(@"Array Count: %d", [myArray3 count]); [myArray3 addObject:@"Test"]; NSLog(@"Array triggered from SecondViewController"); NSLog(@"Array Count: %d", [myArray3 count]); } SecondViewController.m file #import "SecondViewController.h" #import "arrayTestAppDelegate.h" @implementation SecondViewController -(IBAction)addToArray{ arrayTestAppDelegate *object = [[arrayTestAppDelegate alloc] init]; [object addToArray3]; }

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• How to repeatedly show a Dialog with PyGTK / Gtkbuilder?

  - by Julian

  I have created a PyGTK application that shows a Dialog when the user presses a button. The dialog is loaded in my __init__ method with: builder = gtk.Builder() builder.add_from_file("filename") builder.connect_signals(self) self.myDialog = builder.get_object("dialog_name") In the event handler, the dialog is shown with the command self.myDialog.run(), but this only works once, because after run() the dialog is automatically destroyed. If I click the button a second time, the application crashes. I read that there is a way to use show() instead of run() where the dialog is not destroyed, but I feel like this is not the right way for me because I would like the dialog to behave modally and to return control to the code only after the user has closed it. Is there a simple way to repeatedly show a dialog using the run() method using gtkbuilder? I tried reloading the whole dialog using the gtkbuilder, but that did not really seem to work, the dialog was missing all child elements (and I would prefer to have to use the builder only once, at the beginning of the program). [SOLUTION] As pointed out by the answer below, using hide() does the trick. But one has to take care that the dialog is in fact destroyed if one does not catch its "delete-event". A simple example that works is: import pygtk import gtk class DialogTest: def rundialog(self, widget, data=None): self.dia.show_all() result = self.dia.run() def destroy(self, widget, data=None): gtk.main_quit() def closedialog(self, widget, data=None): self.dia.hide() return True def __init__(self): self.window = gtk.Window(gtk.WINDOW_TOPLEVEL) self.window.connect("destroy", self.destroy) self.dia = gtk.Dialog('TEST DIALOG', self.window, gtk.DIALOG_MODAL | gtk.DIALOG_DESTROY_WITH_PARENT) self.dia.vbox.pack_start(gtk.Label('This is just a Test')) self.dia.connect("delete-event", self.closedialog) self.button = gtk.Button("Run Dialog") self.button.connect("clicked", self.rundialog, None) self.window.add(self.button) self.button.show() self.window.show() if __name__ == "__main__": testApp = DialogTest() gtk.main()

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• Javascript and jQuery (Fancybox) question

  - by songdogtech

  Javascript and jQuery (Fancybox) question I'm using the Javascript function below for Twitter sharing (as well as other services; the function code is simplified to just Twitter for this question) that grabs the to-be-shared page URL and title and it is invoked in the link with onclick. That results in the Twitter share page loading in a pop up browser window, i.e.<img src="/images/twitter_16.png" onclick="share.tw()" /> In order to be consistent with other design aspects of the site, what I'd like to be able to do is have the Twitter share page open not in a standard browser window but in a Fancybox (jQuery) window. Fancybox can load an external page in an iFrame when the img or href link contains a class (in this case class="iframe" ) in the link and in the document ready function in the header. Right now, of course, when I give the iframe class to the link that also has the onclick share.tw(), I get two popups: one browser window popup with the correct Twitter share page loaded, and a Fancybox jQuery popup that shows a site 404. How can I change the function to use Fancybox to present the Twitter share page? Is that a correct way to approach it? Or is there a better way, such as implementing the share function in jQuery, too? Thanks... Javascript share function: var share = { tw:function(title,url) { this.share('http://twitter.com/home?status=##URL##+##TITLE##',title,url); }, share:function(tpl,title,url) { if(!url) url = encodeURIComponent(window.location); if(!title) title = encodeURIComponent(document.title); tpl = tpl.replace("##URL##",url); tpl = tpl.replace("##TITLE##",title); window.open(tpl,"sharewindow"+tpl.substr(6,15),"width=640,height=480"); } }; It is invoked, i.e.: <img src="/images/twitter_16.png" onclick="share.tw()" /> Fancybox function, invoked by adding class="iframe" in the img or href link $(".iframe").fancybox({ 'width' : '100%', 'height' : '100%', 'autoScale' : false, 'transitionIn' : 'none', 'transitionOut' : 'none', 'type' : 'iframe' });

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• Windows XP/Firewall -- Can't open UDP port 9100 for JetDirect sharing

  - by Barton Chittenden

  I'm setting up my Dad's laptop (Vista) to print to an HP Deskjet printer attached to a Windows XP Desktop box. The XP box is running Windows firewall. Laptop sits on 192.168.1.66, Desktop 192.168.1.65. I set up logging in the firewall, and determined that it is dropping inbound packets on TCP port 9100, used by JetDirect, the printing protocol. I set up an exception on TCP port 9100, allowing access to the local subnet. There's also an entry under the 'allow applications' tab which was marked for the exact printer model. I selected this as well, then tried to print again... I see more dropped packets from 192.168.1.66 to 192.168.1.65 for TCP port 9100. What do I try next?

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• WPF ResourceDictionary and DynamicResource

  - by lanicor

  i am new to WPF so maybe this will be "noob" question but i can't find answer to it (and it seems so easy)... well i am programing WPF app and i want to use smth similar to css for webpages, so i found ResourceDictionary and tried to use it... I have main window in which i create Frame and on click some UserControl is loaded to that same Frame.I include my ResourceDictionary (root/style/Styles.xaml) to my main window like this: <Window.Resources> <ResourceDictionary x:Key="styles" Source="style/Styles.xaml" /> </Window.Resources> in which i have: <ResourceDictionary xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"> <Style x:Key="ProductsRequired" TargetType="{x:Type Label}"> <Setter Property="Height" Value="28" /> ... I don't use it on my main window but want to use it on my UserControls, which are loaded to that main window and i try to use it like this: <Label Name="product1" Style="{DynamicResource ProductsRequired}" /> Warning i am getting all the time is: The resource "ProductsRequired" could not be resolved. I even tried including Styles to my UserControl <UserControl.Resources> <ResourceDictionary x:Key="styles" Source="../style/Styles.xaml" /> </UserControl.Resources> and nothing happens... Well my question is long but i wanted to be clear... :) P.S. all that logic works in C# code btw private ResourceDictionary myStyles = new ResourceDictionary(); Style ProductsRequired = myStyles["ProductsRequired"] as Style; product1.Style = ProductsRequired;

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• Block ip for long time

  - by Tiziano Dan

  This question is about a iptables, I wanna to know how can I block these ip for 1hour and not only a little time.. because they make to many sql requests, I'm using it for block but it's not enough because there's anyway 100k ip who attack then too much requests for sql server. iptables -N SYN-LIMIT iptables -A SYN-LIMIT -m hashlimit --hashlimit 8/second --hashlimit-mode srcip --hashlimit-name SYN-LIMIT -j RETURN iptables -A SYN-LIMIT -j DROP iptables -I INPUT -p tcp --dport 80 --syn -j SYN-LIMIT iptables -I INPUT -p tcp --dport 80 -m connlimit --connlimit-above 6 -j REJECT --reject-with tcp-reset How can I make the same but block IP for long time ? (Not manually !)

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• How do I switch out Views in a Cocoa application?

  - by David Garcia

  So I'm beginning to learn how to use Cocoa. I think I've pretty much got it but I'm hung up on creating and switching views. I'm rewriting a game I made a little bit ago for practice. All I want is one window (preferably not resizable) and I want to be able to switch out views for different screens in the game. First, I have the main menu (Start Game, High Scores, Exit). Then I need a window for each screen (Gameplay screen, Highscore screen). What I'm getting confused with is how to design this. I looked up NSViewController thinking it manages views but it doesn't. It only manages one view by loading it really. I don't understand why I'd need to use NSViewController then. Couldn't I just have a window class that contains multiple subclasses of NSView and load them like that? I'm not sure I understand the purpose of the ViewController. Does my Window Class really need to subclass NSWindowController? I was trying to follow the example of Apple's ViewController example and it has a window controller class that's a subclass of NSWindowController. I don't see what the purpose was of subclassing that. All NSWindowController seems to add is - initWithPath:(NSString *)newPath but I fail to see the use in that either when I can just edit the plist file to open the window on start up. Apple's example also has an NSView variable and an NSViewController variable. Don't you only need one variable to store the current view? Thanks in advance guys, I'm really confused as to how this works.

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• Input traffic shaping

  - by whitequark

  I know that I can shape output traffic with tc or a similar tool. However, I want to shape the input traffic now—actually, I want to prioritize downloading of files of certain type through a slow lossy connection. I know the reason tc can only shape output traffic: the host itself has no direct control over the amount of input traffic. On the other hand, TCP has some measures built in it which prevent the TCP traffic from overflowing a slow connection. So, can I mangle something in TCP header so that the remote host will think my connection is slower than it thinks? Suppose that I am able to set the corresponding mark on both types of connections with iptables. Is there any way to reduce the input bandwidth of connections of first type, but only if connections of second type are present?

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• Getting list of opened ssh connections by name

  - by lyrae

  I have a config file in my .ssh dir that looks like this Host somehostA HostName 123.45.67.89 User katsh So from my local machine, i can ssh into multiple machines by their name in the config file, like so ssh somehostA ssh somehostB ssh somehostC ... etc Is it possible to get a list of all machines i am connected to, by their name? I know I can do: lsof -i tcp -n | grep '\<ssh\>' and i'll get something like ssh 9871 katsh 3u IPv4 400199 0t0 TCP 987.654.2.2:47329->987.654.2.2:47329:ssh (ESTABLISHED) ssh 20554 katsh 3u IPv4 443965 0t0 TCP 123.456.7.8:41923->123.456.7.8:ssh (ESTABLISHED) But it does not list their names, just IP

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• JSP getParameter problem

  - by user236501

  I have a form, if the timer reach the form will auto redirect to the Servlet to update database. My problem now is if javascript redirect the window to servlet my request.getParameter is null. function verify(f,whichCase){ if(whichCase == "Submit"){ msg = "Are you sure that you want to submit this test?"; var i = confirm(msg) if(i){ parent.window.location = "sindex.jsp" } return i; } } I doing this because i got a iframe in my jsp. Timer update problem have to use iframe. So, when time up or user click submit parent.window.location can let me refresh parent window <form method="POST" action="${pageContext.request.contextPath}/TestServlet" onSubmit="return verify(this,whichPressed)"> My form when user click submit button within the timing, it will trigger the verify function to let user confirm submit. So inside my TestServlet i got this, because using javascript redirect request.getParameter("answer") this keep return me null. protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { if (request.getParameter("Submit") != null) { String ans = request.getParameter("answer"); Answer a = new Answer(ans, no); aa.CreateAnswer(an,t.getTestCode(),username); RequestDispatcher rd = request.getRequestDispatcher("/sindex.jsp"); rd.forward(request, response); } } Below are my timer when time up redirect to TestServlet trigger the doGet method if((mins == 0) && (secs == 0)) { window.alert("Time is up. Press OK to submit the test."); // change timeout message as required var sUrl = "TestServlet"; parent.window.location = sUrl // redirects to specified page once timer ends and ok button is pressed } else { cd = setTimeout("redo()",1000); }

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• How is an AppDelegate instanciated?

  - by pwny

  I have an iOS application for which I want to create a ViewController programmatically. I started an empty XCode project and modified the main method so it looks like this int main(int argc, char *argv[]) { NSAutoreleasePool *pool = [[NSAutoreleasePool alloc] init]; int retVal = UIApplicationMain(argc, argv, nil, @"MyAppDelegate_iPad"); [pool release]; return retVal; } The app is a Universal Application, MyAppDelegate_iPad is a subclass of MyAppDelegate, which is a subclass of NSObject <UIApplicationDelegate>. My problem is that the applicationDidFinishLoading method I've overridden in MyAppDelegate_iPad is never called (break point on the first line never hits). The method looks like this -(void) applicationDidFinishLaunching:(UIApplication *)application { window = [[UIWindow alloc] initWithFrame:[[UIScreen mainScreen] bounds]]; if(!window) { [self release]; return; } window.backgroundColor = [UIColor whiteColor]; rootController = [[MyViewController alloc] init]; [window addSubview:rootController.view]; [window makeKeyAndVisible]; [window layoutSubviews]; } I removed the line to link to a nib file from my plist file (I used to get the default "My Universal app on iPad" white screen) and now all that is displayed is a black screen. applicationDidFinishLoading is still not being called. Am I doing something wrong? How should I properly create my AppDelegate instance?

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• Need help translating rate limiting iptables rules to Puppet format

  - by geoffroy

  I use Puppet Iptables module to manage Iptables rules on my machine. I'd like to implement to rate limit failed SSH connections as described here : Hundreds of failed ssh logins iptables -A INPUT -p tcp --dport 22 -m recent --update --seconds 60 --hitcount 5 --name SSH --rsource -j DROP iptables -A INPUT -p tcp --dport 22 -m recent --set --name SSH --rsource -j ACCEPT Is it possible to translate it to Puppet syntax, such as firewall { '015 drop 5 failed attemps to connect to SSH in a minute ': proto => 'tcp', port => 22, action => 'drop', // what are the other paramters ? } Any help welcome. Best regards Geoffroy

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• ESX Firewall Command Troubles

  - by John

  Hi, I am working on creating some firewall rules to stop some of the SSH brute-force attacks that we have seen recently on our ESX server hosts. I have tried the following rules from the CLI to first block all SSH traffic and then allow the two ranges that I am interested in: esxcfg-firewall --ipruleAdd 0.0.0.0/0,22,tcp,REJECT,"Block_SSH" esxcfg-firewall --ipruleAdd 11.130.0.0/16,22,tcp,ACCEPT,"Allow_PUBLIC_SSH" esxcfg-firewall --ipruleAdd 10.130.0.0/16,22,tcp,ACCEPT,"Allow_PRIVATE_SSH" However, these rules are not working as intended. I know that if you do not enter the block rule first, then the allow rule will not be processed. We are now having the issue where the first entered allow rule is being ignored such that the block rule works and the last entered allow rule works. I was curious if anyone had any ideas on how I could allow a few different ranges of IP's with the esxcfg-firewall --ipruleAdd command? I am at a loss and am having a hard time locating examples or further documentation about this. Thanks in advance for your help with this.

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• Determine mouse click for all screen resolutions

  - by Hallik

  I have some simple javascript that determines where a click happens within a browser here: var clickDoc = (document.documentElement != undefined && document.documentElement.clientHeight != 0) ? document.documentElement : document.body; var x = evt.clientX; var y = evt.clientY; var w = clickDoc.clientWidth != undefined ? clickDoc.clientWidth : window.innerWidth; var h = clickDoc.clientHeight != undefined ? clickDoc.clientHeight : window.innerHeight; var scrollx = window.pageXOffset == undefined ? clickDoc.scrollLeft : window.pageXOffset; var scrolly = window.pageYOffset == undefined ? clickDoc.scrollTop : window.pageYOffset; params = '&x=' + (x + scrollx) + '&y=' + (y + scrolly) + '&w=' + w + '&random=' + Date(); All of this data gets stored in a DB. Later I retrieve it and display where all the clicks happened on that page. This works fine if I do all my clicks in one resolution, and then display it back in the same resolution, but this not the case. there can be large amounts of resolutions used. In my test case I was clicking on the screen with a screen resolution of 1260x1080. I retrieved all the data and displayed it in the same resolution. But when I use a different monitor (tried 1024x768 and 1920x1080. The marks shift to the incorrect spot. My question is, if I am storing the width and height of the client, and the x/y position of the click. If 3 different users all with different screen resolutions click on the same word, and a 4th user goes to view where all of those clicks happened, how can I plot the x/y position correctly to show that everyone clicked in the same space, no matter the resolution? If this belongs in a better section, please let me know as well.

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• In Wireshark's Protocol Hierarchy Statistics screen, is the total byte count of a capture the sum of the Bytes column or just the top line (Frame)?

  - by Howiecamp

  Part 1 - I'm looking at Wireshark's Protocol Hierarchy Statistics screen (sample below), is the total byte count of the capture the sum of the Bytes column or just the top line (Frame)? I'm 99% that it's the latter because of protocol rollup but I wanted to conform. Part 2 - From Wireshark documentation on this screen, "Protocol layers can consist of packets that won't contain any higher layer protocol, so the sum of all higher layer packets may not sum up to the protocols packet count. Example: In the screenshot TCP has 85,83% but the sum of the subprotocols (HTTP, ...) is much less. This may be caused by TCP protocol overhead, e.g. TCP ACK packets won't be counted as packets of the higher layer)." Can you explain this?

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• Postgres Remote Access

  - by boot-baby-boot

  I am trying to connect to postgres remotely.I have followed this tutorial http://www.cyberciti.biz/faq/howto-fedora-linux-install-postgresql-server/ and have executed the following commands to see if the remote access is possible. [root@printmyworld ~]# egrep -i "(listen_addresses|port|tcpip_socket).*=.+" /var /lib/pgsql/data/postgresql.conf #listen_addresses = '*' # what IP address(es) to listen on; #port = 5432 [root@printmyworld ~]# lsof +c0 -anPiTCP -upostgres COMMAND PID USER FD TYPE DEVICE SIZE NODE NAME postmaster 9323 postgres 3u IPv4 2875987353 TCP 127.0.0.1:5432 (LISTEN ) postmaster 9323 postgres 4u IPv6 2875987354 TCP [::1]:5432 (LISTEN) I am suspicious of this line: postmaster 9323 postgres 3u IPv4 2875987353 TCP 127.0.0.1:5432 (LISTEN My server ip address is 1yy.000.1xx.000 .Should it be 1yy.000.1xx.000:5432

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