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  • Password protect user image album

    - by Poland Rocks
    Hi Im making i photo sharint site I want to give the ability for my users to prevent the public to acces their albums with a password. Then they can give the password to the ones they want to be able to see it. To password protect their albums. Im thinking something like this, cant test it on this computer, should work ok. but as im a php/mysql beginner i wanna hear what you experts think if theres a better way/approach Albums id name owner password (if it isnt null the album is considered password protected) The code $id = isset($_GET['albumID']) ? intval($_GET['albumID']) : 0; $result = mysql_query("SELECT * FROM albums WHERE id = $id"); $row = mysql_fetch_object($result); // IS it password protected? if ($row->password != NULL) { echo "This album is password protected."; // User pressed "Enter" if (!empty($_POST['password'])) { $result = mysql_query("SELECT password FROM albums WHERE password = '".mysql_real_escape_string($_POST['password'])."'"); // Was It right password? if (mysql_num_rows($result) == 1) { $authed=1; } echo << <form method="post"> <input type="text" name="password" /> EOT; exit; } else $authed=1; if $authed==1 { // render albumimages etc }

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  • User clicks on Image, video starts playing

    - by cf_PhillipSenn
    I have an image, and I would like to make the image link to an embedded YouTube video, such that if the user clicks on the image, it starts playing in the place where the picture used to be. <div id="myvideo"> <a href="http://www.youtube.com/watch?v=Msef24JErmU&playnext_from=TL&videos=dgzKE_Lyv7o"> <img src="starryeyedsurprise.jpg"></a> </div> Something like what the above code does, except not just hyperlink to it. So I know I have to have javaScript replace what's in #myvideo with: <object width="425" height="344"><param name="movie" value="http://www.youtube.com/v/Msef24JErmU&hl=en_US&fs=1&rel=0&color1=0x2b405b&color2=0x6b8ab6"></param><param name="allowFullScreen" value="true"></param><param name="allowscriptaccess" value="always"></param><embed src="http://www.youtube.com/v/Msef24JErmU&hl=en_US&fs=1&rel=0&color1=0x2b405b&color2=0x6b8ab6" type="application/x-shockwave-flash" allowscriptaccess="always" allowfullscreen="true" width="425" height="344"></embed></object> And then automatically start playing. I guess I don't need it to be a YouTube video per se, I could just host the video on my own site (it's so low volume that I don't have to worry about serving up a video every once in a while).

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  • User input being limited to the alphabet in python

    - by Danger Cat
    I am SUPER new to programming and have my first assignment coming up in python. I am writing a hangman type game, where users are required to guess the word inputted from the other user. I have written most of the code, but the only problem I am having is when users have to input the word, making sure it is only limited to the alphabet. The code I have so far is : word = str.lower(raw_input("Type in your secret word! Shhhh... ")) answer = True while answer == True: for i in range(len(word)): if word[i] not in ("abcdefghijklmnopqrstuvwxyz"): word = raw_input("Sorry, words only contain letters. Please enter a word ") break else: answer = False This works while I input a few tries, but eventually will either exit the loop or displays an error. Is there any easier way to use this? We've really only covered topics up to loops in class, and break and continue are also very new to me. Thank you! (Pardon if the code is sloppy, but as I said I am very new to this....)

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  • write a program that prompts the user to input five decimal numbers : C++

    - by user312309
    This is the question. write a program that prompts the user to input five decimal numbers. the program should then add the five decimal numbers, convert the sum to the nearest integer,m and print the result. This is what I've gotten so far: // p111n9.cpp : Defines the entry point for the console application. // #include <iostream> using namespace std; double a, b , c , d , e, f; int main(int argc, char* argv[]) { cout << "enter 5 decimals: " << endl; cin >> a >> b >> c >> d >> e; f = a + b + c + d + e; return 0; } Now I just need to convert the sum(f) to the nearest integer, m and print the result. How do I do this?

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  • Sanitizing user input before adding it to the DOM in Javascript

    - by I GIVE TERRIBLE ADVICE
    I'm writing the JS for a chat application I'm working on in my free time, and I need to have HTML identifiers that change according to user submitted data. This is usually something conceptually shaky enough that I would not even attempt it, but I don't see myself having much of a choice this time. What I need to do then is to escape the HTML id to make sure it won't allow for XSS or breaking HTML. Here's the code: var user_id = escape(id) var txt = '<div class="chut">'+ '<div class="log" id="chut_'+user_id+'"></div>'+ '<textarea id="chut_'+user_id+'_msg"></textarea>'+ '<label for="chut_'+user_id+'_to">To:</label>'+ '<input type="text" id="chut_'+user_id+'_to" value='+user_id+' readonly="readonly" />'+ '<input type="submit" id="chut_'+user_id+'_send" value="Message"/>'+ '</div>'; What would be the best way to escape id to avoid any kind of problem mentioned above? As you can see, right now I'm using the built-in escape() function, but I'm not sure of how good this is supposed to be compared to other alternatives. I'm mostly used to sanitizing input before it goes in a text node, not an id itself.

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  • Setting the mysql root user password on mac

    - by madaura
    I just Install MySQL on Mac OS X. The next step was setting the root user password, do I did the next: 1-Launch the terminal app to access the unix command line. 2-Under the unix prompt I executed the next commands: madaura$ cd /usr/local/mysql/bin madaura$ ./mysqladmin -u root password 'password' But, when I execute the command madaura$ ./mysql -u root, this is the answer: Welcome to the MySQL monitor. Commands end with ; or \g. Your MySQL connection id is 224 Server version: 5.5.13 MySQL Community Server (GPL) Copyright (c) 2000, 2010, Oracle and/or its affiliates. All rights reserved. Oracle is a registered trademark of Oracle Corporation and/or its affiliates. Other names may be trademarks of their respective owners. Type 'help;' or '\h' for help. Type '\c' to clear the current input statement. mysql> I can get in to the mysql command line without password! Any ideas? Thanks a lot!

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  • Allowing user to type only one "."

    - by Tartar
    I am trying to implement a simple javascript-html calculator. What i want to do is,typing only one '.' by the user. How can i control this ? Here is the code that i tried. I can already find the number of '.' but i'am confused now also this replaceAll function is not replacing '.' with empty string. String.prototype.replaceAll = function(search, replace) { //if replace is null, return original string otherwise it will //replace search string with 'undefined'. if(!replace) return this; return this.replace(new RegExp('[' + search + ']', 'g'), replace); }; function calculate(){ var value = document.calculator.text.value; var valueArray = value.split(""); var arrayLenght = valueArray.length; var character = "."; var charCount = 0; for(i=0;i<arrayLenght;i++){ if (valueArray[i]===character) { charCount += 1; } } if(charCount>1){ var newValue=value.replaceAll(".",""); alert(newValue); } }

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  • Is there a command to change primary group for a new user in Cygwin?

    - by Rob Gilliam
    Is there a way to set a (new) user's primary group in Cygwin's /etc/passwd file without hand-editing the file? I have a local group set up for members of the Dev Team on a Windows Server 2008 R2 box so that we can all modify a particular group files, but the regular users can only read them. As some of the work we do uses scripts that rely on Cygwin tools, this group is also in the /etc/group file. When I need to add a new user to the "Dev Team" group, I add them in Server Manager, and then use mkpasswd to add that user to Cygwin's /etc/passwd file. Unfortunately, they get the regular Domain Users group assigned as their primary group and I then have to go in and edit the passwd file to change the group. I now need to write some instructions for someone else who is not au fait with UNIX/Linux/Cygwin so that they can set up new Dev Team users and obviously "hand editing" /etc/passwd is a recipe for disaster if you don't know what you're doing. So, is there a way of getting mkpasswd to set a different primary group, or another tool like Linux's usermod which can be used for the purpose of changing the group in a more controlled manner?

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  • How do I send e-mails with attachments to a Microsoft WebTV user?

    - by Petr 'PePa' Pavel
    my friend uses Microsoft WebTV (e-mail address ends with @webtv.net) and I'd like to send him an e-mail with a picture attached to it. We went through a series of attempts one of which ended up a success, all others a failure. He just can't see my e-mail in his mailbox, when it contains an attachment. E-mails without attachments always go through all right. What seemed to help in the first successful case, was that he added my e-mail address to his address book and my e-mail suddenly showed up. Seemed to have been delivered before but hidden. He kept my address in his address book however, it didn't help with the following trials. He did look into his junk folder, nothing there. I made sure the file name contains no spaces. It's a regular jpeg, named something-like-this.jpg I downsized it to have only about 50k, as I've read somewhere that that's a limit. I actually doubt this piece of information, because I think the successful attempt was larger. webtv.net contains zero information. I watched their video demo for the e-mail client, so I at least know how the user interface looks like. I've never laid my hands on the real thing. I'm an advanced user myself (a programmer) but I can't wrap my mind around this. He on the other hand, is a very technically inexperienced user and because he's half way across the globe, I can't come and look over his shoulder. He doesn't have a computer, afaik there's no way I could see what he sees. Any ideas on how to debug this? Thanks for your time, guys. P.S. I can't tag this "webtv" because such tag doesn't exist yet and my reputation is too low, sorry.

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  • How do you create an ssh key for the apache user on Redhat?

    - by Josh Smeaton
    As the question asks, how do I generate an ssh key for the user apache on Redhat? My use case, is that we have a mercurial server running under the apache user. We also have several web servers clustered that we need to log on to manually and do pulls from. Ideally, what we'd like to do is have the mercurial server push all changes to all the webservers in the cluster. To do this, we want to use ssh, as setting up http mercurial servers on each of the web servers seems like too much work, and far too heavy. What I've tried to do is the following: > sudo mkdir /var/www/.ssh > sudo chown -R apache:nobody /var/www/.ssh > su - apache -c "ssh-keygen -t rsa" This account is currently not available. I found the above commands elsewhere, but I can only assume that Redhat has differences to whatever distro was used for the above. Is there a way I can generate an ssh-key for the apache user?

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  • Windows user moving to Ubuntu 12.04. Where are the system tools, or equivalents?

    - by Big Endian
    I am a Windows user who has begun experimenting with Ubuntu. Ubuntu seems great, but for all the things it seems like I CAN'T do. How do I get to advanced administration stuff, like the list of drivers, all of the installed software, and something equivalent to Windows' Device Manager. I always heard that Linux was supposed to be very raw, and you had to have lots of computer experience to make it work. This seems just the opposite. Ubuntu seems very modern and user friendly, better in some regards than any operating system I have seen. Unfortunately, I can't find any of the guts of this system beneath all of the user friendly frosting... gunk... crap... stuff. I'm reminded more and more of an Apple computer (except Linux is more affordable :). So how do I peel back this layer and start using the computer? A solution other than installing Gnome 3 would be appreciated.

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  • trying to validate user input in php

    - by user225269
    I'm trying to validate user input in php. This code will check if the values are null or not. If it is null, this will require the user to input the values that are null. When all the text boxes in the html form that came before this. This code will show the submit button, and that submit button will save the inputted data into the mysql database. But the problem is that the value that is saved is zero zero and zero, what might be the cause of this? <html> <head> <title>Admission Information Sheet</title> <meta http-equiv="Content-Type" content="text/html; Western (ISO-8859-1)"> <meta name="author" content=" "> <title> <style> input { font-size: 16px;} </style> <?php include('header.php'); ?> <div id="main_content"> </div> <?php include('footer.php'); ?> <table border="1" width="900" border="0" align="left" cellpadding="0" cellspacing="1" bgcolor="#CCCCCC"> <tr> <form name="form1.1" method="POST" action="aisaction.php"> <?php $NURSE = $_POST[nurse]; $TELNUM = $_POST[telnum]; $HOSPNUM = $_POST[hnum]; $ROOMNUM = $_POST[rnum]; $LASTNAME = $_POST[lname]; $FIRSTNAME = $_POST[fname]; $MIDNAME = $_POST[mname]; $AD = $_POST[ad]; $ADATE = $_POST[adate]; $ADTIME = $_POST[adtime]; $CSTAT = $_POST[cs]; $AGE = $_POST[age]; $BDAY = $_POST[bday]; $SEX = $_POST[sex]; ?> <td> <table width="100%" border="0" cellpadding="2" cellspacing="1" bgcolor="#FFFFFF"> <tr> <td colspan="12" style="background:#9ACD32; color:white; border:white 1px solid; text-align: center"><strong><font size="3">ADMISSION INFORMATION SHEET</strong></td> </tr> <tr> </td><br> <td width="54"><font size="3">Hospital #</td> <td width="3">:</td> <td width="168"><input type="display" name="hnum" disabled="true" value= "<?php print "$HOSPNUM";?>"><br> <font color="red"> <?php if(empty($HOSPNUM)) print "* Hospital Number required!<br>"; ?> </td> <td width="41"><font size="3">Room #</td> <td width="3">:</td> <td width="168"><input type="display" name="rnum" disabled="true" value= "<?php print "$ROOMNUM";?>"><br> <font color="red"> <?php if(empty($ROOMNUM)) print "* Room Number required!<br>"; ?> </td> <td width="67"><font size="3">Admission Date</td> <td width="3">:</td> <td width="168"><input type="display" name="adate" disabled="true" value= "<?php print "$ADATE";?>"><br> <font color="red"> <?php if(empty($ADATE)) print "* Admission Date required!<br>"; ?> </td> </tr> <tr> <td><font size="3">Last Name</td> <td>:</td> <td><input type="display" name="lname" disabled="true" value= "<?php print "$LASTNAME";?>"><br> <font color="red"> <?php if(empty($LASTNAME)) print "* Last Name required!<br>"; ?> </td> <td><font size="3">First Name</td> <td>:</td> <td><input type="display" name="fname" disabled="true" value= "<?php print "$FIRSTNAME";?>"><br> <font color="red"> <?php if(empty($FIRSTNAME)) print "* First Name required!<br>"; ?> </td> <td><font size="3">Middle Name</td> <td>:</td> <td><input type="display" name="mname" disabled="true" value= "<?php print "$MIDNAME";?>"><br> <font color="red"> <?php if(empty($MIDNAME)) print "* Middle Name required!<br>"; ?> </td> <td><font size="3">Admit time</td> <td>:</td> <td><input type="display" name="mname" disabled="true" value= "<?php print "$ADTIME";?>"><br> <font color="red"> <?php if(empty($ADTIME)) print "* Adtime required!<br>"; ?> </td> </tr> <tr> <td><font size="3">Civil Status</td> <td>:</td> <td><input type="display" name="cs" disabled="true" value= "<?php print "$CSTAT";?>"><br> <font color="red"> <?php if(empty($CSTAT)) print "* Civil Status required!<br>"; ?> </td> <td><font size="3">Age</td> <td>:</td> <td><input type="display" name="age" disabled="true" value= "<?php print "$AGE";?>"><br> <font color="red"> <?php if(empty($AGE)) print "* Age required!<br>"; ?> </td> <td><font size="3">Birthday</td> <td>:</td> <td><input type="display" name="bday" disabled="true" value= "<?php print "$BDAY";?>"><br> <font color="red"> <?php if(empty($BDAY)) print "* Birthday required!<br>"; ?> </td> </tr> <tr> <td><font size="3">Address</td> <td>:</td> <td><input type="display" name="address" disabled="true" value= "<?php print "$AD";?>"><br> <font color="red"> <?php if(empty($AD)) print "* Address required!<br>"; ?> </td> <td><font size="3">Telephone #</td> <td>:</td> <td><input type="display" name="telnum" disabled="true" value= "<?php print "$TELNUM";?>"></td> <td width="23"><font size="3">Sex</td> <td width="3">:</td> <td width="174"><input type="display" name="sex" disabled="true" value= "<?php print "$SEX";?>"><br> <font color="red"> <?php if(empty($SEX)) print "* Gender required!<br>"; ?> </td> </tr> <tr> <td><font size="3">Pls. Check</td> <td>:</td> <td><input name="stats1" type="checkbox" id="SSS" value="SSS">SSS</td> <td><font size="3"></td> <td>:</td> <td><input name="stats1" type="checkbox" id="nonmed" value="NonMedicare">Non Medicare</td> <td><font size="3"></td> <td>:</td> <td><input name="stats1" type="checkbox" id="sh" value="stockholder">Stockholder</td> </tr> <tr> <td><font size="3"></td> <td></td> <td><input name="stats1" type="checkbox" id="gsis" value="GSIS">GSIS</td> <td><font size="3"></td> <td></td> <td><input name="stats1" type="checkbox" id="senior" value="seniorcitizen">Senior-Citizen</td> <tr> <td><font size="3"></td> <td></td> <td><input name="stats1" type="checkbox" id="dep" value="dependent">Dependent</td> <td><font size="3"></td> <td></td> <td><input name="stats1" type="checkbox" id="emp" value="employee">Employee</td> </tr> <tr> <td><font size="3">Attending Nurse</td> <td>:</td> <td><input type="display" name="nurse" disabled="true" value= "<?php print "$NURSE";?>"><br> <font color="red"> <?php if(empty($NURSE)) print "* Admitting/Attending Nurse required!<br>"; ?> </td> </tr> <tr> <td>&nbsp;</td> <td>&nbsp;</td> <td><input type="button" value="Back" onClick="history.go(-1);return true;"> <?php $val1 = $_POST['NURSE']; if($_POST['NURSE'] !="") { ?> <form action="aisaction.php" method="POST" target="_window"> <input type="hidden" name="submit" value="yes"> <input type="submit" value="submit"> </form> <?php } ?> </td> </td> </tr> </table> </td> </form> </tr> </table> </head> </html>

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  • EPPlus - .xlsx is locked for editing by 'another user'

    - by AdamTheITMan
    I have searched through every possible answer on SO for a solution, but nothing has worked. I am basically creating an excel file from a database and sending the results to the response stream using EPPlus(OpenXML). The following code gives me an error when trying to open my generated excel sheet "[report].xlsx is locked for editing by 'another user'." It will open fine the first time, but the second time it's locked. Dim columnData As New List(Of Integer) Dim rowHeaders As New List(Of String) Dim letter As String = "B" Dim x As Integer = 0 Dim trendBy = context.Session("TRENDBY").ToString() Dim dateHeaders As New List(Of String) dateHeaders = DirectCast(context.Session("DATEHEADERS"), List(Of String)) Dim DS As New DataSet DS = DirectCast(context.Session("DS"), DataSet) Using excelPackage As New OfficeOpenXml.ExcelPackage Dim excelWorksheet = excelPackage.Workbook.Worksheets.Add("Report") 'Add title to the top With excelWorksheet.Cells("B1") .Value = "Account Totals by " + If(trendBy = "Months", "Month", "Week") .Style.Font.Bold = True End With 'add date headers x = 2 'start with letter B (aka 2) For Each Header As String In dateHeaders With excelWorksheet.Cells(letter + "2") .Value = Header .Style.HorizontalAlignment = OfficeOpenXml.Style.ExcelHorizontalAlignment.Right .AutoFitColumns() End With x = x + 1 letter = Helper.GetColumnIndexToColumnLetter(x) Next 'Adds the descriptive row headings down the left side of excel sheet x = 0 For Each DC As DataColumn In DS.Tables(0).Columns If (x < DS.Tables(0).Columns.Count) Then rowHeaders.Add(DC.ColumnName) End If Next Dim range = excelWorksheet.Cells("A3:A30") range.LoadFromCollection(rowHeaders) 'Add the meat and potatoes of report x = 2 For Each dTable As DataTable In DS.Tables columnData.Clear() For Each DR As DataRow In dTable.Rows For Each item As Object In DR.ItemArray columnData.Add(item) Next Next letter = Helper.GetColumnIndexToColumnLetter(x) excelWorksheet.Cells(letter + "3").LoadFromCollection(columnData) With excelWorksheet.Cells(letter + "3") .Formula = "=SUM(" + letter + "4:" + letter + "6)" .Style.Font.Bold = True .Style.Font.Size = 12 End With With excelWorksheet.Cells(letter + "7") .Formula = "=SUM(" + letter + "8:" + letter + "11)" .Style.Font.Bold = True .Style.Font.Size = 12 End With With excelWorksheet.Cells(letter + "12") .Style.Font.Bold = True .Style.Font.Size = 12 End With With excelWorksheet.Cells(letter + "13") .Formula = "=SUM(" + letter + "14:" + letter + "20)" .Style.Font.Bold = True .Style.Font.Size = 12 End With With excelWorksheet.Cells(letter + "21") .Formula = "=SUM(" + letter + "22:" + letter + "23)" .Style.Font.Bold = True .Style.Font.Size = 12 End With With excelWorksheet.Cells(letter + "24") .Formula = "=SUM(" + letter + "25:" + letter + "26)" .Style.Font.Bold = True .Style.Font.Size = 12 End With With excelWorksheet.Cells(letter + "27") .Formula = "=SUM(" + letter + "28:" + letter + "29)" .Style.Font.Bold = True .Style.Font.Size = 12 End With With excelWorksheet.Cells(letter + "30") .Formula = "=SUM(" + letter + "3," + letter + "7," + letter + "12," + letter + "13," + letter + "21," + letter + "24," + letter + "27)" .Style.Font.Bold = True .Style.Font.Size = 12 End With x = x + 1 Next range.AutoFitColumns() 'send it to response Using stream As New MemoryStream(excelPackage.GetAsByteArray()) context.Response.Clear() context.Response.ContentType = "application/vnd.openxmlformats-officedocument.spreadsheetml.sheet" context.Response.AddHeader("content-disposition", "attachment; filename=filetest.xlsx") context.Response.OutputStream.Write(stream.ToArray(), 0, stream.ToArray().Length) context.Response.Flush() context.Response.Close() End Using End Using

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  • IF adding new Entity gives error me : EntityCommandCompilationException was unhandled bu user code

    - by programmerist
    i have 5 tables in started projects. if i adds new table (Urun enttiy) writing below codes: project.BAL : public static List<Urun> GetUrun() { using (GenoTipSatisEntities genSatisUrunCtx = new GenoTipSatisEntities()) { ObjectQuery<Urun> urun = genSatisUrunCtx.Urun; return urun.ToList(); } } if i receive data form BAL in UI.aspx: using project.BAL; namespace GenoTip.Web.ContentPages.Satis { public partial class SatisUrun : System.Web.UI.Page { protected void Page_Load(object sender, EventArgs e) { if (!IsPostBack) { FillUrun(); } } void FillUrun() { ddlUrun.DataSource = SatisServices.GetUrun(); ddlUrun.DataValueField = "ID"; ddlUrun.DataTextField = "Ad"; ddlUrun.DataBind(); } } } i added URun later. error appears ToList method: EntityCommandCompilationException was unhandled bu user code error Detail: Error 1 Error 3007: Problem in Mapping Fragments starting at lines 659, 873: Non-Primary-Key column(s) [UrunID] are being mapped in both fragments to different conceptual side properties - data inconsistency is possible because the corresponding conceptual side properties can be independently modified. C:\Users\pc\Desktop\GenoTip.Satis\GenoTip.DAL\ModelSatis.edmx 660 15 GenoTip.DAL Error 2 Error 3012: Problem in Mapping Fragments starting at lines 659, 873: Data loss is possible in FaturaDetay.UrunID. An Entity with Key (PK) will not round-trip when: (PK does NOT play Role 'FaturaDetay' in AssociationSet 'FK_FaturaDetay_Urun' AND PK is in 'FaturaDetay' EntitySet) C:\Users\pc\Desktop\GenoTip.Satis\GenoTip.DAL\ModelSatis.edmx 874 11 GenoTip.DAL Error 3 Error 3012: Problem in Mapping Fragments starting at lines 659, 873: Data loss is possible in FaturaDetay.UrunID. An Entity with Key (PK) will not round-trip when: (PK is in 'FaturaDetay' EntitySet AND PK does NOT play Role 'FaturaDetay' in AssociationSet 'FK_FaturaDetay_Urun' AND Entity.UrunID is not NULL) C:\Users\pc\Desktop\GenoTip.Satis\GenoTip.DAL\ModelSatis.edmx 660 15 GenoTip.DAL Error 4 Error 3007: Problem in Mapping Fragments starting at lines 748, 879: Non-Primary-Key column(s) [UrunID] are being mapped in both fragments to different conceptual side properties - data inconsistency is possible because the corresponding conceptual side properties can be independently modified. C:\Users\pc\Desktop\GenoTip.Satis\GenoTip.DAL\ModelSatis.edmx 749 15 GenoTip.DAL Error 5 Error 3012: Problem in Mapping Fragments starting at lines 748, 879: Data loss is possible in Satis.UrunID. An Entity with Key (PK) will not round-trip when: (PK does NOT play Role 'Satis' in AssociationSet 'FK_Satis_Urun' AND PK is in 'Satis' EntitySet) C:\Users\pc\Desktop\GenoTip.Satis\GenoTip.DAL\ModelSatis.edmx 880 11 GenoTip.DAL Error 6 Error 3012: Problem in Mapping Fragments starting at lines 748, 879: Data loss is possible in Satis.UrunID. An Entity with Key (PK) will not round-trip when: (PK is in 'Satis' EntitySet AND PK does NOT play Role 'Satis' in AssociationSet 'FK_Satis_Urun' AND Entity.UrunID is not NULL) C:\Users\pc\Desktop\GenoTip.Satis\GenoTip.DAL\ModelSatis.edmx 749 15 GenoTip.DAL

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  • Detect user logout / shutdown in Python / GTK under Linux - SIGTERM/HUP not received

    - by Ivo Wetzel
    OK this is presumably a hard one, I've got an pyGTK application that has random crashes due to X Window errors that I can't catch/control. So I created a wrapper that restarts the app as soon as it detects a crash, now comes the problem, when the user logs out or shuts down the system, the app exits with status 1. But on some X errors it does so too. So I tried literally anything to catch the shutdown/logout, with no success, here's what I've tried: import pygtk import gtk import sys class Test(gtk.Window): def delete_event(self, widget, event, data=None): open("delete_event", "wb") def destroy_event(self, widget, data=None): open("destroy_event", "wb") def destroy_event2(self, widget, event, data=None): open("destroy_event2", "wb") def __init__(self): gtk.Window.__init__(self, gtk.WINDOW_TOPLEVEL) self.show() self.connect("delete_event", self.delete_event) self.connect("destroy", self.destroy_event) self.connect("destroy-event", self.destroy_event2) def foo(): open("add_event", "wb") def ex(): open("sys_event", "wb") from signal import * def clean(sig): f = open("sig_event", "wb") f.write(str(sig)) f.close() exit(0) for sig in (SIGABRT, SIGILL, SIGINT, SIGSEGV, SIGTERM): signal(sig, lambda *args: clean(sig)) def at(): open("at_event", "wb") import atexit atexit.register(at) f = Test() sys.exitfunc = ex gtk.quit_add(gtk.main_level(), foo) gtk.main() open("exit_event", "wb") Not one of these succeeds, is there any low level way to detect the system shutdown? Google didn't find anything related to that. I guess there must be a way, am I right? :/ EDIT: OK, more stuff. I've created this shell script: #!/bin/bash trap test_term TERM trap test_hup HUP test_term(){ echo "teeeeeeeeeerm" >~/Desktop/term.info exit 0 } test_hup(){ echo "huuuuuuuuuuup" >~/Desktop/hup.info exit 1 } while [ true ] do echo "idle..." sleep 2 done And also created a .desktop file to run it: [Desktop Entry] Name=Kittens GenericName=Kittens Comment=Kitten Script Exec=kittens StartupNotify=true Terminal=false Encoding=UTF-8 Type=Application Categories=Network;GTK; Name[de_DE]=Kittens Normally this should create the term file on logout and the hup file when it has been started with &. But not on my System. GDM doesn't care about the script at all, when I relog, it's still running. I've also tried using shopt -s huponexit, with no success. EDIT2: Also here's some more information aboute the real code, the whole thing looks like this: Wrapper Script, that catches errors and restarts the programm -> Main Programm with GTK Mainloop -> Background Updater Thread The flow is like this: Start Wrapper -> enter restart loop while restarts < max: -> start program -> check return code -> write error to file or exit the wrapper on 0 Now on shutdown, start program return 1. That means either it did hanup or the parent process terminated, the main problem is to figure out which of these two did just happen. X Errors result in a 1 too. Trapping in the shellscript doesn't work. If you want to take a look at the actual code check it out over at GitHub: http://github.com/BonsaiDen/Atarashii

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  • read user Input of custom dialogs

    - by urobo
    I built a custom dialog starting from an AlertDialog to obtain login information from a user. So the dialog contains two EditText fields, using the layoutinflater service I obtain the layout and I'm saving a reference to the fields. LayoutInflater inflater = (LayoutInflater) Home.this.getSystemService(LAYOUT_INFLATER_SERVICE); layoutLogin = inflater.inflate(R.layout.login,(ViewGroup) findViewById(R.id.rl)); usernameInput =((EditText)findViewById(R.id.getNewUsername)); passwordInput = ((EditText)findViewById(R.id.getNewPassword)); Then I have my overridden onCreateDialog(...) : { AlertDialog d = null; AlertDialog.Builder builder = new AlertDialog.Builder(this); switch(id){ ... case Home.DIALOG_LOGIN: builder.setView(layoutLogin); builder.setMessage("Sign in to your DyCaPo Account").setCancelable(false); d=builder.create(); d.setTitle("Login"); Message msg = new Message(); msg.setTarget(Home.this.handleLogin); Bundle data = new Bundle(); data.putString("username", usernameInput.getText().toString());// <---null pointer Exception data.putString("password", passwordInput.getText().toString()); msg.setData(data); d.setButton(Dialog.BUTTON_NEUTRAL,"Sign in",msg); break; ... return d; } and the handler set in the Message: private Handler handleLogin= new Handler(){ /* (non-Javadoc) * @see android.os.Handler#handleMessage(android.os.Message) */ @Override public void handleMessage(Message msg) { // TODO Auto-generated method stub Log.d("Message Received", msg.getData().getString("username")+ msg.getData().getString("password")); } }; which for now works as a debugging tool. That's all. The Question is: what am I doing wrong? Because when I reach the line highlighted in the code ( the line in which I read the fields in the dialog ) I always get a null pointer exception. Could somebody please tell me the reason why it is so? And give some guidelines to work with dialogs. Thanks in advance!

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  • How to honor/inherit user's language settings in WinForm app

    - by msorens
    I have worked with globalization settings in the past but not within the .NET environment, which is the topic of this question. What I am seeing is most certainly due to knowledge I have yet to learn so I would appreciate illumination on the following. Setup: My default language setting is English (en-us specifically). I added a second language (Danish) on my development system (WinXP) and then opened the language bar so I could select either at will. I selected Danish on the language bar then opened Notepad and found the language reverted to English on the language bar. I understand that the language setting is per application, so it seemed that Notepad set the default back to English. (I found that strange since Windows and thus Notepad is used all over the world.) Closing Notepad returned the setting on the language bar to Danish. I then launched my open custom WinForm application--which I know does not set the language--and it also reverted from English to Danish when opened, then back to Danish when terminated! Question #1A: How do I get my WinForm application upon launch to inherit the current setting of the language bar? My experiment seems to indicate that each application starts with the system default and requires the user to manually change it once the app is running--this would seem to be a major inconvenience for anyone that wants to work with more than one language! Question #1B: If one must, in fact, set the language manually in a multi-language scenario, how do I change my default system language (e.g. to Danish) so I can test my app's launch in another language? I added a display of the current language in my application for this next experiment. Specifically I set a MouseEnter handler on a label that set its tooltip to CultureInfo.CurrentCulture.Name so each time I mouse over I thought I should see the current language setting. Since setting the language before I launch my app did not work, I launched it then set the language to Danish. I found that some things (like typing in a TextBox) did honor this Danish setting. But mousing over the instrumented label still showed en-us! Question #2A: Why does CultureInfo.CurrentCulture.Name not reflect the change from my language bar while other parts of my app seem to recognize the change? (Trying CultureInfo.CurrentUICulture.Name produced the same result.) Question #2B: Is there an event that fires upon changes on the language bar so I could recognize within my app when the language setting changes?

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  • Adding ComboBoxItem to a combobox inside a user control (XAML/WPF)

    - by byte
    I am currently learning to create custom controls in WPF. I successfully created a simple custom control using a Label and a Text Box. I was able to allow setting the Label text by DependencyProperty. Now I am creating a user control that has a ComboBox. I need to allow adding items to this ComboBox from outside the control. To achieve this, I tried exposing a DependencyProperty of type ItemsCollection and it will allows access to the ComboBox's Items property (the DP in my control sample is named 'CbItems'). But I get errors because Items property of Combobox is ReadOnly. Control XAML <UserControl x:Class="MyWpfApp.Controls.MyControl" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" Height="Auto" Width="Auto"> <Grid> <Grid.ColumnDefinitions> <ColumnDefinition /> <ColumnDefinition /> </Grid.ColumnDefinitions> <Label Grid.Column="0" Content="{Binding FieldLabel}"></Label> <ComboBox Name="cmb" Grid.Column="1" Width="150"></ComboBox> </Grid> </UserControl> MainWindow XAML <Window x:Class="MyWpfApp.Window1" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" xmlns:ctl="clr-namespace:MyWpfApp.Controls" Title="Window1" Height="300" Width="300"> <Grid> <ctl:MyControl> <ctl:MyControl.CbItems> <ComboBoxItem>Hello</ComboBoxItem> <ComboBoxItem>World</ComboBoxItem> <ComboBoxItem>Hi</ComboBoxItem> </ctl:LobCombox.CbItems> </ctl:LobCombox> </Grid> </Window> I would like to know what the correct way is to achieve this functionality. I believe the answer to this might also help with other controls like GridView etc Many Thanks

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  • How can I conditionally only log something if it's a certain Class?

    - by BryanWheelock
    Something like this: if self.class == "User": logging.debug("%s non_pks were found" % (str(len(non_pks))) ) In [2]: user = User.objects.get(pk=1) In [3]: user.class Out[3]: In [4]: if user.class == 'django.contrib.auth.models.User': print "yes" ...: In [5]: user.class == 'django.contrib.auth.models.User' Out[5]: False In [6]: user.class == 'User' Out[6]: False In [7]: user.class == "" Out[7]: False

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  • Let the user choose what type of document to open

    - by Koning Baard XIV
    I'm creating an NSDocument application, with two document types: Website and Webservice. This is in my Info.plist: <key>CFBundleDocumentTypes</key> <array> <dict> <key>CFBundleTypeName</key> <string>Website</string> <key>CFBundleTypeExtensions</key> <array> <string>website</string> </array> <key>LSTypeIsPackage</key> <true/> <key>CFBundleTypeRole</key> <string>Editor</string> <key>LSHandlerRank</key> <string>Default</string> <key>NSDocumentClass</key> <string>AWWebSite</string> </dict> <dict> <key>CFBundleTypeName</key> <string>Web Service</string> <key>CFBundleTypeExtensions</key> <array> <string>webservice</string> </array> <key>LSTypeIsPackage</key> <true/> <key>CFBundleTypeRole</key> <string>Editor</string> <key>LSHandlerRank</key> <string>Default</string> <key>NSDocumentClass</key> <string>AWWebService</string> </dict> </array> Now, whenever the user opens the application, selects the 'New' item from the menubar, or clicks the Dock icon while there are no open windows, I want to show a window with two options, each for one of the document types. Can anyone help me with this? Thanks

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  • Asp.net MVC appliction showing popup message after updating user

    - by kumar
    This is my Update Json method.. public JsonResult Update(StudentInfo e) { var cache = CacheFactory.GetCacheManager(); var Status= false; for (int i = 0; i <= cache.Count; i++) { var x = (StudentInfo )cache.GetData("a" + i); if (x != null) { Status= common.UpdateStudent(e.Student); } } return Json(Status); } this is my veiw.. <% using (Html.BeginForm("Update", "home", FormMethod.Post)) { %> <%= Html.ValidationSummary(true)%> my scripts.. <script type="text/javascript"> $(document).ready(function() { $('#btnSelectAll').click(function() { $('#btnSelect').click(function() { $('#input[type=checkbox]').attr('checked', 'checked'); }); function validate_excpt(formData, jqForm, options) { var form = jqForm[0]; return true; } // post-submit callback function showResponse(responseText, statusText, xhr, $form) { if (responseText[0].substring(0, 16) != "System.Exception") { $('#error-msg- span:last').html('<strong>Update successful.</strong>'); } else { $('#error-msg- span:last').html('<strong>Update failed.</strong> ' + responseText[0].substring(0, 48)); } $('#error-msg-').removeClass('hide'); $('#gui-stat-').html(responseText[1]); } // post-submit callback $('#exc-').ajaxForm({ target: '#error-msg-', beforeSubmit: validate_excpt, success: showResponse, dataType: 'json' }); $('.button').button(); }); $('.button').button(); $("input[id^='exc-flwup-']").datepicker({ duration: '', showTime: true, constrainInput: true, stepMinutes: 30, stepHours: 1, altTimeField: '', time24h: true, minDate: 0 }); $('#ui-timepicker-div').bgiframe(); }); </script> I am getting popupmessage when Jsonresult Update method has done..but I am seeing that user is updating perfectly.. popup window saying something like you have choosed to open if I open that I am getting string as True in the file.. is that above code I am doing something wrong?

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  • Calling/selecting variables (float valued) with user input in Python

    - by Jonathan Straus
    I've been working on a computational physics project (plotting related rates of chemical reactants with respect to eachother to show oscillatory behavior) with a fair amount of success. However, one of my simulations involves more than two active oscillating agents (five, in fact) which would obviously be unsuitable for any single visual plot... My scheme was hence to have the user select which two reactants they wanted plotted on the x-axis and y-axis respectively. I tried (foolishly) to convert string input values into the respective variable names, but I guess I need a radically different approach if any exist? If it helps clarify any, here is part of my code: def coupledBrusselator(A, B, t_trial,display_x,display_y): t = 0 t_step = .01 X = 0 Y = 0 E = 0 U = 0 V = 0 dX = (A) - (B+1)*(X) + (X**2)*(Y) dY = (B)*(X) - (X**2)*(Y) dE = -(E)*(U) - (X) dU = (U**2)*(V) -(E+1)*(U) - (B)*(X) dV = (E)*(U) - (U**2)*(V) array_t = [0] array_X = [0] array_Y = [0] array_U = [0] array_V = [0] while t <= t_trial: X_1 = X + (dX)*(t_step/2) Y_1 = Y + (dY)*(t_step/2) E_1 = E + (dE)*(t_step/2) U_1 = U + (dU)*(t_step/2) V_1 = V + (dV)*(t_step/2) dX_1 = (A) - (B+1)*(X_1) + (X_1**2)*(Y_1) dY_1 = (B)*(X_1) - (X_1**2)*(Y_1) dE_1 = -(E_1)*(U_1) - (X_1) dU_1 = (U_1**2)*(V_1) -(E_1+1)*(U_1) - (B)*(X_1) dV_1 = (E_1)*(U_1) - (U_1**2)*(V_1) X_2 = X + (dX_1)*(t_step/2) Y_2 = Y + (dY_1)*(t_step/2) E_2 = E + (dE_1)*(t_step/2) U_2 = U + (dU_1)*(t_step/2) V_2 = V + (dV_1)*(t_step/2) dX_2 = (A) - (B+1)*(X_2) + (X_2**2)*(Y_2) dY_2 = (B)*(X_2) - (X_2**2)*(Y_2) dE_2 = -(E_2)*(U_2) - (X_2) dU_2 = (U_2**2)*(V_2) -(E_2+1)*(U_2) - (B)*(X_2) dV_2 = (E_2)*(U_2) - (U_2**2)*(V_2) X_3 = X + (dX_2)*(t_step) Y_3 = Y + (dY_2)*(t_step) E_3 = E + (dE_2)*(t_step) U_3 = U + (dU_2)*(t_step) V_3 = V + (dV_2)*(t_step) dX_3 = (A) - (B+1)*(X_3) + (X_3**2)*(Y_3) dY_3 = (B)*(X_3) - (X_3**2)*(Y_3) dE_3 = -(E_3)*(U_3) - (X_3) dU_3 = (U_3**2)*(V_3) -(E_3+1)*(U_3) - (B)*(X_3) dV_3 = (E_3)*(U_3) - (U_3**2)*(V_3) X = X + ((dX + 2*dX_1 + 2*dX_2 + dX_3)/6) * t_step Y = Y + ((dX + 2*dY_1 + 2*dY_2 + dY_3)/6) * t_step E = E + ((dE + 2*dE_1 + 2*dE_2 + dE_3)/6) * t_step U = U + ((dU + 2*dU_1 + 2*dY_2 + dE_3)/6) * t_step V = V + ((dV + 2*dV_1 + 2*dV_2 + dE_3)/6) * t_step dX = (A) - (B+1)*(X) + (X**2)*(Y) dY = (B)*(X) - (X**2)*(Y) t_step = .01 / (1 + dX**2 + dY**2) ** .5 t = t + t_step array_X.append(X) array_Y.append(Y) array_E.append(E) array_U.append(U) array_V.append(V) array_t.append(t) where previously display_x = raw_input("Choose catalyst you wish to analyze in the phase/field diagrams (X, Y, E, U, or V) ") display_y = raw_input("Choose one other catalyst from list you wish to include in phase/field diagrams ") coupledBrusselator(A, B, t_trial, display_x, display_y) Thanks!

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  • Django Multi-Table Inheritance VS Specifying Explicit OneToOne Relationship in Models

    - by chefsmart
    Hope all this makes sense :) I'll clarify via comments if necessary. Also, I am experimenting using bold text in this question, and will edit it out if I (or you) find it distracting. With that out of the way... Using django.contrib.auth gives us User and Group, among other useful things that I can't do without (like basic messaging). In my app I have several different types of users. A user can be of only one type. That would easily be handled by groups, with a little extra care. However, these different users are related to each other in hierarchies / relationships. Let's take a look at these users: - Principals - "top level" users Administrators - each administrator reports to a Principal Coordinators - each coordinator reports to an Administrator Apart from these there are other user types that are not directly related, but may get related later on. For example, "Company" is another type of user, and can have various "Products", and products may be supervised by a "Coordinator". "Buyer" is another kind of user that may buy products. Now all these users have various other attributes, some of which are common to all types of users and some of which are distinct only to one user type. For example, all types of users have to have an address. On the other hand, only the Principal user belongs to a "BranchOffice". Another point, which was stated above, is that a User can only ever be of one type. The app also needs to keep track of who created and/or modified Principals, Administrators, Coordinators, Companies, Products etc. (So that's two more links to the User model.) In this scenario, is it a good idea to use Django's multi-table inheritance as follows: - from django.contrib.auth.models import User class Principal(User): # # # branchoffice = models.ForeignKey(BranchOffice) landline = models.CharField(blank=True, max_length=20) mobile = models.CharField(blank=True, max_length=20) created_by = models.ForeignKey(User, editable=False, blank=True, related_name="principalcreator") modified_by = models.ForeignKey(User, editable=False, blank=True, related_name="principalmodifier") # # # Or should I go about doing it like this: - class Principal(models.Model): # # # user = models.OneToOneField(User, blank=True) branchoffice = models.ForeignKey(BranchOffice) landline = models.CharField(blank=True, max_length=20) mobile = models.CharField(blank=True, max_length=20) created_by = models.ForeignKey(User, editable=False, blank=True, related_name="principalcreator") modified_by = models.ForeignKey(User, editable=False, blank=True, related_name="principalmodifier") # # # Please keep in mind that there are other user types that are related via foreign keys, for example: - class Administrator(models.Model): # # # principal = models.ForeignKey(Principal, help_text="The supervising principal for this Administrator") user = models.OneToOneField(User, blank=True) province = models.ForeignKey( Province) landline = models.CharField(blank=True, max_length=20) mobile = models.CharField(blank=True, max_length=20) created_by = models.ForeignKey(User, editable=False, blank=True, related_name="administratorcreator") modified_by = models.ForeignKey(User, editable=False, blank=True, related_name="administratormodifier") I am aware that Django does use a one-to-one relationship for multi-table inheritance behind the scenes. I am just not qualified enough to decide which is a more sound approach.

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  • jQuery Table - Reference User Input Row Names and Values

    - by Vic
    I have several tables which are generated by another application, which I have no control over. I am totally new to jQuery and ajax, and have only a limited knowledge of jsp. Two sample rows are: <table class="sicknessForm"> <tr id="row_0" class="datarow"> <td id="col_2"><input name="row_0-col_2" class="tabcell" value="Injuries"></td> <td id="col_4"><input name="row_0-col_4" class="tabcell" value="01"></td> <td id="col_5"><input name="row_0-col_5" class="tabcell" value="2"></td> <td id="col_6"><input name="row_0-col_6" class="tabcell" value="5"></td> </tr> <tr id="row_1" class="datarow"> <td id="col_2"><input name="row_1-col_2" class="tabcell" value="Absences"></td> <td id="col_4"><input name="row_1-col_4" class="tabcell" value="100"></td> <td id="col_5"><input name="row_1-col_5" class="tabcell" value="102"></td> <td id="col_6"><input name="row_1-col_6" class="tabcell" value="105"></td> </tr> </table> There are more rows and columns in the actual tables. What I need to do is to pass the ordered row information to the database, e.g.: Injuries, 1, 2, 5 .... Absences 100, 102, 105... I can retrieve the values for each input using: $('#SicknessForm .userInput').each(function() { alert($(this).val()); }); 1) How can I loop through each row, get the value from the first column (Injuries) and place the data into an array to send to the server? 2) How do I reference the first row of each column to disable user input on it? $(:HowDoIReferenceThis).attr('disabled', ''); 3) I need to validate that each cell is numeric, other than the first column. Any pointers on this (otherwise I can check it in my servlet), especially on how to loop through all valid input cells (everything except 'Injuries','Abences', ... cells). Many Thanks! Vic

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  • Working with hibernate/DAO problems

    - by Gandalf StormCrow
    Hello everyone here is my DAO class : public class UsersDAO extends HibernateDaoSupport { private static final Log log = LogFactory.getLog(UsersDAO.class); protected void initDao() { //do nothing } public void save(User transientInstance) { log.debug("saving Users instance"); try { getHibernateTemplate().saveOrUpdate(transientInstance); log.debug("save successful"); } catch (RuntimeException re) { log.error("save failed", re); throw re; } } public void update(User transientInstance) { log.debug("updating User instance"); try { getHibernateTemplate().update(transientInstance); log.debug("update successful"); } catch (RuntimeException re) { log.error("update failed", re); throw re; } } public void delete(User persistentInstance) { log.debug("deleting Users instance"); try { getHibernateTemplate().delete(persistentInstance); log.debug("delete successful"); } catch (RuntimeException re) { log.error("delete failed", re); throw re; } } public User findById( java.lang.Integer id) { log.debug("getting Users instance with id: " + id); try { User instance = (User) getHibernateTemplate() .get("project.hibernate.Users", id); return instance; } catch (RuntimeException re) { log.error("get failed", re); throw re; } } } Now I wrote a test class(not a junit test) to test is everything working, my user has these fields in the database : userID which is 5characters long string and unique/primary key, and fields such as address, dob etc(total 15 columns in database table). Now in my test class I intanciated User added the values like : User user = new User; user.setAddress("some address"); and so I did for all 15 fields, than at the end of assigning data to User object I called in DAO to save that to database UsersDao.save(user); and save works just perfectly. My question is how do I update/delete users using the same logic? Fox example I tried this(to delete user from table users): User user = new User; user.setUserID("1s54f"); // which is unique key for users no two keys are the same UsersDao.delete(user); I wanted to delete user with this key but its obviously different can someone explain please how to do these. thank you

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