Search Results

Search found 6015 results on 241 pages for 'bottom'.

Page 183/241 | < Previous Page | 179 180 181 182 183 184 185 186 187 188 189 190  | Next Page >

  • How to create a CGBitmapContext which works for Retina display and not wasting space for regular display?

    - by ????
    Is it true that if it is in UIKit, including drawRect, the HD aspect of Retina display is automatically handled? So does that mean in drawRect, the current graphics context for a 1024 x 768 view is actually a 2048 x 1536 pixel Bitmap context? (is there a way to print this size out to verify it). We actually enjoy the luxury of 1 point = 4 pixels automatically handled for us. However, if we use CGBitmapContextCreate, then those will really be pixels, not points? (at least if we provide a data buffer for that bitmap, the size is not for the higher resolution, but for the standard resolution, and even if we pass NULL as the buffer so that CGBitmapContextCreate handles the buffer for us, the size probably is the same as if we pass in a data buffer, and it is just standard resolution, not Retina's resolution). We can always create 2048 x 1536 for iPad 1 and iPad 2 as well as the New iPad, but it will waste memory and processor and GPU power, as it is only needed for the New iPad. So do we have to use a if () { } else { } to create such a bitmap context and how do we actually do so? And all our code CGContextMoveToPoint has to be adjusted for Retina display to use x * 2 and y * 2 vs non-retina display of just using x, y as well? That can be quite messy for the code. (or maybe we can define a local variable scaleFactor and set it to 1 for standard resolution and 2 if it is retina, so our x and y will always be x * scaleFactor, y * scaleFactor instead of just x and y.) It seems that UIGraphicsBeginImageContextWithOptions can create one for Retina automatically if the scale of 0.0 is passed in, but I don't think it can be used if I need to create the context and keep it (and using ivar or property of UIViewController to hold it). If I don't release it using UIGraphicsEndImageContext, then it stays in the graphics context stack, so it seems like I have to use CGBitmapContextCreate instead. (or do we just let it stay at the bottom of the stack and not worry about it?)

    Read the article

  • Java: how to get all subdirs recursively?

    - by HH
    Before debugging the late-hour-out-of-bound-recursive-function: is there a command to get subdirs? giveMeSubDirs(downToPath)? // WARNING: RECURSION out of bound public HashSet<FileObject> getAllDirs(String path) { HashSet<FileObject> checkedDirs = new HashSet<FileObject>(); HashSet<FileObject> allDirs = new HashSet<FileObject>(); String startingPath = path; File fileThing = new File(path); FileObject fileObject = new FileObject(fileThing); for (FileObject dir : getDirsInDir(path)) { // SUBDIR while ( !checkedDirs.contains(dir) && !(getDirsInDir(dir.getFile().getParent()).size() == 0)) { // DO NOT CHECK TOP DIRS if any bottom dir UNCHECKED! while ( uncheckedDirsOnLevel(path, checkedDirs).size() > 0) { while (getDirsInDir(path).size() == 0 || (numberOfCheckedDirsOnLevel(path, checkedDirs)==getDirsInDir(path).size())) { allDirs.add(new FileObject(new File(path))); checkedDirs.add(new FileObject(new File(path))); if(traverseDownOneLevel(path) == startingPath ) return allDirs; //get nearer to the root path = traverseDownOneLevel(path); } path = giveAnUncheckedDir(path, checkedDirs); if ( path == "NoUnchecked.") { checkedDirs.add(new FileObject( (new File(path)).getParentFile() )); break; } } } } return allDirs; }

    Read the article

  • Silverlight ValidationSummary screen real estate

    - by Mark Cooper
    Silverlight 3; I have a ValidationSummary in the top row of my grid. When the ValidationSummary appears, it pushes my button row (row 3) off the bottom of the displayable screen. <Grid HorizontalAlignment="Stretch" VerticalAlignment="Stretch"> <Grid.RowDefinitions> <RowDefinition Height="Auto" /> <RowDefinition Height="Auto" /> <RowDefinition Height="36" /> </Grid.RowDefinitions> <di:ValidationSummary Grid.Row="0" /> <Grid x:Name="gridOuterContentHolder" Grid.Row="1"> <Grid.RowDefinitions> <RowDefinition Height="0.68*" /> <RowDefinition Height="5" /> <RowDefinition Height="0.32*" /> </Grid.RowDefinitions> <!-- elements removed for brevity --> </Grid> <StackPanel x:Name="stack" Grid.Row="2" Orientation="Horizontal" HorizontalAlignment="Right"> <Button Content="Delete" x:Name="btnDelete" Height="20" Width="75" /> </StackPanel> </Grid> I'm a code monkey not a pixel pusher and can't figure out which combination of Stretch's, Auto's and *'s I need. Any pushers out there that can help?? Thanks, Mark

    Read the article

  • Adding a UIPickerView over a UITabBarController

    - by Kai
    I'm trying to have a UIPickerView slide from the bottom of the screen (over the top of a tab bar) but can't seem to get it to show up. The actual code for the animation is coming from one of Apple's example code projects (DateCell). I'm calling this code from the first view controller (FirstViewController.m) under the tab bar controller. - (IBAction)showModePicker:(id)sender { if (self.modePicker.superview == nil) { [self.view.window addSubview:self.modePicker]; // size up the picker view to our screen and compute the start/end frame origin for our slide up animation // // compute the start frame CGRect screenRect = [[UIScreen mainScreen] applicationFrame]; CGSize pickerSize = [self.modePicker sizeThatFits:CGSizeZero]; CGRect startRect = CGRectMake(0.0, screenRect.origin.y + screenRect.size.height, pickerSize.width, pickerSize.height); self.modePicker.frame = startRect; // compute the end frame CGRect pickerRect = CGRectMake(0.0, screenRect.origin.y + screenRect.size.height - pickerSize.height, pickerSize.width, pickerSize.height); // start the slide up animation [UIView beginAnimations:nil context:NULL]; [UIView setAnimationDuration:0.3]; // we need to perform some post operations after the animation is complete [UIView setAnimationDelegate:self]; self.modePicker.frame = pickerRect; // shrink the vertical size to make room for the picker CGRect newFrame = self.view.frame; newFrame.size.height -= self.modePicker.frame.size.height; self.view.frame = newFrame; [UIView commitAnimations]; // add the "Done" button to the nav bar self.navigationItem.rightBarButtonItem = self.doneButton; }} Whenever this action fires via a UIBarButtonItem that lives in a UINavigationBar (which is all under the FirstViewController) nothing happens. Can anyone please offer some advice?

    Read the article

  • How to prevent external translation of a movieclip object on stage in AS3?

    - by Aaron H.
    I have a MovieClip object, which is exported for actionscript (AS3) in an .swc file. When I place an instance of the clip on the stage without any modifications, it appears in the upper left corner, about half off stage (i.e. only the lower right quadrant of the object is visible). I understand that this is because the clip has a registration point which is not the upper left corner. If you call getBounds() on the movieclip you can get the bounds of the clip (presumably from the "point" that it's aligned on) which looks something like (left: -303, top: -100, right: 303, bottom: 100), you can subtract the left and top values from the clip x and y: clip.x -= bounds.left; clip.y -= bounds.top; This seems to properly align the clip fully on stage with the top left of the clip squarely in the corner of the stage. But! Following that logic doesn't seem to work when aligning it on the center of the stage! clip.x = (stage.stageWidth / 2); etc... This creates the crazy parallel universe where the clip is now down in the lower right corner of the stage. The only clue I have is that looking at: clip.transform.matrix and clip.transform.concatenatedMatrix matrix has a tx value of 748 (half of stage height) ty value of 426 (Half of stage height) concatenatedMatrix has a tx value of 1699.5 and ty value of 967.75 That's also obviously where the movieclip is getting positioned, but why? Where is this additional translation coming from?

    Read the article

  • LINQ query code for complex merging of data.

    - by Stacey
    I've posted this before, but I worded it poorly. I'm trying again with a more well thought out structure. Re-writing this a bit to make it more clear. I have the following code and I am trying to figure out the shorter linq expression to do it 'inline'. Please examine the "Run()" method near the bottom. I am attempting to understand how to join two dictionaries together based on a matching identifier in one of the objects - so that I can use the query in this sort of syntax. var selected = from a in items.List() // etc. etc. select a; This is my class structure. The Run() method is what I am trying to simplify. I basically need to do this conversion inline in a couple of places, and I wanted to simplify it a great deal so that I can define it more 'cleanly'. class TModel { public Guid Id { get; set; } } class TModels : List<TModel> { } class TValue { } class TStorage { public Dictionary<Guid, TValue> Items { get; set; } } class TArranged { public Dictionary<TModel, TValue> Items { get; set; } } static class Repository { static public TItem Single<TItem, TCollection>(Predicate<TItem> expression) { return default(TItem); // access logic. } } class Sample { public void Run() { TStorage tStorage = new TStorage(); // access tStorage logic here. Dictionary<TModel, TValue> d = new Dictionary<TModel, TValue>(); foreach (KeyValuePair<Guid, TValue> kv in tStorage.Items) { d.Add(Repository.Single<TModel, TModels>(m => m.Id == kv.Key),kv.Value); } } }

    Read the article

  • How to setup OpenGL camera for a racing game

    - by vian
    I need the view to show the road polygon (a rectangle 3.f * 100.f) with a vanishing point for a road being at 3/4 height of the viewport and the nearest road edge as a viewport's bottom side. See Crazy Taxi game for an example of what I wish to do. I'm using iPhone SDK 3.1.2 default OpenGL ES project template. I setup the projection matrix as follows: glMatrixMode(GL_PROJECTION); glLoadIdentity(); glFrustumf(-2.25f, 2.25f, -1.5f, 1.5f, 0.1f, 1000.0f); Then I use glRotatef to adjust for landscape mode and setup camera. glMatrixMode(GL_MODELVIEW); glLoadIdentity(); glRotatef(-90, 0.0f, 0.0f, 1.0f); const float cameraAngle = 45.0f * M_PI / 180.0f; gluLookAt(0.0f, 2.0f, 0.0f, 0.0f, 0.0f, 100.0f, 0.0f, cos(cameraAngle), sin(cameraAngle)); My road polygon triangle strip is like this: static const GLfloat roadVertices[] = { -1.5f, 0.0f, 0.0f, 1.5f, 0.0f, 0.0f, -1.5f, 0.0f, 100.0f, 1.5f, 0.0f, 100.0f, }; And I can't seem to find the right parameters for gluLookAt. My vanishing point is always at the center of the screen.

    Read the article

  • how to show news without marquee tag

    - by shamim
    Without use of marquee tag I want to show news like below code.I want to use JavaScript instead of marquee tag. How to use JavaScript to do this? <marquee style="width: 292px; border-bottom: 1px solid rgb(221, 221, 221);" align="top" behavior="scroll" direction="up" onmouseout="this.start();" onmouseover="this.stop();" scrollamount="1" scrolldelay="25" truespeed="" id="mSpeed" bgcolor="#f1f2ec" height="500"> <div style="padding: 5px; height: 153px;" class="workshopDesc bottomHorzLine "> <div class="workshopTitle" align="left">Financial Management Training</div> <div class="workshopDate"><font color="#ff0000" size="1"><strong>Date: Friday, May 28, 2010</strong></font></div> <div class="workshopRPName"><strong>Resource Person: Saif Rahman<br>Independent Consultant in Business Case Development and Financial Management</strong></div> <div class="workshopDesc">Mr. Saif Rahman is an Independent Consultant in Business Case Development and Financial Management with rich experience of corporate sectors of both North America and South-East Asia.... <div style="float: right; width: 150px;" align="right"><img src="images/icons_more.gif" align="absmiddle" width="12" height="12" hspace="5"><a href="http://BdjobsTraining.com/workshop_formate.asp?TID=518" class="workshopLink" target="_blank">Click here for detail</a></div> </div> </div> </marquee>

    Read the article

  • How to simulate inner exception in C++

    - by Siva Chandran
    Basically I want to simulate .NET Exception.InnerException in C++. I want to catch exception from bottom layer and wrap it with another exception and throw again to upper layer. The problem here is I don't know how to wrap the catched exception inside another exception. struct base_exception : public std::exception { std::exception& InnerException; base_exception() : InnerException(???) { } // <---- what to initialize with base_exception(std::exception& innerException) : InnerException(innerException) { } }; struct func1_exception : public base_exception { const char* what() const throw() { return "func1 exception"; } }; struct func2_exception : public base_exception { const char* what() const throw() { return "func2 exception"; } }; void func2() { throw func2_exception(); } void func1() { try { func2(); } catch(std::exception& e) { throw func2_exception(e); // <--- is this correct? will the temporary object will be alive? } } int main(void) { try { func1(); } catch(base_exception& e) { std::cout << "Got exception" << std::endl; std::cout << e.what(); std::cout << "InnerException" << std::endl; std::cout << e.InnerException.what(); // <---- how to make sure it has inner exception ? } } In the above code listing I am not sure how to initialize the "InnerException" member when there is no inner exception. Also I am not sure whether the temporary object that is thrown from func1 will survive even after func2 throw?

    Read the article

  • Android - Correspondence between ImageView coordinates and Bitmap Pixels

    - by Matteo
    In my application I want the user to be able to select some content of an Image contained inside an ImageView. To select the content I subclassed the ImageView class making it implement the OnTouchListener so to draw over it a rectangle with borders decided by the user. Here is an example of the result of the drawing (to have an idea you can think of it as when you click with the mouse on your desktop and drag the mouse): Now I need to determine which pixels of the Bitmap image correspond to the selected part. It's kind of easy to determine which are the points of the ImageView belonging to the rectangle, but I don't know how to get the correspondent pixels, since the ImageView has a different aspect ratio than the original image. I followed the approach described especially here, but also here, but am not fully satisfied because in my opinion the correspondence made is 1 on 1 between pixels and points on the ImageView and does not give me all the correspondent pixels on the original image to the selected area. Calling hoveredRect the rectangle on the ImageView the points inside of it are: class Point { float x, y; @Override public String toString() { return x + ", " + y; } } Vector<Point> pointsInRect = new Vector<Point>(); for( int x = hoveredRect.left; x <= hoveredRect.right; x++ ){ for( int y = hoveredRect.top; y <= hoveredRect.bottom; y++ ){ Point pointInRect = new Point(); pointInRect.x = x; pointInRect.y = y; pointsInRect.add(pointInRect); } } How can I obtain a Vector<Pixels> pixelsInImage containing the correspondent pixels?

    Read the article

  • What is better in WPF for UI layout, using one Grid, or nested Grids.

    - by Matthijs Wessels
    I am making a UI in WPF, I have a bunch of functional areas and I use a Grid to organize it. Now the Grid that I want is not uniform, as in, some functional area will span multiple cells in the Grid. I was wondering what the best practise is in solving this. Should I create one grid and then for each functional area set it to span multiple cells, or should I split it up into multiple nested Grids. In this image, the leftmost panel (panels separated by the gray bar) is what I want. The middle panel shows one grid where the blue lines are overlapped by a functional area. The rightmost panel shows how I could do it with nested grids. You can see the green grid has one horizontal split. In the bottom cell is the yellow Grid with a vertical split. In side the left cell is the red Grid with again a horizontal split. I was just wondering what is best practise, the middle or the right panel.

    Read the article

  • Get available screen area in autohotkey

    - by Herms
    I'm trying to write a few simple AutoHotkey scripts for moving windows around, and I'm having trouble getting the correct screen size values. I'm trying to get the size of the usable area on the screen (generally the full screen resolution minus the taskbar, and maybe any other docked windows like the sidebar in Vista). Neither of the methods I've found for getting the screen width seems to work. None of the 3 methods I found to get the screen size are giving me the right values. Here's the test script I'm using (running on XP with the taskbar on the bottom at its default size): #7:: WinMove A,,0,0,A_ScreenWidth,A_ScreenHeight return #8:: ;SM_CXMAXIMIZED and SM_CYMAXIMIZED SysGet, ScreenWidth, 61 SysGet, ScreenHeight, 62 WinMove A,,0,0,ScreenWidth,ScreenHeight return #9:: ;SM_CXFULLSCREEN and SM_CYFULLSCREEN SysGet, ScreenWidth, 16 SysGet, ScreenHeight, 17 WinMove A,,0,0,ScreenWidth,ScreenHeight return #7 causes the window to take up the entire resolution, so it overlaps the taskbar. #8 causes the width to be larger than the resolution (I see the window's right edge show up on my secondary monitor) and the height is slightly too large, so the window partially overlaps the taskbar area. Looks like this is correct except for not taking into account the window decorations at the edges. #9 seems to have the correct width, but the height is too short. It looks like it's subtracting the taskbar's height from the resolution's height, but then subtracting another 30 pixels from it. I could just use what I have in #9 and add 30 to the height I get, but that feels too much like a hack that would break in other configurations. It seems like there has to be a way to get the available screen size properly, but I can't find it in AutoHotkey. For reference, this seems to give me what I need in Java: Toolkit.getDefaultToolkit().getScreenSize();

    Read the article

  • Twig templates, inheritances and block usage

    - by user846226
    I've created three templates using Twig. The first one has block A defined in it, the second one extends from the first one, but includes a third template which sets the content of block A. When loading, through the browser, the url which renders b.html.twig, the content in block A (defined by the 3th template) is not positioned block _A is defined. Example: <!-- base.html.twig --> {% block _css '' %} {% block _header '' %} {% block _content '' %} {% block _footer '' %} {% block _js '' %} <!-- layout.html.twig --> <!-- header and footer are placed in the raight zone --> {% extends ::base.html.twig %} {% block _header %} {% render "MyBundleBundle:Header:header" %} {% endblock %} {% block _footer %} {% render "MyBundleBundle:Footer:footer" %} {% endblock %} <!-- my_template.html.twig --> <!-- content is also placed in the right zone but css and js blocks in the included template are not placed where declared in base.html.twig --> {% extends MyBundleBundle::layout.html.twig %} {% block _content %} SOME_CONTENT {% include MyBundleBundle::my_included_template.html.twig %} {% endblock %} <!-- my_included_template.html.twig --> {% block _css %} <link.......................> {% endblock %} {% block _js %} <script..................> {% endblock %} MORE CONTENT BELONGING TO THE INCLUDED TEMPLATE What i expect here is, _css blocks content to appear on top of the page and _js block content at the bottom, but that's not happening. I hope you can see where i'm going wrong, thanks!

    Read the article

  • Setting WPF control background image using styles?

    - by aviv
    Hi, I have a set of buttons inside a stack panel. I want them all to have a background image. How can i do it using styles? since i don't want to set manually the Background image for each button. Here is a code snippet: <StackPanel Orientation="Horizontal" Height="100px" VerticalAlignment="Top"> <StackPanel.Resources> <Style TargetType="Button"> <Setter Property="Margin" Value="2,4" /> </Style> </StackPanel.Resources> <Button Width="127px" Height="79px" VerticalAlignment="Bottom"> <Button.Background> <ImageBrush ImageSource="images/Tab.png" /> </Button.Background> </Button> <Button>A</Button> <Button>R</Button> <Button>S</Button> </StackPanel> Thanks.

    Read the article

  • Positioning DIV's with Javascript

    - by Andrew P.
    I have two divs that I need to position horizontally dependent on the width of the user's screen. I've styled their vertical position in CSS, and I am trying to position them horizontally using Javascript. My divs: <div id="tl"> blah blah </div> <div id="bl"> blah blah </div> My CSS: #tl { position: absolute; top: -14px; right: 0; } #bl { position: absolute; bottom: 1px; right: 0; } My Javascript: var tl = document.getElementById('tl'); var bl = document.getElementById('bl'); var wide = parseInt(screen.width); var nudge = wide*.86; nudge = nudge+21; tl = tl.style; tl.right = ( parseInt(tl.right) + nudge ); bl = bl.style; bl.right = ( parseInt(bl.right) + nudge ); However... nothing happens. No errors, and definitely no movement from my divs. What am I doing wrong? Can anyone help?

    Read the article

  • jQuery accordion - different image for active sections

    - by Andrew Cassidy
    Hi, I'm using Ryan Stemkoski's "Stupid Simple Jquery Accordion Menu" which is available here: stemkoski.com/stupid-simple-jquery-accordion-menu/ Here is the javascript $(document).ready(function() { //ACCORDION BUTTON ACTION (ON CLICK DO THE FOLLOWING) $('.accordionButton').click(function() { //REMOVE THE ON CLASS FROM ALL BUTTONS $('.accordionButton').removeClass('on'); //NO MATTER WHAT WE CLOSE ALL OPEN SLIDES $('.accordionContent').slideUp('normal'); //IF THE NEXT SLIDE WASN'T OPEN THEN OPEN IT if($(this).next().is(':hidden') == true) { //ADD THE ON CLASS TO THE BUTTON $(this).addClass('on'); //OPEN THE SLIDE $(this).next().slideDown('normal'); } }); /*** REMOVE IF MOUSEOVER IS NOT REQUIRED ***/ //ADDS THE .OVER CLASS FROM THE STYLESHEET ON MOUSEOVER $('.accordionButton').mouseover(function() { $(this).addClass('over'); //ON MOUSEOUT REMOVE THE OVER CLASS }).mouseout(function() { $(this).removeClass('over'); }); /*** END REMOVE IF MOUSEOVER IS NOT REQUIRED ***/ /******************************************************************************************************************** CLOSES ALL S ON PAGE LOAD ********************************************************************************************************************/ $('.accordionContent').hide(); }); and the CSS #wrapper { width: 800px; margin-left: auto; margin-right: auto; } .accordionButton { width: 800px; float: left; _float: none; /* Float works in all browsers but IE6 */ background: #003366; border-bottom: 1px solid #FFFFFF; cursor: pointer; } .accordionContent { width: 800px; float: left; _float: none; /* Float works in all browsers but IE6 */ background: #95B1CE; } /*********************************************************************************************************************** EXTRA STYLES ADDED FOR MOUSEOVER / ACTIVE EVENTS ************************************************************************************************************************/ .on { background: #990000; } .over { background: #CCCCCC; } There is an "on" class which allows the style of the accordionButton class when it is active but I would like to be able to have each active accordionButton class have a different image. http://www.thepool.ie For example, in the above site the word "WORK" should be a darker grey image when the work section is selected, so should COLLAB when it is selected etc. I can't figure out how to do this, any help would be greatly appreciated. Thanks, Andrew

    Read the article

  • Text size for drop down menu/input select not working in Safari

    - by Nick
    Hello All, First question... I'm having trouble getting ANY of the Drop down menu/Input Select's to appear with size 18 font in Safari. Works fine in FF. Code: <form class="form"> <select name="make"> <option value="0"> All</option> </select> </form> Css: .form input{ font-size:18px; margin-bottom:0px; } Any ideas? Can view live at [http://www.motolistr.com][1] Best, Nick EDIT 1: Thanks for the quick reply. I added a style to the select itself to avoid confusion. I tried; <select name='make' style='font-size: 18pt;'> </select> And <select name='make' style='font-size: 18px;'> </select> And <select name='make' style='font-size: 1.3em;'> </select> Still not working in SAFARI...Again FF works fine with all 3. Best, Nick

    Read the article

  • Looping login with Facebook JS SDK and Rails

    - by nafe
    I'm using the Facebook JS SDK for single-sign with my rails app. I translated the php code from the Facebook example (at the bottom of the page under "Single Sign-on with the JavaScript SDK") into ruby. This appeared to be working great but I've noticed one user that gets continual redirects when trying to login. The logs look like: Processing UsersController#login (for X.X.X.X at 2010-05-22 17:25:55) [GET] Redirected to http://myapp.com/ Completed in 0ms (DB: 0) | 302 Found [http://myapp.com/login] (times as many entries as my unfortunate user leaves the browser redirecting in a loop). My client side code includes a callback with the "auth.sessionChange": FB.Event.subscribe('auth.sessionChange', function(response) { if (response.session) { // A user has logged in, and a new cookie has been saved window.location = "/login"; } else { // The user has logged out, and the cookie has been cleared window.location = "/logout"; } }); So it seems to me like this event is continually firing. Although, I can't test this theory because I can't recreate this scenario locally. I don't think it's the rails controller. The code here is just: def login # if first time user create db entry # now redirect back to where the user came from begin redirect_to :back rescue ActionController::RedirectBackError redirect_to root_url end end Does anyone have any idea on what's going on?

    Read the article

  • Inactive area after device rotation

    - by Sébastien
    Hi all, I don't understand what's wrong in my very simple application with device rotation : I built my view with interface builder. (See screen capture here) I specified <key>UIInterfaceOrientation</key><string>UIInterfaceOrientationLandscapeRight</string> in my info.plist file. I had a (BOOL)shouldAutorotateToInterfaceOrientation:(UIInterfaceOrientation)interfaceOrientation {return YES;} in my root view controller. The area on the left (shown in red on the capture), around 20 pixel width, keeps inactive (nothing append if I hit a button in this area). In fact the full screen is active only in portrait mode, in landscape right mode there is this 20 pixels width inactive area, in landscape left mode this inactive area is on the right, in portrait upside down mode this area is on the bottom. I read lots of posts and documentation about UIView rotation, but I did not find anything to solve this problem (I tried to play with view.frame and view.bounds without any success). Anybody has an idea ? Thanks a lot. Regards. Sébastien.

    Read the article

  • Error when decoding image C# asp

    - by Wayneio
    I am trying to use MessagingToolkit to decode an image in C#/ASP. I have managed to encode a qr using this package, but when i try to decode, using the code below it comes up with 2 errors (at the bottom of the page) I believe this is because I am not getting the image correctly after uploading, but can someone point out exactly where I have gone wrong. Thanks. protected void CreateCode_OnClick(object sender, EventArgs e) { string path = "C:\\Users\\Wayneio\\Documents\\Visual Studio 2012\\Projects\\BAMSystem\\BAMSystem\\"; if (QRUpload.HasFiles == true) { FileInfo fi = new FileInfo(QRUpload.FileName); string extA = fi.Extension; if (extA == ".jpg" || extA == ".png") { QRCodeDecoder decoder = new QRCodeDecoder(); QRUpload.SaveAs(path + QRUpload.FileName); System.Drawing.Image myImg = System.Drawing.Image.FromFile(path + QRUpload.FileName); decoder.Decode(myImg); } else { error.Text = "You have uploaded a " + extA + " file. Please upload either a PNG or a JPG"; } } else { error.Text = "You have not uploaded an image."; } } Error1: Error 2 Argument 1: cannot convert from 'System.Drawing.Image' to 'MessagingToolkit.QRCode.Codec.Data.QRCodeImage' c:\users\wayneio\documents\visual studio 2012\Projects\BAMSystem\BAMSystem\default.aspx.cs 38 35 BAMSystem Error2: Error 1 The best overloaded method match for 'MessagingToolkit.QRCode.Codec.QRCodeDecoder.Decode(MessagingToolkit.QRCode.Codec.Data.QRCodeImage)' has some invalid arguments c:\users\wayneio\documents\visual studio 2012\Projects\BAMSystem\BAMSystem\default.aspx.cs 38 20 BAMSystem P.S if anyone has documentation on this MessagingToolkit QR package, it would be useful

    Read the article

  • Ruby script/console and Ruby script/server using two different DBs?

    - by aronchick
    Has anyone seen where script/console and script/server load two different databases (though both report using the same)? Here's the first output $ script/server => Booting WEBrick => Rails 2.3.5 application starting on http://0.0.0.0:3000 => Call with -d to detach => Ctrl-C to shutdown server [2010-03-21 15:54:05] INFO WEBrick 1.3.1 [2010-03-21 15:54:05] INFO ruby 1.8.7 (2010-01-10) [i386-mingw32] [2010-03-21 15:54:05] INFO WEBrick::HTTPServer#start: pid=7148 port=3000 No errors. I then run my standard code for entering a form - no problems. Checking the Dev Database (.yml at bottom): mysql> select * from books; [...] | 712 | Book | Book Name | 2010-03-21 22:29:22 | 2010-03-21 22:29:22 | [...] 712 rows in set (0.00 sec) The code CLEARLY saved it seconds ago And now here's the output of script/console: $ script/console Loading development environment (Rails 2.3.5) >> Books.all => [] Nothing. Further, upon further inspection, it's using the production database, but I can't figure out why. Any thoughts here? All consoles have been closed and reopened. UPDATE: Requested .yml file (can't see how it'd be helpful (user name and password are all the same for each)) - development: adapter: mysql database: BooksDBdev username: <user name> password: <long string> timeout: 5000 # Warning: The database defined as "test" will be erased and # re-generated from your development database when you run "rake". # Do not set this db to the same as development or production. test: adapter: mysql database: BooksDBtest username: <user name> password: <long string> timeout: 5000 production: adapter: mysql database: BooksDB username: <user name> password: <long string> timeout: 5000

    Read the article

  • How do I code a loop for my echo statement?

    - by ggg
    I get only one printed result in the foreach echo loop at the bottom of the page. <?php defined('_JEXEC') or die('Restricted access'); $db =& JFactory::getDBO(); $query0 = "SELECT * FROM `jos_ginfo` WHERE . . . LIMIT 30"; //echo $query0; $db->setQuery($query0); $ginfo = $db->loadObjectList(); //echo //$ginfo[0]; foreach($ginfo as $ginfo[$i]): {$i=0; $i++;} endforeach; echo $db->getErrorMsg(); if(empty($ginfo)){ echo "<center>No game found, try a different entry.</center>"; }else{ $pgndata = array ( $ginfo[$i]->Id); $i=0; foreach($pgndata as $ginfo[$i]->Id): //I am only getting one printed result! { echo "<a href='/index.php?option=com_publishpgn&tactical-game=".$ginfo[$i]->Id."&Itemid=78.html'>\n"; echo "".$ginfo[$i]->White." v. ".$ginfo[$i]->Black." (".$ginfo[$i]->Result.") ".$ginfo[$i]->EventDate." ECO:".$ginfo[$i]->ECO."</a><br>\n"; $i++; } endforeach; //echo "</div>"; } ?>

    Read the article

  • Is MVC 2 client-side validation broken in Visual Studio 2010 RC?

    - by Will
    I can't seem to get client side validation working with the version of MVC released with Visual Studio 2010 RC. I've tried it with two projects -- one upgrade from 1.0, and one using the template that came with VS. I'd think the template version would work, but it doesn't. Added the following scripts: <script type="text/javascript" src="<%= Url.Content("~/Scripts/MicrosoftMvcValidation.js") %>"> </script> <script type="text/javascript" src="<%= Url.Content("~/Scripts/jquery.validate.js")%>"> </script> which are downloaded to the client correctly. Added the following to my form page: <% Html.EnableClientValidation(); %> <%--yes, am aware of the EndForm() bug! --%> <% using (Html.BeginForm()) { %> <%--snip --%> and I can see the client validation scripts have been added to the bottom of the form. But still client validation never happens. What is worse is that in my upgraded project, the client validation scripts are never output in the page! PLEASE NOTE: I am specifically asking about the version of MVC2 that came with VS2010 RC. Also, I do know how to google; please don't waste anybody's time searching and answering if you aren't familiar with this issue in the release candidate of Visual Studio. Thanks.

    Read the article

  • WPF In-Memory Image Display

    - by Aren B
    Im trying to build an Item Template for my list-view and im bound to a list of Entities. The entity I have has a System.Drawing.Image that I'd like to display, but so far I cannot for the life of me figure out how to bind it to the <Image> block. Every example and documentation I can find on the internet pertains to Images accessible via an uri i.e. File on HDD or On Website <DataTemplate x:Key="LogoPreviewItem"> <Border BorderBrush="Black" BorderThickness="1"> <DockPanel Width="150" Height="100"> <Image> <Image.Source> <!-- {Binding PreviewImage} is where the System.Drawing.Image is in this context --> </Image.Source> </Image> <Label DockPanel.Dock="Bottom" Content="{Binding CustomerName}" /> </DockPanel> </Border> </DataTemplate>

    Read the article

  • Custom UIView using CALayers disappears after 180º rotation or navigation controller pop

    - by Steve Madsen
    I have a created a custom UIView subclass that is exhibiting some strange behavior. It is a spinning wheel selector, and for performance reasons it is drawn entirely into two CALayer instances. The bottom layer is the wheel itself, which is rotated using setAffineTransform: according to touches. The top layer is eye candy. drawRect: is fairly simple. If the control hasn't been drawn yet (or it's been invalidated), it calls a method that creates the images and assigns them to the layer contents property. - (void) drawRect:(CGRect)rect { if (imageLayer == nil) { [self drawIntoImageLayer]; } [self updateWheelRotation]; } When the view controller using this view first appears, everything is fine. There are two instances where the view completely disappears, however: If the device is rotated a full 180°. After a view controller is popped off the navigation stack and the view becomes visible again. drawRect: is not called either time. Interestingly enough, it IS called after a 90° orientation change, and that causes the view to re-appear. How can I ensure that a custom view using CALayers is redrawn properly in these situations?

    Read the article

< Previous Page | 179 180 181 182 183 184 185 186 187 188 189 190  | Next Page >