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  • How do I add a property to a Javascript Object using a variable as the name?

    - by Todd R
    I'm pulling items out of the DOM with JQuery and want to set a property on an object using the id of the DOM element. For example: obj = {}; jQuery(itemsFromDom).each(function() { element = jQuery(this); name = element.attr("id"); value = element.attr("value"); //Here's the problem obj.name = value; }); If "itemsFromDom" includes an element with an id of "myId", I want "obj" to have a property named "myId". The above gives me "name". How, in javascript, do I name a property of an object using a variable?

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  • How to add "missing" columns in a column group in reporting services?

    - by Gimly
    Hello, I'm trying to create a report that displays for each months of the year the quantity of goods sold. I have a query that returns the list of goods sold for each month, it looks something like this : SELECT Seller.FirstName, Seller.LastName, SellingHistory.Month, SUM(SellingHistory.QuantitySold) FROM SellingHistory JOIN Seller on SellingHistory.SellerId = Seller.SellerId WHERE SellingHistory.Year = @Year GOUP BY Seller.FirstName, Seller.LastName, SellingHistory.Month What I want to do is display a report that has a column for each months + a total column that will display for each Seller the quantity sold in the selected month. Seller Name | Jan | Feb | Mar | Apr | May | Jun | Jul | Aug | Sep | Oct | Nov | Dec | Total What I managed to do is using a matrix and a column group (group on Month) to display the columns for existing data, if I have data from January to March, it will display the 3 first columns and the total. What I would like to do is always display all the columns. I thought about making that by adding the missing months in the SQL request, but I find that a bit weird and I'm sure there must be some "cleanest" solution as this is something that must be quite frequent. Thanks. PS: I'm using SQL Server Express 2008

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  • How to add ease to this, with jQuery Easing plugin.

    - by user1691441
    I've asked this question previously before, and had a bit of help, but my lack of jQuery skills still didn't accomplish the job. I was wondering if anyone else could help me out with this. I've tried adding easing: "easeIn" right after the duration section, but still didn't work for me. if anyone could help me out that would be wonderful. I'm using the jquery easing plugin $(function() { function scroll(direction) { var scroll, i, positions = [], here = $(window).scrollTop(), collection = $('.part'); collection.each(function() { positions.push(parseInt($(this).offset()['top'],10)); }); for(i = 0; i < positions.length; i++) { if (direction == 'next' && positions[i] > here) { scroll = collection.get(i); break; } if (direction == 'prev' && i > 0 && positions[i] >= here) { scroll = collection.get(i-1); break; } } if (scroll) { $.scrollTo(scroll, { duration: 350 }); } return false; } $("#next,#prev").click(function() { return scroll($(this).attr('id')); }); $(".scrolltoanchor").click(function() { $.scrollTo($($(this).attr("href")), { duration: 350 }); return false; }); });

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  • How to add Transparency information to a HEX color code?

    - by TK123
    I have to modify some code and the previous developer left this comment: color: color, // e.g. '#RRGGBBFF' - Last 2 digits are alpha information On the page there is a color picker that let's the user change text color. It gives HEX values like so: #RRGGBB And there is a slider that allows the user to change a text's transparency. It runs from 0.1 to 1 Somehow I need to get a 2 digit letter from this transparency amount and append it to the HEX value for it to work. Does anyone know how to append Alpga information to HEX color codes? What is the math formula for it? I guess the question can also be answered if anyone knows how to concert RGBA color values with transparency into HEX: rgba(255, 255, 255, 0.6)

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  • How can I add two CSS heights of different divs and make that the height to another div with jquery

    - by NW Tech
    I have three divs, 1 floated left and the other two floated right (they're stacked). I'm trying to combine the height of the two on the right and apply that height to the one on the left. This is what I have, with no luck $(window).bind("load", function() { var slw = $('div.2').height(); var lw = $('div.3').height(); var result = slw += lw; $('div.1').css({ 'height': result + 'px' }); }); TIA

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  • How to add style to parent <li> item if child <ul> exists?

    - by user1292760
    I'm trying to make a menu in advance to be seen whether there is a double nesting. <ul class="parent"> <li class="child"></li> <li class="child"> <ul slass="nesting"> <li></li> <li></li> </ul> </li> <li class="child"></li> </ul> So ul class="nesting" hidden by default but appears during the hover of li class="child". I want to make another design on the li class="child" which have a nested ul. Another words how can i show nesting before hover by the means of Javascript/JQuery? Thnaks in advance!

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  • Python : How to add month to December 2012 and get January 2013?

    - by daydreamer
    >>> start_date = date(1983, 11, 23) >>> start_date.replace(month=start_date.month+1) datetime.date(1983, 12, 23) This works until the month is <=11, as soon as I do >>> start_date = date(1983, 12, 23) >>> start_date.replace(month=start_date.month+1) Traceback (most recent call last): File "<stdin>", line 1, in <module> ValueError: month must be in 1..12 How can I keep adding months which increments the year when new month is added to December?

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  • Why can't I dynamically add rows to a HTML table using JavaScript in Internet Explorer?

    - by karlthorwald
    In Firefox it works, in my Internet Explorer 6 or 7 it doesn't: <html> <head> <script type="text/javascript"> function newLine() { var tdmod = document.createElement('td'); tdmod.appendChild(document.createTextNode("dynamic")); var tr = document.createElement('tr'); tr.appendChild(tdmod); var tt = document.getElementById("t1"); tt.appendChild(tr); } </script> </head> <body> <a href="#" onclick="newLine()">newLine</a> <table id="t1" border="1"> <tr> <td> static </td> </tr> </table> </body> The user clicks on the link "newLine" and new rows should be added to the table. How to make this work also in IE? Edit: Thanks to the accepted answer I changed it like this and now it works: <table border="1"> <tbody id="t1"> <tr> <td> static </td> </tr> </tbody> </table>

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  • Add a custom class name to Wordpress body tag?

    - by Scott B
    I'd like to place a directive in my theme's functions.php file which appends a classname to the wordpress body tag. Is there a built-in API method for this? For example, my body tag code is... <body <?php if(function_exists("body_class") && !is_404()){body_class();} else echo 'class="page default"'?>> And it results in the following being written to the body tag (depending on the context in which the page is presented (page, post, logged-in, etc) <body class="home blog logged-in"> Depending on the child theme I'm using at the time, I want it to be... <body class="home blog logged-in mychildthemename">

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  • How to add values accordingly of the first indices of a dictionary of tuples of a list of strings? Python 3x

    - by TheStruggler
    I'm stuck on how to formulate this problem properly and the following is: What if we had the following values: {('A','B','C','D'):3, ('A','C','B','D'):2, ('B','D','C','A'):4, ('D','C','B','A'):3, ('C','B','A','D'):1, ('C','D','A','B'):1} When we sum up the first place values: [5,4,2,3] (5 people picked for A first, 4 people picked for B first, and so on like A = 5, B = 4, C = 2, D = 3) The maximum values for any alphabet is 5, which isn't a majority (5/14 is less than half), where 14 is the sum of total values. So we remove the alphabet with the fewest first place picks. Which in this case is C. I want to return a dictionary where {'A':5, 'B':4, 'C':2, 'D':3} without importing anything. This is my work: def popular(letter): '''(dict of {tuple of (str, str, str, str): int}) -> dict of {str:int} ''' my_dictionary = {} counter = 0 for (alphabet, picks) in letter.items(): if (alphabet[0]): my_dictionary[alphabet[0]] = picks else: my_dictionary[alphabet[0]] = counter return my_dictionary This returns duplicate of keys which I cannot get rid of. Thanks.

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