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• LINQ to SQL join when there aren't results

  - by Boarder2

  Given the following database structure I'm trying to write a LINQ query that will return images grouped by tags it's associated with. So far I've got this: var images = from img in db.Images join imgTags in db.ImageTags on img.idImage equals imgTags.idImage join t in db.Tags on imgTags.idTag equals t.idTag where img.OCRData.Contains(searchText.Text) group img by new { t.TagName } into aGroup select new { GroupName = aGroup.Key.TagName, Items = from x in aGroup select new ImageFragment() { ImageID = x.idImage, ScanDate = x.ScanTime } }; Which works great. However, I also want to return Images that do not have any tags associated with them in a group of "(Untagged)" or something. I can't wrap my head around how I would do this without inserting a default tag for every image and that seems like generally not a very good solution.

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• Selecting data from SQL Server table according to Month

  - by MarceloRamires

  I have to come up with a way to get data from a SQL server table given it's month There's a smalldatetime type field called "date" in the "events" table and a field from it looks like this: 29/01/2003 17:00:00 It should be one among those that appear in the gridview when I select jan/03 in a given DropDownList control in ASP.NET. What would be the best way to do this? Assuming I only want to go as long as 10 years to the past, wouldn't making a dictionary be a good way? How do I change it so the top month is always the current, and each month another options appeaars in the dropdown ? It should be a common issue, so that shall not be a trick, but I want a good and clean way of doing this, and (since I'm new to asp.net) I myself would come up with something messy after a long time trying. So what I want is: -Select -Best way of populating DropDownList (with the current month always at the top) -Best way to bind the DropDownList user-friendly way of writing months to the select query-friendly way of writing datetimes Info: ASP.NET, (C# or VB.NET), SQL Server 2005

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• SQL SELECT: "Give me all documents where all of the documents procedures are 'work in progress'"

  - by prestonmarshall

  This one really has me stumped. I have a documents table which hold info about the documents, and a procedures table, which is kind of like a revisions table for each document. What I need to do is write a select statement which gives me all of the documents where all of the procedures have the status "work_in_progress". Here's an example procedures table: document_id | status 1 | 'wip' 1 | 'wip' 1 | 'wip' 1 | 'approved' 2 | 'wip' 2 | 'wip' 2 | 'wip' Here, I would want my query to only return document id 2, because all of its statuses are work_in_progress. I DO NOT want document_id 1 since one of its statuses is 'approved'. I believe this is relational division I want, but I'm not sure where to start. This is MySQL 5.0 FYI.

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• SQL Server 2005 Error 701 - out of memory

  - by Tufo

  I'm currently having following error message when executing a .sql file with about 26MB on SQL Server 2005: Msg 701, Level 17, State 123 There is insufficient system memory to run this query. I'm working with 4GB RAM, 64Bit Windows 7 Ultimate, Core2Duo T6400(2GHz)... Is there a way to execute it without receiving this message (maybe force SQL Server to use swap file?) or a way to execute it in parts (like 100 queries a time)... The file is basically a CREATE TABLE followed by thousads of INSERT queries and I have a lot of those (converted .DBF files to SQL queries using ABC DBF Converter) Any idea will be very appreciated!

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• using PHP to create multidimensional array from simple JSON array

  - by Michael Robinson

  I have a php query the returns the following JSON format from a table. [{"memberid":"18", "useridFK":"30", "loginName":"Johnson", "name":"Frank", "age":"23", "place":"School", }, It needs the following format: [{"memberid":"18" { "useridFK":"30", "loginName":"Johnson", "name":"Frank", "age":"23", "place":"School",} }, I was told in another question that PHP would work and it looks like "Transversing" might be appropriate, I'm looking to find out what to put in the Php before it returns the JASON. My Array.plist will look like the following: Root: Dictionary V Rows: Array V Item 0: Dictionary Title: String 18 V Children Array V Item 0 Dictionary Title String 30 etc. Thanks in advance.

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• Best way to optimize queries like this in Django

  - by chris

  I am trying to lower the amount of queries that my django app is using, but I am a little confused on how to do it. I would like to get a query set with one hit to the database and then filter items from that set. I have tried a couple of things, but I always get queries for each set. let's say I want to get all names from my DB, but also separate out the people just named Ted. Both the names and the ted set will be used in the template. This will give me two sets, one with all names and one with Ted.. but also hits the database twice: namelist = People.objects.all() tedList = namelist.filter(name='ted') Is there a way to filter the first set without hitting the data base again?

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• mysql select from a table depending on in which table the data is in

  - by user253530

  I have 3 tables holding products for a restaurant. Products that reside in the bar, food and ingredients. I use php and mysql. I have another table that holds information about the orders that have been made so far. There are 2 fields, the most important ones, that hold information about the id of the product and the type (from the bar, from the kitchen or from the ingredients). I was thinking to write the sql query like below to use either the table for bar products, kitchen or ingredients but it doesn't work. Basically the second table on join must be either "bar", "produse" or "stoc". SELECT K.nume, COUNT(K.cantitate) as cantitate, SUM(K.pret) as pret, P.nume as NumeProduse FROM `clienti_fideli` as K JOIN if(P.tip,bar,produse) AS P ON K.produs = P.id_prod WHERE K.masa=18 and K.nume LIKE 'livrari-la-domiciliu' GROUP BY NumeProduse

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• MySQL top count({column}) with a limit

  - by Josh K

  I have a table with an ip address column. I would like to find the top five addresses which are listed. Right now I'm planning it out the following: Select all distinct ip addresses Loop through them all saying count(id) where IP='{ip}' and storing the count List the top five counts. Downsides include what if I have 500 ip addresses. That's 500 queries I have to run to figure out what are the top five. I'd like to build a query like so select ip from table where 1 order by count({distinct ip}) asc limit 5

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• Create date efficiently

  - by Dave Jarvis

  On Pavel's page is the following function: CREATE OR REPLACE FUNCTION makedate(year int, dayofyear int) RETURNS date AS $$ SELECT (date '0001-01-01' + ($1 - 1) * interval '1 year' + ($2 - 1) * interval '1 day'):: date $$ LANGUAGE sql; I have the following code: makedate(y.year,1) What is the fastest way in PostgreSQL to create a date for January 1st of a given year? Pavel's function would lead me to believe it is: date '0001-01-01' + y.year * interval '1 year' + interval '1 day'; My thought would be more like: to_date( y.year||'-1-1', 'YYYY-MM-DD'); Am looking for the fastest way using PostgreSQL 8.4. (The query that uses the date function can select between 100,000 and 1 million records, so it needs speed.) Thank you!

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• How to find N Consecutive records in a table using SQL

  - by user320587

  Hi, I have the following Table definition with sample data. In the following table, Customer Product & Date are key fields Table One Customer Product Date SALE X A 01/01/2010 YES X A 02/01/2010 YES X A 03/01/2010 NO X A 04/01/2010 NO X A 05/01/2010 YES X A 06/01/2010 NO X A 07/01/2010 NO X A 08/01/2010 NO X A 09/01/2010 YES X A 10/01/2010 YES X A 11/01/2010 NO X A 12/01/2010 YES In the above table, I need to find the N or N consecutive records where there was no sale, Sale value was 'NO' For example, if N is 2, the the result set would return the following Customer Product Date SALE X A 03/01/2010 NO X A 04/01/2010 NO X A 06/01/2010 NO X A 07/01/2010 NO X A 08/01/2010 NO Can someone help me with a SQL query to get the desired results. I am using SQL Server 2005. I started playing using ROW_NUMBER() AND PARTITION clauses but no luck. Thanks for any help

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• Need help with testdisk output

  - by dan

  I had (note the past tense) an ubuntu 12.04 system with separate partitions for the base and /home directories. It started acting wonky, so I decided to do a reinstall with 12.10, intending just to do a reinstall to the base partition. After several seconds, I realize that the installer was repartitioning the drive and reinstalling, so I pulled the power cord. I'm now trying to recover as much as I can with testdisk, but it seems that testdisk is finding 100 unique partitions when I run it - they mostly tend to be HFS+ or solaris /home (which I think is just an ext4; I've never had solaris on the machine). I've pasted an abbreviated version of the testdisk output below (first ~100 lines, and then ~100 lines from the middle of the output). Is there a way to combine or recreate the partitions and then data recovery, or some other way maximize what I can recover (ideally as much of the file system as possible)? I really only care about what was in the /home directory - I'd rather not use photorec since I don't have another 2 TB HD lying around to recover to. Thanks, Dan Mon Dec 10 06:03:00 2012 Command line: TestDisk TestDisk 6.13, Data Recovery Utility, November 2011 Christophe GRENIER <[email protected]> http://www.cgsecurity.org OS: Linux, kernel 3.2.34-std312-amd64 (#2 SMP Sat Nov 17 08:06:32 UTC 2012) x86_64 Compiler: GCC 4.4 Compilation date: 2012-11-27T22:44:52 ext2fs lib: 1.42.6, ntfs lib: libntfs-3g, reiserfs lib: 0.3.1-rc8, ewf lib: none /dev/sda: LBA, HPA, LBA48, DCO support /dev/sda: size 3907029168 sectors /dev/sda: user_max 3907029168 sectors /dev/sda: native_max 3907029168 sectors Warning: can't get size for Disk /dev/mapper/control - 0 B - CHS 1 1 1, sector size=512 /dev/sr0 is not an ATA disk Hard disk list Disk /dev/sda - 2000 GB / 1863 GiB - CHS 243201 255 63, sector size=512 - WDC WD20EARS-00J2GB0, S/N:WD-WCAYY0075071, FW:80.00A80 Disk /dev/sdb - 1013 MB / 967 MiB - CHS 1014 32 61, sector size=512 - Generic Flash Disk, FW:8.07 Disk /dev/sr0 - 367 MB / 350 MiB - CHS 179470 1 1 (RO), sector size=2048 - PLDS DVD+/-RW DH-16AAS, FW:JD12 Partition table type (auto): Intel Disk /dev/sda - 2000 GB / 1863 GiB - WDC WD20EARS-00J2GB0 Partition table type: EFI GPT Analyse Disk /dev/sda - 2000 GB / 1863 GiB - CHS 243201 255 63 Current partition structure: Bad GPT partition, invalid signature. search_part() Disk /dev/sda - 2000 GB / 1863 GiB - CHS 243201 255 63 recover_EXT2: s_block_group_nr=0/14880, s_mnt_count=5/4294967295, s_blocks_per_group=32768, s_inodes_per_group=8192 recover_EXT2: s_blocksize=4096 recover_EXT2: s_blocks_count 487593984 recover_EXT2: part_size 3900751872 MS Data 2048 3900753919 3900751872 EXT4 Large file Sparse superblock, 1997 GB / 1860 GiB Linux Swap 3900755968 3907028975 6273008 SWAP2 version 1, 3211 MB / 3062 MiB Results P MS Data 2048 3900753919 3900751872 EXT4 Large file Sparse superblock, 1997 GB / 1860 GiB P Linux Swap 3900755968 3907028975 6273008 SWAP2 version 1, 3211 MB / 3062 MiB interface_write() 1 P MS Data 2048 3900753919 3900751872 2 P Linux Swap 3900755968 3907028975 6273008 search_part() Disk /dev/sda - 2000 GB / 1863 GiB - CHS 243201 255 63 recover_EXT2: s_block_group_nr=0/14880, s_mnt_count=5/4294967295, s_blocks_per_group=32768, s_inodes_per_group=8192 recover_EXT2: s_blocksize=4096 recover_EXT2: s_blocks_count 487593984 recover_EXT2: part_size 3900751872 MS Data 2048 3900753919 3900751872 EXT4 Large file Sparse superblock, 1997 GB / 1860 GiB block_group_nr 1 recover_EXT2: "e2fsck -b 32768 -B 4096 device" may be needed recover_EXT2: s_block_group_nr=1/14880, s_mnt_count=0/4294967295, s_blocks_per_group=32768, s_inodes_per_group=8192 recover_EXT2: s_blocksize=4096 recover_EXT2: s_blocks_count 487593984 recover_EXT2: part_size 3900751872 MS Data 2046 3900753917 3900751872 EXT4 Large file Sparse superblock Backup superblock, 1997 GB / 1860 GiB block_group_nr 1 recover_EXT2: "e2fsck -b 32768 -B 4096 device" may be needed recover_EXT2: s_block_group_nr=1/14880, s_mnt_count=0/4294967295, s_blocks_per_group=32768, s_inodes_per_group=8192 recover_EXT2: s_blocksize=4096 recover_EXT2: s_blocks_count 487593984 recover_EXT2: part_size 3900751872 MS Data 2048 3900753919 3900751872 EXT4 Large file Sparse superblock Backup superblock, 1997 GB / 1860 GiB block_group_nr 1 recover_EXT2: "e2fsck -b 32768 -B 4096 device" may be needed recover_EXT2: s_block_group_nr=1/14584, s_mnt_count=0/27, s_blocks_per_group=32768, s_inodes_per_group=8192 recover_EXT2: s_blocksize=4096 recover_EXT2: s_blocks_count 477915164 recover_EXT2: part_size 3823321312 MS Data 4094 3823325405 3823321312 EXT4 Large file Sparse superblock Backup superblock, 1957 GB / 1823 GiB block_group_nr 1 ....snip...... MS Data 2046 3900753917 3900751872 EXT4 Large file Sparse superblock Backup superblock, 1997 GB / 1860 GiB MS Data 2048 3900753919 3900751872 EXT4 Large file Sparse superblock, 1997 GB / 1860 GiB MS Data 4094 3823325405 3823321312 EXT4 Large file Sparse superblock Backup superblock, 1957 GB / 1823 GiB MS Data 4096 3823325407 3823321312 EXT4 Large file Sparse superblock Backup superblock, 1957 GB / 1823 GiB MS Data 7028840 7033383 4544 FAT12, 2326 KB / 2272 KiB Mac HFS 67856948 67862179 5232 HFS+ found using backup sector!, 2678 KB / 2616 KiB Mac HFS 67862176 67867407 5232 HFS+, 2678 KB / 2616 KiB Mac HFS 67862244 67867475 5232 HFS+ found using backup sector!, 2678 KB / 2616 KiB Mac HFS 67867404 67872635 5232 HFS+, 2678 KB / 2616 KiB Mac HFS 67867472 67872703 5232 HFS+, 2678 KB / 2616 KiB Mac HFS 67872700 67877931 5232 HFS+, 2678 KB / 2616 KiB Mac HFS 67937834 67948067 10234 [EasyInstall_OSX] HFS found using backup sector!, 5239 KB / 5117 KiB Mac HFS 67938012 67948155 10144 HFS+ found using backup sector!, 5193 KB / 5072 KiB Mac HFS 67948064 67958297 10234 [EasyInstall_OSX] HFS, 5239 KB / 5117 KiB Mac HFS 67948070 67958303 10234 [EasyInstall_OSX] HFS found using backup sector!, 5239 KB / 5117 KiB Mac HFS 67948152 67958295 10144 HFS+, 5193 KB / 5072 KiB Mac HFS 67958292 67968435 10144 HFS+, 5193 KB / 5072 KiB Mac HFS 67958300 67968533 10234 [EasyInstall_OSX] HFS, 5239 KB / 5117 KiB Mac HFS 67992596 67997827 5232 HFS+ found using backup sector!, 2678 KB / 2616 KiB Mac HFS 67997824 68003055 5232 HFS+, 2678 KB / 2616 KiB Mac HFS 67997892 68003123 5232 HFS+ found using backup sector!, 2678 KB / 2616 KiB Mac HFS 68003052 68008283 5232 HFS+, 2678 KB / 2616 KiB Mac HFS 68003120 68008351 5232 HFS+, 2678 KB / 2616 KiB Mac HFS 68008348 68013579 5232 HFS+, 2678 KB / 2616 KiB Solaris /home 84429840 123499141 39069302 UFS1, 20 GB / 18 GiB Solaris /home 84429952 123499253 39069302 UFS1, 20 GB / 18 GiB Solaris /home 84493136 123562437 39069302 UFS1, 20 GB / 18 GiB Solaris /home 84493248 123562549 39069302 UFS1, 20 GB / 18 GiB Solaris /home 84566088 123635389 39069302 UFS1, 20 GB / 18 GiB Solaris /home 84566200 123635501 39069302 UFS1, 20 GB / 18 GiB Solaris /home 84571232 123640533 39069302 UFS1, 20 GB / 18 GiB Solaris /home 84571344 123640645 39069302 UFS1, 20 GB / 18 GiB Solaris /home 84659952 123729253 39069302 UFS1, 20 GB / 18 GiB Solaris /home 84660064 123729365 39069302 UFS1, 20 GB / 18 GiB Solaris /home 84690504 123759805 39069302 UFS1, 20 GB / 18 GiB Solaris /home 84690616 123759917 39069302 UFS1, 20 GB / 18 GiB Solaris /home 84700424 123769725 39069302 UFS1, 20 GB / 18 GiB Solaris /home 84700536 123769837 39069302 UFS1, 20 GB / 18 GiB Solaris /home 84797720 123867021 39069302 UFS1, 20 GB / 18 GiB Solaris /home 84797832 123867133 39069302 UFS1, 20 GB / 18 GiB Solaris /home 84812544 123881845 39069302 UFS1, 20 GB / 18 GiB Solaris /home 84812656 123881957 39069302 UFS1, 20 GB / 18 GiB Solaris /home 84824552 123893853 39069302 UFS1, 20 GB / 18 GiB Solaris /home 84824664 123893965 39069302 UFS1, 20 GB / 18 GiB Solaris /home 84847528 123916829 39069302 UFS1, 20 GB / 18 GiB Solaris /home 84847640 123916941 39069302 UFS1, 20 GB / 18 GiB Solaris /home 84886840 123956141 39069302 UFS1, 20 GB / 18 GiB Solaris /home 84886952 123956253 39069302 UFS1, 20 GB / 18 GiB Solaris /home 84945488 124014789 39069302 UFS1, 20 GB / 18 GiB Solaris /home 84945600 124014901 39069302 UFS1, 20 GB / 18 GiB Solaris /home 84957992 124027293 39069302 UFS1, 20 GB / 18 GiB Solaris /home 84958104 124027405 39069302 UFS1, 20 GB / 18 GiB Solaris /home 84962240 124031541 39069302 UFS1, 20 GB / 18 GiB Solaris /home 84962352 124031653 39069302 UFS1, 20 GB / 18 GiB Solaris /home 84977168 124046469 39069302 UFS1, 20 GB / 18 GiB Solaris /home 84977280 124046581 39069302 UFS1, 20 GB / 18 GiB MS Data 174395467 178483851 4088385 ..... snip (it keeps going on for quite a while)

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• How to search phrase queries in inverted index structure?

  - by Mehdi Amrollahi

  If we want to search a query like this "t1 t2 t3" (t1,t2 ,t3 must be queued) in an inverted index structure , which ways could we do ? 1-First we search the "t1" term and find all documents that contains "t1" , then do this work for "t2" and then "t3" . Then find documents that positions of "t1" , "t2" and "t3" are next to each other . 2-First we search the "t1" term and find all documents that contains "t1" , then in all documents that we found , we search the "t2" and next , in the result of this , we find documents that contains "t3" . thanks .

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• Hibernate advanced select

  - by Marcus

  We want to get a row from a table using Hibernate a la: select max(id) from mytable where date = <date> Then select * from mytable where id = <max_id> We are currently using Hibernate to map mytable to Java domain objects. I know how to load the domain object based on an id. So I could just do #1 using JDBC and then load the domain object using Hibernate the "normal" way. But.. is there a way to do this with one single Hibernate logical query?

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• Intersecting boundaries with lucene

  - by Silvio Donnini

  I'm using Lucene, and I'm trying to find a way to index and retrieve documents that have a ranged property. For example I have: Document 1: Price:[30 TO 50] Document 2: Price:[45 TO 60] Document 3: Price:[60 TO 70] And I would like to search for all the documents whose ranges intersect a specific interval, in the above example, if I search for Price in [55 TO 65] I should get Document 2 and Document 3 as results. I don't think NumericRangeQueries alone would do the trick, I need to work on the index with something similar to R-trees, but are they implemented in Lucene? Also, I suppose that what I need should be a subclass of MultiTermQuery, because the query Price in [55 TO 65] has two boundaries, but I don't see anything suitable among MultiTermQuery's subclasses. Any help is appreciated, thanks, Silvio P.S. I'm using Lucene 2.9.0, but I can update to the latest release if needed.

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• select random value from each type

  - by Joseph Mastey

  I have two tables, rating: +-----------+-----------+-------------+----------+ | rating_id | entity_id | rating_code | position | +-----------+-----------+-------------+----------+ | 1 | 1 | Quality | 0 | | 2 | 1 | Value | 0 | | 3 | 1 | Price | 0 | +-----------+-----------+-------------+----------+ And rating_option +-----------+-----------+------+-------+----------+ | option_id | rating_id | code | value | position | +-----------+-----------+------+-------+----------+ | 1 | 1 | 1 | 1 | 1 | | 2 | 1 | 2 | 2 | 2 | | 3 | 1 | 3 | 3 | 3 | | 4 | 1 | 4 | 4 | 4 | | 5 | 1 | 5 | 5 | 5 | | 6 | 2 | 1 | 1 | 1 | | 7 | 2 | 2 | 2 | 2 | | 8 | 2 | 3 | 3 | 3 | | 9 | 2 | 4 | 4 | 4 | | 10 | 2 | 5 | 5 | 5 | | 11 | 3 | 1 | 1 | 1 | | 12 | 3 | 2 | 2 | 2 | | 13 | 3 | 3 | 3 | 3 | | 14 | 3 | 4 | 4 | 4 | | 15 | 3 | 5 | 5 | 5 | +-----------+-----------+------+-------+----------+ I need a SQL query (not application level, must stay in the database) which will select a set of ratings randomly. A sample result would look like this, but would pick a random value for each rating_id on subsequent calls: +-----------+-----------+------+-------+----------+ | option_id | rating_id | code | value | position | +-----------+-----------+------+-------+----------+ | 1 | 1 | 1 | 1 | 1 | | 8 | 2 | 3 | 3 | 3 | | 15 | 3 | 5 | 5 | 5 | +-----------+-----------+------+-------+----------+ I'm totally stuck on the random part, and grouping by rating_id has been a crap shoot so far. Any MySQL ninjas want to take a stab? Thanks, Joe

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• JPA entitymanager remove operation is not performant

  - by Samuel

  When I try to do an entityManager.remove(instance) the underlying JPA provider issues a separate delete operation on each of the GroupUser entity. I feel this is not right from a performance perspective, since if a Group has 1000 users there will be 1001 calls issued to delete the entire group and itr groupuser entity. Would it make more sense to write a named query to remove all entries in groupuser table (e.g. delete from group_user where group_id=?), so I would have to make just 2 calls to delete the group. @Entity @Table(name = "tbl_group") public class Group { @OneToMany(mappedBy = "group", cascade = CascadeType.ALL, fetch = FetchType.LAZY) @Cascade(value = DELETE_ORPHAN) private Set<GroupUser> groupUsers = new HashSet<GroupUser>(0);

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• Django queries Especial Caracters

  - by Jorge Machado

  Hi, I Working on location from google maps and using django to. My question is: I have a String in request.GET['descricao'] lets say it contains "Via rapida". In my database i have store = "Via Rápida" i'm doing : local = Local.objects.filter(name__icontains=request.GET['descricao']) with that i can get everthing fine like "Via Rapida" but the result that have "Via rápida" never get match in the query (ASCI caracter may be ?) what must i do given a string "Via rapida" match "via rápida" and "via rapida" ? Regular Expressions ? how ? Thanks

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• MySql SELECT AS - Append all field names

  - by jeerose

  I'd like to do something like this: SELECT table.id AS prefix_id, table.name AS prefix_name ... and have the prefix added dynamically to all field names rather than selecting them all manually (ie SELECT table.* AS prefix_* or something) Hopefully I've described that accurately. Any thoughts? Edit To be clear, the reason I'm asking is to make sure that my query result contains every column from each table I call even if there are duplicate field names. For example, I might have a table with lots of fields which means I don't want to alias all the fields manually. Further if 3 tables have a field called name my result won't contain three name results; it will have one. I want to avoid ambiguity with my column names.

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• MySQL: Copy a field to another table

  - by harpax

  I have a table posts that could look like this: id | title | body | created | .. ------------------------------------------- I would like to use the boolean search feature that is offered by a MyISAM Table, but the posts table is InnoDB. So I created another table 'post_contents' that looks like this: post_id | body -------------------- That table is already filled with some contents and I can use the boolean search. However, I need to move the title field in the post_contents table as well and then copy the existing title-data to the new field. I know about the INSERT .. SELECT syntax, but I don't seem to be able to create the correct query.

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• Using PHP to place database rows into an array?

  - by Hamed Szilazi

  I was just wondering how i would be able to code perform an SQL query and then place each row into a new array, for example, lets say a table looked like the following: $people= mysql_query("SELECT * FROM friends") Output: | ID | Name | Age | --1----tom----32 --2----dan----22 --3----pat----52 --4----nik----32 --5----dre----65 How could i create a multidimensional array that works in the following way, the first rows second column data could be accessed using $people[0][1] and fifth rows third column could be accessed using $people[4][2]. How would i go about constructing this type of array? Sorry if this is a strange question, its just that i am new to PHP+SQL and would like to know how to directly access data. Performance and speed is not a issue as i am just writing small test scripts to get to grips with the language.

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• Run time error '3075' in Access 2007

  - by Thys

  I am getting the following error when I try to open a report in Access 2007. The code works fine in Access 2003. run time error '3075' Syntax error (missing operator) in query expression '[COUNTRY_ID]=' here is the code giving the error... How could I fix this? Private Sub List25_Click() Combo20.SetFocus 'DoCmd.FindRecord List25.ItemData(List25.ListIndex) Forms![Country Rate Administration].Filter = "[COUNTRY_ID]=" & List25.ItemData(List25.ListIndex) Forms![Country Rate Administration].FilterOn = True End Sub Thansk in advance for your help!

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• Optimizing ROW_NUMBER() in SQL Server

  - by BlueRaja

  We have a number of machines which record data into a database at sporadic intervals. For each record, I'd like to obtain the time period between this recording and the previous recording. I can do this using ROW_NUMBER as follows: WITH TempTable AS ( SELECT *, ROW_NUMBER() OVER (PARTITION BY Machine_ID ORDER BY Date_Time) AS Ordering FROM dbo.DataTable ) SELECT [Current].*, Previous.Date_Time AS PreviousDateTime FROM TempTable AS [Current] INNER JOIN TempTable AS Previous ON [Current].Machine_ID = Previous.Machine_ID AND Previous.Ordering = [Current].Ordering + 1 The problem is, it goes really slow (several minutes on a table with about 10k entries) - I tried creating separate indicies on Machine_ID and Date_Time, and a single joined-index, but nothing helps. Is there anyway to rewrite this query to go faster?

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• mySQL Left Join on multiple tables with conditions

  - by Jarrod

  Hi, I have a problem. I have 4 tables: Invoice_Payment, Invoice, Client, and Calendar Basically, I have the below query, which works well, except, months with no date_due don't return. I.E only months with a date_due will be returned. I think I have to use a left join and join the calendar table with something like: LEFT JOIN Calendar ON Invoice_Payments.date_paid = Calendar.date_field. But I'm having no luck SELECT MONTHNAME(Invoice_Payments.date_paid) as month, SUM(Invoice_Payments.paid_amount) AS total FROM Invoice, Client, Invoice_Payments WHERE Client.registered_id = 1 AND Client.id = Invoice.client_id And Invoice.id = Invoice_Payments.invoice_id AND date_paid IS NOT NULL GROUP BY YEAR(Invoice_Payments.date_paid), MONTH(Invoice_Payments.date_paid) Any help appreciated.

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• Find products that have a list of attributes.

  - by bellesebastien

  I'm stuck trying to solve a problem that's proving to be more difficult than it seems. Consider there is a table that associates products with attributes, it looks like this: Products_id | Attribute_id 21 | 456 21 | 231 21 | 26 22 | 456 22 | 26 22 | 116 23 | 116 23 | 231 Next, I have a list of attribute_ids which I want to use in order to get the products that have all the attributes in that list. For example if I search in the table above using this list (456, 26) I should get these product_ids 21 and 22. Another example, if I search for (116, 231) I should get an empty response since there are no products that have both these attributes. How can I achieve this using one query? I hope I made my question clear. Thanks.

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• A better way to build this MySQL statement with subselects

  - by Corey Maass

  I have five tables in my database. Members, items, comments, votes and countries. I want to get 10 items. I want to get the count of comments and votes for each item. I also want the member that submitted each item, and the country they are from. After posting here and elsewhere, I started using subselects to get the counts, but this query is taking 10 seconds or more! SELECT `items_2`.*, (SELECT COUNT(*) FROM `comments` WHERE (comments.Script = items_2.Id) AND (comments.Active = 1)) AS `Comments`, (SELECT COUNT(votes.Member) FROM `votes` WHERE (votes.Script = items_2.Id) AND (votes.Active = 1)) AS `votes`, `countrys`.`Name` AS `Country` FROM `items` AS `items_2` INNER JOIN `members` ON items_2.Member=members.Id AND members.Active = 1 INNER JOIN `members` AS `members_2` ON items_2.Member=members.Id LEFT JOIN `countrys` ON countrys.Id = members.Country GROUP BY `items_2`.`Id` ORDER BY `Created` DESC LIMIT 10 My question is whether this is the right way to do this, if there's better way to write this statement OR if there's a whole different approach that will be better. Should I run the subselects separately and aggregate the information?

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