Search Results

Search found 44956 results on 1799 pages for 'type checking'.

Page 184/1799 | < Previous Page | 180 181 182 183 184 185 186 187 188 189 190 191  | Next Page >

  • In Scala 2.8 collections, why was the Traversable type added above Iterable?

    - by Seth Tisue
    I know that to be Traversable, you need only have a foreach method. Iterable requires an iterator method. Both the Scala 2.8 collections SID and the "Fighting Bitrot with Types" paper are basically silent on the subject of why Traversable was added. The SID only says "David McIver... proposed Traversable as a generalization of Iterable." I have vaguely gathered from discussions on IRC that it has to do with reclaiming resources when traversal of a collection terminates? The following is probably related to my question. There are some odd-looking function definitions in TraversableLike.scala, for example: def isEmpty: Boolean = { var result = true breakable { for (x <- this) { result = false break } } result } I assume there's a good reason that wasn't just written as: def isEmpty: Boolean = { for (x <- this) return false true }

    Read the article

  • Skype 5.3 Win7x64: Crashing immediately on startup, tried "everything"

    - by Steve
    Per the title, Skype won't open, throws an APPCRASH error code #C0000005. I have already tried: Checking the "compatibility" setting Removing the appdata/roaming/skype folder (it doesn't exist anyway) Installing versions 5.3.113, 5.3.116, 5.3.120 Checking audio and video drivers for most recent updates Uninstalling with "advanced" registry checking using Revo Uninstaller Anyone got some gems of experience to throw my way? (Unfortunately, it's someone else's computer, and they don't know the last thing they did before it stopped working...)

    Read the article

  • how to control textbox type to double in visual basic?

    - by fema
    Hi, I'd like to make a textbox that accepts only numbers, but not integer, but rather double. I've read here about e.Handled = Not Char.IsDigit(e.KeyChar) and it works, but again, it can be used only for integer, since it declines decimal point. Another thing I've read here is If Not Double.TryParse(TextBox2.Text, value) Then .... and it would work fine, except that it allows only decimal comma instead of point. I don't know whether it's because of my location settings (Hungary, we use commas instead of points), but I don't have any other idea how to solve my problem, and the SQL server I send my data uses decimal point. Thanks in advance.

    Read the article

  • how to make a javascript number keypad popup

    - by user2434653
    i have a website with 3 pages. each page has a form with two input fields. i am trying to make a popup number-keypad that will populate what ever input field called it. below is that base code i keep coming back to. <html> <head><title>test</title></head> <body> <script> function num(id) { return document.getElementById(id); } </script> <form action="/unitPage" method="POST" style=" text-align:center;"> Prefix: <input id="num" name"prefix" type="text" onfocus="num('keypad').style.display='inline-block';"/> Number: <input id="num" name"number" type="text" pattern="[0-9]{6}" onfocus="num('keypad').style.display='inline-block';"/> </form> <div id="keypad" style="display:none; background:#AAA; vertical-align:top;"> <input type="button" value="7" onclick="num('num').value+=7;"/> <input type="button" value="8" onclick="num('num').value+=8;"/> <input type="button" value="9" onclick="num('num').value+=9;"/><br/> <input type="button" value="4" onclick="num('num').value+=4;"/> <input type="button" value="5" onclick="num('num').value+=5;"/> <input type="button" value="6" onclick="num('num').value+=6;"/><br/> <input type="button" value="1" onclick="num('num').value+=1;"/> <input type="button" value="2" onclick="num('num').value+=2;"/> <input type="button" value="3" onclick="num('num').value+=3;"/><br/> <input type="button" value="X" onclick="num('keypad').style.display='none'"/> <input type="button" value="0" onclick="num('num').value+=0;"/> <input type="button" value="&larr;" onclick="num('num').value=num('num').value.substr(0,num('num').value.length-1);"/> </div> </body> </html> is there a way of making one number key pad that i call from any page or do i need to make the above for each input? thanks

    Read the article

  • Hover image - part of forms appears untill hover another How?

    - by Mac
    Im trying to make part of my form/questionnaire appears when hover on image and stay active untill hover another image next to it. and repeat it on 7 images. Of course I need the cheched checkboxes to stay after they'll be hidden so you can come back to them by hover the image and for ex. correct answers and so on.. I was using a j code: <script type="text/javascript"> $("#Oobj51").hover(function(){ $('#Oobj58').show(); },function(){ $('#Oobj58').hide(); }); </script> it works to another elements on my page but not to the form. how can i do it maybe with css class or another j code. Thanks! Parts of html: (let's say I want to hover on "Oobj56" and make "Oobj58" appears and stay as I said before...) <div id="Oobj56"> <button type="submit" class="przed6" onmouseover="this.className='po6'" onmouseout="this.className='przed6'" /> </div> <div id="Oobj57"> <button type="submit" class="przed7" onmouseover="this.className='po7'" onmouseout="this.className='przed7'" /> </div> <div id="Oobj60"> <form action="mailto:" method="post" enctype="text/plain"> <div id="Oobj59"> <input type="text" input size="8" name="imie" placeholder="imie"> <input type="text" input size="11" name="numer" placeholder="numer telefonu"> <br><br> <select name="miasto"> <option selected="Miasto">Miasto</option> <option>Wroclaw</option> <option>Warszawa</option> <option>Kraków</option> <option>Trójmiasto</option> <option>Poznan</option> <option>Szczecin</option> <option>Torun</option> <option>Lódz</option> <option>Bydgoszcz</option> <option>Lublin</option> <option>Katowice</option> </select> <select name="wiek"> <option selected="selected">Wiek</option> <option> <15 </option> <option>15-19</option> <option>20-24</option> <option>25-29</option> <option>30-34</option> <option>35-39</option> <option>40-44</option> <option>45-49</option> <option>50-54</option> <option>55-59</option> <option>60-64</option> <option>65-69</option> <option>70-74</option> <option> >75 </option> </select> <select name="plec"> <option selected="selected">Plec</option> <option>Mezczyzna</option> <option>Kobieta</option> </select></div> <div id="Oobj58"> <script language="JavaScript"> function toggle(source) { checkboxes = document.getElementsByName('sport'); for(var i=0, n=checkboxes.length;i<n;i++) { checkboxes[i].checked = source.checked; } } </script> <input type="checkbox" onClick="toggle(this)" /><br> <input type="checkbox" name="sport" value="gym" />silownia<br /> <input type="checkbox" name="sport" value="fitness" />fitness<br /> <input type="checkbox" name="sport" value="noga" />pilka nozna<br /> <input type="checkbox" name="sport" value="kosz" />koszykówka<br /> <input type="checkbox" name="sport" value="siata" />siatkówka<br /> <input type="checkbox" name="sport" value="ameryka" />football amerykanski<br /> <input type="checkbox" name="sport" value="konie" />jezdziectwo konne<br /> <input type="checkbox" name="sport" value="basen" />basen/sporty wodne<br /> <input type="checkbox" name="sport" value="zima" />sporty zimowe<br /> </div> <div id="Oobj15"> <input type="submit" style="font-family: Open Sans;" value="Wyslij" class="wyslij" /> </div></form> </div>

    Read the article

  • In Java, how do I set a return type if an exception occurs?

    - by beagleguy
    hey all, I'm new to Java and was wondering if I define a method to return a database object like import java.sql.*; public class DbConn { public Connection getConn() { Connection conn; try { Class.forName("com.mysql.jdbc.Driver").newInstance(); if(System.getenv("MY_ENVIRONMENT") == "development") { String hostname = "localhost"; String username = "root"; String password = "root"; } conn = DriverManager.getConnection("jdbc:mysql:///mydb", username, password); return conn; } catch(Exception e) { throw new Exception(e.getMessage()); } } } if the connection fails when I try to create it what should I return? eclipse is telling me I have to return a Connection object but if it fails I'm not sure what to do. thanks!

    Read the article

  • C++: Simple data type for a variable in IF statement?

    - by Jason
    I am new to C++ and am making a simple text RPG, anyway, The scenario is I have a "welcome" screen with choices 1-3, and have a simple IF statement to check them, here: int choice; std::cout << "--> "; std::cin >> choice; if(choice == 1) { //.. That works fine, but if someone enters a letter as selection (instead of 1, 2 or 3) it'll become "-392493492"or something and crash the program. So I came up with: char choice; std::cout << "--> "; std::cin >> choice; if(choice == 1) { //.. This works kinda fine, but when I enter a number it seems to skip the IF statements completely.. Is the char "1" the same as the number 1? I get a compiler errro with this (ISO-CPP or something): if(choice == "1") So how on earth do I see if they entered 1-3 correctly!?

    Read the article

  • syntax error, unexpected ',', expecting ')' RoR

    - by McDoku
    I am trying to get a collection select from an another model and I keep getting the above error. Looked everywhere, got rails casts but nothing makes sense. _form.rb <%= f.label :city %><br /> <%= f.collection_select (:share ,:city_id, City.all , :id, :name ) %> It highlights 'form' on the error report <h1>New share</h1> <%= render 'form' %> <%= link_to 'Back', shares_path %> Here are my models... class Share include Mongoid::Document field :name, type: String field :type, type: String field :summary, type: String field :description, type: String field :city, type: String embedded_in :city has_many :category end class City include Mongoid::Document embedded_in :share field :name, type: String field :country, type: String attr_accessible :name, :city_id, :id end Searched everywhere and I cannot figure it out. It must be something silly.

    Read the article

  • Using a Form With Variables as Part of a Function

    - by John
    Hello, Could the form below be part of a function? I am wondering if it might not be able to be part of a function since it has variables. Thanks in advance, John echo '<form action="http://www...com/sandbox/comments/comments2.php" method="post"> <input type="hidden" value="'.$_SESSION['loginid'].'" name="uid"> <input type="hidden" value="'.$submissionid.'" name="submissionid"> <input type="hidden" value="'.$submission.'" name="submission"> <input type="hidden" value="'.$url.'" name="url"> <input type="hidden" value="'.$submittor.'" name="submittor"> <input type="hidden" value="'.$submissiondate.'" name="submissiondate"> <input type="hidden" value="'.$countcomments.'" name="countcomments"> <input type="hidden" value="'.$dispurl.'" name="dispurl"> <label class="addacomment" for="title">Add a comment:</label> <textarea class="commentsubfield" name="comment" type="comment" id="comment" maxlength="1000"></textarea> <div class="commentsubbutton"><input name="submit" type="submit" value="Submit"></div> </form> ';

    Read the article

  • Should this work?

    - by Noah Roberts
    I am trying to specialize a metafunction upon a type that has a function pointer as one of its parameters. The code compiles just fine but it will simply not match the type. #include <iostream> #include <boost/mpl/bool.hpp> #include <boost/mpl/identity.hpp> template < typename CONT, typename NAME, typename TYPE, TYPE (CONT::*getter)() const, void (CONT::*setter)(TYPE const&) > struct metafield_fun {}; struct test_field {}; struct test { int testing() const { return 5; } void testing(int const&) {} }; template < typename T > struct field_writable : boost::mpl::identity<T> {}; template < typename CONT, typename NAME, typename TYPE, TYPE (CONT::*getter)() const > struct field_writable< metafield_fun<CONT,NAME,TYPE,getter,0> > : boost::mpl::false_ {}; typedef metafield_fun<test, test_field, int, &test::testing, 0> unwritable; int main() { std::cout << typeid(field_writable<unwritable>::type).name() << std::endl; std::cin.get(); } Output is always the type passed in, never bool_.

    Read the article

  • Simple 'database' in c++

    - by DevAno1
    Hello. My task was to create pseudodatabase in c++. There are 3 tables given, that store name(char*), age(int), and sex (bool). Write a program allowing to : - add new data to the tables - show all records - sort tables with criteria : - name increasing/decreasing - age increasing/decreasing - sex Using function templates is a must. Also size of arrays must be variable, depending on the amount of records. I have some code but there are still problems there. Here's what I have: Function tabSize() for returning size of array. But currently it returns size of pointer I guess : #include <iostream> using namespace std; template<typename TYPE> int tabSize(TYPE *T) { int size = 0; size = sizeof(T) / sizeof(T[0]); return size; } How to make it return size of array, not its pointer ? Next the most important : add() for adding new elements. Inside first I get the size of array (but hence it returns value of pointer, and not size it's of no use now :/). Then I think I must check if TYPE of data is char. Or am I wrong ? // add(newElement, table) template<typename TYPE> TYPE add(TYPE L, TYPE *T) { int s = tabSize(T); //here check if TYPE = char. If yes, get the length of the new name int len = 0; while (L[len] != '\0') { len++; } //current length of table int tabLen = 0; while (T[tabLen] != '\0') { tabLen++; } //if TYPE is char //if current length of table + length of new element exceeds table size create new table if(len + tabLen > s) { int newLen = len + tabLen; TYPE newTab = new [newLen]; for(int j=0; j < newLen; j++ ){ if(j == tabLen -1){ for(int k = 0; k < len; k++){ newTab[k] = } } else { newTab[j] = T[j]; } } } //else check if tabLen + 1 is greater than s. If yes enlarge table by 1. } Am I thinking correct here ? Last functions show() is correct I guess : template<typename TYPE> TYPE show(TYPE *L) { int len = 0; while (L[len] == '\0') { len++; } for(int i=0; i<len; i++) { cout << L[i] << endl; } } and problem with sort() is as follows : Ho can I influence if sorting is decreasing or increasing ? I'm using bubble sort here. template<typename TYPE> TYPE sort(TYPE *L, int sort) { int s = tabSize(L); int len = 0; while (L[len] == '\0') { len++; } //add control increasing/decreasing sort int i,j; for(i=0;i<len;i++) { for(j=0;j<i;j++) { if(L[i]>L[j]) { int temp=L[i]; L[i]=L[j]; L[j]=temp; } } } } And main function to run it : int main() { int sort=0; //0 increasing, 1 decreasing char * name[100]; int age[10]; bool sex[10]; char c[] = "Tom"; name[0] = "John"; name[1] = "Mike"; cout << add(c, name) << endl; system("pause"); return 0; }

    Read the article

  • Is it good practice to avoid declaring a pointer to BOOL type in objective C?

    - by Krishnan
    I read this question in stackoverflow. The excerpt answer provided by bbum is below: The problem isn't the assignment, it is much more likely that you declared your instance variable to be BOOL *initialBroadcast;. There is no reason to declare the instance variable to be a pointer (at least not unless you really do need a C array of BOOLs).. Remove the * from the declaration. 1.Is there anything wrong in using a pointer variable even when I do not have to maintain an array of BOOLs? 2.I think even if avoiding them a good practice, it is not specific to objective-C and applies to all programming languages which has pointers. Please answer my questions.

    Read the article

  • Why would you precede the main() function in C with a data type?

    - by Milktrader
    Many are familiar with the hello world program in C #include <stdio.h> main () { printf ("hello world"); return 0; } Why do some precede the main () function with int as in: int main() Also, I've seen the word 'void' entered inside the () as in: int main(void) It seems like extra typing for nothing, but maybe it's a best practice that pays dividends in other situations? Also, why precede main() with an int if you're returning a character string? If anything, one would expect: char main(void) I'm also foggy about why we return 0 at the end of the function.

    Read the article

< Previous Page | 180 181 182 183 184 185 186 187 188 189 190 191  | Next Page >