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  • Convert SVG image with filters to PNG /PDF

    - by user1599669
    I have the following svg image to the png image & pdf image with 300 DPI. <svg width="640" height="480" xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink"> <!-- Created with SVG-edit - http://svg-edit.googlecode.com/ --> <defs> <filter height="200%" width="200%" y="-50%" x="-50%" id="svg_1_blur"> <feGaussianBlur stdDeviation="10" in="SourceGraphic"/> </filter> </defs> <g> <title>Layer 1</title> <image filter="url(#svg_1_blur)" xlink:href="images/logo.png" id="svg_1" height="162.999996" width="223.999992" y="99" x="185"/> <text xml:space="preserve" text-anchor="middle" font-family="serif" font-size="24" id="svg_2" y="210" x="289" stroke-width="0" stroke="#000000" fill="#000000">sdfdsdsfsdf</text> </g> </svg> I want to do this using PHP and I have applied filters to the blur filter to the image and I want to retain that. Also I have problem in viewing this image in the IE, because it doesn't show the blur effect on IE9. Any suggestions?

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  • Adding new elements into DOM using JavaScript (appendChild)

    - by KatieK
    I sometimes need to add elements (such as a new link and image) to an existing HTML page, but I only have access to a small portion of the page far from where I need to insert elements. I want to use DOM based JavaScript techniques, and I must avoid using document.write(). Thus far, I've been using something like this: // Create new image element var newImg = document.createElement("img"); newImg.src = "images/button.jpg"; newImg.height = "50"; newImg.width = "150"; newImg.alt = "Click Me"; // Create new link element var newLink = document.createElement("a"); newLink.href = "/dir/signup.html"; // Append new image into new link newLink.appendChild(newImg); // Append new link (with image) into its destination on the page document.getElementById("newLinkDestination").appendChild(newLink); Is there a more efficient way that I could use to accomplish the same thing? It all seems necessary, but I'd like to know if there's a better way I could be doing this. Thanks!

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  • Major JQuery bug on IE not reproducible - What can i do in this situation to solve this bug?

    - by ming yeow
    I am hoping to get some help on this issue. Some users on IE have been reporting this javascript issue, but I have been unable to re-produce it. In essence, for some class of windows IE users, the game doesn't work (or $.ajax() is not working). What I know: I swapped out an ajax call (ajax_init_trainer) and used a standard link with some request parameters to do the initialization and ppl seemed to get passed the problem until they hit the next ajax call. I read somewhere that IE does crazy caching so you need to make the urls unique, which is why i added the _requestno parameter. However, setting the cache:false is said to also do this. This didn't fix it for someone who was complaining. function done(res, status) { var data = JSON.parse(res.responseText); hide_loading(); if (status == "success") { window.location.href="/bamo/battle/?{{ fb_sig}}"; } else { display_alert("Problem!",data.msg,$("#notifications")); } }; $(".monster_select_class").click(function() { $(this).attr("src","{{MEDIA_URL}}/bamo/button_select_click.png"); monster_class = $(this).attr("monster_class"); monster_type = $(this).attr("monster_type"); ajax_init_trainer(monster_class,monster_type); }); function ajax_init_trainer(trainer_class,monster_type) { var data = {trainer_class:trainer_class,monster_type:monster_type}; var d = new Date(); var args = { type:"POST",url:"/bamo/api/init_trainer/?_requestno="+d.getTime(),data:data,contentType:"application/json;", dataType: "json",cache:false,complete:done}; $.ajax(args); return false; };

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  • Unexpected token ILLEGAL with jQuery

    - by Bram Vanroy
    So, I have a website with an autoFontSize script (Got it from stackoverflow, but slightly edited it too loop over each div with that specific class) (function ($) { $.fn.textfill = function (options) { this.each(function () { var fontSize = options.maxFontPixels; var ourText = $('h2 a', this); var maxHeight = $(this).height(); var maxWidth = $(this).width(); var textHeight; var textWidth; do { ourText.css('font-size', fontSize); textHeight = ourText.height(); textWidth = ourText.width(); fontSize = fontSize - 1; } while ((textHeight > maxHeight || textWidth > maxWidth) && fontSize > 16); }); return this; }; })(jQuery); $(document).ready(function () { $('.fotonode.fotopagina').textfill({ maxFontPixels: 30 }); });? And a (simplified) HTML structure: <div class="fotonode fotopagina"> <h2><a href="#">Testing Title</a></h2> </div> For some reason this doesn't work (neither locally nor live) BUT it does work on JSfiddle: http://jsfiddle.net/Yb9yj/ I read somewhere that this can cause problems. I copied the code from jsfiddle to my file, so maybe I have (unintentionally) copied some white spaces that shouldn't be there or something. I don't know. But how can I solve this then?

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  • highlight page selected in pagination?

    - by Mahmoud
    Hey There i have a php page, that shows all products that are stored on the database, so everything in fine, but my problem is that i am trying to highlight or give a color when a selected number is clicked, example, let say i all my product are showing and there are 2 pages, so when the user clicks on next the next fade and number 2 is colored yellow this well help the user to on which page he is below is my php code <?php echo"<a style:'color:#FFF;font-style:normal;'> "; include "im/config.php"; include('im/ps_pagination.php'); $result = ("Select * from product "); $pager = new PS_Pagination($conn, $result, 5, 6, "product=product"); $rs = $pager->paginate(); echo"<div id='image_container'>"; echo $pager->renderFullNav(); echo "<br /><br />\n"; while($row = mysql_fetch_array($rs)){ echo" <div class='virtualpage hidepiece'><a href='gal/".$row['pro_image']."' rel='lightbox[roadtrip]' title='".$row['pro_name']." : ".$row['pro_mini_des']."' style='color:#000'><img src='thumb/".$row['pro_thumb']."' /> </a></div>"; } echo"</div>"; echo "<br /><br />\n"; echo $pager->renderFullNav(); echo"</a>"; ?> Thank everyone

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  • How would i stop this foreach loop after 3 iterations?

    - by Tapha
    Here is the loop. foreach($results->results as $result){ echo '<div id="twitter_status">'; echo '<img src="'.$result->profile_image_url.'" class="twitter_image">'; $text_n = $result->text; echo "<div id='text_twit'>".$text_n."</div>"; echo '<div id="twitter_small">'; echo "<span id='link_user'".'<a href="http://www.twitter.com/'.$result->from_user.'">'.$result->from_user.'</a></span>'; $date = $result->created_at; $dateFormat = new DateIntervalFormat(); $time = strtotime($result->created_at); echo "<div class='time'>"; print sprintf('Submitted %s ago', $dateFormat->getInterval($time)); echo '</div>'; echo "</div>"; echo "</div>"; Thanks!!!! alot.

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  • why it makes ie6 or ie8 compatible mode crash

    - by hylin
    Anybody can tell me why those code can make ie6 or ie8 compatible mode crash? PS:I know,there is so many ways to avoid this satuation, but I just want to know why. To avoid: Change class="wrapper"--class="wrapper2" or other != "wrapper" $('wrapper').style.overflow='visible'; -- setTimeout(function(){$('wrapper').style.overflow='visible';},10); Or remove any style , js operation... <!DOCTYPE html> <html> <head> <meta charset="utf-8" /> <style>.wrapper{width:975px;margin:60px auto 0}</style> </head> <body id="wrapper" style="overflow:hidden;"> <div id="overlay" style="position:absolute;"></div> <div class="wrapper"> <input type="text" id="input1"/> <a id="btn" href="javascript:;">test</a> </div> <script type="text/javascript"> $('btn').onclick = function(){ $('overlay').style.display='none'; $('wrapper').style.overflow='visible'; $("input1").focus(); } function $(s){ return document.getElementById(s); } </script> </body> </html>

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  • Undefined javascript function?

    - by user74283
    Working on a google maps project and stuck on what seems to be a minor issue. When i call displayMarkers function firebug returns: ReferenceError: displayMarkers is not defined [Break On This Error] displayMarkers(1); <script type="text/javascript"> function initialize() { var center = new google.maps.LatLng(25.7889689, -80.2264393); var map = new google.maps.Map(document.getElementById('map'), { zoom: 10, center: center, mapTypeId: google.maps.MapTypeId.ROADMAP }); //var data = [[25.924292, -80.124314], [26.140795, -80.3204049], [25.7662857, -80.194692]] var data = {"crs": {"type": "link", "properties": {"href": "http://spatialreference.org/ref/epsg/4326/", "type": "proj4"}}, "type": "FeatureCollection", "features": [{"geometry": {"type": "Point", "coordinates": [25.924292, -80.124314]}, "type": "Feature", "properties": {"industry": [2], "description": "hosp", "title": "shaytac hosp2"}, "id": 35}, {"geometry": {"type": "Point", "coordinates": [26.140795, -80.3204049]}, "type": "Feature", "properties": {"industry": [1, 2], "description": "retail", "title": "shaytac retail"}, "id": 48}, {"geometry": {"type": "Point", "coordinates": [25.7662857, -80.194692]}, "type": "Feature", "properties": {"industry": [2], "description": "hosp2", "title": "shaytac hosp3"}, "id": 36}]} var markers = []; for (var i = 0; i < data.features.length; i++) { var latLng = new google.maps.LatLng(data.features[i].geometry.coordinates[0], data.features[i].geometry.coordinates[1]); var marker = new google.maps.Marker({ position: latLng, title: console.log(data.features[i].properties.industry[0]), map: map }); marker.category = data.features[i].properties.industry[0]; marker.setVisible(true); markers.push(marker); } function displayMarkers(category) { var i; for (i = 0; i < markers.length; i++) { if (markers[i].category === category) { markers[i].setVisible(true); } else { markers[i].setVisible(false); } } } } google.maps.event.addDomListener(window, 'load', initialize); </script> <div id="map-container"> <div id="map"></div> </div> <input type="button" value="Retail" onclick="displayMarkers(1);">

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  • Having trouble with php and ajax search function

    - by Andy
    I am still quite new to php/ajax/mysql. In anycase, I'm creating a search function which is returning properly the data I'm looking for. In brief, I have a mysql database set up. A php website that has a search function. I'm now trying to add a link to a mysql database search rather than just showing the results. In my search.php, the echo line is working fine but the $string .= is not returning anything. I'm just trying to get the same as the echo but with the link to the mysql php record. Am I missing something simple? //echo $query; $result = mysqli_query($link, $query); $string = ''; if($result) { if(mysqli_affected_rows($link)!=0) { while($row = mysqli_fetch_array($result,MYSQLI_ASSOC)) { echo '<p> <b>'.$row['title'].'</b> '.$row['post_ID'].'</p>'; $string .= "<p><a href='set-detail.php?recordID=".$row->post_ID."'>".$row->title."</a></p>"; } } else { echo 'No Results for :"'.$_GET['keyword'].'"'; }

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  • how to print data in a table from mysql

    - by robertdd
    hello, i want to extract the last eight entries from my database and print them into a 2 columns table!like this: |1|2| |3|4| |5|6| |7|8| is that possible? this is my code: $db = new Database(DB_SERVER, DB_USER, DB_PASS, DB_DATABASE); $db->connect(); $sql = "SELECT ID, movieno FROM movies ORDER BY ID DESC LIMIT 8 "; $rows = $db->query($sql); print '<table width="307" border="0" cellspacing="5" cellpadding="4">'; while ($record = $db->fetch_array($rows)) { $vidaidi = $record['movieno']; print <<<END <tr> <td> <a href="http://www.youtube.com/watch?v=$vidaidi" target="_blank"> <img src="http://img.youtube.com/vi/$vidaidi/1.jpg" width="123" height="80"></a> </td> </tr> END; } print '</table>';

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  • How to read pair in freemarker

    - by Lukasz Rys
    Ok i'm having little trouble with reading pair. So I'm creating my pair private Pair<Integer, Integer> count(somethink) { int c1 = 2; int c2 = 4; return new Pair<Integer, Integer>(c1, c2); } And 'sending' it to ftl via java mv.addObject("counted", count(somethink)); I won't write everythink how it sends because I dont think it really matters with my issue. So i'm recieving it in "ftl". Then i was trying to 'read' it <#list counted?keys as key> <a href="#offerOrderTab"><@spring.message "someMsg"/>(${key}/${counted[key]})</a> </#list> After then i'm getting error Expecting a string, date or number here, Expression x is instead a freemarker.ext.beans.SimpleMethodModel As i suppose you dont iterate pairs (or I'm wrong?) i know its pair that contains only one key and one value but still i have to do send it that way and I thought its goin be to similar to iterating through map, in java i would use pair.first() and pair.second() but it doesn't work in ftl (ye i know it shouldnt work). I also tried to cast it to String by using ?string but it didnt work too

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  • PHP checking/refreashing functions

    - by user1284360
    ok i have a main document that displays a chatbox, what i want is for the chatbox to refreash on everyone who is logged in's screen whenever someone posts a new message... ive tried many methods including sleep timers and new functions that call then sleep and get recalled but this just generates an endless line of the same or little diffrent data making the form unusable until error... this is my code <?php // set error reporting level if (version_compare(phpversion(), "5.3.0", ">=") == 1) error_reporting(E_ALL & ~E_NOTICE & ~E_DEPRECATED); else error_reporting(E_ALL & ~E_NOTICE); require_once('inc/login.inc.php'); require_once('inc/chat.inc.php'); // initialization of login system and generation code $oSimpleLoginSystem = new SimpleLoginSystem(); $oSimpleChat = new SimpleChat(); // draw login box echo $oSimpleLoginSystem->getLoginBox(); // draw chat application $sChatResult = '<font color="0x99000"> <a href="Register_form.html">New Account</a><br> login to send a message<br> or register for a new account</font>'; if ($_COOKIE['member_name'] && $_COOKIE['member_pass']) { if ($oSimpleLoginSystem->check_login($_COOKIE['member_name'], $_COOKIE['member_pass'])) { $sChatResult = ""; if($oSimpleLoginSystem->check_privledges($_COOKIE['member_name']) >= 2) { $sChatResult .= "<br>privledge check Working<br>"; } $sChatResult .= "<form action=$_SERVER[PHP_SELF] method='post'> <input type='hidden' name='foo' value='<?= $foo ?>' /> <input type='submit' name='submit' value='Refresh Messages' /> </form>"; $sChatResult .= $oSimpleChat->acceptMessages(); $sChatResult .= "<br><br>"; $sChatResult .= $oSimpleChat->getMessages(); } } echo $sChatResult; ?>

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  • Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in

    - by user1493540
    <html> <title>Title</title> <body> <link type="text/css" rel="stylesheet" href="css/bootstrap.css"/> </body> <center> <? mysql_connect ("localhost", "root","") or die (mysql_error()); mysql_select_db ("dbname"); $term = $_POST['term']; $sql = mysql_query("select * from items where name like '%$term%'"); while ($row = mysql_fetch_array($sql)){ echo '<table class="table - striped"> <theader> <tr> <th>ID</th> <th></br> Name</th></tr>'; echo ' <tbody><td>'.$row['id']; echo'</td>'; echo '<td>'; echo '</theader>' .$row['name']; echo '</td>'; echo ''; } ?> </center> <script src="js/bootsrap.js"> </script> </html> I'm, getting this error: Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in /home/runedev1/public_html/itemdb/search.php on line 19 When I run the code on localhost using Xampp, it works fine, when I upload it to the web-host, the error appears. Yes, I am changing the database name, user and password when putting it on the webhost.

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  • Jquery :not()selector

    - by kim
    <html lang="en"> <head> <style> #thisdiv {padding:10px; margin:-15px 0 0 40px; background-color:#333; position:absolute; display:none;} div.block {margin-top:10px; width:200px;} div#thisdiv a {color:#fff;} </style> </head> <body> <div id ="one" class="block"><a href="">one</a></div> <div id="thisdiv">hello</div> <div id ="two"class="block">two</div> <div id ="three"class="block">three/div> <script src="http://code.jquery.com/jquery-latest.js"></script> <script> $(document).ready(function() { $('#one').hover(function() { $('#thisdiv').fadeIn(400); }); $('div:not(#thisdiv)').mouseleave(function() { $('#thisdiv').fadeOut(400) }); }); </script> </body> </html> #thisdiv doesn't fadeOut. I could have used the following, but it only fades out if the cursor mouse outs of #thisdiv. Is there any way i can solve this so when the cursor navigates away from anyway, the div still fade out. $('#thisdiv').mouseleave(function() { $('#thisdiv').fadeOut(400) }); I couldn't figure out what's why jquery's :not selector is not doing what I wanted to. Am i using it wrongly?

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  • jQuery Drill down selector ?

    - by Etienne
    Hi, I have made this piece of code that makes a roll hover effect on any image you add the class 'simplehover' to it : //rollover effect on links $(".simplehover").mouseover(function () { $(this).attr("src", $(this).attr("src").replace("-off.", "-on.")); }).mouseout(function () { $(this).attr("src", $(this).attr("src").replace("-on.", "-off.")); }); <img src="slogan.gif" class="simplehover" /> Im trying to get it work if you add the class 'simplehover' to the surrounding element : . (especially usefull for ASP.net asp:HyperLink tag which automatically generate the IMG tag inside the hyperlink. <a href="#" class="simplehover"> <img src="slogan.gif" /> </a> If I change my selector for : $(".simplehover img") , it will work, however it no longer works in senario #1. I tried this with no luck: $(".simplehover").mouseover(function () { if ($(this).has('img')) { $(this) = $(this).children(); } ... Anyone can figure this out?

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  • Iteration through the HtmlDocument.All collection stops at the referenced stylesheet?

    - by Jonas
    Since "bug in .NET" is often not the real cause of a problem, I wonder if I'm missing something here. What I'm doing feels pretty simple. I'm iterating through the elements in a HtmlDocument called doc like this: System.Diagnostics.Debug.WriteLine("*** " + doc.Url + " ***"); foreach (HtmlElement field in doc.All) System.Diagnostics.Debug.WriteLine(string.Format("Tag = {0}, ID = {1} ", field.TagName, field.Id)); I then discovered the debug window output was this: Tag = !, ID = Tag = HTML, ID = Tag = HEAD, ID = Tag = TITLE, ID = Tag = LINK, ID = ... when the actual HTML document looks like this: <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN"> <html> <head> <title>Protocol</title> <link rel="Stylesheet" type="text/css" media="all" href="ProtocolStyle.css"> </head> <body onselectstart="return false"> <table> <!-- Misc. table elements and cell values --> </table> </body> </html> Commenting out the LINK tag solves the issue for me, and the document is completely parsed. The ProtocolStyle.css file exist on disk and is loaded properly, if that would matter. Is this a bug in .NET 3.5 SP1, or what? For being such a web-oriented framework, I find it hard to believe there would be such a major bug in it.

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  • Spring Controller redirect to another page

    - by user1386375
    Hey I got the following problem. This is the content of the jspx file: function postSMTH() { $.ajax({ type: "POST", url: document.getElementById("urltxt").value, data: parameters, }); } <input type="hidden" value="${pageContext.request.contextPath}/foo/foo2/foodat" name="urltxt" id="urltxt"/> <div class="foodat"><a href="javascript:postSMTH();"><spring:message code="foo_foo2_foodat_text" text="FOODAT"/></a></div> So if I push the submit button, the postSMTH function is called and the ajax object is paste to the Controller which look like this: @Controller @RequestMapping(value="/foo") public class FooController { .............. @RequestMapping(value="/foo2", method=RequestMethod.POST) public String homePOST(HttpServletRequest request) { ........ } @RequestMapping(value="/foo2", method=RequestMethod.GET) public String homeGET(HttpServletRequest request) { ........ } @RequestMapping(value="/foo2/foodat", method=RequestMethod.POST) public String doTHAT(HttpServletRequest request) { // check authorization Map fooMap = request.getParameterMap(); // do something in the Database, depending on the paramMap return "redirect:/foo/foo1"; } } Everything is working fine regarding the Database, but the Problem is, that the redirect at the end DOESN'T work. It just stays at the page foo2. I'm new to Spring, maybe its a little mistake somewhere. I just cant make it out by myself. Would be nice if someone would have some hint. Thanks

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  • android Json show only lasy item

    - by 03uk
    i have one problem, my json parser show only last item! But at Logcat i see all item's! Can you help me? @Override protected void onPostExecute(JSONObject result) { super.onPostExecute(result); Log.d("Log", result.toString()); JSONObject jsn = result; try { JSONArray jarray = jsn.getJSONArray("item"); for (int i = 0; i < jarray.length(); i++){ JSONObject jsno = jarray.getJSONObject(i); title.setText(Html.fromHtml("<a href=\""+jsno.getString("link")+"\">"+jsno.getString("title")+"</a>")); cat.setText(jsno.getString("category")); date.setText(jsno.getString("pubDate")); desc.getSettings().setJavaScriptEnabled(true); desc.getSettings().setDefaultTextEncodingName("charset=UTF-8"); desc.loadData(jsno.getString("description"), "text/html; charset=UTF-8", "utf-8"); } } catch (JSONException e) { e.printStackTrace(); }

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  • Youtube Javascript API play(); not working.. what am I doing wrong?

    - by odpogn
    Hello, I'm playing around with YouTubes Javascript API. I've set up a test page on my local enviornment, but the play function is not working. The video loads, and I can press play on the yt video screen, but my link "play" isn't working. Can someone tell me what I'm doing wrong?? I've been following this: http://code.google.com/apis/youtube/js_api_reference.html <html> <head> <script type="text/javascript" src="public/javascripts/swfobject.js"></script> </head> <body> <div id="ytapiplayer"> You will need Flash 8 or better to view this content. </div> <script type="text/javascript"> var params = { allowScriptAccess: "always" }; var atts = { id: "myytplayer" }; swfobject.embedSWF("http://www.youtube.com/v/OQSNhk5ICTI&enablejsapi=1&playerapiid=ytplayer", "ytapiplayer", "425", "365", "8", null, null, params, atts); function onYouTubePlayerReady(playerId) { ytplayer = document.getElementById("myytplayer"); } function play() { if (ytplayer) { ytplayer.playVideo(); } } </script> <a href="javascript:void(0);" onclick="play();">Play</a> </body> </html>

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  • Worpress WorkFlow Modfications

    - by blgnklc
    Hi All WordPress Lovers, I would like to ask a help about Zensor which is a plugin that you publish a post then a moderator approves the post to be published on the wordpress blog site. When a post is awating for approval, each awaiting post is appearing "waiting moderation". But, I dont want any link appears before moderator approval. Actually I found the joing sentence below; 1- Must be added to the end of JOIN part of any query: LEFT JOIN wp_zensor ON ID = wp_zensor.post_id 2- Must be added to the end of WHERE condition : AND wp_zensor.moderation_status = 'approved' Could you please show me; where should I add these modification on the category link presentation below: <h2>Politics</h2> <?php $recent = new WP_Query("cat=31&showposts=1"); while($recent->have_posts()) : $recent->the_post();?> <b><a href="<?php the_permalink() ?>" rel="bookmark"><?php the_title(); ?></a></b> <?php the_content_limit(140, "devami &raquo;"); ?> <div class="hppostmeta"> <p><?php the_time('j F Y, H:i'); ?> | <?php the_author_posts_link(); ?></p> </div> <?php endwhile; ?> Or any general solutions will be welcomed. Thanks. BK

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  • Slowing Down mywindow.print()

    - by TraderY
    I'm using this nice printing script: <script type="text/javascript"> function PrintElem(elem) { Popup($(elem).text()); } function Popup(data) { var mywindow = window.open('', 'my div', 'height=400,width=600'); mywindow.document.write('<html><head><title>my div</title>'); /*optional stylesheet*/ //mywindow.document.write('<link rel="stylesheet" href="main.css" type="text/css" />'); mywindow.document.write('</head><body >'); mywindow.document.write(data); mywindow.document.write('</body></html>'); mywindow.document.close(); mywindow.print(); return true; } </script> </head> <body> It works fine except for two things: mywindow.print() is triggered before the page has completely loaded so you can't see the material in the window to be printed (if you select "Print" it prints correctly though). The print dialog box opens on top of the window blocking the contents (presuming #1 is an easy fix). How can it positioned? Thanks - TY

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  • help to reiterate through my jquery snippet

    - by s2xi
    Code in question: $("#alpha").click(function(event) { event.preventDefault(); $("#show").slideToggle(); }); I have a list of files and its being outputted with PHP in alphabetical. I use this method in PHP: foreach(range('A','Z') as $i) { if (array_key_exists ("$i", $alpha)) { echo '<div id="alpha"><a href="#" name="'.$i.'"><h2>'.$i.'</h2></a></div><div id="show">'; foreach ($$i as $key=>$value) echo '<p>'.$value.' '.$key.'</p>'; } echo '</div>'; } What I want to do is when the user clicks on the #alpha to toggle the div #show that has the names that belong to a letter up. I can do this with the first listing, but every listing after that isn't affected. how can i tell jquery that foreach letter apply the js code so it can toggle up/down the #show. I don't want to this 26 times (one time for each letter in the alphabet), I tried to use class instead of id but that causes all the #show to toggleup heh.

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  • Switch XML value for another in google maps

    - by JeffP
    all thanks for taking a look. Problem: Using Google maps I need to switch catid value to another value. How would I approach this and display it in a the window. E.G var catid = { 2: { newcatid: 'london' }, 4: { newcatid: 'newyork' } }; function load() { var map = new google.maps.Map(document.getElementById("map"), { center: new google.maps.LatLng(47.6145, -122.3418), zoom: 5, mapTypeId: 'roadmap' }); var infoWindow = new google.maps.InfoWindow; // Change this depending on the name of your PHP file downloadUrl("index_xml.php", function(data) { var xml = data.responseXML; var markers = xml.documentElement.getElementsByTagName("marker"); for (var i = 0; i < markers.length; i++) { var name = markers[i].getAttribute("title"); var address = markers[i].getAttribute("address"); var catid = markers[i].getAttribute("catid"); var point = new google.maps.LatLng( parseFloat(markers[i].getAttribute("latitude")), parseFloat(markers[i].getAttribute("langtitude"))); var html = "<b>" + name + "</b> <br/>" + address + "<br/>" + **catid** + "<br/> <a href='@'>Info</a>" ;

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  • Adding fields to Django form dynamically (and cleanly)

    - by scott
    Hey guys, I know this question has been brought up numerous times, but I'm not quite getting the full implementation. As you can see below, I've got a form that I can dynamically tell how many rows to create. How can I create an "Add Row" link that tells the view how many rows to create? I would really like to do it without augmenting the url... # views.py def myView(request): if request.method == "POST": form = MyForm(request.POST, num_rows=1) if form.is_valid(): return render_to_response('myform_result.html', context_instance=RequestContext(request)) else: form = MyForm(num_rows=1) return render_to_response('myform.html', {'form':form}, context_instance=RequestContext(request)) # forms.py class MyForm(forms.Form): def __init__(self, *args, **kwargs): num_rows = kwargs.pop('num_rows',1) super(MyForm, self).__init__(*args, **kwargs) for row in range(0, num_rows): field = forms.CharField(label="Row") self.fields[str(row)] = field # myform.html http://example.com/myform <form action="." method="POST" accept-charset="utf-8"> <ul> {% for field in form %} <li style="margin-top:.25em"> <span class="normal">{{ field.label }}</span> {{ field }} <span class="formError">{{ field.errors }}</span> </li> {% endfor %} </ul> <input type="submit" value="Save"> </form> <a href="ADD_ANOTHER_ROW?">+ Add Row</a>

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  • stop form during submission if it validates incorrectly

    - by muqman
    I am trying to use JavaScript to validate forms but if the form doesn't validate, I don't want the form to be sent to the "action" page. The validator: <script> function formSubmit() { document.getElementById("signup_form").submit(); var x=document.forms["signup_form"]["tname"].value; if (x==null || x=="") { alert("First name must be filled out"); return false; } } </script> The form itself: <form action="some_file.php" method="post" id="signup_form" name="signup_form" onsubmit="return formSubmit()"> But all this does is if the tname field empty, it will return an alert but as soon as the user hits ok, the form then redirects to some_file.php. What have I missed here? The submit button: <a href="" onclick="return formSubmit(); return false" class="purplebutton">Signup</a> So what have I missed? How do I avoid this in the future?

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