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  • How can I use a php array in a mysql search query?

    - by ThinkingInBits
    I was going to use the scuttle solution on: http://www.pui.ch/phred/archives/2005/04/tags-database-schemas.html for handling searches on my website. I was wondering how I could take the search input from a user and turn it into a single query. For instance, let's say a user inputted 'blue dogs' in their search query... How could I dynamically update the query to include ('blue', 'dogs') in union and intersection queries?

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  • Border coming around hyperlinked images

    - by pallab
    There is a blue border coming around the hyperlinked images in Firefox. However, no such border can be seen on Chrome. Have a look at http://windchimes.co.in/index_w%20-%20Copy.html The icons have a blue border on firefox but no in chrome. what can be the reason and how do i remove the colored border?

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  • How to store enum values in a NSMutableArray

    - by Oysio
    My problem is since an enum in objective-c essentially is an int value, I am not able to store it in a NSMutableArray. Apparently NSMutableArray won't take any c-date types like an int. Is there any common way to achieve this ? typedef enum { green, blue, red } MyColors; NSMutableArray *list = [[NSMutableArray alloc] initWithObjects: green, blue, red, nil]; //Get enum value back out MyColors greenColor = [list objectAtIndex:0];

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  • Detecting Markers Using OpenCV

    - by Hamza Yerlikaya
    I am trying to detect various objects containing colored markers, so a red blue green marker identifies object A, and a red blue red marker identifies object B. My problem is I can't use template matching cause objects can be rotated, currently I am thinking about check for each color then find the object by checking the distance between colors but it seems inefficient, so my question is there a better way to do this?

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  • Is there any way to add a MouseListener to a Graphic object ?

    - by Fahad
    Hi, Is there any way to add a MouseListener to a Graphic object. I have this simple GUI that draw an oval. What I want is handling the event when the user clicks on the oval import java.awt.*; import java.awt.event.MouseEvent; import java.awt.event.MouseListener; import javax.swing.*; public class Gui2 extends JFrame { JFrame frame = new JFrame(); MyDrawPanel drawpanel = new MyDrawPanel(); public static void main(String[] args) { Gui2 gui = new Gui2(); gui.go(); } public void go() { frame.getContentPane().add(drawpanel); // frame.addMouseListener(this); frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); frame.setSize(300, 300); frame.setVisible(true); } } class MyDrawPanel extends JComponent implements MouseListener { public void paintComponent(Graphics g) { int red = (int) (Math.random() * 255); int green = (int) (Math.random() * 255); int blue = (int) (Math.random() * 255); Color startrandomColor = new Color(red, green, blue); red = (int) (Math.random() * 255); green = (int) (Math.random() * 255); blue = (int) (Math.random() * 255); Color endrandomColor = new Color(red, green, blue); Graphics2D g2d = (Graphics2D) g; this.addMouseListener(this); GradientPaint gradient = new GradientPaint(70, 70, startrandomColor, 150, 150, endrandomColor); g2d.setPaint(gradient); g2d.fillOval(70, 70, 100, 100); } @Override public void mouseClicked(MouseEvent e) { if ((e.getButton() == 1) && (e.getX() >= 70 && e.getX() <= 170 && e.getY() >= 70 && e .getY() <= 170)) { this.repaint(); // JOptionPane.showMessageDialog(null,e.getX()+ "\n" + e.getY()); } } @Override public void mouseEntered(MouseEvent e) { // TODO Auto-generated method stub } @Override public void mouseExited(MouseEvent e) { // TODO Auto-generated method stub } @Override public void mousePressed(MouseEvent e) { // TODO Auto-generated method stub } @Override public void mouseReleased(MouseEvent e) { // TODO Auto-generated method stub } } This Works Except it fires when the click is within a virtual box around the oval. Could anyone help me to have it fire when the click is EXACTLY on the oval. Thanks in advance.

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  • How to add changebar in latex?

    - by Rabarberski
    In Latex, I've created a new command 'changedtext' to mark specifics parts in my document and make it appear blue: \newcommand{\changedtext}[1]{\textcolor{blue}{#1} } Is there any easy way to alter the command to have change bars appear next to the text in the resulting PDF? If not possible, any other suggestion for a visual markup (other than change bars) that would be clear on a black & white printout would be useful as well.

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  • Jquery toggle function that doesn't return false?

    - by Tom
    Hi, Is it possible to stop the automatic preventDefault() from applying in a simple Jquery toggle function? $(".mydiv").toggle( function () { $(this).addClass("blue"); }, function () { $(this).removeClass("blue"); } ); The above prevents elements inside the div from responding normally to the click. It doesn't have to be the toggle() function - anything that allows toggling a class on and off AND doesn't return false would be great. Thanks.

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  • (Python) Converting a dictionary to a list?

    - by Daria Egelhoff
    So I have this dictionary: ScoreDict = {"Blue": {'R1': 89, 'R2': 80}, "Brown": {'R1': 61, 'R2': 77}, "Purple": {'R1': 60, 'R2': 98}, "Green": {'R1': 74, 'R2': 91}, "Red": {'R1': 87, 'Lon': 74}} Is there any way how I can convert this dictionary into a list like this: ScoreList = [['Blue', 89, 80], ['Brown', 61, 77], ['Purple', 60, 98], ['Green', 74, 91], ['Red', 87, 74]] I'm not too familiar with dictionaries, so I really need some help here. Thanks in advance!

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  • How to get rid of box around linked image

    - by Earlz
    Hello, I know I've solved this problem before, but I can't remember or find the solution, so here I am... In Firefox 3.5 this code causes an undesirable blue border around the image. How do I get rid of this blue border? <a style="text-decoration: none;" href="index.html"> <img src="http://www.google.com/logos/stpatricksday10-hp.gif" /> </a> http://jsbin.com/umuzo3

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  • Displaying bitmaps in relative positions

    - by JonF
    I'd like to put a couple images on a surfaceview. I understand that the screen sizes of android devices can vary, so I don't think I can just use an x y position or I might end up placing it off different screens. Say I want to put two boxes in the center of the screen, a blue one and a red one. The blue one is to the left of the red one. How can I accomplish that while accounting for different screen sizes?

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  • Python: Comparing specific columns in two csv files

    - by coder999
    Say that I have two CSV files (file1 and file2) with contents as shown below: file1: fred,43,Male,"23,45",blue,"1, bedrock avenue" file2: fred,39,Male,"23,45",blue,"1, bedrock avenue" I would like to compare these two CSV records to see if columns 0,2,3,4, and 5 are the same. I don't care about column 1. What's the most pythonic way of doing this? EDIT: Some example code would be appreciated.

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  • Excelsheet query

    - by kunj
    Hi, Please tell me how can I find the last word from any particular cell in excel sheet if cell contains multiple words or instructions. For ex- The below string is in particular cell: C:\Documents and Settings\All Users\Documents\My Pictures\Sample Pictures\Blue hills.jpg My requirement is to search only last word in that cell i.e. Blue hills.jpg Your early response is highly appreciated!!!

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  • Air/Flex concatenating a variable with a property

    - by Deyon
    I have three text boxes on the stage id=red, blue, green same as the keys in my cars Object/Array public function carsToBox():void { var cars:Object={red:"300zx",blue:"Skyline",green:"Supra"}; for(var tempObj:String in cars) { tempObj.text= cars[tempObj];//this trows errors } } So I'm thinking "tempObj.text" would equal red.text but I can't stick "tempObj" with ".text" is there a way this can be done?

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  • iPod Touch (OS 3.0) bluetooth connection to non apple device

    - by Avi
    I need to know if I can programmatically connect my iPod Touch (OS 3.0) to a non apple blue tooth device, Using the Apple iPhone SDK. I know that I can connect to other iPhone using GameKit API, But can I connect to other non apple Bluetooth devices for example an measuring device that send out real time data over blue tooth?

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  • Line up swing components by edges

    - by rasen58
    Is it possible to line up swing components? The components are in separate panels which both use flow layout. These two panels are in another panel which is using a grid layout. As you can see there is a subtle difference and I find it annoying. I know that all of the jlabels [the rectangles in blue/purple all have the same size, so i think it might be because of the '+' and '*', but I'm not sure because the left sides of the first two boxes aren't lined up. the panels JPanel panel2 = new JPanel(new GridLayout(4, 1)); JPanel panel2a = new JPanel(new FlowLayout()); JPanel panel2b = new JPanel(new FlowLayout()); the first two rectangles (purple) add1 = new JLabel("", JLabel.CENTER); add1.setTransferHandler(new TransferHandler("text")); add1.setBorder(b2); add2 = new JLabel("", JLabel.CENTER); add2.setTransferHandler(new TransferHandler("text")); add2.setBorder(b2); the two blue rectangles textFieldA = new JTextField(); textFieldA.setHorizontalAlignment(JTextField.CENTER); textFieldA.setEditable(false); textFieldA.setBorder(new LineBorder(Color.blue)); textFieldM = new JTextField(); textFieldM.setHorizontalAlignment(JTextField.CENTER); textFieldM.setEditable(false); textFieldM.setBorder(new LineBorder(Color.blue)); the + and * opA = new JLabel("+", JLabel.CENTER); opS = new JLabel("*", JLabel.CENTER); Showing that the rectangles are the same size Dimension d = card1.getPreferredSize(); int width = d.width + 100; int height = d.height + 50; add1.setPreferredSize(new Dimension(width, height)); add2.setPreferredSize(new Dimension(width, height)); mult1.setPreferredSize(new Dimension(width, height)); mult2.setPreferredSize(new Dimension(width, height)); textFieldA.setPreferredSize(new Dimension(width, height)); textFieldM.setPreferredSize(new Dimension(width, height)); Adding to the panels panel2a.add(add1); panel2a.add(opA); panel2a.add(add2); panel2a.add(enterA); panel2a.add(textFieldA); panel2c.add(mult1); panel2c.add(opM); panel2c.add(mult2); panel2c.add(enterM); panel2c.add(textFieldM); panel2.add(panel2a); panel2.add(panel2c);

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  • CSS: a:link vs just a (without the :link part)

    - by Rob
    So we're required to use the following order for CSS anchor pseudo-classes a:link { color: red } a:visited { color: blue } a:hover { color: yellow } a:active { color: lime } But my question is why bother with the a:link part? Rather, is there any advantage to the above (other than perhaps clarity) over: a { color:red; } /* notice no :link part */ a:visited { color: blue; } etc.,etc.

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  • HTG Explains: Why Does Rebooting a Computer Fix So Many Problems?

    - by Chris Hoffman
    Ask a geek how to fix a problem you’ve having with your Windows computer and they’ll likely ask “Have you tried rebooting it?” This seems like a flippant response, but rebooting a computer can actually solve many problems. So what’s going on here? Why does resetting a device or restarting a program fix so many problems? And why don’t geeks try to identify and fix problems rather than use the blunt hammer of “reset it”? This Isn’t Just About Windows Bear in mind that this soltion isn’t just limited to Windows computers, but applies to all types of computing devices. You’ll find the advice “try resetting it” applied to wireless routers, iPads, Android phones, and more. This same advice even applies to software — is Firefox acting slow and consuming a lot of memory? Try closing it and reopening it! Some Problems Require a Restart To illustrate why rebooting can fix so many problems, let’s take a look at the ultimate software problem a Windows computer can face: Windows halts, showing a blue screen of death. The blue screen was caused by a low-level error, likely a problem with a hardware driver or a hardware malfunction. Windows reaches a state where it doesn’t know how to recover, so it halts, shows a blue-screen of death, gathers information about the problem, and automatically restarts the computer for you . This restart fixes the blue screen of death. Windows has gotten better at dealing with errors — for example, if your graphics driver crashes, Windows XP would have frozen. In Windows Vista and newer versions of Windows, the Windows desktop will lose its fancy graphical effects for a few moments before regaining them. Behind the scenes, Windows is restarting the malfunctioning graphics driver. But why doesn’t Windows simply fix the problem rather than restarting the driver or the computer itself?  Well, because it can’t — the code has encountered a problem and stopped working completely, so there’s no way for it to continue. By restarting, the code can start from square one and hopefully it won’t encounter the same problem again. Examples of Restarting Fixing Problems While certain problems require a complete restart because the operating system or a hardware driver has stopped working, not every problem does. Some problems may be fixable without a restart, though a restart may be the easiest option. Windows is Slow: Let’s say Windows is running very slowly. It’s possible that a misbehaving program is using 99% CPU and draining the computer’s resources. A geek could head to the task manager and look around, hoping to locate the misbehaving process an end it. If an average user encountered this same problem, they could simply reboot their computer to fix it rather than dig through their running processes. Firefox or Another Program is Using Too Much Memory: In the past, Firefox has been the poster child for memory leaks on average PCs. Over time, Firefox would often consume more and more memory, getting larger and larger and slowing down. Closing Firefox will cause it to relinquish all of its memory. When it starts again, it will start from a clean state without any leaked memory. This doesn’t just apply to Firefox, but applies to any software with memory leaks. Internet or Wi-Fi Network Problems: If you have a problem with your Wi-Fi or Internet connection, the software on your router or modem may have encountered a problem. Resetting the router — just by unplugging it from its power socket and then plugging it back in — is a common solution for connection problems. In all cases, a restart wipes away the current state of the software . Any code that’s stuck in a misbehaving state will be swept away, too. When you restart, the computer or device will bring the system up from scratch, restarting all the software from square one so it will work just as well as it was working before. “Soft Resets” vs. “Hard Resets” In the mobile device world, there are two types of “resets” you can perform. A “soft reset” is simply restarting a device normally — turning it off and then on again. A “hard reset” is resetting its software state back to its factory default state. When you think about it, both types of resets fix problems for a similar reason. For example, let’s say your Windows computer refuses to boot or becomes completely infected with malware. Simply restarting the computer won’t fix the problem, as the problem is with the files on the computer’s hard drive — it has corrupted files or malware that loads at startup on its hard drive. However, reinstalling Windows (performing a “Refresh or Reset your PC” operation in Windows 8 terms) will wipe away everything on the computer’s hard drive, restoring it to its formerly clean state. This is simpler than looking through the computer’s hard drive, trying to identify the exact reason for the problems or trying to ensure you’ve obliterated every last trace of malware. It’s much faster to simply start over from a known-good, clean state instead of trying to locate every possible problem and fix it. Ultimately, the answer is that “resetting a computer wipes away the current state of the software, including any problems that have developed, and allows it to start over from square one.” It’s easier and faster to start from a clean state than identify and fix any problems that may be occurring — in fact, in some cases, it may be impossible to fix problems without beginning from that clean state. Image Credit: Arria Belli on Flickr, DeclanTM on Flickr     

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  • How to replace a div container with javascript

    - by Kovu
    Hi, I must have a little design in javascript. I have a menu with 5 entrys and only 1 HTML-page. So I will have a content-div and enabled and disabled different static content in it, each menu-entry is another content. I tried with 5 divs and disable 4 of them and enable 1, but the element under each other means every div is like a - enabled or not, so the "content" is moving then. Hope its understandable. Here is the code so far: <html><head><title>Des Einsame-Katerchen's kleine Homepage</title> <style type="text/css"> a:link { font-weight:bold; color:blue; text-decoration:none; } a:visited { font-weight:bold; color:blue; text-decoration:none; } a:focus { font-weight:bold; color:blue; text-decoration:none; } a:hover { font-weight:bold; color:blue; text-decoration:line-through; } a:active { font-weight:bold; color:blue; text-decoration:none; } h1:focus { background-color:red; } h1:hover { background-color:silver; } h1:active { background-color:green; } </style> <script> function an(id) { document.getElementById('start').style.visibility = 'hidden'; document.getElementById('start').style.height = '0px'; document.getElementById('me').style.visibility = 'hidden'; document.getElementById('me').style.height = '0px'; document.getElementById('rpg').style.visibility = 'hidden'; document.getElementById('rpg').style.height = '0px'; document.getElementById('musik').style.visibility = 'hidden'; document.getElementById('musik').style.height = '0px'; document.getElementById('screens').style.visibility = 'hidden'; document.getElementById('screens').style.height = '0px'; document.getElementById(id).style.visibility = 'visible'; document.getElementById(id).style.height = '500px'; } </script> </head> <body style=" " > <div style="width=100%; text-align:center; border: 1px red solid; height:40px;"> <div style="float:left; width:100px;"><a href="#" OnClick="an('start')" >Startseite</a></div> <div style="float:left; width:100px;"><a href="#" OnClick="an('me')" >Über mich</a></div> <div style="float:left; width:100px;"><a href="#" OnClick="an('rpg')" >RPG-Chars</a></div> <div style="float:left; width:100px;"><a href="#" OnClick="an('musik')" >Musik</a></div> <div style="float:left; width:150px;"><a href="#" OnClick="an('screens')" >Knuddels-Screens</a></div> </div> <br> <div id="start" style="border:1px red solid; width:500px; height:500px; overflow: visible; " > a </div> <div id="me" style="border:1px red solid; width:500px; height:0px; overflow: visible; visibility: hidden; " > b </div> <div id="rpg" style="border:1px red solid; width:500px; height:0px; overflow: visible; visibility: hidden; " > c </div> <div id="musik" style="border:1px red solid; width:500px; height:0px; overflow: visible; visibility: hidden; " > d </div> <div id="screens" style="border:1px red solid; width:500px; height:0px; overflow: visible; visibility: hidden; " > e </div> </body>

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