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  • MySQL GROUP_CONCAT + IN() = missing data :-(

    - by Andrew Heath
    Example: Table: box boxID color 01 red 02 blue 03 green Table: boxHas boxID has 01 apple 01 pear 01 grapes 01 banana 02 lime 02 apple 02 pear 03 chihuahua 03 nachos 03 baby crocodile I want to query on the contents of each box, and return a table with each ID, color, and a column that concatenates the contents of each box, so I use: SELECT box.boxID, box.color, GROUP_CONCAT(DISTINCT boxHas.has SEPARATOR ", ") AS contents FROM box LEFT JOIN boxHas ON box.boxID=boxHas.boxID WHERE boxHas.has IN ('apple','pear') GROUP BY box.boxID ORDER BY box.boxID and I get the following table of results: boxID color contents 01 red apple, pear 02 blue apple, pear My question to you is: why isn't it listing ALL the has values in the contents column? Why is my WHERE statement also cropping my GROUP_CONCAT? The table I thought I was going to get is: boxID color contents 01 red apple, banana, grapes, pear 02 blue apple, lime, pear Although I want to limit my boxID results based upon the WHERE statement, I do not want to limit the contents field for valid boxes. :-/ Help?

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  • In which order are CSS styles applied?

    - by citronas
    I have the following HTML. <ul> <li> <a>asdas</a> </li> </ul> In my CSS stylesheet I have general settings for the a tag, and several hundered lines later settings for ul li a. Like this: a:link { color: red; } ... ul li a { color:blue; } Firebug tells me, that first the color:blue is loaded, and afterwards overriden by color:red So far I've always thought, that the order of loading css files and the order of style inside a single css file tell the browser how html elements should be formatted. Unfortunately I'm now experiencing it vice versa. So tell me, how must I correct my style to achieve the a tag inside the li to be rendered blue and not red?

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  • Loop colours from variables for graphics.py [Python 3.2]

    - by user1056548
    I am creating a graphics program that draws 100 x 100 squares next to each other depending on the user-specified grid size. The user also inputs 4 colours for the squares to be coloured (e.g. if they enter red,green,blue,yellow the squares will be coloured in that order, repeating the colours). Is it possible to loop the colours from the variables the user has given? Here is what I have so far: def main(): print ("Please enter four comma seperated colours e.g.: 'red,green,blue,yellow'\n\ Allowed colours are: red, green, blue, yellow and cyan") col1, col2, col3, col4 = input("Enter your four colours: ").split(',') win = GraphWin ("Squares", 500, 500) colours = [col1, col2, col3, col4] drawSquare (win, col1, col2, col3, col4, colours) win.getMouse() win.close() def drawSquare(win, col1, col2, col3, col4, colours): for i in range (4): for j in range (len(colours)): colour = colours[j] x = 50 + (i * 50) circle = Circle (Point (x,50), 20) circle.setFill(colour) circle.draw(win) I think I should be using a list in some way, but can't work out exactly how to do it. Can anybody help?

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  • C/C++ enum and char * array

    - by Eric M
    Ran accross the following code in an article and didn't think it was standard C/C++ syntax for the char* array. As a test, both Visual C++ (visual studio 2005) and C++ Builder Rad XE both reject the 2nd line. Without using #defines, anyone have any tricks/tips for keeping enums and a string array sort of in sync without resorting to STL ? More of a curiosity question. enum TCOLOR { RED, GREEN, BLUE }; char *TNCOLOR[] = { [RED]="Red", [GREEN]="Green", [BLUE]="Blue" }; as an aside, the article this came from is quite old and I believe this might work under GCC but have not tested.

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  • Why would GDI+ colours vary based off whether a tooltip is visible?

    - by dlanod
    I'm displaying a bitmap using GDI+. After loading the bitmap from a DLL resource I set the background colour (blue - #0000FF) to transparent using TransparentBlt. On Windows Vista and later this works as expected. However, on a Windows XP system we're testing on this only works when any tooltip (e.g. the "title" property in IE, or Windows Explorer's tooltip shown when hovering the mouse over a file, etc) is displayed. The rest of the time the background colour is still blue. Has anyone encountered this before, or know of a way to stop this occurring and for the blue to be properly made transparent?

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  • Using Cases to change background colour | Visual Studio 2008

    - by Simon
    I really need help working with cases, I'm only learning it so far, but just can't get a drop down menu to work that would change the background of a Textbox. Private Sub cbColours_SelectedIndexChanged(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles cbColours.SelectedIndexChanged Select Case colours Case Is = "Red" txtSpace.BackColor = Color.Red Case Is = "Blue" txtSpace.BackColor = Color.Blue Case Is = "Green" txtSpace.BackColor = Color.Green End Select End Sub It isn't doing anything at all... In the dropdown menu, it has Red, Blue and Green one per line When the value (e.g. Green) is clicked, it will then change the Textbox to the colour selected. Many help appreciated :)

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  • Re-Add tabBarController's view into window and the device is in landscape mode

    - by user285553
    Hello, I have an app that is a tabBarController based app. I have 4 tabs on it and one of these is for logging in/out in my app. The main ideea is that when I logout, I release the tabBarController (this will release the all 4 view controllers too - I have done this becuse I want to refersh all the views after logging out to look just like the first time).After this, I alloc it again and add the view controllers aagin,set the tabBarItem's titles,etc.This work ok. The problem is when I am in landscape mode;my logout view is painted to fit the landscape area,but after disconnect(now I releasse and alloc again the tabbarController) the view is painted in portrait mode but my device is in lanscape. After disconnected, I call the releaseOldTabView and the createNewTabView.After this tabBarController is in portrait insead of landscape. -(void)releaseOldTabView:(BOOL)tabViewEnabled{ if(tabViewEnabled){ [tabBarController.view removeFromSuperview]; [tabBarController release]; } } -(void)createNewTabView{ tabBarController = [[UITabBarController alloc] init]; NSMutableArray *oneArray = [[NSMutableArray alloc] init]; tabBarController.delegate = self; LoginViewController *login= [[LoginViewController2 alloc] initWithNibName:@"LoginViewController" bundle:nil]; SecondViewController *secondController = [[SecondViewController alloc] initWithNibName:@"SecondViewController" bundle:nil]; ThirdViewController *thirdController = [[ThirdViewController alloc] init]; FourthViewController *fourthController = [[FourthViewController alloc] init]; login.tabBarItem = [[UITabBarItem alloc] initWithTitle:@"Login" image:[UIImage imageNamed:@"connect.png"] tag:0]; secondController.tabBarItem = [[UITabBarItem alloc] initWithTitle:@"TabBar2" image:[UIImage imageNamed:@"tabBar2.png"] tag:1]; thirdController.tabBarItem = [[UITabBarItem alloc] initWithTitle:@"TabBar3" image:[UIImage imageNamed:@"tabBar3.png"] tag:2]; fourthController.tabBarItem = [[UITabBarItem alloc] initWithTitle:@"TabBar4" image:[UIImage imageNamed:@"tabBar4.png"] tag:3]; [oneArray addObject:login]; [oneArray addObject:secondController]; [oneArray addObject:thirdController]; [oneArray addObject:fourthController]; [tabBarController setViewControllers:oneArray]; //[tabBarController.view convertRect:tabBarController.view.frame toView:window]; [window addSubview:tabBarController.view]; [oneArray release]; [login release]; [secondController release]; [thirdController release]; [fourthController release]; } After calling this method, the tabbar view is in portrait,but statusBar(the top bar which says the carrier name) is painted normally(landscape). I also tried the [tabBarController.view convertRect:tabBarController.view.frame toView:window]; but without any succes. Can anyone give a hand of help? Thanks in advance, Alex.

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  • MySQL: Get unique values across multiple columns in alphabetical order

    - by RuCh
    Hey everyone, If my table looks like this: id | colA | colB | colC =========================== 1 | red | blue | yellow 2 | orange | red | red 3 | orange | blue | cyan What SELECT query do I run such that the results returned are: blue, cyan, orange, red, yellow Basically, I want to extract a collective list of distinct values across multiple columns and return them in alphabetical order. I am not concerned with performance optimization, because the results are being parsed to an XML file that will serve as a cache (database is hardly updated). So even a dirty solution would be fine. Thanks for any help!

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  • Separating an Array into a comma seperated string with quotes

    - by user548744
    I'm manually building an SQL query where I'm using an Array in the params hash for an SQL IN statement, like: ("WHERE my_field IN('blue','green','red')"). So I need to take the contents of the array and output them into a string where each element is single quoted and comma seperated (and with no ending comma). So if the array was: my_array = ['blue','green','red'] I'd need a string that looked like: "'blue','green','red'" I'm pretty new to Ruby/Rails but came up with something that worked: if !params[:colors].nil? @categories_array = params[:colors][:categories] @categories_string ="" for x in @categories_array @categories_string += "'" + x + "'," end @categories_string.chop! #remove the last comma end So, I'm good but curious as to what a proper and more consise way of doing this would look like? Thanks

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  • Stable separation for two classes of elements in an array

    - by AndreyT
    Consider the following problem. We are given an array of elements belonging to one two classes: either red or blue. We have to rearrange the elements of the array so that all blue elements come first (and all red elements follow). The rearrangement must be done is stable fashion, meaning that the relative order of blue elements must be preserved (same for red ones). Is there a clever algorithm that would perform the above rearrangement in-place? A non-in place solution is, of course, straightforward. An obvious in-place solution would be to apply any stable sorting algorithm to the array. However, using a full-fledged sorting algorithm on an array intuitively feels like an overkill, especially taking into account the fact that we are only dealing with two classes of elements. Any ideas greatly appreciated.

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  • Regular Expression issue

    - by Christian Sciberras
    I have the following URL structure which I need to match to and get the particular id from: /group/subgroup/id-name In short, I need to translate a URL like the following: /Blue Products/Dark Blue/5-Blue_Jelly To: /?pagename=Blue Products&model=5 IMPORTANT: I don't need to match group, I already have group. Example code: <?php foreach($cats as $cat) $cmd->rewrite('/\/'.$cat.'\/unused\/(ID)-unused\//','/?pagename='.$cat.'&model=%ID%'); ?> Edit: This is the completed code: if($groups->count()){ $names=array(); foreach($groups->rows as $row) $names[]=preg_quote($row->group); $names=implode('|',$names); $regex='('.$names.')/([^/]+)/([0-9]{1,})-([^/]+)/?$'; CmsHost::cms()->rewrite_url($regex,'index.php?pagename=Products',true); }

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  • How do you set a cookie to be accessible across the entire domain in Javascript

    - by Tzarkov
    I suppose there should be a way to set a cookie to be accessible from the entire domain nevermind from which directory you are setting the cookie. Say in mypage.com/blue/index.php y set the cookie "colour=blue;" this way: document.cookie = "colour" + "=" + "blue" + "; expires=" + expireDate.toGMTString() + "; path=/"; Using this code, the cookie retrieval function in mypage.com/home.php can't access the content of the cookie. If it was just from first level directories that the cookie needs to be set, we would be ok by doing path=../ instead of path=/ But how do you go about writing generic code that sets a cookie that is accessible from any page in that domain not minding how deep in the file structure is the page the cookie is being set from?

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  • SEO URL Structure

    - by Neil
    Based on the following example URL structure: mysite.com/mypage.aspx?a=red&b=green&c=blue Pages in the application use ASP.net user controls and some of these controls build a query string. To prevent duplicate keys being created e.g. &pid=12&pid=10, I am researching methods of rewriting the URL: a) mysite.com/mypage.aspx/red/green/blue b) mysite.com/mypage.aspx?controlname=a,red|b,green|c,blue Pages using this structure would be publishing content that I would like to get indexed and ranked - articles and products (8,000 products to start, with thousands more being added later) My gut instinct tells me to go with the first method, but would it would be overkill to add all that infrastructure if the second method will accomplish my goal of getting pages indexed AND ranked. So my question, looking at the pro's and con's, Google Ranking, time to implement etc. which method should I use? Thanks!

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  • comparing 3 arrays and result in 1 array

    - by frightnight
    i have 3 arrays, i want to get the result of those 3 arrays in one, but how can i deleted those same answer in a arrays? here's my example: <?php $array1 = array("a" => "green", "red", "blue"); $array2 = array("b" => "green", "yellow", "red"); $array3 = array("c" => "white", "blue", "black"); $result = ??? ($array1, $array2, $array3); print_r($result); ?> Array ( [0] => green [1] => red [2] => blue [3] => yellow [4] => red [5] => white [5] => black ) please help me guys.. thank you..

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  • R scatterplot overplotting color

    - by rgeekay
    So far I have this: qplot(df[[1]], as.numeric(rownames(df)), group=df[[2]], color=df[[2]], ylab="") I want to use different colors for the points in the 2 groups - perhaps a lighter shade for the what's in black now and a darker - say, red for what's in blue. Also, I want to use hexbin kind of thing for group=0 but not for group=1. I'm not able to get the syntax to get this working. In the current plot 0 is in black and 1 is in blue. Added: I worked on it some more, and by using factor and scale_colour_manual, I got the grey color for 0 and red for 1: > palette1 [1] "grey" "red" "blue" "violet" "black" fy=factor(y, labels=c('grey', 'red')) qplot(x, seq(1:length(x)),col=fy, ylab="") + geom_point() + scale_colour_manual(values=palette1) Pending questions are: How to first plot all the grey and then red on top (some of the red is now hidden because the grey is plotted over). How to apply the hexbin logic for group0 i.e. the grey points only and not for the red.

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  • I'm looking for a blend mode that gives 'realistic' paint colors. (Subtractive)

    - by almosnow
    I've been looking for a blend mode to (well ...) blend two RGB pixels in order to build colors in the samw way that a painter builds them (i.e: subtractive). Here are quick examples of the type of results that I'm expecting: CYAN + MAGENTA = BLUE CYAN + YELLOW = GREEN MAGENTA + YELLOW = RED RED + YELLOW = ORANGE RED + BLUE = PURPLE YELLOW + BLUE = GREEN I'm looking for a formula, like: dest_red = first_red + second_red; dest_green = first_green + second_green; dest_blue = first_blue + second_blue; I've tried with the commonly used 'multiply' formula but it doesn't work; I've tried with custom made formulas but I'm still not able to 'crack' how it should work. And I know already a lot of color theory so please refrain from answers like: Check this link: http://the_difference_betweeen_additive_and_subtractive_lightning.html

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  • xgamma -display parameter for dual monitor setup

    - by Shiplu
    I want to change gamma for my first monitor. Every time I invoke xgamma with different -display parameters it somehow points to my second monitor. But I want to modify first one. I tried these commands. The parameters I have used for -display are :0, :0.0, :0.1, :1.0, :1.1, :1. Only the first 2 works. But it points to my second monitor. Not the first one. Here is a shell script to test it. shiplu@KubuntuD:~$ xgamma -display :0 -> Red 1.000, Green 1.000, Blue 1.000 shiplu@KubuntuD:~$ xgamma -display :0.0 -> Red 1.000, Green 1.000, Blue 1.000 shiplu@KubuntuD:~$ xgamma -display :0.1 xgamma: unable to open display ':0.1' shiplu@KubuntuD:~$ xgamma -display :1.0 xgamma: unable to open display ':1.0' shiplu@KubuntuD:~$ xgamma -display :1.1 xgamma: unable to open display ':1.1' shiplu@KubuntuD:~$ xgamma -display :1 xgamma: unable to open display ':1' How can I change the gamma for the first/primary monitor?

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  • HTG Explains: Why is Printer Ink So Expensive?

    - by Chris Hoffman
    Printer ink is expensive, more expensive per drop than fine champagne or even human blood. If you haven’t gone paperless, you’ll notice that you’re paying a lot for new ink cartridges — more than seems reasonable. Purchasing the cheapest inkjet printer and buying official ink cartridge replacements is the most expensive thing you can do. There are ways to save money on ink if you must continue to print documents. Cheap Printers, Expensive Ink Ink jet printers are often very cheap. That’s because they’re sold at cost, or even at a loss — the manufacturer either makes no profit from the printer itself or loses money. The manufacturer will make most of its money from the printer cartridges you buy later. Even if the company does make a bit of money from each printer sold, it makes a much larger profit margin on ink. Rather than selling you a printer that may be rather expensive, they want to sell you a cheap printer and make money on an ongoing basis by providing expensive printer ink. It’s been compared to the razor model — sell a razor cheaply and mark up the razor blades. Rather than making a one-time profit on the razor, you’ll make continuing profit as the customer keeps buying razor blade replacements — or ink, in this case. Many printer manufacturers go out of their way to make it difficult for you to use unofficial ink cartridges, building microchips into their official ink cartridges. If you use an unofficial cartridge or refill an official cartridge, the printer may refuse to use it. Lexmark once argued in court that unofficial microchips that enable third-party ink cartridges would violate their copyright and Lexmark has argued that creating an unofficial microchip to bypass this restriction on third-party ink would violate Lexmark’s copyright and be illegal under the US DMCA. Luckily, they lost this argument. What Printer Companies Say Printer companies have put forth their own arguments in the past, attempting to justify the high cost of official ink cartridges and microchips that block any competition. In a Computer World story from 2010, HP argued that they spend a billion dollars each year on “ink research and development.” They point out that printer ink “must be formulated to withstand heating to 300 degrees, vaporization, and being squirted at 30 miles per hour, at a rate of 36,000 drops per second, through a nozzle one third the size of a human hair. After all that it must dry almost instantly on the paper.” They also argue that printers have become more efficient and use less ink to print, while third-party cartridges are less reliable. Companies that use microchips in their ink cartridges argue that only the microchip has the ability to enforce an expiration date, preventing consumers from using old ink cartridges. There’s something to all these arguments, sure — but they don’t seem to justify the sky-high cost of printer ink or the restriction on using third-party or refilled cartridges. Saving Money on Printing Ultimately, the price of something is what people are willing to pay and printer companies have found that most consumers are willing to pay this much for ink cartridge replacements. Try not to fall for it: Don’t buy the cheapest inkjet printer. Consider your needs when buying a printer and do some research. You’ll save more money in the long run. Consider these basic tips to save money on printing: Buy Refilled Cartridges: Refilled cartridges from third parties are generally much cheaper. Printer companies warn us away from these, but they often work very well. Refill Your Own Cartridges: You can get do-it-yourself kits for refilling your own printer ink cartridges, but this can be messy. Your printer may refuse to accept a refilled cartridge if the cartridge contains a microchip. Switch to a Laser Printer: Laser printers use toner, not ink cartridges. If you print a lot of black and white documents, a laser printer can be cheaper. Buy XL Cartridges: If you are buying official printer ink cartridges, spend more money each time. The cheapest ink cartridges won’t contain much ink at all, while larger “XL” ink cartridges will contain much more ink for only a bit more money. It’s often cheaper to buy in bulk. Avoid Printers With Tri-Color Ink Cartridges: If you’re printing color documents, you’ll want to get a printer that uses separate ink cartridges for all its colors. For example, let’s say your printer has a “Color” cartridge that contains blue, green, and red ink. If you print a lot of blue documents and use up all your blue ink, the Color cartridge will refuse to function — now all you can do is throw away your cartridge and buy a new one, even if the green and red ink chambers are full. If you had a printer with separate color cartridges, you’d just have to replace the blue cartridge. If you’ll be buying official ink cartridges, be sure to compare the cost of cartridges when buying a printer. The cheapest printer may be more expensive in the long run. Of course, you’ll save the most money if you stop printing entirely and go paperless, keeping digital copies of your documents instead of paper ones. Image Credit: Cliva Darra on Flickr     

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  • How do I change which audio jacks are used for input and output?

    - by yamaha1996
    I'm using a Realtek HD audio card built-in my motherboard. The Windows driver comes with a control panel that allows me to select which back panel jacks are used for what. So for example I can make both the blue jack and green jack for output and only the red one for mic-in. (Whereas by default, the blue jack is for line in, which I never need.) How can I do the same under Linux? If possible, please don't suggest something that involves PulseAudio or JACK; I'd like to do it the plain way, e.g. by editing ALSA configuration files, if possible. The way I understand it, my problem should have nothing to do with software servers redirecting streams, just instructing the driver to treat this jack as so and so because it's hardware supported. Thank you very much!

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  • How To Disable Accelerators In Internet Explorer 8/9

    - by Gopinath
    Internet Explorer 8 introduced Accelerators features that popups blue icon when we select a piece of text in Internet Explorer. If you are annoyed with this blue icon or Accelerators feature in IE 8/ IE 9 you can disable it easily. Follow these steps 1. Launch Internet Explorer 2. Click Tools -> Internet Options -> Advanced 3. Uncheck the box for Display Accelerator button on selection, under Browsing category. 4. Click Apply and OK. 5. Restart Internet Explorer to apply the changes. That’s all. From now onwards Internet Explorer does not display Accelerators Icon when you select text in the browser. This article titled,How To Disable Accelerators In Internet Explorer 8/9, was originally published at Tech Dreams. Grab our rss feed or fan us on Facebook to get updates from us.

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  • Lynx "Alert!: Unable to connect to remote host."

    - by Deepend
    I'm pretty new to Ubuntu server. I'm running Distributor ID: Ubuntu Description: Ubuntu 12.04.4 LTS Release: 12.04 I have installed Lynx via sudo apt-get install lynx everything installed fine but when I try to connect to a website it just seems to time out. When I run lynx google.com it goes to a blank screen with a blue line at the bottom. There is yellow text on the line which says "Making HTTP connection to google.com" but it just sits there. Eventually after 5 - 6 minutes it just goes back to the normal terminal window If I run the below on its own lynx I get the same blue line with the same text "Making HTTP connection to google.com" but after 30 seconds or so it briefly turns to a red line with "alert!: lynx unable to connect to remote host" written on it. I have installed lynx locally and it works fine. Does anyone have any ideas?

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  • Alpha blend 3D png texture in XNA

    - by ProgrammerAtWork
    I'm trying to draw a partly transparent texture a plane, but the problem is that it's incorrectly displaying what is behind that texture. Pseudo code: vertices1 basiceffect1 // The vertices of vertices1 are located BEHIND vertices2 vertices2 basiceffect2 // The vertices of vertices2 are located IN FRONT vertices1 GraphicsDevice.Clear(Blue); PrimitiveBatch.Begin(); //if I draw like this: PrimitiveBatch.Draw(vertices1, trianglestrip, basiceffect1) PrimitiveBatch.Draw(vertices2, trianglestrip, basiceffect2) //Everything gets draw correctly, I can see the texture of vertices2 trough //the transparent parts of vertices1 //but if I draw like this: PrimitiveBatch.Draw(vertices2, trianglestrip, basiceffect2) PrimitiveBatch.Draw(vertices1, trianglestrip, basiceffect1) //I cannot see the texture of vertices1 in behind the texture of vertices2 //Instead, the texture vertices2 gets drawn, and the transparent parts are blue //The clear color PrimitiveBatch.Draw(vertice PrimitiveBatch.End(); My question is, Why does the order in which I call draw matter?

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  • Finding the contact point with SAT

    - by Kai
    The Separating Axis Theorem (SAT) makes it simple to determine the Minimum Translation Vector, i.e., the shortest vector that can separate two colliding objects. However, what I need is the vector that separates the objects along the vector that the penetrating object is moving (i.e. the contact point). I drew a picture to help clarify. There is one box, moving from the before to the after position. In its after position, it intersects the grey polygon. SAT can easily return the MTV, which is the red vector. I am looking to calculate the blue vector. My current solution performs a binary search between the before and after positions until the length of the blue vector is known to a certain threshold. It works but it's a very expensive calculation since the collision between shapes needs to be recalculated every loop. Is there a simpler and/or more efficient way to find the contact point vector?

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