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  • Python finding repeating sequence in list of integers?

    - by tijko
    I have a list of lists and each list has a repeating sequence. I'm trying to count the length of repeated sequence of integers in the list: list_a = [111,0,3,1,111,0,3,1,111,0,3,1] list_b = [67,4,67,4,67,4,67,4,2,9,0] list_c = [1,2,3,4,5,6,7,8,9,0,1,2,3,4,5,6,7,8,9,0,23,18,10] Which would return: list_a count = 4 (for [111,0,3,1]) list_b count = 2 (for [67,4]) list_c count = 10 (for [1,2,3,4,5,6,7,8,9,0]) Any advice or tips would be welcome. I'm trying to work it out with re.compile right now but, its not quite right.

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  • Python 2.7 creating a multidimensional list

    - by poop
    I don't know why I am having so much trouble creating a 3 dimensional list. I need the program to create an empty n by n list. So for n = 4: x = [[[],[],[],[]],[[],[],[],[]],[[],[],[],[]],[[],[],[],[]]] I've tried using: y = [n*[n*[]]] y = [[[]]* n for i in range(n)] Which both appear to be creating copies of a reference. I've also tried naieve application of the list builder with little success: y = [[[]* n for i in range(n)]* n for i in range(n)] y = [[[]* n for i in range(1)]* n for i in range(n)] I've also tried building up the array iteratively using loops, with no success. In my rapid flurry of attempts to not post something stupidly easy to SO, I came upon a solution: y = [] for i in range(0,n): y.append([[]*n for i in range(n)]) Is there an easier/ more intuitive way of doing this?

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  • Move <option> to top of list with Javascript

    - by Adam
    I'm trying to create a button that will move the currently selected OPTION in a SELECT MULTIPLE list to the top of that list. I currently have OptionTransfer.js implemented, which is allowing me to move items up and down the list. I want to add a new function function MoveOptionTop(obj) { ... } Here is the source of OptionTransfer.js // =================================================================== // Author: Matt Kruse // WWW: http://www.mattkruse.com/ // // NOTICE: You may use this code for any purpose, commercial or // private, without any further permission from the author. You may // remove this notice from your final code if you wish, however it is // appreciated by the author if at least my web site address is kept. // // You may *NOT* re-distribute this code in any way except through its // use. That means, you can include it in your product, or your web // site, or any other form where the code is actually being used. You // may not put the plain javascript up on your site for download or // include it in your javascript libraries for download. // If you wish to share this code with others, please just point them // to the URL instead. // Please DO NOT link directly to my .js files from your site. Copy // the files to your server and use them there. Thank you. // =================================================================== /* SOURCE FILE: selectbox.js */ function hasOptions(obj){if(obj!=null && obj.options!=null){return true;}return false;} function selectUnselectMatchingOptions(obj,regex,which,only){if(window.RegExp){if(which == "select"){var selected1=true;var selected2=false;}else if(which == "unselect"){var selected1=false;var selected2=true;}else{return;}var re = new RegExp(regex);if(!hasOptions(obj)){return;}for(var i=0;i(b.text+"")){return 1;}return 0;});for(var i=0;i3){var regex = arguments[3];if(regex != ""){unSelectMatchingOptions(from,regex);}}if(!hasOptions(from)){return;}for(var i=0;i=0;i--){var o = from.options[i];if(o.selected){from.options[i] = null;}}if((arguments.length=0;i--){if(obj.options[i].selected){if(i !=(obj.options.length-1) && ! obj.options[i+1].selected){swapOptions(obj,i,i+1);obj.options[i+1].selected = true;}}}} function removeSelectedOptions(from){if(!hasOptions(from)){return;}for(var i=(from.options.length-1);i=0;i--){var o=from.options[i];if(o.selected){from.options[i] = null;}}from.selectedIndex = -1;} function removeAllOptions(from){if(!hasOptions(from)){return;}for(var i=(from.options.length-1);i=0;i--){from.options[i] = null;}from.selectedIndex = -1;} function addOption(obj,text,value,selected){if(obj!=null && obj.options!=null){obj.options[obj.options.length] = new Option(text, value, false, selected);}} /* SOURCE FILE: OptionTransfer.js */ function OT_transferLeft(){moveSelectedOptions(this.right,this.left,this.autoSort,this.staticOptionRegex);this.update();} function OT_transferRight(){moveSelectedOptions(this.left,this.right,this.autoSort,this.staticOptionRegex);this.update();} function OT_transferAllLeft(){moveAllOptions(this.right,this.left,this.autoSort,this.staticOptionRegex);this.update();} function OT_transferAllRight(){moveAllOptions(this.left,this.right,this.autoSort,this.staticOptionRegex);this.update();} function OT_saveRemovedLeftOptions(f){this.removedLeftField = f;} function OT_saveRemovedRightOptions(f){this.removedRightField = f;} function OT_saveAddedLeftOptions(f){this.addedLeftField = f;} function OT_saveAddedRightOptions(f){this.addedRightField = f;} function OT_saveNewLeftOptions(f){this.newLeftField = f;} function OT_saveNewRightOptions(f){this.newRightField = f;} function OT_update(){var removedLeft = new Object();var removedRight = new Object();var addedLeft = new Object();var addedRight = new Object();var newLeft = new Object();var newRight = new Object();for(var i=0;i0){str=str+delimiter;}str=str+val;}return str;} function OT_setDelimiter(val){this.delimiter=val;} function OT_setAutoSort(val){this.autoSort=val;} function OT_setStaticOptionRegex(val){this.staticOptionRegex=val;} function OT_init(theform){this.form = theform;if(!theform[this.left]){alert("OptionTransfer init(): Left select list does not exist in form!");return false;}if(!theform[this.right]){alert("OptionTransfer init(): Right select list does not exist in form!");return false;}this.left=theform[this.left];this.right=theform[this.right];for(var i=0;i

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  • Search in a List<DataRow>?

    - by grady
    Hello, I have a List which I create from a DataTabe which only has one column in it. Lets say the column is called MyColumn. Each element in the list is an object array containing my columns, in this case, only one (MyColumn). Whats the most elegant way to check if that object array contains a certain value? Thanks

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  • Skip List vs. Binary Tree

    - by Claudiu
    I recently came across the data structure known as a Skip list. They seem to have very similar behavior to a binary search tree... my question is - why would you ever want to use a skip list over a binary search tree?

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  • Python to MATLAB: exporting list of strings using scipy.io

    - by user292461
    I am trying to export a list of text strings from Python to MATLAB using scipy.io. I would like to use scipy.io because my desired .mat file should include both numerical matrices (which I learned to do here) and text cell arrays. I tried: import scipy.io my_list = ['abc', 'def', 'ghi'] scipy.io.savemat('test.mat', mdict={'my_list': my_list) In MATLAB, I load test.mat and get a character array: my_list = adg beh cfi How do I make scipy.io export a list into a MATLAB cell array?

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  • Python most common element in a list

    - by Richard
    What is an efficient way to find the most common element in a Python list? My list items may not be hashable so can't use a dictionary. Also in case of draws the item with the lowest index should be returned. Example: >>> most_common(['duck', 'duck', 'goose']) 'duck' >>> most_common(['goose', 'duck', 'duck', 'goose']) 'goose'

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  • List - Strings - Textfiles

    - by b3y4z1d
    I've got a few questions concerning text files,list and strings. I wonder if it is possible to put in a code which reads the text in a textfile,and then using "string line;" or something else to define each new row of the text and turn all of them into one list. So I can sort the rows, remove a row or two or even all of them or search through the text for a specific row.

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  • Searchable list of objects in Java

    - by Christian
    I want to create a large (~300,000 entries) List of self defined objects of the class Drug. Every Drug has an ID and I want to be able to search the Drugs in logarithmic time via that ID. What kind of List do I have to use? How do I declare that it should be searchable via the ID?

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  • Python filter/remove URLs from a list

    - by Eef
    Hi. I have a text file of URLs, about 14000. Below is a couple of examples: http://www.domainname.com/pagename?CONTENT_ITEM_ID=100&param2=123 http://www.domainname.com/images?IMAGE_ID=10 http://www.domainname.com/pagename?CONTENT_ITEM_ID=101&param2=123 http://www.domainname.com/images?IMAGE_ID=11 http://www.domainname.com/pagename?CONTENT_ITEM_ID=102&param2=123 I have loaded the text file into a Python list and I am trying to get all the URLs with CONTENT_ITEM_ID separated off into a list of their own. What would be the best way to do this in Python? Cheers

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  • List<> own comparer

    - by netmajor
    I have a List where element is: struct element { double priority; int value; } How can I implement my own comparer which allow me sort List by priority ? I try with SortredList... but it don't allow douplicated keys :( Big thanks for help!

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  • filtering directly and indirectly connected things from list

    - by Andreas Romeyke
    Hello, if you have a function "test a b" which returns true if a and b are connected directly and if you have a given unordered list of things, what would be an elegant and fast solution to filter all connected things from given list? Example: let test a b = let diff = a - b in diff == 0 ;; let lst = [4;1;7;3;8;9;2;0] ;; filter_connected 2 lst ;; - [4;1;3;2;0] Any hints?

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  • sorting a doubly linked list with merge sort.

    - by user329820
    Hi I have found this code in the internet and it was for arrays ,I want to change it for doubly linked list(instead of index we should use pointer) would you please help me that how can i change merge method(I have changed sort method by myself) also this is not my home work ,I love working with linked list!! public class MergeSort { private DoublyLinkedList LocalDoublyLinkedList; public MergeSort(DoublyLinkedList list) { LocalDoublyLinkedList = list; } public void sort() { if (LocalDoublyLinkedList.size() <= 1) { return; } DoublyLinkedList listOne = new DoublyLinkedList(); DoublyLinkedList listTwo = new DoublyLinkedList(); for (int x = 0; x < (LocalDoublyLinkedList.size() / 2); x++) { listOne.add(x, LocalDoublyLinkedList.getValue(x)); } for (int x = (LocalDoublyLinkedList.size() / 2) + 1; x < LocalDoublyLinkedList.size`(); x++) {` listTwo.add(x, LocalDoublyLinkedList.getValue(x)); } //Split the DoublyLinkedList again MergeSort sort1 = new MergeSort(listOne); MergeSort sort2 = new MergeSort(listTwo); sort1.sort(); sort2.sort(); merge(listOne, listTwo); } private void merge(DoublyLinkedList a, DoublyLinkedList b) { int x = 0; int y = 0; int z = 0; while (x < first.length && y < second.length) { if (first[x] < second[y]) { a[z] = first[x]; x++; } else { a[z] = second[y]; y++; } z++; } //copy remaining elements to the tail of a[]; for (int i = x; i < first.length; i++) { a[z] = first[i]; z++; } for (int i = y; i < second.length; i++) { a[z] = second[i]; z++; } } }

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  • How to publish a list of integers?

    - by Mason Wheeler
    I want to make a component that includes a list of integers as one of its serialized properties. I know I can't declare a TList<integer> as a published property, because it doesn't descend from TPersistent. I've read that you can define "fake" published properties if you override DefineProperties, but I'm not quite sure how that works, especially when it comes to creating a fake property that's a list, not a single value. Can someone point me in the right direction?

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  • WPF List - ListItem Visibility

    - by niao
    Greetings, I have a FlowDocument where List control is placed. Inside this list I have some ListItem. Is there any way to set some kind of Visibility for specific ListItem? I don't see a coressponding Property like Visibility for ListItem. When I set fontsize="0.1" then application hangs (it goes into infinite loop).

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  • List multiplication

    - by Schitti
    Hi, Python newbie here. I have a list L = [a, b, c] and I want to generate a list of tuples : [(a,a), (a,b), (a,c), (b,a), (b,b), (b,c)...] I tried doing L * L but it didn't work. Can someone tell me how to get this in python.

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  • Convert a list of strings [ '3', '1' , '2'] to a list of sorted integers [ 1, 2, 3] in Python, how?

    - by Shamim
    I have: L1 = ['11', '10', '13', '12', '15', '14', '1', '3', '2', '5', '4', '7', '6', '9', '8'] this is a list of strings, right? I need to make it a list of integers as follows: L2 = [11, 10, 13, 12, 15, 14, 1, 3, 2, 5, 4, 7, 6, 9, 8] finally I will sort it like below: L3 = [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15] by L2.sort() please let me know how I can get to L3 from L1

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  • The best way to use dictionary items as we use the advantages of List

    - by blgnklc
    I want to get use of dictionary items like I do in List generic class, e.g; foreach(item in ItemList) { item.BlaBla; } but in dictionary there s no chance, like e method above... Dictionary<string, HtmlInputImage> smartPenImageDictionary; I mean I got to know the key item for the dictionary item.. but what I want, I want to travel from beginning of the list till the end..

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  • Remove duplicates from a list

    - by Mercer
    Hello i want to remove duplicates from a list i do this but not working List<Customer> listCustomer = new ArrayList<Customer>(); for (Customer customer: tmpListCustomer) { if (!listCustomer.contains(customer)) { listCustomer.add(customer); } }

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