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  • Reporting Services Sum of Inner Group in Outer Group

    - by Spoonybard
    I have a report in Reporting Services 2008 using ASP.net 3.5 and SQL Server 2008. The report has 2 groupings and a detail row. This is the current format: Outer Group Inner Group Detail Row The Detail Row represents an item on a receipt and a receipt can have multiple items. Each receipt was paid with a certain payment method. So the Outer Group is grouped by payment type, the Inner Group is grouped by the receipt's ID, and the Detail Row is each item for the given receipt. My raw data result set has two important columns: The Amount Received and the Amount Applied. The Amount Received is how much money in total was collected for all the items on the receipt. The Amount Applied is how much money each item got from the total Amount Received. Sample Result Set: ReceiptID Item ItemID AmountReceived AmountApplied Payment Method ------------------------------------------------------------------------------------------ 1 Book 1 $200.00 $40.00 Cash 1 CD 2 $200.00 $20.00 Cash 1 Software 3 $200.00 $100.00 Cash 1 Backpack 4 $200.00 $40.00 Cash The Inner Group displays the AmountReceived correctly as $200. However, the Outer Group displays the AmountReceived as $800, because I believe that it is going off each detail row which in this case is a count of 4 items. What I want is to see in the Outer Group that the Amount Received is $200. I tried restricting the scope in my SUM function to be the Inner Group, but I get the error "The scope parameter must be set to a string constant that is equal to either the name of a containing group, the name of a containing data region, or the name of a dataset." Does anyone have any suggestions on how to solve this issue? Thanks.

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  • How do I create a self referential association (self join) in a single class using ActiveRecord in Rails?

    - by Daniel Chang
    I am trying to create a self join table that represents a list of customers who can refer each other (perhaps to a product or a program). I am trying to limit my model to just one class, "Customer". The schema is: create_table "customers", force: true do |t| t.string "name" t.integer "referring_customer_id" t.datetime "created_at" t.datetime "updated_at" end add_index "customers", ["referring_customer_id"], name: "index_customers_on_referring_customer_id" My model is: class Customer < ActiveRecord::Base has_many :referrals, class_name: "Customer", foreign_key: "referring_customer_id", conditions: {:referring_customer_id => :id} belongs_to :referring_customer, class_name: "Customer", foreign_key: "referring_customer_id" end I have no problem accessing a customer's referring_customer: @customer.referring_customer.name ... returns the name of the customer that referred @customer. However, I keep getting an empty array when accessing referrals: @customer.referrals ... returns []. I ran binding.pry to see what SQL was being run, given a customer who has a "referer" and should have several referrals. This is the SQL being executed. Customer Load (0.3ms) SELECT "customers".* FROM "customers" WHERE "customers"."id" = ? ORDER BY "customers"."id" ASC LIMIT 1 [["id", 2]] Customer Exists (0.2ms) SELECT 1 AS one FROM "customers" WHERE "customers"."referring_customer_id" = ? AND "customers"."referring_customer_id" = 'id' LIMIT 1 [["referring_customer_id", 3]] I'm a bit lost and am unsure where my problem lies. I don't think my query is correct -- @customer.referrals should return an array of all the referrals, which are the customers who have @customer.id as their referring_customer_id.

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  • Join us for Live Oracle Linux and Oracle VM Cloud Events in Europe

    - by Monica Kumar
    Join us for a series of live events and discover how Oracle VM and Oracle Linux offer an integrated and optimized infrastructure for quickly deploying a private cloud environment at lower cost. As one of the most widely deployed operating systems today, Oracle Linux delivers higher performance, better reliability, and stability, at a lower cost for your cloud environments. Oracle VM is an application-driven server virtualization solution fully integrated and certified with Oracle applications to deliver rapid application deployment and simplified management. With Oracle VM, you have peace of mind that the entire Oracle stack deployed is fully certified by Oracle. Register now for any of the upcoming events, and meet with Oracle experts to discuss how we can help in enabling your private cloud. Nov 20: Foundation for the Cloud: Oracle Linux and Oracle VM (Belgium) Nov 21: Oracle Linux & Oracle VM Enabling Private Cloud (Germany) Nov 28: Realize Substantial Savings and Increased Efficiency with Oracle Linux and Oracle VM (Luxembourg) Nov 29: Foundation for the Cloud: Oracle Linux and Oracle VM (Netherlands) Dec 5: MySQL Tech Tour, including Oracle Linux and Oracle VM (France) Hope to see you at one of these events!

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  • Join the Dark Side of Visual Studio 2010

    - by InfinitiesLoop
    Hard to believe it’s been so long, but it was almost 4 years ago when I published Join the Dark Side of Visual Studio . That was when a lot of people were still using VS2003, and importing and exporting environment settings required a custom add-in, VSStyler, which has since fallen off the planet and is hard to find (link, anyone? Let me know). Three versions of VS later, and I’m still using and loving the dark side. Pleased, I am (haha). In fact, that article for one reason or another is still one...(read more)

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  • Join Our Call: Sun Storage 2500-M2 Announcement

    - by user797911
    Oracle's Sun Storage 2500-M2 array brings together the latest Fibre Channel (FC) and SAS2 technologies with Oracle's Sun Storage Common Array software from Oracle to create a robust solution that’s equally adept in an entry-level storage area network (SAN) for the mid-size business and integrating into an existing storage network within the enterprise. The Sun Storage 2500-M2 replaces Sun's Storage 2500 array product line and is designed so that the customer may have a quick qualification time for fast and easy deployment in the traditional 2500 environments. Jun Jang, Oracle Principal Product Manager will be hosting this 1 hour live call (a recording will be available), please join us to find out more: Event Date: 24-JUN-11 Event Time: 08:00 am PST/PDT/4pm UK time Web Registration and Access: http://oukc.oracle.com/static09/opn/login/?t=livewebcast|c=1031672594 Access for Mobile Devices: http://my.oracle.com/content/web/cnt636926 Call Provider: Intercall International Participant Dial-In Number: 706-634-8508 Additional International Dial-In Numbers Link: http://www.intercall.com/national/oracleuniversity/gdnam.html Dial-In Passcode: 96395

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  • Join Our Call: Sun Storage 2500-M2 Announcement

    - by mseika
    Oracle's Sun Storage 2500-M2 array brings together the latest Fibre Channel (FC) and SAS2 technologies with Oracle's Sun Storage Common Array software from Oracle to create a robust solution that’s equally adept in an ! entry-level storage area network (SAN) for the mid-size business and integrating into an existing storage network within the enterprise. The Sun Storage 2500-M2 replaces Sun's Storage 2500 array product line and is designed so that the customer may have a quick qualification time for fast and easy deployment in the traditional 2500 environments. Jun Jang, Oracle Principal Product Manager will be hosting this 1 hour live call (a recording will be available), please join us to find out more:24. Jun 2011 08:00 am PST/PDT/4pm UK timeWeb Registration and AccessAccess for Mobile DevicesInternational Participant Dial-In Number: 706-634-8508Additional International Dial-In Numbers LinkDial-In Passcode: 6395

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  • mysql join with multiple values in one column

    - by CYREX
    I need to make a query that creates 3 columns that come from 2 tables which have the following relations: TABLE 1 has Column ID that relates to TABLE 2 with column ID2 In TABLE 1 there is a column called user In TABLE 2 there is a column called names There can be 1 unique user but there can be many names associated to that user. If i do the following i get all data BUT the user column repeats itself for each name it has associated. What i want is for use to appear unique but the names columns appear with all the names associated to the user column but separated by commas, like the following: select user,names from TABLE1 left join TABLE2 on TABLE1.id = TABLE2.id This will show the users repeated everytime a name appears for that user. what i want is to appear like this: USER - NAMES cyrex - pedrox, rambo, zelda homeboy - carmen, carlos, tom, sandra jerry - seinfeld, christine ninja - soloboy etc....

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  • Join Us for the Next Quarterly Customer Update Webcast

    - by michelle.huff
    Join us for the next Oracle Content Management Quarterly Customer Update Webcast scheduled for this coming June 30 / July 1 2010. Don't miss this chance to get an overview on the latest updates to Oracle Content Management. We'll be covering the latest ECM Suite 11g release - highlighting the Universal Content Management (UCM) and Universal Records Management releases. Register Today! Americas / EMEA time zones: Customer Update June 30, 2010 9:00am US PDT / 12:00pm US EDT / 16:00 GMT Length: 1 hour *Please use your corporate email address to register. Asia-Pacific time zones: Customer Update (Repeat Webcast) July 1, 2010 12:00pm Sydney AEST, 10:00am Singapore (June 30, 2010 @ 7:00pm US PDT) Length: 1 hour *Please use your corporate email address to register Please Note: If you have attended previous Quarterly Customer Update Webcasts, we are now using a new web conference system, WebEx, to host the meeting. Missed Previous Customer Quarterly Updates? Get caught up on Oracle & ECM news. View a recording or the presentation from previous Webcasts held since June 2008 (available from My Oracle Support).

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  • Join Us for the Next Quarterly Customer Update Webcast

    - by michelle.huff
    Join us for the next Oracle Content Management Quarterly Customer Update Webcast scheduled for this coming January 19 & 20, 2010. In this webcast we'll bring you up to speed on the latest updates and changes made available these past few months. Additionally, we'll cover the new features and certifications in the latest ODC & ODDC 10.1.3.5.1 release, as well as the upcoming Enterprise Content Management Suite 11gR1 PS3 (patch set 3) release. Register Today! Americas / EMEA time zones: Customer Update January 19, 2010 9:00am US PT / 12:00pm US ET / 17:00 London Length: 1 hour *Please use your corporate email address to register. Asia-Pacific time zones: Customer Update (Repeat Webcast) January 20, 2010 1:00pm Sydney AET, 10:00am Singapore (Jan 19, 2010 @ 6:00pm US PT) Length: 1 hour *Please use your corporate email address to register Missed Previous Customer Quarterly Updates? Get caught up on Oracle & ECM news. View a recording or the presentation from previous Webcasts held since June 2008 (available from My Oracle Support).

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  • Join the SPARC Go To Market Webinar on June 21st

    - by swalker
    Please join the World Wide webinar focused on SPARC, and designed to provide insights and selling guidance, at 5 p.m. CET on Thursday, June 21. The speaker, Bud Koch, Sr Principal Product Marketing Director will focus on SPARC / T4 Marketing: with a review of current assets and where we are going into FY13.  Details about the meeting can be found here. Please plan on joining 10 minutes before the scheduled start time. If you are not able to participate in real time, a replay will be available shortly afterward.

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  • Join the SPARC Go To Market Webinar on June 21st

    - by Cinzia Mascanzoni
    Please join the World Wide webinar focused on SPARC, and designed to provide insights and selling guidance, at 5 p.m. CET on Thursday, June 21. The speaker, Bud Koch, Sr Principal Product Marketing Director will focus on SPARC / T4 Marketing: with a review of current assets and where we are going into FY13.  Details about the meeting can be found here. Please plan on joining 10 minutes before the scheduled start time. If you are not able to participate in real time, a replay will be available shortly afterward.

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  • Joining Two MKV files in Ubuntu?

    - by Ryan McClure
    I have an opera that I'm ripping to my computer in MKV format with Handbrake. This opera is on two discs. Is there a way to join the resulting MKV's together? They will have the same bitrate, resolution, etc. If I do this, can I keep chapters from both MKV files organized? And, since I have subtitles in the file (not burnt in), will they still stay intact? I'm not too sure if this question is off-topic or not. If it is, feel more than free to delete it. :)

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  • Join Gretchen Alarcon In Person for an Oracle HCM Applications Strategy Updates

    - by jay.richey
    How can you benefit from staying current and moving to the latest release of your Oracle HCM applications? Where does Fusion HCM fit in and what do they mean to your existing investments? What does Oracle offer in terms of SaaS for HCM? What is Oracle doing to maintain excellence in your current applications portfolio while innovating in new and creative ways? Join us for an exclusive breakfast briefing where you will have the opportunity to hear about Oracle's current blockbuster releases for HCM: PeopleSoft 9.1 and E-Business Suite 12.1. Take this opportunity to hear about what the latest releases mean to you and learn how organizations like yours are successfully moving forward. Our featured speaker, Gretchen Alarcon, Oracle's Vice President of Fusion HCM Product Strategy will share how Oracle's latest HCM offerings - Fusion HCM and Fusion Talent Management On Demand - can work alongside your Oracle PeopleSoft, E-Business Suite, or JD Edwards HR foundation to show immediate business value. This event promises to provide you with an opportunity to share experiences, best practices, challenges, and successes with fellow business executives. Coming to: Chicago, Minneaoplis, St. Louis

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  • Join Companies in Web and Telecoms by Adopting MySQL Cluster

    - by Antoinette O'Sullivan
    Join Web and Telecom companies who have adopted MySQL Cluster to facilitate application in the following areas: Web: High volume OLTP eCommerce User profile management Session management and caching Content management On-line gaming Telecoms: Subscriber databases (HLR/HSS) Service deliver platforms VAS: VoIP, IPTV and VoD Mobile content delivery Mobile payments LTE access To come up to speed on MySQL Cluster, take the 3-day MySQL Cluster training course. Events already on the schedule include:  Location  Date  Delivery Language  Berlin, Germany  16 December 2013  German  Munich, Germany  2 December 2013  German  Budapest, Hungary  4 December 2013  Hungarian  Madrid, Spain  9 December 2013  Spanish  Jakarta Barat, Indonesia  27 January 2014  English  Singapore  20 December 2013  English  Bangkok, Thailand  28 January 2014  English  San Francisco, CA, United States  28 May 2014  English  New York, NY, United States  17 December 2013  English For more information about this course or to request an additional event, go to the MySQL Curriculum Page (http://education.oracle.com/mysql).

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  • Join us for 2 JCP sessions today + beer

    - by heathervc
    Remember to join the 2 JCP sessions at JavaOne this afternoon in the Hilton.  First up the JCP.Next panel with JCP EC Members, followed by the 101 Ways to Participate BOF.  Stop in to learn what's new and how you can make the future Java and enjoy a beer or 2.  We will also be in the OTN Java Demogrounds in the Hilton Grand Ballroom from 4:00 - 4:30 PM.  Hope to see you there. JCP.Next: Reinvigorating Java Standards Session ID: BOF6272 Location: Hilton San Francisco - Plaza A/B Date and Time: 10/1/12, 4:30 PM - 5:15 PM 101 Ways to Improve Java: Why Developer Participation Matters Session ID: BOF6283 Location: Hilton San Francisco - Continental Ballroom 4 Date and Time: 10/1/12, 5:30 PM - 6:15 PM

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  • Join the CodePlex community on Geeklist

    Community is very important to us at CodePlex. And we love partnering with other like-minded organizations. Geeklist is one of the new kids on the block, building a great place for geeks to share what they've done, who they did it with and connect with great companies and communities.     There are some exciting new experiences coming on-line soon that you won’t want to miss out on. Geeklist is currently in private beta, so if you don't already have an account, use the CodePlex invite code to create your own account. Then, join the CodePlex community and follow the CodePlex team on Geeklist. Once you’ve joined, be proud, tell the world what you have worked on, and who you did it with. And don’t be shy to give out a few high fives to the amazing work others in the community have created.

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  • Advise some swing based (open source) project to join

    - by user592704
    I am looking for some open source Swing based projects which wanted volunteer Java developers to join and the projects which show their products authors' names. I watched many links but most projects for some reason hide their authors names (showing some nick names or something...) and all developing process relative information... For example this one project it seems fine but still I couldn't find any information concerning some current project task(s), its developers group, some chronicles (tips, milestones, feedbacks etc) :( I googled a lot but found less :S So I wondering maybe you know some? I dearly hope you can give me a piece of advice Any useful comment is much appreciated

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  • Scrollbar within a scrollbar only make the inner scrollbar jump to id

    - by Nik
    I have a page that requires a scrollbar - http://www.aus-media.com/dev/site_BYJ/schedule-pricing/pricing.html You will notice (unless you are running at a high resolution with a big screen) that there is an outer scrollbar for the main page as well as an inner scrollbar for the content. When you click on one of the sub items e.g. payments you will notice that the outer page scrolls down as well as the inner scrollbar. Does anybody know of a way to only scroll the inner scrollbar, so only it jumps to the id? Thanks guys Nik

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  • Assigning a variable of a struct that contains an instance of a class to another variable

    - by xport
    In my understanding, assigning a variable of a struct to another variable of the same type will make a copy. But this rule seems broken as shown on the following figure. Could you explain why this happened? using System; namespace ReferenceInValue { class Inner { public int data; public Inner(int data) { this.data = data; } } struct Outer { public Inner inner; public Outer(int data) { this.inner = new Inner(data); } } class Program { static void Main(string[] args) { Outer p1 = new Outer(1); Outer p2 = p1; Console.WriteLine("p1:{0}, p2:{1}", p1.inner.data, p2.inner.data); p1.inner.data = 2; Console.WriteLine("p1:{0}, p2:{1}", p1.inner.data, p2.inner.data); p2.inner.data = 3; Console.WriteLine("p1:{0}, p2:{1}", p1.inner.data, p2.inner.data); Console.ReadKey(); } } }

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  • Error Instantiating an Inner Class in Parent's Constructor...

    - by stormin986
    In my application's main class (subclass of Application), I have a public inner class that simply contains 3 public string objects. In the parent class I declare an object of that inner class. public class MainApplication extends Application { public class Data { public String x; public String y; public String z; } private Data data; MainApplication() { data = new Data() data.x = "String"; } } After I instantiate the object in the constructor, I get a runtime error when I try to assign any of the inner class object's variables. Any idea what's up here??

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  • hiding inner class implementation using namespace

    - by Abruzzo Forte e Gentile
    Hi all I am developing a library and a would like to provide my users a public interface separate from the real implementatino that is hidden in a namespace. This way, I could change only the class HiddenQueue without changing myQueue that will be exposed to users only. If I put the C++ code of HiddenQueue in the myQueue.cpp file the compiler complains saying _innerQueue has incomplete type. I thought that the linker was able to resolve this. What I am doing wrong here? Thanks Afg // myQueue.h namespace inner{ class HiddenQueue; }; class myQueue{ public: myQueue(); ); private: inner::HiddenQueue _innerQueue; }; /////////////////////////// // myQueue.cpp namespace inner{ class HiddenQueue{}; };

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  • T-SQL - Left Outer Joins - Fileters in the where clause versus the on clause.

    - by Greg Potter
    I am trying to compare two tables to find rows in each table that is not in the other. Table 1 has a groupby column to create 2 sets of data within table one. groupby number ----------- ----------- 1 1 1 2 2 1 2 2 2 4 Table 2 has only one column. number ----------- 1 3 4 So Table 1 has the values 1,2,4 in group 2 and Table 2 has the values 1,3,4. I expect the following result when joining for Group 2: `Table 1 LEFT OUTER Join Table 2` T1_Groupby T1_Number T2_Number ----------- ----------- ----------- 2 2 NULL `Table 2 LEFT OUTER Join Table 1` T1_Groupby T1_Number T2_Number ----------- ----------- ----------- NULL NULL 3 The only way I can get this to work is if I put a where clause for the first join: PRINT 'Table 1 LEFT OUTER Join Table 2, with WHERE clause' select table1.groupby as [T1_Groupby], table1.number as [T1_Number], table2.number as [T2_Number] from table1 LEFT OUTER join table2 --****************************** on table1.number = table2.number --****************************** WHERE table1.groupby = 2 AND table2.number IS NULL and a filter in the ON for the second: PRINT 'Table 2 LEFT OUTER Join Table 1, with ON clause' select table1.groupby as [T1_Groupby], table1.number as [T1_Number], table2.number as [T2_Number] from table2 LEFT OUTER join table1 --****************************** on table2.number = table1.number AND table1.groupby = 2 --****************************** WHERE table1.number IS NULL Can anyone come up with a way of not using the filter in the on clause but in the where clause? The context of this is I have a staging area in a database and I want to identify new records and records that have been deleted. The groupby field is the equivalent of a batchid for an extract and I am comparing the latest extract in a temp table to a the batch from yesterday stored in a partioneds table, which also has all the previously extracted batches as well. Code to create table 1 and 2: create table table1 (number int, groupby int) create table table2 (number int) insert into table1 (number, groupby) values (1, 1) insert into table1 (number, groupby) values (2, 1) insert into table1 (number, groupby) values (1, 2) insert into table2 (number) values (1) insert into table1 (number, groupby) values (2, 2) insert into table2 (number) values (3) insert into table1 (number, groupby) values (4, 2) insert into table2 (number) values (4)

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  • SQL different joins not making any difference to result

    - by Chrissi
    I'm trying to write a quick (ha!) program to organise some of my financial information. What I ideally want is a query that will return all records with financial information in them from TableA. There should be one row for each month, but in instances where there were no transactions for a month there will be no record. I get results like this: SELECT Period,Year,TotalValue FROM TableA WHERE Year='1997' Result: Period Year TotalValue 1 1997 298.16 2 1997 435.25 4 1997 338.37 8 1997 336.07 9 1997 578.97 11 1997 361.23 By joining on a table (well a View in this instance) which just contains a field Period with values from 1 to 12, I expect to get something like this: SELECT p.Period,a.Year,a.TotalValue FROM Periods AS p LEFT JOIN TableA AS a ON p.Period = a.Period WHERE Year='1997' Result: Period Year TotalValue 1 1997 298.16 2 1997 435.25 3 NULL NULL 4 1997 338.37 5 NULL NULL 6 NULL NULL 7 NULL NULL 8 1997 336.07 9 1997 578.97 10 NULL NULL 11 1997 361.23 12 NULL NULL What I'm actually getting though is the same result no matter how I join it (except CROSS JOIN which goes nuts, but it's really not what I wanted anyway, it was just to see if different joins are even doing anything). LEFT JOIN, RIGHT JOIN, INNER JOIN all fail to provide the NULL records I am expecting. Is there something obvious that I'm doing wrong in the JOIN? Does it matter that I'm joining onto a View?

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  • Using the JPA Criteria API, can you do a fetch join that results in only one join?

    - by Shaun
    Using JPA 2.0. It seems that by default (no explicit fetch), @OneToOne(fetch = FetchType.EAGER) fields are fetched in 1 + N queries, where N is the number of results containing an Entity that defines the relationship to a distinct related entity. Using the Criteria API, I might try to avoid that as follows: CriteriaBuilder builder = entityManager.getCriteriaBuilder(); CriteriaQuery<MyEntity> query = builder.createQuery(MyEntity.class); Root<MyEntity> root = query.from(MyEntity.class); Join<MyEntity, RelatedEntity> join = root.join("relatedEntity"); root.fetch("relatedEntity"); query.select(root).where(builder.equals(join.get("id"), 3)); The above should ideally be equivalent to the following: SELECT m FROM MyEntity m JOIN FETCH myEntity.relatedEntity r WHERE r.id = 3 However, the criteria query results in the root table needlessly being joined to the related entity table twice; once for the fetch, and once for the where predicate. The resulting SQL looks something like this: SELECT myentity.id, myentity.attribute, relatedentity2.id, relatedentity2.attribute FROM my_entity myentity INNER JOIN related_entity relatedentity1 ON myentity.related_id = relatedentity1.id INNER JOIN related_entity relatedentity2 ON myentity.related_id = relatedentity2.id WHERE relatedentity1.id = 3 Alas, if I only do the fetch, then I don't have an expression to use in the where clause. Am I missing something, or is this a limitation of the Criteria API? If it's the latter, is this being remedied in JPA 2.1 or are there any vendor-specific enhancements? Otherwise, it seems better to just give up compile-time type checking (I realize my example doesn't use the metamodel) and use dynamic JPQL TypedQueries.

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  • Outer class jframe is not hiding when calling the inner class jframe

    - by user2909960
    When i am calling the inner jframe, it is called, but outer jframe is not hiding. instead it gets overlapped. so what will be the solution for this. Is there any way to get out of this. As i tried when i am calling the inner class frame, the outer class frame is also called, and it is not hidden. package com.exp.example; import java.awt.Color; import java.awt.Container; import java.awt.event.ActionEvent; import java.awt.event.ActionListener; import javax.swing.JButton; import javax.swing.JFrame; import javax.swing.JLabel; import javax.swing.JTextField; @SuppressWarnings("serial") public class A extends JFrame implements ActionListener { JFrame rframe = new JFrame(); JLabel CFirstName; JTextField Cfname; JButton jbsubmit; Container cp; public A() { rframe.setSize(500, 200); rframe.setLocationRelativeTo(null); cp = getContentPane(); cp.setLayout(null); setSize(550, 300); rframe.setTitle("Outer Frame"); cp.setBackground(new Color(140, 180, 180)); CFirstName = new JLabel("First Name"); Cfname = new JTextField(10); jbsubmit = new JButton("PREVIEW"); CFirstName.setBounds(10, 20, 100, 35); Cfname.setBounds(150, 20, 150, 25); jbsubmit.setBounds(190, 110, 92, 25); cp.add(CFirstName); cp.add(Cfname); cp.add(jbsubmit); jbsubmit.addActionListener(this); rframe.add(cp); rframe.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); rframe.setVisible(true); } public void actionPerformed(ActionEvent ae) { String action = ae.getActionCommand(); if (action == "PREVIEW") { /* Write the code here * When we click on preview button the frame of outer class(class A) gets * deactivated(closed) and inner frame, frame of inner class(class B) gets visible. * it should not be overlapped. */ /* My Code */ new B(); rframe.setVisible(false); } } public class B { JFrame frm = new JFrame(); Container cp; public B() { frm.setSize(500, 200); frm.setLocationRelativeTo(null); cp = getContentPane(); cp.setLayout(null); setSize(550, 300); frm.setTitle("Inner Frame"); cp.setBackground(new Color(140, 180, 180)); JLabel cpn = new JLabel("hello"); cpn.setBounds(10, 20, 100, 35); cp.add(cpn); frm.add(cp); frm.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); frm.setVisible(true); } } public static void main(String[] args) { new A(); } }

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