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  • Evaluation of Haskell Statements/Expressions using GHC API

    - by Cetin Sert
    For a tool I'm writing ( http://hackage.haskell.org/package/explore ) I need a way to read haskell function definitions at run-time, apply them to values from my tool and retrieve the results of their application. Can anyone give me a very basic example using GHC (6.10.4 or 6.12.1) API? example function definition to be read from a file at run-time: f x = 10**(((4/1102)*x)-1) expected program output --mapM_ print $ map f [428, 410, 389] 3.577165388142748 3.077536885227335 2.5821307011665815

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  • Extract parameter value from url using regular expressions

    - by Oscar Reyes
    This should be very simple ( when you know the answer ). From this question I want to give it a try to the posted solution. And my question is: How to get the parameter value of a given url using javascript regexp? I have: http://www.youtube.com/watch?v=Ahg6qcgoay4 I need: Ahg6qcgoay4 I tried: http://www.youtube.com/watch\\?v=(w{11}) But: I suck...

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  • Using regular expressions to remove relative path slashes

    - by Adam Carlile
    Hey Guys I am trying to remove all the relative image path slashes from a chunk of HTML that contains several other elements. For example <img src="../../../../images/upload/1/test.jpg /> would need to become <img src="http://s3.amazonaws.com/website/images/upload/1/test.jpg" /> I was thinking of writing this as a rails helper, and just passing the entire block into the method, and make using Nokogiri or Hpricot to parse the HTML instead, but I don't really know. Any help would be great Cheers Adam

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  • Using Lambda Expressions trees with IEnumerable

    - by Loathian
    I've been trying to learn more about using Lamba expression trees and so I created a simple example. Here is the code, this works in LINQPad if pasted in as a C# program. void Main() { IEnumerable<User> list = GetUsers().Where(NameContains("a")); list.Dump("Users"); } // Methods public IEnumerable<User> GetUsers() { yield return new User{Name = "andrew"}; yield return new User{Name = "rob"}; yield return new User{Name = "chris"}; yield return new User{Name = "ryan"}; } public Expression<Func<User, bool>> NameContains(string namePart) { return u => u.Name.Contains(namePart); } // Classes public class User { public string Name { get; set; } } This results in the following error: The type arguments for method 'System.Linq.Enumerable.Where(System.Collections.Generic.IEnumerable, System.Func)' cannot be inferred from the usage. Try specifying the type arguments explicitly. However if I just substitute the first line in main with this: IEnumerable<User> list = GetUsers().Where(u => u.Name.Contains("a")); It works fine. Can tell me what I'm doing wrong, please?

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  • Java Regular Expressions

    - by david robers
    Hi All, Im struggling to understand the regex documentation. How would I find the strings that contain exactly one C in the following text: ABCCAMNL YOOBABCCA XNABCCA ZDXUABCCA TAQABCC ISABCCA REABCCA CABCAMONPT Edit: private void matchIt(String regex, ArrayList<String> d) { Pattern p = Pattern.compile("[\\w^C]"); Matcher m = p.matcher(regex); for (int i = 0; i < d.size(); i++) { p.matcher(d.get(i)); if(m.find()){ out.println(d.get(i)); } } } i have the above function and it only outputs: ABCCAMNL YOOBABCCA Why is that?

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  • Greek characters, Regular Expressions, and C#

    - by craigmoliver
    I'm building a CMS for a scientific journal and that uses a lot of Greek characters. I need to validate a field to include a specific character set and Greek characters. Here's what I have now: [^a-zA-Z0-9-()/\s] How do I get this to include Greek characters in addition to alphanumeric, '(', ')', '-', and '_'? I'm using C#, by the way.

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  • VBScript Regular Expressions to check IP address validity with some adtional characters

    - by yael
    How to create VB script Irregular expression syntax to check the VPparam (IP address validity) When the last octatat of the IP address is a range between ip's (x-y) and between each IP we can put the "," separator in order to add another IP example of VBparam VBparam=172.17.202.1-20 VBparam=172.17.202.1-10,192.9.200.1-100 VBparam=172.17.202.1-10,192.9.200.1-100,180.1.1.1-20 THX yael

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  • Named Function Expressions in IE, part 2

    - by Polshgiant
    I asked this question a while back and was happy with the accepted answer. I just now realized, however, that the following technique: var testaroo = 0; (function executeOnLoad() { if (testaroo++ < 5) { setTimeout(executeOnLoad, 25); return; } alert(testaroo); // alerts "6" })(); returns the result I expect. If T.J.Crowder's answer from my first question is correct, then shouldn't this technique not work?

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  • Can't pass a single parameter to lambda function in MVVM Light Toolkit's RelayCommand

    - by Dave
    I don't know if there's a difference between Josh Smith's and Laurent Bugnion's implementations of RelayCommand or not, but everywhere I've looked, it sounds like the Execute portion of RelayCommand can take 0 or 1 parameters. I've only been able to get it to work with 0. When I try something like: public class Test { public RelayCommand MyCommand { get; set; } public Test() { MyCommand = new RelayCommand((param) => SomeFunc(param)); } private void SomeFunc( object param) { } } I get the error: Delegate 'System.Action' does not take '1' arguments. Just to make sure I am not insane, I went to the definition of RelayCommand to make sure I didn't have some rogue implementation in my solution somewhere, but sure enough, it was just Action, and not Action<. What on earth am I missing here?

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  • Regular expressions .net

    - by Tony
    I have the following function that I am using to remove the characters \04 and nulls from my xmlString but I can't find what do I need to change to avoid removing the \ from my ending tags. This is what I get when I run this function <ARR>20080625<ARR><DEP>20110606<DEP><PCIID>626783<PCIID><NOPAX>1<NOPAX><TG><TG><HASPREV>FALSE<HASPREV><HASSUCC>FALSE<HASSUCC> Can anybody help me find out what do I need to change in my expression to keep the ending tag as </tag> Private Function CleanInput(ByVal inputXML As String) As String ' Note - This will perform better if you compile the Regex and use a reference to it. ' That assumes it will still be memory-resident the next time it is invoked. ' Replace invalid characters with empty strings. Return Regex.Replace(inputXML, "[^><\w\.@-]", "") End Function

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  • Regular expressions and the question mark

    - by James P.
    I'm having trouble finding a regular expression that matches the following String. Korben;http://feeds.feedburner.com/KorbensBlog-UpgradeYourMind?format=xml;1 One problem is escaping the question mark. Java's pattern matcher doesn't seem to accept \? as a valid escape sequence but it also fails to work with the tester at myregexp.com. Here's what I have so far: ([a-zA-Z0-9])+;http://([a-zA-Z0-9./-]+);[0-9]+ Any suggestions?

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  • .NET equivalent to Perl regular expressions

    - by r_honey
    I need to convert a Perl script to VB.NET. I have managed almost the entire conversion, but some Perl (seemingly simple) regex are causing an headache. Can someone suggest me .NET equivalent of the following perl regex: 1) $letter =~ s/Users //,; $letter =~ s/Mailboxes //,; if($letter =~ m/$first_char/i){ 2) unless($storegroup =~ /Recovery/ || $storegroup =~ /Users U V W X Y Z/ || $storegroup =~ /Users S T/ || $storegroup =~ /Users Q R/){ The regex look simple to me. I tried to wade through perl.org but understanding a langugae regex takes sometime and I need to complete the conversion quickly.

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  • matching files with regular expressions

    - by Javier
    Dear all, I have an input file with a list of movies (Note that there might be some repeated entries): American_beauty__1h56mn38s_ As_Good_As_It_Gets As_Good_As_It_Gets _DivX-ITA__Casablanca_M_CURTIZ_1942_Bogart-bergman_ Capote_EN_DVDRiP_XViD-GeT-AW _DivX-ITA__Casablanca_M_CURTIZ_1942_Bogart-bergman_ I would to find the corresponding match (line number) from another reference file for each of the entries in the first file: American beauty.(1h56mn38s) As Good As It Gets Capote.EN.DVDRiP.XViD-GeT-AW [DivX-ITA] Casablanca(M.CURTIZ 1942 Bogart-bergman) Quills (2000)(7.4) The desired output would be something like (Reference Movie + Line number from the Reference File): American beauty.(1h56mn38s) 1 As Good As It Gets 2 As Good As It Gets 2 [DivX-ITA] Casablanca(M.CURTIZ 1942 Bogart-bergman) 4 Capote.EN.DVDRiP.XViD-GeT-AW 3 [DivX-ITA] Casablanca(M.CURTIZ 1942 Bogart-bergman) 4 Basically, the difference between the entries in both files is that some characters such as: blank spaces, parenthesis, points, etc. have been replaced by underscores. Does anybody could shed some light on it? Best wishes, Javier

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  • Understanding evaluation of expressions containing '++' and '->' operators in C.

    - by Leif Ericson
    Consider this example: struct { int num; } s, *ps; s.num = 0; ps = &s; ++ps->num; printf("%d", s.num); /* Prints 1 */ It prints 1. So I understand that it is because according to operators precedence, -> is higher than ++, so the value ps->num (which is 0) is firstly fetched and then the ++ operator operates on it, so it increments it to 1. struct { int num; } s, *ps; s.num = 0; ps = &s; ps++->num; printf("%d", s.num); /* Prints 0 */ In this example I get 0 and I don't understand why; the explanation of the first example should be the same for this example. But it seems that this expression is evaluated as follows: At first, the operator ++ operates, and it operates on ps, so it increments it to the next struct. Only then -> operates and it does nothing because it just fetches the num field of the next struct and does nothing with it. But it contradicts the precedence of operators, which says that -> have higher precedence than ++. Can someone explain this behavior? Edit: After reading two answers which refer to a C++ precedence tables which indicate that a prefix ++/-- operators have lower precedence than ->, I did some googling and came up with this link that states that this rule applies also to C itself. It fits exactly and fully explains this behavior, but I must add that the table in this link contradicts a table in my own copy of K&R ANSI C. So if you have suggestions as to which source is correct I would like to know. Thanks.

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  • SQL: Recursively get parent records using Common Table Expressions

    - by Martijn B
    Hi there, Suposse you have to following tables where a sale consists of products and a product can be placed in multiple categories. Whereby categories have a hierachly structure like: Man Shoes Sport Casual Watches Women Shoes Sport Casual Watches Tables: Sale: id name 1 Sale1 Product: id saleidfk name 1 1 a 2 1 b 3 1 c 4 1 d 5 1 e ProductCategory : productid categoryid 1 3 2 3 3 4 4 5 5 10 Category: id ParentCategoryIdFk name 1 null Men 2 1 Shoes 3 2 Sport 4 2 Casual 5 1 Watches 6 null Women 7 6 Shoes 8 7 Sport 9 7 Casual 10 6 Watches Question: Now on my website I want to create a control where only the categories are shown of a certain sale and where the categories are filled with the products of the sale. I also want to include the hierachly structure of the categories. So if we have a leave node, recusivly go up to the top node. So with sale1 I should have a query with the following result: Men Shoes Sport Casual Watches Women Watches This thing is driving me crazy :-) Thanks in advance! Gr Martijn

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  • Merging two Regular Expressions to Truncate Words in Strings

    - by Alix Axel
    I'm trying to come up with the following function that truncates string to whole words (if possible, otherwise it should truncate to chars): function Text_Truncate($string, $limit, $more = '...') { $string = trim(html_entity_decode($string, ENT_QUOTES, 'UTF-8')); if (strlen(utf8_decode($string)) > $limit) { $string = preg_replace('~^(.{1,' . intval($limit) . '})(?:\s.*|$)~su', '$1', $string); if (strlen(utf8_decode($string)) > $limit) { $string = preg_replace('~^(.{' . intval($limit) . '}).*~su', '$1', $string); } $string .= $more; } return trim(htmlentities($string, ENT_QUOTES, 'UTF-8', true)); } Here are some tests: // Iñtërnâtiônàlizætiøn and then the quick brown fox... (49 + 3 chars) echo dyd_Text_Truncate('Iñtërnâtiônàlizætiøn and then the quick brown fox jumped overly the lazy dog and one day the lazy dog humped the poor fox down until she died.', 50, '...'); // Iñtërnâtiônàlizætiøn_and_then_the_quick_brown_fox_... (50 + 3 chars) echo dyd_Text_Truncate('Iñtërnâtiônàlizætiøn_and_then_the_quick_brown_fox_jumped_overly_the_lazy_dog and one day the lazy dog humped the poor fox down until she died.', 50, '...'); They both work as it is, however if I drop the second preg_replace() I get the following: Iñtërnâtiônàlizætiøn_and_then_the_quick_brown_fox_jumped_overly_the_lazy_dog and one day the lazy dog humped the poor fox down until she died.... I can't use substr() because it only works on byte level and I don't have access to mb_substr() ATM, I've made several attempts to join the second regex with the first one but without success. Please help S.M.S., I've been struggling with this for almost an hour. EDIT: I'm sorry, I've been awake for 40 hours and I shamelessly missed this: $string = preg_replace('~^(.{1,' . intval($limit) . '})(?:\s.*|$)?~su', '$1', $string); Still, if someone has a more optimized regex (or one that ignores the trailing space) please share: "Iñtërnâtiônàlizætiøn and then " "Iñtërnâtiônàlizætiøn_and_then_" EDIT 2: I still can't get rid of the trailing whitespace, can someone help me out?

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  • VBScript + Regular Expressions

    - by Karthik
    Dim sString sString = "John;Mary;Anne;Adam;Bill;Ester" Is there a regex I can use to retrieve the following from the above list: John (; at the end of the name) Anne (; at the beginning and end) Ester (; at the beginning) I am currently using the following regex for each: 1. Joh.* 2. .*An.* 3. .*st.* But, the above retrieves the entire string instead of the values I want. How can I get the correct values? Code: Dim oRegex : Set oRegex = New RegExp oRegex.Global = False oRegex.IgnoreCase = False 'John oRegex.Pattern = "Joh.*" Set oMatch = oRegex.Execute(sString) sName = oMatch(0) The above code retrieves the entire string, instead of only John. Same issue with the others :(

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  • Is there a compelling reason to use quantifiers in Perl regular expressions instead of just repeatin

    - by Morinar
    I was performing a code review for a colleague and he had a regular expression that looked like this: if ($value =~ /^\d\d\d\d$/) { #do stuff } I told him he should change it to: if ($value =~ /^\d{4}$/) { #do stuff } To which he replied that he preferred the first for readability (I find the second more readable, but that's a religious debate I'll save for another day). My question: is there an actual benefit to one over the other?

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  • Regular Expressions, Checking for a range of occurrences

    - by gmcalab
    I have a phone number I want to match against a regular expression. The format of the phone number must match this: (123) 123-4567 x12345 The extension is optional. Also the extension must contain 1-5 numbers. Below is a regular expression I wrote that works. ^\(\d{3}\) \d{3}-\d{4}( x\d\d?\d?\d?\d?)?$ I was wondering if there is a better way to check for the extension instead of x\d\d?\d?\d?\d? Can I say 1-5 occurrences of \d instead of the above some how ?

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