Search Results

Search found 933 results on 38 pages for 'xslt 2 0'.

Page 19/38 | < Previous Page | 15 16 17 18 19 20 21 22 23 24 25 26  | Next Page >

  • Comparing XML in SSRS

    - by silves89
    I'm new to SSRS. We'll have two slightly different chunks of XML in a single row of an SQL Server database table. In an SSRS report we'll want to show only the differences between the XML chunks. I don't know how to do this, but I suspect the XML Type in SQLServer 2005 might be useful, or XSLT transformations in SSRS. Could anyone point me in the right direction?

    Read the article

  • .NET Efficient way to generate WORD Doc - Server Side

    - by alexbf
    Hello, .NET 4.0 I am looking for the easiest way to generate a Word document on our server. Limitations : Server side I don't want to install word on the server Data source is XML I tried to generate a DOCX with XSLT which is fast and easy but the only way I could find to validate the generated document is to open it with Word and the only error I get when the document is not valid is "Error while opening document". Not very useful. Any ideas? Thanks, Alex

    Read the article

  • XSL transformation of SVG adds namespace attribute to new tag

    - by Steve
    I have a SVG file that I want to extend by adding onclick handlers to edges and nodes. I also want to add a script tag referring to a JavaScript. The problem is that the script tag gets an empty namespace attribute added to it. I haven't found any information regarding this that I understand. Why does XSLT add an empty namespace? XSL file: <?xml version="1.0"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:svg="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink"> <xsl:output method="xml" encoding="utf-8" /> <xsl:template match="/svg:svg"> <xsl:copy> <script type="text/ecmascript" xlink:href="base.js" /> <!-- this tag gets a namespace attr --> <xsl:apply-templates /> </xsl:copy> </xsl:template> <!-- Identity transform http://www.w3.org/TR/xslt#copying --> <xsl:template match="@*|node()"> <xsl:copy> <xsl:apply-templates select="@*|node()"/> </xsl:copy> </xsl:template> <!-- Check groups and add functions --> <xsl:template match="svg:g"> <xsl:copy> <xsl:if test="@class = 'node'"> <xsl:attribute name="onclick">node_clicked()</xsl:attribute> </xsl:if> <xsl:if test="@class = 'edge'"> <xsl:attribute name="onclick">edge_clicked()</xsl:attribute> </xsl:if> <xsl:apply-templates select="@*|node()" /> </xsl:copy> </xsl:template> </xsl:stylesheet>

    Read the article

  • What is the best way to modify a few fields in an XML using Java

    - by Kailas J C
    I have a big XML which contains around 300 elements. I need to modify 2 or 3 elements in this xml using Java. I don't want to go for conventional marshalling and unmarshalling as it involves the parsing of the whole XML. How is XPath/XSLT manipulation? I know that I can easily read the data but i need to modify the same and put in back in the same XML. The primary concern here is performance. Kindly advise

    Read the article

  • How to force browsers to always reload xslt files?

    - by bitmask
    Related: Apache: How can I force the browser to reload CSS files? I'm building an xml page (on an apache2) that is supposed to be translated to xhtml by the browser, so my server also serves a main.xslt which is used as stylesheet by the xml file, similar to the scenario with the css files in the linked question. However, none of tricks provided in either that answer, nor some issues on SO solve the issue for Opera. While Firefox responds to F5 by fetching not only the xml file but also the xslt file, Opera only reloads the xml file. I tried both, setting the Last-Modified HTTP header via an .htaccess file and using the expires module of apache2. This is what my .htaccess looks right now: AddType text/xsl;charset=utf-8 .xslt ExpiresByType text/xsl "modification plus 1 second" Header set Last-Modified "Wed, 08 Jan 2000 23:11:55 GMT" #Header set Last-Modified "Wed, 08 Jan 2020 23:11:55 GMT" If I open the xsl myself and manually reload it, the xml presentation is updated as well, but this is tedious for development. Note: There is no php or any kind of scripting involved. Everything is static.

    Read the article

  • Where is empathy-log.xsl?

    - by Tom Savage
    Conversation logs saved by Empathy are in XML format. Each one links to a stylesheet "empathy-log.xsl": <?xml-stylesheet type="text/xsl" href="empathy-log.xsl"?> I've trawled my hard drive and the web but cannot find it (there is a empathy-log-manager.xsl but this is different). Does it even exist? If there is no such file I'll create my own but I'd rather use the one provided.

    Read the article

  • XSL 2.0 unparsed text and formatting

    - by Maha
    I want the unparsed text to be formatted for bold characters or increase font-size based on the tag the example here is for replace the searched word with bold characters Example: test <b> how to <b> when bold <b> when there is more <b> than one place to bold Can you please advice what is wrong here? <xsl:variable name="tcline" select="unparsed-text('generic_tc.txt','UTF-8')"/> <xsl:analyze-string select="$tcline" regex="\'<b>'(.*?)\'<b>'"> <xsl:matching-substring> <xsl:value-of select="replace($tcline,'\"<b>"(.*?)\"<b>"','<em>$1\/em/g;')"/> </xsl:matching-substring> <xsl:non-matching-substring> <xsl:value-of select="."/> </xsl:non-matching-substring> </xsl:analyze-string>

    Read the article

  • MOSS Content Query Web part itemstyle.xsl

    - by nav
    Hi, I have a Content Query Webpart (CQWP) pulling the URL and title from a NewsLinks list. The CQWP uses the XSLT style LVIS.News.Links defined in ItemStyle.xsl. I need to sort the title @Title0 field as commented out below because it causes an error. Does anyone know whats causing this error? - Many Thanks. The XSLT code is below: <xsl:template name="LVIS.News.Links" match="Row[@Style='LVIS.News.Links']" mode="itemstyle"> <xsl:param name="CurPos" /> <xsl:param name="Last" /> <xsl:variable name="SafeLinkUrl"> <xsl:call-template name="OuterTemplate.GetSafeLink"> <xsl:with-param name="UrlColumnName" select="'LinkUrl'"/> </xsl:call-template> </xsl:variable> <xsl:variable name="DisplayTitle"> <xsl:call-template name="OuterTemplate.GetTitle"> <xsl:with-param name="Title" select="@URL"/> <xsl:with-param name="UrlColumnName" select="'URL'"/> </xsl:call-template> </xsl:variable> <xsl:variable name="LinkTarget"> <xsl:if test="@OpenInNewWindow = 'True'" >_blank</xsl:if> </xsl:variable> <xsl:variable name="SafeImageUrl"> <xsl:call-template name="OuterTemplate.GetSafeStaticUrl"> <xsl:with-param name="UrlColumnName" select="'ImageUrl'"/> </xsl:call-template> </xsl:variable> <xsl:variable name="Header"> <xsl:if test="$CurPos = 1"> <![CDATA[<ul class="list_Links">]]> </xsl:if> </xsl:variable> <xsl:variable name="Footer"> <xsl:if test="$Last = $CurPos"> <![CDATA[</ul>]]> </xsl:if> </xsl:variable> <xsl:value-of select="$Header" disable-output-escaping="yes" /> <li> <a> <xsl:attribute name="href"> <xsl:value-of select="substring-before($DisplayTitle,', ')"></xsl:value-of> </xsl:attribute> <xsl:attribute name="title"> <xsl:value-of select="@Description"/> </xsl:attribute> <!-- <xsl:sort select="@Title0"/> --> <xsl:value-of select="@Title0"> </xsl:value-of> </a> </li> <xsl:value-of select="$Footer" disable-output-escaping="yes" /> </xsl:template>

    Read the article

  • Set attribute to all child elements via xsl:choose

    - by Camal
    Hi, assuming I got following XML file : <?xml version="1.0" encoding="ISO-8859-1" ?> <MyCarShop> <Car gender="Boy"> <Door>Lamborghini</Door> <Key>Skull</Key> </Car> <Car gender="Girl"> <Door>Normal</Door> <Key>Princess</Key> </Car> </MyCarShop> I want to perform a transformation so the xml looks like this : <?xml version="1.0" encoding="ISO-8859-1" ?> <MyCarShop> <Car gender="Boy"> <Door color="blue">Lamborghini</Door> <Key color="blue">Skull</Key> </Car> <Car gender="Girl"> <Door color="red">Normal</Door> <Key color="red">Princess</Key> </Car> </MyCarShop> So I want to add a color attribut to each subelement of Car depending on the gender information. I came up with this XSLT but it doesnt work : <?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl" > <xsl:output method="xml" indent="yes"/> <!--<xsl:template match="@* | node()"> <xsl:copy> <xsl:apply-templates select="@* | node()"/> </xsl:copy> </xsl:template>--> <xsl:template match="/"> <xsl:element name="MyCarShop"> <xsl:attribute name="version">1.0</xsl:attribute> <xsl:apply-templates/> </xsl:element> </xsl:template> <xsl:template match="Car"> <xsl:element name="Car"> <xsl:apply-templates/> </xsl:element> </xsl:template> <xsl:template match="Door"> <xsl:element name="Door"> <xsl:attribute name="ViewSideIndicator"> <xsl:choose> <xsl:when test="gender = 'Boy' ">Front</xsl:when> <xsl:when test="gender = 'Girl ">Front</xsl:when> </xsl:choose> </xsl:attribute> </xsl:element> </xsl:template> <xsl:template match="Key"> <xsl:element name="Key"> <xsl:apply-templates/> </xsl:element> </xsl:template> </xsl:stylesheet> Does anybody know what might be wrong ? Thanks again!

    Read the article

  • XSLT1.0: remove duplicates combined with an xsl:key

    - by Jannibal
    I have the following piece of XML: <research> <research.record> <research.record_number>1</research.record_number> <research.type> <value lang="en-US">some research type</value> </research.type> <research.type> <value lang="en-US">some other type of research</value> </research.type> <project.record> <priref>101</priref> <project.type> <value lang="en-US">some type of project</value> </project.type> </project.record> </research.record> </research> <research> <research.record> <research.record_number>2</research.record_number> <research.type> <value lang="en-US">some other type of research</value> </research.type> <research.type> <value lang="en-US">a third type of research</value> </research.type> <project.record> <priref>101</priref> <project.type> <value lang="en-US">some type of project</value> </project.type> </project.record> </research.record> </research> <research> <research.record> <research.record_number>3</research.record_number> <research.type> <value lang="en-US">some other type of research</value> </research.type> <research.type> <value lang="en-US">a fourth type</value> </research.type> <project.record> <priref>201</priref> <project.type> <value lang="en-US">some other type of project</value> </project.type> </project.record> </research.record> </research> <research> ... etc ... With XSLT 1.0 I transform this XML into a list of unique project records by using xsl:key. So far, so good... The problem is: I also want to show unique research types for each unique project record. My wanted output would be: project.record 101: some research type, some other type of research, a third type of research project.record 201: some other type of research, a fourth type Hope someone can help me out with the right XSLT/XPATH. (Can only use XSLT1.0)

    Read the article

  • XML Parsing from Non-XML Document

    - by Neel Basu
    in a xml/non-xml File there may exist some XML Block that I need to parse and replace with some other string.. The Scenario is something like this.. Some Text <cnt:use name="abc" call="xyz"> <cnt:param name="x" value="2" /> </cnt:use> Some Text There is no guarantee that the document is a proper XML document. (there may exist some unclosed Tags. or some other common mistakes that a Stupid people can make while typing HTML). so I can't use SAX or DOM. I can't even pass it to XSLT (am I right ?). So Whats the best way to extract the <cnt:*> part from the non-xml Document. and read it then replace with something else.

    Read the article

  • Riddle with "href".

    - by kalininew
    Mysticism. I use XSLT for reception of the address for the reference. <a href="{element/url}"/> In XML i have: <element> <url>www.mysite.ru</url> </element> As a result on page I receive: <a href="www.currentsite.ru/cursection/cursubsection/www.mysite.ru"/> That is: in the beginning there is an address of a current site (the address of current section where we now are), and then there is a reference to an external site. There can be it any problem with metatag BASE? In what a trouble?

    Read the article

  • XslCompiledTransform eats my DOCTYPE!

    - by pukipuki
    Made a xslt template with output instruction for <DOCTYPE> <xsl:output media-type="text/html" method="html" encoding="windows-1251" doctype-public="-//W3C//DTD XHTML 1.1//EN" doctype-system="http://www.w3.org/TR/xhtml11/DTD/xhtml11.dtd" omit-xml-declaration="yes"/> In xsl-debug I'm receiving right <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.1//EN" "http://www.w3.org/TR/xhtml11/DTD/xhtml11.dtd"> on top of the html. But when I'm using XslCompiledTransform etc.. output starts from <html xmlns="http://www.w3.org/1999/xhtml">. So, Doctype is missed. Why? Right properties of XslCompiledTransform initialized just like I set in . How can I get DOCTYPE from XslCompiledTransform?

    Read the article

  • xsl - multiple xsl:if with the same condition

    - by mickthomposn
    Newbie question on xslt. I've multiple xsl:if checks like <xsl:if test="node/node1"> ...</xsl:if> ... <xsl:if test="node/node1"> ...</xsl:if> ... <xsl:if test="node/node1"> ... </xsl:if> Is there a way to parameterize the test condition to make the code more readable and easy to maintain? Maybe with a variable or something like <xsl:variable name="node1Present" select="true()"/> <xsl:if test="$node1Present"> ... </xsl:if> I don't understand how to construct the variable to reflect the 'test a node exist' (test="node/node1")

    Read the article

  • How to select saxon TransformerFactory in Java

    - by pAkY88
    In my web application I need to use Saxon TransformerFactory to use XSLT 2.0 but I can't use setProperty method because I haven't this right on the web server and there is a Security Manager. So i have read that it's possible to do this: Use the Services API (as detailed in the JAR specification), if available, to determine the classname. The Services API will look for a classname in the file META-INF/services/javax.xml.transform.TransformerFactory in jars available to the runtime. I found this file in WEB-INF/lib/saxon9.jar but when I istantiate a TransformerFactory is always selected default factory and not saxon factory. How can I select Saxon Transformer Factory? Thanks

    Read the article

  • Read line comments in INI file

    - by Dave Jarvis
    The parse_ini_file function removes comments in configuration files. What would you do to keep the comments that are associated with the next line? For example: [email] ; Verify that the email's domain has a mail exchange (MX) record. validate_domain = true Am thinking of using X(HT)ML and XSLT to transform the content into an INI file (so that the documentation and options can be single sourced). For example: <h1>email</h1> <p>Verify that the email's domain has a mail exchange (MX) record.</p> <dl> <dt>validate_domain</dt> <dd>true</dd> </dl> Any other ideas?

    Read the article

  • xsl with javascript

    - by Vignesh
    I've a file with xml data. And I want to generate a report out of it. I tried to integrate xsl with java script, but can I get a handle of individual data elements in xsl and pass it on to a java script function. Lets say <value>true</value> is in the xml and I want to pass it on to a javascript function while doing something like this in xsl. <xsl:for-each select="/valgroup"> <xsl:value-of select="value"/> </xsl:for-each> The alternative is to parse the xml in java script and get the values, I've got little idea of how to integrate it with xsl. Are there any java script libraries. I've seen my libraries that run on servers(AJAXSLT), but I need something that runs locally. I'm a new to xslt, so consider this a worthy question.

    Read the article

  • Retrieving XML node from a path specified in an attribute value of another node

    - by Olivier PAYEN
    From this XML source : <?xml version="1.0" encoding="utf-8" ?> <ROOT> <STRUCT> <COL order="1" nodeName="FOO/BAR" colName="Foo Bar" /> <COL order="2" nodeName="FIZZ" colName="Fizz" /> </STRUCT> <DATASET> <DATA> <FIZZ>testFizz</FIZZ> <FOO> <BAR>testBar</BAR> <LIB>testLib</LIB> </FOO> </DATA> <DATA> <FIZZ>testFizz2</FIZZ> <FOO> <BAR>testBar2</BAR> <LIB>testLib2</LIB> </FOO> </DATA> </DATASET> </ROOT> I want to generate this HTML : <html> <head> <title>Test</title> </head> <body> <table border="1"> <tr> <td>Foo Bar</td> <td>Fizz</td> </tr> <tr> <td>testBar</td> <td>testFizz</td> </tr> <tr> <td>testBar2</td> <td>testFizz2</td> </tr> </table> </body> </html> Here is the XSLT I currently have : <?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl"> <xsl:output method="html" indent="yes"/> <xsl:template match="/ROOT"> <html> <head> <title>Test</title> </head> <body> <table border="1"> <tr> <!--Generate the table header--> <xsl:apply-templates select="STRUCT/COL"> <xsl:sort data-type="number" select="@order"/> </xsl:apply-templates> </tr> <xsl:apply-templates select="DATASET/DATA" /> </table> </body> </html> </xsl:template> <xsl:template match="COL"> <!--Template for generating the table header--> <td> <xsl:value-of select="@colName"/> </td> </xsl:template> <xsl:template match="DATA"> <xsl:variable name="pos" select="position()" /> <tr> <xsl:for-each select="/ROOT/STRUCT/COL"> <xsl:sort data-type="number" select="@order"/> <xsl:variable name="elementName" select="@nodeName" /> <td> <xsl:value-of select="/ROOT/DATASET/DATA[$pos]/*[name() = $elementName]" /> </td> </xsl:for-each> </tr> </xsl:template> </xsl:stylesheet> It almost works, the problem I have is to retrieve the correct DATA node from the path specified in the "nodeName" attribute value of the STRUCT block.

    Read the article

  • Using XSL-FO and HTML?

    - by buggy1985
    Hi, I'm trying to transform some XML-data to HTML with XSLT for my bachelor thesis. My professor wants me to consider XSL-FO too, or at least to write some word about it. But I'm very noob to this. So my questions are: Can I combine FO with HTML? Can I use FO istead of HTML and CSS? If yes, how will my browser render this? Are there any examples/tutorials on how to transform xml into web pages with FO? Thank you very much.

    Read the article

  • Replace underscore between words (reg.exp)

    - by lasseespeholt
    Hey, I need a regular expression to solve the following problem (links to similar problems is also appreciated, related tutorials etc.): __some_words_a_b___ => __some words a b___ ____ => ____ So I want underscores between words to be replaced with space and keep leading and trailing underscores. I found this: ^[ \t]+|[ \t]+$ and I guess it most be something like that. I will use it in jQuery, Java (stdlibs) and maybe XSLT. Addition: The sentences do not necessarily start with underscores or ends with underscores. It is also possible that a sentence ain't containing underscores at all. Best regards Lasse Espeholt

    Read the article

  • More XML Problems - Undeclared Entity 'nbsp'

    - by Gogster
    I'm getting the error: Line 49: xml = r.ReadToEnd(); Line 50: Line 51: System.Xml.Linq.XDocument xmlDoc = System.Xml.Linq.XDocument.Parse(xml); Line 52: Line 53: var query = from p in xmlDoc.Descendants("member") On my XML. When I run the code to generate the XML in an empty page, it runs without error, if I call the code within my webpage it throws this error. The only 'nbsp' on the page is a doctype declaration at the top of the XSLT: <!DOCTYPE xsl:stylesheet [ <!ENTITY nbsp "&#x00A0;"> ]> I'm at a loss as to where this error is coming from and I am looking for suggestions please! Thanks.

    Read the article

  • Generating report from an xml file

    - by Vignesh
    I want to generate a report from an xml, preferably html. The html here should be dynamic to allow limiting the view based on some user entered values, preferably selecting from a drop down of categories, which inturn is populated from the xml. I also want to have links in the report to more info which is stored in another xml file. I started off with javascript with xslt for display and I'm still long way in acheiving my desires. Are there any other ways to do it?? Any automated Open sources tools, for this, rather than reinventing.

    Read the article

  • use multiple xsl files with one xml document

    - by paracaudex
    I have a single xml document (data.xml), which I display as HTML using an XSLT document (transform.xsl) with the following line in data.xml. <?xml-stylesheet type="text/xsl" href="transform.xsl"?> Suppose, however, I want to display this information in two different ways, one at http://www.domain.com/data.xml and one at http://www.domain.com/data2.xml. Both of these displays will use the same xml document but with different xsl's. Is there a way to do this without duplicating the xml file?

    Read the article

  • How to put tags inside an html attribute?

    - by Mycol
    Using xslt i want to create an attribute: <span class="tooltip"> <xsl:attribute name="onmouseover"> <xsl:text>javascript:function(</xsl:text> <span class="label">Aggiunta</span> <xsl:apply-tempaltes/> <xsl:text>)</xsl:text> </xsl:attribute> The problem is that only the pure text is putted inside the attribute, like <span class="tooltip" onmouseover="javascript:function(Aggiunta ...)"> whithout the span tags or the tags that may come from apply-templates. So how can I put html code into an attribute?

    Read the article

  • Get variable value from XML to JavaScript. Pure way.

    - by kalininew
    I have XML: <point> ... <longitude>34.123123</longitude> </point> <point> ... <longitude>11.12534534</longitude> </point> <point> ... <longitude>32.567653</longitude> </point> <point> ... <longitude>33.345345</longitude> </point> ... Task: get values of <longitude> in javascript (in variable). Which is purest way? It is possible to do it without XSLT (without making dummy elements)?

    Read the article

< Previous Page | 15 16 17 18 19 20 21 22 23 24 25 26  | Next Page >