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  • Echoing a pseudo column value after a COUNT

    - by rob - not a robber
    Hi Gang... Please don't beat me if this is elementary. I searched and found disjointed stuff relating to pseudo columns. Nothing spot on about what I need. Anyway... I have a table with some rows. Each record has a unique ID, an ID that relates to another entity and finally a comment that relates to that last entity. So, I want to COUNT these rows to basically find what entity has the most comments. Instead of me explaining the query, I'll print it SELECT entity_id, COUNT(*) AS amount FROM comments GROUP BY entity_id ORDER BY amount DESC The query does just what I want, but I want to echo the values from that pseudo column, 'amount' Can it be done, or should I use another method like mysql_num_rows? Thank you!!!

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  • Populate FILE field with default text

    - by dclowd9901
    I'm trying to reutilize code that generates FILE fields for use when something is to be added to the database, and grayed out (and disabled) with data already in the database when the item in question is being edited or viewed in detail. However, I can't seem to get the text to fill the field. I'm using this: echo '<input type="file" name="small[]" value="' . $value_from_database . '" DISABLED><br>'; Am I missing anything? If not, are there any decent workarounds?

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  • How can I set the main theme-font dynamically, in WordPress

    - by windyjonas
    I have created a theme where I already have a custom options page where I let the user set text for footer, twitter user and some other things and that works well. Now i'd like to add the functionality of letting the user select which font that should be used for content on the site. How can i accomplish this? I can probably create a php file that outputs something like: <style type="text/css"> body{ font-family: <?php echo get_option('my-font');?>; } </style> and include that file in header.php, but that means that I have to hit php for every request for this css and I want to avoid that if posssible.

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  • Display Wordpress parent Category with their child category

    - by saorabh
    Hi, I want to display only those the parent category which have some child category with their child category without using child_of= I was trying to display but i am only able to get the list of child category not their parent category name. <?php $querystr = "SELECT wp_terms.name, wp_terms.term_id, wp_terms.name FROM wp_terms, wp_term_taxonomy WHERE wp_terms.term_id = wp_term_taxonomy.term_id AND wp_term_taxonomy.parent !=0 "; $cat_child = $wpdb->get_results($querystr, OBJECT); var_dump($cat_child); foreach ($cat_child as $category) { echo $category->name. ' , '; } ?> Help me.. Thanks

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  • php with two class

    - by lolalola
    Hi Guys, my sample is good or not? I have a good connection to the database, or too should be in the class? Thanks <?php mysql_connect('localhost','root','admin'); mysql_select_db('test'); class UserDisplay { function getDisplayName() { $sql = 'select first_name, last_name, display_name from users where user_id = "3"'; $results = mysql_query($sql); $row = mysql_fetch_array($results); $this->user_id = $user_id; return $this->user_id; } } class UserInsert function InsertName($name) { mysql_query("INSERT INTO Persons (first_name)VALUES ('".$name."')"); } } $userD = new UserDisplay(); echo "User known as: " . $userD->getDisplayName() . "\n"; $userI = new UserInsert(); $userI->InsertName("Peter"); ?>

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  • PHP and Apache environment variables

    - by Simon
    Hello, I want to pass an environment variable in linux to apache on start up. export MYVAR=5 --I define my environment variable on the command line PassEnv MYVAR --set apache to import the variable in apache config file apachectl restart --when I restart apache I don't get an error message. However I have noticed that if I do not create the environment variable in my first step, I get a warning message, so must be working here echo $_SERVER['MYVAR'] --i try to access the environment variable within PHP but it is not defined I've observed that if I try to PassEnv an environment variable that already exits (one that I havn't created myself) it works fine. The SetEnv directive also works fine. I'd really like to pass an environment variable to apache on the fly without writing it in a file. Help much appreciated. I'm using CentOS, PHP5 and Apache2. Thanks.

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  • Mysql Date formats and url query

    - by jasmine
    I want to make a url query with date. I have confused a little : There is a mysql table: calDate : varchar The query : $sql="select * from calTbl"; $result = mysql_query($sql); while ($row = mysql_fetch_array($result)) { $n = str_replace("/", "",$row['calDate']); echo '<a href="index.php?p='.$n.'">'.$n.'</a>'; } I want to see related event from query. Can I set apart month, day and year from this? Or what is the correct table design here? Thanks in advance

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  • php domDocument variables

    - by geoffs3310
    Hi, I have the following code at the moment: $ip = '195.72.186.157'; $xmlDoc = new DOMDocument(); $xmlDoc->loadXML(file_get_contents('http://www.geoffmeierhans.com/services/geo-locator/locate/?ip='.$ip.'&output=xml')); foreach($xmlDoc->getElementsByTagName('city') as $link) { $links = array('text' => $link->nodeValue); } $city = $links['text']; echo $city; Is there a better way to get the city variable? Since there is only one tag called city a loop isn't really needed but I can't get it to work any other way

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  • why won't my ajax work asynchronously

    - by payling
    I'm having trouble understanding why my code will not work asynchronously. When running asynchronously the get_price.php always receives the same $_GET value even though the alert before outputs a unique $_GET value. var arraySize = "<? echo count($_SESSION['items']); ?>"; //get items count var pos = 0; var pid; var qty; getPriceAjax(); function getPriceAjax() { pid = document.cartItemForm.elements[pos].id; //product id qty = document.cartItemForm.elements[pos].value; //quantity alert('Product: ' + pid + ' Quantity: ' + qty); $.ajax({ url:"includes/ajax_php/get_price.php", type:"GET", data:'pid='+pid+'&qty='+qty, async:true, cache:false, success:function(data){ while(pos < arraySize) { document.getElementById(pid + 'result').innerHTML=data; pos++; getPriceAjax(); } } }) }

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  • jQuery works in FF but not in Safari

    - by Hristo
    I have some event handlers that work in FF and not in Safari. Simply put, I have a list of friends, some hard-coded, some pulled in from a database. Clicking on a buddy opens a chat window... this is much like the Facebook chat system. So in Firefox, everything works normally and as expected. In Safari, clicking on buddies that are hard-coded works fine, but clicking on buddies that are pulled in from the database doesn't pull up the chat window. <script type="text/javascript" src="js/jQuery.js"></script> <script type="text/javascript" src="js/chat.js"></script> <script type="text/javascript" src="js/ChatBar.js"></script> <script type="text/javascript" src="js/settings.js"></script> <script type="text/javascript"> var chat = new Chat(); var from = <?php echo "'" .$_SESSION['userid'] . "'"; ?>; chat.getUsers(<?php echo "'" .$_SESSION['userid'] . "'"; ?>); </script> So I load all my buddies with chat.getUsers. That function is: // get list of friends function getBuddyList(userName) { userNameID = userName; $.ajax({ type: "GET", url: "buddyList.php", data: { 'userName': userName, 'current': numOfUsers }, dataType: "json", cache: false, success: function(data) { if (numOfUsers != data.numOfUsers) { numOfUsers = data.numOfUsers; var list = "<li><span>Agents</span></li>"; for (var i = 0; i < data.friendlist.length; i++) { list += "<li><a class=\"buddy\" href=\"#\"><img alt=\"\" src=\"images/chat-thumb.gif\">"+ data.friendlist[i] +"</a></li>"; } $('#friend-list ul').append($(list)); } setTimeout('getBuddyList(userNameID)', 1000); } }); } buddyList.php just pulls in the Users from the database and returns an array with the user names. So the jQuery for clicking a buddy is: // click on buddy in #friends-panel $('#friends-panel a.buddy').click(function() { alert("Loaded"); // close #friends-panel $('.subpanel').hide(); $('#friends-panel a.chat').removeClass('active'); // if a chat window is already active, close it and deactivate $('#mainpanel li[class="active-buddy-tab"] div').not('#chat-box').removeAttr('id'); $('#mainpanel li[class="active-buddy-tab"]').removeClass('active-buddy-tab').addClass('buddy-tab'); // create active buddy chat window $('#mainpanel').append('<li class="active-buddy-tab"><a class="buddy-tab" href="#"></a><div id="chat-window"><h3><p id="to"></p></h3></div></li>'); // create name and close/minimize buttons $('.active-buddy-tab div h3 p#to').text($(this).text()); $('.active-buddy-tab div h3').append('<span class="close"> X </span><span class="minimize"> &ndash; </span>'); $('.active-buddy-tab').append('<span class="close"> X </span>'); // create chat area $('.active-buddy-tab div').append('<div id="chat-box"></div><form id="chat-message"><textarea id="message" maxlength="100"></textarea></form>'); // put curser in chat window $('.active-buddy-tab #message').focus(); // create a chat relationship return false; }); ... and the basic structure of the HTML is: <div id="footpanel"> <ul id="mainpanel"> <li id="friends-panel"> <a href="#" class="chat">Friends (<strong>18</strong>) </a> <div id="friend-list" class="subpanel"> <h3><span> &ndash; </span>Friends Online</h3> <ul> <li><span>Family Members</span></li> <!-- Hard coded buddies --> <li><a href="#" class="buddy"><img src="images/chat-thumb.gif" alt="" /> Your Friend 1</a></li> <li><a href="#" class="buddy"><img src="images/chat-thumb.gif" alt="" /> Your Friend </a></li> <!-- buddies will be added in dynamically here --> </ul> </div> </li> </ul> </div> I'm not too sure where to begin solving this issue. I thought it might be a rendering bug or something with the DOM but I've been staring at this code all day and I'm stuck. Any ideas on why it works in FF and not in Safari? btw... I'm testing on Snow Leopard. Thanks, Hristo

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  • How to redirect to the current page with form in php?

    - by garcon1986
    Hello, I tried to redirect to the current page with form in my php application. Now i have met a problem. <form name="myform" action="?page=matching" method="GET"> <input id="match_button" type="submit" name="button" value="button" onClick="func_load3()" /> </form> action="?page=matching" means the current page, because i use the single entry in my php application. With the code upon, When i click the button, it redirects to the homepage. And I tried to use: <form name="myform" action="<?php echo $_SERVER['PHP_SELF']; ?>" method="GET"> but it still doesn't work. So i have to ask for help from you. Do you have any ideas about that? How to fix it? Thanks in advance.

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  • passing parameters to javacsript using php

    - by ayush
    i have the following line of code - <a href="javascript:;" onClick="tweeet('myid')">My Tweets!</a> Now while this is working perfectly fine the following line is not - <a href="javascript:;" onClick="tweeet(<?php echo 'myid'; ?>)">My Tweets!</a> Can anyone help me out why it is not working and suggest any changes. The variable i want to pass to the javascript function is a php variable. also i have tried the php with single quotes and double quotes but it is not working.

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  • textbox disappears in paging - php

    - by fusion
    i'm calling the search.php page via ajax to search.html. the problem is, since i've implemented paging, the textbox with the search keyword from search.html 'disappears' when the user clicks the 'Next' button [because the page goes to search.php which has no textbox element] i'd like the textbox with the search keyword to be there, when the user goes through the records via paging. how'd i achieve this? search.html: <body> <form name="myform" class="wrapper"> <input type="text" name="q" onkeyup="showPage();" class="txt_search"/> <input type="button" name="button" onclick="showPage();" class="button"/> <p> <div id="txtHint"></div> <div id="page"></div> </form> </body> search.php [the relevant part]: $self = $_SERVER['PHP_SELF']; $limit = 5; //Number of results per page $numpages=ceil($totalrows/$limit); $query = $query." ORDER BY idQuotes LIMIT " . ($page-1)*$limit . ",$limit"; $result = mysql_query($query, $conn) or die('Error:' .mysql_error()); ?> <div class="caption">Search Results</div> <div class="center_div"> <table> <?php while ($row= mysql_fetch_array($result, MYSQL_ASSOC)) { $cQuote = highlightWords(htmlspecialchars($row['cQuotes']), $search_result); ?> <tr> <td style="text-align:right; font-size:15px;"><?php h($row['cArabic']); ?></td> <td style="font-size:16px;"><?php echo $cQuote; ?></td> <td style="font-size:12px;"><?php h($row['vAuthor']); ?></td> <td style="font-size:12px; font-style:italic; text-align:right;"><?php h($row['vReference']); ?></td> </tr> <?php } ?> </table> </div> <?php //Create and print the Navigation bar $nav=""; if($page > 1) { $nav .= "<a href=\"$self?page=" . ($page-1) . "&q=" .urlencode($search_result) . "\">< Prev</a>"; $first = "<a href=\"$self?page=1&q=" .urlencode($search_result) . "\"><< First</a>" ; } else { $nav .= "&nbsp;"; $first = "&nbsp;"; } for($i = 1 ; $i <= $numpages ; $i++) { if($i == $page) { $nav .= "<B>$i</B>"; }else{ $nav .= "<a href=\"$self?page=" . $i . "&q=" .urlencode($search_result) . "\">$i</a>"; } } if($page < $numpages) { $nav .= "<a href=\"$self?page=" . ($page+1) . "&q=" .urlencode($search_result) . "\">Next ></a>"; $last = "<a href=\"$self?page=$numpages&q=" .urlencode($search_result) . "\">Last >></a> "; } else { $nav .= "&nbsp;"; $last = "&nbsp;"; } echo "<br /><br />" . $first . $nav . $last; }

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  • Kohana controller shows blank page if missing URI segment/argument

    - by Petruza
    When accessing http://www.nowplayingnashville.com/event2/detail/440698386/Whatever the controller shows normally. But when omitting the last parameter (event's title, which can be any string), http://www.nowplayingnashville.com/event2/detail/440698386/ It shows blank. I added a default value and tried to hardcode the title on the first line of the controller, but it doesn't work anyway. It looks like a view issue, because I can add an echo at the end of the controller and it gets printed, so the controller is executing to the end, but the views aren't displayed. This problem is present on the live site, but I checked out the code on my local machine and it works perfectly without a title. That's strange. Could it be a Kohana or Apache configuration issue?

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  • How to begin writing an Application Server over Apache?

    - by Cracker
    For my college project, I want to create a simple application server in C that runs over Apache. Like .php, .asp, .jsp, the extension of my files would be .sas. I have already written a parser which reads the .sas files and generates the output. For example, consider a file index.sas with the below code: <% echo "Hello"; %> Now, if I execute: sas index.sas The result would be: Hello Now I want to use this program as an application server over Apache just as PHP, Tomcat, etc. work over Apache. I have heard of cgi-bin but I think PHP uses a different approach. I want to learn the approach which PHP uses. Please advice.

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  • How to build unlimited level of menu through PHP and mysql

    - by Starx
    Well, to build my menu my menu I use a db similar structure like this To assign another submenu for existing submenu I simply assign its parent's id as its value of parent field. parent 0 means top menu now there is not problem while creating submenu inside another submenu now this is way I fetch the submenu for the top menu <ul class="topmenu"> <? $list = $obj -> childmenu($parentid); //this list contains the array of submenu under $parendid foreach($list as $menu) { extract($menu); echo '<li><a href="#">'.$name.'</a></li>'; } ?> </ul> What I want to do is. I want to check if a new menu has other child menu and I want to keep on checking until it searches every child menu that is available and I want to display its child menu inside its particular list item like this Home ........

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  • pagination in css/php

    - by fusion
    two questions: --1-- it displays all the number of pages. but i'd like it to display as: << Prev . . 3 4 [5] 6 7 . . Next --2-- when i hover on the current page no, it should change color or increase the font-size, but when i modify the css of a:hover, all the page nos change color or size instead of the one which i'm pointing to. also, when modifying a:active, nothing happens. this is my paging code in php: $self = $_SERVER['PHP_SELF']; $limit = 2; //Number of results per page $numpages=ceil($totalrows/$limit); $query = $query." ORDER BY idQuotes LIMIT " . ($page-1)*$limit . ",$limit"; $result = mysql_query($query, $conn) or die('Error:' .mysql_error()); ?> <div class="caption">Search Results</div> <div class="center_div"> <table> <?php while ($row= mysql_fetch_array($result, MYSQL_ASSOC)) { $cQuote = highlightWords(htmlspecialchars($row['cQuotes']), $search_result); ?> <tr> <td style="text-align:right; font-size:15px;"><?php h($row['cArabic']); ?></td> <td style="font-size:16px;"><?php echo $cQuote; ?></td> <td style="font-size:12px;"><?php h($row['vAuthor']); ?></td> <td style="font-size:12px; font-style:italic; text-align:right;"><?php h($row['vReference']); ?></td> </tr> <?php } ?> </table> </div> <div class="searchmain"> <?php //Create and print the Navigation bar $nav=""; $next = $page+1; $prev = $page-1; if($page > 1) { $nav .= "<span class=\"searchpage\"><a onclick=\"showPage('','$prev'); return false;\" href=\"$self?page=" . $prev . "&q=" .urlencode($search_result) . "\">< Prev</a></span>"; $first = "<span class=\"searchpage\"><a onclick=\"showPage('','1'); return false;\" href=\"$self?page=1&q=" .urlencode($search_result) . "\"> << </a></span>" ; } else { $nav .= "&nbsp;"; $first = "&nbsp;"; } for($i = 1 ; $i <= $numpages ; $i++) { if($i == $page) { $nav .= "<span class=\"searchpage\">$i</span>"; }else{ $nav .= "<span class=\"searchpage\"><a onclick=\"showPage('',$i); return false;\" href=\"$self?page=" . $i . "&q=" .urlencode($search_result) . "\">$i</a></span>"; } } if($page < $numpages) { $nav .= "<span class=\"searchpage\"><a onclick=\"showPage('','$next'); return false;\" href=\"$self?page=" . $next . "&q=" .urlencode($search_result) . "\">Next ></a></span>"; $last = "<span class=\"searchpage\"><a onclick=\"showPage('','$numpages'); return false;\" href=\"$self?page=$numpages&q=" .urlencode($search_result) . "\"> >> </a></span>"; } else { $nav .= "&nbsp;"; $last = "&nbsp;"; } echo $first . $nav . $last; ?> </div> and this is how it displays currently: css: .searchmain { margin:30px; text-align: center; } .searchpage { border: solid 1px #ddd; background: #fff; text-align:left; font-size: 16px; padding:9px 12px; color: #FEBE33; margin-left:2px; } .searchpage a{ text-decoration: none; color: #808080; } .searchpage a:hover { color: #FEBE33; border-color: #036; text-decoration: none; } .searchpage a:visited { color: #808080; }

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  • modx revo snippet variable in query

    - by Meddie
    I noticed something weird when using a query in a snippet. When I have a query like this: $sql = 'SELECT * FROM table WHERE colomn = ' . $variable; And I echo $sql, the query reads: SELECT * FROM table WHERE colomn = <code class="php plain">2</code> .. wich will result in an error because the sql is no longer valid. So for now I use strip_tags to remove the code tag, but I find it not a very clean method. I couldnt find anything about this, so maybe someone can shed some light on this for me?

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  • pass php array to jquery with getJSON

    - by robertdd
    i want to pass a php aray to jQuery: $.getimagesarr = function() { $.getJSON('operations.php', {'operation':'getimglist'}, function(data){ var arr = new Array(); arr = data; return arr; }); } var data = $.getimagesarr(); if (data){ jQuery.each(data, function(i, val) { .... }); } it return undefined in php i have this: function getimglist(){ $results = $_SESSION['files']; echo json_encode($results); } it is possible?

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  • update a column in input file by taking value from Database in perl.

    - by Rahul Singh
    input file: 1,a,USA,, 2,b,UK,, 3,c,USA,, i want to update the 4th column in the input file from taking values from one of the table. my code looks like this: my $customer_dbh = DBI-connect("DBI:Oracle:$INST", $USER, $PASS ) or die "Couldn't connect to datbase $INST"; my $cust_smh; print "connected \n "; open FILE , "+$input_file" or die "can't open the input file"; print "echo \n"; while(my $line=) { my @line_a=split(/\,/,$line); my $customer_id=$line_a[3]; print "$customer_id\n"; $cust_smh = $customer_dbh-prepare("SELECT phone_no from book where number = $line_a[0]"); $cust_smh-execute() or die "Couldn't execute stmt, error : $DBI::errstr"; my $number = $cust_smh-fetchrow_array(); $line_a[3]=$number; }

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  • How to show / debug PEAR::DB errors in webpage?

    - by Markus Ossi
    I am connecting to MySQL database on my webpage and have this copy-pasted code for errors: if(DB::isError($db)) die($db->getMessage()); I have the connection code in an outside file called connection.inc that I include at the beginning of my page before the DOCTYPE and html tags. For debugging purposes, how can I print the database errors on my webpage? I thought I could do something like this: echo 'Could not connect to database. The error was:' . $db->getMessage(); but this returns: Fatal error: Call to undefined method DB_mysql::getMessage()

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  • How much time roughly it takes to learn ASP.net programming

    - by Mirage
    I am a PHP MYSQL person but now i have got webiste to do it ASP.net. I kow nothing about ASP.NET. INitially i was thinking of ASP.NET as a programming language but now i now its not , i really don't know what it is. Someone told me that i have to do c sharp to build the website. I i have to display simple data from database how much different is c sharp from php. Does it has all function like php to echo stuff etc

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  • How to make a form using ajax, onchange event, reload to SAME page

    - by user1348220
    I've been studying this for a while and I'm not sure if I'm going about this the right way because every form I setup according to examples, it doesn't do what I need. I need to setup a form that will: set session when you select from dropdown menu not reload/refresh page (i've read that using AJAX solves this) submit and stay on SAME page (confused because most AJAX examples send it to different process.php page which is supposedly "invisible" but it doesn't "stay" on the same page, it redirects. Basically, client selects quantity of 1 to 10. If they select "2"... it does NOT reload the page.. but it DOES set a session[quantity]=2. Should be simple... but do I POST to same page as form? or POST to different page and it somehow redirects? Also, one test I did it kept pasting my "echo session[quantity]" down the page like 7, 2, 3, 5, etc. etc. each time instead of replacing it. I would paste code but it's all over the place and I'm hoping for direction on which methods to use. Feel I need to start all over again. Edit: trying to add code below but can't seem to paste it properly. <? ob_start();?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <?php session_start(); ?> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>Submit Form with out refreshing page Tutorial</title> <!-- JavaScript --> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.0/jquery.min.js"></script> <script type="text/javascript" > $(function() { $(".submit").click(function() { var gender = $("#gender").val(); var dataString = '&gender=' + gender; if(gender=='') { $('.success').fadeOut(200).hide(); $('.error').fadeOut(200).show(); } else { $.ajax({ type: "POST", url: "join.php", data: dataString, success: function(){ $('.success').fadeIn(200).show(); $('.error').fadeOut(200).hide(); } }); } return false; }); }); </script> <style type="text/css"> body{ } .error{ color:#d12f19; font-size:12px; } .success{ color:#006600; font-size:12px; } </style> </head> <body id="public"> <div style="height:30px"></div> <div id="container"> <div style="height:30px"></div> <form method="post" name="form"> <select id="gender" name="gender"> <option value="">Gender</option> <option value="male">Male</option> <option value="female">Female</option> </select> <div> <input type="submit" value="Submit" class="submit"/> <span class="error" style="display:none"> Please Enter Valid Data</span> <span class="success" style="display:none"> Your gender is <?php echo $_SESSION['gender'];?></span> </div> </form> <div style="height:20px"></div> </div><!--container--> </body> </html> <? ob_flush(); ?> and here is my page where the POST goes called join.php (called that in example so I went with it for now) <?php session_start(); if($_POST) { $gender = $_POST['gender']; $_SESSION['gender'] = $gender; } else { } ?>

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  • php open_socket

    - by sea_1987
    Hello, I am trying to open a socket to use with secure tradings xpay api, however when I check to see if the socket is open I get error returned, Can't assign requested address I need to open up 127.0.0.1:5000 is there something wring with my code that means I cannot do this? if (isset($xpay_port) and ($socket=socket_create(AF_INET, SOCK_STREAM, SOL_TCP)) and (socket_connect($socket, $address, $port))) { $text="Connection successful on IP $address, port $port"; socket_close($socket); } else $text="Unable to connect<pre>".socket_strerror(socket_last_error())."</pre>"; echo "<html><head></head><body>". $text. "</body></html>";

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  • Why does _GET in PHP wrongly decodes slash?

    - by Boaz
    Hi, Today I run into some oddity with PHP, which I fail find a proper explanation for in the documentation. Consider the following code: <?php echo $_GET['t']. PHP_EOL; ?> The code is simple - it takes a single t parameter on the url and outputs it back. So if you call it with test.php?t=%5Ca (%5c is a '\'), I expected to see: \a However, this is what I got: $ curl http://localhost/~boaz/test.php?t=%5Ca \\a Notice the double slash. Can anyone explains what's going on and give recipe for retrieving the strings as it was supplied on the URL? Thanks, Boaz

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