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• Getting x/y coordinate of a UITouch...

  - by Tarek

  HI, I have been trying to get the x/y coordinates from a touch on any iDevice. When getting the touch locations, everything looks ok if the touch is in the middle of the screen. But if I drag my finger to the bottom of the screen, I can only get a y coordinate of 1015. It should be getting to 1023. Same thing for dragging my finger to the top of the screen. I get -6. It should be 0. I have explicitly set the window and views to an origin of 0,0 and the width, height of the device's screen. Still nothing. I am really lost on what might be going on. Is something shifted? Am I not reading the x/y coordinates properly. Does something need to be transformed or converted? Any help would be much appreciated. T

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• How to include css in a hmvc setup in codeigniter

  - by tariq

  I have setup the combination Codeigniter + HMVC + Twitter Bootstrap using this tutorial. I have created two modules named app and session. The app module contains the twitter bootstrap sample. When I click on About link, a new login page is displayed which is the session module configured using <?php echo Modules::run('session/session/index'); ?> The problem I am facing is that when I include the twitter bootstrap in both the views, the app module gets realigned and corousal doesnt work. How do I get the CSS to work with the session module ?

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• Android ScrollView issue

  - by Salman

  Guys, We are trying to make a board with sticky notes. We have used ScrollView in which we have LinearLayout. We have four columns. If there are more than 3 notes in one column, scrollview comes up. Issue is, if I try to move Row 5 column 1 note to Row 1 Column 2, scroll views hides all the notes. If we scroll to top of the board, notes become visible again. Any idea what's the issue ? Thanks Salman

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• Sorting an array in descending order in Ruby.

  - by Waseem

  Hi, I have an array of hashes like following [ { :foo => 'foo', :bar => 2 }, { :foo => 'foo', :bar => 3 }, { :foo => 'foo', :bar => 5 }, ] I am trying to sort above array in descending order according to the value of :bar in each hash. I am using sort_by like following to sort above array. a.sort_by { |h| h[:bar] } However above sorts the array in ascending order. How do I make it sort in descending order? One solution was to do following: a.sort_by { |h| -h[:bar] } But that negative sign does not seem appropriate. Any views?

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• Upgrading a SharePoint list instance that was deployed via feature

  - by Goldmember

  I'm curious how others address this issue. Using VSEWSS 1.3, I have created a site content type, a list definition (w event receivers), and a list instance. All of them are in the same WSP solution and each is activated individually via features. Now let's assume that all the features have been activated for some time, and the list instance contains a number of items (that can't be deleted). Now suppose I need to make a change to the schema.xml (inject some javascript, modify views, whatever) of the list. Is it even possible to "upgrade" the schema of the existing list instance? Otherwise I would think I'm stuck creating a new instance and copying items over.

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• Django - transactions in the model?

  - by orokusaki

  Models (disregard typos / minor syntax issues. It's just pseudo-code): class SecretModel(models.Model): some_unique_field = models.CharField(max_length=25, unique=True) # Notice this is unique. class MyModel(models.Model): secret_model = models.OneToOneField(SecretModel, editable=False) # Not in the form spam = models.CharField(max_length=15) foo = models.IntegerField() def clean(self): SecretModel.objects.create(some_unique_field=self.spam) Now if I go do this: MyModel.objects.create(spam='john', foo='OOPS') # Obviously foo won't take "OOPS" as it's an IntegerField. #.... ERROR HERE MyModel.objects.create(spam='john', foo=5) # So I try again here. #... IntegrityError because SecretModel with some_unique_field = 'john' already exists. I understand that I could put this into a view with a request transaction around it, but I want this to work in the Admin, and via an API, etc. Not just with forms, or views. How is it possible?

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• how to get additional response in ajax?

  - by udaya

  Hi I am using ajax to showing the error message ...I am getting the values in success: function(msgqq) This is my ajax if want to get another response then how to get ex: I want success: function(msgqq) and success: function(msg) This is my ajax function UserNameAvailablity(inp) { $.ajax({ type: "GET", url: "<?=base_url()?>/system/application/views/ssitAjax.php", cache: false, data: "txtUserName="+inp, success: function(msgqq){ document.getElementById('showErrmessage').innerHTML=msgqq; $("#showErrmessage").html(msgqq); if(txtUserName.value =="") { document.getElementById('txtUserName').focus(); document.getElementById('txtUserName').value=""; } } }); }

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• Question about rights for svn

  - by diadiora

  I have a web application written in asp.net mvc. I have in MyApp.Web assembly the list of views and and the content files(images, scripts, css, and so on). In MyApp.WebBase I have the rest of fonctionality(Controllers, domain(entities, repositories, services)). Now the question is the following: I want to give to third party html coder access only to MyApp.Web source code in order he to be able to compile the application locally and see the results. By other hand the developer team shoul have access to full source code. The problem is that in order the html coder to be able to compile the application locally he need in his project the references to the MyApp.WebBase.dll Can anyone help me? Thanks.

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• MVC paths in Extjs

  - by Oleg

  I have got a ExtJs application (MVC). So, I define many controllers, models, views and stores. At now, the structure of my project is not easy. For example my model: Ext.define('KP.model.account.AccountList', { extend: 'Ext.data.Model', fields: ['parameter', 'string_value'] }); I define my store with model like this: Ext.define('KP.store.account.AccountList', { extend: 'Ext.data.Store', alias: 'store.s_AccountList', model: 'KP.model.account.AccountList', ...................................... }); If I want to move some .js files, I must rewrite many paths in classes definitions. So, how can I declare my classes (by alias maybe) and use them more effectively? It's need, If I move files on files tree. Thanks!

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• Rhino Mocks Partial Mock

  - by dotnet crazy kid

  I am trying to test the logic from some existing classes. It is not possible to re-factor the classes at present as they are very complex and in production. What I want to do is create a mock object and test a method that internally calls another method that is very hard to mock. So I want to just set a behaviour for the secondary method call. But when I setup the behaviour for the method, the code of the method is invoked and fails. Am I missing something or is this just not possible to test without re-factoring the class? I have tried all the different mock types (Strick,Stub,Dynamic,Partial ect.) but they all end up calling the method when I try to set up the behaviour. using System; using MbUnit.Framework; using Rhino.Mocks; namespace MMBusinessObjects.Tests { [TestFixture] public class PartialMockExampleFixture { [Test] public void Simple_Partial_Mock_Test() { const string param = "anything"; //setup mocks MockRepository mocks = new MockRepository(); var mockTestClass = mocks.StrictMock<TestClass>(); //record beahviour *** actualy call into the real method stub *** Expect.Call(mockTestClass.MethodToMock(param)).Return(true); //never get to here mocks.ReplayAll(); //this is what i want to test Assert.IsTrue(mockTestClass.MethodIWantToTest(param)); } public class TestClass { public bool MethodToMock(string param) { //some logic that is very hard to mock throw new NotImplementedException(); } public bool MethodIWantToTest(string param) { //this method calls the if( MethodToMock(param) ) { //some logic i want to test } return true; } } } }

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• ASP.NET MVC pass information from controller to view WITHOUT ViewData, ViewModel, or Session

  - by josh

  I have a unique scenario where I want a base controller to grab some data and store it in a list. The list should be accessible from my views just as ViewData is. I will be using this list on every page and would like a cleaner solution than just shoving it in the ViewDataDictionary. After attempting to come up with a solution, I thought I would create a custom ViewPage with a property to hold my list. My custom ViewPage would inherit from System.Web.MVC.ViewPage. However, I do not know where MVC passes the viewdata from the controller off to the view. More importantly, how do I get it to pass my list down to the view? Thanks for the help.

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• UISplitViewController: how to get toolbar if details controller is UITableView?

  - by Krumelur

  Hi, I checked out Apple's example on how to exchange detail views in the UISplitViewController (http://developer.apple.com/library/ios/#samplecode/MultipleDetailViews/Introduction/Intro.html#//apple_ref/doc/uid/DTS40009775) and it seems that they put the UIToolbar in every detail controller. Then, if the device is rotated, they hide the toolbar or show it and add a popover button which will show the root controller. I'd like to adopt this pattern to show my root controller in a popover using a button in the toolbar, but unfortunately, my detail controllers are all UITableViewControllers and they do not allow adding other UI elements than a table view. So how do I deal with that? Is there an example around? René

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• How do you implement paging in ASP.NET MVC?

  - by Kevin Pang

  Currently, I'm using a strategy found on many blog posts. Basically, the URL contains the page number (e.g. /Users/List/5 will give you the users on page 5 of your paged list of users). However, I'm not running into a situation where one page must list two separate paged lists. How do I go about doing this using ASP.NET MVC? Do I simply provide two url parameters (e.g. /Users/List?page1=1&page2=2)? Is there a better way by using partial views?

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• How to handle similar items in rails MVC?

  - by mocker

  I'm working on building a pretty simple site mainly as an exercise in learning more about rails. You can see my rough progress at statific.com. It's working pretty much as I wanted it for keeping track of server information, but now I'd like to expand it to other things, next on the list being firewalls. I can pretty easily duplicate all the models, views, etc.. that I have for my servers. The problem I see with that is that it isn't very DRY since most of the code would look the same, the only difference would be the attributes I have setup for firewalls would be different than for servers. I know in plain ruby this is pretty simple, you can have a 'Product' w/ common attributes ('manufacturer', 'model') and then have children with more specific attributes. Does the same type of concept exist for rails, or am I just over thinking this?

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• Pros and Cons on where to place business logic: app level or DB

  - by Juri

  Hi, I always again encounter discussions about where to place the business logic: inside a business layer in the application code or down in the DB in terms of stored procedures. Personally I'd tend to the 1st approach, but I'd like to hear some opinions from your part first, without influencing you with my personal views. I know there doesn't exist a one-size-fits-all solution and it often depends on many factors, but we can discuss about that. Btw, we are in the context of web applications and our current approach is to have UI layer which accepts UI input and does a first, client-side validation Business layer with a number of service-classes which contains the business logic including validation for user input (server-side) Data Access Layer which calls stored procedures from the DB for doing persistency/read operations Many people however tend to move the business layer stuff (especially regarding the validation) down to the DB in terms of stored procedures. What do you think about it? I'd like to discuss.

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• Is there a way to only backup a SQL 2005 database structure fully, but only the data in a certain se

  - by TheSoftwareJedi

  I have several schemas in my database, and the largest one ("large" meaning disk space consumed) is my "web" schema which is a denormalized copy of data in the operational schemas. This denormalized data is able to be reconstructed at anytime, and is merely there for extremely fast read purposes. Since the data is redundant, and VERY large - I'd like to exclude it from being backed up. I already have stored procedures that can regenerate all of the data in that schema in a couple of hours - for use in the event of a failure. I assume I can split the tables in this schema out to another data file or such (ideally even on another drive for faster reads), but is there a way to never have that data file backup, yet still in the event of a failure its structure could be restored (and other DDL stuff like procs, views, etc)? Somewhat related, can I also have these tables not do transaction logging, if I go to "Full" backup mode for the rest of the database?

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• C# Xamarin.IOS / MonoTouch - Toolbar Disappears

  - by Goober

  I have a Xamarin.IOS/Monotouch project with 2 views - MainView and View2. My MainView window has a navigationController at the top, and a toolbar at the bottom. When I call PushViewController(View2,true); - I get pushed from MainView to my second view (View2). View2 also has a navigationController at the top, but it DOES NOT have a toolbar at the bottom - intentionally. When I click the "Back" button on View2 to push back to my MainView, the toolbar at the bottom of MainView has disappeared. Any ideas on how to get around this? Much appreciated.

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• UIViewController prevent view from unloading

  - by Ican Zilb

  When my iPhone app receives a Memory warning the views of UIViewControllers that are not currently visible get unloaded. In one particular controller unloading the view and the outlets is rather fatal. I'm looking for a way to prevent this view from being unloaded. I find this behavior rather stupid - I have a cache mechanism, so when a memory warning comes - I unload myself tons of data and I free enough memory, but I definitely need this view untouched. I see UIViewController has a method 'unloadViewIfReloadable', which gets called when the Memory Warning comes. Does anybody know how to tell Cocoa Touch that my view is not reloadable? Any other suggestions how to prevent my view from being unloaded on Memory Warning? Thanks in advance

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• iphone navigation tutorial with simple form

  - by iamthewit

  Hi All, I'm looking to create quite a basic app with a very simple navigation system but each of the tutorials I've come across so far go into too much depth or just involve lots of different form elements. I want to keep it as straight forward and simple as I can. If anyone knows of any tutorials that can show me how to create a root view with say 5 or 6 sub views each displaying a form for collecting different types of data I would be very grateful. This seems like quite a simple thing to achieve but so far I havent found anything that specifically relates to what I want to do. thanks in advance!

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• ASP .net MVC Invoking default controller and action vs Setting a startup page

  - by SARAVAN

  Hi, I am developing code on the sample ASP .net MVC template provided by VS2010. The first time I ran the code without adding anything, the index.aspx page was invoked which is expected. But for some reasons I added a login.aspx and then accidentally set that as a startup page. Now when I ran the application the default startup url look like http://localhost/Views/login.aspx. I am thinking this is not a valid MVC routing path and I get the requested resource cannot be found error. I am not sure how to revert this back and make sure the default ../home/index is invoked. Can any one throw some light on this? Also should I not set the startup page as we do in asp .net webforms?

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• Pageview implementation

  - by The Elite Gentleman

  Hi everyone I want to add a pageview feature on my current web application. This page view is based on the count of user viewing the page. It must be unique, i.e. I must not view a person's page 10000 times and record it as 10000 views, just record 1 view instead. My question is, should I base my pageview count on IP address? If not, what is/are the best approach in doing this? I know that if the person has logged in to my system, I can simply use the user id stored in the session and check on the record if the user has/hasn't viewed the page and update accordingly. But for "anonymous" viewers, what is the best approach? Thanks. PS How does Youtube does it?

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• Limiting the maximum number of concurrent requests django/apache

  - by Johan

  Hi, I have a django site that demonstrates the usage of a tool. One of my views takes a file as input and runs some fairly heavy computation trough an external python script and returns some output to the user. The tool runs fast enough to return the output in the same request though. I would however want to limit how many concurrent requests to this URL/view to keep the server from getting congested. Any tips on how i would go about doing this? The page in itself is very simple and the usage will be low.

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• HDFS some datanodes of cluster are suddenly disconnected while reducers are running

  - by user1429825

  I have 8 slave computers and 1 master computer for running Hadoop (ver 0.21) some datanodes of cluster are suddenly disconnected while I was running MapReduce code on 10GB data After all mappers finished and around 80% of reducers was processed, randomly one or more datanode disconned from network. and then the other datanodes start to disappear from network even if I killed the MapReduce job when I found some datanode was disconnected. I've tried to change dfs.datanode.max.xcievers to 4096, turned off fire-walls of all computing node, disabled selinux and increased the number of file open limit to 20000 but they didn't work at all... anyone have a idea to solve this problem? followings are error log from mapreduce 12/06/01 12:31:29 INFO mapreduce.Job: Task Id : attempt_201206011227_0001_r_000006_0, Status : FAILED java.io.IOException: Bad connect ack with firstBadLink as ***.***.***.148:20010 at org.apache.hadoop.hdfs.DFSOutputStream$DataStreamer.createBlockOutputStream(DFSOutputStream.java:889) at org.apache.hadoop.hdfs.DFSOutputStream$DataStreamer.nextBlockOutputStream(DFSOutputStream.java:820) at org.apache.hadoop.hdfs.DFSOutputStream$DataStreamer.run(DFSOutputStream.java:427) and followings are logs from datanode 2012-06-01 13:01:01,118 INFO org.apache.hadoop.hdfs.server.datanode.DataNode: Receiving block blk_-5549263231281364844_3453 src: /*.*.*.147:56205 dest: /*.*.*.142:20010 2012-06-01 13:01:01,136 INFO org.apache.hadoop.hdfs.server.datanode.DataNode: DatanodeRegistration(*.*.*.142:20010, storageID=DS-1534489105-*.*.*.142-20010-1337757934836, infoPort=20075, ipcPort=20020) Starting thread to transfer block blk_-3849519151985279385_5906 to *.*.*.147:20010 2012-06-01 13:01:19,135 WARN org.apache.hadoop.hdfs.server.datanode.DataNode: DatanodeRegistration(*.*.*.142:20010, storageID=DS-1534489105-*.*.*.142-20010-1337757934836, infoPort=20075, ipcPort=20020):Failed to transfer blk_-5797481564121417802_3453 to *.*.*.146:20010 got java.net.ConnectException: > Connection timed out at sun.nio.ch.SocketChannelImpl.checkConnect(Native Method) at sun.nio.ch.SocketChannelImpl.finishConnect(SocketChannelImpl.java:701) at org.apache.hadoop.net.SocketIOWithTimeout.connect(SocketIOWithTimeout.java:206) at org.apache.hadoop.net.NetUtils.connect(NetUtils.java:373) at org.apache.hadoop.hdfs.server.datanode.DataNode$DataTransfer.run(DataNode.java:1257) at java.lang.Thread.run(Thread.java:722) 2012-06-01 13:06:20,342 INFO org.apache.hadoop.hdfs.server.datanode.DataBlockScanner: Verification succeeded for blk_6674438989226364081_3453 2012-06-01 13:09:01,781 WARN org.apache.hadoop.hdfs.server.datanode.DataNode: DatanodeRegistration(*.*.*.142:20010, storageID=DS-1534489105-*.*.*.142-20010-1337757934836, infoPort=20075, ipcPort=20020):Failed to transfer blk_-3849519151985279385_5906 to *.*.*.147:20010 got java.net.SocketTimeoutException: 480000 millis timeout while waiting for channel to be ready for write. ch : java.nio.channels.SocketChannel[connected local=/*.*.*.142:60057 remote=/*.*.*.147:20010] at org.apache.hadoop.net.SocketIOWithTimeout.waitForIO(SocketIOWithTimeout.java:246) at org.apache.hadoop.net.SocketOutputStream.waitForWritable(SocketOutputStream.java:164) at org.apache.hadoop.net.SocketOutputStream.transferToFully(SocketOutputStream.java:203) at org.apache.hadoop.hdfs.server.datanode.BlockSender.sendChunks(BlockSender.java:388) at org.apache.hadoop.hdfs.server.datanode.BlockSender.sendBlock(BlockSender.java:476) at org.apache.hadoop.hdfs.server.datanode.DataNode$DataTransfer.run(DataNode.java:1284) at java.lang.Thread.run(Thread.java:722) hdfs-site.xml <configuration> <property> <name>dfs.name.dir</name> <value>/home/hadoop/data/name</value> </property> <property> <name>dfs.data.dir</name> <value>/home/hadoop/data/hdfs1,/home/hadoop/data/hdfs2,/home/hadoop/data/hdfs3,/home/hadoop/data/hdfs4,/home/hadoop/data/hdfs5</value> </property> <property> <name>dfs.replication</name> <value>3</value> </property> <property> <name>dfs.datanode.max.xcievers</name> <value>4096</value> </property> <property> <name>dfs.http.address</name> <value>0.0.0.0:20070</value> <description>50070 The address and the base port where the dfs namenode web ui will listen on. If the port is 0 then the server will start on a free port. </description> </property> <property> <name>dfs.datanode.http.address</name> <value>0.0.0.0:20075</value> <description>50075 The datanode http server address and port. If the port is 0 then the server will start on a free port. </description> </property> <property> <name>dfs.secondary.http.address</name> <value>0.0.0.0:20090</value> <description>50090 The secondary namenode http server address and port. If the port is 0 then the server will start on a free port. </description> </property> <property> <name>dfs.datanode.address</name> <value>0.0.0.0:20010</value> <description>50010 The address where the datanode server will listen to. If the port is 0 then the server will start on a free port. </description> <property> <name>dfs.datanode.ipc.address</name> <value>0.0.0.0:20020</value> <description>50020 The datanode ipc server address and port. If the port is 0 then the server will start on a free port. </description> </property> <property> <name>dfs.datanode.https.address</name> <value>0.0.0.0:20475</value> </property> <property> <name>dfs.https.address</name> <value>0.0.0.0:20470</value> </property> </configuration> mapred-site.xml <configuration> <property> <name>mapred.job.tracker</name> <value>masternode:29001</value> </property> <property> <name>mapred.system.dir</name> <value>/home/hadoop/data/mapreduce/system</value> </property> <property> <name>mapred.local.dir</name> <value>/home/hadoop/data/mapreduce/local</value> </property> <property> <name>mapred.map.tasks</name> <value>32</value> <description> default number of map tasks per job.</description> </property> <property> <name>mapred.tasktracker.map.tasks.maximum</name> <value>4</value> </property> <property> <name>mapred.reduce.tasks</name> <value>8</value> <description> default number of reduce tasks per job.</description> </property> <property> <name>mapred.map.child.java.opts</name> <value>-Xmx2048M</value> </property> <property> <name>io.sort.mb</name> <value>500</value> </property> <property> <name>mapred.task.timeout</name> <value>1800000</value> <!-- 30 minutes --> </property> <property> <name>mapred.job.tracker.http.address</name> <value>0.0.0.0:20030</value> <description> 50030 The job tracker http server address and port the server will listen on. If the port is 0 then the server will start on a free port. </description> </property> <property> <name>mapred.task.tracker.http.address</name> <value>0.0.0.0:20060</value> <description> 50060 </property> </configuration>

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• Ruby on Rails - where to write business logic while processing a request? (newbie)

  - by Genadinik

  I am learning Ruby on Rails. I made a simple link like this: <%= link_to "Alex Link", alexes_path(@alex) %> then I routed it in routes.rb like this: resources :alexes get "home/index" then I am a bit unclear, but I think it goes to this part of the controller: def index #@alexes = Alex.all respond_to do |format| format.html # index.html.erb format.json { render json: @alexes } end end Am I correct that it goes to this part of the controller? Then nothing much happens and it goes to the next page which is index.html.rb under views\alexes So what I am wondering is - if I needed to do some business logic, would I write that in the controller snippet? Where inside the snippet? An example would be nice to take a look. Also, I would like to connect to a MongoDb database. Would I also write that in the middle of the controller? Thanks!

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• Prevent Django from redirecting to add trailing slash

  - by konrad

  UPDATED: Sorry, it looks like it's Apache that's rewriting it for some reason, not Django. I'll investigate further and post my findings. I need to add a /xmlrpc.php to my Byteflow installation to handle an application that is written for PHP blog engines and uses this hardcoded path. For some reason Byteflow appends a slash to this URL using a 301 Moved Permanently redirect, which breaks the application. It does not do so for the /robots.txt that is configured in a similar way. Relevant lines from the project urls.py: url(r'^xmlrpc.php$', 'django_xmlrpc.views.xmlrpc_handler'), url(r'^robots.txt$', include('robots.urls')), I read that the behavior was changed in the Django codebase in commit 6852 (in 2007) to prevent redirects being done for urls that have been explicitly configured not to contain any trailing slashes. I'm using Django 1.1. I assume that once I have fixed this problem, I should be able to use this application with Byteflow, because the application uses the MetaWeblog XML-RPC API. Any clue?

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