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• Spring webflow 1.0 - Downloading a file

  - by Dave

  I am using spring webflow 1.0. I am uploading a csv file, parsing it, and displying results before proceeding. The user has an option to download a csv file that contains the records that did not pass validation. When I click the link in a JSP to download this file, webflow invokes a form Action. The form action writes out a file via getting the output stream off the response: HttpServletResponse response = ((ServletExternalContext) context.getExternalContext()).getResponse(); I do not want to leave the jsp I'm currently on. I just want to download the file. In other words, I do not want to transition to another state. I just want to serve the dynamically rendered file. Everything works (I don't leave the page, and I download the file), but I'm getting the following error in my console: _pEncydKfggPHJo8=org.springframework.webflow.engine.NoMatchingTransitionException: No transition was matched on the event(s) signaled by the [1] action(s) that executed in this action state 'downloadErrorReportAction' of flow 'myFlow'; transitions must be defined to handle action result outcomes -- possible flow configuration error? Note: the eventIds signaled were: 'array<String>[[null]]', while the supported set of transitional criteria for this action state is 'array<TransitionCriteria>[[empty]]' at org.springframework.webflow.engine.ActionState.doEnter(ActionState.java:187) at org.springframework.webflow.engine.State.enter(State.java:191) at org.springframework.webflow.engine.Transition.execute(Transition.java:212) at org.springframework.webflow.engine.TransitionableState.onEvent(TransitionableState.java:107) at org.springframework.webflow.engine.Flow.onEvent(Flow.java:534) Truncated. see log file for complete stacktrace Here is the relevant portion of my webflow config. <view-state id="showUploadResults" view="UploadResults3.0"> <render-actions> <action bean="UploadResultsAction" method="transitionToWebflow"/> <action bean="UploadResultsAction" method="setupData"/> </render-actions> <transition on="submit" to="proceed"/> <transition on="downloadErrorReport" to="downloadErrorReportAction"/> </view-state> <action-state id="downloadErrorReportAction"> <action bean="UploadResultsAction" method="downloadErrorReport" name="downloadErrorReport"/> </action-state>

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• COMException Problem

  - by Jack Harvin

  Wondering if anyone could help with my problem. Below is the code, and after the code an explination of where the exception is thrown. using System; using System.Collections.Generic; using System.ComponentModel; using System.Data; using System.Drawing; using System.Linq; using System.Text; using System.Windows.Forms; using System.Web; using WatiN.Core; using System.Threading; using System.IO; namespace WindowsFormsApplication1 { public partial class Form1 : System.Windows.Forms.Form { public Form1() { InitializeComponent(); } private void Form1_Load(object sender, EventArgs e) { } private void button1_Click(object sender, EventArgs e) { Thread t = new Thread(createApplications); Settings.AutoStartDialogWatcher = false; t.SetApartmentState(System.Threading.ApartmentState.STA); t.Start(); } private void createApplications() { createApp("username", "password", "Test App", "This is just a test description", "http:/mysite.com"); } private void createApp(String username, String password, String appName, String description, String appUrl) { var currentBrowser = new IE("http://mysite.com/login/php"); currentBrowser.TextField(Find.ById("username")).TypeText(username); currentBrowser.TextField(Find.ById("password")).TypeText(password); currentBrowser.Button(Find.ById("submit")).Click(); currentBrowser.GoTo("http://mysite.com/createmusicapp.php"); currentBrowser.TextField(Find.ById("application_name")).TypeText(appName); currentBrowser.TextField(Find.ById("application_description")).TypeText(description); currentBrowser.TextField(Find.ById("application_url")).TypeText(appUrl); currentBrowser.RadioButton(Find.ById("client_application_desktop_1")).Click(); currentBrowser.RadioButton(Find.ById("client_application_is_writable_1")).Click(); WatiN.Core.Image captchaImage = currentBrowser.Div(Find.ById("recaptcha_image")).Image(Find.ByStyle("display", "block")); Form2 captcha = new Form2(captchaImage.Src); captcha.ShowDialog(); } } } The exception is thrown on this line: currentBrowser.TextField(Find.ById("username")).TypeText(username); BUT, it's thrown when it gets to this line: captcha.ShowDialog(); It logs in, and fills in the app details and Form2 loads fine, but once loaded, after around 2-3 seconds the exception happens. I am wondering if it's anything to do with the threads? But I wouldn't know how to solve it if it was. The complete exception thrown is: The object invoked has disconnected from its clients. (Exception from HRESULT: 0x80010108 (RPC_E_DISCONNECTED))

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• ASP.NET MVC: How to display strongly typed view model, containing list of items, which also contain

  - by Sam Delaney

  Hi, I'm building an app using ASP.NET MVC which I want to use a strongly type view model, which contains a List called items which contains an id int and itemName string. The view model also conatins a List called people, and the Person class contains a List. The way I want to display the information is as a table, with each row having a column of Person name, then n number of columns which contain checkboxes, one for each of the List, and checked based on whether the Person's List (called items) contains the id of the Item. I have the display working fine, but I'm struggling to understand how to name the items so that the posted method can read the data. This is what I have in the BeginForm: <table cellpadding="20"> <thead> <th>Person name</th> <!-- for each of the items, create a column with the item name --> <% foreach( var i in Model.items ) { %> <th><%= Html.Encode(i.itemName) %></th> <% } %> </thead> <% foreach( var p in Model.people ) { %> <tr> <td><%= Html.Encode(p.name) %></td> <!-- for each item, create a column with a checkbox --> <% foreach( var i in Model.items ) { %> <td> <% if( p.items.Contains(i.id) ) { %> <!-- vm is the name of the view model passed to the view --> <%= Html.CheckBox( "vm.people[" + p.id + "].items[" + i.id + "]", true ) %> <% } else { %> <%= Html.CheckBox( "vm.people[" + p.id + "].items[" + i.id + "]", false ) %> <% } %> </td> <% } %> </tr> <% } %> </table> And this code displays the information perfectly. When I click submit, however, I get an Object Reference Not Set.. error message. Can anyone help with this please?

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• Asp.Net MVC2 Model Binding Problem.

  - by Pino

  Why is my controller recieving an empty model in this case? Using the following, <%@ Page Title="" Language="C#" MasterPageFile="~/Views/Shared/Site.Master" Inherits="System.Web.Mvc.ViewPage<X.Models.ProductModel>" %> <asp:Content ID="Content1" ContentPlaceHolderID="MainContent" runat="server"> <h2>Product</h2> <% using (Html.BeginForm() {%> <%: Html.ValidationSummary(true) %> <div class="editor-label"> Product Name </div> <div class="editor-field"> <%: Html.TextBoxFor(model => model.Name) %> <%: Html.ValidationMessageFor(model => model.Name) %> </div> <br /> <div class="editor-label"> Short Description </div> <div class="editor-field"> <%: Html.TextAreaFor(model => model.ShortDesc) %> <%: Html.ValidationMessageFor(model => model.ShortDesc) %> </div> <br /> <div class="editor-label"> Long Description </div> <div class="editor-field"> <%: Html.TextAreaFor(model => model.LongDesc) %> <%: Html.ValidationMessageFor(model => model.LongDesc) %> </div> <p> <input type="submit" value="Create" /> </p> <% } %> </asp:Content> and the following controller using System.Web.Mvc; using X.Lib.Services; using X.Models; namespace X.Admin.Controllers { public class ProductController : Controller { [HttpGet] public ActionResult ProductData() { return View(); } [HttpPost] public ActionResult ProductData(ProductModel NewProduct) { //Validate and save if(ModelState.IsValid) { //Save And do stuff. var ProductServ = new ProductService(); ProductServ.AddProduct(NewProduct); } return View(); } } }

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• Associated models in Rails?

  - by dannymcc

  Hi Everyone, In my rails application I have two models called Kases and Notes. They work in the same way comments do with blog posts, I.e. each Kase entry can have multiple notes attached to it. I have got everything working, but for some reason I cannot get the destroy link to work for the Notes. I think I am overlooking something that is different with associated models to standard models. Notes Controller class NotesController < ApplicationController # POST /notes # POST /notes.xml def create @kase = Kase.find(params[:kase_id]) @note = @kase.notes.create!(params[:note]) respond_to do |format| format.html { redirect_to @kase } format.js end end end Kase Model class Kase < ActiveRecord::Base validates_presence_of :jobno has_many :notes Note Model class Note < ActiveRecord::Base belongs_to :kase end In the Kase show view I call a partial within /notes called _notes.html.erb: Kase Show View <div id="notes"> <h2>Notes</h2> <%= render :partial => @kase.notes %> <% form_for [@kase, Note.new] do |f| %> <p> <h3>Add a new note</h3> <%= f.text_field :body %><%= f.submit "Add Note" %> </p> <% end %> </div> /notes/_note.html.erb <% div_for note do %> <div id="sub-notes"> <p> <%= h(note.body) %><br /> <span style="font-size:smaller">Created <%= time_ago_in_words(note.created_at) %> ago on <%= note.created_at %></span> </p> <%= link_to "Remove Note", kase_path(@kase), :confirm => 'Are you sure?', :method => :delete, :class => 'important' %> </div> <% end %> As you can see, I have a Remove Note destroy link, but that destroys the entire Kase the note is associated with. How do I make the destroy link remove only the note? <%= link_to "Remove Note", kase_path(@kase), :confirm => 'Are you sure?', :method => :delete, :class => 'important' %> Any help would, as always, be greatly appreciated! Thanks, Danny

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• Having to hit the site login button twice after first turning on computer

  - by John

  Hello, The code below is for a login that I'm using. It works fine, but when I first try logging in after turning on my computer, it only works the second time that I hit the "Login" button. Any idea how I can make it not require hitting the "Login" button twice in this situation? Thanks in advance, John function isLoggedIn() { if (session_is_registered('loginid') && session_is_registered('username')) { return true; // the user is loged in } else { return false; // not logged in } return false; } if (!isLoggedIn()) { if (isset($_POST['cmdlogin'])) { if (checkLogin($_POST['username'], $_POST['password'])) { show_userbox(); } else { echo "Incorrect Login information !"; show_loginform(); } } else { show_loginform(); } } else { show_userbox(); } function show_loginform($disabled = false) { echo '<form name="login-form" id="login-form" method="post" action="./index.php"> <div class="usernameformtext"><label title="Username">Username: </label></div> <div class="usernameformfield"><input tabindex="1" accesskey="u" name="username" type="text" maxlength="30" id="username" /></div> <div class="passwordformtext"><label title="Password">Password: </label></div> <div class="passwordformfield"><input tabindex="2" accesskey="p" name="password" type="password" maxlength="15" id="password" /></div> <div class="registertext"><a href="http://www...com/sandbox/register.php" title="Register">Register</a></div> <div class="lostpasswordtext"><a href="http://www...com/sandbox/lostpassword.php" title="Lost Password">Lost password?</a></div> <p class="loginbutton"><input tabindex="3" accesskey="l" type="submit" name="cmdlogin" value="Login" '; if ($disabled == true) { echo 'disabled="disabled"'; } echo ' /></p></form>'; } EDIT: Here is another function that is used. function isLoggedIn() { if (session_is_registered('loginid') && session_is_registered('username')) { return true; // the user is loged in } else { return false; // not logged in } return false; }

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• navigator.onLine

  - by cf_PhillipSenn

  I'm playing with the incomplete example found at http://www.w3.org/TR/offline-webapps/ But I'm distressed to see comments in it like: "renders the note somewhere", and "report error", and "// …" So, will someone please help me write a valid example? Here's what I've got so far: <!DOCTYPE HTML> <html manifest="cache-manifest"> <head> <script> var db = openDatabase("notes", "", "The Example Notes App!", 1048576); function renderNote(row) { // renders the note somewhere } function reportError(source, message) { // report error } function renderNotes() { db.transaction(function(tx) { tx.executeSql('CREATE TABLE IF NOT EXISTS Notes(title TEXT, body TEXT)', []); tx.executeSql(‘SELECT * FROM Notes’, [], function(tx, rs) { for(var i = 0; i < rs.rows.length; i++) { renderNote(rs.rows[i]); } }); }); } function insertNote(title, text) { db.transaction(function(tx) { tx.executeSql('INSERT INTO Notes VALUES(?, ?)', [ title, text ], function(tx, rs) { // … }, function(tx, error) { reportError('sql', error.message); }); }); } </script> <style> label { display:block; } </style> </head> <body> <form> <label for="mytitle">Title:</label> <input name="mytitle"> <label for="mytext">Text:</label> <textarea name="mytext"></textarea> <!-- There is no submit button because I want to save the info on every keystroke --> </form> </body> </html> I also know that I have to incorporate this in there somewhere: if (navigator.onLine) { // Send data using XMLHttpRequest } else { // Queue data locally to send later } But I'm not sure what even I would tie that too.

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• Basic Ruby On Rails Linking Help

  - by dweebsonduty

  So I am beginning to work with Rails and I get some of the concepts but am stuck on an important one. Let's say I have customers which has many jobs and jobs which belongs to customers. How would I go about creating a new job for a customer? I can create a link that goes to customers/1/jobs/new and I can grab the customer ID but how do I tell it that I am creating a job for customer 1? I know this is the most basic of things but I just need a push in the right direction. This is my form so far: How do I get :customer_id to populate with the customer_id param? <h1>New job</h1> <% form_for(@job) do |f| %> <%= f.error_messages %> <p> <%= f.label :customer_id %><br /> <%= f.text_field :customer_id %> </p> <p> <%= f.label :manufacturer %><br /> <%= f.text_field :manufacturer %> </p> <p> <%= f.label :serial_number %><br /> <%= f.text_field :serial_number %> </p> <p> <%= f.label :problem %><br /> <%= f.text_area :problem %> </p> <p> <%= f.label :notes %><br /> <%= f.text_area :notes %> </p> <p> <%= f.label :status %><br /> <%= f.text_field :status %> </p> <p> <%= f.label :tech_id %><br /> <%= f.text_field :tech_id %> </p> <p> <%= f.submit 'Create' %> </p> <% end %> <%= link_to 'Back', jobs_path %>

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• MVC Rendered Partial, how to get partial/view model in main model post to controller

  - by user1475788

  I have a text file and when users upload the file, the controller action method parses that file using state machine and uses a generic list to store some values. I pass this back to the view in the form of an IEnumerable. Within my main view, based on this ienumerable list I render a partail view to iterate items and display labels and a textarea. Users could add their input in the text area. When the users hit the save button this ienumrable list from the partial view rendered is null. so please advice any solutions. here is my main view @model RunLog.Domain.Entities.RunLogEntry @{ ViewBag.Title = "Create"; Layout = "~/Views/Shared/_Layout.cshtml"; } @using (Html.BeginForm("Create", "RunLogEntry", FormMethod.Post, new { enctype = "multipart/form-data" })) { <div id="inputTestExceptions" style="display: none;"> <table class="grid" style="width: 450px; margin: 3px 3px 3px 3px;"> <thead> <tr> <th> Exception String </th> <th> Comment </th> </tr> </thead> <tbody> @if (Model.TestExceptions != null) { foreach (var p in Model.TestExceptions) { Html.RenderPartial("RunLogTestExceptionSummary", p); } } </tbody> </table> </div> } partial view as follows: @model RunLog.Domain.Entities.RunLogEntryTestExceptionDisplay <tr> <td> @Model.TestException@ </td> <td>@Html.TextAreaFor(Model.Comment, new { style = "width: 200px; height: 80px;" }) </td> </tr> Controller action [HttpPost] public ActionResult Create(RunLogEntry runLogEntry, String ServiceRequest, string Hour, string Minute, string AMPM, string submit, IEnumerable<HttpPostedFileBase> file, String AssayPerformanceIssues1, IEnumerable<RunLogEntryTestExceptionDisplay> models) { } The problem is test exceptions which contains exception string and comment is comming back null.

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• Unrequired property keeps getting data-val-required attribute

  - by frennky

  This is the model with it's validation: [MetadataType(typeof(TagValidation))] public partial class Tag { } public class TagValidation { [Editable(false)] [HiddenInput(DisplayValue = false)] public int TagId { get; set; } [Required] [StringLength(20)] [DataType(DataType.Text)] public string Name { get; set; } //... } Here is the view: <h2>Create</h2> <script src="@Url.Content("~/Scripts/jquery.validate.min.js")" type="text/javascript"></script> <script src="@Url.Content("~/Scripts/jquery.validate.unobtrusive.min.js")" type="text/javascript"></script> @using (Html.BeginForm()) { @Html.ValidationSummary(true) <fieldset> <legend>Tag</legend> <div>@Html.EditorForModel()</div> <p> <input type="submit" value="Create" /> </p> </fieldset> } <div> @Html.ActionLink("Back to List", "Index") </div> And here is what get's renderd: <form action="/Tag/Create" method="post"> <fieldset> <legend>Tag</legend> <div><input data-val="true" data-val-number="The field TagId must be a number." data-val-required="The TagId field is required." id="TagId" name="TagId" type="hidden" value="" /> <div class="editor-label"><label for="Name">Name</label></div> <div class="editor-field"><input class="text-box single-line" data-val="true" data-val-length="The field Name must be a string with a maximum length of 20." data-val-length-max="20" data-val-required="The Name field is required." id="Name" name="Name" type="text" value="" /> <span class="field-validation-valid" data-valmsg-for="Name" data-valmsg-replace="true"></span></div> ... </fieldset> </form> The problem is that TagId validation gets generated althoug thare is no Required attribute set on TagId property. Because of that I can't even pass the client-side validation in order to create new Tag in db. What am I missing?

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• How to update textbox value

  - by Thomas

  I have a textbox in my View. I input a number into the textbox, and then i want the controller to multiply the number and put the result into the textbox. How can I do that? This is what i have done already. Let's start with the View: <%@ Page Language="C#" Inherits="System.Web.Mvc.ViewPage<dynamic>" %> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" > <head runat="server"> <title>Index</title> </head> <body> <div> <h2>Please enter a number</h2> <% using (Html.BeginForm()) { %> <%=Html.TextBox("number")%> <input type="submit" value="Index" name ="Index" /> <% } %> </div> </body> </html> As you can see I have a simple textbox and button. This is my controller: using System.Web.Mvc; namespace MvcApplication1.Controllers { public class HomeController : Controller { // // GET: /Home/ public ActionResult Index() { return View(); } [HttpPost] public ActionResult Index(int number) { number = number * 2; ViewData["id"] = number; return View(ViewData); } } } But nothing really happens. Yeah, I see the Post is being done, and the coded steps into public ActionResult Index(int number). I see that the number is taken from the textbox, it's multiplied correctly. I've tried using ViewData as you can see. I've also used TempData. This is another code for the textbox in the View I've tried: <%=Html.TextBox("number", ViewData["number"])%> But it doesn't matter. The textbox doesn't get updated with the new value. How can I do that?

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• PHP uploads file - enctype="multipart/form-data" issue

  - by user147685

  Hi all, I have this upload code. there are no problem running it individually, but when i try to add into my other codes, it did not get the $_files parameter. Im guessing it was becoz of enctype="multipart/form-data" in the form tag, based on this post: http://stackoverflow.com/questions/1695246/why-file-upload-didnt-work-without-enctype the enctype is needed. SO my problem is, how can i do upload files without concern to this? can we juz change the code structure so that it will be compatible with other codes? if($_POST['check']){ $faillampiran=$_POST['faillampiran']; $file=$_FILES['faillampiran']["name"]; $fileSize = $_FILES['faillampiran']['size']; $fileType = $_FILES['faillampiran']['type']; if ($_FILES["faillampiran"]["error"] > 0 ) { echo "Return Code: " . $_FILES["faillampiran"]["error"] . "<br />"; } else { move_uploaded_file($_FILES["faillampiran"]["tmp_name"],"upload/" . $_FILES["faillampiran"]["name"]); echo '<table align = "center">'; echo "<tr><td>"; echo "Your file has been successfully stored."; echo "</td></tr>"; echo '</table>'; } } ?> <form method="post" name="form1" id="form1" enctype="multipart/form-data"> <tr><td></td><td><input type="hidden" name="MAX_FILE_SIZE" value=""> </td> </tr> <tr><td> Please choose a file</td><td>:</td></tr> <tr> <input type="file" size="50" name="faillampiran" alt="faillampiran" id="faillampiran" 1value= "<?=$faillampiran;?>" /> <tr align = "center"><td colspan = "3"><input type="submit" value="Hantar" name="check"/></td></tr> </tr></form> thank you.

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• open,edit and save xml file with schema using php

  - by Neat

  Hy... I'm new in XML Schema, XSL,... (I have basic understanding) On web page: http://w3schools.com/xsl/xsl_editxml.asp is shown example for open,edit,save xml file, but with asp. Do anyone know how can i open/edit and save xml file using php for next example: <?xml version="1.0" encoding="ISO-8859-1"?> <tools> <tool id="1"> <field id="prodName"> <value>HAMMER HG2606</value> </field> <field id="prodNo"> <value>32456240</value> </field> <field id="price"> <value>$30.00</value> </field> </tool> <tool id="2"> <field id="prodName"> <value>Audi</value> </field> <field id="prodNo"> <value>88885</value> </field> <field id="price"> <value>$26.00</value> </field> </tool> </tools> and do i need <tool id="2"> or just <tool> is enough. Thanks very much on replay, and i don't need another xsl like shown on w3s, just fine is refresh submitted php file after submit (will do something with ajax after). I saw replay from Mr. Writman on questions/377632/add-update-and-edit-an-xml-file-with-php but that is for now 2 complex for me...:) is there any simpler answer (solution). Thanks in advance!!!

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• Asp.Net GridView

  - by user329419

  I need to hide columns in GridView Then access the values of these in the GridViewSelectedIndexChanged using vb.net. When I set DataBound columns is false cant acces the values. Please help. <asp:GridView ID="GridView1" runat="server" AllowPaging="True" AllowSorting="True" AutoGenerateColumns="False" BorderStyle="Outset" CellPadding="4" DataSourceID="odsA02_Tracking" Font-Size="Small" ForeColor="#333333" GridLines="Vertical" Style="border-right: #0000ff thin solid; table-layout: auto; border-top: #0000ff thin solid; font-size: x-small; border-left: #0000ff thin solid; border-bottom: #0000ff thin solid; font-family: Arial; border-collapse: separate" PageSize="30"> <FooterStyle BackColor="#507CD1" Font-Bold="True" ForeColor="White" /> <Columns> <asp:CommandField ShowSelectButton="True" /> <asp:BoundField DataField="Since" HeaderText="Submit Date" ReadOnly="True" SortExpression="Since" /> <asp:BoundField DataField="Started_By" HeaderText="Submitted By" SortExpression="Started_By" /> <asp:BoundField DataField="FullName" HeaderText="Client Name" ReadOnly="True" SortExpression="FullName" /> <asp:BoundField DataField="Product_Desc" HeaderText="Product" ReadOnly="True" SortExpression="Product_Desc" /> <asp:BoundField DataField="Branch_List" HeaderText="Branch" ReadOnly="True" SortExpression="Branch_List" /> <asp:BoundField DataField="Event_AssignedID" HeaderText="Assigned To" ReadOnly="True" SortExpression="Event_AssignedID" /> <asp:BoundField DataField="DaysElapsed" HeaderText="Days Open" ReadOnly="True" SortExpression="DaysElapsed" /> <asp:BoundField DataField="Status" HeaderText="Status" SortExpression="Status" /> <asp:BoundField DataField="Instance_ID" HeaderText="Instance_ID" SortExpression="Instance_ID" Visible=True /> <asp:TemplateField Visible=False> <ItemTemplate> <asp:HiddenField ID=hdnSeqID Value='<%#Eval("Seq_ID") %>' runat=server/> </ItemTemplate> </asp:TemplateField> <asp:TemplateField HeaderText="FormCode" Visible=false> <ItemTemplate> <asp:HiddenField ID=hdnFormCode Value='<%#Eval("Form_Code") %>' runat=server/> </ItemTemplate> </asp:TemplateField> </Columns> Protected Sub GridView1_SelectedIndexChanged(ByVal sender As Object, ByVal e As System.EventArgs) Handles GridView1.SelectedIndexChanged Dim Instance_ID As String Dim Seq_ID As String Dim Form_Code As String Dim PARMS As String Dim DestinationURL As String Dim DestinationParms As String 'fill text box's with values from selected row ' store values from selected row Dim seqID As String = CType(GridView1.SelectedRow.FindControl("hdnSeqID"), HiddenField).Value Dim formCode As String = CType(GridView1.SelectedRow.FindControl("hdnFormCode"), HiddenField).Value End Sub

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• Why always fires OnFailure when return View() to Ajax Form ?

  - by Wahid Bitar

  I'm trying to make a log-in log-off with Ajax supported. I made some logic in my controller to sign the user in and then return simple partial containing welcome message and log-Off ActionLink my Action method looks like this : public ActionResult LogOn(LogOnModel model, string returnUrl) { if (ModelState.IsValid) { if (MembershipService.ValidateUser(model.UserName, model.Password)) { FormsService.SignIn(model.UserName, model.RememberMe); if (Request.IsAjaxRequest()) { //HERE IS THE PROBLEM :( return View("LogedInForm"); } else { if (!String.IsNullOrEmpty(returnUrl)) return Redirect(returnUrl); else return RedirectToAction("Index", "Home"); } } else { ModelState.AddModelError("", "The user name or password provided is incorrect."); if (Request.IsAjaxRequest()) { return Content("There were an error !"); } } } return View(model); } and I'm trying to return this simple partial : Welcome <b><%= Html.Encode(Model.UserName)%></b>! <%= Html.ActionLink("Log Off", "LogOff", "Account") %> and of-course the two partial are strongly-typed to LogOnModel. But if i returned View("PartialName") i always get OnFailure with status code 500. While if i returned Content("My Message") everything is going right. so please tell me why i always get this "StatusCode = 500" ??. where is the big mistake ??. By the way in my Site MasterPage i rendered partial to show long-on simple form this partial looks like this : <script type="text/javascript"> function ShowErrorMessage(ajaxContext) { var response = ajaxContext.get_response(); var statusCode = response.get_statusCode(); alert("Sorry, the request failed with status code " + statusCode); } function ShowSuccessMessage() { alert("Hey everything is OK!"); } </script> <div id="logedInDiv"> </div> <% using (Ajax.BeginForm("LogOn", "Account", new AjaxOptions { UpdateTargetId = "logedInDiv", InsertionMode = InsertionMode.Replace, OnSuccess = "ShowSuccessMessage", OnFailure = "ShowErrorMessage" })) { %> <%= Html.TextBoxFor(m => m.UserName)%> <%= Html.PasswordFor(m => m.Password)%> <%= Html.CheckBoxFor(m => m.RememberMe)%> <input type="submit" value="Log On" /> < <% } %>

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• ASP.NET MVC 2 AJAX dilemma: Lose Models concept or create unmanageable JavaScript

  - by Slightly Frustrated

  Hi, Ok, let's assume we are working with ASP.NET MVC 2 (latest and greatest preview) and we want to create AJAX user interface with jQuery. So what are our real options here? Option 1 - Pass Json from the Controller to the view, and then the view submits Json back to the controller. This means (in the order given): User opens some View (let's say - /Invoices/January) which has to visualize a list of data (e.g. <IEnumerable<X.Y.Z.Models.Invoice>>) Controller retrieves the Model from the repository (assuming we are using repository pattern). Controller creates a new instance of a class which we will serialize to Json. The reasaon we do this, is because the model may not be serializable (circular reference ftl) Controller populates the soon-to-be-serialized class with data Controller serializes the class to Json and passes it the view. User does some change and submits the 'form' The View submits back Json to the controller The Controller now must 'manually' validate the input, because the Json passed does not bind to a Model See, if our View is communicating to the controller via Json, we lose the Model validation, which IMHO is incredible disadvantage. In this case, forget about data annotations and stuff. Option 2 - Ok, the alternative of the first approach is to pass the Models to the Views, which is the default behavior in the template when you start a new project. We pass a strong typed model to the view The view renders the appropriate html and javascript, sticking to the model property names. This is important! The user submits the form. If we stick to the model names, when we .serialize() the form and submit it to the controller it will map to a model. There is no Json mapping. The submitted form directly binds to a strongly typed model, hence, we can use the model validation. E.g. we keep the business logic where it should be. Problem with this approach is, if we refactor some of the Models (change property names, types, etc), the javascript we wrote would become invalid. We will have to manually refactor the scripting and hope we don't miss something. There is no way you can test it either. Ok, the question is - how to write an AJAX front end, which keeps the business logic validation in the model (e.g. controller passes and receives a Model type), but in the same time doesn't screw up the javascript and html when we refactor the model?

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• jQuery 1.4.2 and IE6: change event not firing first time using keyboard

  - by macca1

  I've done a good amount of research on this and found a bunch of reported problems and solutions but the general consensus seems that all change problems in IE6 were fixed in jQuery 1.4.2. I'm having an issue where a change event is not firing in jQuery 1.4.2, but it did fire successfully in jQuery 1.3.2. This is in IE6. I'm about to submit a bug for this, but for my sanity I wanted to post it here first to see if there's something dumb I'm missing. I don't understand why this is working this way... <HTML> <HEAD> <TITLE>jQuery 1.4.2 Problem </TITLE> <script src="jquery-1.4.2.min.js" type="text/javascript"></script> <script> $(document).ready( function() { $("#firstBox").change(function() { alert("CHANGE"); }); // ONLOAD of document autofocus into the first element... $("form").find(":input:visible:first").focus() }); </script> </HEAD> <BODY> <form> <select id="firstBox"> <option value="" selected="selected">--</option> <option value="1">One</option> <option value="2">Two</option> </select> <br><br> <input size="10" id="secondBox"> </form> </BODY> </HTML> Simple enough, right? Onload of the page, give the first element focus. Onchange of the first element, alert. If you use the mouse, it works as expected. The page loads, the focus is in the drop down, you change the option, you get the alert. The problem is if you use the keyboard. The page loads, the focus is in the drop down, you press the down arrow. The option changes. Tab off the field, no alert. Weird. To make it even weirder, if you tab back into the field and change it again (all using the keyboard), the change event DOES fire after tab out this time. Any ideas?

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• How do I use accepts_nested_attributes_for? I cannot use the .build method (!)

  - by Angela

  Editing my question for conciseness and to update what I've done: How do I model having multiple Addresses for a Company and assign a single Address to a Contact, and be able to assign them when creating or editing a Contact? Here is my model for Contacts: class Contact < ActiveRecord::Base attr_accessible :first_name, :last_name, :title, :phone, :fax, :email, :company, :date_entered, :campaign_id, :company_name, :address_id, :address_attributes belongs_to :company belongs_to :address accepts_nested_attributes_for :address end Here is my model for Address: class Address < ActiveRecord::Base attr_accessible :street1, :street2, :city, :state, :zip has_many :contacts end I would like, when creating an new contact, access all the Addresses that belong to the other Contacts that belong to the Company. So here is how I represent Company: class Company < ActiveRecord::Base attr_accessible :name, :phone, :addresses has_many :contacts has_many :addresses, :through => :contacts end Here is how I am trying to create a field in the View for _form for Contact so that, when someone creates a new Contact, they pass the address to the Address model and associate that address to the Contact: <% f.fields_for :address, @contact.address do |builder| %> <p> <%= builder.label :street1, "Street 1" %> </br> <%= builder.text_field :street1 %> <p> <% end %> When I try to Edit, the field for Street 1 is blank. And I don't know how to display the value from show.html.erb. At the bottom is my error console -- can't seem to create values in the address table: My Contacts controller is as follows: def new @contact = Contact.new @contact.address.build # I GET AN ERROR HERE: says NIL CLASS @contact.date_entered = Date.today @campaigns = Campaign.find(:all, :order => "name") if params[:campaign_id].blank? else @campaign = Campaign.find(params[:campaign_id]) @contact.campaign_id = @campaign.id end if params[:company_id].blank? else @company = Company.find(params[:company_id]) @contact.company_name = @company.name end end def create @contact = Contact.new(params[:contact]) if @contact.save flash[:notice] = "Successfully created contact." redirect_to @contact else render :action => 'new' end end def edit @contact = Contact.find(params[:id]) @campaigns = Campaign.find(:all, :order => "name") end Here is a snippet of my error console: I am POSTING the attribute, but it is not CREATING in the Address table.... Processing ContactsController#create (for 127.0.0.1 at 2010-05-12 21:16:17) [POST] Parameters: {"commit"="Submit", "authenticity_token"="d8/gx0zy0Vgg6ghfcbAYL0YtGjYIUC2b1aG+dDKjuSs=", "contact"={"company_name"="Allyforce", "title"="", "campaign_id"="2", "address_attributes"={"street1"="abc"}, "fax"="", "phone"="", "last_name"="", "date_entered"="2010-05-12", "email"="", "first_name"="abc"}} Company Load (0.0ms)[0m [0mSELECT * FROM "companies" WHERE ("companies"."name" = 'Allyforce') LIMIT 1[0m Address Create (16.0ms)[0m [0;1mINSERT INTO "addresses" ("city", "zip", "created_at", "street1", "updated_at", "street2", "state") VALUES(NULL, NULL, '2010-05-13 04:16:18', NULL, '2010-05-13 04:16:18', NULL, NULL)[0m Contact Create (0.0ms)[0m [0mINSERT INTO "contacts" ("company", "created_at", "title", "updated_at", "campaign_id", "address_id", "last_name", "phone", "fax", "company_id", "date_entered", "first_name", "email") VALUES(NULL, '2010-05-13 04:16:18', '', '2010-05-13 04:16:18', 2, 2, '', '', '', 5, '2010-05-12', 'abc', '')[0m

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• Where i am doing wrong in this?

  - by kumar

  <script type="text/javascript"> $(document).ready(function() { $('#PbtnSubmit').attr('disabled', 'disabled'); $('#PbtnCancel').attr('disabled', 'disabled'); $('#PbtnSelectAll').click(function() { $('#PricingEditExceptions input[type=checkbox]').attr('checked', 'checked'); $('#PbtnSubmit').removeAttr('disabled'); $('#PbtnCancel').removeAttr('disabled'); $('fieldset').find("input,select,textarea").removeAttr('disabled'); }); $('#PbtnCancel').click(function() { $('#PricingEditExceptions input[name=PMchk]').attr('checked', false); $('#PbtnSubmit').attr('disabled', 'disabled'); $('#PbtnCancel').attr('disabled', 'disabled'); $('fieldset').find("input:not(:checkbox),select,textarea").attr('disabled', 'disabled'); $('#genericfieldset').find("input,select,textarea").removeAttr('disabled'); }); $('#PbtnSubmit').click(function() { $('#PricingEditExceptions input[name=PMchk]').each(function() { if ($("#PricingEditExceptions input:checkbox:checked").length > 0) { var checked = $('#PricingEditExceptions input[type=checkbox]:checked'); var PMstrIDs = checked.map(function() { return $(this).val(); }).get().join(','); $('#1_exceptiontypes').attr('value', exceptiontypes) $('#1_PMstrIDs').attr('value', PMstrIDs); } else { alert("Please select atleast one exception"); return false; } }); }); function validate_excpt(formData, jqForm, options) { var form = jqForm[0]; } // post-submit callback function showResponse(responseText, statusText, xhr, $form) { if (responseText[0].substring(0, 16) != "System.Exception") { $('#error-msg-ID span:last').html('<strong>Update successful.</strong>'); } else { $('#error-msg-ID span:last').html('<strong>Update failed.</strong> ' + responseText[0].substring(0, 48)); } $('#error-msg-ID').removeClass('hide'); } $('#exc-').ajaxForm({ target: '#error-msg-ID', beforeSubmit: validate_excpt, success: showResponse, dataType: 'json' }); $('.button').button(); }); </script> This is my button.. at very first when page load I am trying Make Disabled PbtnSubmit and PbtnCancel and when we click PbtnSelectAll I am enabling back again.. but its not doing with this code. is that something I am doing worng in this? thanks

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• Performance tuning of a Hibernate+Spring+MySQL project operation that stores images uploaded by user

  - by Umar

  Hi I am working on a web project that is Spring+Hibernate+MySQL based. I am stuck at a point where I have to store images uploaded by a user into the database. Although I have written some code that works well for now, but I believe that things will mess up when the project would go live. Here's my domain class that carries the image bytes: @Entity public class Picture implements java.io.Serializable{ long id; byte[] data; ... // getters and setters } And here's my controller that saves the file on submit: public class PictureUploadFormController extends AbstractBaseFormController{ ... protected ModelAndView onSubmit(HttpServletRequest request, HttpServletResponse response, Object command, BindException errors) throws Exception{ MutlipartFile file; // getting MultipartFile from the command object ... // beginning hibernate transaction ... Picture p=new Picture(); p.setData(file.getBytes()); pictureDAO.makePersistent(p); // this method simply calls getSession().saveOrUpdate(p) // committing hiernate transaction ... } ... } Obviously a bad piece of code. Is there anyway I could use InputStream or Blob to save the data, instead of first loading all the bytes from the user into the memory and then pushing them into the database? I did some research on hibernate's support for Blob, and found this in Hibernate In Action book: java.sql.Blob and java.sql.Clob are the most efficient way to handle large objects in Java. Unfortunately, an instance of Blob or Clob is only useable until the JDBC transaction completes. So if your persistent class defines a property of java.sql.Clob or java.sql.Blob (not a good idea anyway), you’ll be restricted in how instances of the class may be used. In particular, you won’t be able to use instances of that class as detached objects. Furthermore, many JDBC drivers don’t feature working support for java.sql.Blob and java.sql.Clob. Therefore, it makes more sense to map large objects using the binary or text mapping type, assuming retrieval of the entire large object into memory isn’t a performance killer. Note you can find up-to-date design patterns and tips for large object usage on the Hibernate website, with tricks for particular platforms. Now apparently the Blob cannot be used, as it is not a good idea anyway, what else could be used to improve the performance? I couldn't find any up-to-date design pattern or any useful information on Hibernate website. So any help/recommendations from stackoverflowers will be much appreciated. Thanks

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• java spring and ftl

  - by bobby

  I defined a modelview object named "buttonpressed" in spring controller file and I need to access that modelview object in ftl(freemarker) file which is being returned as a view from a controller like abcd.java The abcd.java controller code is as below if (questionAnswer.getAnswerId() == 1045) { modelAndView.addObject("buttonPressed","You have been added in mailing list"); modelAndView.setViewName("enterCode_nextSteps"); } else { modelAndView.addObject("buttonPressed","Not added in the mailing list"); modelAndView.setViewName("enterCode_nextSteps"); } the below ajax function is working fine currently but I am not sure how to access this object called "buttonpressed" in this ajax function. I have written like the way mentioned below but when i am clicking the submit link its not calling "partner.do" and also throwing error saying #buttonPressed is undefind (but in the script below its working fine and calling "partner.do" and even posting data) So is that problem coming from javsscript code i mean due to incorrect use of "buttonPressed" or might be problem from spring controller abcd.java file. <div class="partnerOptInBox"> <div id="optInContent"> <form name="partnerOptIn"> <h4>Want the Latest</h4> <p class="pad10Top">${partnerOpt.translation}</p> <div class="pad10Top"> <input type="radio" name="questionAnswer['${partnerOpt.questionId}']" value="${partnerOpt.getAnswers()[0].answerId}" class="radioButton" /> <label for="questionAnswer['${partnerOpt.questionId}']" class="formLabel pad20Right">Yes</label> <input type="radio" name="questionAnswer['${partnerOpt.questionId}']" class="radioButton" value="${partnerOpt.getAnswers()[1].answerId}" /> <label for="questionAnswer['${partnerOpt.questionId}']" class="formLabel">No</label> </div> <div id="optInError" class="formError" style="display:none;">Oops... your request did not go through, please try again.</div> <div class="pad15Top"> <a href="javascript:submitOptIn();"><img src="images/theme/btn_opt_in_submit.gif"/></a> </div> </form> <script type="text/javascript"> function submitOptIn() { $('optInError').hide(); dataString = $('#partnerOptIn').serialize(); $.ajax({ data: dataString, url: "partnerOpt.do", timeout: 30000, type: "POST", success: function(html){ var newHtml = "<h4>Thank you</h4><p>We appreciate your time to respond to our request.</p>"; $('#optInContent').html(newHtml); }, */trying this code for sucess is throwing me an error /* <!-- buttonpressed function--> success: function(html){ $('#optInContent').html(${buttonPressed}); }, <!-- buttonpressed function--> error: function(){ $('#optInError').show(); } }); } </script>

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• Why is this simple file upload not working? JSF

  - by Nitesh Panchal

  Hello, Why is this code not working? I always get size() = 0, whenever i upload file. xhtml file :- <?xml version='1.0' encoding='UTF-8' ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xmlns:h="http://java.sun.com/jsf/html"> <h:head> <title>Abc</title> </h:head> <h:body> <center> <form method="post" enctype="multipart/form-data" id="form" action="/upload/uploadFile"> <input type="file"/> <br/> <input type="Submit" value="upload"/> </form> </center> </h:body> </html> This is my servlet :- package servlets; import java.io.IOException; import java.util.List; import java.util.logging.Level; import java.util.logging.Logger; import javax.servlet.ServletException; import javax.servlet.annotation.WebServlet; import javax.servlet.http.HttpServlet; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import org.apache.commons.fileupload.FileItem; import org.apache.commons.fileupload.FileUploadException; import org.apache.commons.fileupload.disk.DiskFileItemFactory; import org.apache.commons.fileupload.servlet.ServletFileUpload; @WebServlet(name="uploadFile", urlPatterns={"/uploadFile"}) public class uploadFile extends HttpServlet { protected void processRequest(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException, FileUploadException { System.out.println("executed!"); List<FileItem> items = new ServletFileUpload(new DiskFileItemFactory()).parseRequest(request); System.out.println(items.size()); for (FileItem item : items) { if (!item.isFormField()) { System.out.println("Name: " + item.getName()); System.out.println("Size: " + item.getSize()); System.out.println("Type: " + item.getContentType()); } } } @Override protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { try { processRequest(request, response); } catch (FileUploadException ex) { ex.printStackTrace(); } } @Override protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { try { processRequest(request, response); } catch (FileUploadException ex) { ex.printStackTrace(); } } @Override public String getServletInfo() { return "Short description"; } }

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• "Can't mass-assign protected attributes" with nested protected models

  - by JohnnyFive

  I'm having a hell of a time trying to get this nested model working. I've tried all manner of pluralization/singular, removing the attr_accessible altogether, and who knows what else. restaurant.rb: # == RESTAURANT MODEL # # Table name: restaurants # # id :integer not null, primary key # name :string(255) # created_at :datetime not null # updated_at :datetime not null # class Restaurant < ActiveRecord::Base attr_accessible :name, :job_attributes has_many :jobs has_many :users, :through => :jobs has_many :positions accepts_nested_attributes_for :jobs, :allow_destroy => true validates :name, presence: true end job.rb: # == JOB MODEL # # Table name: jobs # # id :integer not null, primary key # restaurant_id :integer # shortname :string(255) # user_id :integer # created_at :datetime not null # updated_at :datetime not null # class Job < ActiveRecord::Base attr_accessible :restaurant_id, :shortname, :user_id belongs_to :user belongs_to :restaurant has_many :shifts validates :name, presence: false end restaurants_controller.rb: class RestaurantsController < ApplicationController before_filter :logged_in, only: [:new_restaurant] def new @restaurant = Restaurant.new @user = current_user end def create @restaurant = Restaurant.new(params[:restaurant]) if @restaurant.save flash[:success] = "Restaurant created." redirect_to welcome_path end end end new.html.erb: <% provide(:title, 'Restaurant') %> <%= form_for @restaurant do |f| %> <%= render 'shared/error_messages' %> <%= f.label "Restaurant Name" %> <%= f.text_field :name %> <%= f.fields_for :job do |child_f| %> <%= child_f.label "Nickname" %> <%= child_f.text_field :shortname %> <% end %> <%= f.submit "Done", class: "btn btn-large btn-primary" %> <% end %> Output Parameters: {"utf8"=>"?", "authenticity_token"=>"DjYvwkJeUhO06ds7bqshHsctS1M/Dth08rLlP2yQ7O0=", "restaurant"=>{"name"=>"The Pink Door", "job"=>{"shortname"=>"PD"}}, "commit"=>"Done"} The error i'm receiving is: ActiveModel::MassAssignmentSecurity::Error in RestaurantsController#create Cant mass-assign protected attributes: job Rails.root: /home/johnnyfive/Dropbox/Projects/sa Application Trace | Framework Trace | Full Trace app/controllers/restaurants_controller.rb:11:in `new' app/controllers/restaurants_controller.rb:11:in `create' Anyone have ANY clue how to get this to work? Thanks!

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• Sanity Check: change event not firing first time using keyboard

  - by macca1

  I've done a good amount of research on this and found a bunch of reported problems and solutions but the general consensus seems that all change problems in IE6 were fixed in jQuery 1.4.2. I'm having an issue where a change event is not firing in jQuery 1.4.2, but it did fire successfully in jQuery 1.3.2. This is in IE6. I'm about to submit a bug for this, but for my sanity I wanted to post it here first to see if there's something dumb I'm missing. I don't understand why this is working this way... <HTML> <HEAD> <TITLE>jQuery 1.4.2 Problem </TITLE> <script src="jquery-1.4.2.min.js" type="text/javascript"></script> <script> $(document).ready( function() { $("#firstBox").change(function() { alert("CHANGE"); }); // ONLOAD of document autofocus into the first element... $("form").find(":input:visible:first").focus() }); </script> </HEAD> <BODY> <form> <select id="firstBox"> <option value="" selected="selected">--</option> <option value="1">One</option> <option value="2">Two</option> </select> <br><br> <input size="10" id="secondBox"> </form> </BODY> </HTML> Simple enough, right? Onload of the page, give the first element focus. Onchange of the first element, alert. If you use the mouse, it works as expected. The page loads, the focus is in the drop down, you change the option, you get the alert. The problem is if you use the keyboard. The page loads, the focus is in the drop down, you press the down arrow. The option changes. Tab off the field, no alert. Weird. To make it even weirder, if you tab back into the field and change it again (all using the keyboard), the change event DOES fire after tab out this time. Any ideas?

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• properies profile when writing word file

  - by avani-nature

  Hai frnds i am new to php i am having following problems in my coding... 1.Actually i am opening word document with com object and storing it in textarea. 2.when content gets opened in textarea i am editing that content and saving the document 3.actually when i edited that file and done save after that if i open word document then file properties-custom the old content getting removed i wannt to retain that even if i edited the word document..please do the needful i am using below code <?php $filename = 'C:/xampp/htdocs/mts/sites/default/files/a.doc'; //echo $filename; if(isset($_REQUEST['Save'])){ $somecontent = stripslashes($_POST['somecontent']); // Let's make sure the file exists and is writable first. if (is_writable($filename)) { // In our example we're opening $filename in append mode. // The file pointer is at the bottom of the file hence // that's where $somecontent will go when we fwrite() it. if (!$handle = fopen($filename, 'w')) { echo "Cannot open file ($filename)"; exit; } // Write $somecontent to our opened fi<form action="" method="get"></form>le. if (fwrite($handle, $somecontent) === FALSE) { echo "Cannot write to file ($filename)"; exit; } echo "Success, wrote ($somecontent) to file ($filename) <a href=".$_SERVER['PHP_SELF']."> - Continue - "; fclose($handle); } else { echo "The file $filename is not writable"; } } else{ // get contents of a file into a string $handle = fopen($filename, "r"); $somecontent = fread($handle, filesize($filename)); $word = new COM("word.application") or die ("Could not initialise MS Word object."); $word->Documents->Open(realpath("$filename")); // Extract content. $somecontent = (string) $word->ActiveDocument->Content; //echo $somecontent; $word->ActiveDocument->Close(false); $word->Quit(); $word = null; unset($word); fclose($handle); } ?> <h6>Edit file --------><? $filenam=explode("/",$filename);$filename=$filename[7]; echo $filename ;?></h6> <form name="form1" method="post" action=""> <p> <textarea name="somecontent" cols="100" rows="20"><? echo $somecontent ;?></textarea> </p> <div style='padding-left:250px;'><input type="submit" name="Save" value="Save"></div> </p> </form> <? } ?>

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