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  • Question about DispatcherUnhandledException

    - by Diego Pacheco
    The problem in this code is that when it's run and I push "Yes" button, This is shown: This means that my application stopped working, I just want it to end. private void App_DispatcherUnhandledException(object sender, DispatcherUnhandledExceptionEventArgs e) { string message = "An unhandled exception has ocurred, do you want close the app?"; MessageBoxResult currentMB = MessageBox.Show(message, "SomeTitleApp", MessageBoxButton.YesNo, MessageBoxImage.Exclamation); if (currentMB == MessageBoxResult.Yes) { Application.Current.Shutdown(); } else { e.Handled = true; } }

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  • How do I detect server status in a port scanner java implementation

    - by akz
    I am writing a port scanner in Java and I want to be able to distinct the following 4 use cases: port is open port is open and server banner was read port is closed server is not live I have the following code: InetAddress address = InetAddress.getByName("google.com"); int[] ports = new int[]{21, 22, 23, 80, 443}; for (int i = 0; i < ports.length; i++) { int port = ports[i]; Socket socket = null; try { socket = new Socket(address, port); socket.setSoTimeout(500); System.out.println("port " + port + " open"); BufferedReader reader = new BufferedReader( new InputStreamReader(socket.getInputStream())); String line = reader.readLine(); if (line != null) { System.out.println(line); } socket.close(); } catch (SocketTimeoutException ex) { // port was open but nothing was read from input stream ex.printStackTrace(); } catch (ConnectException ex) { // port is closed ex.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } finally { if (socket != null && !socket.isClosed()) { try { socket.close(); } catch (Exception e) { e.printStackTrace(); } } } } The problem is that I get a ConnectionException both when the port is closed and the server cannot be reached but with a different exception message: java.net.ConnectException: Connection timed out: connect when the connection was never established and java.net.ConnectException: Connection refused: connect when the port was closed so I cannot make the distinction between the two use cases without digging into the actual exception message. Same thing happens when I try a different approach for the socket creation. If I use: socket = new Socket(); socket.setSoTimeout(500); socket.connect(new InetSocketAddress(address, port), 1000); I have the same problem but with the SocketTimeoutException instead. I get a java.net.SocketTimeoutException: Read timed out if port was open but there was no banner to be read and java.net.SocketTimeoutException: connect timed out if server is not live or port is closed. Any ideas? Thanks in advance!

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  • I've caught an exception!! Now what?

    - by Jonesy
    Hi folks, I've started using try catch blocks (bit late i know!) but now im not sure what to do with the exception once i've caught it. What do people usually do here? -- Jonesy Try connection.Open() Dim sqlCmd As New SqlCommand("do some SQL", connection) Dim sqlDa As New SqlDataAdapter(sqlCmd) sqlDa.Fill(dt) Catch ex As SQLException ' ahhhh what to do now!!!? Finally connection.Close() End Try

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  • Hide command button on word doc

    - by d daly
    Hi I have a .doc with a command button (cmdStart) which opens a form. After populating the form I click a button to close the form and populate the .doc. I want to hide the initial cmdStart on the .doc as well when the form closes, Ive tries document.shapes(1).visible=false and cmdStart.visible=false but none seems to work. Any ideas? thanks (ps I cant just opne the form from the autonew, I need the cmdStart visible to begin with)

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  • Launch an app from within another (iPhone)

    - by Jeff
    Is it possible to launch any arbitrary iPhone application from within another app? For example in my application if I want the user to push a button and launch right into the Phone app (close the current app, open the Phone app), would this be possible? I know this can be done for making phone calls with the tel URL link, but I want to instead just have the Phone app launch without dialing any specific number.

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  • Why do my horizontal toolstrips keep stacking verticaly?

    - by Eric
    I'm using a ToolStripContainer that contains three ToolStrips. At design time I move the ToolStrips to the positions I want them in, which is in a horizontal row across the top of the form like this: I then close and save the Form. However, if I open the form up again the ToolStrips end up stacked up on the left side of the ToolStripContainer like this: How can I keep the ToolStrips in the positions that I specify?

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  • python and palindromes

    - by tekknolagi
    i recently wrote a method to cycle through /usr/share/dict/words and return a list of palindromes using my ispalindrome(x) method here's some of the code...what's wrong with it? it just stalls for 10 minutes and then returns a list of all the words in the file def reverse(a): return a[::-1] def ispalindrome(a): b = reverse(a) if b.lower() == a.lower(): return True else: return False wl = open('/usr/share/dict/words', 'r') wordlist = wl.readlines() wl.close() for x in wordlist: if not ispalindrome(x): wordlist.remove(x) print wordlist

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  • How can I make Emacs start-up faster?

    - by Colin
    I use Emacs v. 22 (the console version, either remotely with PuTTY or locally with Konsole) as my primary text editor on Linux. It takes a while to load up each time I start it though, probably almost a second, although I never timed it. I tend to open and close Emacs a lot, because I'm more comfortable using the Bash command-line for file/directory manipulation and compiling. How can I speed up the start-up time?

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  • plane bombing problems- help

    - by peiska
    I'm training code problems, and on this one I am having problems to solve it, can you give me some tips how to solve it please. The problem is something like this: Your task is to find the sequence of points on the map that the bomber is expected to travel such that it hits all vital links. A link from A to B is vital when its absence isolates completely A from B. In other words, the only way to go from A to B (or vice versa) is via that link. Notice that if we destroy for example link (d,e), it becomes impossible to go from d to e,m,l or n in any way. A vital link can be hit at any point that lies in its segment (e.g. a hit close to d is as valid as a hit close to e). Of course, only one hit is enough to neutralize a vital link. Moreover, each bomb affects an exact circle of radius R, i.e., every segment that intersects that circle is considered hit. Due to enemy counter-attack, the plane may have to retreat at any moment, so the plane should follow, at each moment, to the closest vital link possible, even if in the end the total distance grows larger. Given all coordinates (the initial position of the plane and the nodes in the map) and the range R, you have to determine the sequence of positions in which the plane has to drop bombs. This sequence should start (takeoff) and finish (landing) at the initial position. Except for the start and finish, all the other positions have to fall exactly in a segment of the map (i.e. it should correspond to a point in a non-hit vital link segment). The coordinate system used will be UTM (Universal Transverse Mercator) northing and easting, which basically corresponds to a Euclidian perspective of the world (X=Easting; Y=Northing). Input Each input file will start with three floating point numbers indicating the X0 and Y0 coordinates of the airport and the range R. The second line contains an integer, N, indicating the number of nodes in the road network graph. Then, the next N (<10000) lines will each contain a pair of floating point numbers indicating the Xi and Yi coordinates (1 No two links will ever cross with each other. Output The program will print the sequence of coordinates (pairs of floating point numbers with exactly one decimal place), each one at a line, in the order that the plane should visit (starting and ending in the airport). Sample input 1 102.3 553.9 0.2 14 342.2 832.5 596.2 638.5 479.7 991.3 720.4 874.8 744.3 1284.1 1294.6 924.2 1467.5 659.6 1802.6 659.6 1686.2 860.7 1548.6 1111.2 1834.4 1054.8 564.4 1442.8 850.1 1460.5 1294.6 1485.1 17 1 2 1 3 2 4 3 4 4 5 4 6 6 7 7 8 8 9 8 10 9 10 10 11 6 11 5 12 5 13 12 13 13 14 Sample output 1 102.3 553.9 720.4 874.8 850.1 1460.5 102.3 553.9

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  • How to upload a file into database by using Servlet?

    - by user1765496
    Hi all iam working on servlets, so i need to upload a file by using servlet as follows my code. package com.limrasoft.image.servlets; import java.io.*; import javax.servlet.*; import javax.servlet.http.*; import javax.servlet.annotation.*; import java.sql.*; @WebServlet(name="serv1",value="/s1") public class Account extends HttpServlet{ public void doPost(HttpServletRequest req,HttpServletResponse res)throws ServletException,IOException{ try{ Class.forName("oracle.jdbc.driver.OracleDriver"); Connecection con=null; try{ con=DriverManager.getConnection("jdbc:oracle:thin:@localhost:1521:xe","system","sajid"); PrintWriter pw=res.getWriter(); res.setContentType("text/html"); String s1=req.getParameter("un"); string s2=req.getParameter("pwd"); String s3=req.getParameter("g"); String s4=req.getParameter("uf"); PreparedStatement ps=con.prepareStatement("insert into account(?,?,?,?)"); ps.setString(1,s1); ps.setString(2,s2); ps.setString(3,s3); File file=new File("+s4+"); FileInputStream fis=new FileInputStream(fis); int len=(int)file.length(); ps.setBinaryStream(4,fis,len); int c=ps.executeUpdate(); if(c==0){pw.println("<h1>Registratin fail");} else{pw.println("<h1>Registration fail");} } finally{if(con!=null)con.close();} } catch(ClassNotFoundException ce){pw.println("<h1>Registration Fail");} catch(SQLException se){pw.println("<h1>Registration Fail");} pw.flush(); pw.close(); } } I have written the above code for file upload into database, but it giving error as "HTTP Status 500 - Servlet3.java (The system cannot find the file specified)" Could you plz help me to do this code,thanks in advanse.

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  • Silverlight penetration rate

    - by sthg
    Duplicate of: Silverlight Install Base - How big is it? Hi, Anyone knows the penetration rate (in %) for all North-American internet users with the Silverlight plugin installed? Been looking all around, but couldn't find any comprehensive numbers. I'm looking for General Public penetration rates, not only within the dev community. Something close to Adobe's flash version penetration stats would be great.

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  • String array definition in JAVA

    - by Mohamed KALLEL
    Is it possible to define array in this way in JAVA, otherwise are there an alternative close this definition? private final int CONST_0= 0; private final int CONST_1= 1; private final int CONST_2= 2; private final int CONST_3= 3; private final String[] CONST_TXTRECORDS = new String[] {[CONST_0] = "test0", {[CONST_1] = "test1", {[CONST_2] = "test2", {[CONST_3] = "test3"};

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  • How can I find the dimensions of a matrix in Python?

    - by PBD10017
    How can I find the dimensions of a matrix in Python. Len(A) returns only one variable. Edit: Hi Thanks. close = dataobj.get_data(timestamps, symbols, closefield) Is (I assume) generating a matrix of integers (less likely strings). I need to find the size of that matrix, so I can run some tests without having to iterate through all of the elements. As far as the data type goes, I assume it's an array of arrays (or list of lists).

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  • Is MobiForms for Android worth investigating ?

    - by Alan B
    I'm working my way through the NotePad tutorial, and that's all fine - I'm not a Java programmer but it's close enough to C# (or vice versa) to make it easy to pick up. I'm surprised that there aren't any RAD tools for Android apart from Mobiforms. Is there anyone out there with experience of Mobiforms ?

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  • What is the best way to download files via HTTP using .NET?

    - by Shamika
    In one of my application I'm using the WebClient class to download files from a web server. Depending on the web server sometimes the application download millions of documents. It seems to be when there are lot of documents, performance vise the WebClient doesn't scale up well. Also it seems to be the WebClient doesn't immediately close the connection it opened for the WebServer even after it successfully download the particular document. I would like to know what other alternatives I have.

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  • "document.body is null" is fixed now I get ".setStyle is not a function"

    - by rymarchant
    Hi All, I'm running into a similar problem as this: link text I've done the fix as in the answer but now I end up with an error a couple lines later: $$([overlay = (new Element("div", {id: "mbOverlay"})).addEvent("click", close), center = new Element("div", {id: "mbCenter"})]).setStyle is not a function [Break on this error] ]).setStyle("display", "none") It's on this page: link text When you click on 'showreel' it should pop up into the media box, but instead it just goes to a new page. Any help would be much appreciated. Thanks!

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  • How can I programmatically drop a Windows Mobile GPRS Connection?

    - by Rodriguez
    Hello, is there a way to explicitly close a GPRS connection? I'm setting up a connection with ConnectionManager and I've set the cache time to 10 seconds. Anyway after releasing it, the connection is still on, forever, alas I cannot use the registry key "gprs_by_if_device_off". I'm not using C# but plain C++. My idea is to simulate the activity of the windows button "disconnect data connection", but I really cannot understand what it does under the curtain. Thanx.

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  • Help me with this java program

    - by aser
    The question : Input file: customer’s account number, account balance at beginning of month, transaction type (withdrawal, deposit, interest), transaction amount Output: account number, beginning balance, ending balance, total interest paid, total amount deposited, number of deposits, total amount withdrawn, number of withdrawals package sentinel; import java.io.*; import java.util.*; public class Ex7 { /** * @param args the command line arguments */ public static void main(String[] args) throws FileNotFoundException { int AccountNum; double BeginningBalance; double TransactionAmount; int TransactionType; double AmountDeposited=0; int NumberOfDeposits=0; double InterestPaid=0.0; double AmountWithdrawn=0.0; int NumberOfWithdrawals=0; boolean found= false; Scanner inFile = new Scanner(new FileReader("Account.in")); PrintWriter outFile = new PrintWriter("Account.out"); AccountNum = inFile.nextInt(); BeginningBalance= inFile.nextDouble(); while (inFile.hasNext()) { TransactionAmount=inFile.nextDouble(); TransactionType=inFile.nextInt(); outFile.printf("Account Number: %d%n", AccountNum); outFile.printf("Beginning Balance: $%.2f %n",BeginningBalance); outFile.printf("Ending Balance: $%.2f %n",BeginningBalance); outFile.println(); switch (TransactionType) { case '1': // case 1 if we have a Deposite BeginningBalance = BeginningBalance + TransactionAmount; AmountDeposited = AmountDeposited + TransactionAmount; NumberOfDeposits++; outFile.printf("Amount Deposited: $%.2f %n",AmountDeposited); outFile.printf("Number of Deposits: %d%n",NumberOfDeposits); outFile.println(); break; case '2':// case 2 if we have an Interest BeginningBalance = BeginningBalance + TransactionAmount; InterestPaid = InterestPaid + TransactionAmount; outFile.printf("Interest Paid: $%.2f %n",InterestPaid); outFile.println(); break; case '3':// case 3 if we have a Withdraw BeginningBalance = BeginningBalance - TransactionAmount; AmountWithdrawn = AmountWithdrawn + TransactionAmount; NumberOfWithdrawals++; outFile.printf("Amount Withdrawn: $%.2f %n",AmountWithdrawn); outFile.printf("Number of Withdrawals: %d%n",NumberOfWithdrawals); outFile.println(); break; default: System.out.println("Invalid transaction Tybe: " + TransactionType + TransactionAmount); } } inFile.close(); outFile.close(); } } But is gives me this : Exception in thread "main" java.util.InputMismatchException at java.util.Scanner.throwFor(Scanner.java:840) at java.util.Scanner.next(Scanner.java:1461) at java.util.Scanner.nextInt(Scanner.java:2091) at java.util.Scanner.nextInt(Scanner.java:2050) at sentinel.Ex7.main(Ex7.java:36) Java Result: 1

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  • Speed up a web service for auto complete and avoid too many method calls.

    - by jphenow
    So I've got my jquery autocomplete 'working,' but its a little fidgety since I call the webservice method each time a keydown() fires so I get lots of methods hanging and sometimes to get the "auto" to work I have to type it out and backspace a bit because i'm assuming it got its return value a little slow. I've limited the query results to 8 to mininmize time. Is there anything i can do to make this a little snappier? This thing seems near useless if I don't get it a little more responsive. javascript $("#clientAutoNames").keydown(function () { $.ajax({ type: "POST", url: "WebService.asmx/LoadData", data: "{'input':" + JSON.stringify($("#clientAutoNames").val()) + "}", contentType: "application/json; charset=utf-8", dataType: "json", success: function (data) { if (data.d != null) { var serviceScript = data.d; } $("#autoNames").html(serviceScript); $('#clientAutoNames').autocomplete({ minLength: 2, source: autoNames, delay: 100, focus: function (event, ui) { $('#project').val(ui.item.label); return false; }, select: function (event, ui) { $('#clientAutoNames').val(ui.item.label); $('#projectid').val(ui.item.value); $('#project-description').html(ui.item.desc); pkey = $('#project-id').val; return false; } }) .data("autocomplete")._renderItem = function (ul, item) { return $("<li></li>") .data("item.autocomplete", item) .append("<a>" + item.label + "<br>" + item.desc + "</a>") .appendTo(ul); } } }); }); WebService.asmx <WebMethod()> _ Public Function LoadData(ByVal input As String) As String Dim result As String = "<script>var autoNames = [" Dim sqlOut As Data.SqlClient.SqlDataReader Dim connstring As String = *Datasource* Dim strSql As String = "SELECT TOP 2 * FROM v_Clients WHERE (SearchName Like '" + input + "%') ORDER BY SearchName" Dim cnn As Data.SqlClient.SqlConnection = New Data.SqlClient.SqlConnection(connstring) Dim cmd As Data.SqlClient.SqlCommand = New Data.SqlClient.SqlCommand(strSql, cnn) cnn.Open() sqlOut = cmd.ExecuteReader() Dim c As Integer = 0 While sqlOut.Read() result = result + "{" result = result + "value: '" + sqlOut("ContactID").ToString() + "'," result = result + "label: '" + sqlOut("SearchName").ToString() + "'," 'result = result + "desc: '" + title + " from " + company + "'," result = result + "}," End While result = result + "];</script>" sqlOut.Close() cnn.Close() Return result End Function I'm sure I'm just going about this slightly wrong or not doing a better balance of calls or something. Greatly appreciated!

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  • Unable to save file in python

    - by some1
    Trying to save files in python: g = open('~/ccna_pages/'+filename, 'w') g.write(page) g.close() Get this error: Traceback (most recent call last): File "dl-pages.py", line 50, in g = open('~/ccna_pages/'+filename, 'w') IOError: [Errno 2] No such file or directory: '~/ccna_pages/1.0.1.1.html' However, the directory does exist at that location. This syntax seems to be the what the python docs recommend.. http://docs.python.org/release/1.5/tut/node46.html What am I missing? Thanks..

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  • Facebook Connect from Localhost, doing some weird stuff

    - by Brett
    So maybe the documentation is out of date, or I am just off here. But I have done a slew of FB iframe apps (connect), but I am starting my first FB Connect site. Running it from localhost, and the Connect URL is http:// my_external_IP_address. When I click on the FB login button on my site, it pops up, says waiting for facebook, and it returns my site in that box, with the URL up top with the http:// mysite/?session={session key, user_id, etc.} The user_id is infact my FB id. And so it thinks I am logged in. If I close the popup, I'm not logged in. I'm not sure why the pop up isn't doing the normal fb connect dialog. I'm following these steps. (I added spaces to the http:// as to not be detected as 'spam') html xmlns="http://www.w3.org/1999/xhtml" xmlns:fb="http://www.facebook.com/2008/fbml" right after <body> <script src="http://static.ak.connect.facebook.com/js/api_lib/v0.4/FeatureLoader.js.php" type="text/javascript"> At the end, before the body close tag: script type="text/javascript"> FB.init("fbkey", "http://127.0.0.1/xd_receiver.htm"); I have tried using xd_receiver.htm, /xd_receiver.htm (and other combos), and that brings up a blank page. using the http://127.0.0.1 at least does something. In my config file, which is called before all of those, it checks for a PHP session key to see if they are logged in, if that doesn't exist it looks for a cookie, and if that doesn't exist it does this: require_once('includes/facebook.php'); $facebook = new Facebook($fbkey, $fbsec); $user_id = $facebook->get_loggedin_user(); if($user_id > 0){ $user = $ac->getUserFromFB($user_id); $_SESSION['user_id'] = $user['user_id']; } The user_id is always empty when I echo it out to the screen to test. The session event never occurs as well. So I don't know what it is doing in the popup, but I think Facebook thinks it is logging me in. Not sure. Pretty stumped on this one. Any help would be appreciated. Thanks!

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