Search Results

Search found 18661 results on 747 pages for 'linq to mysql'.

Page 192/747 | < Previous Page | 188 189 190 191 192 193 194 195 196 197 198 199  | Next Page >

  • Configured MySQL for SSL , but SLL is still not in use..!

    - by Sunrays
    I configured SSL for MySQL using the following script. #!/bin/bash # mkdir -p /root/abc/ssl_certs cd /root/abc/ssl_certs # echo "--> 1. Create CA cert, private key" openssl genrsa 2048 > ca-key.pem echo "--> 2. Create CA cert, certificate" openssl req -new -x509 -nodes -days 1000 -key ca-key.pem > ca-cert.pem echo "--> 3. Create Server certificate, key" openssl req -newkey rsa:2048 -days 1000 -nodes -keyout server-key.pem > server-req.pem echo "--> 4. Create Server certificate, cert" openssl x509 -req -in server-req.pem -days 1000 -CA ca-cert.pem -CAkey ca-key.pem -set_serial 01 > server-cert.pem echo "" echo echo "" echo "--> 5. Create client certificate, key. Use DIFFERENT common name then server!!!!" echo "" openssl req -newkey rsa:2048 -days 1000 -nodes -keyout client-key.pem > client-req.pem echo "6. Create client certificate, cert" openssl x509 -req -in client-req.pem -days 1000 -CA ca-cert.pem -CAkey ca-key.pem -set_serial 01 > client-cert.pem exit 0 The following files were created: ca-key.pem ca-cert.pem server-req.pem server-key.pem server-cert.pem client-req.pem client-key.pem client-cert.pem Then I combined server-cert.pem and client-cert.pem into ca.pem (I read in a post to do so..) I created a ssl user in MySQL: GRANT ALL ON *.* to sslsuer@hostname IDENTIFIED BY 'pwd' REQUIRE SSL; Next I added the following in my.cnf [mysqld] ssl-ca = /root/abc/ssl_certs/ca.pem ssl-cert = /root/abc/ssl_certs/server-cert.pem ssl-key = /root/abc/ssl_certs/server-key.pem After restarting the server,I connected to mysql but SSL was still not in use :( mysql -u ssluser -p SSL: Not in use Even the have_ssl parameter was still showing disabled.. :( mysql> show variables like '%ssl%'; +---------------+---------------------------------------------+ | Variable_name | Value | +---------------+---------------------------------------------+ | have_openssl | DISABLED | | have_ssl | DISABLED | | ssl_ca | /root/abc/ssl_certs/ca.pem | | ssl_capath | | | ssl_cert | /root/abc/ssl_certs/server-cert.pem | | ssl_cipher | | | ssl_key | /root/abc/ssl_certs/server-key.pem | +---------------+---------------------------------------------+ Have I missed any step, or whats wrong.. Answers with missed steps in detail will be highly appreciated..

    Read the article

  • connection to apache server switches sockets connection

    - by Newben
    I have just post a question but I post an other one because the problem is not the one I had in thought when asking the latter. So, I am running some rails app on osx, when I run rails s, everything works fine. If I shut down the apache server (mamp) and if I run rails s again, I have this message Can't connect to local MySQL server through socket '/Applications/MAMP/tmp/mysql/mysql.sock', which for sure is normal. For info, my mamp server is running, and the connection must pass through /Applications/MAMP/Library/bin/mysql, so I aliased it by setting in my bash profile : alias mysql="/Applications/MAMP/Library/bin/mysql" Now, when I launch a rails generate command type, I get this message : /$root/vendor/bundle/ruby/2.0.0/gems/mysql2-0.3.11/lib/mysql2/client.rb:44:in `connect': Can't connect to local MySQL server through socket '/tmp/mysql.sock' (2) (Mysql2::Error) So how it can be ?

    Read the article

  • How can give privilege for DB to a user [ ERROR 1044 (42000): Access denied for user ''@'localhost']

    - by Ahn
    I have created user in mysql 5.1 and given the ALL privilege, details given below, mysql> show GRANTS FOR test; +-------------------------------------------------------------+ | Grants for test@% | +-------------------------------------------------------------+ | GRANT ALL PRIVILEGES ON *.* TO 'test'@'%' WITH GRANT OPTION | | GRANT ALL PRIVILEGES ON `tt`.* TO 'test'@'%' | +-------------------------------------------------------------+ 2 rows in set (0.00 sec) But the show databases is not showing the databases on the mysql. It only shows as given below. How can give privilege for other DB s tables as well for the user 'test'? mysql> show databases; +--------------------+ | Database | +--------------------+ | information_schema | | test | +--------------------+ Error while I tried to use the mysql DB as user test: mysql> use mysql; ERROR 1044 (42000): Access denied for user ''@'localhost' to database 'mysql'

    Read the article

  • Trouble Starting MySL Community Server on Windows 7

    - by CodeAngel
    I have installed Netbeans 7 on my Windows 7. In addition, the MySQL Community Server 5.6.12 is installed with the MSI installer on thesame 7 PC. The MySQL server is integrated with the Netbeans IDE. However , it is not possible to start or stop the MySQL server from the command prompt or the Netbeans IDE. I am only able to start or stop the server from the Windows 7 services tool. Also , it is difficult running SQL queries from the Netbeans IDE even though it shows there is connection with the MySQL server. I have added the my.ini file to the installed directory of the MySQL server , that is : C:\Program Files\MySQL\MySQL Server 5.6 below is the my.ini file : # For advice on how to change settings please see # http://dev.mysql.com/doc/refman/5.6/en/server-configuration-defaults.html # *** DO NOT EDIT THIS FILE. It's a template which will be copied to the # *** default location during install, and will be replaced if you # *** upgrade to a newer version of MySQL. [mysqld] # Remove leading # and set to the amount of RAM for the most important data # cache in MySQL. Start at 70% of total RAM for dedicated server, else 10%. # innodb_buffer_pool_size = 128M # Remove leading # to turn on a very important data integrity option: logging # changes to the binary log between backups. # log_bin # These are commonly set, remove the # and set as required. # basedir = ..... # datadir = ..... port = 3306 # server_id = ..... # Remove leading # to set options mainly useful for reporting servers. # The server defaults are faster for transactions and fast SELECTs. # Adjust sizes as needed, experiment to find the optimal values. # join_buffer_size = 128M # sort_buffer_size = 2M # read_rnd_buffer_size = 2M sql_mode=NO_ENGINE_SUBSTITUTION,STRICT_TRANS_TABLES Any suggestion is welcomed.

    Read the article

  • MySQL - ODBC Data Connector

    - by Stuart Brierley
    Having previsouly installed and then configured MySQL, you may now need to install the ODBC Data Connector driver in order to connect to your MySQL database. Following the Splash screen the first thing to choose is the Setup Type for your installation.  As usual I chose custom so that I could see the components that were actually being installed.  In this case the custom set up screen allows you to choose to install the driver and the documentation. Finally you can complete the installation Assuming it completes okay you have now installed the MySQL ODBC driver. My intention for installing all these MySQL components is so that I can now attempt to get BizTalk 2009 talking to the MySQL database for a solution that I am currently working on.  For this I will next be looking at the Community ODBC Adapter.

    Read the article

  • How to install mysql?

    - by batman
    I tried mysql in my command line : I get : The program 'mysql' is currently not installed. You can install it by typing: sudo apt-get install mysql-client-core-5.5 But when I do: sudo apt-get install mysql-client-core-5.5 But I get: Reading package lists... Done Building dependency tree Reading state information... Done mysql-client-core-5.5 is already the newest version. 0 upgraded, 0 newly installed, 0 to remove and 47 not upgraded. I'm very much confused! Thanks in advance.

    Read the article

  • Webmatrix fails to connect PHP website to MySQL

    - by Roni
    I downloaded the latest versions of Webmatrix and MySQL. I downloaded a PHP-MySQL Connector: http://dev.mysql.com/downloads/connector/php-mysqlnd/ In the "Databases" Workspace I pressed "New Connection" button and choose "MySQL Connection" In the Dialog box I filled-in all connection details -- It looks like the database was added. But then when I double-click on the database, I get a short error message saying it cannot connect. I tried everything, searched the web... I'm sure it's a very simple question, so please whoever can help I'll be grateful. I think best solution for me would be if someone could please just give me a link to download of: Webmatrix,MySQL,Connector; and instructions on how to install and then how to connect. This would be the safest way to help me.

    Read the article

  • MySQL User Group Meeting in Madrid, Spain

    - by Lenka Kasparova
    We are pleased to announce another MySQL User Group meeting scheduled for June 5 in Madrid, Spain. Keith Hollman, the MySQL Principal Sales Consultant will be talking about MySQL & Oracle strategy and MySQL Cluster. A small demo of MySQL Cluster will be part of the presentation.  Details about the event: Date: June 5, 2014 Time: 7:00 pm-8:30 pm Place: Edificio Telefonica, Gran via 28, Madrid, Entrada por C/ Valverde 2 We are looking forward to seeing you in Madrid! See more information & registration.

    Read the article

  • MySQL Query performance - huge difference in time

    - by Damo
    I have a query that is returning in vastly different amounts of time between 2 datasets. For one set (database A) it returns in a few seconds, for the other (database B)....well I haven't waited long enough yet, but over 10 minutes. I have dumped both of these databases to my local machine where I can reproduce the issue running MySQL 5.1.37. Curiously, database B is smaller than database A. A stripped down version of the query that reproduces the problem is: SELECT * FROM po_shipment ps JOIN po_shipment_item psi USING (ship_id) JOIN po_alloc pa ON ps.ship_id = pa.ship_id AND pa.UID_items = psi.UID_items JOIN po_header ph ON pa.hdr_id = ph.hdr_id LEFT JOIN EVENT_TABLE ev0 ON ev0.TABLE_ID1 = ps.ship_id AND ev0.EVENT_TYPE = 'MAS0' LEFT JOIN EVENT_TABLE ev1 ON ev1.TABLE_ID1 = ps.ship_id AND ev1.EVENT_TYPE = 'MAS1' LEFT JOIN EVENT_TABLE ev2 ON ev2.TABLE_ID1 = ps.ship_id AND ev2.EVENT_TYPE = 'MAS2' LEFT JOIN EVENT_TABLE ev3 ON ev3.TABLE_ID1 = ps.ship_id AND ev3.EVENT_TYPE = 'MAS3' LEFT JOIN EVENT_TABLE ev4 ON ev4.TABLE_ID1 = ps.ship_id AND ev4.EVENT_TYPE = 'MAS4' LEFT JOIN EVENT_TABLE ev5 ON ev5.TABLE_ID1 = ps.ship_id AND ev5.EVENT_TYPE = 'MAS5' WHERE ps.eta >= '2010-03-22' GROUP BY ps.ship_id LIMIT 100; The EXPLAIN query plan for the first database (A) that returns in ~2 seconds is: +----+-------------+-------+--------+----------------------------------------------------------------------------------------------------------------------------------------+----------------------------------+---------+------------------------------+------+----------------------------------------------+ | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra | +----+-------------+-------+--------+----------------------------------------------------------------------------------------------------------------------------------------+----------------------------------+---------+------------------------------+------+----------------------------------------------+ | 1 | SIMPLE | ps | range | PRIMARY,IX_ETA_DATE | IX_ETA_DATE | 4 | NULL | 174 | Using where; Using temporary; Using filesort | | 1 | SIMPLE | ev0 | ref | IX_EVENT_ID_EVENT_TYPE | IX_EVENT_ID_EVENT_TYPE | 36 | UNIVIS_PROD.ps.ship_id,const | 1 | | | 1 | SIMPLE | ev1 | ref | IX_EVENT_ID_EVENT_TYPE | IX_EVENT_ID_EVENT_TYPE | 36 | UNIVIS_PROD.ps.ship_id,const | 1 | | | 1 | SIMPLE | ev2 | ref | IX_EVENT_ID_EVENT_TYPE | IX_EVENT_ID_EVENT_TYPE | 36 | UNIVIS_PROD.ps.ship_id,const | 1 | | | 1 | SIMPLE | ev3 | ref | IX_EVENT_ID_EVENT_TYPE | IX_EVENT_ID_EVENT_TYPE | 36 | UNIVIS_PROD.ps.ship_id,const | 1 | | | 1 | SIMPLE | ev4 | ref | IX_EVENT_ID_EVENT_TYPE | IX_EVENT_ID_EVENT_TYPE | 36 | UNIVIS_PROD.ps.ship_id,const | 1 | | | 1 | SIMPLE | ev5 | ref | IX_EVENT_ID_EVENT_TYPE | IX_EVENT_ID_EVENT_TYPE | 36 | UNIVIS_PROD.ps.ship_id,const | 1 | | | 1 | SIMPLE | psi | ref | PRIMARY,IX_po_shipment_item_po_shipment1,FK_po_shipment_item_po_shipment1 | IX_po_shipment_item_po_shipment1 | 4 | UNIVIS_PROD.ps.ship_id | 1 | | | 1 | SIMPLE | pa | ref | IX_po_alloc_po_shipment_item2,IX_po_alloc_po_details_old,FK_po_alloc_po_shipment1,FK_po_alloc_po_shipment_item1,FK_po_alloc_po_header1 | FK_po_alloc_po_shipment1 | 4 | UNIVIS_PROD.psi.ship_id | 5 | Using where | | 1 | SIMPLE | ph | eq_ref | PRIMARY,IX_HDR_ID | PRIMARY | 4 | UNIVIS_PROD.pa.hdr_id | 1 | | +----+-------------+-------+--------+----------------------------------------------------------------------------------------------------------------------------------------+----------------------------------+---------+------------------------------+------+----------------------------------------------+ The EXPLAIN query plan for the second database (B) that returns in 600 seconds is: +----+-------------+-------+--------+----------------------------------------------------------------------------------------------------------------------------------------+----------------------------------+---------+--------------------------------+------+----------------------------------------------+ | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra | +----+-------------+-------+--------+----------------------------------------------------------------------------------------------------------------------------------------+----------------------------------+---------+--------------------------------+------+----------------------------------------------+ | 1 | SIMPLE | ps | range | PRIMARY,IX_ETA_DATE | IX_ETA_DATE | 4 | NULL | 38 | Using where; Using temporary; Using filesort | | 1 | SIMPLE | psi | ref | PRIMARY,IX_po_shipment_item_po_shipment1,FK_po_shipment_item_po_shipment1 | IX_po_shipment_item_po_shipment1 | 4 | UNIVIS_DEV01.ps.ship_id | 1 | | | 1 | SIMPLE | ev0 | ref | IX_EVENT_ID_EVENT_TYPE | IX_EVENT_ID_EVENT_TYPE | 36 | UNIVIS_DEV01.psi.ship_id,const | 1 | | | 1 | SIMPLE | ev1 | ref | IX_EVENT_ID_EVENT_TYPE | IX_EVENT_ID_EVENT_TYPE | 36 | UNIVIS_DEV01.psi.ship_id,const | 1 | | | 1 | SIMPLE | ev2 | ref | IX_EVENT_ID_EVENT_TYPE | IX_EVENT_ID_EVENT_TYPE | 36 | UNIVIS_DEV01.ps.ship_id,const | 1 | | | 1 | SIMPLE | ev3 | ref | IX_EVENT_ID_EVENT_TYPE | IX_EVENT_ID_EVENT_TYPE | 36 | UNIVIS_DEV01.psi.ship_id,const | 1 | | | 1 | SIMPLE | ev4 | ref | IX_EVENT_ID_EVENT_TYPE | IX_EVENT_ID_EVENT_TYPE | 36 | UNIVIS_DEV01.psi.ship_id,const | 1 | | | 1 | SIMPLE | ev5 | ref | IX_EVENT_ID_EVENT_TYPE | IX_EVENT_ID_EVENT_TYPE | 36 | UNIVIS_DEV01.ps.ship_id,const | 1 | | | 1 | SIMPLE | pa | ref | IX_po_alloc_po_shipment_item2,IX_po_alloc_po_details_old,FK_po_alloc_po_shipment1,FK_po_alloc_po_shipment_item1,FK_po_alloc_po_header1 | IX_po_alloc_po_shipment_item2 | 4 | UNIVIS_DEV01.ps.ship_id | 4 | Using where | | 1 | SIMPLE | ph | eq_ref | PRIMARY,IX_HDR_ID | PRIMARY | 4 | UNIVIS_DEV01.pa.hdr_id | 1 | | +----+-------------+-------+--------+----------------------------------------------------------------------------------------------------------------------------------------+----------------------------------+---------+--------------------------------+------+----------------------------------------------+ When database B is running I can look at the MySQL Administrator and the state remains at "Copying to tmp table" indefinitely. Database A also has this state but for only a second or so. There are no differences in the table structure, indexes, keys etc between these databases (I have done show create tables and diff'd them). The sizes of the tables are: database A: po_shipment 1776 po_shipment_item 1945 po_alloc 36298 po_header 71642 EVENT_TABLE 1608 database B: po_shipment 463 po_shipment_item 470 po_alloc 3291 po_header 56149 EVENT_TABLE 1089 Some points to note: Removing the WHERE clause makes the query return < 1 sec. Removing the GROUP BY makes the query return < 1 sec. Removing ev5, ev4, ev3 etc makes the query get faster for each one removed. Can anyone suggest how to resolve this issue? What have I missed? Many Thanks.

    Read the article

  • MySQL "ERROR 1005 (HY000): Can't create table 'foo.#sql-12c_4' (errno: 150)"

    - by Ankur Banerjee
    Hi, I was working on creating some tables in database foo, but every time I end up with errno 150 regarding the foreign key. Firstly, here's my code for creating tables: CREATE TABLE Clients ( client_id CHAR(10) NOT NULL , client_name CHAR(50) NOT NULL , provisional_license_num CHAR(50) NOT NULL , client_address CHAR(50) NULL , client_city CHAR(50) NULL , client_county CHAR(50) NULL , client_zip CHAR(10) NULL , client_phone INT NULL , client_email CHAR(255) NULL , client_dob DATETIME NULL , test_attempts INT NULL ); CREATE TABLE Applications ( application_id CHAR(10) NOT NULL , office_id INT NOT NULL , client_id CHAR(10) NOT NULL , instructor_id CHAR(10) NOT NULL , car_id CHAR(10) NOT NULL , application_date DATETIME NULL ); CREATE TABLE Instructors ( instructor_id CHAR(10) NOT NULL , office_id INT NOT NULL , instructor_name CHAR(50) NOT NULL , instructor_address CHAR(50) NULL , instructor_city CHAR(50) NULL , instructor_county CHAR(50) NULL , instructor_zip CHAR(10) NULL , instructor_phone INT NULL , instructor_email CHAR(255) NULL , instructor_dob DATETIME NULL , lessons_given INT NULL ); CREATE TABLE Cars ( car_id CHAR(10) NOT NULL , office_id INT NOT NULL , engine_serial_num CHAR(10) NULL , registration_num CHAR(10) NULL , car_make CHAR(50) NULL , car_model CHAR(50) NULL ); CREATE TABLE Offices ( office_id INT NOT NULL , office_address CHAR(50) NULL , office_city CHAR(50) NULL , office_County CHAR(50) NULL , office_zip CHAR(10) NULL , office_phone INT NULL , office_email CHAR(255) NULL ); CREATE TABLE Lessons ( lesson_num INT NOT NULL , client_id CHAR(10) NOT NULL , date DATETIME NOT NULL , time DATETIME NOT NULL , milegage_used DECIMAL(5, 2) NULL , progress CHAR(50) NULL ); CREATE TABLE DrivingTests ( test_num INT NOT NULL , client_id CHAR(10) NOT NULL , test_date DATETIME NOT NULL , seat_num INT NOT NULL , score INT NULL , test_notes CHAR(255) NULL ); ALTER TABLE Clients ADD PRIMARY KEY (client_id); ALTER TABLE Applications ADD PRIMARY KEY (application_id); ALTER TABLE Instructors ADD PRIMARY KEY (instructor_id); ALTER TABLE Offices ADD PRIMARY KEY (office_id); ALTER TABLE Lessons ADD PRIMARY KEY (lesson_num); ALTER TABLE DrivingTests ADD PRIMARY KEY (test_num); ALTER TABLE Applications ADD CONSTRAINT FK_Applications_Offices FOREIGN KEY (office_id) REFERENCES Offices (office_id); ALTER TABLE Applications ADD CONSTRAINT FK_Applications_Clients FOREIGN KEY (client_id) REFERENCES Clients (client_id); ALTER TABLE Applications ADD CONSTRAINT FK_Applications_Instructors FOREIGN KEY (instructor_id) REFERENCES Instructors (instructor_id); ALTER TABLE Applications ADD CONSTRAINT FK_Applications_Cars FOREIGN KEY (car_id) REFERENCES Cars (car_id); ALTER TABLE Lessons ADD CONSTRAINT FK_Lessons_Clients FOREIGN KEY (client_id) REFERENCES Clients (client_id); ALTER TABLE Cars ADD CONSTRAINT FK_Cars_Offices FOREIGN KEY (office_id) REFERENCES Offices (office_id); ALTER TABLE Clients ADD CONSTRAINT FK_DrivingTests_Clients FOREIGN KEY (client_id) REFERENCES Clients (client_id); These are the errors that I get: mysql> ALTER TABLE Applications ADD CONSTRAINT FK_Applications_Cars FOREIGN KEY (car_id) REFERENCES Cars (car_id); ERROR 1005 (HY000): Can't create table 'foo.#sql-12c_4' (errno: 150) I ran SHOW ENGINE INNODB STATUS which gives a more detailed error description: ------------------------ LATEST FOREIGN KEY ERROR ------------------------ 100509 20:59:49 Error in foreign key constraint of table practice9/#sql-12c_4: FOREIGN KEY (car_id) REFERENCES Cars (car_id): Cannot find an index in the referenced table where the referenced columns appear as the first columns, or column types in the table and the referenced table do not match for constraint. Note that the internal storage type of ENUM and SET changed in tables created with >= InnoDB-4.1.12, and such columns in old tables cannot be referenced by such columns in new tables. See http://dev.mysql.com/doc/refman/5.1/en/innodb-foreign-key-constraints.html for correct foreign key definition. ------------ I searched around on StackOverflow and elsewhere online - came across a helpful blog post here with pointers on how to resolve this error - but I can't figure out what's going wrong. Any help would be appreciated!

    Read the article

  • Changing html <-> ajax <-> php/mysql to threaded approach

    - by Saif Bechan
    I have an application that needs to be updated real-time. There are various counters and other information that have to come from the database and the system needs to be up to date for the user. My approach now is just a normal ajax request every second to get the new values from the database. There is a JavaScript which loops every second getting the values trough ajax. This works fine but I think its very inefficient. The problem There is an ajax script that loops every second requesting data from php # On the server it has to load the PHP interpeter The PHP file has to get the data and format it correctly # PHP has to make a connection with the mysql database Work with the database(reads,never writes) Format the data so it can be send Send the data back to the browser # Close the database connection, and close the php interpeter Last the browser has to read these values and update the various html parts Now with this approach it has to load the interpreter and make a db connection every second. I was thinking of a way to make this more efficient, and maybe use a threaded approach to this. Threaded aprouch Do a post to the PHP when you enter the page and keep the connection alive In PHP only load the interpreter once, and make a connection to the DB ones Every second send an ajax response to the javascript listener The javascript listener than just changes values as the response from php arrives. I think this approach will be a great optimization to the server load and overall performance. But I can spot some weak point in the system and i need some help with these. Problems with the approach PHP execution time limit I don't think PHP is designed for such a setup. I know there is a time limit on php script execution. I don't know if an everlasting loop in PHP will cause any serious cpu/memory problems. Sending ajax request without breaking I don't know if it is possible to have just one ajax post action and have open and accepting data. user exists the page What will happen when the user exists the page and the PHP script is still going. Will it go on forever. security issues so far i can't think of any security issues. Almost every setup you use have some security issues. Maybe there are some with this solution I do not know of. Open to other solution I really want to change the setup as it is now and move to a threaded approach or better. If someone has a better approach to tackle this I definitely want to hear that. Maybe the usage of some other scripts is better suited for having an ongoing runtime. I only know php and java so any suggestions are welcome and I am willing to dig trough. I know there are things like perl, python etcetera that are used for this type of threaded but i don't know which one is best suited. When using other script If the best way is to go with other type of script like perl,python etcetera I do have some critera. The script has to be accessible via ajax post If it accepts some kind of json encode/decode it would be nice The script has to be able to access the session file This is essential because I need to know if the user is logged in The script has to be able to easily talk to MySQL All comments are welcome, and I hope this question is helpful to other also. Cheers!

    Read the article

  • How to select all options from a drop list in php / mysql

    - by Mirage81
    Thanks to stackoverflow.com's frienly experts I've managed to create my first php + mysql application. The code searches a mysql database for last names and cities. The choices are made through two drop lists like these: Choose city: All cities Liverpool Manchester Choose last name: All last names Lennon Gallagher The code would return eg. all the Lennons living in Liverpool. However, I haven't been able to make the options "All cities" and "All last names" to work so that the code would return eg. all the Lennons living in any city or all the people living in Liverpool. So, how can that be done? The code so far: index.php <?php $conn = mysql_connect('localhost', 'user', 'password') or die("Connection failed"); mysql_select_db("database", $conn) or die("Switch database failed"); //this gets the cities from the database to the drop list $query = "SELECT DISTINCT city FROM user".mysql_real_escape_string($city); $result = mysql_query($query, $conn); $options=""; while ($row=mysql_fetch_array($result)) { $city=$row["city"]; $options.="<OPTION VALUE=\"$city\">".$city; } //this gets the last names from the database to the drop list $query2 = "SELECT DISTINCT lastname FROM user".mysql_real_escape_string($lastname); $result2 = mysql_query($query2, $conn); $options2=""; while ($row2=mysql_fetch_array($result2)) { $lastname=$row2["lastname"]; $options2.="<OPTION VALUE=\"$lastname\">".$lastname; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"> <html> <head> <meta content="text/html; charset=ISO-8859-1" http-equiv="content-type"> <title>test</title> </head> <body> <form action="get.php" method="post"> <p> <select name="city"> <option value=0>Choose <option value=1>All cities <?=$options?> </select> </p> <p> <select name="lastname"> <option value=0>Choose <option value=1>All last names <?=$options2?> </select> </p> <p> <input value="Search" type="submit"> </p> </form> <br> </body> </html> get.php <?php $conn = mysql_connect('localhost', 'user', 'password') or die("Connection failed"); mysql_select_db("database", $conn) or die("Switch database failed"); $query = "SELECT * FROM user WHERE city = '".mysql_real_escape_string($_POST['city'])."' AND lastname = '".mysql_real_escape_string($_POST['lastname'])."'"; $result = mysql_query($query, $conn); echo $rowcount; $zerorows=true; while ($row = mysql_fetch_assoc($result)) { $zerorows=false; echo '<b>City: </b>'.htmlspecialchars($row[city]).'<br />'; echo '<b>Last name: </b>'.htmlspecialchars($row[lastname]).'<br />'; echo '<b>Information: </b>'.htmlspecialchars($row[information]).'<br />'.'<br />'; } if($zerorows) echo "No results"; mysql_close($conn); ?>

    Read the article

  • MySQL and INT auto_increment fields

    - by PHPguy
    Hello folks, I'm developing in LAMP (Linux+Apache+MySQL+PHP) since I remember myself. But one question was bugging me for years now. I hope you can help me to find an answer and point me into the right direction. Here is my challenge: Say, we are creating a community website, where we allow our users to register. The MySQL table where we store all users would look then like this: CREATE TABLE `users` ( `uid` int(2) unsigned NOT NULL auto_increment COMMENT 'User ID', `name` varchar(20) NOT NULL, `password` varchar(32) NOT NULL COMMENT 'Password is saved as a 32-bytes hash, never in plain text', `email` varchar(64) NOT NULL, `created` int(11) unsigned NOT NULL default '0' COMMENT 'Timestamp of registration', `updated` int(11) unsigned NOT NULL default '0' COMMENT 'Timestamp of profile update, e.g. change of email', PRIMARY KEY (`uid`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8; So, from this snippet you can see that we have a unique and automatically incrementing for every new user 'uid' field. As on every good and loyal community website we need to provide users with possibility to completely delete their profile if they want to cancel their participation in our community. Here comes my problem. Let's say we have 3 registered users: Alice (uid = 1), Bob (uid = 2) and Chris (uid = 3). Now Bob want to delete his profile and stop using our community. If we delete Bob's profile from the 'users' table then his missing 'uid' will create a gap which will be never filled again. In my opinion it's a huge waste of uid's. I see 3 possible solutions here: 1) Increase the capacity of the 'uid' field in our table from SMALLINT (int(2)) to, for example, BIGINT (int(8)) and ignore the fact that some of the uid's will be wasted. 2) introduce the new field 'is_deleted', which will be used to mark deleted profiles (but keep them in the table, instead of deleting them) to re-utilize their uid's for newly registered users. The table will look then like this: CREATE TABLE `users` ( `uid` int(2) unsigned NOT NULL auto_increment COMMENT 'User ID', `name` varchar(20) NOT NULL, `password` varchar(32) NOT NULL COMMENT 'Password is saved as a 32-bytes hash, never in plain text', `email` varchar(64) NOT NULL, `is_deleted` int(1) unsigned NOT NULL default '0' COMMENT 'If equal to "1" then the profile has been deleted and will be re-used for new registrations', `created` int(11) unsigned NOT NULL default '0' COMMENT 'Timestamp of registration', `updated` int(11) unsigned NOT NULL default '0' COMMENT 'Timestamp of profile update, e.g. change of email', PRIMARY KEY (`uid`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8; 3) Write a script to shift all following user records once a previous record has been deleted. E.g. in our case when Bob (uid = 2) decides to remove his profile, we would replace his record with the record of Chris (uid = 3), so that uid of Chris becomes qual to 2 and mark (is_deleted = '1') the old record of Chris as vacant for the new users. In this case we keep the chronological order of uid's according to the registration time, so that the older users have lower uid's. Please, advice me now which way is the right way to handle the gaps in the auto_increment fields. This is just one example with users, but such cases occur very often in my programming experience. Thanks in advance!

    Read the article

  • mysql to excel exporting data using php getting html code also

    - by pmms
    hi all following is code for getting xlsheet from mysql using php ` if( ($_POST['Submit']=='generateexcel')) { $tblname=$_GET['generateexcel']; global $obj_mysql; $table="tbl_js_login"; // this is the tablename that you want to export to csv from mysql. function exportMysqlToCsv($table,$filename = 'export.csv') { $csv_terminated = "\n"; $csv_separator = ","; $csv_enclosed = '"'; $csv_escaped = "\"; $sql_query = "select fld_id, fld_fname,fld_lname from $table"; // Gets the data from the database $result = mysql_query($sql_query); $fields_cnt = mysql_num_fields($result); $schema_insert = ''; for ($i = 0; $i < $fields_cnt; $i++) { $l = $csv_enclosed . str_replace($csv_enclosed, $csv_escaped . $csv_enclosed, stripslashes(mysql_field_name($result, $i))) . $csv_enclosed; $schema_insert .= $l; $schema_insert .= $csv_separator; } // end for $out = trim(substr($schema_insert, 0, -1)); $out .= $csv_terminated; // Format the data while ($row = mysql_fetch_array($result)) { $schema_insert = ''; for ($j = 0; $j < $fields_cnt; $j++) { if ($row[$j] == '0' || $row[$j] != '') { if ($csv_enclosed == '') { $schema_insert .= $row[$j]; } else { $schema_insert .= $csv_enclosed . str_replace($csv_enclosed, $csv_escaped . $csv_enclosed, $row[$j]) . $csv_enclosed; } } else { $schema_insert .= ''; } if ($j < $fields_cnt - 1) { $schema_insert .= $csv_separator; } } // end for $out .= $schema_insert; $out .= $csv_terminated; $out1 = strip_tags($out); } // end while header("Cache-Control: must-revalidate, post-check=0, pre-check=0"); header("Content-Length: " . strlen($out1)); // Output to browser with appropriate mime type, you choose ;) header("Content-type: text/x-csv"); //header("Content-type: text/csv"); //header("Content-type: application/csv"); header("Content-Disposition: attachment; filename=$filename"); echo $out1; exit; } exportMysqlToCsv($table); } include_once $path."includes/jobseeker_form.php"; /* function is_duplicate($login_name) { global $obj_mysql; $sql="SELECT * FROM tbl_admin_details WHERE fld_login ='$login_name'"; $num=$obj_mysql-get_num_rows($sql); if($num==0) return false; else return true; }*/ ?` the above code we are using for genrating the xlsheet along with xlsheet we are getting html at th top . following is the screen shot of xlsheet please provide some help how to remove the html code from xlsheet

    Read the article

  • Script to create a table and fields in SQL wont work

    - by Jacksta
    Warning this is lenghty! attack if you knowledagble. well at least more then a newb beginner like me. This script uses three files as detailed below. It is suppoed to create the database and fields from the form input. It gets to the end and shows my_contacts has been created!. But when i go into phpMyadmin the table has not been created. I have a file named show_createtable.html which is used to create a table in MySQL <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> <h1>Step 1: Name and Number</h1> <form method="post" action="do_showfielddef.php" /> <p><strong>Table Name:</strong><br /> <input type="text" name="table_name" size="30" /></p> <p><strong>Number of fields:</strong><br /> <input type="text" name="num_fields" size="30" /></p> <p><input type="submit" name="submit" value="go to step2" /></p> </form> </body> </html> This Form Posts to do_showfielddef.php <?php //validate important input if ((!$_POST[table_name]) || (!$_POST[num_fields])) { header( "location: show_createtable.html"); exit; } //begin creating form for display $form_block = " <form action=\"do_createtable.php\" method=\"post\"> <input name=\"table_name\" type=\"hidden\" value=\"$_POST[table_name]\"> <table cellspacing=\"5\" cellpadding=\"5\"> <tr> <th>Field Name</th><th>Field Type</th><th>Table Length</th><th>Primary Key?</th><th>Auto-Increment?</th> </tr>"; //count from 0 until you reach the number fo fields for ($i = 0; $i <$_POST[num_fields]; $i++) { $form_block .=" <tr> <td align=center><input type=\"texr\" name=\"field name[]\" size=\"30\"></td> <td align=center> <select name=\"field_type[]\"> <option value=\"char\">char</option> <option value=\"date\">date</option> <option value=\"float\">float</option> <option value=\"int\">int</option> <option value=\"text\">text</option> <option value=\"varchar\">varchar</option> </select> </td> <td align=center><input type=\"text\" name=\"field_length[]\" size=\"5\"></td> <td aligh=center><input type=\"checkbox\" name=\"primary[]\" value=\"Y\"></td> <td aligh=center><input type=\"checkbox\" name=\"auto_increment[]\" value=\"Y\"></td> </tr>"; } //finish up the form $form_block .= " <tr> <td align=center colspan=3><input type =\"submit\" value=\"create table\"> </td> </tr> </table> </form>"; ?> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Create a database table: Step 2</title> </head> <body> <h1>defnie fields for <? echo "$_POST[table_name]"; ?> </h1> <? echo "$form_block"; ?> </body> </html> Which in turn creates the table and fields with this file do_showfielddef.php //connect to database $connection = @mysql_connect("localhost", "user", "pass") or die(mysql_error()); $db = @mysql_select_db($db_name, $connection) or die(mysql_error()); //start creating the SQL statement $sql = "CREATE TABLE $_POST[table_name]("; //continue the SQL statement for each new field for ($i = 0; $i < count($_POST[field_name]); $i++) { $sql .= $_POST[field_name][$i]." ".$_POST[field_type][$i]; if ($_POST[auto_increment][$i] =="Y") { $additional = "NOT NULL auto_increment"; } else { $additional = ""; } if ($_POST[primary][$i] =="Y") { $additional .= ", primary key (".$_POST[field_name][$i].")"; } else { $additional = ""; } if ($_POST[field_length][$i] !="") { $sql .= " (".$_POST[field_length][$i].") $additional ,"; } else { $sql .=" $additional ,"; } } //clean up the end of the string $sql = substr($sql, 0, -1); $sql .= ")"; //execute the query $result = mysql_query($sql, $connection) or die(mysql_error()); //get a giid message for display upon success if ($result) { $msg = "<p>" .$_POST[table_name]." has been created!</p>"; } ?> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Create A Database Table: Step 3</title> </head> <body> <h1>Adding table to <? echo "$db_name"; ?>...</h1> <? echo "$msg"; ?> </body> </html>

    Read the article

  • Set default MySQL connect charset for PHP (in RHEL)?

    - by Martijn Heemels
    We're running a hundred or so legacy PHP websites on an older server which runs Gentoo Linux. When these sites were built latin1 was still the common charset, both in PHP and MySQL. To make sure those older sites used latin1 by default, while still allowing newer sites to use utf8 (our current standard), we set the default connect charset in php.ini: mysql.connect_charset = latin1 mysqli.connect_charset = latin1 pdo_mysql.connect_charset = latin1 Specific more modern sites could override this in their bootstrapping code with: <?php mysql_set_charset("utf8", $dsn ); ...and all was well. Now the server is overloaded and we're no longer with that hoster, so we're moving all these sites to a faster server at our standard hoster, which uses RHEL 5 as their OS of choice. In setting up this new server I discover to my surprise that the *.connect_charset directives are a Gentoo specific patch to PHP, and RHEL's version of PHP doesn't recognize them! Now how do I set PHP to connect to MySQL with the latin1 charset? I thought about setting a default in my.cnf but would prefer not to force every app and client to default to latin1. Our policy is to use utf8, and we'd like to restrict the exception to PHP only. Also, converting every legacy site to properly use utf8 is not doable since many are of the touch 'm and you break 'm kind. We simply don't have the time to go fix them all. How would I set a default mysql/mysqli/pdo_mysql connection charset to latin1 for PHP, while still allowing individual scripts to override this to utf8 with mysql_set_charset()?

    Read the article

  • How can MySQL be in GDAL's dependencies when it's already installed?

    - by Julien Fouilhé
    I'm trying to install GDAL on my CentOS 64 bits server to be able to make some GIS operations. I tried a simple: # yum install gdal First, the GDAL version is 1.4 (the last released one is 1.9) Then, I see in the dependencies list mysql. But I have mysql already installed, from another repository (remi), with a newer version than the one suggested by yum... Is it a problem of architecture (yum suggests i386)? I risked a yes, but still impossible to install it! Here's the error I have. Transaction Check Error: package mysql-5.5.28-1.el5.remi.x86_64 (which is newer than mysql-5.0.95-1.el5_7.1.i386) is already installed Then, I tried to install it from sources with last version available (1.9.2). I downloaded the GDAL tar.gz, extracted the files and installed it like following: # tar -xzf gdal-1.9.2.tar.gz # ./configure --with-static-proj4=/usr/local/lib --with-threads --with-libtiff=internal --with-geotiff=internal --with-jpeg=internal --with-gif=internal --with-png=internal --with-libz=internal # make # make install But during the make, I have some strange errors displaying, about RegisterOGRMySQL, that I can't understand: chmod a+x gdal-config /bin/sh /home/benjamin/gdal-1.9.2/libtool --mode=link g++ gdalinfo.lo /home/benjamin/gdal-1.9.2/libgdal.la -o gdalinfo libtool: link: g++ .libs/gdalinfo.o -o .libs/gdalinfo /home/benjamin/gdal-1.9.2/.libs/libgdal.so -L/usr/local/lib/lib -L/usr/kerberos/lib64 -lproj -lsqlite3 /usr/lib64/libexpat.so -lpthread -lrt -lcurl -ldl -lgssapi_krb5 -lkrb5 -lk5crypto -lcom_err -lidn -lssl -lcrypto -lz -Wl,-rpath -Wl,/usr/local/lib -Wl,-rpath -Wl,/usr/lib64 /home/benjamin/gdal-1.9.2/.libs/libgdal.so: undefined reference to `RegisterOGRMySQL' collect2: ld returned 1 exit status make[1]: *** [gdalinfo] Error 1 make[1]: Leaving directory `/home/benjamin/gdal-1.9.2/apps' make: *** [apps-target] Error 2 Has anyone a solution? Thanks a lot!

    Read the article

  • Is Ubuntu a bad distro for a standalone mysql database server?

    - by DhruvPathak
    I read an article here : http://www.mysqlperformanceblog.com/2011/12/08/which-linux-distribution-for-mysql-server/ On the other end there are Debian and Ubuntu. Both use tool called dpkg for package management. There isn’t a month that I log in to a system based on either distribution where there are no issues with packages consistency. Unfinished installations, unresolved conflicts are so common that it’s just beyond simple negligence. The packaging system is just not robust enough. Another problem is that one broken package may block you from installing or uninstalling anything else. Imagine that someone left system in such shape, you prepared for downtime, stopped MySQL and… error – text editor has not been properly installed, so you cannot upgrade MySQL either until the problem is fixed. In a stressful situation when downtime clock ticks – annoying at best We prefer Ubuntu server because of familiarity and Ubuntu also being development environment. Questions: Is Ubuntu used commonly in production for a mysql database server ? Is it worth the trouble ever to have one distro eg Ubuntu in web server, and another say Red Hat in database server ? Or Is a homogenous server pool a better choice ?

    Read the article

  • mysql disk io keeps increasing ... is that normal?

    - by trustfundbaby
    So I've been trying to figure out this disk IO problem I have been having with my linode VPS. Over the last day or two I've just left watch -n1 pidstat -d running in a console window and the output looks like this: Monitoring it over the last few days, I've noticed that my problem lies with the init, searchd, and mysql processes. Searchd is sphinx and all its indexes are on disk, so disk io there is inevitable (apparently). What I can't understand is why the disk reads (kB_rd/s) for mysql refuse to stabilize and just keep going up. It started out at 154 yesterday and is up to what you see in that screen shot. but disk writes (kB_wr/s) have remained pretty constant the entire time. My VPS only has 768MB RAM, my mysql db has a size of about 220MB and after running mysqltuner.pl and reading a bit about it, I've been advised to set my innodb_buffer_pool_size to 220MB but I simply cannot afford to do that ... I have it up to 150MB. My question is twofold. Why does the init process have that much disk reading to do? Why is mysql doing so much disk reading?

    Read the article

  • JPA/Hibernate and MySQL transaction isolation level

    - by armandino
    I have a native query that does a batch insert into a MySQL database: String sql = "insert into t1 (a, b) select x, y from t2 where x = 'foo'"; EntityTransaction tx = entityManager.getTransaction(); try { tx.begin(); int rowCount = entityManager.createNativeQuery(sql).executeUpdate(); tx.commit(); return rowCount; } catch(Exception ex) { tx.rollback(); log.error(...); } This query causes a deadlock: while it reads from t2 with insert .. select, another process tries to insert a row into t2. I don't care about the consistency of reads from t2 when doing an insert .. select and want to set the transaction isolation level to READ_UNCOMMITTED. How do I go about setting it in JPA backed by Hibernate?

    Read the article

  • How to generate simple Packing List with MySQL ?

    - by Stephen
    Hi, I need help on how to create a packing list of a shipment with MySQL. Let's say i have 32 boxes of keyboard ready to ship, the master carton can contain 12 boxes. I only have value 32 boxes and volume of 12. The other value in result below is generated by sql command. Not coming from record. So this easily calculate that the number of master carton would be 3 master cartons, with one as a non-standard quantity. How to perform query on this ? As i would like to be this result: +----------+---------------+-------------------+--------+------------+---------+ | Quantity | Standard_Qty | Non_Standard_Qty | Box_N | Box_Total | RowType | +----------+---------------+-------------------+--------+------------+---------+ | 12 | 1 | 0 | 1 | 3 | Detail | | 12 | 1 | 0 | 2 | 3 | Detail | | 8 | 0 | 1 | 3 | 3 | Detail | | 32 | 2 | 1 | | | Summary | +----------+---------------+-------------------+--------+------------+---------+ It looks like two query i know and probably the use of FLOOR command, in which i was teach in here. How to make this result? Thanks in advance. Stephen

    Read the article

  • MySQL and GROUP_CONCAT() maximum length

    - by zewaren
    Hello everyone, I'm using GROUP_CONCAT() in a MySQL query to convert multiple rows into a single string. However, the maximum length of the result of this function is 1024 characters. I'm very well aware that I can change the param group_concat_max_len to increase this limit: SET SESSION group_concat_max_len = 1000000; However, on the server I'm using, I can't change any param. Not by using the preceding query and not by editing any configuration file. So my question is: Is there any other way to get the output of a multiple row query into a single string? Thank you for your answers.

    Read the article

  • How to write php->mysql queries?

    - by Bluemagica
    Is there any good tutorial that has all the basic rules for writing queries to store $_Post vars from php to mysql? Like when to use backticks and singleqoutes, and how to safely write code with functions like get_magic_quotes_gpc()? Another thing is, assuming there is no javascript validation(since the user can easily turn it off), how should I handle empty form fields being sent as empty $_post variables and throwing errors? Do I have to use isset() call on all the post variables? What is the best way to handle users turning off javascript validation on a form?

    Read the article

  • NoSQL vs Ehcache caching advise for speeding up read only mysql Database

    - by paddydub
    I'm building a Route Planner Webapp using Spring/Hibernate/Tomcat and a mysql database, I have a database containing read only data, such as Bus Stop Coordinates, Bus times which is never updated. I'm trying to make the app run faster, each time the application is run it will preform approx 1000 reads to the database to calculate a route. I have setup a Ehcache which greatly improves the read from database times. I'm now setting terracotta + Ehcache distributed caching to share the cache with multiple Tomcat JVMs. This seems a bit complicated. I've tried memcached but it was not performing as fast as ehcache. I'm wondering if a MongoDb or Redis would be better suited. I have no experience with nosql but I would appreciate if anyone has any ideas. What i need is quick access to the read only database.

    Read the article

  • MySQL Query Select using sub-select takes too long

    - by True Soft
    I noticed something strange while executing a select from 2 tables: SELECT * FROM table_1 WHERE id IN ( SELECT id_element FROM table_2 WHERE column_2=3103); This query took approximatively 242 seconds. But when I executed the subquery SELECT id_element FROM table_2 WHERE column_2=3103 it took less than 0.002s (and resulted 2 rows). Then, when I did SELECT * FROM table_1 WHERE id IN (/* prev.result */) it was the same: 0.002s. I was wondering why MySQL is doing the first query like that, taking much more time than the last 2 queries separately? Is it an optimal solution for selecting something based from the results of a sub-query? Other details: table_1 has approx. 9000 rows, and table_2 has 90000 rows. After I added an index on column_2 from table_2, the first query took 0.15s.

    Read the article

< Previous Page | 188 189 190 191 192 193 194 195 196 197 198 199  | Next Page >