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  • problem with list return type??

    - by kaushik
    my list has value such as m=[['na','1','2']['ka','31','45']['ra','3','5'] d=0 r=2 t=m[d][r] print t # this is givin number i.e 2 Now when I use this value u=[] u=m[t] I am getting an err msg saying type error list does take str values... i want to use like this how can i convert that t into a integer?? please suggest.. thanks..

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  • Can XCode draw the call graph of a program?

    - by Werner
    Hi, I am new to Mac OSX, and I wonder if Xcode can generate , for a given C++ source code, the call graph of the program in a visual way. I also wonder if for each function, and after a run, whether it can also print the %time spent on the function If so, I would thank really some links with tutorials or info, after googling I did not find anything relevant Thanks

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  • removing elements incrementally from a list

    - by Javier
    Dear all, I've a list of float numbers and I would like to delete incrementally a set of elements in a given range of indexes, sth. like: for j in range(beginIndex, endIndex+1): print ("remove [%d] => val: %g" % (j, myList[j])) del myList[j] However, since I'm iterating over the same list, the indexes (range) are not valid any more for the new list. Does anybody has some suggestions on how to delete the elements properly? Best wishes

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  • python-nth perfect square

    - by kasyap
    Write a program that computes the sum of the logarithms of all the primes from 2 to some number n, and print out the sum of the logs of the primes, the number n, and the ratio of these two quantities. Test this for different values of n.

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  • Tried http post doesn't work

    - by Rebol Tutorial
    I wanted to try the example here http://www.codeconscious.com/rebol/rebol-net.html#HTTP print read/custom http://babelfish.altavista.com/translate.dyn reduce ['POST {text=REBOL+Rules&lp=en_fr}] Since the page has changed since I modified it to write clipboard:// read/custom http://babelfish.altavista.com/translate.dyn reduce ['POST {trtext=hello+world&lp=en_fr&btnTrTxt=Translate}] It does return an html page but it doesn't contain any translation. What did I miss thanks ?

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  • C++ problem with string stream istringstream

    - by user69514
    I am reading a file in the following format 1001 16000 300 12.50 2002 24000 360 10.50 3003 30000 300 9.50 where the items are: loan id, principal, months, interest rate. I'm not sure what it is that I am doing wrong with my input string stream, but I am not reading the values correctly because only the loan id is read correctly. Everything else is zero. Sorry this is a homework, but I just wanted to know if you could help me identify my error. if( inputstream.is_open() ){ /** print the results **/ cout << fixed << showpoint << setprecision(2); cout << "ID " << "\tPrincipal" << "\tDuration" << "\tInterest" << "\tPayment" <<"\tTotal Payment" << endl; cout << "---------------------------------------------------------------------------------------------" << endl; /** assign line read while we haven't reached end of file **/ string line; istringstream instream; while( inputstream >> line ){ instream.clear(); instream.str(line); /** assing values **/ instream >> loanid >> principal >> duration >> interest; /** compute monthly payment **/ double ratem = interest / 1200.0; double expm = (1.0 + ratem); payment = (ratem * pow(expm, duration) * principal) / (pow(expm, duration) - 1.0); /** computer total payment **/ totalPayment = payment * duration; /** print out calculations **/ cout << loanid << "\t$" << principal <<"\t" << duration << "mo" << "\t" << interest << "\t$" << payment << "\t$" << totalPayment << endl; } }

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  • problem in getting desired date format in loop

    - by Rishi2686
    Hi there, I have a date format like this : $date1 = "Sun May 09 20:07:50 +0000 2010"; and I have to convert it to: 09-05-2010 I am using date("d-m-Y", $date1)); When I print this individually it gives proper result but I am using it in loop it gives me results like: 31-12-1969 I don't understand why this is so? Can you help, please?

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  • python how to find the median of a list

    - by user3450574
    I'm trying to write a function named median that takes a list as an input and returns the median value of the list. I'm working with Python 2.7.2 The list can be of any size and the numbers are not guaranteed to be in any particular order. If the list contains an even number of elements, the function should return the average of the middle two. This is the code I'm starting with: def median(list): print(median([7,12,3,1,6,9]))

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  • CUPS Server compiled for Windows?

    - by Peter Illes
    Is there a version of the CUPS server available for Windows? Looking at the CUPS source code it seems it is ready for Visual Studio compilation, but I did not find any trace of an actual supported package. I'd like to set up a CUPS server on Windows so that I can print form Linux/MacOSX/Win clients to printers I set up on this server.

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  • Lambda recursive PHP functions.

    - by Kendall Hopkins
    Is it possible to have a PHP function that is both recursive and anonymous (lambda). This is my attempt to get it to work, but it doesn't pass in the function name. $factorial = function( $n ) use ( $factorial ) { if( $n == 1 ) return 1; return $factorial( $n - 1 ) * $n; }; print $factorial( 5 ); I'm also aware that this is a bad way to implement factorial, it's just an example.

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  • Is there a Silverlight equivalent to "Application.OpenForms"?

    - by lightmeetsdark
    Basically, I'm trying to take information entered by the user on one page and print it out to another page via a "printer friendly" version, or report, of something. I have a MainPage.xaml that is, as the name suggests, my main page, but in a window there is the subpage AdCalculator.xaml where the user enters the information and PrintEstimate.xaml that is navigated to via a button on AdCalculator. I would like to be able to transfer the information entered in the textboxes from AdCalculator and print it out via text blocks in PrintEstimate. So in order to do that I have the following code: Views.AdCalculator AdCalc = new Views.AdCalculator(); string PrintCompanyName = AdCalc.CompanyName; string PrintContactName = AdCalc.txt_CustomerName.Text; string PrintBillingAddress1 = AdCalc.txt_BillingAddress.Text; string PrintBillingAddress2 = AdCalc.txt_BillingAddressLine2.Text; string PrintPhoneNumber = AdCalc.txt_PhoneNumber.Text; string PrintNumOfAds = AdCalc.txt_NumofAds.Text; string PrintRateOfPlay = AdCalc.Cmb_Rate.SelectedValue.ToString(); string PrintNumOfMonths = AdCalc.txt_NumofMonths.Text; string PrintTotalDue = AdCalc.txt_InvoiceSummary_TotalDue.Text; PrintEstimate PrintEstimatePage = new PrintEstimate(); PrintEstimatePage.txt_CompanyName.Text = PrintCompanyName; PrintEstimatePage.txt_CustomerName.Text = PrintContactName; PrintEstimatePage.txt_BillingAddress.Text = PrintBillingAddress1; PrintEstimatePage.txt_BillingAddressLine2.Text = PrintBillingAddress2; PrintEstimatePage.txt_PhoneNumber.Text = PrintPhoneNumber; PrintEstimatePage.txt_InvoiceSummary_NumofAds.Text = PrintNumOfAds; PrintEstimatePage.txt_InvoiceSummary_RateofPlay.Text = PrintRateOfPlay; PrintEstimatePage.txt_InvoiceSummary_NumOfMonths.Text = PrintNumOfMonths; PrintEstimatePage.txt_EstimateTotal.Text = PrintTotalDue; Only problem is, when I instantiate the new AdCalculator page, it clears the values, so nothing is actually retained as far as user-input goes. Following a lead from a colleague, I believe all I need to do is change the line Views.AdCalculator AdCalc = new Views.AdCalculator(); to Views.AdCalculator AdCalc = (AdCalculator)Application.OpenForms["AdCalculator"]; except the "Apllication.OpenForms" doesn't register. I know there are a lot of differences in the way C# code-behind is laid out for silverlight applications, so I didn't know if there was an equivalent that anyone knew about to "Application.OpenForms" that would help solve my issue or if there was any other way to go about getting my task done. Thank you very much!

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  • What's the non brute force way to filter a Python dictionary?

    - by Thierry Lam
    I can filter the following dictionary like: data = { 1: {'name': 'stackoverflow', 'traffic': 'high'}, 2: {'name': 'serverfault', 'traffic': 'low'}, 3: {'name': 'superuser', 'traffic': 'low'}, 4: {'name': 'mathoverflow', 'traffic': 'low'}, } traffic = 'low' for k, v in data.items(): if v['traffic'] == traffic: print k, v Is there an alternate way to do the above filtering?

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  • Create lags with a for-loop in R

    - by cptn
    I've got a data.frame with stock data of several companies (here it's only two). I want 10 additional columns in my stock data.frame df with lagged dates (from -5 days to +5 days) for both companies in my event data.frame. I'm using a for loop which is probably not the best solution, but it works partially. DATE <- c("01.01.2000","02.01.2000","03.01.2000","06.01.2000","07.01.2000","09.01.2000","10.01.2000","01.01.2000","02.01.2000","04.01.2000","06.01.2000","07.01.2000","09.01.2000","10.01.2000") RET <- c(-2.0,1.1,3,1.4,-0.2, 0.6, 0.1, -0.21, -1.2, 0.9, 0.3, -0.1,0.3,-0.12) COMP <- c("A","A","A","A","A","A","A","B","B","B","B","B","B","B") df <- data.frame(DATE, RET, COMP, stringsAsFactors=F) df # DATE RET COMP # 1 01.01.2000 -2.00 A # 2 02.01.2000 1.10 A # 3 03.01.2000 3.00 A # 4 06.01.2000 1.40 A # 5 07.01.2000 -0.20 A # 6 09.01.2000 0.60 A # 7 10.01.2000 0.10 A # 8 01.01.2000 -0.21 B # 9 02.01.2000 -1.20 B # 10 04.01.2000 0.90 B # 11 06.01.2000 0.30 B # 12 07.01.2000 -0.10 B # 13 09.01.2000 0.30 B # 14 10.01.2000 -0.12 B this loop works fine comp <- as.vector(unique(df$COMP)) mylist <- vector('list', length(comp)) # create lags in DATE for(i in 1:length(comp)) { print(i) comp_i <- comp[i] df_k <- df[df$COMP %in% comp_i, ] # all trading days of one firm df_k <- transform(df_k, DATEm1 = c(NA, head(DATE, -1)), DATEm2 = c(NA, NA, head(DATE, -2)), DATEm3 = c(NA, NA, NA, head(DATE, -3)), DATEm4 = c(NA, NA, NA, NA,head(DATE, -4)), DATEm5 = c(NA, NA, NA, NA, NA, head(DATE, -5)), DATEp1 = c(DATE[-1], NA)) #DATEp2 = c(DATE[-2], NA, NA), #DATEp3 = c(DATE[-3], NA, NA, NA), #DATEp4 = c(DATE[-4], NA, NA, NA, NA), #DATEp5 = c(DATE[-5], NA, NA, NA, NA, NA)) mylist[[i]] = df_k } df1 <- do.call(rbind, mylist) But if I add the lines with DATEp2, DATEp3, DATEp4, DATEp5. the code doesn't work. Can anybody tell me what I'm doing wrong here? Here the code with all the lagged dates. # create lags in DATE for(i in 1:length(comp)) { print(i) comp_i <- comp[i] df_k <- df[df$COMP %in% comp_i, ] # all trading days of one firm df_k <- transform(df_k, DATEm1 = c(NA, head(DATE, -1)), DATEm2 = c(NA, NA, head(DATE, -2)), DATEm3 = c(NA, NA, NA, head(DATE, -3)), DATEm4 = c(NA, NA, NA, NA,head(DATE, -4)), DATEm5 = c(NA, NA, NA, NA, NA, head(DATE, -5)), DATEp1 = c(DATE[-1], NA), DATEp2 = c(DATE[-2], NA, NA), DATEp3 = c(DATE[-3], NA, NA, NA), DATEp4 = c(DATE[-4], NA, NA, NA, NA), DATEp5 = c(DATE[-5], NA, NA, NA, NA, NA)) mylist[[i]] = df_k } df1 <- do.call(rbind, mylist)

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  • pagination - 10 pages per page

    - by arthur
    I have a pagination script that displays a list of all pages like so: prev [1][2][3][4][5][6][7][8][9][10][11][12][13][14] next But I would like to only show ten of the numbers at a time: prev [3][4][5][6][7][8][9][10][11][12] next How can I accomplish this? Here is my code so far: <?php /* Set current, prev and next page */ $page = (!isset($_GET['page']))? 1 : $_GET['page']; $prev = ($page - 1); $next = ($page + 1); /* Max results per page */ $max_results = 2; /* Calculate the offset */ $from = (($page * $max_results) - $max_results); /* Query the db for total results. You need to edit the sql to fit your needs */ $result = mysql_query("select title from topics"); $total_results = mysql_num_rows($result); $total_pages = ceil($total_results / $max_results); $pagination = ''; /* Create a PREV link if there is one */ if($page > 1) { $pagination .= '< a hr_ef="?page='.$prev.'">Previous</a> '; } /* Loop through the total pages */ for($i = 1; $i <= $total_pages; $i++) { if(($page) == $i) { $pagination .= $i; } else { $pagination .= '< a hr_ef="index.php?page='.$i.'">'.$i.'</a>'; } } /* Print NEXT link if there is one */ if($page < $total_pages) { $pagination .= '< a hr_ef="?page='.$next.'"> Next</a>'; } /* Now we have our pagination links in a variable($pagination) ready to print to the page. I pu it in a variable because you may want to show them at the top and bottom of the page */ /* Below is how you query the db for ONLY the results for the current page */ $result=mysql_query("select * from topics LIMIT $from, $max_results "); while ($i = mysql_fetch_array($result)) { echo $i['title'].'<br />'; } echo $pagination; ?>

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  • Clarification needed about Python CSV file format parsing

    - by HH
    Format is like: CHINA;2002-06-25 00:00:00.000;5,60 CHINA;2002-06-26 00:00:00.000;5,32 CHINA;2002-06-27 00:00:00.000;5,31 and I try to use Python's CSV tools to parse it but cannot understand the paragraph, source: And while the module doesn’t directly support parsing strings, it can easily be done: import csv for row in csv.reader(['one,two,three']): print row Could someone clarify the line ['one,two,three']? How would you use it with format A;B;C?

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  • counting paragraphs in text file

    - by robjez
    I need to create perl code which allows counting paragraphs in text files. I tried this and doesn't work: open(READFILE, "<$filename") or die "could not open file \"$filename\":$!"; $paragraphs = 0; my($c); while($c = getc(READFILE)) { if($C ne"\n") { $paragraphs++; } } close(READFILE); print("Paragraphs: $paragraphs\n");

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