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  • Measure work perfomance

    - by Neir0
    Does anyone know utility which can measure work intensity. For example - keystrokes\mouse clicks per second, time spent in IDE\other developer tools, total lines of code per hour...etc.

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  • Invert a stack, without using extra data structures?

    - by vks
    How would you invert a stack, without using extra data structures, like a second, or temporary, stack. Thus no stack1-stack2 or stack-queue-stack implementation in the answer. You just have access to push/pop feature of a standard stack. I think there is way to do it by keeping a global counter and using pointer manipulation. If I solve it myself, I will post it. If someone else figures it out, please post your solution.

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  • How do i create nice looking controls?

    - by KoolKabin
    hi guys, I found a nice controls used by a software so wanted to use or build similar nice looking controls for my applications in vb.net First Sample control is nice rounded cornor group box [ i guess so ]: http://sachicomputer.com/kabin/samples/control1.jpg and second control is nice looking tab control: http://sachicomputer.com/kabin/samples/control1.jpg

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  • FCBKcomplete, Create a new TAG with Commas as opposed to Enter

    - by nobosh
    Currently, FCBKcomplete created new tags after you type something in and press enter. Is there a way to get the plug-in to allow for comma's (which is how tags are commonly separated) to create new tags? I'd hate to have to try to retrain users to user enter as opposed to the more standard comma separator. Plugin: http://www.emposha.com/javascript/fcbkcomplete.html Demo (use the second control): http://www.emposha.com/demo/fcbkcomplete_2/

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  • How to better create stacked bar graphs with multiple variables from ggplot2?

    - by deoksu
    I often have to make stacked barplots to compare variables, and because I do all my stats in R, I prefer to do all my graphics in R with ggplot2. I would like to learn how to do two things: First, I would like to be able to add proper percentage tick marks for each variable rather than tick marks by count. Counts would be confusing, which is why I take out the axis labels completely. Second, there must be a simpler way to reorganize my data to make this happen. It seems like the sort of thing I should be able to do natively in ggplot2 with plyR, but the documentation for plyR is not very clear (and I have read both the ggplot2 book and the online plyR documentation. My best graph looks like this, the code to create it follows: the R code I use to get it is the following: library(epicalc) ### recode the variables to factors ### recode(c(int_newcoun, int_newneigh, int_neweur, int_newusa, int_neweco, int_newit, int_newen, int_newsp, int_newhr, int_newlit, int_newent, int_newrel, int_newhth, int_bapo, int_wopo, int_eupo, int_educ), c(1,2,3,4,5,6,7,8,9, NA), c('Very Interested','Somewhat Interested','Not Very Interested','Not At All interested',NA,NA,NA,NA,NA,NA)) ### Combine recoded variables to a common vector Interest1<-c(int_newcoun, int_newneigh, int_neweur, int_newusa, int_neweco, int_newit, int_newen, int_newsp, int_newhr, int_newlit, int_newent, int_newrel, int_newhth, int_bapo, int_wopo, int_eupo, int_educ) ### Create a second vector to label the first vector by original variable ### a1<-rep("News about Bangladesh", length(int_newcoun)) a2<-rep("Neighboring Countries", length(int_newneigh)) [...] a17<-rep("Education", length(int_educ)) Interest2<-c(a1, a2, a3, a4, a5, a6, a7, a8, a9, a10, a11, a12, a13, a14, a15, a16, a17) ### Create a Weighting vector of the proper length ### Interest.weight<-rep(weight, 17) ### Make and save a new data frame from the three vectors ### Interest.df<-cbind(Interest1, Interest2, Interest.weight) Interest.df<-as.data.frame(Interest.df) write.csv(Interest.df, 'C:\\Documents and Settings\\[name]\\Desktop\\Sweave\\InterestBangladesh.csv') ### Sort the factor levels to display properly ### Interest.df$Interest1<-relevel(Interest$Interest1, ref='Not Very Interested') Interest.df$Interest1<-relevel(Interest$Interest1, ref='Somewhat Interested') Interest.df$Interest1<-relevel(Interest$Interest1, ref='Very Interested') Interest.df$Interest2<-relevel(Interest$Interest2, ref='News about Bangladesh') Interest.df$Interest2<-relevel(Interest$Interest2, ref='Education') [...] Interest.df$Interest2<-relevel(Interest$Interest2, ref='European Politics') detach(Interest) attach(Interest) ### Finally create the graph in ggplot2 ### library(ggplot2) p<-ggplot(Interest, aes(Interest2, ..count..)) p<-p+geom_bar((aes(weight=Interest.weight, fill=Interest1))) p<-p+coord_flip() p<-p+scale_y_continuous("", breaks=NA) p<-p+scale_fill_manual(value = rev(brewer.pal(5, "Purples"))) p update_labels(p, list(fill='', x='', y='')) I'd very much appreciate any tips, tricks or hints. Thanks.

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  • Sqldatareader and rowcount

    - by phenevo
    Hi, I have a query: declare @Code nvarchar(100) select @Code="BMW" select name from NewCars where code=@Code if @@rowcount = 0 Select name from OldCars where code=@Code In Sql managment studio first part give me 0 resuklts, and second 1 one result, and that is ok, but in sqldatareader I use the same query ofcource without: declare @Code nvarchar(100) select @Code="BMW" because I use: cmd.Parameters.AddWithValue("@Code", "BMW"); And using (SqlDataReader reader = cmd.ExecuteReader()) { if (reader.HasRows) { while (reader.Read()) { Name= reader["Name"].ToString(); } } else { throw new NotSupportedException("Lack of car with this Code"); } } gives me zero result

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  • PHP bitwise left shifting 32 spaces problem and bad results with large numbers arithmetic operations

    - by Victor Stanciu
    Hello, I have the following problems: First: I am trying to do a 32-spaces bitwise left shift on a large number, and for some reason the number is always returned as-is. For example: echo(516103988<<32); // echoes 516103988 Because shifting the bits to the left one space is the equivalent of multiplying by 2, i tried multiplying the number by 2^32, and it works, it returns 2216649749795176448. Second: I have to add 9379 to the number from the above point: printf('%0.0f', 2216649749795176448 + 9379); // prints 2216649749795185920 Should print: 2216649749795185827

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  • progressIndicator does not update till about 10 seconds after awakeFromNib occures

    - by theprojectabot
    I have been trying to get this one section of my UI to immediatly up date when the document loads into view. The awakeFromNib fires the pasted code and then starts a timer to repeat every 10 seconds... I load a default storage location: ~/Movies... which shows up immediately.. yet the network location that is saved in the document that gets pulled from the XML only seems to show up after the second firing of the - (void)updateDiskSpaceDisplay timer. I have set breakpoints and know that the ivars that contain the values that are being put into the *fileSystemAttributes is the network location right when the awakeFromNib occurs... Im confused why it magically appears after the second time firing instead of immediately displaying the write values. - (void)updateDiskSpaceDisplay { // Obtain information about the file system used on the selected storage path. NSError *error = NULL; NSDictionary *fileSystemAttributes = [[NSFileManager defaultManager] attributesOfFileSystemForPath:[[[self settings] containerSettings] storagePath] error:&error]; if( !fileSystemAttributes ) return; // Get the byte capacity of the drive. long long byteCapacity = [[fileSystemAttributes objectForKey:NSFileSystemSize] unsignedLongLongValue]; // Get the number of free bytes. long long freeBytes = [[fileSystemAttributes objectForKey:NSFileSystemFreeSize] unsignedLongLongValue]; // Update the level indicator, and the text fields to show the current information. [totalDiskSpaceField setStringValue:[self formattedStringFromByteCount:byteCapacity]]; [totalDiskSpaceField setNeedsDisplay:YES]; [usedDiskSpaceField setStringValue:[self formattedStringFromByteCount:(byteCapacity - freeBytes)]]; [usedDiskSpaceField setNeedsDisplay:YES]; [diskSpaceIndicator setMaxValue:100]; [diskSpaceIndicator setIntValue:(((float) (byteCapacity - freeBytes) / (float) byteCapacity) * 100.0)]; [diskSpaceIndicator display:YES]; } thoughts? my awakeFromNib: - (void)awakeFromNib { [documentWindow setAcceptsMouseMovedEvents:YES]; [documentWindow setDelegate:self]; [self updateSettingsDisplay]; [self updateDiskSpaceDisplay]; [self setDiskSpaceUpdateTimer:[NSTimer scheduledTimerWithTimeInterval:10.0 target:self selector:@selector(updateDiskSpaceDisplay) userInfo:NULL repeats:YES]]; [self setUpClipInfoTabButtons]; [self performSelector:@selector(setupEngineController) withObject:NULL afterDelay:0.1]; }

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  • How to iterate over all the page breaks in an Excel 2003 worksheet via COM

    - by Martin
    I've been trying to retrieve the locations of all the page breaks on a given Excel 2003 worksheet over COM. Here's an example of the kind of thing I'm trying to do: Excel::HPageBreaksPtr pHPageBreaks = pSheet->GetHPageBreaks(); long count = pHPageBreaks->Count; for (long i=0; i < count; ++i) { Excel::HPageBreakPtr pHPageBreak = pHPageBreaks->GetItem(i+1); Excel::RangePtr pLocation = pHPageBreak->GetLocation(); printf("Page break at row %d\n", pLocation->Row); pLocation.Release(); pHPageBreak.Release(); } pHPageBreaks.Release(); I expect this to print out the row numbers of each of the horizontal page breaks in pSheet. The problem I'm having is that although count correctly indicates the number of page breaks in the worksheet, I can only ever seem to retrieve the first one. On the second run through the loop, calling pHPageBreaks->GetItem(i) throws an exception, with error number 0x8002000b, "invalid index". Attempting to use pHPageBreaks->Get_NewEnum() to get an enumerator to iterate over the collection also fails with the same error, immediately on the call to Get_NewEnum(). I've looked around for a solution, and the closest thing I've found so far is http://support.microsoft.com/kb/210663/en-us. I have tried activating various cells beyond the page breaks, including the cells just beyond the range to be printed, as well as the lower-right cell (IV65536), but it didn't help. If somebody can tell me how to get Excel to return the locations of all of the page breaks in a sheet, that would be awesome! Thank you. @Joel: Yes, I have tried displaying the user interface, and then setting ScreenUpdating to true - it produced the same results. Also, I have since tried combinations of setting pSheet->PrintArea to the entire worksheet and/or calling pSheet->ResetAllPageBreaks() before my call to get the HPageBreaks collection, which didn't help either. @Joel: I've used pSheet->UsedRange to determine the row to scroll past, and Excel does scroll past all the horizontal breaks, but I'm still having the same issue when I try to access the second one. Unfortunately, switching to Excel 2007 did not help either.

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  • Kohana ORM syntax question

    - by anthony
    I'm using the "join_table" function with Kohana's ORM to build a query. The following works: $category = ORM::factory('category')->join_table('product'); But this doesn't: $category = ORM::factory('category'); $category->join_table('product'); The documentation uses the second as an example, but it returns 0 while the first example returns "categories_products" which is correct. Any ideas?

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  • how to preserve filter values after opertion on grid.

    - by Pankaj Pareek
    Hi experts. I have some filter and one grid.And grid have some buttons like modify/edit.I am selecting some value from filters and getting some result in grid.now i want to modify some record.when i come again on grid data in filter should be remain same. There is two pages. one contain filters and grid second contain modify details. Thanks Pankaj Pareek.

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  • How Can I Use This jSON data like array

    - by mTuran
    hi, i have json data like this: {"Adobe Photoshop":"70","Adobe Premier":"71","Animasyon":"72","AutoCAD":"73","Bro\u015f\u00fcr & Bilet":"75","CorelDraw":"76","Flash":"77","Grafik Tasar\u0131m":"68","Karikat\u00fcr":"78","Kartvizit Tasar\u0131m":"79","Logo Tasar\u0131m":"80","Poster":"81","Reklam Tasar\u0131m":"74","Ses D\u00fczenleme":"82","Video D\u00fczenleme":"69","Web Tasar\u0131m":"83"} First think(Adobe Photoshop) means tag name, second thing(70) means tag id. I want to use this information in jquery like array to build checkboxes for every tag. How can i done this ? Thanks

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  • Custom Event Handler

    - by Dremation
    I have a function that I'm using while(true) to repeatedly scan memory addresses of an application to detect change. I sleep the thread 1 second between iterations and this helps performance. However, is there a way to create a custom event handler to do away with the loops?

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  • Is there a way to reuse an XmlReader?

    - by uriDium
    I have a process that uses an XmlReader. I have already done a lot to squeeze maximum performance out of it. So far we have had huge gains from using the Reader as opposed to XmlDoc or DataSet.GetXml(). We expect to get XML many times a second and I would like to avoid the overhead of recreating the reader every time. I have already cached the XmlReaderSettings but is there anyway to reuse the XmlReader or do I need to recreate it every time?

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  • asp.net with jquery valduation issue

    - by Eyla
    Greetings, I have 2 textboxs, 2 checkboxs and 2 labels. first textbox, checkbox, and label related to each other and the same for the rest. textbox should accept valid phone number based on jquery validation plugin and when the chackbox check the validation rule would change and in both option the error message would disply inside the label. I have no problem to implement that for one text box but when I add second one will have a problem and only the validation will happen for the second one only. please look at my code and advice. <script src="js/jquery-1.4.1.js" type="text/javascript"></script> <script src="js/jquery.validate.js" type="text/javascript"></script> <script type="text/javascript"> var RegularExpression; var USAPhone = /^[01]?[- .]?(\([2-9]\d{2}\)|[2-9]\d{2})[- .]?\d{3}[- .]?\d{4}$/; var InterPhone = /^\d{9,12}$/; var errmsg; function ValidPhoneHome(sender) { if (sender.checked == true) { RegularExpression = InterPhone; errmsg = "Enter 9 to 12 numbers as international number"; } else { RegularExpression = USAPhone; errmsg = "Enter a valid number"; } jQuery.validator.addMethod("phonehome", function(value, element) { return this.optional(element) || RegularExpression.test(value); }, errmsg); } function ValidMobileHome(sender) { if (sender.checked == true) { RegularExpression = InterPhone; errmsg = "Enter 9 to 12 numbers as international number"; } else { RegularExpression = USAPhone; errmsg = "Enter a valid number"; } jQuery.validator.addMethod("mobilephone", function(value, element) { return this.optional(element) || RegularExpression.test(value); }, errmsg); } $(document).ready(function() { ValidPhoneHome("#<%= chkIntphoneHome%>"); ValidMobileHome("#<%= chkIntMobileHome%>"); $("#aspnetForm").validate({ rules: { "<%=txtHomePhone.UniqueID %>": { phonehome: true } } , errorLabelContainer: "#lblHomePhone", rules: { "<%=txtMobileHome.UniqueID %>": { mobilephone: true } } , errorLabelContainer: "#lblMobileHome" }) </script> <asp:CheckBox ID="chkIntphoneHome" runat="server" Text="Internation Code" onclick="ValidPhoneHome(this)" > <asp:TextBox ID="txtHomePhone" runat="server" ></asp:TextBox> <label id="lblHomePhone"></label> <asp:CheckBox ID="chkIntMobileHome" runat="server" Text="Internation Code" onclick="ValidMobileHome(this)" /> <asp:TextBox ID="txtMobileHome" runat="server"></asp:TextBox> <label id="lblMobileHome"></label>

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  • md5 decoding. How they do it?

    - by Syom
    i thought, that it is impossible to decode md5 hashes, but i found tools, which decode them here. but i have no idea, how they do it in such a short period of time(it takes about a second). Help me please to understand it. Thanks

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  • XDocument unable to digest url in header if encountered twice

    - by Paul Connolly
    Hi there, I am consuming an xml response from a government gateway which contains a url in its root node twice (being firstly xsi:schemaLocation="http://www.govtalk.gov.uk/CM/envelope" and also xmlns="http://www.govtalk.gov.uk/CM/envelope") XDocument will only parse this if I pull out the second one (the xmlns one) from the node. Is there some way I can prepare XDocument to digest this repeated URL without having to manipulate the incoming xml in any way? Thanks Paul

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  • Java code optimization on matrix windowing computes in more time

    - by rano
    I have a matrix which represents an image and I need to cycle over each pixel and for each one of those I have to compute the sum of all its neighbors, ie the pixels that belong to a window of radius rad centered on the pixel. I came up with three alternatives: The simplest way, the one that recomputes the window for each pixel The more optimized way that uses a queue to store the sums of the window columns and cycling through the columns of the matrix updates this queue by adding a new element and removing the oldes The even more optimized way that does not need to recompute the queue for each row but incrementally adjusts a previously saved one I implemented them in c++ using a queue for the second method and a combination of deques for the third (I need to iterate through their elements without destructing them) and scored their times to see if there was an actual improvement. it appears that the third method is indeed faster. Then I tried to port the code to Java (and I must admit that I'm not very comfortable with it). I used ArrayDeque for the second method and LinkedLists for the third resulting in the third being inefficient in time. Here is the simplest method in C++ (I'm not posting the java version since it is almost identical): void normalWindowing(int mat[][MAX], int cols, int rows, int rad){ int i, j; int h = 0; for (i = 0; i < rows; ++i) { for (j = 0; j < cols; j++) { h = 0; for (int ry =- rad; ry <= rad; ry++) { int y = i + ry; if (y >= 0 && y < rows) { for (int rx =- rad; rx <= rad; rx++) { int x = j + rx; if (x >= 0 && x < cols) { h += mat[y][x]; } } } } } } } Here is the second method (the one optimized through columns) in C++: void opt1Windowing(int mat[][MAX], int cols, int rows, int rad){ int i, j, h, y, col; queue<int>* q = NULL; for (i = 0; i < rows; ++i) { if (q != NULL) delete(q); q = new queue<int>(); h = 0; for (int rx = 0; rx <= rad; rx++) { if (rx < cols) { int mem = 0; for (int ry =- rad; ry <= rad; ry++) { y = i + ry; if (y >= 0 && y < rows) { mem += mat[y][rx]; } } q->push(mem); h += mem; } } for (j = 1; j < cols; j++) { col = j + rad; if (j - rad > 0) { h -= q->front(); q->pop(); } if (j + rad < cols) { int mem = 0; for (int ry =- rad; ry <= rad; ry++) { y = i + ry; if (y >= 0 && y < rows) { mem += mat[y][col]; } } q->push(mem); h += mem; } } } } And here is the Java version: public static void opt1Windowing(int [][] mat, int rad){ int i, j = 0, h, y, col; int cols = mat[0].length; int rows = mat.length; ArrayDeque<Integer> q = null; for (i = 0; i < rows; ++i) { q = new ArrayDeque<Integer>(); h = 0; for (int rx = 0; rx <= rad; rx++) { if (rx < cols) { int mem = 0; for (int ry =- rad; ry <= rad; ry++) { y = i + ry; if (y >= 0 && y < rows) { mem += mat[y][rx]; } } q.addLast(mem); h += mem; } } j = 0; for (j = 1; j < cols; j++) { col = j + rad; if (j - rad > 0) { h -= q.peekFirst(); q.pop(); } if (j + rad < cols) { int mem = 0; for (int ry =- rad; ry <= rad; ry++) { y = i + ry; if (y >= 0 && y < rows) { mem += mat[y][col]; } } q.addLast(mem); h += mem; } } } } I recognize this post will be a wall of text. Here is the third method in C++: void opt2Windowing(int mat[][MAX], int cols, int rows, int rad){ int i = 0; int j = 0; int h = 0; int hh = 0; deque< deque<int> *> * M = new deque< deque<int> *>(); for (int ry = 0; ry <= rad; ry++) { if (ry < rows) { deque<int> * q = new deque<int>(); M->push_back(q); for (int rx = 0; rx <= rad; rx++) { if (rx < cols) { int val = mat[ry][rx]; q->push_back(val); h += val; } } } } deque<int> * C = new deque<int>(M->front()->size()); deque<int> * Q = new deque<int>(M->front()->size()); deque<int> * R = new deque<int>(M->size()); deque< deque<int> *>::iterator mit; deque< deque<int> *>::iterator mstart = M->begin(); deque< deque<int> *>::iterator mend = M->end(); deque<int>::iterator rit; deque<int>::iterator rstart = R->begin(); deque<int>::iterator rend = R->end(); deque<int>::iterator cit; deque<int>::iterator cstart = C->begin(); deque<int>::iterator cend = C->end(); for (mit = mstart, rit = rstart; mit != mend, rit != rend; ++mit, ++rit) { deque<int>::iterator pit; deque<int>::iterator pstart = (* mit)->begin(); deque<int>::iterator pend = (* mit)->end(); for(cit = cstart, pit = pstart; cit != cend && pit != pend; ++cit, ++pit) { (* cit) += (* pit); (* rit) += (* pit); } } for (i = 0; i < rows; ++i) { j = 0; if (i - rad > 0) { deque<int>::iterator cit; deque<int>::iterator cstart = C->begin(); deque<int>::iterator cend = C->end(); deque<int>::iterator pit; deque<int>::iterator pstart = (M->front())->begin(); deque<int>::iterator pend = (M->front())->end(); for(cit = cstart, pit = pstart; cit != cend; ++cit, ++pit) { (* cit) -= (* pit); } deque<int> * k = M->front(); M->pop_front(); delete k; h -= R->front(); R->pop_front(); } int row = i + rad; if (row < rows && i > 0) { deque<int> * newQ = new deque<int>(); M->push_back(newQ); deque<int>::iterator cit; deque<int>::iterator cstart = C->begin(); deque<int>::iterator cend = C->end(); int rx; int tot = 0; for (rx = 0, cit = cstart; rx <= rad; rx++, ++cit) { if (rx < cols) { int val = mat[row][rx]; newQ->push_back(val); (* cit) += val; tot += val; } } R->push_back(tot); h += tot; } hh = h; copy(C->begin(), C->end(), Q->begin()); for (j = 1; j < cols; j++) { int col = j + rad; if (j - rad > 0) { hh -= Q->front(); Q->pop_front(); } if (j + rad < cols) { int val = 0; for (int ry =- rad; ry <= rad; ry++) { int y = i + ry; if (y >= 0 && y < rows) { val += mat[y][col]; } } hh += val; Q->push_back(val); } } } } And finally its Java version: public static void opt2Windowing(int [][] mat, int rad){ int cols = mat[0].length; int rows = mat.length; int i = 0; int j = 0; int h = 0; int hh = 0; LinkedList<LinkedList<Integer>> M = new LinkedList<LinkedList<Integer>>(); for (int ry = 0; ry <= rad; ry++) { if (ry < rows) { LinkedList<Integer> q = new LinkedList<Integer>(); M.addLast(q); for (int rx = 0; rx <= rad; rx++) { if (rx < cols) { int val = mat[ry][rx]; q.addLast(val); h += val; } } } } int firstSize = M.getFirst().size(); int mSize = M.size(); LinkedList<Integer> C = new LinkedList<Integer>(); LinkedList<Integer> Q = null; LinkedList<Integer> R = new LinkedList<Integer>(); for (int k = 0; k < firstSize; k++) { C.add(0); } for (int k = 0; k < mSize; k++) { R.add(0); } ListIterator<LinkedList<Integer>> mit; ListIterator<Integer> rit; ListIterator<Integer> cit; ListIterator<Integer> pit; for (mit = M.listIterator(), rit = R.listIterator(); mit.hasNext();) { Integer r = rit.next(); int rsum = 0; for (cit = C.listIterator(), pit = (mit.next()).listIterator(); cit.hasNext();) { Integer c = cit.next(); Integer p = pit.next(); rsum += p; cit.set(c + p); } rit.set(r + rsum); } for (i = 0; i < rows; ++i) { j = 0; if (i - rad > 0) { for(cit = C.listIterator(), pit = M.getFirst().listIterator(); cit.hasNext();) { Integer c = cit.next(); Integer p = pit.next(); cit.set(c - p); } M.removeFirst(); h -= R.getFirst(); R.removeFirst(); } int row = i + rad; if (row < rows && i > 0) { LinkedList<Integer> newQ = new LinkedList<Integer>(); M.addLast(newQ); int rx; int tot = 0; for (rx = 0, cit = C.listIterator(); rx <= rad; rx++) { if (rx < cols) { Integer c = cit.next(); int val = mat[row][rx]; newQ.addLast(val); cit.set(c + val); tot += val; } } R.addLast(tot); h += tot; } hh = h; Q = new LinkedList<Integer>(); Q.addAll(C); for (j = 1; j < cols; j++) { int col = j + rad; if (j - rad > 0) { hh -= Q.getFirst(); Q.pop(); } if (j + rad < cols) { int val = 0; for (int ry =- rad; ry <= rad; ry++) { int y = i + ry; if (y >= 0 && y < rows) { val += mat[y][col]; } } hh += val; Q.addLast(val); } } } } I guess that most is due to the poor choice of the LinkedList in Java and to the lack of an efficient (not shallow) copy method between two LinkedList. How can I improve the third Java method? Am I doing some conceptual error? As always, any criticisms is welcome. UPDATE Even if it does not solve the issue, using ArrayLists, as being suggested, instead of LinkedList improves the third method. The second one performs still better (but when the number of rows and columns of the matrix is lower than 300 and the window radius is small the first unoptimized method is the fastest in Java)

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  • How do I add custom buttons to Formtastic?

    - by jklina
    I'm using the Formtastic Rails gem in my app and its been great, but I would really like to add a second button, other than the bundled "commit" button that redirects back. I can't seem to find any information on how to add a custom button. Any information would be greatly appreciated!

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  • IPHONE MPMoviePlayer: Playing video under button layers that can be interacted with while video play

    - by nicholas
    I would like to have layers of buttons over video playing in the background on my IPHONE application. Basically, I'm looking to adjust the Movie Player code, in order to allow the application user to tap on different portions of the screen while a video plays and call other commands (for example a video of puppets talking, if you touch one of the puppets, the video pauses and a second (smaller) window appears with a list of information about that puppet; when you exit that list, the video continues where it was paused).

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  • How Do I code this in python with simplejson

    - by Spikie
    how do i code a python program that return a json element that look like this {1:{'name':foo,'age':xl} 2:{'name':vee,'age':xx} .... } What i meant is that i want return nested dictionaries What i hoped to accomplish is something like this var foo = 1.name # to the the value of name in the clientside I hope all this made sense .English is my second language thanks in advance

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  • assert fact into file in prolog

    - by smile
    Hello everyone, How can I assert a fact into a file without deleting the previous fact? In the following line, when I execute it twice, the second fact overwrites the first fact: tell('animal.txt'),write(Animal),nl,told. But when I use assert or assertz it will do nothing. Help me please. Thank you :)

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