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  • Server returns 500 error only when called by Java client using urlConnection/httpUrlConnection

    - by user455889
    Hi - I'm having a very strange problem. I'm trying to call a servlet (JSP) with an HTTP GET and a few parameters (http://mydomain.com/method?param1=test&param2=123). If I call it from the browser or via WGET in a bash session, it works fine. However, when I make the exact same call in a Java client using urlConnection or httpURLConnection, the server returns a 500 error. I've tried everything I have found online including: urlConn.setRequestProperty("Accept-Language", "en-us,en;q=0.5"); Nothing I've tried, however, has worked. Unfortunately, I don't have access to the server I'm calling so I can't see the logs. Here's the latest code: private String testURLConnection() { String ret = ""; String url = "http://localhost:8080/TestService/test"; String query = "param1=value1&param2=value2"; try { URLConnection connection = new URL(url + "?" + query).openConnection(); connection.setRequestProperty("Accept-Charset", "UTF-8"); connection.setRequestProperty("Accept-Language", "en-us,en;q=0.5"); BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(connection.getInputStream())); String line; StringBuilder content = new StringBuilder(); while ((line = bufferedReader.readLine()) != null) { content.append(line + "\n"); } bufferedReader.close(); metaRet = content.toString(); log.debug(methodName + " return = " + metaRet); } catch (Exception ex) { log.error("Exception: " + ex); log.error("stack trace: " + getStackTrace(ex)); } return metaRet; } Any help would be greatly appreciated!

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  • Running an RMI registry on one computer and connecting to it from another

    - by Hippopotamus
    Hello. I am doing a student assignment, using java RMI. I've programmed a simple RMI-server application that provides method which return some strings to the client. When I start the server on localhost and connect to it by client on the same computer, everything goes well. However, I am not able to do this between two computers on home network. The computers both have no trouble of connecting by a simple C program with similar functionality, so I guess the problem is with JVM here. I am binding the class to rmiregistry with try{ ComputeImpl R = new ComputeImpl(); Naming.rebind("rmi://localhost/ComputeService",R); } catch(Exception e){ System.out.println("Trouble: " +e); } And I'm doing the lookup for RMI registry in the client application with providing the argument while launching the application: StringBuffer rmi_address = new StringBuffer(); rmi_address.append("rmi://").append(args[1]).append("/ComputeService"); Compute R = (Compute) Naming.lookup(rmi_address.toString()); Is the problem with my code or with JVM? Thanks in advance.

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  • Adding an unknown number of JComponents to a JPanel

    - by Matthew
    Good day, I am building an Applet (JApplet to be exact) and I sub divided that into two panels. The top panel is called DisplayPanel which is a custom class that extends JPanel. The bottom panel is called InputPanel which also extends JPanel. As mentioned above, I can add those two Panel's to the applet and they display fine. The next thing that I would like to do is have the InputPanel be able to hold a random number of JComponent Objects all listed veritcally. This means that the InputPanel should be able to have JButtons, JLabels, JTextFields etc thrown at it. I then want the InputPanel to display some sort of scrolling capability. The catch is that since these two panels are already inside my applet, I need the InputPanel to stay the same size as it was given when added to the Applet. So for example, if my applet (from the web-browser html code) was given the size 700,700, and then the DisplayPanel was 700 by 350, and the InputPanel was below it with the same dimensions, I want to then be able to add lots of JComponents like buttons, to the InputPanel and the panel would stay 700 x 350 in the same position that it is at, only the panel would have scroll bars if needed. I've played with many different combinations of JScrollPane, but just cannot get it. Thank you.

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  • Design: How to declare a specialized memory handler class

    - by Michael Dorgan
    On an embedded type system, I have created a Small Object Allocator that piggy backs on top of a standard memory allocation system. This allocator is a Boost::simple_segregated_storage< class and it does exactly what I need - O(1) alloc/dealloc time on small objects at the cost of a touch of internal fragmentation. My question is how best to declare it. Right now, it's scope static declared in our mem code module, which is probably fine, but it feels a bit exposed there and is also now linked to that module forever. Normally, I declare it as a monostate or a singleton, but this uses the dynamic memory allocator (where this is located.) Furthermore, our dynamic memory allocator is being initialized and used before static object initialization occurs on our system (as again, the memory manager is pretty much the most fundamental component of an engine.) To get around this catch 22, I added an extra 'if the small memory allocator exists' to see if the small object allocator exists yet. That if that now must be run on every small object allocation. In the scheme of things, this is nearly negligable, but it still bothers me. So the question is, is there a better way to declare this portion of the memory manager that helps decouple it from the memory module and perhaps not costing that extra isinitialized() if statement? If this method uses dynamic memory, please explain how to get around lack of initialization of the small object portion of the manager.

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  • javascript error handeling

    - by pankaj
    I have a javascript function for checking errors which i am callin on OnClicentClick event of a button. Once it catch a error i want to stop execution of click event . But in my case it always it always executes the onclick event. Following is my function: function DisplayError() { if (document.getElementById('<%=txtPassword.ClientID %>').value.length < 6 || document.getElementById('<%=txtPassword.ClientID %>').value.length > 12) { document.getElementById('<%=lblError.ClientID %>').innerText = "Password length must be between 6 to 12 characters"; return false; } var str = <%=PhoneNumber()%>; if(str.length <10) { alert('<%=phoneNum%>'.length); document.getElementById('<%=lblError.ClientID %>').innerText = "Phone Number not in correct format"; return false; } } button html code: <asp:Button runat="server" Text="Submit" ID="btnSubmit" ValidationGroup="submit" onclick="btnSubmit_Click" OnClientClick="DisplayError()"/> It should not execute the button click event once it satisfies any of the IF condition in javascript function.

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  • Wrapper Classes for Backward compatibility in Java

    - by Casebash
    There is an interesting article here on maintaing backwards compatibility for Java. In the wrapper class section, I can't actually understand what the wrapper class accomplishes. In the following code from MyApp, WrapNewClass.checkAvailable() could be replaced by Class.forName("NewClass"). static { try { WrapNewClass.checkAvailable(); mNewClassAvailable = true; } catch (Throwable ex) { mNewClassAvailable = false; } } Consider when NewClass is unavailable. In the code where we use the wrapper (see below), all we have done is replace a class that doesn't exist, with one that exists, but which can't be compiled as it uses a class that doesn't exist. public void diddle() { if (mNewClassAvailable) { WrapNewClass.setGlobalDiv(4); WrapNewClass wnc = new WrapNewClass(40); System.out.println("newer API is available - " + wnc.doStuff(10)); }else { System.out.println("newer API not available"); } } Can anyone explain why this makes a difference? I assume it has something to do with how Java compiles code - which I don't know much about.

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  • VB.NET: Dialog exits when enter pressed?

    - by Camilo Martin
    Hi all; My problem seems to be quite simple, but it's not working the intuitive way. I'm designing a Windows Forms Application, and there is a dialog that should NOT exit when the enter key is pressed, instead it has to validate data first, in case enter was pressed after changing the text of a ComboBox. I've tried by telling it what to do on KeyPress event of the ComboBox if e is the Enter key: Private Sub ComboBoxSizeChoose_KeyPress(ByVal sender As System.Object, ByVal e As System.Windows.Forms.KeyPressEventArgs) Handles ComboBoxSizeChoose.KeyPress If e.KeyChar = Convert.ToChar(Keys.Enter) Then Try TamanhoDaNovaFonte = Single.Parse(ComboBoxSizeChoose.Text) Catch ex As Exception Dim Dialogo2 As New Dialog2 Dialog2.ShowDialog() ComboBoxSizeChoose.Text = TamanhoDaNovaFonte End Try End If End Sub But no success so far. When the Enter key is pressed, even with the ComboBox on focus, the whole dialog is closed, returning to the previous form. The validation is NOT done at all, and it has to be done before exiting. In fact, I don't even want to exit on the form's enter KeyPress, the only purpose of the enter key on the whole dialog is to validate the ComboBox (but only when in focus, for the sake of an intuitive UI). I've also tried appending the validation to the KeyPress event of the whole dialog's form, if the key is Enter. NO SUCCESS! It's like my code wasn't there at all. What should I do? (Visual Studio 2008, VB.NET)

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  • iPhone table header lables not showing up in Release build but show up OK in Debug build

    - by Robert
    My table header shows up ok with Release build or Debug build for the iPhone simulator, but the header labels only show up with debug build on the iPhone. No header labels show up on the iPhone for release build. Any ideas? Thanks, Robert My code for the header is below - (UIView *) tableView:(UITableView *)tableView viewForHeaderInSection:(NSInteger)sectionNum { @try { // create the parent view that will hold header Label UIView* customView = [[[UIView alloc] initWithFrame:CGRectMake(HEADER_RELX_OFFSET, HEADER_RELY_OFFSET, HEADER_ROW_WIDTH, HEADER_HEIGHT)] autorelease]; UILabel* headerLabel = [[UILabel alloc] initWithFrame:CGRectZero]; headerLabel.backgroundColor = [UIColor clearColor]; headerLabel.opaque = NO; headerLabel.numberOfLines = 0; headerLabel.textColor = [UIColor blackColor]; headerLabel.highlightedTextColor = [UIColor whiteColor]; headerLabel.font = [UIFont boldSystemFontOfSize:HEADER_FONT_SIZE]; headerLabel.textAlignment = UITextAlignmentCenter; headerLabel.lineBreakMode = UILineBreakModeWordWrap; headerLabel.frame = CGRectMake(HEADER_RELX_OFFSET, HEADER_RELY_OFFSET, HEADER_ROW_WIDTH, HEADER_HEIGHT); if(sectionNum == 0) headerLabel.text = @"My Label"; else headerLabel.text = @""; [customView addSubview:headerLabel]; return customView; @catch (NSException* exception) { NSLog(@"viewForHeaderInSection: %@: %@",[exception name],[exception reason]); } }

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  • How to print a page when a JButton is pressed in java swing using PrinterJob?

    - by Prayag Upd
    I tried the following code AWT but at runtime shows multiple print dialogs repeatedly.... package printerjob; import java.awt.BasicStroke; import java.awt.Frame; import java.awt.Graphics; import java.awt.Graphics2D; import java.awt.event.WindowAdapter; import java.awt.print.PageFormat; import java.awt.print.Printable; import java.awt.print.PrinterException; import java.awt.print.PrinterJob; /** * * @author pragX */ public class FramePrinterJob extends Frame implements Printable{ public void start(){ add(button); } @Override public void paint(Graphics graphics){ PrinterJob printerJob=PrinterJob.getPrinterJob(); printerJob.setPrintable(this); if(printerJob.printDialog()){ try{ printerJob.print(); }catch(PrinterException printerException){ //printerException.printStackTrace(); System.out.println("Error Printing." + printerException); } } } public int print(Graphics graphics, PageFormat pageFormat, int pageIndex) throws PrinterException { //throw new UnsupportedOperationException("Not supported yet."); if(pageIndex>=1){ return Printable.NO_SUCH_PAGE; } graphics.translate((int) pageFormat.getImageableX(), (int)pageFormat.getImageableY()); Graphics2D graphics2D=(Graphics2D)graphics; graphics2D.setStroke(new BasicStroke(4f)); graphics2D.drawLine(20, 20, 20, 120); graphics2D.drawLine(40, 20, 40, 120); graphics2D.drawLine(20, 70, 40, 70); graphics2D.drawLine(60, 70, 60, 120); graphics2D.drawLine(60, 40, 60, 45); return Printable.PAGE_EXISTS; } public static void main(String args[]){ Frame frame=new FramePrinterJob(); frame.addWindowListener(new WindowAdapter() { public void windowClosing(){System.exit(0);}}); frame.setSize(300,400); frame.setVisible(true); } }

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  • translate a PHP $string using google translator API

    - by Toni Michel Caubet
    hey there! been google'ing for a while how is the best way to translate with google translator in PHP, found very different ways converting URLS, or using Js but i want to do it only with php (or with a very simple solution JS/JQUery) example: //hopefully with $from_lan and $to_lan being like 'en','de', .. or similar function translate($from_lan, $to_lan, $text){ // do return $translated_text; } can you give me a clue? or maybe you already have this function.. my intention it's to use it only for the languages i have not already defined (or keys i haven't defined), that's why i wan it so simple, will be only temporal.. EDIT thanks for your replies we are now trying this soulutions: function auto_translate($from_lan, $to_lan, $text){ // do $json = json_decode(file_get_contents('https://ajax.googleapis.com/ajax/services/language/translate?v=1.0&q=' . urlencode($text) . '&langpair=' . $from_lan . '|' . $to_lan)); $translated_text = $json->responseData->translatedText; return $translated_text; } (there was a extra 'g' on variables for lang... anyway) it returns: works now :) i don't really understand much the function, so any idea why is not acepting the object? (now i do) OR: unction auto_translate($from_lan, $to_lan, $text){ // do // $json = json_decode(file_get_contents('https://ajax.googleapis.com/ajax/services/language/translate?v=1.0&q=' . urlencode($text) . '&langpair=' . $from_lan . '|' . $to_lan)); // $translated_text = $json['responseData']['translatedText']; error_reporting(1); require_once('GTranslate.php'); try{ $gt = new Gtranslate(); $translated_text = $gt-english_to_german($text); } catch (GTranslateException $ge) { $translated_text= $ge->getMessage(); } return $translated_text; } And this one looks great but it doesn't even gives me an error, the page won't load (error_report(1) :S) thanks in advance!

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  • How to repeatedly show a Dialog with PyGTK / Gtkbuilder?

    - by Julian
    I have created a PyGTK application that shows a Dialog when the user presses a button. The dialog is loaded in my __init__ method with: builder = gtk.Builder() builder.add_from_file("filename") builder.connect_signals(self) self.myDialog = builder.get_object("dialog_name") In the event handler, the dialog is shown with the command self.myDialog.run(), but this only works once, because after run() the dialog is automatically destroyed. If I click the button a second time, the application crashes. I read that there is a way to use show() instead of run() where the dialog is not destroyed, but I feel like this is not the right way for me because I would like the dialog to behave modally and to return control to the code only after the user has closed it. Is there a simple way to repeatedly show a dialog using the run() method using gtkbuilder? I tried reloading the whole dialog using the gtkbuilder, but that did not really seem to work, the dialog was missing all child elements (and I would prefer to have to use the builder only once, at the beginning of the program). [SOLUTION] As pointed out by the answer below, using hide() does the trick. But one has to take care that the dialog is in fact destroyed if one does not catch its "delete-event". A simple example that works is: import pygtk import gtk class DialogTest: def rundialog(self, widget, data=None): self.dia.show_all() result = self.dia.run() def destroy(self, widget, data=None): gtk.main_quit() def closedialog(self, widget, data=None): self.dia.hide() return True def __init__(self): self.window = gtk.Window(gtk.WINDOW_TOPLEVEL) self.window.connect("destroy", self.destroy) self.dia = gtk.Dialog('TEST DIALOG', self.window, gtk.DIALOG_MODAL | gtk.DIALOG_DESTROY_WITH_PARENT) self.dia.vbox.pack_start(gtk.Label('This is just a Test')) self.dia.connect("delete-event", self.closedialog) self.button = gtk.Button("Run Dialog") self.button.connect("clicked", self.rundialog, None) self.window.add(self.button) self.button.show() self.window.show() if __name__ == "__main__": testApp = DialogTest() gtk.main()

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  • How to disable server-side caching on IIS 7.5 (asp net mvc3)

    - by troebr
    I'm struggling with my IIS setup regarding caching, here's a brief description of my problem: I'm making a site for mobile and non-mobile, sharing the same controllers. IE: mysite/page will serve either mysite/page.cshtml, or mysite/M/page.cshtml, depending on the device. Here's the catch, it worked fine with my local and integration environment (cassiini and iis 6), but on another machine (2008r2/iis 7.5), apparently there is an aggressive server-side caching policy: If I access the website from a desktop machine, I have the correct pages (desktop version) If now I use my mobile phone to access the site, I will have the desktop version, (which implies a server-side cache, my phone is not using the same network). On the contrary, if I were to restart the server and access the site using my phone first, then I will get the mobile version on my desktop (only for the pages I already visited of course). I tried 2 solutions so far: Disabling OutputCache from my Web.config: <httpModules> [..] <remove name="OutputCache" /> </httpModules> And unchecking "Enable output cache" in "Output Caching" for my site in IIS. What's bugging me is that I do not have this problem with my other server (iis 6.0), although caching is enabled on this one, which leads me to think it is related to iis 7 caching addition. My question is simple: how does one disable server-side caching on IIS 7.5? Thanks in advance for your iis lights!

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  • Apache is looking for htaccess and htpasswd files that aren't there

    - by user1094092
    Having an issue where Apache is requesting authentication, and looking for an .htpasswd file, based on instructions from an .htaccess file that's no longer in DocumentRoot. Background: In my DocumentRoot, I'd previously copied an .htaccess and .htpasswd file from another machine (along with all of the other website files). .htaccess contents: AuthType Basic AuthName "Password is required" AuthUserFile /some/directory/that/was/on/the/other/server/not/this/one/.htpasswd Require valid-user Here's the catch: I moved .htaccess and .htpasswd out of DocumentRoot and even renamed the files. There is no longer an .htaccess file in DocumentRoot at all. But, when I try to access localhost from a browser, I am prompted to enter the login and password. When I enter the login and password (from the old, not-in-DocumentRoot .hpasswd file), I get a 500 Internal Server error and the log shows: [error] [client 127.0.0.1] (2)No such file or directory: Could not open password file: /some/directory/that/was/on/the/other/server/not/this/one/.htpasswd This has been quite a puzzle, because there's no longer a .htaccess or .htpasswd file anywhere in DocumentRoot !! Have tried several apache restarts and also tried using a blank .htaccess file in the DocumentRoot. Even grepped the entire machine for references to AuthType Basic to see if I missed anything. httpd.conf looks normal enough...I can post that if needed, but this question seems long enough as it is :) Thanks for any assistance you can provide

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  • Issue while saving image using savefiledialog

    - by user1097772
    I'm using savefiledialog to save an image. Canvas is picturebox and the loaded image is bitmap. When I try to save it the file is created but somehow corrupted. Cause when I try againt load the image or show in different viewer it doesn't work - I mean the saved file is corrupted. There is an method for saving image. private void saveFileDialog1_FileOk(object sender, CancelEventArgs e) { System.IO.FileStream fs = (System.IO.FileStream)saveFileDialog1.OpenFile(); try { switch (saveFileDialog1.FilterIndex) { case 1: canvas.Image.Save(saveFileDialog1.FileName, System.Drawing.Imaging.ImageFormat.Bmp); break; case 2: canvas.Image.Save(saveFileDialog1.FileName, System.Drawing.Imaging.ImageFormat.Jpeg); break; case 3: canvas.Image.Save(saveFileDialog1.FileName, System.Drawing.Imaging.ImageFormat.Png); break; case 4: canvas.Image.Save(saveFileDialog1.FileName, System.Drawing.Imaging.ImageFormat.Tiff); break; } } catch (Exception ex) { System.Console.WriteLine("Exception " + ex); } I should also mention the property Filter. saveFileDialog1.Filter has value: bmp (*.bmp)|*.bmp|jpeg (*.jpeg)|*.jpeg|png (*.png)|*.png|tiff (*.tiff)|*.tiff

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  • Could DataGridView be this dumb? or its me?lol

    - by Selase
    Am trying to bind data to a dropdown list on pageload based on a condition. Code explains further below. public partial class AddExhibit : System.Web.UI.Page { string adminID, caseIDRetrieved; DataSet caseDataSet = new DataSet(); SqlDataAdapter caseSqlDataAdapter = new SqlDataAdapter(); string strConn = WebConfigurationManager.ConnectionStrings["CMSSQL3ConnectionString1"].ConnectionString; protected void Page_Load(object sender, EventArgs e) { adminID = Request.QueryString["adminID"]; caseIDRetrieved = Request.QueryString["caseID"]; if (caseIDRetrieved != null) { CaseIDDropDownList.Text = caseIDRetrieved; //CaseIDDropDownList.Enabled = false; } else { try { CreateDataSet(); DataView caseDataView = new DataView(caseDataSet.Tables[0]); CaseIDDropDownList.DataSource = caseDataView; CaseIDDropDownList.DataBind(); } catch (Exception ex) { string script = "<script>alert('" + ex.Message + "');</script>"; } } } The CreateDataset method that is called in the if..else statement is contains the following code. private void CreateDataSet() { SqlConnection caseConnection = new SqlConnection(strConn); caseSqlDataAdapter.SelectCommand = new SqlCommand("Select CaseID FROM Cases", caseConnection); caseSqlDataAdapter.Fill(caseDataSet); } However when i load the page and as usual the condition that is supposed to bid the data is met, the gridview decides to displays as follows... IS IT ME OR ITS THE DATAGRID?...??

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  • Disable validation in an object in Ruby on Rails

    - by J. Pablo Fernández
    I have an object which whether validation happens or not should depend on a boolean, or in another way, validation is optional. I haven't found a clean way to do it. What I'm currently doing is this (disclaimer: you cannot unsee, leave this page if you are too sensitive): def valid? if perform_validation super else super # Call valid? so that callbacks get called and things like encrypting passwords and generating salt in before_validation actually happen errors.clear # but then clear the errors true # and claim ourselves to be valid. This is super hacky! end end Any better ways? Before you point to the :if argument of many validations, this is for a user model which is using authlogic so it has a lot of validation rules. You can stop reading here if you belive me. If you don't, authlogic already sets some :ifs like: :if => :email_changed? which I have to turn into :if => Proc.new {|user| user.email_changed? and user.perform_validation} and in some other cases, since I'm also using authlogic-oid (OpenID) I just don't have control over the :if, authlogic-oid sets it in a way I cannot change it (in time) without further monkey patching. So I have to override seemingly unrelated functions, catch exceptions if a method doesn't exist, etc. The previous hacky solution if the best of my two attempts.

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  • Accessing MS Access database from C#

    - by Abilash
    I want to use MS Access as database for my C# windows form application.I have used OleDb driver for connecting MS Access. I am able to select the records from the MS Access using OleDbConnection and ExecuteReader.But I am un able to insert,update and delete records. My code is as follows: OleDbConnection con=new OleDbConnection(strCon); try { con.Open(); OleDbCommand com = new OleDbCommand("INSERT INTO DPMaster(DPID,DPName,ClientID,ClientName) VALUES('53','we','41','aw')", con); int a=com.ExecuteNonQuery(); //OleDbCommand com = new OleDbCommand("SELECT * FROM DPMaster", con); //OleDbDataReader dr = com.ExecuteReader(); //while (dr.Read()) //{ // MessageBox.Show(dr[2].ToString()); //} MessageBox.Show(a.ToString()); } catch { MessageBox.Show("cannot"); } If I execute the commented block the application works.But the insert block doesnt works.Why I am unable to insert/update/delete the records into database? My Connection String is as follows: string strCon="Provider=Microsoft.Jet.OLEDB.4.0;Data Source=xyz.mdb;Persist Security Info=True";

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  • Getting Outlook calendar items based on subject

    - by EKS
    I'm trying to get a list of calendar objects from exchange and sorting them based on subject. The part of of getting the objects just based on date and sorting out via subject is in "code" is now working, but i want to do a sort on subject in the "sql" first, but im unable to make it work ( Currently getting error from exchange saying the query is wrong. The line I added is: + "AND lcase(\"urn:schemas:calendar:subject\") = 'onsite%' " What I want is the ability to catch all appointments that start with onsite, both in upper and lower case. strQuery = "<?xml version=\"1.0\"?>" + "<g:searchrequest xmlns:g=\"DAV:\">" + "<g:sql>SELECT \"urn:schemas:calendar:location\", \"urn:schemas:httpmail:subject\", " + "\"urn:schemas:calendar:dtstart\", \"urn:schemas:calendar:dtend\", " + "\"urn:schemas:calendar:busystatus\", \"urn:schemas:calendar:instancetype\" " + "FROM Scope('SHALLOW TRAVERSAL OF \"" + strCalendarURI + "\"') " + "WHERE NOT \"urn:schemas:calendar:instancetype\" = 1 " + "AND \"DAV:contentclass\" = 'urn:content-classes:appointment' " + "AND \"urn:schemas:calendar:dtstart\" > '2003/06/01 00:00:00' " //'" + DateString + "'" + "AND lcase(\"urn:schemas:calendar:subject\") = 'onsite' " + "ORDER BY \"urn:schemas:calendar:dtstart\" ASC" + "</g:sql></g:searchrequest>";

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  • How to get the dynamic generated content of an external ASP file using PhP?

    - by theCrius
    This is the situation: I've a PhP login page that check is an external ASP page has generated something (nickname). For example: i'm logged? So opening directly the asp page will display "nickname:thecrius" and nothing more. I'm not logged? So opening the ASP page will display nothing. Now i've to catch the "thecrius" string with a PhP page. Using file_get_contents only return me "nickname:", the "static" part of the asp page. What i'm doing wrong? Some codes: $aspSource = "http://www.domain.com/inc/whois.asp"; //ASP external $file = file_get_contents($aspSource); //get content of the asp page $start = strpos($file, "username:") + 9; //cutting off the "nickname:" $username = substr($file, $start); //get the username echo "URL-> $aspSource<br>Content-> $file<br>Start-> $start<br>Username-> $username<br>END"; But the result is only URL-> http://www.domain.com/inc/whois.asp Content-> username: Start-> 9 Username-> END Thanks in advance to anyone will help!

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  • Developing Job References

    - by Joe Smith
    How do you develop references for jobs? I have 6 years of programming experience spanning two jobs, but sadly I don't have a lot of people I can draw on as references. It's been several years since I left my last job, which was at a small company, and I've lost touch with the few people I knew there. I now work at another small company. I think I've gone as far as I can in my current position, and would like to look for greener pastures, but I can't exactly use my current boss as a reference, even though I have a very good repore with him. I'm sure he'd make a great reference down the road, but I'm afraid I'd insult him or jeopardize my current job by mentioning that I'm thinking of leaving and would like him to help me. I've applied to some jobs, and I have gotten several replies like, "Oh, you're exactly what we're looking for. Send us a couple references and we'll schedule an interview. Oh, no references? You must be a psychopath, nevermind." I've tried doing some small freelance work on the side, just so I can have a contact who can vouch for my work, but the competition for even small projects is pretty fierce and I can rarely devote adequate time to freelancing while holding a full time job. In addition, I often encounter a Catch-22 where a lot of freelancing jobs also require references. So how do programmers maintain existing references and develop new ones, especially while holding a full time job?

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  • How can I remove a JPanel from a JFrame?

    - by Roman
    Recently I asked here how to add a new JPanel to JFrame. The answer helped me to get a working code. But not I have a related question: "How can I remove an old JPanel". I need that because of the following problem. A new JPanel appears appears when I want (either time limit is exceeded or user press the "Submit" button). But in several seconds some element of the old JPanel appears together with the component of the new JPanel. I do not understand why it happens. I thought that it is because I have to other threads which update the window. But the first thread just add the old panel once (so, it should be finished). And in the second thread I have a loop which is broken (so, it also should be finished). Here is my code: private Thread controller = new Thread() { public void run() { // First we set the initial pane (for the selection of partner). SwingUtilities.invokeLater(new Runnable() { public void run() { frame.getContentPane().add(generatePartnerSelectionPanel()); frame.invalidate(); frame.validate(); } }); // Update the pane for the selection of the parnter. for (int i=40; i>0; i=i-1) { final int sec = i; SwingUtilities.invokeLater(new Runnable() { public void run() { timeLeftLabel.setText(sec + " seconds left."); } }); try {Thread.sleep(1000);} catch (InterruptedException e) {} if (partnerSubmitted) {break;} } // For the given user the selection phase is finished (either the time is over or form was submitted). SwingUtilities.invokeLater(new Runnable() { public void run() { frame.getContentPane().add(generateWaitForGamePanel()); frame.invalidate(); frame.validate(); } }); } };

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  • Centralized Exception handling for Eclipse plug-in

    - by Svilen
    Hello, At first I thought this would be question often asked, however trying (and failing) to look up info on this proved me wrong. Is there a mechanism in Eclipse platform for centralized exception handling of exceptions? For example... You have plug-in project which connects to a DB and issues queries, results of which are used to populate some e.g. views. This is like the most common example ever. :) Queries are executed almost for any user action, from every UI control the plug-in provides. Most likely the DB Query API will have some specific to the DB SomeDBGeneralException declared as being thrown by it. That's OK, you can handle those according to whatever your software design is. But how about unchecked exceptions which are likely to occur, e.g. , when communication with DB suddenly breaks for some network related reason? What if in such case one would like to catch those exceptions in a central place and for example provide user friendly message to the user (rather than the low level communication protocol api messages) and even some possible actions the user could execute in order to deal with the specific problem? Thinking in Eclipse platform context, the question may be rephrased as "Is there an extension point like "org.eclipse.ExceptionHandler" which allows to declare exception handlers for specific (some kind of filtering support) exceptions giving a lot of flexibility with the actual handling?"

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  • From Servlet to JSP

    - by kawtousse
    When trying to pass a table built with HTML in my servlet like that: response.setContentType("text/html" ); PrintWriter out = response.getWriter(); out.println("<html>" ); out.println("<head>" ); out.println("<title>Imput OPC</title>" ); out.println("</head>" ); out.println("<body>" ); ... and then response.sendRedirect("/xxx.jsp" ); But I did not found any table in the JSP. A friend told me to use a Bean but how can i catch values from the form ( because I have a treatement with the form before constructing table)in a bean.I must use a servlet for that. So what I want is exactly to construct in the response a table then send it to jsp knowing that: .sendRedirect and getServletContext().getRequestDispatcher("/xxx.jsp").forward(request, response); gives nothing at all. Please Help its urgent. Thinks.

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  • Problems with LWUIT in J2ME on Nokia E72

    - by Andre Mariano
    Well, I'm developing a app in my cellphone that is going to connect to my PC, the problem is that everytime that I return a URLRequest to the cellphone, it shows the previous Form on the screen and not de actual one, for example this is what goes in my actionListener: public void actionPerformed(ActionEvent ae) { if (ae.getCommand() == guiaUtil.cSelecionar()) { LoginRemote loginRemote = new LoginRemote(); try { //This is the request, returns true or false, does not affect the form loginRemote.login(tLogin.getText(), tPassword.getText()); } catch (Exception e) { GuiaUtil.error(e); return; } guiaUtil.mainApp().startMenu(); } } Then in the "guiaUtil.mainApp().startMenu()" I have this public void startMenu() { if (itemsMenu == null) { itemsMenu = new List(); itemsMenu.setWidth(320); itemsMenu.addItem("Sincronize Spots"); itemsMenu.addItem("Find Spots"); itemsMenu.addItem("Work"); itemsMenu.setFocus(true); this.addComponent(itemsMenu); this.addCommandListener(this); this.addCommand(guiaUtil.cSelect()); Form form = new Form(); form.addComponent(itemsMenu); } form.show(); } Anyway, after the request returns, it shows my Login form again, instead of showing the Menu List

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  • javamail api isertion of main class help

    - by bobby
    import javax.servlet.*; import javax.servlet.http.*; import java.io.*; import javax.mail.*; import javax.mail.internet.*; import javax.mail.event.*; import javax.mail.Authenticator; import java.net.*; import java.util.*; public class servletmail extends HttpServlet { public void doPost(HttpServletRequest request,HttpServletResponse response)throws ServletException,IOException { PrintWriter out=response.getWriter(); response.setContentType("text/html"); try { Properties props=new Properties(); props.put("mail.transport.protocol", "smtp"); props.put("mail.smtp.host","smtp.googlemail.com"); props.put("mail.smtp.port", "995"); props.put("mail.smtp.auth", "true"); javax.mail.Authenticator authenticator = new javax.mail.Authenticator() { protected javax.mail.PasswordAuthentication getPasswordAuthentication() { return new javax.mail.PasswordAuthentication("[email protected]", "password"); } }; Session sess=Session.getDefaultInstance(props,authenticator); sess.setDebug (true); Transport transport =sess.getTransport ("smtp"); Message msg=new MimeMessage(sess); msg.setFrom(new InternetAddress("[email protected]")); msg.addRecipient(Message.RecipientType.TO, new InternetAddress("[email protected]")); msg.setSubject("Hello JavaMail"); msg.setText("Welcome to JavaMail"); transport.connect(); transport.send(msg); out.println("mail has been sent"); } catch(Exception e) { System.out.println("err"+e); } } } how to insert main class in above java code and how to pass arguments of "from" and "to"

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