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  • Mysql Query problem ?

    - by deep
    ID NAME AMT 1 Name1 1000 2 Name2 500 3 Name3 3000 4 Name1 5000 5 Name2 2000 6 Name1 3000 consider above table as sample. am having a problem in my sql query, Am using like this. Select name,amt from sample where amt between 1000 and 5000 it returns all the values in the table between 1000 and 5000, instead I want to get maximum amount record for each name i.e., 3 name3 3000 4 name1 5000 5 name2 2000

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  • how to do this in MySql Query??

    - by deep
    ID NAME AMT 1 Name1 1000 2 Name2 500 3 Name3 3000 4 Name1 5000 5 Name2 2000 6 Name1 3000 consider above table as sample. am having a problem in my sql query, Am using like this. Select name,amt from sample where amt between 1000 and 5000 it returns all the values in the table between 1000 and 5000, instead I want to get maximum amount record for each name i.e., 3 name3 3000 4 name1 5000 5 name2 2000

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  • Of C# Iterators and Performance

    - by James Michael Hare
    Some of you reading this will be wondering, "what is an iterator" and think I'm locked in the world of C++.  Nope, I'm talking C# iterators.  No, not enumerators, iterators.   So, for those of you who do not know what iterators are in C#, I will explain it in summary, and for those of you who know what iterators are but are curious of the performance impacts, I will explore that as well.   Iterators have been around for a bit now, and there are still a bunch of people who don't know what they are or what they do.  I don't know how many times at work I've had a code review on my code and have someone ask me, "what's that yield word do?"   Basically, this post came to me as I was writing some extension methods to extend IEnumerable<T> -- I'll post some of the fun ones in a later post.  Since I was filtering the resulting list down, I was using the standard C# iterator concept; but that got me wondering: what are the performance implications of using an iterator versus returning a new enumeration?   So, to begin, let's look at a couple of methods.  This is a new (albeit contrived) method called Every(...).  The goal of this method is to access and enumeration and return every nth item in the enumeration (including the first).  So Every(2) would return items 0, 2, 4, 6, etc.   Now, if you wanted to write this in the traditional way, you may come up with something like this:       public static IEnumerable<T> Every<T>(this IEnumerable<T> list, int interval)     {         List<T> newList = new List<T>();         int count = 0;           foreach (var i in list)         {             if ((count++ % interval) == 0)             {                 newList.Add(i);             }         }           return newList;     }     So basically this method takes any IEnumerable<T> and returns a new IEnumerable<T> that contains every nth item.  Pretty straight forward.   The problem?  Well, Every<T>(...) will construct a list containing every nth item whether or not you care.  What happens if you were searching this result for a certain item and find that item after five tries?  You would have generated the rest of the list for nothing.   Enter iterators.  This C# construct uses the yield keyword to effectively defer evaluation of the next item until it is asked for.  This can be very handy if the evaluation itself is expensive or if there's a fair chance you'll never want to fully evaluate a list.   We see this all the time in Linq, where many expressions are chained together to do complex processing on a list.  This would be very expensive if each of these expressions evaluated their entire possible result set on call.    Let's look at the same example function, this time using an iterator:       public static IEnumerable<T> Every<T>(this IEnumerable<T> list, int interval)     {         int count = 0;         foreach (var i in list)         {             if ((count++ % interval) == 0)             {                 yield return i;             }         }     }   Notice it does not create a new return value explicitly, the only evidence of a return is the "yield return" statement.  What this means is that when an item is requested from the enumeration, it will enter this method and evaluate until it either hits a yield return (in which case that item is returned) or until it exits the method or hits a yield break (in which case the iteration ends.   Behind the scenes, this is all done with a class that the CLR creates behind the scenes that keeps track of the state of the iteration, so that every time the next item is asked for, it finds that item and then updates the current position so it knows where to start at next time.   It doesn't seem like a big deal, does it?  But keep in mind the key point here: it only returns items as they are requested. Thus if there's a good chance you will only process a portion of the return list and/or if the evaluation of each item is expensive, an iterator may be of benefit.   This is especially true if you intend your methods to be chainable similar to the way Linq methods can be chained.    For example, perhaps you have a List<int> and you want to take every tenth one until you find one greater than 10.  We could write that as:       List<int> someList = new List<int>();         // fill list here         someList.Every(10).TakeWhile(i => i <= 10);     Now is the difference more apparent?  If we use the first form of Every that makes a copy of the list.  It's going to copy the entire list whether we will need those items or not, that can be costly!    With the iterator version, however, it will only take items from the list until it finds one that is > 10, at which point no further items in the list are evaluated.   So, sounds neat eh?  But what's the cost is what you're probably wondering.  So I ran some tests using the two forms of Every above on lists varying from 5 to 500,000 integers and tried various things.    Now, iteration isn't free.  If you are more likely than not to iterate the entire collection every time, iterator has some very slight overhead:   Copy vs Iterator on 100% of Collection (10,000 iterations) Collection Size Num Iterated Type Total ms 5 5 Copy 5 5 5 Iterator 5 50 50 Copy 28 50 50 Iterator 27 500 500 Copy 227 500 500 Iterator 247 5000 5000 Copy 2266 5000 5000 Iterator 2444 50,000 50,000 Copy 24,443 50,000 50,000 Iterator 24,719 500,000 500,000 Copy 250,024 500,000 500,000 Iterator 251,521   Notice that when iterating over the entire produced list, the times for the iterator are a little better for smaller lists, then getting just a slight bit worse for larger lists.  In reality, given the number of items and iterations, the result is near negligible, but just to show that iterators come at a price.  However, it should also be noted that the form of Every that returns a copy will have a left-over collection to garbage collect.   However, if we only partially evaluate less and less through the list, the savings start to show and make it well worth the overhead.  Let's look at what happens if you stop looking after 80% of the list:   Copy vs Iterator on 80% of Collection (10,000 iterations) Collection Size Num Iterated Type Total ms 5 4 Copy 5 5 4 Iterator 5 50 40 Copy 27 50 40 Iterator 23 500 400 Copy 215 500 400 Iterator 200 5000 4000 Copy 2099 5000 4000 Iterator 1962 50,000 40,000 Copy 22,385 50,000 40,000 Iterator 19,599 500,000 400,000 Copy 236,427 500,000 400,000 Iterator 196,010       Notice that the iterator form is now operating quite a bit faster.  But the savings really add up if you stop on average at 50% (which most searches would typically do):     Copy vs Iterator on 50% of Collection (10,000 iterations) Collection Size Num Iterated Type Total ms 5 2 Copy 5 5 2 Iterator 4 50 25 Copy 25 50 25 Iterator 16 500 250 Copy 188 500 250 Iterator 126 5000 2500 Copy 1854 5000 2500 Iterator 1226 50,000 25,000 Copy 19,839 50,000 25,000 Iterator 12,233 500,000 250,000 Copy 208,667 500,000 250,000 Iterator 122,336   Now we see that if we only expect to go on average 50% into the results, we tend to shave off around 40% of the time.  And this is only for one level deep.  If we are using this in a chain of query expressions it only adds to the savings.   So my recommendation?  If you have a resonable expectation that someone may only want to partially consume your enumerable result, I would always tend to favor an iterator.  The cost if they iterate the whole thing does not add much at all -- and if they consume only partially, you reap some really good performance gains.   Next time I'll discuss some of my favorite extensions I've created to make development life a little easier and maintainability a little better.

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  • Specifying --host1 as localhost with port 8983 in autobench

    - by mamatha
    I am using autobench for benchmarking in ubuntu 8.10 autobench --single_host --host1 localhost --uri1 /solr/admin --low_rate 20 --high_rate 200 --rate_step 20 --num_call 10 --num_conn 5000 --timeout 5 --file bench1.tsv This is the command which I gave. It is taking the default port as 80 and the number of replies and requests are as shown below **Errors: total 5000 client-timo 0 socket-timo 0 connrefused 5000 connreset 0 Errors: fd-unavail 0 addrunavail 0 ftab-full 0 other 0 Zero replies received, test invalid: rate 20 httperf --timeout=5 --client=0/1 --server=localhost --port=80 --uri=/solr/admin --rate=40 --send-buffer=4096 --recv-buffer=16384 --num-conns=5000 --num-calls=10 Maximum connect burst length: 4 Total: connections 5000 requests 0 replies 0 test-duration 124.976 s** But, I want the port to be 8983. In all the examples that I have seen in the autobench tutorial, --host1 is a website (such as, www.test.com). Can anyone suggest how to use localhost taking the port as 8983? Thanks, in advance.

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  • how to declare object variable name in loop

    - by user3717895
    public class Node{ Node p,l,r; int height; String s; { /** class body**/ } } String[] S=new String[5000]; int i=0; while (i<5000){ Node x=new Node(); x=S[i]; } I want to make 5000 Node object. above code assign same variable name x every time but i want different variable name . then how to declare 5000 class variable name without declaring it manually. is there something by which i can create 5000 Node class object with ease.

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  • Why is PLINQ slower than LINQ for this code?

    - by Rob Packwood
    First off, I am running this on a dual core 2.66Ghz processor machine. I am not sure if I have the .AsParallel() call in the correct spot. I tried it directly on the range variable too and that was still slower. I don't understand why... Here are my results: Process non-parallel 1000 took 146 milliseconds Process parallel 1000 took 156 milliseconds Process non-parallel 5000 took 5187 milliseconds Process parallel 5000 took 5300 milliseconds using System; using System.Collections.Generic; using System.Diagnostics; using System.Linq; namespace DemoConsoleApp { internal class Program { private static void Main() { ReportOnTimedProcess( () => GetIntegerCombinations(), "non-parallel 1000"); ReportOnTimedProcess( () => GetIntegerCombinations(runAsParallel: true), "parallel 1000"); ReportOnTimedProcess( () => GetIntegerCombinations(5000), "non-parallel 5000"); ReportOnTimedProcess( () => GetIntegerCombinations(5000, true), "parallel 5000"); Console.Read(); } private static List<Tuple<int, int>> GetIntegerCombinations( int iterationCount = 1000, bool runAsParallel = false) { IEnumerable<int> range = Enumerable.Range(1, iterationCount); IEnumerable<Tuple<int, int>> integerCombinations = from x in range from y in range select new Tuple<int, int>(x, y); return runAsParallel ? integerCombinations.AsParallel().ToList() : integerCombinations.ToList(); } private static void ReportOnTimedProcess( Action process, string processName) { var stopwatch = new Stopwatch(); stopwatch.Start(); process(); stopwatch.Stop(); Console.WriteLine("Process {0} took {1} milliseconds", processName, stopwatch.ElapsedMilliseconds); } } }

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  • Algorithm to measure how "diffused" 5,000 pennies are in an economy?

    - by makerofthings7
    Please allow me to use this example/metaphor to describe an algorithm I need. Objects There are 5 thousand pennies. There are 50 cups. There is a tracking history (Passport "stamp" etc) that is associated with each penny as it moves between cups. Definition I'll define a "highly diffused" penny as one that passes through many cups. A "poorly diffused" penny is one that either passes back and forth between 2 cups Question How can I objectively measure the diffusion of a penny as: The number of moves the penny has gone through The number of cups the penny has been in A unit of time (day, week, month) Why am I doing this? I want to detect if a cup is hoarding pennies. Resistance from bad actors Since hoarding is bad, the "bad cup" may simply solicit a partner and simply move pennies between each other. This will reduce the amount of time a coin isn't in transit, and would skew hoarding detection. A solution might be to detect if a cup (or set of cups) are common "partners" with each other, though I'm not sure how to think though this problem. Broad applicability Any assistance would be helpful, since I would think that this algorithm is common to Economics The study of migration patterns of animals, citizens of a country Other natural occurring phenomena ... and probably exists as a term or concept I'm unfamiliar with.

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  • Folder to save images with AutoHotkey

    - by horiageorg
    When I try to save an image from a Web page with a program written in AutoHotkey,it always chooses the last folder I had chosen manually to save Web images. This is the script (assuming I'm on Web page and I want to save the images of a series of Web pages): FileSelectFolder, OutputVar, , 3 if OutputVar = MsgBox, You didn't select a folder. else MsgBox, You selected folder "%OutputVar%". Sleep 10000 Loop 25 { MouseClick, left, 185, 250 Sleep 5000 Send {ENTER} Sleep 5000 MouseClick, left, 75, 397 Sleep 5000 }

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  • Office 2007 constantly crashes, logged as Event ID 1000

    - by Nori
    I have a user, who despite my best efforts, is having constant Office 2007 crashes. I've tried deleting their profile and setting it up again, repairing office, uninstalling completely and then reinstalling, and swapping out memory sticks. One event log error I keep getting is the following: (note all the Office errors are event id 1000) Faulting application name: OUTLOOK.EXE, version: 12.0.6539.5000, time stamp: 0x4c12486d Faulting module name: EMSMDB32.DLL, version: 12.0.6539.5000, time stamp: 0x4c1246f8 Exception code: 0xc0000005 Fault offset: 0x0005d8e2 Faulting process id: 0xf6c Faulting application start time: 0x01cb6633f33384f3 Faulting application path: C:\Program Files (x86)\Microsoft Office\Office12\OUTLOOK.EXE Faulting module path: c:\progra~2\micros~1\office12\EMSMDB32.DLL Report Id: 0d4a2eab-d231-11df-80a0-4061868f5d10 I also get this: Faulting application name: OUTLOOK.EXE, version: 12.0.6539.5000, time stamp: 0x4c12486d Faulting module name: olmapi32.dll, version: 12.0.6538.5000, time stamp: 0x4bfc6ad9 Exception code: 0xc0000005 Fault offset: 0x002357a9 Faulting process id: 0x5e4 Faulting application start time: 0x01cb661f4546aa77 Faulting application path: C:\Program Files (x86)\Microsoft Office\Office12\OUTLOOK.EXE Faulting module path: c:\progra~2\micros~1\office12\olmapi32.dll Report Id: a4a90658-d224-11df-80a0-4061868f5d10 The Excel error is this: Faulting application name: EXCEL.EXE, version: 12.0.6535.5002, time stamp: 0x4bd2a7f1 Faulting module name: KERNELBASE.dll, version: 6.1.7600.16385, time stamp: 0x4a5bdbdf Exception code: 0xe06d7363 Fault offset: 0x0000b727 Faulting process id: 0x14a8 Faulting application start time: 0x01cb61ab7bc0abab Faulting application path: C:\Program Files (x86)\Microsoft Office\Office12\EXCEL.EXE Faulting module path: C:\Windows\syswow64\KERNELBASE.dll Report Id: ba0c454b-cd9e-11df-80a0-4061868f5d10 Also have gotten this for PowerPoint: Faulting application name: POWERPNT.EXE, version: 12.0.6500.5000, time stamp: 0x49a68f9d Faulting module name: COMShim.dll, version: 2010.3.325.110, time stamp: 0x4c51e0b1 Exception code: 0x40000015 Fault offset: 0x0001e388 Faulting process id: 0x1480 Faulting application start time: 0x01cb5fe9a0660e81 Faulting application path: C:\Program Files (x86)\Microsoft Office\Office12\POWERPNT.EXE Faulting module path: C:\Program Files (x86)\FactSet\COMShim.dll Report Id: e03d2a21-cbdc-11df-9bc8-4061868f5d10 (Some of the above lines edited to keep you from scroll horizontally.) Lastly, I get this error several times a day, I don't think it is related but maybe it is: Failed extract of third-party root list from auto update cab at: http://www.download.windowsupdate.com/msdownload/update/v3/static/trustedr/en/authrootstl.cab with error: A required certificate is not within its validity period when verifying against the current system clock or the timestamp in the signed file. Any ideas? This is driving me nuts.

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  • HTML5 data-* (custom data attribute)

    - by Renso
    Goal: Store custom data with the data attribute on any DOM element and retrieve it. Previously under HTML4 we used to use classes to store custom data, something to the affect of <input class="account void limit-5000 over-4999" /> and then have to parse the data out of the class In a book published by Peter-Paul Koch in 2007, ppk on JavaScript, he explains why and how to use custom attributes to make data more accessible to JavaScript, using name-value pairs. Accessing a custom attribute account-limit=5000 is much easier and more intuitive than trying to parse it out of a class, Plus, what if the class name for example "color-5" has a representative class definition in a CSS stylesheet that hides it away or worse some JavaScript plugin that automatically adds 5000 to it, or something crazy like that, just because it is a valid class name. As you can see there are quite a few reasons why using classes is a bad design and why it was important to define custom data attributes in HTML5. Syntax: You define the data attribute by simply prefixing any data item you want to store with any HTML element with "data-". For example to store our customers account data with a hidden input element: <input type="hidden" data-account="void" data-limit=5000 data-over=4999  /> How to access the data: account  -     element.dataset.account limit    -     element.dataset.limit You can also access it by using the more traditional get/setAttribute method or if using jQuery $('#element').attr('data-account','void') Browser support: All except for IE. There is an IE hack around this at http://gist.github.com/362081. Special Note: Be AWARE, do not use upper-case when defining your data elements as it is all converted to lower-case when reading it, so: data-myAccount="A1234" will not be found when you read it with: element.dataset.myAccount Use only lowercase when reading so this will work: element.dataset.myaccount

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  • Most efficient way to implement delta time

    - by Starkers
    Here's one way to implement delta time: /// init /// var duration = 5000, currentTime = Date.now(); // and create cube, scene, camera ect ////// function animate() { /// determine delta /// var now = Date.now(), deltat = now - currentTime, currentTime = now, scalar = deltat / duration, angle = (Math.PI * 2) * scalar; ////// /// animate /// cube.rotation.y += angle; ////// /// update /// requestAnimationFrame(render); ////// } Could someone confirm I know how it works? Here what I think is going on: Firstly, we set duration at 5000, which how long the loop will take to complete in an ideal world. With a computer that is slow/busy, let's say the animation loop takes twice as long as it should, so 10000: When this happens, the scalar is set to 2.0: scalar = deltat / duration scalar = 10000 / 5000 scalar = 2.0 We now times all animation by twice as much: angle = (Math.PI * 2) * scalar; angle = (Math.PI * 2) * 2.0; angle = (Math.PI * 4) // which is 2 rotations When we do this, the cube rotation will appear to 'jump', but this is good because the animation remains real-time. With a computer that is going too quickly, let's say the animation loop takes half as long as it should, so 2500: When this happens, the scalar is set to 0.5: scalar = deltat / duration scalar = 2500 / 5000 scalar = 0.5 We now times all animation by a half: angle = (Math.PI * 2) * scalar; angle = (Math.PI * 2) * 0.5; angle = (Math.PI * 1) // which is half a rotation When we do this, the cube won't jump at all, and the animation remains real time, and doesn't speed up. However, would I be right in thinking this doesn't alter how hard the computer is working? I mean it still goes through the loop as fast as it can, and it still has render the whole scene, just with different smaller angles! So this a bad way to implement delta time, right? Now let's pretend the computer is taking exactly as long as it should, so 5000: When this happens, the scalar is set to 1.0: angle = (Math.PI * 2) * scalar; angle = (Math.PI * 2) * 1; angle = (Math.PI * 2) // which is 1 rotation When we do this, everything is timsed by 1, so nothing is changed. We'd get the same result if we weren't using delta time at all! My questions are as follows Mostly importantly, have I got the right end of the stick here? How do we know to set the duration to 5000 ? Or can it be any number? I'm a bit vague about the "computer going too quickly". Is there a way loop less often rather than reduce the animation steps? Seems like a better idea. Using this method, do all of our animations need to be timesed by the scalar? Do we have to hunt down every last one and times it? Is this the best way to implement delta time? I think not, due to the fact the computer can go nuts and all we do is divide each animation step and because we need to hunt down every step and times it by the scalar. Not a very nice DSL, as it were. So what is the best way to implement delta time? Below is one way that I do not really get but may be a better way to implement delta time. Could someone explain please? // Globals INV_MAX_FPS = 1 / 60; frameDelta = 0; clock = new THREE.Clock(); // In the animation loop (the requestAnimationFrame callback)… frameDelta += clock.getDelta(); // API: "Get the seconds passed since the last call to this method." while (frameDelta >= INV_MAX_FPS) { update(INV_MAX_FPS); // calculate physics frameDelta -= INV_MAX_FPS; } How I think this works: Firstly we set INV_MAX_FPS to 0.01666666666 How we will use this number number does not jump out at me. We then intialize a frameDelta which stores how long the last loop took to run. Come the first loop frameDelta is not greater than INV_MAX_FPS so the loop is not run (0 = 0.01666666666). So nothing happens. Now I really don't know what would cause this to happen, but let's pretend that the loop we just went through took 2 seconds to complete: We set frameDelta to 2: frameDelta += clock.getDelta(); frameDelta += 2.00 Now we run an animation thanks to update(0.01666666666). Again what is relevance of 0.01666666666?? And then we take away 0.01666666666 from the frameDelta: frameDelta -= INV_MAX_FPS; frameDelta = frameDelta - INV_MAX_FPS; frameDelta = 2 - 0.01666666666 frameDelta = 1.98333333334 So let's go into the second loop. Let's say it took 2(? Why not 2? Or 12? I am a bit confused): frameDelta += clock.getDelta(); frameDelta = frameDelta + clock.getDelta(); frameDelta = 1.98333333334 + 2 frameDelta = 3.98333333334 This time we enter the while loop because 3.98333333334 = 0.01666666666 We run update We take away 0.01666666666 from frameDelta again: frameDelta -= INV_MAX_FPS; frameDelta = frameDelta - INV_MAX_FPS; frameDelta = 3.98333333334 - 0.01666666666 frameDelta = 3.96666666668 Now let's pretend the loop is super quick and runs in just 0.1 seconds and continues to do this. (Because the computer isn't busy any more). Basically, the update function will be run, and every loop we take away 0.01666666666 from the frameDelta untill the frameDelta is less than 0.01666666666. And then nothing happens until the computer runs slowly again? Could someone shed some light please? Does the update() update the scalar or something like that and we still have to times everything by the scalar like in the first example?

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  • Efficient way to check for changes to the contents of folders

    - by MrVimes
    I am creating an application that maintains a database of files of a certain type in a given folder (and all subfolders) Initially the program will recurse the folders and add any file it finds of that type to the database. I want the application to have the ability to re-scan the folder and add any files that were not there the last time the folders were scanned. It can't use the date created property of the file because there is a high chance of a file being added to the folders that isn't a new file. I am wondering what the most efficient way of doing this is, and if there is a way that doesn't involve checking each file is in the database already (which, if there are 5000 files would mean 5000 queries of a list 5000 items in size, or 25 million 'checks' for the sql engine to perform) I suppose a more specific question to acheive the same goal would be - is there a property of a file (in Microsoft Windows) that will reliably tell you when that file arrived in that folder.

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  • WCF binding programatically and adding metadata excange

    - by totem
    Hi, My problem is im trying to enable mex on a service that uses net.tcp binding. that binding is for localhost port 5000, when i want to enable mex on the same port, and have it avilable for http i have to enable the HttpGetEnabled on the Service host. All this works well but when i try to add the binding it fails becuase the binding is "net.tcp://localhost:5000/test". is there a way to enable mex on the same port but with a diffrent uri? Without enableing NetTcpPortSharing. I dont think the code is the issue since i can add the MEX on a diffrent port through the code an it works fine, the question is how to have net.tcp://localhost:5000/test as the WCF tcp based enpoint and net.tcp://localhost:5000/test/mex as the http mex endpoint that gives the WSDL for the TCP endpoint. thanks, Totem

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  • How to make a Round Robin? or Is there an easier way other than Round Robin?

    - by candies
    The problem that I face is in what way if there is issue like the example below: Codes 1000, 2000, 3000, 4000, 5000 ID 1, 2, 3 ======================================== This: ID number 1 has codes 1000, 2000, 3000, 4000 ID number 2 has codes 2000, 4000, 3000 ID number 3 has codes 3000, 4000, 5000 ======================================== When all the fields are connected, each ID has found the same codes. From the example above, I want to produce fair result and adjusted to the code that it had before on each ID as below: ======================================== To be: ID number 1 has codes 1000, 2000 (1000 must be on number 1 cause only it has than other) ID number 2 has codes 3000, 4000 ID number 3 has codes 5000 (5000 must be on number 3 cause only it has than other) ======================================== Some say using Round Robin, but I never heard Round Robin before and I don't have idea how to use it, such a blank mind. Is there another easier way like to use PHP may be? I'm lost. Thanks.

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  • Get data types from arbitrary sql statement in SQL Server 2008

    - by Christopherous 5000
    Given some arbitrary SQL I would like to get the data types of the returned columns. The statement might join many tables, views, TVFs, etc. I know I could create a view based on the query and get the datatypes from that, hoping there's a quicker way. Only think I've been able to think of is writing a .net utility to run the SQL and examine the results, wondering if there is a TSQL answer. i.e. Given (not real tables just an example) SELECT p.Name AS PersonName, p.Age, a.Account as AccountName FROM Person as p LEFT JOIN Account as a ON p.Id = a.OwnerId I would like to have something like PersonName: (nvarchar(255), not null) Age: (smallInt, not null) etc...

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  • Confusing of TTimeSpan usage in Delphi 2010

    - by stanleyxu2005
    Hi All, I tried the new Record type TTimeSpan in Delphi 2010. But I encourage a very strange problem. assert(TTimeSpan.FromMilliseconds(5000).Milliseconds == 5000); This assertion does not pass. The value of 'TTimeSpan.FromMilliseconds(5000).Milliseconds' is always 0. I really cannot explain.

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  • Truly understand the threshold for document set in document library in SharePoint

    - by ybbest
    Recently, I am working on an issue with threshold. The problem is that when the user navigates to a view of the document library, it displays the error message “list view threshold is exceeded”. However, in the view, it has no data. The list view threshold limit is 5000 by default for the non-admin user. This limit is not the number of items returned by your query; it is the total number of items the database needs to read to calculate the returned result set. So although the view does not return any result but to calculate the result (no data to show), it needs to access more than 5000 items in the database. To fix the issue, you need to create an index for the column that you use in the filter for the view. Let’s look at the problem in details. You can download a solution to replicate this issue here. 1. Go to Central Admin ==> Web Application Management ==>General Settings==> Click on Resource Throttling 2. Change the list view threshold in web application from 5000 to 2000 so that I can show the problem without loading more than 5000 items into the list. FROM TO 3. Go to the page that displays the approved view of the Loan application document set. It displays the message as shown below although I do not have any data returned for this view. 4. To get around this, you need to create an index column. Go to list settings and click on the Index columns. 5. Click on the “Create a new index” link. 6. Select the LoanStatus field as I use this filed as the filter to create the view. 7. After the index is created now I can access the approved view, as you can see it does not return any data. Notes: List View Threshold: Specify the maximum number of items that a database operation can involve at one time. Operations that exceed this limit are prohibited. References: SharePoint lists V: Techniques for managing large lists Manage large SharePoint lists for better performance http://blogs.technet.com/b/speschka/archive/2009/10/27/working-with-large-lists-in-sharepoint-2010-list-throttling.aspx

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  • Cumulative Update #1 for SQL Server 2005 SP4

    - by AaronBertrand
    Well, much quicker than I would have suspected, the SQL Server Release Services team has incorporated all of the fixes in 2005 SP3's CU #12 into the first CU for SP4. Thanks to Chris Wood for the heads up. You can get the new Cumulative Update here: KB #2464079 : Cumulative update package 1 for SQL Server 2005 Service Pack 4 The nice round number of build 5000 didn't last long either; this CU will update you from 9.00.5000 to 9.00.5254....(read more)

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  • Postfix mail server: can't connect via POP/IMAP

    - by MelkerOVan
    I've followed this guide on setting up a mail server on my dedicated server. I've been able to send mails from the php application I'm using and the linux commandline (using telnet, php, etc). The problem is that I cannot connect to the server via IMAP/POP which I've setup using Courier. I've tried using thunderbird but it complains that the username or password is wrong. I doubt it is the username/password but I don't know how to trouble shoot this. Edit: Here's the messages in mail.log: Jan 9 22:43:38 mail authdaemond: received auth request, service=imap, authtype=login Jan 9 22:43:38 mail authdaemond: authmysql: trying this module Jan 9 22:43:38 mail authdaemond: SQL query: SELECT id, crypt, "", uid, gid, home, "", "", name, "" FROM users WHERE id = '[email protected]' AND (enabled=1) Jan 9 22:43:38 mail authdaemond: password matches successfully Jan 9 22:43:38 mail authdaemond: authmysql: sysusername=<null>, sysuserid=5000, sysgroupid=5000, homedir=/var/spool/mail/virtual, [email protected], fullname=peter, maildir=<null>, quota=<null>, options=<null> Jan 9 22:43:38 mail authdaemond: authmysql: clearpasswd=<null>, passwd=6SrBcYq65l8QU Jan 9 22:43:38 mail authdaemond: Authenticated: sysusername=<null>, sysuserid=5000, sysgroupid=5000, homedir=/var/spool/mail/virtual, [email protected], fullname=peter, maildir=<null>, quota=<null>, options=<null> Jan 9 22:43:38 mail authdaemond: Authenticated: clearpasswd=peter, passwd=6SrBcYq65l8QU Jan 9 22:43:38 mail imapd: chdir Maildir: No such file or directory

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  • Unable to receive any emails using postfix, dovecot, mysql, and virtual domain/mailboxes

    - by stkdev248
    I have been working on configuring my mail server for the last couple of weeks using postfix, dovecot, and mysql. I have one virtual domain and a few virtual mailboxes. Using squirrelmail I have been able to log into my accounts and send emails out (e.g. I can send to googlemail just fine), however I am not able to receive any emails--not from the outside world nor from within my own network. I am able to telnet in using localhost, my private ip, and my public ip on port 25 without any problems (I've tried it from the server itself and from another computer on my network). This is what I get in my logs when I send an email from my googlemail account to my mail server: mail.log Apr 14 07:36:06 server1 postfix/qmgr[1721]: BE01B520538: from=, size=733, nrcpt=1 (queue active) Apr 14 07:36:06 server1 postfix/pipe[3371]: 78BC0520510: to=, relay=dovecot, delay=45421, delays=45421/0/0/0.13, dsn=4.3.0, status=deferred (temporary failure. Command output: Can't open log file /var/log/mail-dovecot.log: Permission denied) Apr 14 07:36:06 server1 postfix/pipe[3391]: 8261B520534: to=, relay=dovecot, delay=38036, delays=38036/0.06/0/0.12, dsn=4.3.0, status=deferred (temporary failure. Command output: Can't open log file /var/log/mail-dovecot.log: Permission denied ) Apr 14 07:36:06 server1 postfix/pipe[3378]: 63927520532: to=, relay=dovecot, delay=38105, delays=38105/0.02/0/0.17, dsn=4.3.0, status=deferred (temporary failure. Command output: Can't open log file /var/log/mail-dovecot.log: Permission denied ) Apr 14 07:36:06 server1 postfix/pipe[3375]: 07F65520522: to=, relay=dovecot, delay=39467, delays=39467/0.01/0/0.17, dsn=4.3.0, status=deferred (temporary failure. Command output: Can't open log file /var/log/mail-dovecot.log: Permission denied ) Apr 14 07:36:06 server1 postfix/pipe[3381]: EEDE9520527: to=, relay=dovecot, delay=38361, delays=38360/0.04/0/0.15, dsn=4.3.0, status=deferred (temporary failure. Command output: Can't open log file /var/log/mail-dovecot.log: Permission denied ) Apr 14 07:36:06 server1 postfix/pipe[3379]: 67DFF520517: to=, relay=dovecot, delay=40475, delays=40475/0.03/0/0.16, dsn=4.3.0, status=deferred (temporary failure. Command output: Can't open log file /var/log/mail-dovecot.log: Permission denied ) Apr 14 07:36:06 server1 postfix/pipe[3387]: 3C7A052052E: to=, relay=dovecot, delay=38259, delays=38259/0.05/0/0.13, dsn=4.3.0, status=deferred (temporary failure. Command output: Can't open log file /var/log/mail-dovecot.log: Permission denied ) Apr 14 07:36:06 server1 postfix/pipe[3394]: BE01B520538: to=, relay=dovecot, delay=37682, delays=37682/0.07/0/0.11, dsn=4.3.0, status=deferred (temporary failure. Command output: Can't open log file /var/log/mail-dovecot.log: Permission denied ) Apr 14 07:36:07 server1 postfix/pipe[3384]: 3C7A052052E: to=, relay=dovecot, delay=38261, delays=38259/0.04/0/1.3, dsn=4.3.0, status=deferred (temporary failure. Command output: Can't open log file /var/log/mail-dovecot.log: Permission denied ) Apr 14 07:39:23 server1 postfix/anvil[3368]: statistics: max connection rate 1/60s for (smtp:209.85.213.169) at Apr 14 07:35:32 Apr 14 07:39:23 server1 postfix/anvil[3368]: statistics: max connection count 1 for (smtp:209.85.213.169) at Apr 14 07:35:32 Apr 14 07:39:23 server1 postfix/anvil[3368]: statistics: max cache size 1 at Apr 14 07:35:32 Apr 14 07:41:06 server1 postfix/qmgr[1721]: ED6005203B7: from=, size=1463, nrcpt=1 (queue active) Apr 14 07:41:06 server1 postfix/pipe[4594]: ED6005203B7: to=, relay=dovecot, delay=334, delays=334/0.01/0/0.13, dsn=4.3.0, status=deferred (temporary failure. Command output: Can't open log file /var/log/mail-dovecot.log: Permission denied ) Apr 14 07:51:06 server1 postfix/qmgr[1721]: ED6005203B7: from=, size=1463, nrcpt=1 (queue active) Apr 14 07:51:06 server1 postfix/pipe[4604]: ED6005203B7: to=, relay=dovecot, delay=933, delays=933/0.02/0/0.12, dsn=4.3.0, status=deferred (temporary failure. Command output: Can't open log file /var/log/mail-dovecot.log: Permission denied ) mail-dovecot-log (the log I set for debugging): Apr 14 07:28:26 auth: Info: mysql(127.0.0.1): Connected to database postfixadmin Apr 14 07:28:26 auth: Debug: sql([email protected],127.0.0.1): query: SELECT password FROM mailbox WHERE username = '[email protected]' Apr 14 07:28:26 auth: Debug: client out: OK 1 [email protected] Apr 14 07:28:26 auth: Debug: master in: REQUEST 1809973249 3356 1 7cfb822db820fc5da67d0776b107cb3f Apr 14 07:28:26 auth: Debug: sql([email protected],127.0.0.1): SELECT '/home/vmail/mydomain.com/some.user1' as home, 5000 AS uid, 5000 AS gid FROM mailbox WHERE username = '[email protected]' Apr 14 07:28:26 auth: Debug: master out: USER 1809973249 [email protected] home=/home/vmail/mydomain.com/some.user1 uid=5000 gid=5000 Apr 14 07:28:26 imap-login: Info: Login: user=, method=PLAIN, rip=127.0.0.1, lip=127.0.0.1, mpid=3360, secured Apr 14 07:28:26 imap([email protected]): Debug: Effective uid=5000, gid=5000, home=/home/vmail/mydomain.com/some.user1 Apr 14 07:28:26 imap([email protected]): Debug: maildir++: root=/home/vmail/mydomain.com/some.user1/Maildir, index=/home/vmail/mydomain.com/some.user1/Maildir/indexes, control=, inbox=/home/vmail/mydomain.com/some.user1/Maildir Apr 14 07:48:31 imap([email protected]): Info: Disconnected: Logged out bytes=85/681 From the output above I'm pretty sure that my problems all stem from (temporary failure. Command output: Can't open log file /var/log/mail-dovecot.log: Permission denied ), but I have no idea why I'm getting that error. I've have the permissions to that log set just like the other mail logs: root@server1:~# ls -l /var/log/mail* -rw-r----- 1 syslog adm 196653 2012-04-14 07:58 /var/log/mail-dovecot.log -rw-r----- 1 syslog adm 62778 2012-04-13 21:04 /var/log/mail.err -rw-r----- 1 syslog adm 497767 2012-04-14 08:01 /var/log/mail.log Does anyone have any idea what I may be doing wrong? Here are my main.cf and master.cf files: main.cf: # See /usr/share/postfix/main.cf.dist for a commented, more complete version # Debian specific: Specifying a file name will cause the first # line of that file to be used as the name. The Debian default # is /etc/mailname. #myorigin = /etc/mailname smtpd_banner = $myhostname ESMTP $mail_name (Ubuntu) biff = no # appending .domain is the MUA's job. append_dot_mydomain = no # Uncomment the next line to generate "delayed mail" warnings #delay_warning_time = 4h readme_directory = no # TLS parameters smtpd_tls_cert_file=/etc/ssl/certs/ssl-cert-snakeoil.pem smtpd_tls_key_file=/etc/ssl/private/ssl-cert-snakeoil.key smtpd_use_tls=yes smtpd_tls_session_cache_database = btree:${data_directory}/smtpd_scache smtp_tls_session_cache_database = btree:${data_directory}/smtp_scache # See /usr/share/doc/postfix/TLS_README.gz in the postfix-doc package for # information on enabling SSL in the smtp client. myhostname = server1.mydomain.com alias_maps = hash:/etc/aliases alias_database = hash:/etc/aliases myorigin = /etc/mailname mydestination = relayhost = mynetworks = 127.0.0.0/8 [::ffff:127.0.0.0]/104 [::1]/128 mailbox_command = procmail -a "$EXTENSION" mailbox_size_limit = 0 recipient_delimiter = + inet_interfaces = all # Virtual Configs virtual_uid_maps = static:5000 virtual_gid_maps = static:5000 virtual_mailbox_base = /home/vmail virtual_mailbox_domains = mysql:/etc/postfix/mysql_virtual_mailbox_domains.cf virtual_mailbox_maps = mysql:/etc/postfix/mysql_virtual_mailbox_maps.cf virtual_alias_maps = mysql:/etc/postfix/mysql_virtual_alias_maps.cf relay_domains = mysql:/etc/postfix/mysql_relay_domains.cf smtpd_recipient_restrictions = permit_mynetworks, permit_sasl_authenticated, reject_non_fqdn_hostname, reject_non_fqdn_sender, reject_non_fqdn_recipient, reject_unauth_destination, reject_unauth_pipelining, reject_invalid_hostname smtpd_sasl_auth_enable = yes smtpd_sasl_security_options = noanonymous virtual_transport=dovecot dovecot_destination_recipient_limit = 1 master.cf: # # Postfix master process configuration file. For details on the format # of the file, see the master(5) manual page (command: "man 5 master"). # # Do not forget to execute "postfix reload" after editing this file. # # ========================================================================== # service type private unpriv chroot wakeup maxproc command + args # (yes) (yes) (yes) (never) (100) # ========================================================================== smtp inet n - - - - smtpd #smtp inet n - - - 1 postscreen #smtpd pass - - - - - smtpd #dnsblog unix - - - - 0 dnsblog #tlsproxy unix - - - - 0 tlsproxy #submission inet n - - - - smtpd # -o smtpd_tls_security_level=encrypt # -o smtpd_sasl_auth_enable=yes # -o smtpd_client_restrictions=permit_sasl_authenticated,reject # -o milter_macro_daemon_name=ORIGINATING #smtps inet n - - - - smtpd # -o smtpd_tls_wrappermode=yes # -o smtpd_sasl_auth_enable=yes # -o smtpd_client_restrictions=permit_sasl_authenticated,reject # -o milter_macro_daemon_name=ORIGINATING #628 inet n - - - - qmqpd pickup fifo n - - 60 1 pickup cleanup unix n - - - 0 cleanup qmgr fifo n - n 300 1 qmgr #qmgr fifo n - - 300 1 oqmgr tlsmgr unix - - - 1000? 1 tlsmgr rewrite unix - - - - - trivial-rewrite bounce unix - - - - 0 bounce defer unix - - - - 0 bounce trace unix - - - - 0 bounce verify unix - - - - 1 verify flush unix n - - 1000? 0 flush proxymap unix - - n - - proxymap proxywrite unix - - n - 1 proxymap smtp unix - - - - - smtp # When relaying mail as backup MX, disable fallback_relay to avoid MX loops relay unix - - - - - smtp -o smtp_fallback_relay= # -o smtp_helo_timeout=5 -o smtp_connect_timeout=5 showq unix n - - - - showq error unix - - - - - error retry unix - - - - - error discard unix - - - - - discard local unix - n n - - local virtual unix - n n - - virtual lmtp unix - - - - - lmtp anvil unix - - - - 1 anvil scache unix - - - - 1 scache # # ==================================================================== # Interfaces to non-Postfix software. Be sure to examine the manual # pages of the non-Postfix software to find out what options it wants. # # Many of the following services use the Postfix pipe(8) delivery # agent. See the pipe(8) man page for information about ${recipient} # and other message envelope options. # ==================================================================== # # maildrop. See the Postfix MAILDROP_README file for details. # Also specify in main.cf: maildrop_destination_recipient_limit=1 # maildrop unix - n n - - pipe flags=DRhu user=vmail argv=/usr/bin/maildrop -d ${recipient} # # ==================================================================== # # Recent Cyrus versions can use the existing "lmtp" master.cf entry. # # Specify in cyrus.conf: # lmtp cmd="lmtpd -a" listen="localhost:lmtp" proto=tcp4 # # Specify in main.cf one or more of the following: # mailbox_transport = lmtp:inet:localhost # virtual_transport = lmtp:inet:localhost # # ==================================================================== # # Cyrus 2.1.5 (Amos Gouaux) # Also specify in main.cf: cyrus_destination_recipient_limit=1 # #cyrus unix - n n - - pipe # user=cyrus argv=/cyrus/bin/deliver -e -r ${sender} -m ${extension} ${user} # # ==================================================================== # Old example of delivery via Cyrus. # #old-cyrus unix - n n - - pipe # flags=R user=cyrus argv=/cyrus/bin/deliver -e -m ${extension} ${user} # # ==================================================================== # # See the Postfix UUCP_README file for configuration details. # uucp unix - n n - - pipe flags=Fqhu user=uucp argv=uux -r -n -z -a$sender - $nexthop!rmail ($recipient) # # Other external delivery methods. # ifmail unix - n n - - pipe flags=F user=ftn argv=/usr/lib/ifmail/ifmail -r $nexthop ($recipient) bsmtp unix - n n - - pipe flags=Fq. user=bsmtp argv=/usr/lib/bsmtp/bsmtp -t$nexthop -f$sender $recipient scalemail-backend unix - n n - 2 pipe flags=R user=scalemail argv=/usr/lib/scalemail/bin/scalemail-store ${nexthop} ${user} ${extension} mailman unix - n n - - pipe flags=FR user=list argv=/usr/lib/mailman/bin/postfix-to-mailman.py ${nexthop} ${user} dovecot unix - n n - - pipe flags=DRhu user=vmail:vmail argv=/usr/lib/dovecot/deliver -d ${recipient}

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  • Mail server: can't connect via POP/IMAP

    - by MelkerOVan
    I've followed this guide on setting up a mail server on my dedicated server. I've been able to send mails from the php application I'm using and the linux commandline (using telnet, php, etc). The problem is that I cannot connect to the server via IMAP/POP which I've setup using Courier. I've tried using thunderbird but it complains that the username or password is wrong. I doubt it is the username/password but I don't know how to trouble shoot this. Edit: Here's the messages in mail.log: Jan 9 22:43:38 mail authdaemond: received auth request, service=imap, authtype=login Jan 9 22:43:38 mail authdaemond: authmysql: trying this module Jan 9 22:43:38 mail authdaemond: SQL query: SELECT id, crypt, "", uid, gid, home, "", "", name, "" FROM users WHERE id = '[email protected]' AND (enabled=1) Jan 9 22:43:38 mail authdaemond: password matches successfully Jan 9 22:43:38 mail authdaemond: authmysql: sysusername=<null>, sysuserid=5000, sysgroupid=5000, homedir=/var/spool/mail/virtual, [email protected], fullname=peter, maildir=<null>, quota=<null>, options=<null> Jan 9 22:43:38 mail authdaemond: authmysql: clearpasswd=<null>, passwd=password Jan 9 22:43:38 mail authdaemond: Authenticated: sysusername=<null>, sysuserid=5000, sysgroupid=5000, homedir=/var/spool/mail/virtual, [email protected], fullname=peter, maildir=<null>, quota=<null>, options=<null> Jan 9 22:43:38 mail authdaemond: Authenticated: clearpasswd=peter, passwd=password Jan 9 22:43:38 mail imapd: chdir Maildir: No such file or directory

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  • Courier IMAP always disconnects since update

    - by Raffael Luthiger
    Since one of our customers updated their server courier does not handle IMAP connections properly any more. POP3 works without any problems. When I try to test IMAP with telnet then it is always like this: $ telnet domain.com 143 Trying 188.40.46.214... Connected to domain.com. Escape character is '^]'. * OK [CAPABILITY IMAP4rev1 UIDPLUS CHILDREN NAMESPACE THREAD=ORDEREDSUBJECT THREAD=REFERENCES SORT QUOTA IDLE ACL ACL2=UNION STARTTLS] Courier-IMAP ready. Copyright 1998-2011 Double Precision, Inc. See COPYING for distribution information. 01 LOGIN [email protected] test Connection closed by foreign host. I enabled debugging in the authdaemond but the output does not really help much: Apr 12 23:10:04 servername authdaemond: received auth request, service=imap, authtype=login Apr 12 23:10:04 servername authdaemond: authmysql: trying this module Apr 12 23:10:04 servername authdaemond: SQL query: SELECT login, password, "", uid, gid, homedir, maildir, quota, "", concat('disableimap=',disableimap,',disablepop3=',disablepop3) FROM mail_user WHERE login = '[email protected]' Apr 12 23:10:04 servername authdaemond: password matches successfully Apr 12 23:10:04 servername authdaemond: authmysql: sysusername=<null>, sysuserid=5000, sysgroupid=5000, homedir=/var/vmail, [email protected], fullname=<null>, maildir=/var/vmail/domain.com/test, quota=0, options=disableimap=n,disablepop3=n Apr 12 23:10:04 servername authdaemond: Authenticated: sysusername=<null>, sysuserid=5000, sysgroupid=5000, homedir=/var/vmail, [email protected], fullname=<null>, maildir=/var/vmail/domain.com/test, quota=0, options=disableimap=n,disablepop3=n Right after the "Authenticated" line the output stops. There is no other message. And in no other log file I've checked I could find any other related message. The system was updated from Ubuntu 10.10 to 12.04. How could I get more information? Or does anybody have an idea what could go wrong here?

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  • Multiple *NIX Accounts with Identical UID

    - by Tim
    I am curious whether there is a standard expected behavior and whether it is considered bad practice when creating more than one account on Linux/Unix that have the same UID. I've done some testing on RHEL5 with this and it behaved as I expected, but I don't know if I'm tempting fate using this trick. As an example, let's say I have two accounts with the same IDs: a1:$1$4zIl1:5000:5000::/home/a1:/bin/bash a2:$1$bmh92:5000:5000::/home/a2:/bin/bash What this means is: I can log in to each account using its own password. Files I create will have the same UID. Tools such as "ls -l" will list the UID as the first entry in the file (a1 in this case). I avoid any permissions or ownership problems between the two accounts because they are really the same user. I get login auditing for each account, so I have better granularity into tracking what is happening on the system. So my questions are: Is this ability designed or is it just the way it happens to work? Is this going to be consistent across *nix variants? Is this accepted practice? Are there unintended consequences to this practice? Note, the idea here is to use this for system accounts and not normal user accounts.

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  • How big can my SharePoint 2010 installation be?

    - by Sahil Malik
    Ad:: SharePoint 2007 Training in .NET 3.5 technologies (more information). 3 years ago, I had published “How big can my SharePoint 2007 installation be?” Well, SharePoint 2010 has significant under the covers improvements. So, how big can your SharePoint 2010 installation be? There are three kinds of limits you should know about Hard limits that cannot be exceeded by design. Configurable that are, well configurable – but the default values are set for a pretty good reason, so if you need to tweak, plan and understand before you tweak. Soft limits, you can exceed them, but it is not recommended that you do. Before you read any of the limits, read these two important disclaimers - 1. The limit depends on what you’re doing. So, don’t take the below as gospel, the reality depends on your situation. 2. There are many additional considerations in planning your SharePoint solution scalability and performance, besides just the below. So with those in mind, here goes.   Hard Limits - Zones per web app 5 RBS NAS performance Time to first byte of any response from NAS must be less than 20 milliseconds List row size 8000 bytes driven by how SP stores list items internally Max file size 2GB (default is 50MB, configurable). RBS does not increase this limit. Search metadata properties 10,000 per item crawled (pretty damn high, you’ll never need to worry about it). Max # of concurrent in-memory enterprise content types 5000 per web server, per tenant Max # of external system connections 500 per web server PerformancePoint services using Excel services as a datasource No single query can fetch more than 1 million excel cells Office Web Apps Renders One doc per second, per CPU core, per Application server, limited to a maximum of 8 cores.   Configurable Limits - Row Size Limit 6, configurable via SPWebApplication.MaxListItemRowStorage property List view lookup 8 join operations per query Max number of list items that a single operation can process at one time in normal hours 5000 Configurable via SPWebApplication.MaxItemsPerThrottledOperation   Also you get a warning at 3000, which is configurable via SPWebApplication.MaxItemsPerThrottledOperationWarningLevel   In addition, throttle overrides can be requested, throttle overrides can be disabled, and time windows can be set when throttle is disabled. Max number of list items for administrators that a single operation can process at one time in normal hours 20000 Configurable via SPWebApplication.MaxItemsPerThrottledOperationOverride Enumerating subsites 2000 Word and Powerpoint co-authoring simultaneous editors 10 (Hard limit is 99). # of webparts on a page 25 Search Crawl DBs per search service app 10 Items per crawl db 25 million Search Keywords 200 per site collection. There is a max limit of 5000, which can then be modified by editing the web.config/client.config. Concurrent # of workflows on a content db 15. Workflows running in the timer service are not counted in this limit. Further workflows are queued. Can be configured via the Set-SPFarmConfig powershell commandlet. Number of events picked by the workflow timer job and delivered to workflows 100. You can increase this limit by running additional instances of the workflow timer service. Visio services file size 50MB Visio web drawing recalculation timeout 120 seconds Configurable via – Powershell commandlet Set-SPVisioPerformance Visio services minimum and maximum cache age for data connected diagrams 0 to 24 hours. Default is 60 minutes. Configurable via – Powershell commandlet Set-SPVisioPerformance   Soft Limits - Content Databases 300 per web app Application Pools 10 per web server Managed Paths 20 per web app Content Database Size 200GB per Content DB Size of 1 site collection 100GB # of sites in a site collection 250,000 Documents in a library 30 Million, with nesting. Depends heavily on type and usage and size of documents. Items 30 million. Depends heavily on usage of items. SPGroups one SPUser can be in 5000 Users in a site collection 2 million, depends on UI, nesting, containers and underlying user store AD Principals in a SPGroup 5000 SPGroups in a site collection 10000 Search Service Instances 20 Indexed Items in Search 100 million Crawl Log entries 100 million Search Alerts 1 million per search application Search Crawled Properties 1/2 million URL removals in search 100 removals per operation User Profiles 2 million per service application Social Tags 500 million per social database Comment on the article ....

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