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  • How to display specific data from a file

    - by user1067332
    My program is supposed to ask the user for firstname, lastname, and phone number till the users stops. Then when to display it asks for the first name and does a search in the text file to find all info with the same first name and display lastname and phones of the matches. import java.util.*; import java.io.*; import java.util.Scanner; public class WritePhoneList { public static void main(String[] args)throws IOException { BufferedWriter output = new BufferedWriter(new FileWriter(new File( "PhoneFile.txt"), true)); String name, lname, age; int pos,choice; try { do { Scanner input = new Scanner(System.in); System.out.print("Enter First name, last name, and phone number "); name = input.nextLine(); output.write(name); output.newLine(); System.out.print("Would you like to add another? yes(1)/no(2)"); choice = input.nextInt(); }while(choice == 1); output.close(); } catch(Exception e) { System.out.println("Message: " + e); } } } Here is the display code, when i search for a name, it finds a match but displays the last name and phone number of the same name 3 times, I want it to display all of the possible matches with the first name. import java.util.*; import java.io.*; import java.util.Scanner; public class DisplaySelectedNumbers { public static void main(String[] args)throws IOException { String name; String strLine; try { FileInputStream fstream = new FileInputStream("PhoneFile.txt"); // Get the object of DataInputStream DataInputStream in = new DataInputStream(fstream); BufferedReader br = new BufferedReader(new InputStreamReader(in)); Scanner input = new Scanner(System.in); System.out.print("Enter a first name"); name = input.nextLine(); strLine= br.readLine(); String[] line = strLine.split(" "); String part1 = line[0]; String part2 = line[1]; String part3 = line[2]; //Read File Line By Line while ((strLine= br.readLine()) != null) { if(name.equals(part1)) { // Print the content on the console System.out.print("\n" + part2 + " " + part3); } } }catch (Exception e) {//Catch exception if any System.out.println("Error: " + e.getMessage()); } } }

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  • java timer and socket problem

    - by Guru
    Hi there, I'm trying to make a program which listens to the client input stream by using socket programming and timer but whenever timer executes.. it gets hanged Please help me out here is the code... private void jButton1MouseClicked(java.awt.event.MouseEvent evt) { // TODO add your handling code here: try { ServerUserName=jTextField1.getText(); ss=new ServerSocket(5000); jButton1.enable(false); jTextArea1.enable(true); jTextField2.enable(true); Timer t=new Timer(2000, new ActionListener() { public void actionPerformed(ActionEvent e) { try { s=ss.accept(); InputStream is=s.getInputStream(); DataInputStream dis=new DataInputStream(is); jTextArea1.append(dis.readUTF()); } catch(IOException IOE) { } catch(Exception ex) { setLbl(ex.getMessage()); } } }); t.start(); } catch(IOException IOE) { } } Thanks in advance

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  • Programming error in Java Socket

    - by Akhil K Nambiar
    Can you tell me what is the error in this code? Socket socket = new Socket(hostname, port); PrintWriter out = new PrintWriter(socket.getOutputStream(), true); //DataInputStream is = new DataInputStream(socket.getInputStream()); out.println("hi"); System.out.print(in.readLine()); The Server Socket program is written in .Net and it echoes back the data. The data is sent successfully but could not be retrieved properly. I tried the same by using the linux command nc 192.168.1.6 8425 (enter) Hi (Sent data) Hi (recieved data) When I checked the code the data is found to have sent as byteStream in .Net. Is that a problem. In that case what modification should I make.

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  • Line by line image swing

    - by user1046017
    I want to show an image as it is downloading, I have the URL, and I am trying to get the image parts like this: InputStream openStream = url.openStream(); DataInputStream dis = new DataInputStream(new BufferedInputStream(openStream)); ByteArrayOutputStream os = new ByteArrayOutputStream(); while ((s = dis.read(b)) != -1) { os.write(b , 0, s); support.firePropertyChange("stream", null, os); } This way, any listener get the stream and creates an image, this way: if("stream".equals(evt.getPropertyName())){ try { ByteArrayOutputStream stream = (ByteArrayOutputStream) evt.getNewValue(); byte[] byteArray = stream.toByteArray(); stream.flush(); Image createImage = Toolkit.getDefaultToolkit().createImage(byteArray); this.getContentPane().add(new JLabel(new ImageIcon(createImage))); } catch (IOException ex) { Logger.getLogger(ImageTest.class.getName()).log(Level.SEVERE, null, ex); } } However, I am getting a "Premature end of JPEG file sun.awt.image.ImageFormatException: JPEG datastream contains no image" error, the image is a JPG image format, is there any library or method known to make something similar?

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  • AudioTrack lag: obtainBuffer timed out

    - by BTR
    I'm playing WAVs on my Android phone by loading the file and feeding the bytes into AudioTrack.write() via the FileInputStream BufferedInputStream DataInputStream method. The audio plays fine and when it is, I can easily adjust sample rate, volume, etc on the fly with nice performance. However, it's taking about two full seconds for a track to start playing. I know AudioTrack has an inescapable delay, but this is ridiculous. Every time I play a track, I get this: 03-13 14:55:57.100: WARN/AudioTrack(3454): obtainBuffer timed out (is the CPU pegged?) 0x2e9348 user=00000960, server=00000000 03-13 14:55:57.340: WARN/AudioFlinger(72): write blocked for 233 msecs, 9 delayed writes, thread 0xba28 I've noticed that the delayed write count increases by one every time I play a track -- even across multiple sessions -- from the time the phone has been turned on. The block time is always 230 - 240ms, which makes sense considering a minimum buffer size of 9600 on this device (9600 / 44100). I've seen this message in countless searches on the Internet, but it usually seems to be related to not playing audio at all or skipping audio. In my case, it's just a delayed start. I'm running all my code in a high priority thread. Here's a truncated-yet-functional version of what I'm doing. This is the thread callback in my playback class. Again, this works (only playing 16-bit, 44.1kHz, stereo files right now), it just takes forever to start and has that obtainBuffer/delayed write message every time. public void run() { // Load file FileInputStream mFileInputStream; try { // mFile is instance of custom file class -- this is correct, // so don't sweat this line mFileInputStream = new FileInputStream(mFile.path()); } catch (FileNotFoundException e) {} BufferedInputStream mBufferedInputStream = new BufferedInputStream(mFileInputStream, mBufferLength); DataInputStream mDataInputStream = new DataInputStream(mBufferedInputStream); // Skip header try { if (mDataInputStream.available() > 44) mDataInputStream.skipBytes(44); } catch (IOException e) {} // Initialize device mAudioTrack = new AudioTrack(AudioManager.STREAM_MUSIC, ConfigManager.SAMPLE_RATE, AudioFormat.CHANNEL_CONFIGURATION_STEREO, AudioFormat.ENCODING_PCM_16BIT, ConfigManager.AUDIO_BUFFER_LENGTH, AudioTrack.MODE_STREAM); mAudioTrack.play(); // Initialize buffer byte[] mByteArray = new byte[mBufferLength]; int mBytesToWrite = 0; int mBytesWritten = 0; // Loop to keep thread running while (mRun) { // This flag is turned on when the user presses "play" while (mPlaying) { try { // Check if data is available if (mDataInputStream.available() > 0) { // Read data from file and write to audio device mBytesToWrite = mDataInputStream.read(mByteArray, 0, mBufferLength); mBytesWritten += mAudioTrack.write(mByteArray, 0, mBytesToWrite); } } catch (IOException e) { } } } } If I can get past the artificially long lag, I can easily deal with the inherit latency by starting my write at a later, predictable position (ie, skip past the minimum buffer length when I start playing a file).

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  • How to Upload a file from client to server using OFBIZ?

    - by SIVAKUMAR.J
    I'm new to ofbiz so try to keep your answer as simple as possibly. If you can give examples that would be kind. My problem is I created a project inside the ofbiz/hot-deploy folder namely productionmgntSystem. Inside the folder ofbiz\hot-deploy\productionmgntSystem\webapp\productionmgntSystem I created a file app_details_1.ftl. The following are the code of this file <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1"> <title>Insert title here</title> <script TYPE="TEXT/JAVASCRIPT" language=""JAVASCRIPT"> function uploadFile() { //alert("Before calling upload.jsp"); window.location='<@ofbizUrl>testing_service1</@ofbizUrl>' } </script> </head> <!-- <form action="<@ofbizUrl>testing_service1</@ofbizUrl>" enctype="multipart/form-data" name="app_details_frm"> --> <form action="<@ofbizUrl>logout1</@ofbizUrl>" enctype="multipart/form-data" name="app_details_frm"> <center style="height: 299px; "> <table border="0" style="height: 177px; width: 788px"> <tr style="height: 115px; "> <td style="width: 103px; "> <td style="width: 413px; "><h1>APPLICATION DETAILS</h1> <td style="width: 55px; "> </tr> <tr> <td style="width: 125px; ">Application name : </td> <td> <input name="app_name_txt" id="txt_1" value=" " /> </td> </tr> <tr> <td style="width: 125px; ">Excell sheet &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;: </td> <td> <input type="file" name="filename"/> </td> </tr> <tr> <td> <!-- <input type="button" name="logout1_cmd" value="Logout" onclick="logout1()"/> --> <input type="submit" name="logout_cmd" value="logout"/> </td> <td> <!-- <input type="submit" name="upload_cmd" value="Submit" /> --> <input type="button" name="upload1_cmd" value="Upload" onclick="uploadFile()"/> </td> </tr> </table> </center> </form> </html> the following coding is present in the file ofbiz\hot-deploy\productionmgntSystem\webapp\productionmgntSystem\WEB-INF\controller.xml ...... ....... ........ <request-map uri="testing_service1"> <security https="true" auth="true"/> <event type="java" path="org.ofbiz.productionmgntSystem.web_app_req.WebServices1" invoke="testingService"/> <response name="ok" type="view" value="ok_view"/> <response name="exception" type="view" value="exception_view"/> </request-map> .......... ............ .......... <view-map name="ok_view" type="ftl" page="ok_view.ftl"/> <view-map name="exception_view" type="ftl" page="exception_view.ftl"/> ................ ............. ............. The following are the coding present in the file ofbiz\hot-deploy\productionmgntSystem\src\org\ofbiz\productionmgntSystem\web_app_req\WebServices1.java package org.ofbiz.productionmgntSystem.web_app_req; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import java.io.DataInputStream; import java.io.FileOutputStream; import java.io.IOException; public class WebServices1 { public static String testingService(HttpServletRequest request, HttpServletResponse response) { //int i=0; String result="ok"; System.out.println("\n\n\t*************************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response)- Start"); String contentType=request.getContentType(); System.out.println("\n\n\t*************************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response)- contentType : "+contentType); String str=new String(); // response.setContentType("text/html"); //PrintWriter writer; if ((contentType != null) && (contentType.indexOf("multipart/form-data") >= 0)) { System.out.println("\n\n\t**********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) after if (contentType != null)"); try { // writer=response.getWriter(); System.out.println("\n\n\t**********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) - try Start"); DataInputStream in = new DataInputStream(request.getInputStream()); int formDataLength = request.getContentLength(); byte dataBytes[] = new byte[formDataLength]; int byteRead = 0; int totalBytesRead = 0; //this loop converting the uploaded file into byte code while (totalBytesRead < formDataLength) { byteRead = in.read(dataBytes, totalBytesRead,formDataLength); totalBytesRead += byteRead; } String file = new String(dataBytes); //for saving the file name String saveFile = file.substring(file.indexOf("filename=\"") + 10); saveFile = saveFile.substring(0, saveFile.indexOf("\n")); saveFile = saveFile.substring(saveFile.lastIndexOf("\\")+ 1,saveFile.indexOf("\"")); int lastIndex = contentType.lastIndexOf("="); String boundary = contentType.substring(lastIndex + 1,contentType.length()); int pos; //extracting the index of file pos = file.indexOf("filename=\""); pos = file.indexOf("\n", pos) + 1; pos = file.indexOf("\n", pos) + 1; pos = file.indexOf("\n", pos) + 1; int boundaryLocation = file.indexOf(boundary, pos) - 4; int startPos = ((file.substring(0, pos)).getBytes()).length; int endPos = ((file.substring(0, boundaryLocation)).getBytes()).length; //creating a new file with the same name and writing the content in new file FileOutputStream fileOut = new FileOutputStream("/"+saveFile); fileOut.write(dataBytes, startPos, (endPos - startPos)); fileOut.flush(); fileOut.close(); System.out.println("\n\n\t**********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) - try End"); } catch(IOException ioe) { System.out.println("\n\n\t*********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) - Catch IOException"); //ioe.printStackTrace(); return("exception"); } catch(Exception ex) { System.out.println("\n\n\t*********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) - Catch Exception"); return("exception"); } } else { System.out.println("\n\n\t********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) else part"); result="exception"; } System.out.println("\n\n\t*************************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response)- End"); return(result); } } I want to upload a file to the server. The file is get from user " tag in the "app_details_1.ftl" file & it is updated into the server by using the method "testingService(HttpServletRequest request, HttpServletResponse response)" in the class "WebServices1". But the file is not uploaded. Give me a good solution for uploading a file to the server.

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  • Java File I/O problems

    - by dwwilson66
    This is my first time working with file i/o in java, and it's not working. The section of the program where I parse individual lines and output a semicolon delimited line works like a charm when I hardcode a file and display on screen. Whne I try to write to a file public static OutputStream... errors out as an illegal start to expression, and I've been unable to get the program to step through an entire directory of files instead of one at a time. Where I'm not clear: I'm note setting an output filename anywhere...whare am I supposed to do that? The path variable won't pass. What's the proper format for a path? Can anyone see what I need to debug here? import java.io.*; public class FileRead { public static void main(String args[]) { try { // Open the file(s) // single file works OK FileInputStream fstream = new FileInputStream("testfile.txt"); Path startingDir = R:\Data\cs\RoboHelp\CorrLib\Output\Production\WebHelp; PrintFiles pf = new PrintFiles(); Files.walkFileTree(startingDir, pf); // Get the object of DataInputStream DataInputStream in = new DataInputStream(fstream); BufferedReader br = new BufferedReader(new InputStreamReader(in)); String inputLine; String desc = ""; String docNo = ""; String replLtr = ""; String specCond = ""; String states = ""; String howGen = ""; String whenGen = ""; String owner = ""; String lastChange = ""; //Read File Line By Line while ((inputLine = br.readLine()) != null) { int testVal=0; int stringMax = inputLine.length(); // if(inputLine.startsWith("Description")) {desc = inputLine.substring(13,inputLine.length());} else if(inputLine.startsWith("Reference Number")) {docNo = inputLine.substring(20,inputLine.length());} else if(inputLine.startsWith("Replaces Letter")) {replLtr = inputLine.substring(17,inputLine.length());} else if(inputLine.startsWith("Special Conditions")) {specCond = inputLine.substring(21,inputLine.length());} else if(inputLine.startsWith("States Applicable")) {states = inputLine.substring(19,inputLine.length());} else if(inputLine.startsWith("How Generated")) {howGen = inputLine.substring(15,inputLine.length());} else if(inputLine.startsWith("When Generated")) {whenGen = inputLine.substring(16,inputLine.length());} else if(inputLine.startsWith("Owner")) {owner = inputLine.substring(7,inputLine.length());} else if(inputLine.startsWith("Last Change Date")) {lastChange = inputLine.substring(17,inputLine.length());} } //close while loop // Print the content on the console String outStr1 = (desc + ";" + docNo + ";" + replLtr + ";" + specCond + ";" + states); String outStr2 = (";" + howGen + ";" + whenGen + ";" + owner + ";" + lastChange); String outString = (outStr1 + outStr2); System.out.print(inputLine + "\n" + outString); String lineItem = (outStr1+outStr2); // try (OutputStream out = new BufferedOutputStream (logfile.newOutputStream(CREATE, APPEND))) { out.write(lineItem, 0, lineItem.length); } catch (IOException x) { System.err.println(x); } public static OutputStream newOutputStream() throws IOException { // append to an existing file, create file if it doesn't initially exist out = Files.newOutputStream(c:, CREATE, APPEND); } //Close the input stream in.close(); } catch (Exception e) { //Catch exception if any System.err.println("Error: " + e.getMessage()); } } }

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  • Why does my program not read full files?

    - by user593395
    I have written code in Java to read the content of a file. But it is working for small line of file only not for more than 1000 line of file. Please tell me me what error I have made in the below program. program: import java.io.DataInputStream; import java.io.DataOutputStream; import java.io.File; import java.io.FileInputStream; import java.io.FileNotFoundException; import java.io.FileOutputStream; import java.util.regex.Matcher; import java.util.regex.Pattern; public class aaru { public static void main(String args[]) throws FileNotFoundException { File sourceFile = new File("E:\\parser\\parse3.txt"); File destinationFile = new File("E:\\parser\\new.txt"); FileInputStream fileIn = new FileInputStream(sourceFile); FileOutputStream fileOut = new FileOutputStream(destinationFile); DataInputStream dataIn = new DataInputStream(fileIn); DataOutputStream dataOut = new DataOutputStream(fileOut); String str=""; String[] st; String sub[]=null; String word=""; String contents=""; String total=""; String stri="";; try { while((contents=dataIn.readLine())!=null) { total = contents.replaceAll(",",""); String str1=total.replaceAll("--",""); String str2=str1.replaceAll(";","" ); String str3=str2.replaceAll("&","" ); String str4=str3.replaceAll("^","" ); String str5=str4.replaceAll("#","" ); String str6=str5.replaceAll("!","" ); String str7=str6.replaceAll("/","" ); String str8=str7.replaceAll(":","" ); String str9=str8.replaceAll("]","" ); String str10=str9.replaceAll("\\?",""); String str11=str10.replaceAll("\\*",""); String str12=str11.replaceAll("\\'",""); Pattern pattern = Pattern.compile("\\s+", Pattern.CASE_INSENSITIVE | Pattern.DOTALL | Pattern.MULTILINE); Matcher matcher = pattern.matcher(str12); //boolean check = matcher.find(); String result=str12; Pattern p=Pattern.compile("^www\\.|\\@"); Matcher m=p.matcher(result); stri = m.replaceAll(" "); int i; int j; st=stri.split("\\."); for(i=0;i<st.length;i++) { st[i]=st[i].trim(); /*if(st[i].startsWith(" ")) st[i]=st[i].substring(1,st[i].length);*/ sub=st[i].split(" "); if(sub.length>1) { for(j=0;j<sub.length-1;j++) { word = word+sub[j]+","+sub[j+1]+"\r\n"; } } else { word = word+st[i]+"\r\n"; } } } System.out.println(word); dataOut.writeBytes(word+"\r\n"); fileIn.close(); fileOut.close(); dataIn.close(); dataOut.close(); } catch(Exception e) { System.out.print(e); } } }

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  • jrunscript as a cross platform scripting environment

    - by user12798506
    ?????????????????????????????????????????????????????????sh????????????UNIX???????????????????sh???????????????????????????????????????????Windows????????????????? sh??????????????find?grep?sed?awk???Windows??????????????????????????????????????????????????????????????????????????????????????????????Windows???Cygwin????????????sh??????Windows??????????????Cygwin????????????????????????????????????????????JDK?????jrunscript?????JavaScript???????????????????????1?????????jrunscript??????????????????? Windows???UNIX??????????????????????? find?grep?sed?awk?????????sh???????????????Windows Script Host??????? Java????????????? ??????????????????????????????????????????????????????????(?????????????????????????????????????????) ?????????????JDK 6??????????????????????????PC????????????????JDK 6?PC????????????????????????????????????JDK????????????????????????????????????????jrunscript?????????????????????????? ?????jrunscript????JavaScript?????????????????????????????????????????? 1) Windows???UNIX????????????????? ?????????????????????????????????????????JavaScript???mytool.js???????????????????????jrunscript???????????UNIX????sh???????Windows????bat????????????????????? mytool.sh (UNIX?): #!/bin/sh bindir=$(cd $(dirname $0) && pwd) case "`uname`" in CYGWIN*) bindir=`cygpath -w "$bindir"` ;; esac jrunscript "${bindir}/mytool.js" $* mytool.bat (Windows?): @echo off set bindir=%~dp0 jrunscript "%bindir%mytool.js" %* UNIX??sh????????Cygwin???????????????????????????????????????????js??????????????UNIX?Windows??????????????????????????????? 2) jrunscript??cat, cp, find?grep?????? jrunscript???UNIX?????????????????????????????????? jrunscript JavaScript built-in functions ????UNIX??sh?????????????????????UNIX?????????????????????????????????????????src??????????java????????????enum???????java?????????????????????????????????????????????? find('src', '.*.java', function(f) { grep('enum', f); }); ???????UNIX?????????????????????????????????????????????????????????????????????????????????????????cp(from, to)??????????????????????????????????????????UNIX??????????? $ cp -r src/* tmp/ ?????????????????????????????????????????find()???????cp -r????????·?????????????????????? function cpr(fromdir, todir, pattern) { if (pattern == undefined) { pattern = ".*"; } var frdir = pathToFile(fromdir).getCanonicalPath(); find(fromdir, pattern, function(f) { // relative dir of file f from 'fromdir'. var relative = f.getParentFile().getCanonicalPath().substring(frdir.length() + 1); var dstdir = pathToFile(todir + "/" + relative); if (!dstdir.exists()) { // Create the destination dir for file f. mkdirs(dstdir); } // Copy file f to 'dstdir'. cp(f, dstdir + "/" + f.getName()); }); } java?????I/O?API??Windows?????????????"/"??????????????????????????????UNIX?Windows?????????????? ????????????exec(cmd)?????????jar???????????????????????????????????????????? $ jrunscript js> exec("jar xvf example.jar") META-INF/ ?????????????µ???B META-INF/MANIFEST.MF ???W?J???????µ???B com/ ?????????????µ???B com/example/ ?????????????µ???B com/example/Bar.class ???W?J???????µ???B com/example/dummy/ ?????????????µ???B com/example/dummy/dummy.txt ?????o???????µ???B com/example/dummy.properties ?????o???????µ???B com/example/Foo.class ???W?J???????µ???B ???exec()?????????????????????????????????????????????????????????????????Windows????????????I/O??????????????????????????????????BAT????????? errmsg.bat: for /L %%i in (1,1,50) do echo "Error Message count = %%i" 1&2 jrunscript??exec()???????????????18??????????????????????????????????? C:\tmp>jrunscript -e "exec('errmsg.bat')" C:\tmp>for /L %i in (1 1 100) do echo "Error Message count = %i" 1>&2 C:\tmp>echo "Error Message count = 1" 1>&2 : C:\tmp>echo "Error Message count = 18" 1>&2 ? ??? ???????????exec()?????????????????????????????????????????????????????????????????DataInputStream???????????????????????? $ jrunscript js this["exec"].toString() function exec(cmd) { var process = java.lang.Runtime.getRuntime().exec(cmd); var inp = new DataInputStream(process.getInputStream()); var line = null; while ((line = inp.readLine()) != null) { println(line); } process.waitFor(); $exit = process.exitValue(); } ?????????????????????????????????????????????????????exec()???????????????exec()?????????????????????????????exec()??????? function exec(cmd) { var process = java.lang.Runtime.getRuntime().exec(cmd); var stdworker = new java.lang.Runnable( {run: function() { cat(process.getInputStream()); }}); var errworker = new java.lang.Runnable( {run: function() { cat(process.getErrorStream()); }}); new java.lang.Thread(stdworker).start(); new java.lang.Thread(errworker).start(); return proc.waitFor(); } ???????????????????cat()???????????cat()?InputStreamReader?????????????????????????????????????????????????? 3) JavaScript???????????????? JavaScript?Java???????????????????????JavaScript????????????Ruby?Groovy?Scala???????????????????????????????????????????????10MB?????????????????????????????????????JavaScript????????????????????KB?????????????MB?JAR??????????????????????????JRE?JDK?????????????????????????????????????????

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  • Java RMI timeout in callback

    - by sakra
    We are using Java RMI for communication. An RMI client passes a processing request and an object with a callback method to an RMI server. The server invokes the callback when it is done with processing. The setup is similar to the one described in RMI Callbacks. Occasionally we are getting a "read time out" exception in the server upon invoking the callback method. The callback thread stalls for about a minute before the exception is raised. java.rmi.ConnectIOException: error during JRMP connection establishment; nested exception is: java.net.SocketTimeoutException: Read timed out at sun.rmi.transport.tcp.TCPChannel.createConnection(TCPChannel.java:286) at sun.rmi.transport.tcp.TCPChannel.newConnection(TCPChannel.java:184) at sun.rmi.server.UnicastRef.invoke(UnicastRef.java:110) at java.rmi.server.RemoteObjectInvocationHandler.invokeRemoteMethod(RemoteObjectInvocationHandler.java:178) at java.rmi.server.RemoteObjectInvocationHandler.invoke(RemoteObjectInvocationHandler.java:132) at $Proxy2.finished(Unknown Source) at com.unrisk.db.grid.GridTask.invokeCallback(com.unrisk.db.grid.GridTask:1292) at com.unrisk.db.grid.GridTask.invokeCallbacks(com.unrisk.db.grid.GridTask:1304) at com.unrisk.db.service.tasks.EquityMDTask.afterRun(com.unrisk.db.service.tasks.EquityMDTask:276) at com.unrisk.db.grid.GridTask.run(com.unrisk.db.grid.GridTask:720) at java.util.concurrent.ThreadPoolExecutor$Worker.runTask(ThreadPoolExecutor.java:886) at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:908) at java.lang.Thread.run(Thread.java:619) Caused by: java.net.SocketTimeoutException: Read timed out at java.net.SocketInputStream.socketRead0(Native Method) at java.net.SocketInputStream.read(SocketInputStream.java:129) at java.io.BufferedInputStream.fill(BufferedInputStream.java:218) at java.io.BufferedInputStream.read(BufferedInputStream.java:237) at java.io.DataInputStream.readByte(DataInputStream.java:248) at sun.rmi.transport.tcp.TCPChannel.createConnection(TCPChannel.java:228) ... 12 more We are using Sun Java JDK 1.6.0_18 under Windows Server 2003 32-bit. Is it possible to work around the connection problems by tuning RMI related system properties?

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  • Texture loading at joGL

    - by Nour
    hi I've been trying to load a bmp picture to use it as a texture at my program I've used a IOstream Class to extend DataInputStream to read the pixels at the photo with this code "based on a texture loader code for c++ " : //class Data members public static int BMPtextures[]; public static int BMPtexCount = 30; public static int currentTextureID = 0; //loading methode static int loadBMPTexture(int index, String fileName, GL gl) { try { IOStream wdis = new IOStream(fileName); wdis.skipBytes(18); int width = wdis.readIntW(); int height = wdis.readIntW(); wdis.skipBytes(28); byte buf[] = new byte[wdis.available()]; wdis.read(buf); wdis.close(); gl.glBindTexture(GL.GL_TEXTURE_2D, BMPtextures[index]); gl.glTexImage2D(GL.GL_TEXTURE_2D, 0, 3, width, height, 0, GL.GL_BGR, GL.GL_UNSIGNED_BYTE, buf); gl.glTexParameteri(GL.GL_TEXTURE_2D, GL.GL_TEXTURE_MAG_FILTER, GL.GL_LINEAR); gl.glTexParameteri(GL.GL_TEXTURE_2D, GL.GL_TEXTURE_MIN_FILTER, GL.GL_LINEAR); currentTextureID = index; return currentTextureID; } catch (IOException ex) { // Utils.msgBox("File Error\n" + fileName, "Error", Utils.MSG_WARN); return -1; } } and IOStream code : public class IOStream extends DataInputStream { public IOStream(String file) throws FileNotFoundException { super(new FileInputStream(file)); } public short readShortW() throws IOException { return (short)(readUnsignedByte() + readUnsignedByte() * 256); } public int readIntW() throws IOException { return readShortW() + readShortW() * 256 * 256; } void read(Buffer[] buf) { } } and the calling: GTexture.loadBMPTexture(1,"/BasicJOGL/src/basicjogl/data/Font.bmp",gl); after debugging I figured out that when it come to this line : IOStream wdis = new IOStream(fileName); an IOExeption occurred and it's a dispatchException .. what this impose to mean ?? and how can I solve it ? by the way i tried to : 1- use \ and \ and / and // 2- change the path of the photo and take all the path from c:\ to the photoname.bmp 3- rename the photo using numbers like 1.bmp but nothing seems to work :(

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  • search data from FileReader in Java

    - by maya
    hi I'm new in java how to read and search data from file (txt) and then display the data in TextArea or Jtable. for example I have file txt contains data and I need to display this data in textarea after I clicked a button, I have used FileReader , and t1 t2 tp are attributes in the file import java.io.FileReader; import java.io.IOException; String t1,t2,tp; Ffile f1= new Ffile(); FileReader fin = new FileReader("test2.txt"); Scanner src = new Scanner(fin); while (src.hasNext()) { t1 = src.next(); textarea.setText(t1); t2 = src.next(); textarea.setText(t2); tp = src.next(); textarea.setText(tp); f1.insert(t1,t2,tp); } fin.close(); also I have used the inputstream DataInputStream dis = null; String dbRecord = null; try { File f = new File("text2.text"); FileInputStream fis = new FileInputStream(f); BufferedInputStream bis = new BufferedInputStream(fis); dis = new DataInputStream while ( (dbRecord = dis.readLine()) != null) { StringTokenizer st = new StringTokenizer(dbRecord, ":"); String t1 = st.nextToken(); String t2 = st.nextToken(); String tp = st.nextToken(); textarea.setText(textarea.getText()+t1); textarea.setText(textarea.getText()+t2); textarea.setText(textarea.getText()+tp); } } catch (IOException e) { // catch io errors from FileInputStream or readLine() System.out.println("Uh oh, got an IOException error: " + e.getMessage()); } finally { } but both of them don't work ,so please any one help me I want to know how to read data and also search it from file and i need to display the data in textarea . thanks in advance

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  • Java - Save video stream from Socket to File

    - by Alex
    I use my Android application for streaming video from phone camera to my PC Server and need to save them into file on HDD. So, file created and stream successfully saved, but the resulting file can not play with any video player (GOM, KMP, Windows Media Player, VLC etc.) - no picture, no sound, only playback errors. I tested my Android application into phone and may say that in this instance captured video successfully stored on phone SD card and after transfer it to PC played witout errors, so, my code is correct. In the end, I realized that the problem in the video container: data streamed from phone in MP4 format and stored in *.mp4 files on PC, and in this case, file may be incorrect for playback with video players. Can anyone suggest how to correctly save streaming video to a file? There is my code that process and store stream data (without errors handling to simplify): // getOutputMediaFile() returns a new File object DataInputStream in = new DataInputStream (server.getInputStream()); FileOutputStream videoFile = new FileOutputStream(getOutputMediaFile()); int len; byte buffer[] = new byte[8192]; while((len = in.read(buffer)) != -1) { videoFile.write(buffer, 0, len); } videoFile.close(); server.close(); Also, I would appreciate if someone will talk about the possible "pitfalls" in dealing with the conservation of media streams. Thank you, I hope for your help! Alex.

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  • Calling webservice via server causes java.net.MalformedURLException: no protocol

    - by Thomas
    I am writing a web-service, which parses an xml file. In the client, I read the whole content of the xml into a String then I give it to the web-service. If I run my web-service with main as a Java-Application (for tests) there is no problem, no error messages. However when I try to call it via the server, I get the following error: java.net.MalformedURLException: no protocol I use the same xml file, the same code (without main), and I just cannot figure out, what the cause of the error can be. here is my code: DOMParser parser=new DOMParser(); try { parser.setFeature("http://xml.org/sax/features/validation", true); parser.setFeature("http://apache.org/xml/features/validation/schema",true); parser.setFeature("http://apache.org/xml/features/validation/dynamic",true); parser.setErrorHandler(new myErrorHandler()); parser.parse(new InputSource(new StringReader(xmlFile))); document=parser.getDocument(); xmlFile is constructed in the client so: String myFile ="C:/test.xml"; File file=new File(myFile); String myString=""; FileInputStream fis=new FileInputStream(file); BufferedInputStream bis=new BufferedInputStream(fis); DataInputStream dis=new DataInputStream(bis); while (dis.available()!=0) { myString=myString+dis.readLine(); } fis.close(); bis.close(); dis.close(); Any suggestions will be appreciated!

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  • how to use cookies in HttpsURLConnection in android.

    - by sajjoo
    hello guys, actually i am new in Android and now i have to add the cookies in my project. i am using HttpsUrlConnection. here is how i am making request and getting response from a webserver and now i have to add cookies aswell. URL url = new URL(strUrl); HttpsURLConnection connection = (HttpsURLConnection) url.openConnection(); connection.setRequestMethod("POST"); connection.setRequestProperty("Content-Type", "application/soap+xml; charset=utf-8"); connection.setRequestProperty("Content-Length", ""+ Integer.toString(request.getBytes().length)); connection.setUseCaches (false); connection.setDoInput(true); connection.setDoOutput(true); // send Request... DataOutputStream wr = new DataOutputStream (connection.getOutputStream()); wr.writeBytes (request); wr.flush (); wr.close (); //Get response... DataInputStream is = new DataInputStream(connection.getInputStream()); String line; StringBuffer response = new StringBuffer(); while((line = is.readLine()) != null) { response.append(line); } is.close(); FileLogger.writeFile("Soap.txt", "RESPONSE: " + methodName + "\n" + response); HashMap<String, String> parameters = null; try { parameters = SoapRequest.responseParser(response.toString(), methodName); } catch (ParserConfigurationException e) { // TODO Auto-generated catch block e.printStackTrace(); } catch (SAXException e) { // TODO Auto-generated catch block e.printStackTrace(); } return parameters; any help will be appreciative, thanks

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  • Download dynamic file with GWT

    - by Maksim
    I have a GWT page where user enter data (start date, end date, etc.), then this data goes to the server via RPC call. On the server I want to generate Excel report with POI and let user save that file on their local machine. This is my test code to stream file back to the client but for some reason I think it does not know how to stream file to the client when I'm using RPC: public class ReportsServiceImpl extends RemoteServiceServlet implements ReportsService { public String myMethod(String s) { File f = new File("/excelTestFile.xls"); String filename = f.getName(); int length = 0; try { HttpServletResponse resp = getThreadLocalResponse(); ServletOutputStream op = resp.getOutputStream(); ServletContext context = getServletConfig().getServletContext(); resp.setContentType("application/octet-stream"); resp.setContentLength((int) f.length()); resp.setHeader("Content-Disposition", "attachment; filename*=\"utf-8''" + filename + ""); byte[] bbuf = new byte[1024]; DataInputStream in = new DataInputStream(new FileInputStream(f)); while ((in != null) && ((length = in.read(bbuf)) != -1)) { op.write(bbuf, 0, length); } in.close(); op.flush(); op.close(); } catch (Exception ex) { ex.printStackTrace(); } return "Server says: " + filename; } } I've red somewhere on internet that you can't do file stream with RPC and I have to use Servlet for that. Is there any example of how to use Servlet and how to call that servlet from ReportsServiceImpl. Do I really need to make a servlet or it is possible to stream it back with my RPC?

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  • Download dynaic file with GWT

    - by Maksim
    I have a GWT page where user enter data (start date, end date, etc.), then this data goes to the server via RPC call. On the server I want to generate Excel report with POI and let user save that file on their local machine. This is my test code to stream file back to the client but for some reason it does not know: public class ReportsServiceImpl extends RemoteServiceServlet implements ReportsService { public String myMethod(String s) { File f = new File("/excelTestFile.xls"); String filename = f.getName(); int length = 0; try { HttpServletResponse resp = getThreadLocalResponse(); ServletOutputStream op = resp.getOutputStream(); ServletContext context = getServletConfig().getServletContext(); resp.setContentType("application/octet-stream"); resp.setContentLength((int) f.length()); resp.setHeader("Content-Disposition", "attachment; filename*=\"utf-8''" + filename + ""); byte[] bbuf = new byte[1024]; DataInputStream in = new DataInputStream(new FileInputStream(f)); while ((in != null) && ((length = in.read(bbuf)) != -1)) { op.write(bbuf, 0, length); } in.close(); op.flush(); op.close(); } catch (Exception ex) { ex.printStackTrace(); } return "Server says: " + filename; } } I've red somewhere on internet that you can't do file stream with RPC and I have to use Servlet for that. Is there any example of how to use Servlet and how to call that servlet from ReportsServiceImpl

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  • alternatyve in php (from java)

    - by Valdas
    I have some problem have class in java. But now need have in php. it's possible rewrite? Code: public class RealityStream { public RealityStream(byte abyte0[]) { m_dstream = null; m_dstream = new DataInputStream(new ByteArrayInputStream(abyte0)); } public int available() throws IOException { return m_dstream.available(); } public float readFloat() throws IOException { byte byte0 = m_dstream.readByte(); byte byte1 = m_dstream.readByte(); byte byte2 = m_dstream.readByte(); byte byte3 = m_dstream.readByte(); int i = (byte3 & 0xff) << 24 | (byte2 & 0xff) << 16 | (byte1 & 0xff) << 8 | byte0 & 0xff; return Float.intBitsToFloat(i); } public int readInt() throws IOException { byte byte0 = m_dstream.readByte(); byte byte1 = m_dstream.readByte(); byte byte2 = m_dstream.readByte(); byte byte3 = m_dstream.readByte(); return (byte3 & 0xff) << 24 | (byte2 & 0xff) << 16 | (byte1 & 0xff) << 8 | byte0 & 0xff; } public int readShort() throws IOException { byte byte0 = m_dstream.readByte(); byte byte1 = m_dstream.readByte(); return byte1 << 8 | byte0 & 0xff; } public int readUnsignedChar() throws IOException { return m_dstream.readUnsignedByte(); } private DataInputStream m_dstream; } very need. very thaks.

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  • Multiple HTTP requests using sockets in java

    - by codeomnitrix
    How could i send multiple http requests from my java program using sockets. actually i have tried as: import java.net.*; import java.io.*; class htmlPageFetch{ public static void main(String[] args){ try{ Socket s = new Socket("127.0.0.1", 80); DataInputStream dIn = new DataInputStream(s.getInputStream()); PrintWriter dOut = new PrintWriter(s.getOutputStream(), true); dOut.println("GET /mytesting/justCheck.html HTTP/1.1\r\nHost:localhost\r\n\r\n"); boolean more_data = true; String str; int i = 0; while(more_data){ str = dIn.readLine(); if(str==null){ //Now server has stopped sending data //So now write again the inputs dOut.println("GET /mytesting/justCheck1.html HTTP/1.1\r\nHost:localhost\r\n\r\n"); continue; } System.out.println(str); } }catch(IOException e){ } } } But when I send the request again it was not processed? Thank in advance.

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  • Servlet File Upload Memory Consumption

    - by Scott
    Hi, I'm using a servlet to do a multi fileupload (using apache commons fileupload to help). A portion of my code is posted below. My problem is that if I upload several files at once, the memory consumption of the app server jumps rather drastically. This is probably OK if it were only until the file upload is finished, but the app server seems to hang on to the memory and never return it to the OS. I'm worried that when I put this into production I'll end up getting an out of memory exception on the server. Any ideas on why this is happening? I'm thinking the server may have started a session and will give the memory back after it expires, but I'm not 100% positive. if(ServletFileUpload.isMultipartContent(request)) { ServletFileUpload upload = new ServletFileUpload(); FileItemIterator iter = upload.getItemIterator(request); while(iter.hasNext()) { FileItemStream license = iter.next(); if(license.getFieldName().equals("upload_button") || license.getName().equals("")) continue; //DataInputStream stream = new DataInputStream(license.openStream()); InputStream stream = license.openStream(); ArrayList<Integer> byteArray = new ArrayList<Integer>(); int tempByte; do { tempByte = stream.read(); byteArray.add(tempByte); }while(tempByte != -1); stream.close(); byteArray.remove(byteArray.size()-1); byte[] bytes = new byte[byteArray.size()]; int i = 0; for(Integer tByte : byteArray) { bytes[i++] = tByte.byteValue(); } Thanks in advanced!!

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  • Functioning Socket read no longer works when called in AsyncTask

    - by bibismcbryde
    I'm making an app that sends a string to a server over a socket and then reads the output after the server has processed that data. It worked perfectly when it was my foreground task, but I have since used AsyncTask to show a process dialog while the socket communication runs in the background, and things start breaking after I read the output from the server and then try to close the socket. private class Progressor extends AsyncTask<String, Void, Void> { ProgressDialog dialog; protected void onPreExecute() { dialog = ProgressDialog.show(ClearTalkInputActivity.this, "Loading..", "Analyzing Text", true, false); } protected Void doInBackground(String... strings) { String language = strings[0].toLowerCase(); String the_text = strings[1]; Socket socket = null; DataOutputStream dos = null; DataInputStream dis = null; try { socket = new Socket(my_ip, port); dos = new DataOutputStream(socket.getOutputStream()); dis = new DataInputStream(socket.getInputStream()); dos.writeUTF(language+"****"+the_text); String in = ""; while (in.indexOf("</content>") < 0) { in += dis.readUTF(); } socket.close(); save_str(OUTPUT_KEY, in); } catch (UnknownHostException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } finally { if (socket != null) { try { socket.close(); } catch (IOException e) { e.printStackTrace(); } } } if (dos != null) { try { dos.close(); } catch (IOException e) { e.printStackTrace(); } } if (dis != null) { try { dis.close(); } catch (IOException e) { e.printStackTrace(); } } return null; } protected void onPostExecute() { if (dialog.isShowing()) dialog.dismiss(); startActivity(new Intent (output_intent)); } }

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  • Java if/else behaving strangely

    - by Alex
    I'm a real newbie to java, so please excuse me if this is a hopelessly straightforward problem. I have the following from my java game server: // Get input from the client DataInputStream in = new DataInputStream (server.getInputStream()); PrintStream out = new PrintStream(server.getOutputStream()); disconnect=false; while((line = in.readLine().trim()) != null && !line.equals(".") && !line.equals("") && !disconnect) { System.out.println("Received "+line); if(line.equals("h")){ out.println("h"+EOF); // Client handshake System.out.println("Matched 1"); }else if (line.equals("<policy-file-request/>")) { out.println("..."+EOF); // Policy file System.out.println(server.getInetAddress()+": Policy Request"); disconnect=true; System.out.println("Matched 2"); }else if(line.substring(0,3).equals("GET")||line.substring(0,4).equals("POST")){ out.println("HTTP/1.0 200 OK\nServer: VirtuaRoom v0.9\nContent-Type: text/html\n\n..."); // HTML status page disconnect=true; System.out.println("Matched 3"); } else { System.out.println(server.getInetAddress()+": Unknown command, client disconnected."); disconnect=true; System.out.println("Matched else"); } } server.close(); First of all, the client sends an "h" packet, and expects the same back (handshake). However, I want it to disconnect the client when an unrecognised packet is received. For some reason, it responds fine to the handshake and HTML status request, but the else clause is never executed when there's an unknown packet. Thanks

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  • How to Upload a file from client to server using OFBIZ?

    - by SIVAKUMAR.J
    Hi all, Im new to ofbiz.So is my question is have any mistake forgive me for my mistakes.Im new to ofbiz so i did not know some terminologies in ofbiz.Sometimes my question is not clear because of lack of knowledge in ofbiz.So try to understand my question and give me a good solution with respect to my level.Because some solutions are in very high level cannot able to understand for me.So please give the solution with good examples. My problem is i created a project inside the ofbiz/hot-deploy folder namely "productionmgntSystem".Inside the folder "ofbiz\hot-deploy\productionmgntSystem\webapp\productionmgntSystem" i created a .ftl file namely "app_details_1.ftl" .The following are the coding of this file <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1"> <title>Insert title here</title> <script TYPE="TEXT/JAVASCRIPT" language=""JAVASCRIPT"> function uploadFile() { //alert("Before calling upload.jsp"); window.location='<@ofbizUrl>testing_service1</@ofbizUrl>' } </script> </head> <!-- <form action="<@ofbizUrl>testing_service1</@ofbizUrl>" enctype="multipart/form-data" name="app_details_frm"> --> <form action="<@ofbizUrl>logout1</@ofbizUrl>" enctype="multipart/form-data" name="app_details_frm"> <center style="height: 299px; "> <table border="0" style="height: 177px; width: 788px"> <tr style="height: 115px; "> <td style="width: 103px; "> <td style="width: 413px; "><h1>APPLICATION DETAILS</h1> <td style="width: 55px; "> </tr> <tr> <td style="width: 125px; ">Application name : </td> <td> <input name="app_name_txt" id="txt_1" value=" " /> </td> </tr> <tr> <td style="width: 125px; ">Excell sheet &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;: </td> <td> <input type="file" name="filename"/> </td> </tr> <tr> <td> <!-- <input type="button" name="logout1_cmd" value="Logout" onclick="logout1()"/> --> <input type="submit" name="logout_cmd" value="logout"/> </td> <td> <!-- <input type="submit" name="upload_cmd" value="Submit" /> --> <input type="button" name="upload1_cmd" value="Upload" onclick="uploadFile()"/> </td> </tr> </table> </center> </form> </html> the following coding is present in the file "ofbiz\hot-deploy\productionmgntSystem\webapp\productionmgntSystem\WEB-INF\controller.xml" ...... ....... ........ <request-map uri="testing_service1"> <security https="true" auth="true"/> <event type="java" path="org.ofbiz.productionmgntSystem.web_app_req.WebServices1" invoke="testingService"/> <response name="ok" type="view" value="ok_view"/> <response name="exception" type="view" value="exception_view"/> </request-map> .......... ............ .......... <view-map name="ok_view" type="ftl" page="ok_view.ftl"/> <view-map name="exception_view" type="ftl" page="exception_view.ftl"/> ................ ............. ............. The following are the coding present in the file "ofbiz\hot-deploy\productionmgntSystem\src\org\ofbiz\productionmgntSystem\web_app_req\WebServices1.java" package org.ofbiz.productionmgntSystem.web_app_req; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import java.io.DataInputStream; import java.io.FileOutputStream; import java.io.IOException; public class WebServices1 { public static String testingService(HttpServletRequest request, HttpServletResponse response) { //int i=0; String result="ok"; System.out.println("\n\n\t*************************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response)- Start"); String contentType=request.getContentType(); System.out.println("\n\n\t*************************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response)- contentType : "+contentType); String str=new String(); // response.setContentType("text/html"); //PrintWriter writer; if ((contentType != null) && (contentType.indexOf("multipart/form-data") >= 0)) { System.out.println("\n\n\t**********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) after if (contentType != null)"); try { // writer=response.getWriter(); System.out.println("\n\n\t**********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) - try Start"); DataInputStream in = new DataInputStream(request.getInputStream()); int formDataLength = request.getContentLength(); byte dataBytes[] = new byte[formDataLength]; int byteRead = 0; int totalBytesRead = 0; //this loop converting the uploaded file into byte code while (totalBytesRead < formDataLength) { byteRead = in.read(dataBytes, totalBytesRead,formDataLength); totalBytesRead += byteRead; } String file = new String(dataBytes); //for saving the file name String saveFile = file.substring(file.indexOf("filename=\"") + 10); saveFile = saveFile.substring(0, saveFile.indexOf("\n")); saveFile = saveFile.substring(saveFile.lastIndexOf("\\")+ 1,saveFile.indexOf("\"")); int lastIndex = contentType.lastIndexOf("="); String boundary = contentType.substring(lastIndex + 1,contentType.length()); int pos; //extracting the index of file pos = file.indexOf("filename=\""); pos = file.indexOf("\n", pos) + 1; pos = file.indexOf("\n", pos) + 1; pos = file.indexOf("\n", pos) + 1; int boundaryLocation = file.indexOf(boundary, pos) - 4; int startPos = ((file.substring(0, pos)).getBytes()).length; int endPos = ((file.substring(0, boundaryLocation)).getBytes()).length; //creating a new file with the same name and writing the content in new file FileOutputStream fileOut = new FileOutputStream("/"+saveFile); fileOut.write(dataBytes, startPos, (endPos - startPos)); fileOut.flush(); fileOut.close(); System.out.println("\n\n\t**********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) - try End"); } catch(IOException ioe) { System.out.println("\n\n\t*********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) - Catch IOException"); //ioe.printStackTrace(); return("exception"); } catch(Exception ex) { System.out.println("\n\n\t*********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) - Catch Exception"); return("exception"); } } else { System.out.println("\n\n\t********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) else part"); result="exception"; } System.out.println("\n\n\t*************************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response)- End"); return(result); } } I want to upload a file to the server.The file is get from user "<input type="file"..> tag in the "app_details_1.ftl" file & it is updated into the server by using the method "testingService(HttpServletRequest request, HttpServletResponse response)" in the class "WebServices1".But the file is not uploaded. Give me a good solution for uploading a file to the server. Thanks & Regards, Sivakumar.J

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  • Need help receiving ByteArray data

    - by k80sg
    Hi folks, I am trying to receive byte array data from a machine. It sends out 3 different types of data structure each with different number of fields which consist of mostly int and a few floats, and byte sizes, the first being 320 bytes, 420 for the second type and 560 for the third. When the sending program is launched, it fires all 3 types of data simultaneouly with an interval of 1 sec. Example: Sending order: Pack1 - 320 bytes 1 sec later Pack2 - 420 bytes 1 sec later Pack3 - 560 bytes 1 sec later Pack1 - 320 bytes ... .. . How do I check the incoming byte size before passing it to: byte[] handsize = new byte[bytesize]; as the data I receive are all out of order, for instance using the following the read all int: System.out.println("Reading data in int format:" + " " + datainput.readInt()); I get many different sets of values whenever I run my prog although with some valid field data but they are all over the place. I am not too sure how exactly should I do it but I tried the following and apparently my data fields are not receiving in correct sequence: BufferedInputStream bais = new BufferedInputStream(requestSocket.getInputStream()); DataInputStream datainput = new DataInputStream(bais); byte[] handsize = new byte[560]; datainput.readFully(handsize); int n = 0; int intByte[] = new int[140]; for (int i = 0; i < 140 ; i++) { System.out.println("Reading data in int format:" + " " + datainput.readInt()); intByte[n] = datainput.readInt(); n = n + 1; System.out.println("The value in array is:" + intByte[0]); System.out.println("The value in array is:" + intByte[1]); System.out.println("The value in array is:" + intByte[2]); System.out.println("The value in array is:" + intByte[3]); Also from the above code, the order of the values printed out with System.out.println("Reading data in int format:" + " " + datainput.readInt()); and System.out.println("The value in array is:" + intByte[0]); System.out.println("The value in array is:" + intByte[1]); are different. Any help will be appreciated. Thanks

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  • How to handle ordering of @Rule's when they are dependant on eachother

    - by Lennart Schedin
    I use embedded servers that run inside Junit test cases. Sometimes these servers require a working directory (for example the Apache Directory server). The new @Rule in Junit 4.7 can handle these cases. The TemporaryFolder-Rule can create a temporary directory. A custom ExternalResource-Rule can be created for server. But how do I handle if I want to pass the result from one rule into another: import static org.junit.Assert.assertEquals; import java.io.*; import org.junit.*; import org.junit.rules.*; public class FolderRuleOrderingTest { @Rule public TemporaryFolder folder = new TemporaryFolder(); @Rule public MyNumberServer server = new MyNumberServer(folder); @Test public void testMyNumberServer() throws IOException { server.storeNumber(10); assertEquals(10, server.getNumber()); } /** Simple server that can store one number */ private static class MyNumberServer extends ExternalResource { private TemporaryFolder folder; /** The actual datafile where the number are stored */ private File dataFile; public MyNumberServer(TemporaryFolder folder) { this.folder = folder; } @Override protected void before() throws Throwable { if (folder.getRoot() == null) { throw new RuntimeException("TemporaryFolder not properly initialized"); } //All server data are stored to a working folder File workingFolder = folder.newFolder("my-work-folder"); dataFile = new File(workingFolder, "datafile"); } public void storeNumber(int number) throws IOException { dataFile.createNewFile(); DataOutputStream out = new DataOutputStream(new FileOutputStream(dataFile)); out.writeInt(number); } public int getNumber() throws IOException { DataInputStream in = new DataInputStream(new FileInputStream(dataFile)); return in.readInt(); } } } In this code the folder is sent as a parameter into the server so that the server can create a working directory to store data. However this does not work because Junit processes the rules in reverse order as they are defined in the file. The TemporaryFolder Rule will not be executed before the server Rule. Thus the root-folder in TempraryFolder will be null, resulting that any files are created relative to the current working directory. If I reverse the order of the attributes in my class I get a compile error because I cannot reference a variable before it is defined. I'm using Junit 4.8.1 (because the ordering of rules was fixed a bit from the 4.7 release)

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