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• Using XmlSerializer deserialize complex type elements are null

  - by Jean Bastos

  I have the following schema: <?xml version="1.0"?> <xsd:schema xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:tipos="http://www.ginfes.com.br/tipos_v03.xsd" targetNamespace="http://www.ginfes.com.br/servico_consultar_situacao_lote_rps_resposta_v03.xsd" xmlns="http://www.ginfes.com.br/servico_consultar_situacao_lote_rps_resposta_v03.xsd" attributeFormDefault="unqualified" elementFormDefault="qualified"> <xsd:import schemaLocation="tipos_v03.xsd" namespace="http://www.ginfes.com.br/tipos_v03.xsd" /> <xsd:element name="ConsultarSituacaoLoteRpsResposta"> <xsd:complexType> <xsd:choice> <xsd:sequence> <xsd:element name="NumeroLote" type="tipos:tsNumeroLote" minOccurs="1" maxOccurs="1"/> <xsd:element name="Situacao" type="tipos:tsSituacaoLoteRps" minOccurs="1" maxOccurs="1"/> </xsd:sequence> <xsd:element ref="tipos:ListaMensagemRetorno" minOccurs="1" maxOccurs="1"/> </xsd:choice> </xsd:complexType> </xsd:element> </xsd:schema> and the following class: [System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "2.0.50727.3038")] [System.SerializableAttribute()] [System.Diagnostics.DebuggerStepThroughAttribute()] [System.ComponentModel.DesignerCategoryAttribute("code")] [System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true, Namespace = "http://www.ginfes.com.br/servico_consultar_situacao_lote_rps_envio_v03.xsd")] [System.Xml.Serialization.XmlRootAttribute(Namespace = "http://www.ginfes.com.br/servico_consultar_situacao_lote_rps_envio_v03.xsd", IsNullable = false)] public partial class ConsultarSituacaoLoteRpsEnvio { [System.Xml.Serialization.XmlElementAttribute(Order = 0)] public tcIdentificacaoPrestador Prestador { get; set; } [System.Xml.Serialization.XmlElementAttribute(Order = 1)] public string Protocolo { get; set; } } Use the following code to deserialize the object: XmlSerializer respSerializer = new XmlSerializer(typeof(ConsultarSituacaoLoteRpsResposta)); StringReader reader = new StringReader(resp); ConsultarSituacaoLoteRpsResposta respModel = (ConsultarSituacaoLoteRpsResposta)respSerializer.Deserialize(reader); does not occur any error but the properties of objects are null, anyone know what is happening?

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• not able to Deserialize object

  - by Ravisha

  I am having following peice of code ,where in i am trying to serialize and deserailize object of StringResource class. Please note Resource1.stringXml = its coming from resource file.If i pass strelemet.outerXMl i get the object from Deserialize object ,but if i pass Resource1.stringXml i am getting following exception {"< STRING xmlns='' was not expected."} System.Exception {System.InvalidOperationException} class Program { static void Main(string[] args) { StringResource str = new StringResource(); str.DELETE = "CanDelete"; str.ID= "23342"; XmlElement strelemet = SerializeObjectToXmlNode (str); StringResource strResourceObject = DeSerializeXmlNodeToObject<StringResource>(Resource1.stringXml); Console.ReadLine(); } public static T DeSerializeXmlNodeToObject<T>(string objectNodeOuterXml) { try { TextReader objStringsTextReader = new StringReader(objectNodeOuterXml); XmlSerializer stringResourceSerializer = new XmlSerializer(typeof(T),string.Empty); return (T)stringResourceSerializer.Deserialize(objStringsTextReader); } catch (Exception excep) { return default(T); } } public static XmlElement SerializeObjectToXmlNode(object obj) { using (MemoryStream memoryStream = new MemoryStream()) { try { XmlSerializerNamespaces xmlNameSpace = new XmlSerializerNamespaces(); xmlNameSpace.Add(string.Empty, string.Empty); XmlWriterSettings writerSettings = new XmlWriterSettings(); writerSettings.CloseOutput = false; writerSettings.Encoding = System.Text.Encoding.UTF8; writerSettings.Indent = false; writerSettings.OmitXmlDeclaration = true; XmlWriter writer = XmlWriter.Create(memoryStream, writerSettings); XmlSerializer xmlserializer = new XmlSerializer(obj.GetType()); xmlserializer.Serialize(writer, obj, xmlNameSpace); writer.Close(); memoryStream.Position = 0; XmlDocument serializeObjectDoc = new XmlDocument(); serializeObjectDoc.Load(memoryStream); return serializeObjectDoc.DocumentElement; } catch (Exception excep) { return null; } } } } public class StringResource { [XmlAttribute] public string DELETE; [XmlAttribute] public string ID; }

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• Deserialize complex JSON (VB.NET)

  - by Ssstefan

  I'm trying to deserialize json returned by some directions API similar to Google Maps API. My JSON is as follows (I'm using VB.NET 2008): jsontext = { "version":0.3, "status":0, "route_summary": { "total_distance":300, "total_time":14, "start_point":"43", "end_point":"42" }, "route_geometry":[[51.025421,18.647631],[51.026131,18.6471],[51.027802,18.645639]], "route_instructions": [["Head northwest on 43",88,0,4,"88 m","NW",334.8],["Continue on 42",212,1,10,"0.2 km","NW",331.1,"C",356.3]] } So far I came up with the following code: Dim js As New System.Web.Script.Serialization.JavaScriptSerializer Dim lstTextAreas As Output_CloudMade() = js.Deserialize(Of Output_CloudMade())(jsontext) I'm not sure how to define complex class, i.e. Output_CloudMade. I'm trying something like: Public Class RouteSummary Private mTotalDist As Long Private mTotalTime As Long Private mStartPoint As String Private mEndPoint As String Public Property TotalDist() As Long Get Return mTotalDist End Get Set(ByVal value As Long) mTotalDist = value End Set End Property Public Property TotalTime() As Long Get Return mTotalTime End Get Set(ByVal value As Long) mTotalTime = value End Set End Property Public Property StartPoint() As String Get Return mStartPoint End Get Set(ByVal value As String) mStartPoint = value End Set End Property Public Property EndPoint() As String Get Return mEndPoint End Get Set(ByVal value As String) mEndPoint = value End Set End Property End Class Public Class Output_CloudMade Private mVersion As Double Private mStatus As Long Private mRSummary As RouteSummary 'Private mRGeometry As RouteGeometry 'Private mRInstructions As RouteInstructions Public Property Version() As Double Get Return mVersion End Get Set(ByVal value As Double) mVersion = value End Set End Property Public Property Status() As Long Get Return mStatus End Get Set(ByVal value As Long) mStatus = value End Set End Property Public Property Summary() As RouteSummary Get Return mRSummary End Get Set(ByVal value As RouteSummary) mRSummary = value End Set End Property 'Public Property Geometry() As String ' Get ' End Get ' Set(ByVal value As String) ' End Set 'End Property 'Public Property Instructions() As String ' Get ' End Get ' Set(ByVal value As String) ' End Set 'End Property End Class but it does not work. The problem is with complex properties, like route_summary. It is filled with "nothing". Other properties, like "status" or "version" are filled properly. Any ideas, how to define class for the above JSON? Can you share some working code for deserializing JSON in VB.NET? Thanks,

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• Handling FormatExceptions using XmlSerializer.Deserialize

  - by qntmfred

  I have a third party web service that returns this xml <book> <release_date>0000-00-00</release_date> </book> I am trying to deserialize it into this class public class Book { [XmlElement("release_date")] public DateTime ReleaseDate { get; set; } } But because 0000-00-00 isn't a valid DateTime, I get a FormatException. What's the best way to handle this?

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• How to deserialize "<MyType><StartDate>01/01/2000</StartDate></MyType>"

  - by afin

  How to deserialize "<MyType><StartDate>01/01/2000</StartDate></MyType>" below is the MyType definition [Serializable] public class MyType { DateTime _StartDate; public DateTime StartDate { set { _StartDate = value; } get { return _StartDate; } } } Got the following error while deserializing {"The string '01/01/2000' is not a valid AllXsd value."} [System.FormatException]: {"The string '01/01/2000' is not a valid AllXsd value."} Data: {System.Collections.ListDictionaryInternal} HelpLink: null InnerException: null Message: "The string '01/01/2000' is not a valid AllXsd value." Source: "System.Xml" StackTrace: " at System.Xml.Schema.XsdDateTime..ctor(String text, XsdDateTimeFlags kinds)\r\n at System.Xml.XmlConvert.ToDateTime(String s, XmlDateTimeSerializationMode dateTimeOption)\r\n at System.Xml.Serialization.XmlCustomFormatter.ToDateTime(String value)\r\n at System.Xml.Serialization.XmlSerializationReader.ToDateTime(String value)\r\n at Microsoft.Xml.Serialization.GeneratedAssembly.XmlSerializationReaderMyType.Read2_MyType(Boolean isNullable, Boolean checkType)\r\n at Microsoft.Xml.Serialization.GeneratedAssembly.XmlSerializationReaderMyType.Read3_MyType()" TargetSite: {Void .ctor(System.String, System.Xml.Schema.XsdDateTimeFlags)}

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• Custom Designers deserialize SplitContainer problem

  - by Hamid

  Hi I just using this link http://msdn.microsoft.com/en-us/magazine/cc163634.aspx for extent custom designer. I using BasicDesignerLoader type because need xml data for save in db. all thing work properly. I try add SplitContainer to form and then serialize form, it's ok, but when try deserialize it, items that contains in SplitContainer Panel, failed. after i check it see not implement ReadRefrence method (only wrote WriteReference method) How to implement it fast ? Note: After download sample from http://download.microsoft.com/download/f/2/7/f279e71e-efb0-4155-873d-5554a0608523/DesignerHosting.exe, you must add typeof(System.Windows.Forms.SplitContainer) to ToolboxXmlManager.cs(Line 13) in ToolBox project. Note2: Find (De)Serialize method in BasicHostLoader.cs at Loader Project Thanks in advanced

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• Deserialize XML to custom Class in Flex?

  - by MysticEarth

  Is it possible to deserialize an XML file to a class in Flex without manually checking the XML and/or creating the class, with the help of a HttpService? Edit: Explained a bit more and better. We have an XML file which contains: <Project> <Name>NameGoesHere</Name> <Number>15</Number> </Project> In Flex we want this to be serialized to our Project class: package com.examplepackage { import mx.collections.ArrayCollection; [XmlClass] public class Project { public var Name:String; public var Number:int; public function Project() { } } } The XML is loaded with a HTTPService.

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• Deserialize array values to .NET properties using DataContractJsonSerializer

  - by James Cadd

  I'm working with the DataContractJsonSerializer in Silverlight 4 and would like to deserialize the following JSON: { "collectionname":"Books", "collectionitems": [ ["12345-67890",201, "Book One"], ["09876-54321",45, "Book Two"] ] } Into classes like the following: class BookCollection { public string collectionname { get; set; } public List<Book> collectionitems { get; set; } } class Book { public string Id { get; set; } public int NumberOfPages { get; set; } public string Title { get; set; } } What's the proper place to extend DataContractJsonSerializer to map the unnamed first array element in "collectionitems" to the Id property of the Book class, the second element to the NumberOfPages property and the final element to Title? I don't have control over the JSON generation in this instance and would like the solution to work with the Silverlight subset of .NET. It would be great if the solution could perform the reverse for serialization as well.

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• XmlSerializer Deserialize failures

  - by smvlad

  I have wsdl from third party server. Method that i'm interested in returns XmlNode. My thought was wrap web methods and use XmlSerializer to return strongly typed objects. Returned xml looks like this (i removed soap headers): <Response xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:type="ResponseExt" xmlns="http://www.thirdparty.com/lr/"> <Code>0</Code> <Message>SUCCESS</Message> <SessionId>session_token</SessionId> </Response> Looked simple. Created a class: [XmlRoot("Response")] public class MyClass { public string Code {get; set;} public string Message {get; set;} public string SessionId {get; set;} } Processing time: //XmlNode node = xml from above XmlSerializer serializer = new XmlSerializer(typeof(MyClass)); XmlNodeReader reader = new XmlNodeReader(node); Myclass myclass = serializer.Deserialize(reader) as MyClass Last line is where it blows up with inner exception message: The specified type was not recognized: name='ResponseExt', namespace='http://www.thirdparty.com/lr/', at . I can't figure out how to make Serializer happy and what exactly these two mean xsi:type="ResponseExt" xmlns="http://www.thirdparty.com/lr/ As always any advice and pointer are appreciated

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• WCF service The maximum array length quota (16384) has been exceeded

  - by dmitry.baranovsky

  I have a wsf service and a client application. While trying to communicate the client and the service I've gotten the following message: "The formatter threw an exception while trying to deserialize the message: There was an error while trying to deserialize parameter http://tempuri.org/:blob. The InnerException message was 'There was an error deserializing the object of type FileBlob. The maximum array length quota (16384) has been exceeded while reading XML data. This quota may be increased by changing the MaxArrayLength property on the XmlDictionaryReaderQuotas object used when creating the XML reader. Line 1, position 25931.'. Please see InnerException for more details." I have the customBinding element and it doesn't allow me to insert "readerQuotas" section. In both the client and service configs I have the following binding element: <customBinding> <binding name="LicenseServiceBinding" closeTimeout="00:01:00" openTimeout="00:01:00" receiveTimeout="00:10:00" sendTimeout="00:01:00"> <security authenticationMode="UserNameOverTransport"> <localClientSettings maxClockSkew="00:07:00" /> <localServiceSettings maxClockSkew="00:07:00" /> </security> <windowsStreamSecurity /> <httpsTransport maxReceivedMessageSize="2147483646"/> </binding> </customBinding> Thanks in advance for any help:)

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• WCF Datacontract, some fields do not deserialize

  - by jhersh

  Problem: I have a WCF service setup to be an endpoint for a call from an external system. The call is sending plain xml. I am testing the system by sending calls into the service from Fiddler using the RequestBuilder. The issue is that all of my fields are being deserialized with the exception of two fields. price_retail and price_wholesale. What am I missing? All of the other fields deserialize without an issue - the service responds. It is just these fields. XML Message: <widget_conclusion> <list_criteria_id>123</list_criteria_id> <list_type>consumer</list_type> <qty>500</qty> <price_retail>50.00</price_retail> <price_wholesale>40.00</price_wholesale> <session_id>123456789</session_id> </widget_conclusion> Service Method: public string WidgetConclusion(ConclusionMessage message) { var priceRetail = message.PriceRetail; } Message class: [DataContract(Name = "widget_conclusion", Namespace = "")] public class ConclusionMessage { [DataMember(Name = "list_criteria_id")] public int CriteriaId { get; set;} [DataMember(Name = "list_type")] public string ListType { get; set; } [DataMember(Name = "qty")] public int ListQuantity { get; set; } [DataMember(Name = "price_retail")] public decimal PriceRetail { get; set; } [DataMember(Name = "price_wholesale")] public decimal PriceWholesale { get; set; } [DataMember(Name = "session_id")] public string SessionId { get; set; } }

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• XML Serialize and Deserialize Problem XML Structure

  - by Ph.E

  Camarades, I'm having the following problem. Caught a list Struct, Serialize (Valid W3C) and send to a WebService. In the WebService I receive, transform to a string, valid by the W3C and then Deserializer, but when I try to run it, always occurs error, saying that some objects were not closed. Any help? Sent Code: #region ListToXML private XmlDocument ListToXMLDocument(object __Lista) { XmlDocument _ListToXMLDocument = new XmlDocument(); try { XmlDocument _XMLDoc = new XmlDocument(); MemoryStream _StreamMem = new MemoryStream(); XmlSerializer _XMLSerial = new XmlSerializer(__Lista.GetType()); StreamWriter _StreamWriter = new StreamWriter(_StreamMem, Encoding.UTF8); _XMLSerial.Serialize(_StreamWriter, __Lista); _StreamMem.Position = 0; _XMLDoc.Load(_StreamMem); if (_XMLDoc.ChildNodes.Count > 0) _ListToXMLDocument = _XMLDoc; } catch (Exception __Excp) { new uException(__Excp).GerarLogErro(CtNomeBiblioteca); } return _ListToXMLDocument; } #endregion Receive Code: #region XMLDocumentToTypedList private List<T> XMLDocumentToTypedList<T>(string __XMLDocument) { List<T> _XMLDocumentToTypedList = new List<T>(); try { XmlSerializer _XMLSerial = new XmlSerializer(typeof(List<T>)); MemoryStream _MemStream = new MemoryStream(); StreamWriter _StreamWriter = new StreamWriter(_MemStream, Encoding.UTF8); _StreamWriter.Write(__XMLDocument); _MemStream.Position = 0; _XMLDocumentToTypedList = (List<T>)_XMLSerial.Deserialize(_MemStream); return _XMLDocumentToTypedList; } catch (Exception _Ex) { new uException(_Ex).GerarLogErro(CtNomeBiblioteca); throw _Ex; } } #endregion

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• Cast errors with IXmlSerializable

  - by Nathan

  I am trying to use the IXmlSerializable interface to deserialize an Object (I am using it because I need specific control over what gets deserialized and what does not. See my previous question for more information). However, I'm stumped as to the error message I get. Below is the error message I get (I have changed some names for clarity): An unhandled exception of type 'System.InvalidCastException' occurred in App.exe Additional information: Unable to cast object of type 'System.Xml.XmlNode[]' to type 'MyObject'. MyObject has all the correct methods defined for the interface, and regardless of what I put in the method body for ReadXml() I still get this error. It doesn't matter if it has my implementation code or if it's just blank. I did some googling and found an error that looks similar to this involving polymorphic objects that implement IXmlSerializable. However, my class does not inherit from any others (besides Object). I suspected this may be an issue because I never reference XmlNode any other time in my code. Microsoft describes a solution to the polymorphism error: https://connect.microsoft.com/VisualStudio/feedback/details/422577/incorrect-deserialization-of-polymorphic-type-that-implements-ixmlserializable?wa=wsignin1.0#details The code the error occurs at is as follows. The object to be read back in is an ArrayList of "MyObjects" IO::FileStream ^fs = gcnew IO::FileStream(filename, IO::FileMode::Open); array<System::Type^>^ extraTypes = gcnew array<System::Type^>(1); extraTypes[0] = MyObject::typeid; XmlSerializer ^xmlser = gcnew XmlSerializer(ArrayList::typeid, extraTypes); System::Object ^obj; obj = xmlser->Deserialize(fs); fs->Close(); ArrayList ^al = safe_cast<ArrayList^>(obj); MyObject ^objs; for each(objs in al) //Error occurs here { //do some processing } Thanks for reading and for any help.

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• How to deserialize implementation classes in OSGi

  - by Daniel Schneller

  In an eRCP OSGi based application the user can push a button and go to a lock screen similar to that of Windows or Mac OS X. When this happens, the current state of the application is serialized to a file and control is handed over to the lock screen. In this mobile application memory is very tight, so we need to get rid of the original view/controller when the lock screen comes up. This works fine and we end up with a binary serialized file. Once the user logs back in, the file is read in again and the original state of the application restored. This works fine as well, except when the controller that was serialized contained a reference to an object which comes from a different bundle. In my concrete case the original controller (from bundle A) can call a web service and gets a result back. Nothing fancy, just some Strings and Numbers in a simple value holder class. However the controller only sees this as a Result interface; the actual runtime object (ResultImpl) is defined and created in a different bundle (bundle B, the webservice client implementation) and returned via a service call. When the deserialization now tries to thaw the controller from the file, it throws a ClassNotFound exception, complaining about not being able to deserialize the result object, because deserialization is called from bundle A, which cannot see the ResultImpl class from bundle B. Any ideas on how to work around that? The only thing I could come up with is to clone all the individual values into another object, defined in the controller's bundle, but this seems like quite a hassle.

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• Deserialize xml which uses attribute name/value pairs

  - by Bodyloss

  My application receives a constant stream of xml files which are more or less a direct copy of the database record <record type="update"> <field name="id">987654321</field> <field name="user_id">4321</field> <field name="updated">2011-11-24 13:43:23</field> </record> And I need to deserialize this into a class which provides nullable property's for all columns class Record { public long? Id { get; set; } public long? UserId { get; set; } public DateTime? Updated { get; set; } } I just cant seem to work out a method of doing this without having to parse the xml file manually and switch on the field's name attribute to store the values. Is their a way this can be achieved quickly using an XmlSerializer? And if not is their a more efficient way of parsing it manually? Regards and thanks My main problem is that the attribute name needs to have its value set to a property name and its value as the contents of a <field>..</field> element

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• C++: how serialize/deserialize objects without any library?

  - by Winte Winte

  I try to understand how serializing/deserializing works in c++, so I want to do that without any libs. But I really stuck with that. I start with simple objects but when I try to deserilize a vector I understand that I can't get a vector without if I don't write it size before. Moreover, I don't know which format of file I should choose because if digits will be existed before size of vector I haven't chance to read it right. However it is only the vector but I also want to do that with classes and map container. My task is serialize/deserialize a objects as this: PersonInfo { unsigned int age_; string name_; enum { undef, man, woman } sex_; } Person : PersonInfo { vector<Person> children_; map<string, PersonInfo> addrBook_; } Currently I know how to serialize simple objects in way as this: vector<PersonInfo> vecPersonInfo; vecPersonInfo.push_back(*personInfo); vecPersonInfo.push_back(*oneMorePersonInfo); ofstream file("file", ios::out | ios::binary); if (!file) { cout<<"can not open file"; } else { vector<PersonInfo>::const_iterator iterator = vecPersonInfo.begin(); for (; iterator != vecPersonInfo.end(); iterator++) { file<<*iterator; } Could you please suggest how I can do this for this conplex object or a good tutorial that explain it clearly?

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• Deserialize an XML file - an error in xml document (1,2)

  - by Lindsay Fisher

  I'm trying to deserialize an XML file which I receive from a vendor with XmlSerializer, however im getting this exception: There is an error in XML document (1, 2).InnerException Message "<delayedquotes xmlns=''> was not expected.. I've searched the stackoverflow forum, google and implemented the advice, however I'm still getting the same error. Please find the enclosed some content of the xml file: <delayedquotes id="TestData"> <headings> <title/> <bid>bid</bid> <offer>offer</offer> <trade>trade</trade> <close>close</close> <b_time>b_time</b_time> <o_time>o_time</o_time> <time>time</time> <hi.lo>hi.lo</hi.lo> <perc>perc</perc> <spot>spot</spot> </headings> <instrument id="Test1"> <title id="Test1">Test1</title> <bid>0</bid> <offer>0</offer> <trade>0</trade> <close>0</close> <b_time>11:59:00</b_time> <o_time>11:59:00</o_time> <time>11:59:00</time> <perc>0%</perc> <spot>0</spot> </instrument> </delayedquotes> and the code [Serializable, XmlRoot("delayedquotes"), XmlType("delayedquotes")] public class delayedquotes { [XmlElement("instrument")] public string instrument { get; set; } [XmlElement("title")] public string title { get; set; } [XmlElement("bid")] public double bid { get; set; } [XmlElement("spot")] public double spot { get; set; } [XmlElement("close")] public double close { get; set; } [XmlElement("b_time")] public DateTime b_time { get; set; } [XmlElement("o_time")] public DateTime o_time { get; set; } [XmlElement("time")] public DateTime time { get; set; } [XmlElement("hi")] public string hi { get; set; } [XmlElement("lo")] public string lo { get; set; } [XmlElement("offer")] public double offer { get; set; } [XmlElement("trade")] public double trade { get; set; } public delayedquotes() { } }

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• Gson Deserialize to Java Tree

  - by MountainX

  I need to deserialize some JSON to a Java tree structure that contains TreeNodes and NodeData. TreeNodes are thin wrappers around NodeData. I'll provide the JSON and the classes below. I have looked at the usual Gson help sources, including here, but I can't seem to come up with the solution. Serialization works fine with Gson. The JSON below was produced by Gson. But deserialization is the problem I need help with. Can someone show me how to write the deserializer (or suggest an alternative approach using Gson best practices)? Here is my JSON. The "data" element corresponds to class NodeData, and the "subList" JSON element corresponds to Java class TreeNode. { "data": { "version": "032", "name": "root", "path": "/", "id": "1", "parentId": "0", "toolTipText": "rootNode" }, "subList": [ { "data": { "version": "032", "name": "level1", "labelText": "Some Label Text at Level1", "path": "/root", "id": "2", "parentId": "1", "toolTipText": "a tool tip for level1" }, "subList": [ { "data": { "version": "032", "name": "level1_1", "labelText": "Label level1_1", "path": "/root/level1", "id": "3", "parentId": "2", "toolTipText": "ToolTipText for level1_1" } }, { "data": { "version": "032", "name": "level1_2", "labelText": "Label level1_2", "path": "/root/level1", "id": "4", "parentId": "2", "toolTipText": "ToolTipText for level1_2" } } ] }, { "data": { "version": "032", "name": "level2", "path": "/root", "id": "5", "parentId": "1", "toolTipText": "ToolTipText for level2" }, "subList": [ { "data": { "version": "032", "name": "level2_1", "labelText": "Label level2_1", "path": "/root/level2", "id": "6", "parentId": "5", "toolTipText": "ToolTipText for level2_1" }, "subList": [ { "data": { "version": "032", "name": "level2_1_1", "labelText": "Label level2_1_1", "path": "/root/level2/level2_1", "id": "7", "parentId": "6", "toolTipText": "ToolTipText for level2_1_1" } } ] } ] } ] } Here are the Java classes: public class Tree { private TreeNode rootElement; private HashMap<String, TreeNode> indexById; private HashMap<String, TreeNode> indexByKey; private long nextAvailableID = 0; public Tree() { indexById = new HashMap<String, TreeNode>(); indexByKey = new HashMap<String, TreeNode>(); } public long getNextAvailableID() { return this.nextAvailableID; } ... [snip] ... } public class TreeNode { private Tree tree; private NodeData data; public List<TreeNode> subList; private HashMap<String, TreeNode> indexById; private HashMap<String, TreeNode> indexByKey; //this default ctor is used only for Gson deserialization public TreeNode() { this.tree = new Tree(); indexById = tree.getIdIndex(); indexByKey = tree.getKeyIndex(); this.makeRoot(); tree.setRootElement(this); } //makes this node the root node. Calling this obviously has side effects. public NodeData makeRoot() { NodeData rootProp = new NodeData(TreeFactory.version, "example", "rootNode"); String nextAvailableID = getNextAvailableID(); if (!nextAvailableID.equals("1")) { throw new IllegalStateException(); } rootProp.setId(nextAvailableID); rootProp.setParentId("0"); rootProp.setKeyPathOnly("/"); rootProp.setSchema(tree); this.data = rootProp; rootProp.setNode(this); indexById.put(rootProp.getId(), this); indexByKey.put(rootProp.getKeyFullName(), this); return rootProp; } ... [snip] ... } public class NodeData { protected static Tree tree; private LinkedHashMap<String, String> keyValMap; protected String version; protected String name; protected String labelText; protected String path; protected String id; protected String parentId; protected TreeNode node; protected String toolTipText;//tool tip or help string protected String imagePath;//for things like images; not persisted to properties protected static final String delimiter = "/"; //this default ctor is used only for Gson deserialization public NodeData() { this("NOT_SET", "NOT_SET", "NOT_SET"); } ... [snip] ... } Side note: The tree data structure is a bit strange, as it includes indexes. Obviously, this isn't a typical search tree. In fact, the tree is used mainly to create a hierarchical path element (String) in each NodeData element. (Example: "path": "/root/level2/level2_1".) The indexes are actually used for NodeData retrieval.

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• How to Deserialize this Xml file?

  - by Robin-Hood

  Hello experts, I have this Xml file, and I need to Deserialize it back to a class. The problem is: what is the right structure/design of this class considering that the count of the Xml element (RowInfo) is not constant? The Xml File: <?xml version="1.0"?> <SomeObject xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" > <Layers> <Layer Id="0"> <RowInfo>1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1</RowInfo> <RowInfo>1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,0,1</RowInfo> <RowInfo>1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1</RowInfo> <RowInfo>1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1</RowInfo> <RowInfo>1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1</RowInfo> <RowInfo>1,1,1,0,0,1,1,1,1,1,1,1,1,1,1,0,0,1,1,1</RowInfo> <RowInfo>1,1,1,0,0,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1</RowInfo> <RowInfo>1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1</RowInfo> <RowInfo>1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1</RowInfo> <RowInfo>1,1,1,1,1,1,1,1,1,0,0,1,1,1,1,1,1,1,1,1</RowInfo> <RowInfo>1,1,1,0,0,1,1,1,1,1,1,1,1,1,1,1,0,0,1,1</RowInfo> <RowInfo>1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1</RowInfo> <RowInfo>1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1</RowInfo> <RowInfo>1,1,1,1,1,1,1,1,1,0,0,1,1,1,1,1,1,1,1,1</RowInfo> <RowInfo>1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1</RowInfo> <RowInfo>1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1</RowInfo> <RowInfo>1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1</RowInfo> <RowInfo>1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1</RowInfo> <RowInfo>1,1,1,0,0,1,1,1,1,1,1,1,1,1,0,0,1,0,0,1</RowInfo> <RowInfo>1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,0,1,1,1,1</RowInfo> </Layer> </Layers> </SomeObject> Appreciate your help. Thanks. Edit1:also considering that (Layers) may contains more than one layer.

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• How to deserialize MXML with PHP?

  - by Ivan Petrushev

  Hello, I have an array structure that have to be converted to MXML. I know of PEAR XML_Serialize extension but it seems the output format it produces is a bit different. PHP generated XML: <zone columns="3"> <select column="1" /> <select column="4" /> </zone> MXML format: <mx:zone columns="3"> <mx:select column="1" /> <mx:select column="4" /> </mx:zone> Is that "mx:" prefix required for all the tags? If yes, can I make the XML_Serialize put it before each tag (without renaming my data structure fields to "mx:something")? Here are my options for XML_Serialize: $aOptions = array('addDecl' => true, 'indent' => " ", 'rootName' => 'template', 'scalarAsAttributes' => true, 'mode' => 'simplexml');

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• c# xml deserialize

  - by Moony

  I have xml wherein i have xml within it again, like: <?xml version=\"1.0\" encoding=\"UTF-8\"?> <Tag> <Value1> </Value1> <Value2><?xml version=\"1.0\" encoding=\"UTF-8\"?>... </Value2> </Tag> Deserializing doesnt work on this string in c#. I construct this string in java and send it to a c# app. how can i get around this?

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• serialize/deserialize a LinkedHashMap (android) java

  - by user348058

  So i want to pass a LinkedHashMap to an intent. //SEND THE MAP Intent singlechannel = new Intent(getBaseContext(),singlechannel.class); singlechannel.putExtra("db",shows1);//perase to startActivity(singlechannel); //GET THE MAP LinkedHashMap<String,String> db = new LinkedHashMap<String,String>(); db=(LinkedHashMap<String,String>) getIntent().getSerializableExtra("db"); This one Worked Like a charm with HashMap. But with LinkedHashMap i got a problem I got a warning "Type safety: Unchecked cast from Serializable to LinkedHashMap" But i had this warning with HashMap too? Any ideas.Any help is much appreciated Also I just saw this. https://issues.apache.org/jira/browse/HARMONY-6498

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• XmlSerializer.Deserialize method appends timezone to a time and datetime field

  - by G33kKahuna

  Have a small script in Microsoft.NET 2.0 that deserializes a XML back to a typed object, connects dyanimcally to a web service using ServiceDescription and binds the deserialized typed object to the WebMethod inbound. The XML prior to serialization looks like below <completion_time>12:19:38</completion_time> on the wire when communicating to the web service looks like below <completion_time>12:19:38.0000000-04:00</completion_time> with the timezone appended to the end. This is causing the time to be read differently when communicating to a web service at a different timezone. is there anyway to let XmlSerializer skip the timezone? Or any other known workarounds?

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• How to serialize an Object of type System.Net.Mime.ContentType?

  - by Emanuel

  I want to parse a text message and store in into an object of type System.Net.Mime.Attachment. The problem comes when I want to serialize this object. Error: Type "System.Net.Mime.ContentType" is not marked as serializable. How can I avoid this? Thanks.

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• c# send recive object over network?

  - by Data-Base

  Hello, I'm working on a server/client project the client will be asking the server for info and the server will send them back to the client the info may be string,number, array, list, arraylist or any other object I found allot of examples but I faced issues!!!! the solution I found so far is to serialize the object (data) and send it then de-serialize it to process here is the server code public void RunServer(string SrvIP,int SrvPort) { try { var ipAd = IPAddress.Parse(SrvIP); /* Initializes the Listener */ if (ipAd != null) { var myList = new TcpListener(ipAd, SrvPort); /* Start Listeneting at the specified port */ myList.Start(); Console.WriteLine("The server is running at port "+SrvPort+"..."); Console.WriteLine("The local End point is :" + myList.LocalEndpoint); Console.WriteLine("Waiting for a connection....."); while (true) { Socket s = myList.AcceptSocket(); Console.WriteLine("Connection accepted from " + s.RemoteEndPoint); var b = new byte[100]; int k = s.Receive(b); Console.WriteLine("Recieved..."); for (int i = 0; i < k; i++) Console.Write(Convert.ToChar(b[i])); string cmd = Encoding.ASCII.GetString(b); if (cmd.Contains("CLOSE-CONNECTION")) break; var asen = new ASCIIEncoding(); // sending text s.Send(asen.GetBytes("The string was received by the server.")); // the line bove to be modified to send serialized object? Console.WriteLine("\nSent Acknowledgement"); s.Close(); Console.ReadLine(); } /* clean up */ myList.Stop(); } } catch (Exception e) { Console.WriteLine("Error..... " + e.StackTrace); } } here is the client code that should return an object public object runClient(string SrvIP, int SrvPort) { object obj = null; try { var tcpclnt = new TcpClient(); Console.WriteLine("Connecting....."); tcpclnt.Connect(SrvIP, SrvPort); // use the ipaddress as in the server program Console.WriteLine("Connected"); Console.Write("Enter the string to be transmitted : "); var str = Console.ReadLine(); Stream stm = tcpclnt.GetStream(); var asen = new ASCIIEncoding(); if (str != null) { var ba = asen.GetBytes(str); Console.WriteLine("Transmitting....."); stm.Write(ba, 0, ba.Length); } var bb = new byte[2000]; var k = stm.Read(bb, 0, bb.Length); string data = null; for (var i = 0; i < k; i++) Console.Write(Convert.ToChar(bb[i])); //convert to object code ?????? Console.ReadLine(); tcpclnt.Close(); } catch (Exception e) { Console.WriteLine("Error..... " + e.StackTrace); } return obj; } I need to know a good serialize/serialize and how to integrate it into the solution above :-( I would be really thankful for any help cheers

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