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  • why are read only form fields in django a bad idea?

    - by jamida
    I've been looking for a way to create a read-only form field and every article I've found on the subject comes with a statement that "this is a bad idea". Now for an individual form, I can understand that there are other ways to solve the problem, but using a read only form field in a modelformset seems like a completely natural idea. Consider a teacher grade book application where the teacher would like to be able to enter all the students' (note the plural students) grades with a single SUBMIT. A modelformset could iterate over all the student-grades in such a way that the student name is read-only and the grade is the editable field. I like the power and convenience of the error checking and error reporting you get with a modelformset but leaving the student name editable in such a formset is crazy. Since the expert django consensus is that read-only form fields are a bad idea, I was wondering what the standard django best practice is for the example student-grade example above?

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  • Django admin.py missing field error

    - by user782400
    When I include 'caption', I get an error saying EntryAdmin.fieldsets[1][1]['fields']' refers to field 'caption' that is missing from the form In the admin.py; I have imported the classes from joe.models import Entry,Image Is that because my class from models.py is not getting imported properly ? Need help in resolving this issue. Thanks. models.py class Image(models.Model): image = models.ImageField(upload_to='joe') caption = models.CharField(max_length=200) imageSrc = models.URLField(max_length=200) user = models.CharField(max_length=20) class Entry(models.Model): image = models.ForeignKey(Image) mimeType = models.CharField(max_length=20) name = models.CharField(max_length=200) password = models.URLField(max_length=50) admin.py class EntryAdmin(admin.ModelAdmin): fieldsets = [ ('File info', {'fields': ['name','password']}), ('Upload image', {'fields': ['image','caption']})] list_display = ('name', 'mimeType', 'password') admin.site.register(Entry, EntryAdmin) admin.site.register(Image)

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  • A Django form for entering a 0 to n email addresses

    - by Erik
    I have a Django application with some fairly common models in it: UserProfile and Organization. A UserProfile or an Organization can both have 0 to n emails, so I have an Email model that has a GenericForeignKey. UserProfile and Organization Models both have a GenericRelation called emails that points back to the Email model (summary code provided below). The question: what is the best way to provide an Organization form that allows a user to enter organization details including 0 to n email addresses? My Organization create view is a Django class-based view. I'm leading towards creating a dynamic form and an enabling it with Javascript to allow the user to add as many email addresses as necessary. I will render the form with django-crispy-forms. I've thought about doing this with a formset embedded within the form, but this seems like overkill for email addresses. Embedding a formset in a form delivered by a class-based view is cumbersome too. Note that the same issue occurs with the Organization fields phone_numbers and locations. emails.py: from django.db import models from parent_mixins import Parent_Mixin class Email(Parent_Mixin,models.Model): email_type = models.CharField(blank=True,max_length=100,null=True,default=None,verbose_name='Email Type') email = models.EmailField() class Meta: app_label = 'core' organizations.py: from emails import Email from locations import Location from phone_numbers import Phone_Number from django.contrib.contenttypes import generic from django.db import models class Organization(models.Model): active = models.BooleanField() duns_number = models.CharField(blank=True,default=None,null=True,max_length=9) # need to validate this emails = generic.GenericRelation(Email,content_type_field='parent_type',object_id_field='parent_id') legal_name = models.CharField(blank=True,default=None,null=True,max_length=200) locations = generic.GenericRelation(Location,content_type_field='parent_type',object_id_field='parent_id') name = models.CharField(blank=True,default=None,null=True,max_length=200) organization_group = models.CharField(blank=True,default=None,null=True,max_length=200) organization_type = models.CharField(blank=True,default=None,null=True,max_length=200) phone_numbers = generic.GenericRelation(Phone_Number,content_type_field='parent_type',object_id_field='parent_id') taxpayer_id_number = models.CharField(blank=True,default=None,null=True,max_length=9) # need to validate this class Meta: app_label = 'core' parent_mixins.py from django.contrib.contenttypes.models import ContentType from django.contrib.contenttypes import generic from django.db import models class Parent_Mixin(models.Model): parent_type = models.ForeignKey(ContentType,blank=True,null=True) parent_id = models.PositiveIntegerField(blank=True,null=True) parent = generic.GenericForeignKey('parent_type', 'parent_id') class Meta: abstract = True app_label = 'core'

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  • Populating Models from other Models in Django?

    - by JT
    This is somewhat related to the question posed in this question but I'm trying to do this with an abstract base class. For the purposes of this example lets use these models: class Comic(models.Model): name = models.CharField(max_length=20) desc = models.CharField(max_length=100) volume = models.IntegerField() ... <50 other things that make up a Comic> class Meta: abstract = True class InkedComic(Comic): lines = models.IntegerField() class ColoredComic(Comic): colored = models.BooleanField(default=False) In the view lets say we get a reference to an InkedComic id since the tracer, err I mean, inker is done drawing the lines and it's time to add color. Once the view has added all the color we want to save a ColoredComic to the db. Obviously we could do inked = InkedComic.object.get(pk=ink_id) colored = ColoredComic() colored.name = inked.name etc, etc. But really it'd be nice to do: colored = ColoredComic(inked_comic=inked) colored.colored = True colored.save() I tried to do class ColoredComic(Comic): colored = models.BooleanField(default=False) def __init__(self, inked_comic = False, *args, **kwargs): super(ColoredComic, self).__init__(*args, **kwargs) if inked_comic: self.__dict__.update(inked_comic.__dict__) self.__dict__.update({'id': None}) # Remove pk field value but it turns out the ColoredComic.objects.get(pk=1) call sticks the pk into the inked_comic keyword, which is obviously not intended. (and actually results in a int does not have a dict exception) My brain is fried at this point, am I missing something obvious, or is there a better way to do this?

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  • Testing Django Inline ModelForms: How to arrange POST data?

    - by unclaimedbaggage
    Hi folks, I have a Django 'add business' view which adds a new business with an inline 'business_contact' form. The form works fine, but I'm wondering how to write up the unit test - specifically, the 'postdata' to send to self.client.post(settings.BUSINESS_ADD_URL, postdata) I've inspected the fields in my browser and tried adding post data with corresponding names, but I still get a 'ManagementForm data is missing or has been tampered with' error when run. Anyone know of any resources for figuring out how to post inline data? Relevant models, views & forms below if it helps. Lotsa thanks. MODEL: class Contact(models.Model): """ Contact details for the representatives of each business """ first_name = models.CharField(max_length=200) surname = models.CharField(max_length=200) business = models.ForeignKey('Business') slug = models.SlugField(max_length=150, unique=True, help_text=settings.SLUG_HELPER_TEXT) created = models.DateTimeField(auto_now_add=True) updated = models.DateTimeField(auto_now=True) phone = models.CharField(max_length=100, null=True, blank=True) mobile_phone = models.CharField(max_length=100, null=True, blank=True) email = models.EmailField(null=True) deleted = models.BooleanField(default=False) class Meta: db_table='business_contact' def __unicode__(self): return '%s %s' % (self.first_name, self.surname) @models.permalink def get_absolute_url(self): return('business_contact', (), {'contact_slug': self.slug }) class Business(models.Model): """ The business clients who you are selling products/services to """ business = models.CharField(max_length=255, unique=True) slug = models.SlugField(max_length=100, unique=True, help_text=settings.SLUG_HELPER_TEXT) description = models.TextField(null=True, blank=True) primary_contact = models.ForeignKey('Contact', null=True, blank=True, related_name='primary_contact') business_type = models.ForeignKey('BusinessType') deleted = models.BooleanField(default=False) created = models.DateTimeField(auto_now_add=True) updated = models.DateTimeField(auto_now=True) address_1 = models.CharField(max_length=255, null=True, blank=True) address_2 = models.CharField(max_length=255, null=True, blank=True) suburb = models.CharField(max_length=255, null=True, blank=True) city = models.CharField(max_length=255, null=True, blank=True) state = models.CharField(max_length=255, null=True, blank=True) country = models.CharField(max_length=255, null=True, blank=True) phone = models.CharField(max_length=40, null=True, blank=True) website = models.URLField(null=True, blank=True) class Meta: db_table = 'business' def __unicode__(self): return self.business def get_absolute_url(self): return '%s%s/' % (settings.BUSINESS_URL, self.slug) VIEWS: class Contact(models.Model): """ Contact details for the representatives of each business """ first_name = models.CharField(max_length=200) surname = models.CharField(max_length=200) business = models.ForeignKey('Business') slug = models.SlugField(max_length=150, unique=True, help_text=settings.SLUG_HELPER_TEXT) created = models.DateTimeField(auto_now_add=True) updated = models.DateTimeField(auto_now=True) phone = models.CharField(max_length=100, null=True, blank=True) mobile_phone = models.CharField(max_length=100, null=True, blank=True) email = models.EmailField(null=True) deleted = models.BooleanField(default=False) class Meta: db_table='business_contact' def __unicode__(self): return '%s %s' % (self.first_name, self.surname) @models.permalink def get_absolute_url(self): return('business_contact', (), {'contact_slug': self.slug }) class Business(models.Model): """ The business clients who you are selling products/services to """ business = models.CharField(max_length=255, unique=True) slug = models.SlugField(max_length=100, unique=True, help_text=settings.SLUG_HELPER_TEXT) description = models.TextField(null=True, blank=True) primary_contact = models.ForeignKey('Contact', null=True, blank=True, related_name='primary_contact') business_type = models.ForeignKey('BusinessType') deleted = models.BooleanField(default=False) created = models.DateTimeField(auto_now_add=True) updated = models.DateTimeField(auto_now=True) address_1 = models.CharField(max_length=255, null=True, blank=True) address_2 = models.CharField(max_length=255, null=True, blank=True) suburb = models.CharField(max_length=255, null=True, blank=True) city = models.CharField(max_length=255, null=True, blank=True) state = models.CharField(max_length=255, null=True, blank=True) country = models.CharField(max_length=255, null=True, blank=True) phone = models.CharField(max_length=40, null=True, blank=True) website = models.URLField(null=True, blank=True) class Meta: db_table = 'business' def __unicode__(self): return self.business def get_absolute_url(self): return '%s%s/' % (settings.BUSINESS_URL, self.slug) FORMS: class AddBusinessForm(ModelForm): class Meta: model = Business exclude = ['deleted','primary_contact',] class ContactForm(ModelForm): class Meta: model = Contact exclude = ['deleted',] AddBusinessFormSet = inlineformset_factory(Business, Contact, can_delete=False, extra=1, form=AddBusinessForm, )

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  • django models objects filter

    - by ha22109
    Hello All, I have a model 'Test' ,in which i have 2 foreignkey models.py class Test(models.Model): id =models.Autofield(primary_key=True) name=models.ForeignKey(model2) login=models.ForeignKey(model1) status=models.CharField(max_length=200) class model1(models.Model): id=models.CharField(primary_key=True) . . is_active=models.IntergerField() class model2(model.Model): id=models.ForeignKey(model1) . . status=model.CharField(max_length=200) When i add object in model 'Test' , if i select certain login then only the objects related to that objects(model2) should be shown in field 'name'.How can i achieve this.THis will be runtime as if i change the login field value the objects in name should also change.

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  • Customizing Django form widgets? - Django

    - by RadiantHex
    Hi folks, I'm having a little problem here! I have discovered the following as being the globally accepted method for customizing Django admin field. from django import forms from django.utils.safestring import mark_safe class AdminImageWidget(forms.FileInput): """ A ImageField Widget for admin that shows a thumbnail. """ def __init__(self, attrs={}): super(AdminImageWidget, self).__init__(attrs) def render(self, name, value, attrs=None): output = [] if value and hasattr(value, "url"): output.append(('<a target="_blank" href="%s">' '<img src="%s" style="height: 28px;" /></a> ' % (value.url, value.url))) output.append(super(AdminImageWidget, self).render(name, value, attrs)) return mark_safe(u''.join(output)) I need to have access to other field of the model in order to decide how to display the field! For example: If I am keeping track of a value, let us call it "sales". If I wish to customize how sales is displayed depending on another field, let us call it "conversion rate". I have no obvious way of accessing the conversion rate field when overriding the sales widget! Any ideas to work around this would be highly appreciated! Thanks :)

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  • Dajano admin site foreign key fields

    - by user292652
    hi i have the following models setup class Player(models.Model): #slug = models.slugField(max_length=200) Player_Name = models.CharField(max_length=100) Nick = models.CharField(max_length=100, blank=True) Jersy_Number = models.IntegerField() Team_id = models.ForeignKey('Team') Postion_Choices = ( ('M', 'Manager'), ('P', 'Player'), ) Poistion = models.CharField(max_length=1, blank=True, choices =Postion_Choices) Red_card = models.IntegerField( blank=True, null=True) Yellow_card = models.IntegerField(blank=True, null=True) Points = models.IntegerField(blank=True, null=True) #Pic = models.ImageField(upload_to=path/for/upload, height_field=height, width_field=width, max_length=100) class PlayerAdmin(admin.ModelAdmin): list_display = ('Player_Name',) search_fields = ['Player_Name',] admin.site.register(Player, PlayerAdmin) class Team(models.Model): """Model docstring""" #slug = models.slugField(max_length=200) Team_Name = models.CharField(max_length=100,) College = models.CharField(max_length=100,) Win = models.IntegerField(blank=True, null=True) Loss = models.IntegerField(blank=True, null=True) Draw = models.IntegerField(blank=True, null=True) #logo = models.ImageField(upload_to=path/for/upload, height_field=height, width_field=width, max_length=100) class Meta: pass #def __unicode__(self): # return Team_Name #def save(self, force_insert=False, force_update=False): # pass @models.permalink def get_absolute_url(self): return ('view_or_url_name') class TeamAdmin(admin.ModelAdmin): list_display = ('Team_Name',) search_fields = ['Team_Name',] admin.site.register(Team, TeamAdmin) my question is how do i get to the admin site to show Team_name in the add player form Team_ID field currently it is only showing up as Team object in the combo box

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  • Select a subset of foreign key elements in inlineformset_factory in Django

    - by Enis Afgan
    Hello, I have a model with two foreign keys: class Model1(models.Model): model_a = models.ForeignKey(ModelA) model_b = models.ForeignKey(ModelB) value = models.IntegerField() Then, I create an inline formset class, like so: an_inline_formset = inlineformset_factory(ModelA, Model1, fk_name="model_a") and then instantiate it, like so: a_formset = an_inline_formset(request.POST, instance=model_A_object) Once this formset gets rendered in a template/page, there is ChoiceField associated with the model_b field. The problem I'm having is that the elements in the resulting drop down menu include all of the elements found in ModelB table. I need to select a subset of those based on some criteria from ModelB. At the same time, I need to keep the reference to the instance of model_A_object when instantiating inlineformset_factory and, therefore, I can't just use this example. Any suggestions?

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  • Default value for hidden field in Django model

    - by Daniel Garcia
    I have this Model: class Occurrence(models.Model): id = models.AutoField(primary_key=True, null=True) reference = models.IntegerField(null=True, editable=False) def save(self): self.collection = self.id super(Occurrence, self).save() I want for the reference field to be hidden and at the same time have the same value as id. This code works if the editable=True but if i want to hide it it doesnt change the value of reference. how can i fix that?

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  • Limiting choices from an intermediary ManyToMany junction table in Django

    - by Matthew Rankin
    Background I've created three Django models—Inventory, SalesOrder, and Invoice—to model items in inventory, sales orders for those items, and invoices for a particular sales order. Each sales order can have multiple items, so I've used an intermediary junction table—SalesOrderItems—using the through argument for the ManyToManyField. Also, partial billing of a sales orders is allowed, so I've created a ForeignKey in the Invoice model related to the SalesOrder model, so that a particular sales order can have multiple invoices. Here's where I deviate from what I've normally seen. Instead of relating the Invoice model to the Item model via a ManyToManyField, I've related the Invoice model to the SalesOrderItem intermediary junction table through the intermediary junction table InvoiceItem. I've done this because it better models reality—our invoices are tied to sales orders and can only include items that are tied to that sales order as opposed to any item in inventory. I will admit that it does seem strange having the intermediary junction table of a ManyToManyField related to the intermediary junction table of another ManyToManyField. Question How can I limit the choices available for the invoice_items in the Invoice model to just the sales_order_items of the SalesOrder model for that particular Invoice? (I tried using limit_choices_to= {'sales_order': self.invoice.sales_order}) as part of the item = models.ForeignKey(SalesOrderItem) in the InvoiceItem model, but that didn't work. Am I correct in thinking that limiting the choices for the invoice_items should be handled in the model instead of in a form? Code class Item(models.Model): item_num = models.SlugField(unique=True) default_price = models.DecimalField(max_digits=10, decimal_places=2, blank=True, null=True) class SalesOrderItem(models.Model): item = models.ForeignKey(Item) sales_order = models.ForeignKey('SalesOrder') unit_price = models.DecimalField(max_digits=10, decimal_places=2) quantity = models.DecimalField(max_digits=10, decimal_places=4) class SalesOrder(models.Model): customer = models.ForeignKey(Party) so_num = models.SlugField(max_length=40, unique=True) sales_order_items = models.ManyToManyField(Item, through=SalesOrderItem) class InvoiceItem(models.Model): item = models.ForeignKey(SalesOrderItem) invoice = models.ForeignKey('Invoice') unit_price = models.DecimalField(max_digits=10, decimal_places=2) quantity = models.DecimalField(max_digits=10, decimal_places=4) class Invoice(models.Model): invoice_num = models.SlugField(max_length=25) sales_order = models.ForeignKey(SalesOrder) invoice_items = models.ManyToManyField(SalesOrderItem, through='InvoiceItem')

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  • django: error while migrating from 1.1 to 1.2

    - by gruszczy
    I am trying to migrate our django project from 1.1 to 1.2, but I get following error: Traceback (most recent call last): File "./manage.py", line 11, in <module> execute_manager(settings) File "/usr/local/lib/python2.6/dist-packages/django/core/management/__init__.py", line 438, in execute_manager utility.execute() File "/usr/local/lib/python2.6/dist-packages/django/core/management/__init__.py", line 379, in execute self.fetch_command(subcommand).run_from_argv(self.argv) File "/usr/local/lib/python2.6/dist-packages/django/core/management/base.py", line 191, in run_from_argv self.execute(*args, **options.__dict__) File "/usr/local/lib/python2.6/dist-packages/django/core/management/base.py", line 209, in execute translation.activate('en-us') File "/usr/local/lib/python2.6/dist-packages/django/utils/translation/__init__.py", line 66, in activate return real_activate(language) File "/usr/local/lib/python2.6/dist-packages/django/utils/functional.py", line 55, in _curried return _curried_func(*(args+moreargs), **dict(kwargs, **morekwargs)) File "/usr/local/lib/python2.6/dist-packages/django/utils/translation/__init__.py", line 36, in delayed_loader return getattr(trans, real_name)(*args, **kwargs) File "/usr/local/lib/python2.6/dist-packages/django/utils/translation/trans_real.py", line 193, in activate _active[currentThread()] = translation(language) File "/usr/local/lib/python2.6/dist-packages/django/utils/translation/trans_real.py", line 176, in translation default_translation = _fetch(settings.LANGUAGE_CODE) File "/usr/local/lib/python2.6/dist-packages/django/utils/translation/trans_real.py", line 159, in _fetch app = import_module(appname) File "/usr/local/lib/python2.6/dist-packages/django/utils/importlib.py", line 35, in import_module __import__(name) File "/home/gruszczy/Programy/bozorth/../bozorth/notifications/__init__.py", line 2, in <module> from django.db.models.signals import post_save File "/usr/local/lib/python2.6/dist-packages/django/db/__init__.py", line 75, in <module> connection = connections[DEFAULT_DB_ALIAS] File "/usr/local/lib/python2.6/dist-packages/django/db/utils.py", line 92, in __getitem__ conn = backend.DatabaseWrapper(db, alias) File "/usr/local/lib/python2.6/dist-packages/django/db/backends/sqlite3/base.py", line 154, in __init__ super(DatabaseWrapper, self).__init__(*args, **kwargs) TypeError: __init__() takes exactly 2 arguments (3 given) Anyone encountered this problem and know, how to solve?

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  • Django automatically compress Model Field on save() and decompress when field is accessed

    - by Brian M. Hunt
    Given a Django model likeso: from django.db import models class MyModel(models.Model): textfield = models.TextField() How can one automatically compress textfield (e.g. with zlib) on save() and decompress it when the property textfield is accessed (i.e. not on load), with a workflow like this: m = MyModel() textfield = "Hello, world, how are you?" m.save() # compress textfield on save m.textfield # no decompression id = m.id() m = MyModel.get(pk=id) # textfield still compressed m.textfield # textfield decompressed I'd be inclined to think that you would overload MyModel.save, but I don't know the pattern for in-place modification of the element when saving. I also don't know the best way in Django to decompress when the field when it's accessed (overload __getattr__?). Or would a better way to do this be to have a custom field type? I'm certain I've seen an example of almost exactly this, but alas I've not been able to find it recently. Thank you for reading – and for any input you may be able to provide.

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  • Django model manager didn't work with related object when I do aggregated query

    - by Satoru.Logic
    Hi, all. I'm having trouble doing an aggregation query on a many-to-many related field. Let's begin with my models: class SortedTagManager(models.Manager): use_for_related_fields = True def get_query_set(self): orig_query_set = super(SortedTagManager, self).get_query_set() # FIXME `used` is wrongly counted return orig_query_set.distinct().annotate( used=models.Count('users')).order_by('-used') class Tag(models.Model): content = models.CharField(max_length=32, unique=True) creator = models.ForeignKey(User, related_name='tags_i_created') users = models.ManyToManyField(User, through='TaggedNote', related_name='tags_i_used') objects_sorted_by_used = SortedTagManager() class TaggedNote(models.Model): """Association table of both (Tag , Note) and (Tag, User)""" note = models.ForeignKey(Note) # Note is what's tagged in my app tag = models.ForeignKey(Tag) tagged_by = models.ForeignKey(User) class Meta: unique_together = (('note', 'tag'),) However, the value of the aggregated field used is only correct when the model is queried directly: for t in Tag.objects.all(): print t.used # this works correctly for t in user.tags_i_used.all(): print t.used #prints n^2 when it should give n Would you please tell me what's wrong with it? Thanks in advance.

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  • Django Formset validation with an optional ForeignKey field

    - by Camilo Díaz
    Having a ModelFormSet built with modelformset_factory and using a model with an optional ForeignKey, how can I make empty (null) associations to validate on that form? Here is a sample code: ### model class Prueba(models.Model): cliente = models.ForeignKey(Cliente, null = True) valor = models.CharField(max_length = 20) ### view def test(request): PruebaFormSet = modelformset_factory(model = Prueba, extra = 1) if request.method == 'GET': formset = PruebaFormSet() return render_to_response('tpls/test.html', {'formset' : formset}, context_instance = RequestContext(request)) else: formset = PruebaFormSet(request.POST) # dumb tests, just to know if validating if formset.is_valid(): return HttpResponse('0') else: return HttpResponse('1') In my template, i'm just calling the {{ form.cliente }} method which renders the combo field, however, I want to be able to choose an empty (labeled "------") value, as the FK is optional... but when the form gets submitted it doesn't validate. Is this normal behaviour? How can i make this field to skip required validation?

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  • Django loading mysql data into template correctly

    - by user805981
    I'm new to django and I'm trying to get display a list of buildings and sort them alphabetically, then load it into an html document. Is there something that I am not doing correctly? below is models.py class Class(models.Model): building = models.CharField(max_length=20) class Meta: db_table = u'class' def __unicode__(self): return self.building below is views.py views.py def index(request): buildinglist = Class.objects.all().order_by('building') c = {'buildinglist': buildinglist} t = loader.get_template('index.html') return HttpResponse(t.render(c)) below is index.html index.html {% block content%} <h3>Buildings:</h3> <ul> {% for building in buildinglist %} <li> <a href='www.{% building %}.com'> # ex. www.searstower.com </li> {% endfor %} </ul> {% endblock %} Can you guys point me in the right direction? Thank you in advance guys! I appreciate your help very much.

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  • How do I upgrade django on ubuntu 9.04?

    - by Lorin Hochstein
    I've got Django 1.0.2 installed on Ubuntu 9.04. I'd like to upgrade Django, because I have an app that needs Django 1.1 or greater. I tried using pip to do the upgrade, but got the following: $ sudo pip install Django==1.1 Downloading/unpacking Django==1.1 Downloading Django-1.1.tar.gz (5.6Mb): 5.6Mb downloaded Running setup.py egg_info for package Django Installing collected packages: Django Found existing installation: Django 1.0.2-final Not uninstalling Django at /var/lib/python-support/python2.6, outside environment /usr Running setup.py install for Django changing mode of build/scripts-2.6/django-admin.py from 644 to 755 changing mode of /usr/local/bin/django-admin.py to 755 Successfully installed Django It seems like it worked, but it refuses to remove the original Django 1.02, and sure enough: $ pip freeze | grep -i django Django==1.0.2-final django-debug-toolbar==0.8.3 django-sphinx==2.2.3 $ /usr/local/bin/django-admin.py --version 1.0.2 final The problem, apparently, is that pip won't uninstall files outside of /usr. I'd like to remove the existing Django files manually, but I have no idea how to do that, because I'm unfamiliar with how Python packages are laid out in Ubuntu. It looks pretty complicated. The site-packages directory is: $ python -c "from distutils.sysconfig import get_python_lib; print get_python_lib()" /usr/lib/python2.6/dist-packages However, that's not where the django files live: $ ls -ld /usr/lib/python2.6/dist-packages/[Dd]jango* ls: cannot access /usr/lib/python2.6/dist-packages/[Dd]jango*: No such file or directory There's a /var/lib/python-support/python2.6/django directory, and the __init__.py file in that directory points to /usr/share/python-support/python-django/django/__init__.py. Clearly, pip is able to figure out where the files live. Is there any way to retrieve the list of files associated with the django package so I can just delete them manually?

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  • *UPDATED* help with django and accented characters?

    - by Asinox
    Hi guys, i have a problem with my accented characters, Django admin save my data without encoding to something like "&aacute;" Example: if im trying a word like " Canción ", i would like to save in this way: Canci&oacute;n, and not Canción. im usign Sociable app: {% load sociable_tags %} {% get_sociable Facebook TwitThis Google MySpace del.icio.us YahooBuzz Live as sociable_links with url=object.get_absolute_url title=object.titulo %} {% for link in sociable_links %} <a href="{{ link.link }}"><img alt="{{ link.site }}" title="{{ link.site }}" src="{{ link.image }}" /></a> {% endfor %} But im getting error if my object.titulo (title of the article) have a accented word. aught KeyError while rendering: u'\xfa' Any idea ? i had in my SETTING: DEFAULT_CHARSET = 'utf-8' i had in my mysql database: utf8_general_ci COMPLETED ERROR: Traceback: File "C:\wamp\bin\Python26\lib\site-packages\django\core\handlers\base.py" in get_response 100. response = callback(request, *callback_args, **callback_kwargs) File "C:\wamp\bin\Python26\lib\site-packages\django\views\generic\date_based.py" in object_detail 366. response = HttpResponse(t.render(c), mimetype=mimetype) File "C:\wamp\bin\Python26\lib\site-packages\django\template\__init__.py" in render 173. return self._render(context) File "C:\wamp\bin\Python26\lib\site-packages\django\template\__init__.py" in _render 167. return self.nodelist.render(context) File "C:\wamp\bin\Python26\lib\site-packages\django\template\__init__.py" in render 796. bits.append(self.render_node(node, context)) File "C:\wamp\bin\Python26\lib\site-packages\django\template\debug.py" in render_node 72. result = node.render(context) File "C:\wamp\bin\Python26\lib\site-packages\django\template\loader_tags.py" in render 125. return compiled_parent._render(context) File "C:\wamp\bin\Python26\lib\site-packages\django\template\__init__.py" in _render 167. return self.nodelist.render(context) File "C:\wamp\bin\Python26\lib\site-packages\django\template\__init__.py" in render 796. bits.append(self.render_node(node, context)) File "C:\wamp\bin\Python26\lib\site-packages\django\template\debug.py" in render_node 72. result = node.render(context) File "C:\wamp\bin\Python26\lib\site-packages\django\template\loader_tags.py" in render 62. result = block.nodelist.render(context) File "C:\wamp\bin\Python26\lib\site-packages\django\template\__init__.py" in render 796. bits.append(self.render_node(node, context)) File "C:\wamp\bin\Python26\lib\site-packages\django\template\debug.py" in render_node 72. result = node.render(context) File "C:\wamp\bin\Python26\lib\site-packages\sociable\templatetags\sociable_tags.py" in render 37. 'link': sociable.genlink(site, **self.values), File "C:\wamp\bin\Python26\lib\site-packages\sociable\sociable.py" in genlink 20. values['title'] = quote_plus(kwargs['title']) File "C:\wamp\bin\Python26\lib\urllib.py" in quote_plus 1228. s = quote(s, safe + ' ') File "C:\wamp\bin\Python26\lib\urllib.py" in quote 1222. res = map(safe_map.__getitem__, s) Exception Type: TemplateSyntaxError at /noticia/2010/jun/10/matan-domingo-paquete-en-la-avenida-san-vicente-de-paul/ Exception Value: Caught KeyError while rendering: u'\xfa' thanks, sorry with my English

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  • How to make custom join query with Django ?

    - by xRobot
    I have these 2 models: genre = ( ('D', 'Dramatic'), ('T', 'Thriller'), ('L', 'Love'), ) class Book(models.Model): title = models.CharField(max_length=100) genre = models.CharField(max_length=1, choices=genre) class Author(models.Model): user = models.ForeignKey(User, unique=True) born = models.DateTimeField('born') book = models.ForeignKey(Book) I need to retrieve first_name and last_name of all authors of dramatic's books. How can I do this in django ?

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  • Numerology with Python And Django

    - by Asinox
    Hi guys, i have a function that give me the result that im expecting in console mode, but if i try to use the function with Django, the page never load and just have a loop calculating and never end. Any idea ? *sorry with my english Console function (WORK GREAT): def sum_digitos(n): sum = 0; while n != 0: sum += n % 10 n /= 10 if sum > 9: x = str(sum) y =list(x) sum = int(y[0]) + int(y[1]) return sum print sum_digitos(2461978) Django views: def Calcular(request): if request.method == 'POST': form = NumerologiaForm(request.POST) if form.is_valid(): sum = 0; ano = str(request.POST['fecha_year']) mes = str(request.POST['fecha_month']) dia = str(request.POST['fecha_day']) data = dia + mes + ano fecha = int(data) while fecha != 0: f = fecha sum += f % 10 f /= 10 if sum > 9: x = str(sum) y =list(x) sum = int(y[0]) + int(y[1]) resultado = get_object_or_404(Numero,numero = sum) return HttpResponseRedirect(resultado.get_absolute_url()) else: form = NumerologiaForm() return render_to_response('numerologiaForm.html',{'form':form})

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  • ModelName(django.contrib.auth.models.User) vs ModelName(models.Model)

    - by amr.negm
    I am developing a django project. I created some apps, some of those are related to User model, for instance, I have a feeds app that handles user feeds, and another app that deals with extra user data like age, contacts, and friends. for each of these, I created a table that should be connected to the User model, which I using for storing and authenticating users. I found two ways to deal with this issue. One, is through extending User model to be like this: ModelName(User): friends = models.ManyToMany('self') ..... Two, is through adding a foreign key to the new table like this: ModelName(models.Model): user = models.ForeignKey(User, unique=True) friends = friends = models.ManyToMany('self') ...... I can't decide which to use in which case. in other words, what are the core differences between both?

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  • Django: What's an awesome plugin to maintain images in the admin?

    - by meder
    I have an articles entry model and I have an excerpt and description field. If a user wants to post an image then I have a separate ImageField which has the default standard file browser. I've tried using django-filebrowser but I don't like the fact that it requires django-grappelli nor do I necessarily want a flash upload utility - can anyone recommend a tool where I can manage image uploads, and basically replace the file browse provided by django with an imagepicking browser? In the future I'd probably want it to handle image resizing and specify default image sizes for certain article types. Edit: I'm trying out adminfiles now but I'm having issues installing it. I grabbed it and added it to my python path, added it to INSTALLED_APPS, created the databases for it, uploaded an image. I followed the instructions to modify my Model to specify adminfiles_fields and registered but it's not applying in my admin, here's my admin.py for articles: from django.contrib import admin from django import forms from articles.models import Category, Entry from tinymce.widgets import TinyMCE from adminfiles.admin import FilePickerAdmin class EntryForm( forms.ModelForm ): class Media: js = ['/media/tinymce/tiny_mce.js', '/media/tinymce/load.js']#, '/media/admin/filebrowser/js/TinyMCEAdmin.js'] class Meta: model = Entry class CategoryAdmin(admin.ModelAdmin): prepopulated_fields = { 'slug': ['title'] } class EntryAdmin( FilePickerAdmin ): adminfiles_fields = ('excerpt',) prepopulated_fields = { 'slug': ['title'] } form = EntryForm admin.site.register( Category, CategoryAdmin ) admin.site.register( Entry, EntryAdmin ) Here's my Entry model: class Entry( models.Model ): LIVE_STATUS = 1 DRAFT_STATUS = 2 HIDDEN_STATUS = 3 STATUS_CHOICES = ( ( LIVE_STATUS, 'Live' ), ( DRAFT_STATUS, 'Draft' ), ( HIDDEN_STATUS, 'Hidden' ), ) status = models.IntegerField( choices=STATUS_CHOICES, default=LIVE_STATUS ) tags = TagField() categories = models.ManyToManyField( Category ) title = models.CharField( max_length=250 ) excerpt = models.TextField( blank=True ) excerpt_html = models.TextField(editable=False, blank=True) body_html = models.TextField( editable=False, blank=True ) article_image = models.ImageField(blank=True, upload_to='upload') body = models.TextField() enable_comments = models.BooleanField(default=True) pub_date = models.DateTimeField(default=datetime.datetime.now) slug = models.SlugField(unique_for_date='pub_date') author = models.ForeignKey(User) featured = models.BooleanField(default=False) def save( self, force_insert=False, force_update= False): self.body_html = markdown(self.body) if self.excerpt: self.excerpt_html = markdown( self.excerpt ) super( Entry, self ).save( force_insert, force_update ) class Meta: ordering = ['-pub_date'] verbose_name_plural = "Entries" def __unicode__(self): return self.title Edit #2: To clarify I did move the media files to my media path and they are indeed rendering the image area, I can upload fine, the <<<image>>> tag is inserted into my editable MarkItUp w/ Markdown area but it isn't rendering in the MarkItUp preview - perhaps I just need to apply the |upload_tags into that preview. I'll try adding it to my template which posts the article as well.

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  • Django make model field name a link

    - by Daniel Garcia
    what Im looking to do is to have a link on the name of a field of a model. So when im filling the form using the admin interface i can access some information. I know this doesn't work but shows what i want to do class A(models.Model): item_type = models.CharField(max_length=100, choices=ITEMTYPE_CHOICES, verbose_name="<a href='http://www.quackit.com/html/codes'>Item Type</a>") Other option would be to put a description next to the field. Im not even sure where to start from.

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  • Delete manytomanyfield in Django

    - by Mike
    I have the following models class Database(models.Model): user = models.ForeignKey(User) name = models.CharField(max_length=100) created = models.DateTimeField(auto_now_add=True) updated = models.DateTimeField(auto_now=True) class DatabaseUser(models.Model): user = models.ForeignKey(User) name = models.CharField(max_length=100) password = models.CharField(max_length=100) database = models.ManyToManyField(Database) created = models.DateTimeField(auto_now_add=True) updated = models.DateTimeField(auto_now=True) One DatabaseUser can have many Databases under it's control. The issue I have if I go to delete a Database it wants to Delete the DatabaseUser also.. Is there a way to stop this from happening easily?

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  • Editing Django's admin index <div id='module'> tag

    - by zen
    I am new to the Django framework. On Django's admin index page I'd like to get rid of the "s" at the end of my model names. Example: <div class="module"> <table summary="Models available in the my application."> <caption><a href="" class="section">My application</a></caption> <tr> <th scope="row"><a href="model/">Model**s**</a></th> <td><a href="model/add/" class="addlink">Add</a></td> <td><a href="model/" class="changelink">Change</a></td> </tr> </table> </div> I know of a way to do this but I am really looking for the file I should edit. Where is it and what exactly should I do? I can't seem to pinpoint where it is coming from.

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