Search Results

Search found 6723 results on 269 pages for 'django models'.

Page 8/269 | < Previous Page | 4 5 6 7 8 9 10 11 12 13 14 15  | Next Page >

• How to display total record count against models in django admin

  - by Rog

  Is there a neat way to make the record/object count for a model appear on the main model list in the admin module? I have found techniques for showing counts of related objects within sets in the list_display page (and I can see the total in the pagination section at the bottom of the same), but haven't come across a neat way to show the record count at the model list level.

  Read the article

• Django syncdb not making tables for my app

  - by Rosarch

  It used to work, and now it doesn't. python manage.py syncdb no longer makes tables for my app. From settings.py: INSTALLED_APPS = ( 'django.contrib.auth', 'django.contrib.contenttypes', 'django.contrib.sessions', 'django.contrib.sites', 'mysite.myapp', 'django.contrib.admin', ) What could I be doing wrong? The break appeared to coincide with editing this model in models.py, but that could be total coincidence. I commented out the lines I changed, and it still doesn't work. class MyUser(models.Model): user = models.ForeignKey(User, unique=True) takingReqSets = models.ManyToManyField(RequirementSet, blank=True) takingTerms = models.ManyToManyField(Term, blank=True) takingCourses = models.ManyToManyField(Course, through=TakingCourse, blank=True) school = models.ForeignKey(School) # minCreditsPerTerm = models.IntegerField(blank=True) # maxCreditsPerTerm = models.IntegerField(blank=True) # optimalCreditsPerTerm = models.IntegerField(blank=True) UPDATE: When I run python manage.py loadddata initial_data, it gives an error: DeserializationError: Invalid model identifier: myapp.SomeModel Loading this data had worked fine before. This error is thrown on the very first data object in the data file.

  Read the article

• Value [...] not a valid choice, django-updown

  - by tamara

  I am trying to implemet django-updown https://github.com/weluse/django-updown. When I try to add vote trough the admin panel it says Value 1 not a valid choice. This is the models.py from the application: _SCORE_TYPE_CHOICES = ( ('-1', 'DISLIKE'), ('1', 'LIKE'), ) SCORE_TYPES = dict((value, key) for key, value in _SCORE_TYPE_CHOICES) class Vote(models.Model): content_type = models.ForeignKey(ContentType, related_name="updown_votes") object_id = models.PositiveIntegerField() key = models.CharField(max_length=32) score = models.SmallIntegerField(choices=_SCORE_TYPE_CHOICES) user = models.ForeignKey(User, blank=True, null=True, related_name="updown_votes") ip_address = models.IPAddressField() date_added = models.DateTimeField(default=datetime.datetime.now, editable=False) date_changed = models.DateTimeField(default=datetime.datetime.now, editable=False) Do you have an idea what could be wrong?

  Read the article

• Django form and User data

  - by Dean

  I have a model that looks like this: class Client(models.Model): name = models.CharField(max_length=100, primary_key=True) user = models.ForeignKey(User) class Contract(models.Model): title = models.CharField(max_length=100, primary_key=True) start_date = models.DateField() end_date = models.DateField() description = models.TextField() client = models.ForeignKey(Client) user = models.ForeignKey(User) How can i configure a django form so that only clients associated with that user show in the field in the form? My initial thought was this in my forms.py: client = forms.ModelChoiceField(queryset=Client.objects.filter(user__username = User.username)) But it didn't work. So how else would I go about it?

  Read the article

• Django - Can you use property as the field in an aggregation function?

  - by orokusaki

  I know the short answer because I tried it. Is there any way to accomplish this though (even if only on account of a hack)? class Ticket(models.Model): account = modelfields.AccountField() uuid = models.CharField(max_length=36, unique=True) created = models.DateTimeField(auto_now_add=True) class Meta: ordering = ['created'] @property def repair_cost(self): # cost is a @property of LineItem(models.Model) return self.lineitem_set.aggregate(models.Sum('cost'))

  Read the article

• Tricky model inheritance - Django

  - by RadiantHex

  Hi folks, I think this is a bit tricky, at least for me. :) So I have 4 models Person, Singer, Bassist and Ninja. Singer, Bassist and Ninja inherit from Person. The problem is that each Person can be any of its subclasses. e.g. A person can be a Singer and a Ninja. Another Person can be a Bassist and a Ninja. Another one can be all three. How should I organise my models? Help would be much appreciated!

  Read the article

• Modify on-the-fly verbose_name in a model field on django admin

  - by PerroVerd

  Hi I have this sample model working with the admin class Author(models.Model): name = models.CharField(_('Text in here'), max_length=100) with verbose_name set as ugettext_lazy 'Text in here', but sometimes, depending on the site_id i want to present a diferent verbose name, so I modified the init in this way def __init__(self, *args, **kwargs): super(Author, self).__init__(*args, **kwargs) #some logic in here self._meta.get_field('name').verbose_name = _('Other text') It works, displaying the 'Other text' instead the 'Text in here'... except for the very first time the author/add view is used. ¿Is it the right way to do it? ¿How can i fix the first time problem? Thanks in advance

  Read the article

• Invalidating Memcached Keys on save() in Django

  - by Zack

  I've got a view in Django that uses memcached to cache data for the more highly trafficked views that rely on a relatively static set of data. The key word is relatively: I need invalidate the memcached key for that particular URL's data when it's changed in the database. To be as clear as possible, here's the meat an' potatoes of the view (Person is a model, cache is django.core.cache.cache): def person_detail(request, slug): if request.is_ajax(): cache_key = "%s_ABOUT_%s" % settings.SITE_PREFIX, slug # Check the cache to see if we've already got this result made. json_dict = cache.get(cache_key) # Was it a cache hit? if json_dict is None: # That's a negative Ghost Rider person = get_object_or_404(Person, display = True, slug = slug) json_dict = { 'name' : person.name, 'bio' : person.bio_html, 'image' : person.image.extra_thumbnails['large'].absolute_url, } cache.set(cache_key) # json_dict will now exist, whether it's from the cache or not response = HttpResponse() response['Content-Type'] = 'text/javascript' response.write(simpljson.dumps(json_dict)) # Make sure it's all properly formatted for JS by using simplejson return response else: # This is where the fully templated response is generated What I want to do is get at that cache_key variable in it's "unformatted" form, but I'm not sure how to do this--if it can be done at all. Just in case there's already something to do this, here's what I want to do with it (this is from the Person model's hypothetical save method) def save(self): # If this is an update, the key will be cached, otherwise it won't, let's see if we can't find me try: old_self = Person.objects.get(pk=self.id) cache_key = # Voodoo magic to get that variable old_key = cache_key.format(settings.SITE_PREFIX, old_self.slug) # Generate the key currently cached cache.delete(old_key) # Hit it with both barrels of rock salt # Turns out this doesn't already exist, let's make that first request even faster by making this cache right now except DoesNotExist: # I haven't gotten to this yet. super(Person, self).save() I'm thinking about making a view class for this sorta stuff, and having functions in it like remove_cache or generate_cache since I do this sorta stuff a lot. Would that be a better idea? If so, how would I call the views in the URLconf if they're in a class?

  Read the article

• Django: Only one of two fields can be filled in

  - by Giovanni Di Milia

  I have this model: class Journals(models.Model): jid = models.AutoField(primary_key=True) code = models.CharField("Code", max_length=50) name = models.CharField("Name", max_length=2000) publisher = models.CharField("Publisher", max_length=2000) price_euro = models.CharField("Euro", max_length=2000) price_dollars = models.CharField("Dollars", max_length=2000) Is there a way to let people fill out either price_euro or price_dollars? I do know that the best way to solve the problem is to have only one field and another table that specify the currency, but I have constraints and I cannot modify the DB. Thanks!

  Read the article

• django sync db question

  - by Hulk

  In django models say this model exist in details/models.py class OccDetails(models.Model): title = models.CharField(max_length = 255) occ = models.ForeignKey(Occ) So when sync db is made the following fields get created and later to this of two more fields are added and sync db is made the new fields doesnt get created.How is this to be solved,Also what is auto_now=true in the below these are the new fields created_date = models.DateTimeField(auto_now_add=True) modified_date = models.DateTimeField(auto_now_add=True, auto_now=True)

  Read the article

• Django aggregation query on related one-to-many objects

  - by parxier

  Here is my simplified model: class Item(models.Model): pass class TrackingPoint(models.Model): item = models.ForeignKey(Item) created = models.DateField() data = models.IntegerField() In many parts of my application I need to retrieve a set of Item's and annotate each item with data field from latest TrackingPoint from each item ordered by created field. For example, instance i1 of class Item has 3 TrackingPoint's: tp1 = TrackingPoint(item=i1, created=date(2010,5,15), data=23) tp2 = TrackingPoint(item=i1, created=date(2010,5,14), data=21) tp3 = TrackingPoint(item=i1, created=date(2010,5,12), data=120) I need a query to retrieve i1 instance annotated with tp1.data field value as tp1 is the latest tracking point ordered by created field. That query should also return Item's that don't have any TrackingPoint's at all. If possible I prefer not to use QuerySet's extra method to do this. That's what I tried so far... and failed :( Item.objects.annotate(max_created=Max('trackingpoint__created'), data=Avg('trackingpoint__data')).filter(trackingpoint__created=F('max_created')) Any ideas?

  Read the article

• I want to select the distict value from models field and then update them (django)

  - by qulzam

  I have models... class Item(models.Model): name = models.CharField('Item Name', max_length = 30) item_code = models.CharField(max_length = 10) color = models.CharField(max_length = 150, null = True, blank = True) size = models.CharField(max_length = 30, null = True, blank = True) fabric_code = models.CharField(max_length = 30, null = True, blank = True) I have values in Item. in Item model name field has the similar values..(but the other values of record are change). I want to select the name field values distinctly(ie similar values select only ones). in one box(like combo box). What kind of form or views i use??

  Read the article

• Extended Django base-class with multiple instances

  - by Gijs

  I'm modeling a simple movie database using Django. models.py defines a base model Person. I extend Person into Actor and Director, which works as I imagined. Persons must be unique. When (in the Admin) I create an instance of Actor, and this person is also a Director, it won't save because of the unique = True. Any ideas how to solve this problem? (generic foreign keys?) Thx

  Read the article

• Django Admin validation

  - by etam

  Hi, I'd like to validate user input with regular expression in Django Admin CharField... How is it possible? Thanks in advance, Etam.

  Read the article

• How to store an integer leaded by zeros in django

  - by Oscar Carballal

  Hello, I'm trying to store a number in django that looks like this: 000001 My problem is that if I type this inside an IntegerField it gets converted to "1" without the leading zeros. I've tried also with a DecimalField with the same result. How can I store the leading zeros whithout using a CharField? (I need to manipulate that number in it's integer form)

  Read the article

• Django: name of many to many items in the admin interface

  - by Adam

  I have a many to many field, which I'm displaying in the django admin panel. When I add multiple items, they all come up as "ASGGroup object" in the display selector. Instead, I want them to come up as whatever the ASGGroup.name field is set to. How do I do this? My models looks like: class Thing(Model): read_groups = ManyToManyField('ASGGroup', related_name="thing_read", blank=True) class ASGGroup(Model): name = CharField(max_length=63, null=True) But what I'm seeing the m2m widget display is:

  Read the article

• Accessing updated M2M fields in overriden save() in django's admin

  - by Jonathan

  I'd like to use the user updated values of a ManyToManyField in a model's overriden save() method when I save an instance in admin. It turns out that by design, django does not update the M2M field before calling save(), but only after the save() is complete as part of the form save... How can I access the new values of this field in the override save() ?

  Read the article

• django auth : strange error with authenticate()

  - by Rohit

  I am using authenticate() to authenticating users manually. Using admin interface I can see that there is no 'last_login' attribute for Users Debug traceback is : Environment: Request Method: GET Request URL: https://localhost/login/ Django Version: 1.1.1 Python Version: 2.6.5 Installed Applications: ['django.contrib.auth', 'django.contrib.contenttypes', 'django.contrib.sessions', 'django.contrib.sites', 'django.contrib.admin', 'mobius.polls'] Installed Middleware: ('django.middleware.common.CommonMiddleware', 'django.contrib.sessions.middleware.SessionMiddleware', 'django.contrib.auth.middleware.AuthenticationMiddleware') Traceback: File "/usr/lib/pymodules/python2.6/django/core/handlers/base.py" in get_response 92. response = callback(request, *callback_args, **callback_kwargs) File "/usr/lib/pymodules/python2.6/django/contrib/auth/__init__.py" in login 55. user.last_login = datetime.datetime.now() Exception Type: AttributeError at /login/ Exception Value: 'unicode' object has no attribute 'last_login' I cant figure out, why is there this discrepancy. Any kind of help would be appreciated. Thanks in advance!

  Read the article

• Filtering manager for django model, customized by user

  - by valya

  Hi there! I have a model, smth like this: class Action(models.Model): def can_be_applied(self, user): #whatever return True and I want to override its default Manager. But I don't know how to pass the current user variable to the manager, so I have to do smth like this: [act for act in Action.objects.all() if act.can_be_applied(current_user)] How do I get rid of it by just overriding the manager? Thanks.

  Read the article

• Django data migration when changing a field to ManyToMany

  - by Ken H

  I have a Django application in which I want to change a field from a ForeignKey to a ManyToManyField. I want to preserve my old data. What is the simplest/best process to follow for this? If it matters, I use sqlite3 as my database back-end. If my summary of the problem isn't clear, here is an example. Say I have two models: class Author(models.Model): author = models.CharField(max_length=100) class Book(models.Model): author = models.ForeignKey(Author) title = models.CharField(max_length=100) Say I have a lot of data in my database. Now, I want to change the Book model as follows: class Book(models.Model): author = models.ManyToManyField(Author) title = models.CharField(max_length=100) I don't want to "lose" all my prior data. What is the best/simplest way to accomplish this? Ken

  Read the article

• Django ForeignKey _set on an inherited model

  - by neolaser

  I have two models Category and Entry. There is another model ExtEntry that inherits from Entry class Category(models.Model): title = models.CharField('title', max_length=255) description = models.TextField('description', blank=True) ... class Entry(models.Model): title = models.CharField('title', max_length=255) categories = models.ManyToManyField(Category) ... class ExtEntry(Entry): groups= models.CharField('title', max_length=255) value= models.CharField('title', max_length=255) ... I am able to use the Category.entry_set but I want to be able to do Category.blogentry_set but it is not available. If this is not available,then I need another method to get all ExtEntryrelated to one particular Category Thanks

  Read the article

• Installing Django on Shared Server: No module named MySQLdb?

  - by Mark

  I'm getting this error Traceback (most recent call last): File "/home/<username>/flup/server/fcgi_base.py", line 558, in run File "/home/<username>/flup/server/fcgi_base.py", line 1116, in handler File "/home/<username>/python/django/django/core/handlers/wsgi.py", line 241, in __call__ response = self.get_response(request) File "/home/<username>/python/django/django/core/handlers/base.py", line 73, in get_response response = middleware_method(request) File "/home/<username>/python/django/django/contrib/sessions/middleware.py", line 10, in process_request engine = import_module(settings.SESSION_ENGINE) File "/home/<username>/python/django/django/utils/importlib.py", line 35, in import_module __import__(name) File "/home/<username>/python/django/django/contrib/sessions/backends/db.py", line 2, in ? from django.contrib.sessions.models import Session File "/home/<username>/python/django/django/contrib/sessions/models.py", line 4, in ? from django.db import models File "/home/<username>/python/django/django/db/__init__.py", line 41, in ? backend = load_backend(settings.DATABASE_ENGINE) File "/home/<username>/python/django/django/db/__init__.py", line 17, in load_backend return import_module('.base', 'django.db.backends.%s' % backend_name) File "/home/<username>/python/django/django/utils/importlib.py", line 35, in import_module __import__(name) File "/home/<username>/python/django/django/db/backends/mysql/base.py", line 13, in ? raise ImproperlyConfigured("Error loading MySQLdb module: %s" % e) ImproperlyConfigured: Error loading MySQLdb module: No module named MySQLdb when I try to run this script on my shared server #!/usr/bin/python import sys, os sys.path.insert(0, "/home/<username>/python/django") sys.path.insert(0, "/home/<username>/python/django/www") # projects directory os.chdir("/home/<username>/python/django/www/<project>") os.environ['DJANGO_SETTINGS_MODULE'] = "<project>.settings" from django.core.servers.fastcgi import runfastcgi runfastcgi(method="threaded", daemonize="false") But, my web host just installed MySQLdb for me a few hours ago. When I run python from the shell I can import MySQLdb just fine. Why would this script report that it can't find it?

  Read the article

• Django deployment - can't import app.urls

  - by hora

  I just moved a django project to a deployment server from my dev server, and I'm having some issues deploying it. My apache config is as follows: <Location "/"> Order allow,deny Allow from all SetHandler python-program PythonHandler django.core.handlers.modpython SetEnv DJANGO_SETTINGS_MODULE project.settings PythonDebug On PythonPath "['/home/django/'] + sys.path" </Location> Django does work, since it renders the Django debug views, but I get the following error: ImportError at / No module named app.urls And here is all the information Django gives me: Request Method: GET Request URL: http://myserver.com/ Django Version: 1.1.1 Python Version: 2.6.5 Installed Applications: ['django.contrib.auth', 'django.contrib.contenttypes', 'django.contrib.sessions', 'django.contrib.sites', 'django.contrib.admin', 'django.contrib.admindocs', 'project.app'] Installed Middleware: ('django.middleware.common.CommonMiddleware', 'django.contrib.sessions.middleware.SessionMiddleware', 'django.contrib.auth.middleware.AuthenticationMiddleware') Traceback: File "/usr/lib64/python2.6/site-packages/django/core/handlers/base.py" in get_response 83. request.path_info) File "/usr/lib64/python2.6/site-packages/django/core/urlresolvers.py" in resolve 218. sub_match = pattern.resolve(new_path) File "/usr/lib64/python2.6/site-packages/django/core/urlresolvers.py" in resolve 216. for pattern in self.url_patterns: File "/usr/lib64/python2.6/site-packages/django/core/urlresolvers.py" in _get_url_patterns 245. patterns = getattr(self.urlconf_module, "urlpatterns", self.urlconf_module) File "/usr/lib64/python2.6/site-packages/django/core/urlresolvers.py" in _get_urlconf_module 240. self._urlconf_module = import_module(self.urlconf_name) File "/usr/lib64/python2.6/site-packages/django/utils/importlib.py" in import_module 35. __import__(name) Exception Type: ImportError at / Exception Value: No module named app.urls Any ideas as to why I get an import error?

  Read the article

• extending satchmo user profile

  - by z3a

  I'm trying to extend the basic user registration form and profile included in satchmo store, but I'm in problems with that. This what I've done: Create a new app "extendedprofile" Wrote a models.py that extends the satchmo_store.contact.models class and add the custom name fields. wrote an admin.py that unregister the Contact class and register my newapp but this still showing me the default user profile form. Maybe some one can show me the correct way to do this?

  Read the article

• Django authentication in django nonrel on GAE

  - by tooba

  I'm using the Django nonrel project on a google app engine project running locally in development. I've created my own models and these are fine when they are saved and retrieved in the datastore. I'm hoping to use django.contrib.auth to provide the user functionality. I can use the shell to create users and these get assigned an ID. When I create one of my own models which references User I have to pass in a user ID as it quite rightly fails otherwise. However, checking via the gae admin interface I can't see the User model in the datastore for the users I've created via the shell. Nor can I retreive the user details from one of my models which references them. Calls to mymodel.user.username return nothing. Nor can I log into admin using the username and password I've set up. I can see saved versions of the models I've made in the gae admin app. I get the impression that users are being created somewhere other than the datastore. Is there something else I need to do to use the standard contrib.auth users with django-nonrel and gae?

  Read the article

< Previous Page | 4 5 6 7 8 9 10 11 12 13 14 15  | Next Page >