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  • Windows 7 Folder Redirection (GPO)

    - by Kev
    I have been fighting this issue for a day or two now, so I am looking for some insight. I am taking over admin duties in a domain of 800 users, and the previous admins really did not employ much of any GPO settings for the clients of the Domain. In each site, there is a location on the file server where "Home" folders were manually created. EX: \server\home\enduser Whenever a user got a machine, the admin would manually right-click on the "My Documents" folder and manually enter the path to the home folder. We are planning to start putting Windows 7 machines on the Network, and I am wanting to automate as much as I can, everything that was not done in the past. Since everyone has exising "Home" folders I have been fighting and trying to get Folder Redirection to work with a new Windows 7 machine (In a Test OU). I am getting all kinds of errors and I can't get the Windows 7 "Documents" folder to redirect to the users EXISTING home folders. As I stated earlier, all of the Home folders were (and still are) manually created on the File Server and are set with the following Security permissions - Domain Admins - Full Control euser (end user) - Modify (Everything but Full) Can someone point me in the right direction on the proper setting to put in the Folder Redirection GPO to get this to work with the Existing Home folders.

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  • win 7: copy all files from a complex folder structure to one folder

    - by Jason
    I'd have a complex folder structure like: h:\folder1\folder2\folder3 h:\folder1\folder2\a h:\folder1\b h:\folder1\folder3 h:\folder1\folder4\d Only with probably 100's of folders and a depth of around 4 (I'm guessing) Anyway I want to run a command that will move all the files from every sub folder into the top level folder. so something like h:\folder1\*\*.* to h:\folder1 Is there a tool I can use to do this? does win 7 have a command that will do this? Thanks Jason

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  • Event Driven Behavior Tree: deterministic traversal order with parallel

    - by Heisenbug
    I've studied several articles and listen some talks about behavior trees (mostly the resources available on AIGameDev by Alex J. Champandard). I'm particularly interested on event driven behavior trees, but I have still some doubts on how to implement them correctly using a scheduler. Just a quick recap: Standard Behavior Tree Each execution tick the tree is traversed from the root in depth-first order The execution order is implicitly expressed by the tree structure. So in the case of behaviors parented to a parallel node, even if both children are executed during the same traversing, the first leaf is always evaluated first. Event Driven BT During the first traversal the nodes (tasks) are enqueued using a scheduler which is responsible for updating only running ones every update The first traversal implicitly produce a depth-first ordered queue in the scheduler Non leaf nodes stays suspended mostly of the time. When a leaf node terminate(either with success or fail status) the parent (observer) is waked up allowing the tree traversing to continue and new tasks will be enqueued in the scheduler Without parallel nodes in the tree there will be up to 1 task running in the scheduler Without parallel nodes, the tasks in the queue(excluding dynamic priority implementation) will be always ordered in a depth-first order (is this right?) Now, from what is my understanding of a possible implementation, there are 2 requirements I think must be respected(I'm not sure though): Now, some requirements I think needs to be guaranteed by a correct implementation are: The result of the traversing should be independent from which implementation strategy is used. The traversing result must be deterministic. I'm struggling trying to guarantee both in the case of parallel nodes. Here's an example: Parallel_1 -->Sequence_1 ---->leaf_A ---->leaf_B -->leaf_C Considering a FIFO policy of the scheduler, before leaf_A node terminates the tasks in the scheduler are: P1(suspended),S1(suspended),leaf_A(running),leaf_C(running) When leaf_A terminate leaf_B will be scheduled (at the end of the queue), so the queue will become: P1(suspended),S1(suspended),leaf_C(running),leaf_B(running) In this case leaf_B will be executed after leaf_C at every update, meanwhile with a non event-driven traversing from the root node, the leaf_B will always be evaluated before leaf_A. So I have a couple of question: do I have understand correctly how event driven BT work? How can I guarantee the depth first order is respected with such an implementation? is this a common issue or am I missing something?

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  • What is the kd tree intersection logic?

    - by bobobobo
    I'm trying to figure out how to implement a KD tree. On page 322 of "Real time collision detection" by Ericson The text section is included below in case Google book preview doesn't let you see it the time you click the link text section Relevant section: The basic idea behind intersecting a ray or directed line segment with a k-d tree is straightforward. The line is intersected against the node's splitting plane, and the t value of intersection is computed. If t is within the interval of the line, 0 <= t <= tmax, the line straddles the plane and both children of the tree are recursively descended. If not, only the side containing the segment origin is recursively visited. So here's what I have: (open image in new tab if you can't see the lettering) The logical tree Here the orange ray is going thru the 3d scene. The x's represent intersection with a plane. From the LEFT, the ray hits: The front face of the scene's enclosing cube, The (1) splitting plane The (2.2) splitting plane The right side of the scene's enclosing cube But here's what would happen, naively following Ericson's basic description above: Test against splitting plane (1). Ray hits splitting plane (1), so left and right children of splitting plane (1) are included in next test. Test against splitting plane (2.1). Ray actually hits that plane, (way off to the right) so both children are included in next level of tests. (This is counter-intuitive - shouldn't only the bottom node be included in subsequent tests) Can some one describe what happens when the orange ray goes through the scene correctly?

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  • Create new folder for new sender name and move message into new folder

    - by Dave Jarvis
    Background I'd like to have Outlook 2010 automatically move e-mails into folders designated by the person's name. For example: Click Rules Click Manage Rules & Alerts Click New Rule Select "Move messages from someone to a folder" Click Next The following dialog is shown: Problem The next part usually looks as follows: Click people or public group Select the desired person Click specified Select the desired folder Question How would you automate those problematic manual tasks? Here's the logic for the new rule I'd like to create: Receive a new message. Extract the name of the sender. If it does not exist, create a new folder under Inbox Move the new message into the folder assigned to that person's name I think this will require a VBA macro. Related Links http://www.experts-exchange.com/Software/Office_Productivity/Groupware/Outlook/A_420-Extending-Outlook-Rules-via-Scripting.html http://msdn.microsoft.com/en-us/library/office/ee814735.aspx http://msdn.microsoft.com/en-us/library/office/ee814736.aspx http://stackoverflow.com/questions/11263483/how-do-i-trigger-a-macro-to-run-after-a-new-mail-is-received-in-outlook http://en.kioskea.net/faq/6174-outlook-a-macro-to-create-folders http://blogs.iis.net/robert_mcmurray/archive/2010/02/25/outlook-macros-part-1-moving-emails-into-personal-folders.aspx Update #1 The code might resemble something like: Public WithEvents myOlApp As Outlook.Application Sub Initialize_handler() Set myOlApp = CreateObject("Outlook.Application") End Sub Private Sub myOlApp_NewMail() Dim myInbox As Outlook.MAPIFolder Dim myItem As Outlook.MailItem Set myInbox = myOlApp.GetNamespace("MAPI").GetDefaultFolder(olFolderInbox) Set mySenderName = myItem.SenderName On Error GoTo ErrorHandler Set myDestinationFolder = myInbox.Folders.Add(mySenderName, olFolderInbox) Set myItems = myInbox.Items Set myItem = myItems.Find("[SenderName] = " & mySenderName) myItem.Move myDestinationFolder ErrorHandler: Resume Next End Sub Update #2 Split the code as follows: Sent a test message and nothing happened. The instructions for actually triggering a message when a new message arrives are a little light on details (for example, no mention is made regarding ThisOutlookSession and how to use it). Thank you.

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  • Algorithm for parsing a flat tree into a non-flat tree

    - by Chad Johnson
    I have the following flat tree: id name parent_id is_directory =========================================================== 50 app 0 1 31 controllers 50 1 11 application_controller.rb 31 0 46 models 50 1 12 test_controller.rb 31 0 31 test.rb 46 0 and I am trying to figure out an algorithm for getting this into the following tree structuree: [{ id: 50, name: app, is_directory: true children: [{ id: 31, name: controllers, is_directory: true, children: [{ id: 11, name: application_controller.rb is_directory: false },{ id: 12, name: test_controller.rb, is_directory: false }], },{ id: 46, name: models, is_directory: true, children: [{ id: 31, name: test.rb, is_directory: false }] }] }] Can someone point me in the right direction? I'm looking for steps (eg. build an associative array; loop through the array looking for x; etc.).

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  • Create Templates folder in Windows 7 profile

    - by Michael Itzoe
    I'd like to create a Templates folder in my profile on Windows 7, but there's already a junction to AppData\Roaming\Microsoft\Windows\Templates. I assume this is a system configuration so I don't want to delete it. I'm currently calling my folder File Templates, but that seems to verbose to me. Is there anything I can do?

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  • How to rename folder? Folder in use [closed]

    - by Colonel Panic
    Possible Duplicate: Deleting folders give access denied error message on Windows 7, although I am administrator I am trying to rename a folder, but apparently it is in use. I don't think it is. I'd like to rename my folder. How can I do that? This happens regularly, and at random, particularly in my music folder. I'd like to know the cause and fix that. Rather than workaround with some special tool whenever I want to rename a file.

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  • Implementation of Race Game Tree

    - by Mert Toka
    I build a racing game right in OpenGL using Glut, and I'm a bit lost in all the details. First of all, any suggestions as a road map would be more than great. So far what I thought is this: Tree implementation for transformations. Simulated dynamics.(*) Octree implementation for collusion detection. Actual collusion detection.(*) Modelling in Maya and export them as .OBJs. Polishing the game with GLSL or something like that for graphics quality. (*): I am not sure the order of these two. So I started with the simulated dynamics without tree, and it turned out to be a huge chaos for me. Is there any way you can think of such that could help me to build such tree to use in racing game? I thought something like this but I have no idea how to implement it. Reds are static, yellows are dynamic nodes

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  • Writing files in a sub folder of the web folder (apache security)

    - by Homunculus Reticulli
    I need to save session data for a dynamic web page script by writing to file. I have two questions: Are there any security preferences as to whether to save the data UNDER the web folder, or OUTSIDE the web folder? I attempted to write to the folder an (unsuprisingly), I had a 'file permission refused' type error. Should I set the folder ownership to the apache user (600, 640 or 644?) [[Edit]] core <- 'OUTSIDE' web folder (php script live here) data <- 'OUTSIDE' web folder (session data and other misc data resides here) web <- web root folder js <- any folder below is 'INSIDE' the web folder css html For example, in a php script (i.e. a dynamic PHP page), I can attempt to write to a file using something like fput('../data',data) yet (as I understand it) ../data should not be accessible - for security reasons. Could someone please provide a simple example that shows how to provide access to ../data/ in the example given above?. What are the actual SPECIFIC steps required? BTW, I am running on a LAMP stack.

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  • How to create a folder in SharePoint2010 root folder and set permission to it

    - by ybbest
    If you need to create a folder in SharePoint2010 root folder and set permission to it, here is piece of code that does it. In the script, I have created a folder called Temp in Logs folder under SharePoint2010 root and then I grant read/write access to the Windows group WSS_WPG and full access to the group WSS_ADMIN_WPG for that folder. $Folder=New-Item "C:\Program Files\Common Files\Microsoft Shared\Web Server Extensions\14\LOGS\temp" -Type Directory -force $acl = Get-Acl $Folder ##The following line has been commented out , if you like to break the permission inheritance from the parent floder , uncommented the code. #$acl.SetAccessRuleProtection($True, $False) $rule = New-Object System.Security.AccessControl.FileSystemAccessRule("WSS_ADMIN_WPG","FullControl", "ContainerInherit, ObjectInherit", "None", "Allow") $acl.AddAccessRule($rule) $rule = New-Object System.Security.AccessControl.FileSystemAccessRule("WSS_WPG","Modify", "ContainerInherit, ObjectInherit", "None", "Allow") $acl.AddAccessRule($rule) Set-Acl $Folder $acl References: http://technet.microsoft.com/en-us/library/ff730951.aspx http://msdn.microsoft.com/en-us/library/tbsb79h3.aspx http://blogs.technet.com/b/josebda/archive/2010/11/12/how-to-handle-ntfs-folder-permissions-security-descriptors-and-acls-in-powershell.aspx http://chrisfederico.wordpress.com/2008/02/01/setting-acl-on-a-file-or-directory-in-powershell/

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  • Programmatically disclosing a node in af:tree and af:treeTable

    - by Frank Nimphius
    A common developer requirement when working with af:tree or af:treeTable components is to programmatically disclose (expand) a specific node in the tree. If the node to disclose is not a top level node, like a location in a LocationsView -> DepartmentsView -> EmployeesView hierarchy, you need to also disclose the node's parent node hierarchy for application users to see the fully expanded tree node structure. Working on ADF Code Corner sample #101, I wrote the following code lines that show a generic option for disclosing a tree node starting from a handle to the node to disclose. The use case in ADF Coder Corner sample #101 is a drag and drop operation from a table component to a tree to relocate employees to a new department. The tree node that receives the drop is a department node contained in a location. In theory the location could be part of a country and so on to indicate the depth the tree may have. Based on this structure, the code below provides a generic solution to parse the current node parent nodes and its child nodes. The drop event provided a rowKey for the tree node that received the drop. Like in af:table, the tree row key is not of type oracle.jbo.domain.Key but an implementation of java.util.List that contains the row keys. The JUCtrlHierBinding class in the ADF Binding layer that represents the ADF tree binding at runtime provides a method named findNodeByKeyPath that allows you to get a handle to the JUCtrlHierNodeBinding instance that represents a tree node in the binding layer. CollectionModel model = (CollectionModel) your_af_tree_reference.getValue(); JUCtrlHierBinding treeBinding = (JUCtrlHierBinding ) model.getWrappedData(); JUCtrlHierNodeBinding treeDropNode = treeBinding.findNodeByKeyPath(dropRowKey); To disclose the tree node, you need to create a RowKeySet, which you do using the RowKeySetImpl class. Because the RowKeySet replaces any existing row key set in the tree, all other nodes are automatically closed. RowKeySetImpl rksImpl = new RowKeySetImpl(); //the first key to add is the node that received the drop //operation (departments).            rksImpl.add(dropRowKey);    Similar, from the tree binding, the root node can be obtained. The root node is the end of all parent node iteration and therefore important. JUCtrlHierNodeBinding rootNode = treeBinding.getRootNodeBinding(); The following code obtains a reference to the hierarchy of parent nodes until the root node is found. JUCtrlHierNodeBinding dropNodeParent = treeDropNode.getParent(); //walk up the tree to expand all parent nodes while(dropNodeParent != null && dropNodeParent != rootNode){    //add the node's keyPath (remember its a List) to the row key set    rksImpl.add(dropNodeParent.getKeyPath());      dropNodeParent = dropNodeParent.getParent(); } Next, you disclose the drop node immediate child nodes as otherwise all you see is the department node. Its not quite exactly "dinner for one", but the procedure is very similar to the one handling the parent node keys ArrayList<JUCtrlHierNodeBinding> childList = (ArrayList<JUCtrlHierNodeBinding>) treeDropNode.getChildren();                     for(JUCtrlHierNodeBinding nb : childList){   rksImpl.add(nb.getKeyPath()); } Next, the row key set is defined as the disclosed row keys on the tree so when you refresh (PPR) the tree, the new disclosed state shows tree.setDisclosedRowKeys(rksImpl); AdfFacesContext.getCurrentInstance().addPartialTarget(tree.getParent()); The refresh in my use case is on the tree parent component (a layout container), which usually shows the best effect for refreshing the tree component. 

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  • WS2008R2 / W7PRO: Cannot rename folder - folder redirection

    - by castor
    After few months from migrating one of my networks on Active Directory this issue started. A few users are encountering an issue from time to time - they cannot rename folders and files on desktop. The system throws an error saying the folder or file is already in use. Folder redirection takes place in this scenario (Desktop and My Documents) Subnet with user PCs is different from subnet with servers (Cisco ASA5505 Security Plus between - all inspection policies disabled on these interfaces) Users are running Windows 7 Professional x86 Server is running Windows Server 2008 R2 Standard Any ideas?

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  • Find the minimum gap between two numbers in an AVL tree

    - by user1656647
    I have a data structures homework, that in addition to the regular AVL tree functions, I have to add a function that returns the minimum gap between any two numbers in the AVL tree (the nodes in the AVL actually represent numbers.) Lets say we have the numbers (as nodes) 1 5 12 20 23 21 in the AVL tree, the function should return the minimum gap between any two numbers. In this situation it should return "1" which is |20-21| or |21-20|. It should be done in O(1). Tried to think alot about it, and I know there is a trick but just couldn't find it, I have spent hours on this. There was another task which is to find the maximum gap, which is easy, it is the difference between the minimal and maximal number.

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  • Can a binary tree or tree be always represented in a Database as 1 table and self-referencing?

    - by Jian Lin
    I didn't feel this rule before, but it seems that a binary tree or any tree (each node can have many children but children cannot point back to any parent), then this data structure can be represented as 1 table in a database, with each row having an ID for itself and a parentID that points back to the parent node. That is in fact the classical Employee - Manager diagram: one boss can have many people under him... and each person can have n people under him, etc. This is a tree structure and is represented in database books as a common example as a single table Employee.

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  • Can a binary tree or tree be always represented in a Database table as 1 table and self-referencing?

    - by Jian Lin
    I didn't feel this rule before, but it seems that a binary tree or any tree (each node can have many children but children cannot point back to any parent), then this data structure can be represented as 1 table in a database, with each row having an ID for itself and a parentID that points back to the parent node. That is in fact the classical Employee - Manager diagram: one boss can have many people under him... and each person under him can have n people under him, etc. This is a tree structure and is represented in database books as a common example as a single table Employee.

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  • Inorder tree traversal in binary tree in C

    - by srk
    In the below code, I'am creating a binary tree using insert function and trying to display the inserted elements using inorder function which follows the logic of In-order traversal.When I run it, numbers are getting inserted but when I try the inorder function( input 3), the program continues for next input without displaying anything. I guess there might be a logical error.Please help me clear it. Thanks in advance... #include<stdio.h> #include<stdlib.h> int i; typedef struct ll { int data; struct ll *left; struct ll *right; } node; node *root1=NULL; // the root node void insert(node *root,int n) { if(root==NULL) //for the first(root) node { root=(node *)malloc(sizeof(node)); root->data=n; root->right=NULL; root->left=NULL; } else { if(n<(root->data)) { root->left=(node *)malloc(sizeof(node)); insert(root->left,n); } else if(n>(root->data)) { root->right=(node *)malloc(sizeof(node)); insert(root->right,n); } else { root->data=n; } } } void inorder(node *root) { if(root!=NULL) { inorder(root->left); printf("%d ",root->data); inorder(root->right); } } main() { int n,choice=1; while(choice!=0) { printf("Enter choice--- 1 for insert, 3 for inorder and 0 for exit\n"); scanf("%d",&choice); switch(choice) { case 1: printf("Enter number to be inserted\n"); scanf("%d",&n); insert(root1,n); break; case 3: inorder(root1); break; default: break; } } }

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  • Can't create new folder from anywhere in Windows 7

    - by ymasood
    I have this problem on two of my new laptops and can't seem to find a decent workable solution elsewhere in forum land. The problem is that on my Windows 7 Professional machines the right mouse button doesn't show the New Folder option and elsewhere as well (via Explorer) I'm unable to create new folders. I'll be happy to get this tiny problem resolved and declare that Windows 7 is almost perfect! Thanks to all of you in advance for your contribution! PS: None of the Vista solutions seem to work here!

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  • AVL tree in C language

    - by I_S_W
    Hey all; i am currently doing a project that requires the use of AVL trees , the insert function i wrote for the avl does not seem to be working , it works for 3 or 4 nodes at maximum ; i would really appreciate your help The attempt is below enter code here Tree insert(Tree t,char name[80],int num) { if(t==NULL) { t=(Tree)malloc(sizeof(struct node)); if(t!=NULL) { strcpy(t->name,name); t->num=num; t->left=NULL; t->right=NULL; t->height=0; } } else if(strcmp(name,t->name)<0) { t->left=insert(t->left,name,num); if((height(t->left)-height(t->right))==2) if(strcmp(name,t->left->name)<0) { t=s_rotate_left(t);} else{ t=d_rotate_left(t);} } else if(strcmp(name,t-name)0) { t-right=insert(t-right,name,num); if((height(t-right)-height(t-left))==2) if(strcmp(name,t-right-name)0){ t=s_rotate_right(t); } else{ t=d_rotate_right(t);} } t-height=max(height(t-left),height(t-right))+1; return t; }

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  • New to AVL tree implementation.

    - by nn
    I am writing a sliding window compression algorithm (LZ77) that searches for phrases in a "moving" dictionary. So far I have written a BST where each node is stored in an array and it's index in the array is also the value of the starting position in the window itself. I am now looking at transforming the BST to an AVL tree. I am a little confused at the sample implementations I have seen. Some only appear to store the balance factors whereas others store the height of each tree. Are there any performance advantage/disadvantages of storing the height and/or balance factor for each node? Apologies if this is a very simple question, but I'm still not visualizing how I want to restructure my BST to implement height balancing. Thanks.

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  • Convert a binary tree to linked list, breadth first, constant storage/destructive

    - by Merlyn Morgan-Graham
    This is not homework, and I don't need to answer it, but now I have become obsessed :) The problem is: Design an algorithm to destructively flatten a binary tree to a linked list, breadth-first. Okay, easy enough. Just build a queue, and do what you have to. That was the warm-up. Now, implement it with constant storage (recursion, if you can figure out an answer using it, is logarithmic storage, not constant). I found a solution to this problem on the Internet about a year back, but now I've forgotten it, and I want to know :) The trick, as far as I remember, involved using the tree to implement the queue, taking advantage of the destructive nature of the algorithm. When you are linking the list, you are also pushing an item into the queue. Each time I try to solve this, I lose nodes (such as each time I link the next node/add to the queue), I require extra storage, or I can't figure out the convoluted method I need to get back to a node that has the pointer I need. Even the link to that original article/post would be useful to me :) Google is giving me no joy. Edit: Jérémie pointed out that there is a fairly simple (and well known answer) if you have a parent pointer. While I now think he is correct about the original solution containing a parent pointer, I really wanted to solve the problem without it :) The refined requirements use this definition for the node: struct tree_node { int value; tree_node* left; tree_node* right; };

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  • How to functionally generate a tree breadth-first. (With Haskell)

    - by Dennetik
    Say I have the following Haskell tree type, where "State" is a simple wrapper: data Tree a = Branch (State a) [Tree a] | Leaf (State a) deriving (Eq, Show) I also have a function "expand :: Tree a - Tree a" which takes a leaf node, and expands it into a branch, or takes a branch and returns it unaltered. This tree type represents an N-ary search-tree. Searching depth-first is a waste, as the search-space is obviously infinite, as I can easily keep on expanding the search-space with the use of expand on all the tree's leaf nodes, and the chances of accidentally missing the goal-state is huge... thus the only solution is a breadth-first search, implemented pretty decent over here, which will find the solution if it's there. What I want to generate, though, is the tree traversed up to finding the solution. This is a problem because I only know how to do this depth-first, which could be done by simply called the "expand" function again and again upon the first child node... until a goal-state is found. (This would really not generate anything other then a really uncomfortable list.) Could anyone give me any hints on how to do this (or an entire algorithm), or a verdict on whether or not it's possible with a decent complexity? (Or any sources on this, because I found rather few.)

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  • Phone pictures not showing in UbuntuOne folder on computer

    - by user34924
    I downloaded the Android app for my phone and set it up to move my pictures from the phone into UbuntuOne. When I go to the UbuntuOne web site the folder shows up and I can view the pictures after I download them. But when I open the UbuntuOne folder on my laptop, the folder with the pictures from my phone isn't listed. How can I get the picture folder to show up in the UbuntuOne folder on my laptop? I was hoping this would be an easy way to get photos from phone to computer.

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