Search Results

Search found 13454 results on 539 pages for 'left'.

Page 2/539 | < Previous Page | 1 2 3 4 5 6 7 8 9 10 11 12  | Next Page >

• LEFT OUTER JOIN in NHibernate with SQL semantics

  - by Yuval

  Hi, Is it possible to use HQL/ICritera to produce a query with the same semantics as the following SQL query: select table1.A, table2.B, count(*) from table1 left join (select table2.parent_id, table2.B from table2 where table2.C = 'Some value') as table2 on table2.parent_id = table1.id group by table1.A, table2.B order by table1.A In particular, what I'd like is to receive rows (that is, objects) from table1 that have no matching rows in table2. However, I only get the rows from table1 that have matches in table2. Is this the meaning of 'LEFT JOIN' in HQL? And if so, how can I get it to join on a subquery? Tnx.

  Read the article

• mySQL Left Join on multiple tables with conditions

  - by Jarrod

  Hi, I have a problem. I have 4 tables: Invoice_Payment, Invoice, Client, and Calendar Basically, I have the below query, which works well, except, months with no date_due don't return. I.E only months with a date_due will be returned. I think I have to use a left join and join the calendar table with something like: LEFT JOIN Calendar ON Invoice_Payments.date_paid = Calendar.date_field. But I'm having no luck SELECT MONTHNAME(Invoice_Payments.date_paid) as month, SUM(Invoice_Payments.paid_amount) AS total FROM Invoice, Client, Invoice_Payments WHERE Client.registered_id = 1 AND Client.id = Invoice.client_id And Invoice.id = Invoice_Payments.invoice_id AND date_paid IS NOT NULL GROUP BY YEAR(Invoice_Payments.date_paid), MONTH(Invoice_Payments.date_paid) Any help appreciated.

  Read the article

• Nhibernate Left Outer Join Return First Record of the Join

  - by Touch

  I have the following mappings of which Im trying to bring back 0 - 1 Media Id associated with a Product using a left join (I havnt included my attempt as it confuses the situation) ICriteria productCriteria = Session.CreateCriteria(typeof(Product)); productCriteria .CreateAlias("ProductCategories", "pc", JoinType.InnerJoin) .CreateAlias("pc.ParentCategory", "category") .CreateAlias("category.ParentCategory", "group") .Add(Restrictions.Eq("group.Id", 333)) .SetProjection( Projections.Distinct( Projections.ProjectionList() .Add(Projections.Alias(Projections.Property("Id"), "Id")) .Add(Projections.Alias(Projections.Property("Title"), "Title")) .Add(Projections.Alias(Projections.Property("Price"), "Price")) .Add(Projections.Alias(Projections.Property("media.Id"), "SearchResultMediaId")) // I NEED THIS ) ) .SetResultTransformer(Transformers.AliasToBean<Product>()); IList<Product> products = productCriteria .SetFirstResult(0) .SetMaxResults(10) .List<Product>(); I need the query to populate the SearchResultMediaId with Media.Id, I only want to bring back the first Media in a left outer join, as this is 1 to many association between Product and Media Product is mapped to Media in the following way mapping.HasManyToMany<Media>(x => x.Medias) .Table("ProductMedias") .ParentKeyColumn("ProductId") .ChildKeyColumn("MediaId") .Cascade.AllDeleteOrphan() .LazyLoad() .AsBag(); Any Help would be fantastic.

  Read the article

• SELECT subset from two tables and LEFT JOIN results

  - by Doctor Trout

  Hi all, I'm trying to write a bit of SQL for SQLITE that will take a subset from two tables (TableA and TableB) and then perform a LEFT JOIN. This is what I've tried, but this produces the wrong result: Select * from TableA Left Join TableB using(key) where TableA.key2 = "xxxx" AND TableB.key3 = "yyyy" This ignore cases where key2="xxxx" but key3 != "yyyy". I want all the rows from TableA that match my criteria whether or not their corresponding value in TableB matches, but only those rows from TableB that match both conditions. I did manage to solve this by using a VIEW, but I'm sure there must be a better way of doing this. It's just beginning to drive me insane tryng to solve it now. (Thanks for any help, hope I've explained this well enough).

  Read the article

• right-to-left unordered list

  - by Crippletoe

  hi all, i am trying to make an unordered list to behave in different browsers. i have a 2 level list which i am trying to display horizontally in one line. on safari and firefox everything looks good. on IE (7) everything goes nuts for some reason, and only when i am trying to make the list go right-to-left. when i try displaying it left to right, all browsers behave. a simple example of what i was doing is here: http://www.g6pdrecords.com/svk/test.html the CSS is found in the . any ideas anyone? thanks

  Read the article

• Broken count(*) after adding LEFT JOIN

  - by Iain Urquhart

  Since adding the LEFT JOIN to the query below, the count(*) has been returning some strange values, it seems to have added the total rows returned in the query to the 'level': SELECT `n`.*, exp_channel_titles.*, round((`n`.`rgt` - `n`.`lft` - 1) / 2, 0) AS childs, count(*) - 1 + (`n`.`lft` > 1) + 1 AS level, ((min(`p`.`rgt`) - `n`.`rgt` - (`n`.`lft` > 1)) / 2) > 0 AS lower, (((`n`.`lft` - max(`p`.`lft`) > 1))) AS upper FROM `exp_node_tree_6` `n` LEFT JOIN `exp_channel_titles` ON (`n`.`entry_id`=`exp_channel_titles`.`entry_id`), `exp_node_tree_6` `p`, `exp_node_tree_6` WHERE `n`.`lft` BETWEEN `p`.`lft` AND `p`.`rgt` AND ( `p`.`node_id` != `n`.`node_id` OR `n`.`lft` = 1 ) GROUP BY `n`.`node_id` ORDER BY `n`.`lft` I'm totally stumped... Thank you!

  Read the article

• Multiple left joins, how to output in php

  - by Dan

  I have 3 tables I need to join. The contracts table is the main table, the 'jobs' and 'companies' table are extra info that can be associated to the contracts table. so, since I want all entries from my 'contracts' table, and the 'jobs' and 'companies' data only if it exists, I wrote the query like this.... $sql = "SELECT * FROM contracts LEFT JOIN jobs ON contracts.job_id = jobs.id LEFT JOIN companies ON contracts.company_id = companies.id ORDER BY contracts.end_date"; Now how would I output this in PHP? I tried this but kept getting an undefined error "Notice: Undefined index: contracts.id"... $sql_result = mysql_query($sql,$connection) or die ("Fail."); if(mysql_num_rows($sql_result) > 0){ while($row = mysql_fetch_array($sql_result)) { $contract_id = stripslashes($row['contracts.id']); $job_number = stripslashes($row['jobs.job_number']); $company_name = stripslashes($row['companies.name']); ?> <tr id="<?=$contract_id?>"> <td><?=$job_number?></td> <td><?=$company_name?></td> </tr> <? } }else{ echo "No records found"; } Any help is appreciated.

  Read the article

• SQL Standard Regarding Left Outer Join and Where Conditions

  - by Ryan

  I am getting different results based on a filter condition in a query based on where I place the filter condition. My questions are: Is there a technical difference between these queries? Is there anything in the SQL standard that explains the different resultsets in the queries? Given the simplified scenario: --Table: Parent Columns: ID, Name, Description --Table: Child Columns: ID, ParentID, Name, Description --Query 1 SELECT p.ID, p.Name, p.Description, c.ID, c.Name, c.Description FROM Parent p LEFT OUTER JOIN Child c ON (p.ID = c.ParentID) WHERE c.ID IS NULL OR c.Description = 'FilterCondition' --Query 2 SELECT p.ID, p.Name, p.Description, c.ID, c.Name, c.Description FROM Parent p LEFT OUTER JOIN Child c ON (p.ID = c.ParentID AND c.Description = 'FilterCondition') I assumed the queries would return the same resultsets and I was surprised when they didn't. I am using MS SQL2005 and in the actual queries, query 1 returned ~700 rows and query 2 returned ~1100 rows and I couldn't detect a pattern on which rows were returned and which rows were excluded. There were still many rows in query 1 with child rows with data and NULL data. I prefer the style of query 2 (and I think it is more optimal), but I thought the queries would return the same results.

  Read the article

• Mysql Left Join Null Result

  - by Ozzy

  I have this query SELECT articles.*, users.username AS `user` FROM `articles` LEFT JOIN `users` ON articles.user_id = users.id ORDER BY articles.timestamp Basically it returns the list of articles and the username that the article is associated to. Now if there is no entry in the users table for a particular user id, the users var is NULL. Is there anyway to make it that if its null it returns something like "User Not Found"? or would i have to do this using php?

  Read the article

• Removing right-to-left mark and other unicode characters from input in Python

  - by Earl Bellinger

  I am writing a forum in Python. I want to strip input containing the right-to-left mark and things like that. Suggestions? Possibly a regular expression?

  Read the article

• Website in right-to-left languages (Arabic, Hebrew)

  - by jack

  I currently developing a multi-language interface for a Django project. But when I started to work on Arabic and Hebrew languages, I noticed all pages messed up after dir="rtl" to html tag (according to instructions on http://www.w3.org/International/tutorials/bidi-xhtml/) Does that mean I need separate stylesheets for right-to-left languages?

  Read the article

• Using CASE Statements in LEFT OUTER JOIN in SQL

  - by s khan

  I've got a scenario where I want to switch on two different tables in an outer join. It goes something like this:- select mytable.id, yourtable.id from mytable left outer join (case when mytable.id = 2 then table2 yourtable on table1.id = table2.id else table3 yourtable on table1.id = table3.id end) ...but it doesn't work. Any suggestions?

  Read the article

• jCarousel scrolling from right to left

  - by Crippletoe

  Hi everyone, i am trying to reverse the scrolling direction of Jcarousel and make it scroll from right to left. anyone knows how that is done? thanks!

  Read the article

• LINQ to SQL left outer joins

  - by César

  Is this query equivalent to a LEFT OUTER join? var rows = from a in query join s in context.ViewSiteinAdvise on a.Id equals s.SiteInAdviseId where a.Order == s.Order select new {....}; I tried this but it did not result from s in ViewSiteinAdvise join q in query on s.SiteInAdviseId equals q.Id into sa from a in sa.DefaultIfEmpty() where s.Order == a.Order select new {s,a} I need all columns from View

  Read the article

• MySQL 5 left join unknown column

  - by NP

  I had the below query working in mysql 4.1, but does not in 5.0: SELECT * FROM email e, event_email ee LEFT JOIN member m on m.email=e.email WHERE ee.email_id = e.email_id The error: 1054 (Unknown column 'e.email' in 'on clause')

  Read the article

• MySql left join on several regs

  - by egidiocs

  Hi there! I have this table1 idproduct(PK) | date_to_go 1 2010-01-18 2 2010-02-01 3 2010-02-21 4 2010-02-03 and this other table2 that controls date_to_go updates id | idproduct(FK) | prev_date_to_go | date_to_go | update_date 1 1 2010-01-01 2010-01-05 2009-12-01 2 1 2010-01-05 2010-01-10 2009-12-20 3 1 2010-01-10 2010-01-18 2009-12-20 4 3 2010-01-20 2010-02-03 2010-01-05 So, in this example, for table1.idproduct #1 2010-01-18 is the actual date_to_go and 2010-01-01 (table2.prev_date_to_go, first reg) is the original date_to_go . using this query select v.idproduct, v.date_to_go, p.prev_date_to_go original_date_to_go from table1 v left join produto_datas p on p.idproduto = v.idproduto group by (v.idproduto) order by v.idproduto can I assume that original_date_to_go will be the first related reg of table2? idproduct | date_to_go | original_date_to_go 1 2010-01-18 2010-01-01 2 2010-02-01 NULL 3 2010-02-21 2010-01-20 4 2010-02-03 NULL

  Read the article

• django left join with null

  - by SledgehammerPL

  The model: class Product(models.Model): name = models.CharField(max_length = 128) def __unicode__(self): return self.name class Receipt(models.Model): name = models.CharField(max_length=128) components = models.ManyToManyField(Product, through='ReceiptComponent') class Admin: pass def __unicode__(self): return self.name class ReceiptComponent(models.Model): product = models.ForeignKey(Product) receipt = models.ForeignKey(Receipt) quantity = models.FloatField(max_length=9) unit = models.ForeignKey(Unit) def __unicode__(self): return unicode(self.quantity!=0 and self.quantity or '') + ' ' + unicode(self.unit) + ' ' + self.product.genitive The idea: there are a components on stock. I'd like to find out which recipes I can made with components which I have. It's not easy - but possible - I made a SQL view, which gets the solution. But I'm learning python and Django so I'd like to make it Django-style ;D The concept of solution: get the set of recipes which has at last one component: list_of_available_components = ReceiptComponent.objects.filter(product__in=list_of_available_products).distinct() list_of_related_receipts = Receipt.objects.filter(receiptcomponent__in = list_of_available_components).distinct() get recipes (from list_of_related_receipts) which has not at last one component list_of_incomplete_recipes = (SELECT * FROM drinkbook_receiptcomponent LEFT JOIN drinkstore_stock_products USING(product_id) WHERE drinkstore_stock_products.stock_id IS NULL AND receipt_id IN (SELECT receipt_id FROM drinkbook_receiptcomponent JOIN drinkstore_stock_products USING(product_id))) get recipes (from list_of_related_receipts) which are not in "list_of_incomplete_recipes"

  Read the article

• Customizing Hibernate Criteria - Adding conditions to a left join

  - by Douglas Ferguson

  I need to be able to do the following: Select * from Table1 left join Table2 on id1 = id2 AND i1 = ? Hibernate criteria doesn't allow be to specify the i1 = ? part. The existing code is using hibernate criteria and it would be a huge refactor to swap out for HQL Does anybody have any tips how I could implement this differently or any way to override the Hibernate Criteria? I'm not opposed to cracking open hibernate and modifying, but when I began to dig it, there seems to be layers upon layers of abstractions. I never found the the point where SQL is actually generated...

  Read the article

• mySQL Left Join on multiple tables

  - by Jarrod

  Hi I'm really struggling with this query. I have 4 tables (http://oberto.co.nz/db-sql.png): Invoice_Payement, Invoice, Client and Calendar. I'm trying to create a report by summing up the 'paid_amount' col, in Invoice_Payment, by month/year. The query needs to include all months, even those with no data There query needs the condition (Invoice table): registered_id = [id] I have tried with the below query, which works, but falls short when 'paid_date' does not have any records for a month. The outcome is that month does not show in the results I added a Calendar table to resolved this but not sure how to left join to it. SELECT MONTHNAME(Invoice_Payments.date_paid) as month, SUM(Invoice_Payments.paid_amount) AS total FROM Invoice, Client, Invoice_Payments WHERE Client.registered_id = 1 AND Client.id = Invoice.client_id And Invoice.id = Invoice_Payments.invoice_id AND date_paid IS NOT NULL GROUP BY YEAR(Invoice_Payments.date_paid), MONTH(Invoice_Payments.date_paid) Please see the above link for a basic ERD diagram of my scenario. Thanks for reading. I've posted this Q before but I think I worded it badly.

  Read the article

• SQL query for getting count on same table using left outer join

  - by Sasi

  Hi all, I have a table from which i need to get the count grouped on two columns. the table has two columns one datetime column and another one is success value(-1,1,0) What i am looking for is something like this... count of success value for each month month----success-----count 11------- -1 ------- 50 11------- 1 --------- 50 11------- 0 ------- 50 12------- -1 ------- 50 12------- 1 ------- 50 12------- 0 ------- 50 if there is no success value for a month then the count should be null or zero. I have tried with left outer join as well but of no use it gives the count incorrectly. Thanks in advance Sasi

  Read the article

• LINQ, Left Join, Only Get where null in join table

  - by kmehta

  Hi. I am trying to do a left outer join on two tables, but I only want to return the results from the first table where the second table does not have a record (null). var agencies = from a in agencyList join aa in joinTable on a.AgencyId equals aa.AgencyId into joined from aa in joined.DefaultIfEmpty() where aa == null) select a; But this does not exclude the non null values of aa, and returns all the records just the same as if the 'where aa == null' was not there. Any help is appreciated. Thanks.

  Read the article

• Left outer join null using VB.NET and LINQ

  - by jvcoach23

  I've got what I think is a working left outer join LINQ query, but I'm having problems with the select because of null values in the right hand side of the join. Here is what I have so far Dim Os = From e In oExcel Group Join c In oClassIndexS On c.tClassCode Equals Mid(e.ClassCode, 1, 4) Into right1 = Group _ From c In right1.DefaultIfEmpty I want to return all of e and one column from c called tClassCode. I was wondering what the syntax would be. As you can see, I'm using VB.NET. Update... Here is the query doing join where I get the error: _message = "Object reference not set to an instance of an object." Dim Os = From e In oExcel Group Join c In oClassIndexS On c.tClassCode Equals Mid(e.ClassCode, 1, 4) Into right1 = Group _ From c In right1.DefaultIfEmpty Select e, c.tClassCode If I remove the c.tClassCode from the select, the query runs without error. So I thought perhaps I needed to do a select new, but I don't think I was doing that correctly either.

  Read the article

• mysql filtering result using left outer join

  - by user288178

  my query: SELECT content.*, activity_log.content_id FROM content LEFT JOIN activity_log ON content.id = activity_log.content_id AND sess_id = '$sess_id' WHERE activity_log.content_id IS NULL AND visibility = $visibility AND content.reported < ".REPORTED_LIMIT." AND content.file_ready = 1 LIMIT 1 The purpose of that query is to get 1 row from the content table that has not been viewed by the user (identified by session_id), but it still returns contents that have been viewed. What is wrong? ( I have checked the table making sure that the content_ids are there) Note: I think this is more efficient than using subqueries, thoughts?

  Read the article

• Left Join not returning all rows

  - by DisgruntledGoat

  I have this query in MySQL: SELECT pr.*, pr7.value AS `room_price_high` FROM `jos_hp_properties` pr LEFT OUTER JOIN `jos_hp_properties2` pr7 ON pr7.property=pr.id WHERE pr7.field=23 The jos_hp_properties table has 27 rows but the query only returns one. Based on this question I think it may be because of the WHERE clause. The jos_hp_properties2 table has fields id, property, field, value, where field is a foreign key to a third table (which I don't need to get data from). Is there a way to select all the rows from the first table, including the value from table #2 where the field is 23 (or NULL if there is no field 23)?

  Read the article

• SQL LEFT JOIN help

  - by Stolz

  My scenario: There are 3 tables for storing tv show information; season, episode and episode_translation. My data: There are 3 seasons, with 3 episodes each one, but there is only translation for one episode. My objetive: I want to get a list of all the seasons and episodes for a show. If there is a translation available in a specified language, show it, otherwise show null. My attempt to get serie 1 information in language 1: SELECT season_number AS season,number AS episode,name FROM season NATURAL JOIN episode NATURAL LEFT JOIN episode_trans WHERE id_serie=1 AND id_lang=1 ORDER BY season_number,number result: +--------+---------+--------------------------------+ | season | episode | name | +--------+---------+--------------------------------+ | 3 | 3 | Episode translated into lang 1 | +--------+---------+--------------------------------+ expected result +-----------------+--------------------------------+ | season | episode| name | +-----------------+--------------------------------+ | 1 | 1 | NULL | | 1 | 2 | NULL | | 1 | 3 | NULL | | 2 | 1 | NULL | | 2 | 2 | NULL | | 2 | 3 | NULL | | 3 | 1 | NULL | | 3 | 2 | NULL | | 3 | 3 | Episode translated into lang 1 | +--------+--------+--------------------------------+ Full DB dump http://pastebin.com/Y8yXNHrH

  Read the article

< Previous Page | 1 2 3 4 5 6 7 8 9 10 11 12  | Next Page >