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• SEO issue - External links rel="nofollow" or NOT!

  - by Mary Melody

  Previously I created a website for promo codes and coupons. That have hundreds of external links to the Retailer's websites and I used rel="nofollow" tag. But my site SEO rank was very very... bad especially on Google. So then I removed the rel="nofollow" tag, but no improvement. The only difference between this site and my other sites is "External links". My other sites have good ranking on Google. Now I'm creating a site for reviews. So this is also similar situation for me. I just want to know about how does SEO react with external links? and then what possibly happened in my case?

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• Programming in R help

  - by mary

  I needed help in converting the temperature from Farenheit to Celsius. Below are several attempts and each of these fails. I have ran the following below and need help in saying what error message is created by: a) (temp -32) Can you please let me know the error message in a comment, and what it means and how to directly relate the wording of the error message with the problem you find in the expression. likewise for: b) (temp - 32)5/9 don't know the erorr on this one c) 5/9(temp - 32) need an asterisk, but not specific enough d) [temp - 32]5/9 I know braces is off.

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• Php: Overriding abstract method goes wrong

  - by Lu4

  Hi! I think there is a problem in php's OOP implementation. EDIT: Consider more illustrative example: abstract class Animal { public $name; // public function Communicate(Animal $partner) {} // Works public abstract function Communicate(Animal $partner); // Gives error } class Panda extends Animal { public function Communicate(Panda $partner) { echo "Hi {$partner->name} I'm a Panda"; } } class Human extends Animal { public function Communicate(Human $partner) { echo "Hi {$partner->name} I'm a Human"; } } $john = new Human(); $john->name = 'John'; $mary = new Human(); $mary->name = 'Mary'; $john->Communicate($mary); // should be ok $zuzi = new Panda(); $zuzi->name = 'Zuzi'; $zuzi->Communicate($john); // should give error The problem is that when Animal::Communicate is an abstract method, php tells that the following methods are illegal: "public function Communicate(Panda $partner)" "public function Communicate(Human $partner)" but when Animal::Communicate is non-abstract but has zero-implementation Php thinks that these methods are legal. So in my opinion it's not right because we are doing override in both cases, and these both cases are equal, so it seems like it's a bug... Older part of the post: Please consider the following code: Framework.php namespace A { class Component { ... } abstract class Decorator { public abstract function Decorate(\A\Component $component); } } Implementation.php namespace B { class MyComponent extends \A\Component { ... } } MyDecorator.php namespace A { class MyDecorator extends Decorator { public function Decorate(\B\MyComponent $component) { ... } } } The following code gives error in MyDecorator.php telling Fatal error: Declaration of MyDecorator::Decorate() must be compatible with that of A\Decorator::Decorate() in MyDecorator.php on line ... But when I change the Framework.php::Decorator class to the following implementation: abstract class Decorator { public function Decorate(\A\Component $component) {} } the problem disappears.

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• Parsing back to 'messy' API strcuture

  - by Eric Fail

  I'm fetching data from an online database (REDcap) via API and the data gets delivered in as comma separated string like this, RAW.API <- structure("id,event_arm,name,dob,pushed_text,pushed_calc,complete\n\"01\",\"event_1_arm_1\",\"John\",\"1979-05-01\",\"\",\"\",2\n\"01\",\"event_2_arm_1\",\"John\",\"2012-09-02\",\"abc\",\"123\",1\n\"01\",\"event_3_arm_1\",\"John\",\"2012-09-10\",\"\",\"\",2\n\"02\",\"event_1_arm_1\",\"Mary\",\"1951-09-10\",\"def\",\"456\",2\n\"02\",\"event_2_arm_1\",\"Mary\",\"1978-09-12\",\"\",\"\",2\n", "`Content-Type`" = structure(c("text/html", "utf-8"), .Names = c("", "charset"))) I have this script that nicely parses it into a data frame, (df <- read.table(file = textConnection(RAW.API), header = TRUE, sep = ",", na.strings = "", stringsAsFactors = FALSE)) id event_arm name dob pushed_text pushed_calc complete 1 1 event_1_arm_1 John 1979-05-01 <NA> NA 2 2 1 event_2_arm_1 John 2012-09-02 abc 123 1 3 1 event_3_arm_1 John 2012-09-10 <NA> NA 2 4 2 event_1_arm_1 Mary 1951-09-10 def 456 2 5 2 event_2_arm_1 Mary 1978-09-12 <NA> NA 2 I then do some calculations and write them to pushed_text and pushed_calc whereafter I need to format the data back to the messy comma separated structure it came in. I imagine something like this, API.back <- `some magic command`(df, ...) identical(RAW.API, API.back) [1] TRUE Some command that can format my data from the data frame I made, df, back to the structure that the raw API-object came in, RAW.API. Any help would be very appreciated.

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• Get results by name in Excel 2010

  - by Tom

  I need to parse through the data below and show results like: Mary notready=483 training=452 break=30 I have the formulas — what I'm having trouble with is: The names are first, then 7 to 10 rows of data and what I need is some kind of array that will pull 1st Break_100 under that name, even though they are in different rows. Mary Summary: 08:02:32 () 9/19/2012 Not_Ready_Default_Reason_Code 00:00:05 Training_3000 07:32:21 Break_1000 00:30:06 daily 9/19/2012 08:02:32 Agent: 08:02:32 Dan Summary: 01:18:33 () 9/19/2012 Break_1000 00:34:27 Not_Ready_Default_Reason_Code 00:01:37 Personal_4000 00:42:29 daily 9/19/2012 01:18:33 Agent: 01:18:33

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• Convert Normalize table to Unormalize table

  - by M R Jafari

  I have tow tables, Table A has 3 columns as StudentID, Name, Course, ClassID and Table B has many columns as StudentID, Name, Other1, Other2, Other3 ... I want convert Table A to Table B. Please help me! Table A StudentID Name Course ClassID 85001 David Data Base 11 85001 David Data Structure 22 85002 Bob Math 33 85002 Bob Data Base 44 85002 Bob Data Structure 55 85002 Bob C# 66 85003 Sara C# 77 85003 Sara Data Base 88 85004 Mary Math 99 85005 Mary Math 100 … Table B SdentdID Name Other 1 Other 2 Other 3 Other 4 … 85001 David DBase,11 DS,22 85002 Bob Math,33 DB,44 DS,55 C#,66 85003 Sara C#,77 DBase,88 85004 Mary Math,99

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• Graph databases and Php

  - by stagas

  I want to use a graph database using php. Can you point out some resources on where to get started? Is there any example code / tutorial out there? Or are there any other methods of storing data that relate to each other in totally random/abstract situations? Very abstract example of the relations needed: John relates to Mary, both relate to School, John is Tall, Mary is Short, John has Blue Eyes, Mary has Green Eyes, query I want is which people are related to 'Short people that have Green Eyes and go to School' - answer John It is possible in MySQL but it would require a fixed set of attributes/columns for each item and a complex non-flexible query, instead I need every attribute to be an item by itself and instead of 'belonging' to something, to be 'related' to something.

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• Objective C - RegexKitLite - Parsing inner contents of a string, ie: start(.*?)end

  - by Stu

  Please consider the following: NSString *myText = @"mary had a little lamb"; NSString *regexString = @"mary(.*?)little"; for)NSString *match in [myText captureComponentsMatchedByRegex:regexString]){ NSLog(@"%@",match); } This will output to the console two things: 1) "mary had a little" 2) "had a" What I want is just the 2nd bit of information "had a". Is there is a way of matching a string and returning just the inner part? I'm fairly new to Objective C, this feels a rather trivial question yet I can't find a less messy way of doing this than incrementing an integer in the for loop and on the second iteration storing the "had a" in an NSString.

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• AJAX response inside jqplot not working

  - by JuanGesino

  I'm trying to render data from an AJAX response as a bar chart with jqplot. To render this bar chart I use two variables: s1 which contains the numbers ex: s1 = [22,67,32,89] ticks which contains the name corresponding to a number inside s1 ex: ticks = ["Jack", "Mary", "Paul", "John"] So my AJAX returns two variables, data1 and data2. When I console.log(data1) I get 22,67,32,89 When I console.log(data2) I get "Jack", "Mary", "Paul", "John" I then add the square brackets and change variable: s1 = [data1] ticks = [data2] When I console.log(s1) I get ["22,67,32,89"] When I console.log(ticks) I get "Jack", "Mary", "Paul", "John" And the graph does not render, this is my code: s1 = [data]; ticks = [data]; plot4 = $.jqplot('chartdiv4', [s1], { animate: !$.jqplot.use_excanvas, series:[{color:'#5FAB78'}], seriesDefaults:{ renderer:$.jqplot.BarRenderer, pointLabels: { show: true } }, axes: { xaxis: { renderer: $.jqplot.CategoryAxisRenderer, ticks: ticks }, yaxis:{min:0, max:100, label:'%',labelRenderer: $.jqplot.CanvasAxisLabelRenderer} }, highlighter: { show: false } }); });

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• Latest Edition of Security Inside Out Newsletter Now Available

  - by Troy Kitch

  The latest edition of Security Inside Out newsletter is now available. If you don't get this bi-monthly security newsletter in your inbox, then subscribe to get the latest database security news. This bi-monthly edition includes: Q&A: Oracle CSO Mary Ann Davidson on Meeting Tomorrow's Security Threats Oracle Chief Security Officer Mary Ann Davidson shares her thoughts on next-generation security threats.  Read More New Study: Increased Security Spending Still Not Protecting Right Assets Despite widespread belief that database breaches represent the greatest security risk to their business, organizations continue to devote a far greater share of their security resources to network assets rather than database assets, according to a new report issued by CSO and sponsored by Oracle. Read More

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• What is the effect of this order_by clause?

  - by bread

  I don't understand what this order_by clause is doing and whether I need it or not: select c.customerid, c.firstname, c.lastname, i.order_date, i.item, i.price from items_ordered i, customers c where i.customerid = c.customerid group by c.customerid, i.item, i.order_date order by i.order_date desc; This produces this data: 10330 Shawn Dalton 30-Jun-1999 Pogo stick 28.00 10101 John Gray 30-Jun-1999 Raft 58.00 10410 Mary Ann Howell 30-Jan-2000 Unicycle 192.50 10101 John Gray 30-Dec-1999 Hoola Hoop 14.75 10449 Isabela Moore 29-Feb-2000 Flashlight 4.50 10410 Mary Ann Howell 28-Oct-1999 Sleeping Bag 89.22 10339 Anthony Sanchez 27-Jul-1999 Umbrella 4.50 10449 Isabela Moore 22-Dec-1999 Canoe 280.00 10298 Leroy Brown 19-Sep-1999 Lantern 29.00 10449 Isabela Moore 19-Mar-2000 Canoe paddle 40.00 10413 Donald Davids 19-Jan-2000 Lawnchair 32.00 10330 Shawn Dalton 19-Apr-2000 Shovel 16.75 10439 Conrad Giles 18-Sep-1999 Tent 88.00 10298 Leroy Brown 18-Mar-2000 Pocket Knife 22.38 10299 Elroy Keller 18-Jan-2000 Inflatable Mattress 38.00 10438 Kevin Smith 18-Jan-2000 Tent 79.99 10101 John Gray 18-Aug-1999 Rain Coat 18.30 10449 Isabela Moore 15-Dec-1999 Bicycle 380.50 10439 Conrad Giles 14-Aug-1999 Ski Poles 25.50 10449 Isabela Moore 13-Aug-1999 Unicycle 180.79 10101 John Gray 08-Mar-2000 Sleeping Bag 88.70 10299 Elroy Keller 06-Jul-1999 Parachute 1250.00 10438 Kevin Smith 02-Nov-1999 Pillow 8.50 10101 John Gray 02-Jan-2000 Lantern 16.00 10315 Lisa Jones 02-Feb-2000 Compass 8.00 10449 Isabela Moore 01-Sep-1999 Snow Shoes 45.00 10438 Kevin Smith 01-Nov-1999 Umbrella 6.75 10298 Leroy Brown 01-Jul-1999 Skateboard 33.00 10101 John Gray 01-Jul-1999 Life Vest 125.00 10330 Shawn Dalton 01-Jan-2000 Flashlight 28.00 10298 Leroy Brown 01-Dec-1999 Helmet 22.00 10298 Leroy Brown 01-Apr-2000 Ear Muffs 12.50 While if I remove the order_by clause completely, as in this query: select c.customerid, c.firstname, c.lastname, i.order_date, i.item, i.price from items_ordered i, customers c where i.customerid = c.customerid group by c.customerid, i.item, i.order_date; I get these results: 10101 John Gray 30-Dec-1999 Hoola Hoop 14.75 10101 John Gray 02-Jan-2000 Lantern 16.00 10101 John Gray 01-Jul-1999 Life Vest 125.00 10101 John Gray 30-Jun-1999 Raft 58.00 10101 John Gray 18-Aug-1999 Rain Coat 18.30 10101 John Gray 08-Mar-2000 Sleeping Bag 88.70 10298 Leroy Brown 01-Apr-2000 Ear Muffs 12.50 10298 Leroy Brown 01-Dec-1999 Helmet 22.00 10298 Leroy Brown 19-Sep-1999 Lantern 29.00 10298 Leroy Brown 18-Mar-2000 Pocket Knife 22.38 10298 Leroy Brown 01-Jul-1999 Skateboard 33.00 10299 Elroy Keller 18-Jan-2000 Inflatable Mattress 38.00 10299 Elroy Keller 06-Jul-1999 Parachute 1250.00 10315 Lisa Jones 02-Feb-2000 Compass 8.00 10330 Shawn Dalton 01-Jan-2000 Flashlight 28.00 10330 Shawn Dalton 30-Jun-1999 Pogo stick 28.00 10330 Shawn Dalton 19-Apr-2000 Shovel 16.75 10339 Anthony Sanchez 27-Jul-1999 Umbrella 4.50 10410 Mary Ann Howell 28-Oct-1999 Sleeping Bag 89.22 10410 Mary Ann Howell 30-Jan-2000 Unicycle 192.50 10413 Donald Davids 19-Jan-2000 Lawnchair 32.00 10438 Kevin Smith 02-Nov-1999 Pillow 8.50 10438 Kevin Smith 18-Jan-2000 Tent 79.99 10438 Kevin Smith 01-Nov-1999 Umbrella 6.75 10439 Conrad Giles 14-Aug-1999 Ski Poles 25.50 10439 Conrad Giles 18-Sep-1999 Tent 88.00 10449 Isabela Moore 15-Dec-1999 Bicycle 380.50 10449 Isabela Moore 22-Dec-1999 Canoe 280.00 10449 Isabela Moore 19-Mar-2000 Canoe paddle 40.00 10449 Isabela Moore 29-Feb-2000 Flashlight 4.50 10449 Isabela Moore 01-Sep-1999 Snow Shoes 45.00 10449 Isabela Moore 13-Aug-1999 Unicycle 180.79 I'm not sure what the order_by is doing here and if it's having the intended effects.

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• Class Problem (c++ and prolog)

  - by Joshua Green

  I am using the C++ interface to Prolog (the classes and methods of SWI-cpp.h). For working out a simple backtracking that john likes mary and emma and sara: likes(john, mary). likes(john, emma). likes(john, ashley). I can just do: { PlFrame fr; PlTermv av(2); av[0] = PlCompound("john"); PlQuery q("likes", av); while (q.next_solution()) { cout << (char*)av[1] << endl; } } This works in a separate code, so the syntax is correct. But I am also trying to get this simple backtracking to work within a class: class UserTaskProlog { public: UserTaskProlog(ArRobot* r); ~UserTaskProlog(); protected: int cycles; char* argv[1]; ArRobot* robot; void logTask(); }; This class works fine, with my cycles variable incrementing every robot cycle. However, when I run my main code, I get an Unhandled Exception error message: UserTaskProlog::UserTaskProlog(ArRobot* r) : robotTaskFunc(this, &UserTaskProlog::logTask) { cycles = 0; PlEngine e(argv[0]); PlCall("consult('myFile.pl')"); robot->addSensorInterpTask("UserTaskProlog", 50, &robotTaskFunc); } UserTaskProlog::~UserTaskProlog() { robot->remSensorInterpTask(&robotTaskFunc); // Do I need a destructor here for pl? } void UserTaskProlog::logTask() { cycles++; cout << cycles; { PlFrame fr; PlTermv av(2); av[0] = PlCompound("john"); PlQuery q("likes", av); while (q.next_solution()) { cout << (char*)av[1] << endl; } } } I have my opening and closing brackets for PlFrame. I have my frame, my query, etc... The exact same code that backtracks and prints out mary and emma and sara. What am I missing here that I get an error message? Here is what I think the code should do: I expect mary and emma and sara to be printed out once, every time cycles increments. However, it opens SWI-cpp.h file automatically and points to class PlFrame. What is it trying to tell me? I don't see anything wrong with my PlFrame class declaration. Thanks,

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• hash of array in objective-c, how?

  - by Horace Ho

  How is a hash of integer array can be represented in objective-c? Here is the ruby hash as an example: hi_scores = { "John" => [1, 1000], "Mary" => [2, 8000], "Bob" => [5, 2000] } such that can be accessed by: puts hi_scores["Mary"][1] => 8000 hopefully easy to serialize too. Thanks!

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• Potential issues using member's "from" address and the "sender" header

  - by Paul Burney

  Hi all, A major component of our application sends email to members on behalf of other members. Currently we set the "From" address to our system address and use a "Reply-to" header with the member's address. The issue is that replies from some email clients (and auto-replies/bounces) don't respect the "Reply-to" header so get sent to our system address, effectively sending them to a black hole. We're considering setting the "From" address to our member's address, and the "Sender" address to our system address. It appears this way would pass SPF and Sender-ID checks. Are there any reasons not to switch to this method? Are there any other potential issues? Thanks in advance, -Paul Here are way more details than you probably need: When the application was first developed, we just changed the "from" address to be that of the sending member as that was the common practice at the time (this was many years ago). We later changed that to have the "from" address be the member's name and our address, i.e., From: "Mary Smith" <[email protected]> With a "reply-to" header set to the member's address: Reply-To: "Mary Smith" <[email protected]> This helped with messages being mis-categorized as spam. As SPF became more popular, we added an additional header that would work in conjunction with our SPF records: Sender: <[email protected]> Things work OK, but it turns out that, in practice, some email clients and most MTA's don't respect the "Reply-To" header. Because of this, many members send messages to [email protected] instead of the desired member. So, I started envisioning various schemes to add data about the sender to the email headers or encode it in the "from" email address so that we could process the response and redirect appropriately. For example, From: "Mary Smith" <[email protected]> where the string after "messages" is a hash representing Mary Smith's member in our system. Of course, that path could lead to a lot of pain as we need to develop MTA functionality for our system address. I was looking again at the SPF documentation and found this page interesting: http://www.openspf.org/Best_Practices/Webgenerated They show two examples, that of evite.com and that of egreetings.com. Basically, evite.com is doing it the way we're doing it. The egreetings.com example uses the member's from address with an added "Sender" header. So the question is, are there any potential issues with using the egreetings method of the member's from address with a sender header? That would eliminate the replies that bad clients send to the system address. I don't believe that it solves the bounce/vacation/whitelist issue since those often send to the MAIL FROM even if Return Path is specified.

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• LINQ/C#: Where & Foreach using index in a list/array

  - by Andrew White

  Hi, I have a list/array and need to process certain elements, but also need the index of the element in the processing. Example: List Names = john, mary, john, bob, simon Names.Where(s = s != "mary").Foreach(MyObject.setInfo(s.index, "blah") But cannot use the "index" property with lists, inversely if the names were in an Array I cannot use Foreach... Any suggestions?

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• How to do a join that removes values?

  - by Georg

  Customers Holidays id | name customer_id | start | end ---+------ ------------+--------+------ 1 | Peter 1 | 5 | 10 2 | Simon 1 | 15 | 20 3 | Mary 2 | 5 | 20 How should my SQL query look that out of start=11,end=14 I get these customers: Peter Mary Is this even manageable with a simple SQL join, or do I need to use sub-queries?

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• How to loop through items in a js object?

  - by Blankman

  how can I loop through these items? var userCache = {}; userCache['john'] = {ID: 234, name: 'john', ... }; userCache['mary'] = {ID: 567, name: 'mary', ... }; userCache['douglas'] = {ID: 42, name: 'douglas', ... }; the length property doesn't work? userCache.length

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• Create a binary indicator matrix in R

  - by Brian Vanover

  I have a list of data indicating attendance to conferences like this: Event Participant ConferenceA John ConferenceA Joe ConferenceA Mary ConferenceB John ConferenceB Ted ConferenceC Jessica I would like to create a binary indicator attendance matrix of the following format: Event John Joe Mary Ted Jessica ConferenceA 1 1 1 0 0 ConferenceB 1 0 0 1 0 ConferenceC 0 0 0 0 1 Is there a way to do this in R? Sorry for the poor formatting.

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• piping in UNIX doubt

  - by Happy Mittal

  In The Unix Programming Environment by K & P, it is written that " The programs in a pipeline actually run at the same time, not one after another. This means that programs in a pipeline can be interactive;" How can programs run at same time? For ex: $ who | grep mary | wc -l How grep mary will be executed until who is run or how wc -l will be executed until it knows results of previous programs?

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• Encoding arbitrary data into numbers?

  - by Pekka

  Is there a common method to encode and decode arbitrary data so the encoded end result consists of numbers only - like base64_encode but without the letters? Fictitious example: $encoded = numbers_encode("Mary had a little lamb"); echo $encoded; // outputs e.g. 122384337422394237423 (fictitious result) $decoded = numbers_decode("122384337422394237423"); echo $decoded; // outputs "Mary had a little lamb"

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• Simplest way to print an array in Java

  - by Alex Spurling

  What's the simplest way of printing an array of primitives or of objects in Java? Here are some example inputs and outputs: int[] intArray = new int[] {1, 2, 3, 4, 5}; //output: [1, 2, 3, 4, 5] String[] strArray = new String[] {"John", "Mary", "Bob"}; //output: [John, Mary, Bob]

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• Prolog Family tree

  - by Tania

  Hi I have a Question in prolog , I did it but its not showing answers When i ask about the brothers,sisters,uncles,aunts This is what I wrote, what's wrong ? /*uncle(X, Y) :– male(X), sibling(X, Z), parent(Z, Y).*/ /*uncle(X, Y) :– male(X), spouse(X, W), sibling(W, Z), parent(Z, Y).*/ uncle(X,Y) :- parent(Z,Y), brother(X,Z). aunt(X,Y) :- parent(Z,Y), sister(X,Z). sibling(X, Y) :- parent(Z, X), parent(Z, Y), X \= Y. sister(X, Y) :- sibling(X, Y), female(X). brother(X, Y) :- sibling(X, Y), male(X). parent(Z,Y) :- father(Z,Y). parent(Z,Y) :- mother(Z,Y). grandparent(C,D) :- parent(C,E), parent(E,D). aunt(X, Y) :– female(X), sibling(X, Z), parent(Z, Y). aunt(X, Y) :– female(X), spouse(X, W), sibling(W, Z), parent(Z, Y). male(john). male(bob). male(bill). male(ron). male(jeff). female(mary). female(sue). female(nancy). mother(mary, sue). mother(mary, bill). mother(sue, nancy). mother(sue, jeff). mother(jane, ron). father(john, sue). father(john, bill). father(bob, nancy). father(bob, jeff). father(bill, ron). sibling(bob,bill). sibling(sue,bill). sibling(nancy,jeff). sibling(nancy,ron). sibling(jell,ron). And one more thing, how do I optimize the rule of the brother so that X is not brother to itself.

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• How do I Handle Ties When Ranking Results in MySQL?

  - by Laxmidi

  Hi, How does one handle ties when ranking results in a mysql query? I've simplified the table names and columns in this example, but it should illustrate my problem: SET @rank=0; SELECT student_names.students, @rank := @rank +1 AS rank, scores.grades FROM student_names LEFT JOIN scores ON student_names.students = scores.students ORDER BY scores.grades DESC So imagine the the above query produces: Students Rank Grades Al 1 90 Amy 2 90 George 3 78 Bob 4 73 Mary 5 NULL William 6 NULL Even though Al and Amy have the same grade, one is ranked higher than the other. Amy got ripped-off. How can I make it so that Amy and Al have the same ranking, so that they both have a rank of 1. Also, William and Mary didn't take the test. They bagged class and were smoking in the boy's room. They should be tied for last place. The correct ranking should be: Students Rank Grades Al 1 90 Amy 1 90 George 3 78 Bob 4 73 Mary 5 NULL William 5 NULL If anyone has any advice, please let me know. Thank you! -Laxmidi

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• Graph-structured databases and Php

  - by stagas

  I want to use a graph database using php. Can you point out some resources on where to get started? Is there any example code / tutorial out there? Or are there any other methods of storing data that relate to each other in totally random/abstract situations? - Very abstract example of the relations needed: John relates to Mary, both relate to School, John is Tall, Mary is Short, John has Blue Eyes, Mary has Green Eyes, query I want is which people are related to 'Short people that have Green Eyes and go to School' - answer John - Another example: TrackA -> ArtistA -> ArtistB -> AlbumA -----> [ label ] -> AlbumB -----> [ A ] -> TrackA:Remix -> Genre:House -> [ Album ] -----> [ label ] TrackB -> [ C ] [ B ] Example queries: Which Genre is TrackB closer to? answer: House - because it's related to Album C, which is related to TrackA and is related to Genre:House Get all Genre:House related albums of Label A : result: AlbumA, AlbumB - because they both have TrackA which is related to Genre:House - It is possible in MySQL but it would require a fixed set of attributes/columns for each item and a complex non-flexible query, instead I need every attribute to be an item by itself and instead of 'belonging' to something, to be 'related' to something.

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• making arrays from tab-delimited text file column

  - by absolutenewbie

  I was wondering if anyone could help a desperate newbie with perl with the following question. I've been trying all day but with my perl book at work, I can't seem to anything relevant in google...or maybe am genuinely stupid with this. I have a file that looks something like the following: Bob April Bob April Bob March Mary August Robin December Robin April The output file I'm after is: Bob April April March Mary August Robin December April So that it lists each month in the order that it appears for each person. I tried making it into a hash but of course it wouldn't let me have duplicates so I thought I would like to have arrays for each name (in this example, Bob, Mary and Robin). I'm afraid to upload the code I've been trying to tweak because I know it'll be horribly wrong. I think I need to define(?) the array. Would this be correct? Any help would be greatly appreciated and I promise I will be studying more about perl in the meantime. Thank you for your time, patience and help. #!/usr/bin/perl -w while (<>) { chomp; if (defined $old_name) { $name=$1; $month=$2; if ($name eq $old_name) { $array{$month}++; } else { print "$old_name"; foreach (@array) { push (@array, $month); print "\t@array"; } print "\n"; @array=(); $array{$month}++; } } else { $name=$1; $month=$2; $array{month}++; } $old_name=$name; } print "$old_name"; foreach (@array) { push (@array, $month); print "\t@array"; } print "\n";

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