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• After installing mysqli phpmyadmin stop loading

  - by phreakbox

  On Linux host 3.2.0-30-generic #48-Ubuntu SMP Fri Aug 24 16:52:48 UTC 2012 x86_64 x86_64 x86_64 GNU/Linux phpmyadmin won't load after installing mysqlnd. I'm using php5, mysql AND mysqlnd. Maybe mysql and mysqlnd conflicts for phpmyadmin. Problem: If I remove mysqlnd (mysqli support), PHP5 not working with mysqli, PHP5 only works with mysql. (Results for tests: function_exists('mysqli_fetch_all') return FALSE. That's ok. If I installed mysqlnd, php5-mysqlnd, PHP works with mysql + mysqli sumulately. Problems affected after mysqlnd install: After installing mysqli (mysqlnd) support, phpmyadmin won't load. Works PHP5 mysql + mysqlnd. When installing once again phpmyadmin than mysqlnd won't load. PHP PDO and mysql only works.

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• PHP MySQLi timeout not working

  - by Marcin

  Hi guys I have a weird problem with mysqli timeout options, here you go: I am using mysqli_init() and real_connect() in order to set MYSQLI_OPT_CONNECT_TIMEOUT $this->__mysqli = mysqli_init(); if(!$this->__mysqli->options(MYSQLI_OPT_CONNECT_TIMEOUT,1)) throw new Exception('Timeout settings failed') $this->__mysqli->real_connect(host,user,pass,db); .... Then I am initiating query on locked table (LOCKE TABLE users WRITE) and its just hanging, ignoring all my settings even: set_time_limit(1); ini_set('max_execution_time',1); ini_set('default_socket_timeout',1); ini_set('mysql.connect_timeout',1); I understand why set_time_limit(1) and max_execution_time is ignored but why other timeouts and especially MYSQLI_OPT_CONNECT_TIMEOUT are ignored and how to solve it. I am using PHP 5.3.1 on Windows and Linux boxes, please help.

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• PHP MySQLi timeout on locked tables?

  - by Marcin

  Hi guys I have a weird problem with mysqli timeout options, here you go: I am using mysqli_init() and real_connect() in order to set MYSQLI_OPT_CONNECT_TIMEOUT $this->__mysqli = mysqli_init(); if(!$this->__mysqli->options(MYSQLI_OPT_CONNECT_TIMEOUT,1)) throw new Exception('Timeout settings failed') $this->__mysqli->real_connect(host,user,pass,db); .... Then I am initiating query on locked table (LOCKE TABLE users WRITE) and its just hanging, ignoring all my settings even: set_time_limit(1); ini_set('max_execution_time',1); ini_set('default_socket_timeout',1); ini_set('mysql.connect_timeout',1); I understand why set_time_limit(1) and max_execution_time is ignored but why other timeouts and especially MYSQLI_OPT_CONNECT_TIMEOUT are ignored and how to solve it. I am using PHP 5.3.1 on Windows and Linux boxes, please help.

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• mysqli prepared statements select *

  - by Victor Dallecio

  I've spent this sunday trying to find what is wrong to the following code as it is not counting the rows. Could somebody help me with it? Thanks! /*check if same IP has visited today*/ if ($stmt = $mysqli->query('SELECT * FROM table WHERE colum1 = ? AND colum2 > DATE_SUB(NOW(), INTERVAL 1 DAY)')) { $stmt->bind_param('s', $ip); /* execute query */ $stmt->execute(); /*number of rows */ /*store result when using prepared statements*/ $stmt->store_result(); $row_cnt = $stmt->num_rows; printf("Result set has %d rows.\n", $row_cnt); $stmt->close(); }

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• mysqli insert problem

  - by Simon

  Hello i have this error: Warning: mysqli_stmt::bind_param() [mysqli-stmt.bind-param]: Number of elements in type definition string doesn't match number of bind variables in E:\wamp\www\classes\UserLogin.php on line 31 and i dont know what it is :/ here is my code function createUser($username, $password) { $mysql = connect(); if($stmt = $mysql->prepare('INSERT INTO users (username, password, alder, hood, fornavn, efternavn, city, ip, level, email) VALUES (?,?,?,?,?,?,?,?,?,?)')) { $stmt->bind_param($username,$password, $alder, $hood, $fornavn, $efternavn, $city, $ip, $level, $email); $stmt->execute(); $stmt->close(); } else { echo 'error: ' . $mysql->error; } then my user create the user they only need to type username and password, and later they can edit the profile and edit, email,alder,hood and like that :). Thanks for helping me

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• switch to mysqli a good idea?

  - by Rob

  I'm considering switching to mysqli for all my php projects. The way my code is written (I run very simple websites and built my own basic framework which I use across all of them) I shouldn't have too many problems modifying the functions and classes. However, i've only heard positive things about prepared statements, bar a few grumblings about the php functions available, most notably the lack of a simple replacement for using mysql_fetch_array in a while. This sounds a bit too good to be true, so I wondered if anyone could highlight some of the issues with using prepared statements, such as speed and resource usage.

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• Php mysqli and stored-procedure

  - by Mneva skoko

  I have a stored procedure: Create procedure news(in dt datetime,in title varchar(10),in desc varchar(200)) Begin Insert into news values (dt,title,desc); End Now my php: $db = new mysqli("","","",""); $dt = $_POST['date']; $ttl = $_POST['title']; $desc = $_POST['descrip']; $sql = $db-query("CALL news('$dt','$ttl','$desc')"); if($sql) { echo "data sent"; }else{ echo "data not sent"; } I'm new with php please help thank you

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• mysqli and field types

  - by Mikk

  Hi, I'd like to know if there is a simple way to fetch data from mysql tables with "correct" data types? What i mean, if field type is for example INT or SMALLINT is it possible to pass those types directly to PHP as integers? I did some searching and found mysqli_fetch_fields, but for SMALLIT type is 2, for INT 3 and so on. It could be done that way, but it looks rather clumsy workaround. Is there any better way? I'm using PHP and mysqli. Thank you.

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• PHP and MySQLi close()

  - by Theopile

  Hello all. I am new to mysql and php, but am attempting to make my own cms to help make managing my websites easier. Can someone explain the mysqli's close() function. 1)Is it nesseccary? 2)What exactly does it do? 3)I heard that after php runs its script that it closes the connection, is that true? 4)Lastly, is there a security issue when not closing your connection to the database? Thanks

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• mysqli returns only one row instead of multiple rows

  - by Tristan

  Hello, i'm totally new to mysqli and i took a generated code and adapted it for my need. public function getServeurByName($string) { $stmt = mysqli_prepare($this->connection, "SELECT DISTINCT * FROM $this->tablename where GSP_nom=?"); $this->throwExceptionOnError(); mysqli_stmt_bind_param($stmt, 's', $string); $this->throwExceptionOnError(); mysqli_stmt_execute($stmt); $this->throwExceptionOnError(); mysqli_stmt_bind_result($stmt, $row->idServ, $row->timestamp, ........... ........... $row->email); if(mysqli_stmt_fetch($stmt)) { $row->timestamp = new DateTime($row->timestamp); return $row; } else { return null; } } the problem, this example i took the template on returns only one row instead of all the records. how to fix that please ?

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• Does SELECT COUNT(*) work with MySQLi prepared statements?

  - by wordman

  I'm working on a test page and am using MySQLi prepared statements in my queries after reading they make my code safe from SQL injection. I have been successful with prepared statements so far with retrieving data from my DB, that all works great. What I want to do now is count the number of galleries within a project using SELECT COUNT(*). That's it. Without using a prepared statement, my old query looked like this: // count number of galleries per project $conn = dbConnect('query'); $galNumb = "SELECT COUNT(*) FROM pj_galleries WHERE project = {$pjInfo['pj_id']}"; $gNumb = $conn->query($galNumb); $row = $gNumb->fetch_row(); $galTotal = $row[0]; But for all my reading and searching the internet, I can not find out the proper way to write this as a prepared statement. I'm no PHP whiz here, and not coding daily isn't helping my skills. If I've missed anything please ask. Many thanks!

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• I having a problem with the mysqli free() member function

  - by neo skosana

  Hi I have code where I connected to the database like so: $db = new mysqli("localhost", "user", "pass", "company"); Now when I query the database like so: //query calls to a stored procedure 'user_info' $result = $db->query("CALL user_info('$instruc', 'c_register', '$eml', '$pass', '')"); //I use the $result This query works well. Now when I try and free that result like so: $result->free(); or $result->close(); It seems like it doesn't do anything because $result is still set. When I try to run another query it gives me this error: Fatal error: Call to a member function fetch_array() on a non-object in... For me to run this other query I have to close the db conection and connect again, then it will work. I want to know if there is a way I could run the other query without having to disconnect and reconnect to the database. thanks in advance.

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• I'm trying to populate a MySQL table with some data, but, mysqli won't let me insert every 10th stat

  - by Tunji Gbadamosi

  I want to initialise a 'ticket' table with some ticket IDs. To do this, I want to insert 120 ticket IDs into the table. However, at every 10th statement, MySQL tells me that the ID already exists and thus won't let me insert it. Here's my code: //make a query $insert_ticket_query = "INSERT INTO ticket (id) VALUES (?)"; $insert_ticket_stmt = $mysqli->stmt_init(); $insert_ticket_stmt->prepare($insert_ticket_query); $insert_ticket_stmt->bind_param('s', $ticket_id); $mysqli->autocommit(FALSE); //start transaction for($i=0;$i<NO_GUESTS;$i++){ $id = generate_id($i); $ticket_id = format_id($id, $prefix['ticket'], $suffix['ticket']); $t_id = $ticket_id; //echo '<p>'.$ticket_id.'</p>'; //$result = $mysqli->query("SELECT * FROM ticket WHERE id='".$ticket_id."'"); //$row_count = $result->num_rows; if(($result = $mysqli->query("SELECT * FROM ticket WHERE id='".$t_id."'")) == FALSE){ $result->close(); if($insert_ticket_stmt->execute()){ $mysqli->commit(); echo "<p>".$t_id."added to the ticket table!</p>"; } else{ $mysqli->rollback(); echo "problem inserting'".$t_id."' to the ticket table"; } } else{ echo "<p>".$t_id."already exists, so not adding it!</p>"; $result->close(); } } $mysqli->autocommit(TRUE); $insert_ticket_stmt->close(); ?>

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• mysqli - Do I really need to do $result->close(); & $mysqli->close(); ?

  - by James

  Just started using mysqli. If I'm working with small data sets on small websites (traffic-wise), do I really need to use these all the time? $result-close(); $mysqli-close(); also, for someone doing custom php & mysql work, without a framework, is mysqli the general preferred way of interacting with mysql?

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• Variable amount of columns returned in mysqli prepared statement

  - by manyxcxi

  I have a situation where a dynamic query is being generated that could select anywhere from 1 to over 300 different columns across multiple tables. It currently works fine just doing a query, however the issue I'm running into in using a prepared statement is that I do not know how to handle the fact that I don't know how many columns I will be asking for each time and therefor don't know how to process the results. The reason I believe a bind statement will help is because once this query is run once, it will most likely (though not always) be run again with the exact same parameters. Currently I have something like this: $rows = array(); $this->statement = $this->db->prepare($query); $this->statement->bind_param('i',$id); $this->statement->execute(); $this->statement->bind_result($result); while($this->statement->fetch()) { $rows[] = $result; } I know this doesn't work as I want it to, my question is how do I get the data back out of the query. Is it possible to bring the columns back in an associative array by column name, like a standard mysqli query?

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• How to output multiple rows from an SQL query using the mysqli object

  - by Jonathan

  Assuming that the mysqli object is already instantiatied (and connected) with the global variable $mysql, here is the code I am trying to work with. class Listing { private $mysql; function getListingInfo($l_id = "", $category = "", $subcategory = "", $username = "", $status = "active") { $condition = "`status` = '$status'"; if (!empty($l_id)) $condition .= "AND `L_ID` = '$l_id'"; if (!empty($category)) $condition .= "AND `category` = '$category'"; if (!empty($subcategory)) $condition .= "AND `subcategory` = '$subcategory'"; if (!empty($username)) $condition .= "AND `username` = '$username'"; $result = $this->mysql->query("SELECT * FROM listing WHERE $condition") or die('Error fetching values'); $this->listing = $result->fetch_array() or die('could not create object'); foreach ($this->listing as $key => $value) : $info[$key] = stripslashes(html_entity_decode($value)); endforeach; return $info; } } there are several hundred listings in the db and when I call $result-fetch_array() it places in an array the first row in the db. however when I try to call the object, I can't seem to access more than the first row. for instance: $listing_row = new Listing; while ($listing = $listing_row-getListingInfo()) { echo $listing[0]; } this outputs an infinite loop of the same row in the db. Why does it not advance to the next row? if I move the code: $this->listing = $result->fetch_array() or die('could not create object'); foreach ($this->listing as $key => $value) : $info[$key] = stripslashes(html_entity_decode($value)); endforeach; if I move this outside the class, it works exactly as expected outputting a row at a time while looping through the while statement. Is there a way to write this so that I can keep the fetch_array() call in the class and still loop through the records?

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• num_rows is 0 when it should be >0 for php mysqli code

  - by jpporterVA

  My num_rows is coming back as 0, and I've tried calling it several ways, but I'm stuck. Here is my code: $conn = new mysqli($dbserver, "dbuser", "dbpass", $dbname); // get the data $sql = 'SELECT AT.activityName, AT.createdOn FROM userActivity UA, users U, activityType AT WHERE U.userId = UA.userId and AT.activityType = UA.activityType and U.username = ? order by AT.createdOn'; $stmt = $conn->stmt_init(); $stmt->prepare($sql); $stmt->bind_param('s', $requestedUsername); $stmt->bind_result($activityName, $createdOn); $stmt->execute(); // display the data $numrows = $stmt->num_rows; $result=array("user activity report for: " . $requestedUsername . " with " . $numrows . " rows:"); $result[]="Created On --- Activity Name"; while ($stmt->fetch()) { $msg = " " . $createdOn . " --- " . $activityName . " "; $result[] = $msg; } $stmt->close(); There are multiple rows found, and the fetch loop process them just fine. Any suggestions on what will enable me to get the number of rows returned in the query? Suggestions are much appreciated. Thanks in advance.

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• MySQLi Wrapper -- will this slow down performance?

  - by Kerry

  I found the following code on php.net. I'm trying to write a wrapper for the MySQLi library to make things incredibly simple. If this is going to slow down performance, I'll skip it and find another way, if this works, then I'll do that. I have a single query function, if someone passes in more than one variable, I assume the function has to be prepared. The function that I would use to pass in an array to mysqli_stmt_bind_param is call_user_func_array, I have a feeling that is going to slow things down. Am I right? <?php /* just explaining how to call mysqli_stmt_bind_param with a parameter array */ $sql_link = mysqli_connect('localhost', 'my_user', 'my_password', 'world'); $type = "isssi"; $param = array("5", "File Description", "File Title", "Original Name", time()); $sql = "INSERT INTO file_detail (file_id, file_description, file_title, file_original_name, file_upload_date) VALUES (?, ?, ?, ?, ?)"; $sql_stmt = mysqli_prepare ($sql_link, $sql); call_user_func_array('mysqli_stmt_bind_param', array_merge (array($sql_stmt, $type), $param); mysqli_stmt_execute($sql_stmt); ?>

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• login not working when changing from mysql to mysqli

  - by user1438647

  I have a code below where it logs a teacher in by matching it's username and password in the database, if correct, then log in, if incorrect, then display a message. <?php session_start(); $username="xxx"; $password="xxx"; $database="mobile_app"; $link = mysqli_connect('localhost',$username,$password); mysqli_select_db($link, $database) or die( "Unable to select database"); foreach (array('teacherusername','teacherpassword') as $varname) { $$varname = (isset($_POST[$varname])) ? $_POST[$varname] : ''; } ?> <form action="<?php echo htmlentities($_SERVER['PHP_SELF']); ?>" method="post" id="teachLoginForm"> <p>Username</p><p><input type="text" name="teacherusername" /></p> <!-- Enter Teacher Username--> <p>Password</p><p><input type="password" name="teacherpassword" /></p> <!-- Enter Teacher Password--> <p><input id="loginSubmit" type="submit" value="Login" name="submit" /></p> </form> <?php if (isset($_POST['submit'])) { $query = " SELECT * FROM Teacher t WHERE (t.TeacherUsername = '".mysqli_real_escape_string($teacherusername)."') AND (t.TeacherPassword = '".mysqli_real_escape_string($teacherpassword)."') "; $result = mysqli_query($link, $query); $num = mysqli_num_rows($result); $loged = false; while($row = mysqli_fetch_array($result)) { if ($_POST['teacherusername'] == ($row['TeacherUsername']) && $_POST['teacherpassword'] == ($row['TeacherPassword'])) { $loged = true; } $_SESSION['teacherforename'] = $row['TeacherForename']; $_SESSION['teachersurname'] = $row['TeacherSurname']; $_SESSION['teacherusername'] = $row['TeacherUsername']; } if ($loged == true){ header( 'Location: menu.php' ) ; }else{ echo "The Username or Password that you Entered is not Valid. Try Entering it Again."; } mysqli_close($link); } ?> Now the problem is that even if the teacher has entered in the correct username and password, it still doesn't let the teacher log in. When the code above was the old mysql() code, it worked fine as teacher was able to login when username and password match, but when trying to change the code into mysqli then it causes login to not work even though username and password match. What am I doing wrong?

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• Using wildcards in prepared statement - MySQLi

  - by Michael Irwin

  Hi! I'm trying to run the following query, and I'm having trouble with the wildcard. function getStudents() { global $db; $users = array(); $query = $db->prepare("SELECT id, adminRights FROM users WHERE classes LIKE ? && adminRights='student'"); $query->bind_param('s', '%' . $this->className . '%'); $query->execute(); $query->bind_result($uid, $adminRights); while ($query->fetch()) { if (isset($adminRights[$this->className]) && $adminRights[$this->className] == 'student') $users[] = $uid; } $query->close(); return $users; } I'm getting an error that states: Cannot pass parameter 2 by reference. The reason I need to use the wildcard is because the column's data contains serialized arrays. I guess, if there's an easier way to handle this, what could I do? Thanks in advance!

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• Mysqli results memory usage

  - by Poe

  Why is the memory consumption in this query continuing to rise as the internal pointer progresses through loop? How to make this more efficient and lean? $link = mysqli_connect(...); $result = mysqli_query($link,$query); // 403,268 rows in result set while ($row = mysqli_fetch_row($result)) { // print time, (get memory usage), -- row number } mysqli_free_result(); mysqli_close($link); /* 06:55:25 (1240336) -- Run query 06:55:26 (39958736) -- Query finished 06:55:26 (39958784) -- Begin loop 06:55:26 (39960688) -- Row 0 06:55:26 (45240712) -- Row 10000 06:55:26 (50520712) -- Row 20000 06:55:26 (55800712) -- Row 30000 06:55:26 (61080712) -- Row 40000 06:55:26 (66360712) -- Row 50000 06:55:26 (71640712) -- Row 60000 06:55:26 (76920712) -- Row 70000 06:55:26 (82200712) -- Row 80000 06:55:26 (87480712) -- Row 90000 06:55:26 (92760712) -- Row 100000 06:55:26 (98040712) -- Row 110000 06:55:26 (103320712) -- Row 120000 06:55:26 (108600712) -- Row 130000 06:55:26 (113880712) -- Row 140000 06:55:26 (119160712) -- Row 150000 06:55:26 (124440712) -- Row 160000 06:55:26 (129720712) -- Row 170000 06:55:27 (135000712) -- Row 180000 06:55:27 (140280712) -- Row 190000 06:55:27 (145560712) -- Row 200000 06:55:27 (150840712) -- Row 210000 06:55:27 (156120712) -- Row 220000 06:55:27 (161400712) -- Row 230000 06:55:27 (166680712) -- Row 240000 06:55:27 (171960712) -- Row 250000 06:55:27 (177240712) -- Row 260000 06:55:27 (182520712) -- Row 270000 06:55:27 (187800712) -- Row 280000 06:55:27 (193080712) -- Row 290000 06:55:27 (198360712) -- Row 300000 06:55:27 (203640712) -- Row 310000 06:55:27 (208920712) -- Row 320000 06:55:27 (214200712) -- Row 330000 06:55:27 (219480712) -- Row 340000 06:55:27 (224760712) -- Row 350000 06:55:27 (230040712) -- Row 360000 06:55:27 (235320712) -- Row 370000 06:55:27 (240600712) -- Row 380000 06:55:27 (245880712) -- Row 390000 06:55:27 (251160712) -- Row 400000 06:55:27 (252884360) -- End loop 06:55:27 (1241264) -- Free */

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• MySqli Prepared Statment Fetch Row

  - by pws5068

  I'm looking for an efficient way to select a specific row with a php prepared statement. $iDB = new mysqliDB(); $stmt = $iDB->prepare($sql); $stmt->bind_param('s',$searhStr); $stmt->execute(); $stmt->store_result(); $stmt->bind_result($objID,$typeID,$year,$updated); // Now jump to row $rowNumber echo("Obj ID = {$objID}"); Any suggestions? Thanks!

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• Searching with MATCH(), AGAINST() and AS score with mysqli and php

  - by Drew

  Below is the code I am using to search my table. I have made the relevant columns FULLTEXT in the table. This doesn't return me anything. Can someone tell me what it is that i'm doing wrong? Thanks in advance. $sql = 'SELECT id,uname,class,school, MATCH(uname, class, school) AGAINST(?) AS score FROM images WHERE MATCH(uname, class, school) AGAINST(? IN BOOLEAN MODE) ORDER BY score DES'; $stmt = $db_connection->prepare($sql); $stmt->bind_param('ss',$keyword,$keyword); $stmt->execute(); $stmt->store_result(); $stmt->bind_result($id,$uname,$class,$school); $xml = "<data>".PHP_EOL; while($stmt->fetch()){ $xml .= " <person>".PHP_EOL; $xml .= " <id>$id</id>".PHP_EOL; $xml .= " <name>$uname</name>".PHP_EOL; $xml .= " <class>$class</class>".PHP_EOL; $xml .= " <school>$school</school>".PHP_EOL; $xml .= " </person>".PHP_EOL; } $xml .= "</data>"; echo $xml; Below is an image of the indexes of the table:

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• PHP MySQLi isn't letting me alter a table (adding a new column)

  - by asdasd

  Well thats pretty much it. This is my query: $query = 'ALTER TABLE permissions ADD '.$name.' INT NOT NULL DEFAULT \'0\''; Where $name is already checked to exist with only lower case alpha letters, and not more than 20 length. Im just starting this out with very simple names. The next 4 lines of code after that one are: if($stmt = $db -> prepare($query)) { $success = $stmt -> execute(); $stmt -> close(); if(!$success) echo 'ERROR: Unsuccessful query: ',$db->error,PHP_EOL; } And I get back, every time ERROR: Unsuccessful query: And no error message. Is there a way to get more error messages so I can see what is failing? I can add new columns through phpmyadmin, but that really doesnt help me at all. The $db is fine, i do lots of stuff before and after this one section. It is only adding new column to the table that fails. side question: prepare() rejected my query every time when i tried to make those 2 variables, the $name and the 0 value as ? ? prepared statement values. Thats why they are in the real query and not bound later. If i could change that too I would like that.

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• MySQLi insert into prepare error

  - by JPM

  Hi I inserted a lot of stuff into a mysql databse. But now I get an error in the prepare statement. I see Database prepare error. What am I doing wrong? This is my Code: $sql = "INSERT INTO Contact (IP,To,Name,Email,Subject,Text) VALUES ( ?, ?, ?, ?, ?, ? ) "; if (!$stmt = $db->prepare($sql)) { echo 'Database prepare error'; exit; } $stmt->bind_param('ssssss', $ip_contact, $to_contact, $name_contact, $email_contact, $subject_contact, $text_contact); if (!$stmt->execute()) { echo 'Database execute error'; exit; } $stmt->close(); My SQL table looks like this: Contact: - ID int(11) auto_increment primary key - IP varchar(15) - To varchar(5) - Name varchar(20) - Email varchar(20) - Subject varchar(20) - Text varchar(600)

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